(a) The speed of the particle at t = 2 s is 10 m/s.
(b) The acceleration of the particle at t = 4 s is -18 m/s².
The position of a particle as a function of time is given by r = (3t2 − 2t)i − t3, where r is in meters and t in seconds.
(a) Determine its speed at t = 2 s:To find the speed of the particle, we have to take the derivative of the position of the particle with respect to time. So, v(t) = dr/dt.
Here, r = (3t² − 2t)i − t³v(t)
= (d/dt) [(3t² − 2t)i − t³]v(t)
= (6t − 2)i − 3t²v(2)
= (6(2) − 2)i − 3(2)²v(2)
= 10i m/s.
Therefore, the speed of the particle at t = 2 s is 10 m/s.
(b) Determine its acceleration at 4 s: To find the acceleration of the particle, we have to take the derivative of the velocity of the particle with respect to time. So, a(t) = dv/dt.
Here, v(t) = (6t − 2)i − 3t²a(t)
= (d/dt) [(6t − 2)i − 3t²]a(t)
= 6i − 6t a(4)
= 6i − 6(4) a(4) = -18i m/s².
Therefore, the acceleration of the particle at t = 4 s is -18 m/s².
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when a mass m hangs from a vertical wire of length l, waves travel on this wire with a speed v.A. what will be the speed of these waves if we triple M without stretching the wire?
B. what will be the speed of these waves if we replace the wire with an identical one, except twice as long?
C. What will be the speed of these waves if we replace the wire with one of the same length, but two times as heavy
D. what will be the speed of these waves if we stretch the wire to thrice its original length
E. What will be the speed of these waves (in terms of V) if we increase M by a factor of 18.0, which stretches the wire to double its origina length?
A. The speed of the waves will remain unchanged if the mass is tripled without stretching the wire.
B. The speed of the waves will be halved if the wire is replaced with an identical one, except twice as long. This is because the waves will have to travel twice the distance in the same amount of time.
C. The speed of the waves will remain unchanged if the wire is replaced with one of the same lengths, but two times as heavy.
D. The speed of the waves will be halved if the wire is stretched to thrice its original length. This is because the waves will have to travel thrice the distance in the same amount of time.
E. The speed of the waves will be halved if the mass is increased by a factor of 18.0 and the wire is stretched to double its original length. This is because the waves will have to travel twice the distance in the same amount of time. The speed of the waves will thus be V/2.
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A puck attached to a 50-cm -long string rotates in a horizontal circle on a frictionless table at 40 rpm. The length of the string is gradually reduced to 25 cm as it is slowly pulled through a hole in the table. What is the puck's angular velocity, in rpm, on the shorter string? Express your answer in revolutions per minute
The puck's angular velocity on the shorter string would be 160 rpm.
The conservation of angular momentum states that the product of the moment of inertia and the angular velocity is conserved as long as there are no external torques acting on the system. Therefore, we can use the following equation to solve this problem:
I₁ × ω₁ = I₂ × ω₂
where I₁ and I₂ are the moments of inertia of the puck on the longer and shorter strings, respectively, and ω₁ and ω₂ are the corresponding angular velocities in radians per second.
To solve for the angular velocity on the shorter string in revolutions per minute, we need to convert the angular velocity from radians per second to revolutions per minute. Since there are 2π radians in one revolution and 60 seconds in one minute, we can use the following conversion factor:
1 radian per second = (1/2π) revolutions per minute
Now, let's find the moments of inertia of the puck on the longer and shorter strings. The moment of inertia of a point mass rotating about an axis perpendicular to its motion is given by:
I = mr²
where m is the mass of the puck and r is the distance from the axis of rotation to the mass. On the longer string, the distance from the axis of rotation to the center of mass of the puck is 50 cm, so the moment of inertia is:
I1 = m(0.5)² = 0.25m
On the shorter string, the distance from the axis of rotation to the center of mass of the puck is 25 cm, so the moment of inertia is:
I2 = m(0.25)² = 0.0625m
Now we can plug these values into the conservation of angular momentum equation:
I₁ × ω₁ = I₂ × ω₂
0.25m × (40 rpm) × (2π/60) = 0.0625m × ω₂ × (2π/60)
Simplifying and solving for ω₂ in rpm:
ω₂ = (0.25/0.0625) × 40 = 160 rpm
So the puck's angular velocity on the shorter string is 160 rpm.
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Barry slides across an icy pond. The coefficient of kinetic friction between his
shoes and the ice is 0.15. If his mass is 83 kg, what is the force of friction
acting on him?
OA. 813 N
B. 1150 N
C. 122 N
D. 352 N
The force of friction acting on him is 122 N. The correct answer is option C
What is Friction ?Friction is a force that opposes the motion of a static or a moving object.
Given that Barry slides across an icy pond. The coefficient of kinetic friction between his shoes and the ice is 0.15. If his mass is 83 kg
The given parameters are;
Mass m = 83 kgCoefficient of kinetic friction μ = 0.15Frictional force \(F_{r}\) = ?The normal reaction N on the body = mg
N = 83 x 9.8
N = 813.4 N
The Frictional force formula is \(F_{r}\) = μN
\(F_{r}\) = 0.15 x 813.4
\(F_{r}\) = 122.01 N
Therefore, the force of friction acting on him is 122 N approximately.
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if h equals 50 km/sec/mpc, then a galaxy with a radial velocity of 50,000 km/sec will have a distance of about 1 mpc.
T/F
If h equals 50 km/sec/mpc, then a galaxy with a radial velocity of 50,000 km/sec will have a distance of about 1 mpc is false.
The formula used to calculate the distance to a galaxy based on its radial velocity is given by Hubble's Law: v = H0 × d
where v is the radial velocity of the galaxy, H0 is the Hubble constant, and d is the distance to the galaxy.
In this case, the radial velocity is given as 50,000 km/sec, and if we assume the value of the Hubble constant (H0) to be 50 km/sec/Mpc, we can rearrange the equation to solve for the distance:
d = v / H0 = 50,000 km/sec / 50 km/sec/Mpc = 1,000 Mpc
Therefore, a galaxy with a radial velocity of 50,000 km/sec would have a distance of 1,000 Mpc, not 1 Mpc. Hence, the statement is False.
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A 12 kg mass, moving at 16 m/s, experiences an opposing force of 18 n for 3. 0 s. What is the magnitude of the change in momentum of the object?.
The momentum of an object is the product of its mass and velocity. If the object is moving with a certain velocity and an external force is applied on it then there is a change in the momentum of the object.
The formula for calculating impulse is FΔt, where F is the force and Δt is the time for which the force acts on the object. The impulse acting on the object is equal to the change in momentum of the object.
The time for which the force acts on the object is Δt = 3.0 s. Therefore, the magnitude of the change in momentum of the object is 54 kg m/s. The impulse acting on the object is also 54 N s.
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when observing a binary counter circuit on the oscilloscope, why is it advisable to trigger off the lowest (counter) counter frequency signal?
The most comprehensive variety of oscilloscope software for applications-specific debugging, compliance, and debugging is provided by Keysight.
Which Oscilloscope Probe Do You Need?For oscilloscopes from the Infinitives and Infinium Series, Keysight offers a wide selection of voltage, current, and optical probing solutions. For information on the best probe for your testing requirements, consult this page.Your Keysight oscilloscope and the software are fully compatible, and the program gives you the knowledge you need to rapidly and efficiently innovate your greatest designs. Learn how automated software testing may help you produce, test, and validate your designs more quickly. You can also use the more than 50 compliance test software packages to keep up with the current requirements.Guide to Selecting Oscilloscope Probes : Making precise measurements depends on being aware of typical probing errors. In your system, probes can cause jitter, noise, and loading. Your measurement results are significantly impacted by the electrical behavior of your probes, which may even affect how well your device works. This eBook will teach you how to steer clear of typical oscilloscope probing hazards.To Learn more About binary counter circuit refer To:
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During a spontaneous fission reaction, net energy ____
Group of answer choices
is released
is absorbed
is zero
Following a lecture on transverse and longitudinal waves, four students make venn diagrams to characterize these waves. which venn diagram is correct? a venn diagram with two intersecting circles. the circle on the left is labeled transverse waves with entries light, can travel through a vacuum, vibrating string, created by a disturbance and medium motion is perpendicular. the circle on the right is labeled longitudinal waves with entries medium motion is parallel, has regions of high and low density, sound and travel faster in a denser medium. the overlapping region has entries has speed and travels through solids. a venn diagram with two intersecting circles. the circle on the left is labeled transverse waves with entries light, can travel through a vacuum, vibrating string and medium motion is perpendicular. the circle on the right is labeled longitudinal waves with entries medium motion is parallel, has regions of high and low density, sound and travel faster in a denser medium. the overlapping region has entries, created by a disturbance, has speed and travels through solids. a venn diagram with two intersecting circles. the circle on the left is labeled transverse waves with entries light, all parts of the electromagnetic spectrum, vibrating string, medium motion is perpendicular. the circle on the right is labeled longitudinal waves with entries medium motion is parallel, has regions of high and low density, sound and can travel through a vacuum. the overlapping region has entries, created by a disturbance, has speed and travels through solids. a venn diagram with two intersecting circles. the circle on the left is labeled transverse waves with entries light, can travel through a vacuum, vibrating string and medium motion is perpendicular. the circle on the right is labeled longitudinal waves with entries medium motion is parallel, has regions of high and low density, all parts of the electromagnetic spectrum and travel faster in a denser medium. the overlapping region has entries, created by a disturban
Venn diagram B is correct. A Venn diagram is a type of graph that uses circles to depict connections between objects or fixed groups of entities.
What Is a Venn Diagram and how does It Work?A Venn diagram is a diagram that uses circles to depict relationships between objects or finite groups of objects. Circles that overlap share characteristics, whereas circles that do not overlap do not.
A Venn diagram with two intersecting circles. the circle on the left is labeled transverse waves with entries light, can travel through a vacuum, vibrating string and medium motion is perpendicular.
The circle on the right is labeled longitudinal waves with entries medium motion is parallel, has regions of high and low density, sound and travel faster in a denser medium.
The overlapping region has entries, created by a disturbance, has speed, and travels through solids.
Hence Venn diagram B is correct
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Uncle Fester's CD's
Congratulations, your uncle fester has just willed you his CD collection!!! Using what you know about classification, see if you can arrange these CDs into similar groups to make them easier for your customers to find. Make a list of four groups that these CDs can be classified into.
The rest of the graph looks like this but here are the CD's for group 3 and Group 4.
Group 3
The Beatles
Beyonce
Alicia Keys
Carrie Underwood
Group 4
Bach
Blake Shelton
Beach Boys
Post Malone
I am having trouble with the graph.
Answer: hey
Explanation:
________________________ is the distance traveled from the time your brain tells your foot to move from the accelerator until your foot is actually pushing the brake pedal.
a) Braking distance.
b) Reaction distance.
c) Perception distance.
d) Total stopping distance.
Reaction distance._ is the distance traveled from the time your brain tells your foot to move from the accelerator until your foot is actually pushing the brake pedal. The correct answer is b)
Reaction distance refers to the distance traveled from the moment your brain receives a stimulus or perceives a need to take action, to the moment your muscles actually respond to that stimulus. In the given scenario, the brain receives the signal to move the foot from the accelerator to the brake pedal.When driving, various factors can affect the reaction distance, such as alertness, attentiveness, and the speed of the vehicle. It takes a certain amount of time for the brain to process the information, send the signal to the muscles, and for the muscles to respond accordingly.
Braking distance, on the other hand, refers to the distance traveled by the vehicle from the moment the brakes are applied until it comes to a complete stop. It includes the reaction distance, but also takes into account other factors like the braking efficiency, road conditions, and the vehicle's deceleration. Perception distance refers to the distance covered while a driver recognizes a potential hazard and becomes aware of the need to take action. It is the time taken to process visual cues and mentally process the situation. Total stopping distance is the sum of the reaction distance and the braking distance, representing the entire distance covered by the vehicle from the moment the driver perceives the need to stop until the vehicle comes to a complete halt.
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Important support for general relativity came from studies of the precession of the orbit of?
Important support for general relativity came from studies of the precession of the orbit of Mercury
A route that an object in space follows around another is known as an orbit. A satellite is a thing that orbits the earth. An Earth- or moon-like natural satellite is one possibility. Moons are satellites that orbit many planets. A man-made satellite is also possible, such as the International Space Station.
Albert Einstein created the gravitational theory known as general relativity between 1907 and 1915. According to general relativity theory, the apparent gravitational pull between masses is caused by the bending of spacetime caused by those masses.
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a vertical spring launcher is attached to the top of a block and a ball is placed in the launcher. while the block slides at constant speed to the right across a horizontal surface with negligible friction between the block and the surface, the ball is launched upward. when the ball reaches its maximum height, what will be the position of the ball relative to the launcher?
The ball's initial speed decreases as it moves upward from the vertical spring launcher. At its maximum height, the ball has zero speed and begins to fall back down. Since the block is sliding at a constant speed with negligible friction, the position of the launcher relative to the ground remains unchanged.
Since the block is sliding at a constant speed across a horizontal surface with negligible friction, it means the block is moving at a steady pace without being slowed down by the surface. Meanwhile, the ball is launched vertically upward from the launcher.
When the ball reaches its maximum height, it will momentarily have zero vertical speed before starting to descend due to gravity. However, during its upward and downward journey, the ball maintains the same horizontal speed as the block, since there is negligible friction between the block and the surface.
As a result, the position of the ball relative to the launcher will remain the same horizontally when it reaches its maximum height. The ball will be vertically above the launcher at the maximum height, maintaining the same horizontal position throughout its motion.
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Choose the word to fill in the blank, which best completes the sentence. Light entering a clear glass prism. A rainbow exits the prism on the opposite side. Prisms made of glass will ________ light and create colored rainbows on a wall, as is shown in the image above. A. Transmit c. Refract b. Transfer d. Absorb.
Answer:
the answer is B!!!! just took the topic test
Explanation:
b
Answer:
B. most commonly found in sand or quartz.
Explanation:
Got 100% on EDGE
Which types of light are absorbed by genetic material?
ultraviolet (UV)
visible
infrared (IR)
microwave F radio
Explanation:
the answerer is visible
Genetic material is known to absorb UV light. Given what we know, we can confirm that genetic material is not known to absorb light originating from an infrared or microwave radio source.
What light does genetic material absorb?Genetic material is the hereditary substance in the cell. It carries all information specific to an organism. It is known as DNA (deoxyribonucleic acid) or RNA (ribonucleic acid)
UV light is electromagnetic radiation, and the primary source of UV light that we are exposed to is the sun.
Therefore, given that the only form of light listed that genetic material is known to absorb is that of Ultraviolet or UV light, we can confirm that the answer to the question proposed is infrared and microwave radio light.
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Describe the moons of Mars?
Answer:
The two moons of Mars are Phobos and Deimos. They are irregular in shape. Both were discovered by American astronomer Asaph Hall in August 1877 and are named after the Greek mythological twin characters Phobos (fear) and Deimos (panic) who accompanied their father Ares into battle, SO they were irregular in shape
Explanation:
Which best compares radiation and conduction?
A. Both transfer thermal energy from warm objects to cooler objects.
B. Both can transfer energy through empty space.
C. Both transfer thermal energy by electromagnetic waves.
D. Both involve the transfer of energy through direct contact.
And also who likes Rick and Morty OwO
Answer:
A
Explanation:
An 81.7-kg baseball player slides into second base. The coefficient of kinetic friction between the player and the ground is 0.50. If the player comes to rest after 1.4 s, what was his initial velocity?
The initial velocity of the baseball player is 6.86 m/s.
What is the acceleration of the baseball player?
The acceleration of the player is calculated by applying Newton's second law of motion.
ma = μmg
a = μg
where;
μ is coefficient of frictiong is acceleration due to gravity.
a = 0.5 x 9.8 m/s²
a = 4.9 m/s²
The initial velocity of the player is calculated as follows;
v = u - at
where;
v is the final velocity when he stops, = 0u is the initial velocityt is the time of motion0 = u - at
u = at
u = 4.9 m/s² x 1.4 s
u = 6.86 m/s
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Collision 1: Blue Cart Initially at Rest Set the initial blue cart velocity to 0 m/s. Set the mass values to different values. Run the simulation and record the mass and velocity values. Before Collision After Collision mRed = _________ kg mBlue = _________ kg Use mass and velocity values to complete the following momentum table. Before Collision After Collision ∆Momentum Red Cart ________kg x _______m/s = ____________kg•m/s ________kg x _______m/s = ____________kg•m/s Blue Cart ________kg x _______m/s = ____________kg•m/s ________kg x _______m/s = ____________kg•m/s
Answer:
it is very hard but i am trying to help you.
Explanation:
I need help!! Any feedback, please?
Answer:
A. Quarter or less of the entire moon
Explanation:
This is because as the Moon revolves around the Earth, the light of the sun that is falling on the moon gets blocked by the Earth when we see the crescent moon.
That's why we only see the quarter or less of the entire moon shining on crescent moon night.
Korbel pushes a 15 kg chair for a distance of 30 meters. How much
work did he do?
The work that has been done by the Korbel is 4.41kJ.
What is the work done?We have to note that we define work in physics as the product of the force and the distance. In the case of the chair in the question, we have been told that Korbel pushes a 15 kg chair for a distance of 30 meters.
The force in this case would be the weight of the chair that we have and we can write that;
W = mgh
m = mass
g = acceleration due to gravity
h = height
Thus
W = 15 * 9.8 * 30
W = 4.41kJ
Thus a work of about 4.41kJ is done.
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Julio rubs a balloon with a cloth and places the balloon next to his head. He uses another balloon and places it next to his head without rubbing a cloth against it. Select the control in Julio's experiment.a.Both balloons he used in the experimentb.The balloon that was not rubbed with a clothc.The balloon that was rubbed with a clothd.Placing the balloon next to his hair
In Julio's experiment, the control would be the balloon that was not rubbed with a cloth (option b).
The control is an essential part of an experiment, as it serves as a basis for comparison and helps to determine the cause of observed changes. In this case, the control balloon helps to isolate the effect of rubbing the cloth on the other balloon.
When Julio rubs a balloon with a cloth, he is creating a buildup of static electricity, which can cause the balloon to attract objects, such as his hair. By using a second balloon without rubbing it with a cloth, he can compare the effects of the static electricity generated in the first balloon to the behavior of the second balloon, which has not been subjected to the same treatment.
By comparing the two balloons, Julio can better understand the influence of rubbing the cloth on the balloon and the role of static electricity in this phenomenon. Without the control balloon, it would be more difficult to determine whether the observed effects are solely due to the rubbing of the cloth or other factors.
In conclusion, the control in Julio's experiment is the balloon that was not rubbed with a cloth. This control helps to isolate the effects of rubbing the cloth and demonstrates the role of static electricity in the experiment. The correct option is b.
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What would be the final temperature of a mixture of 100 g of water at 90°Cand 600 g of water at 20°C?
Final temperature = T
Lost 100 g at 90° = gained 600 g at 20°
Apply the formula:
100 x S x (90 - T ) = 600 x S x (T-20)
90 - T =[ 600 x S x (T-20) ]/ (100 x S)
90 - T = 6 (T-20 )
90 -T = 6T - 120
90 + 120 =6T+T
210 = 7T
210/7 = T
T = 30°
Final temperature = 30°
A rock breaks loose from the top of a 119 m cliff. How fast is the rock going when it reaches the ground below?
Rock will reach the ground with the velocity of 48.29m/s.
What is Velocity?Velocity is defined as the vector expression of displacement an object or particle undergoes with respect to time. The standard unit of velocity for expressing velocity magnitude is meter per second (m/s) or centimeter per second (cm/s). It is a vector quantity because it has both magnitude and direction.
Velocity can be expressed by the formula:
Velocity= Displacement/ Time taken
v= d/t
In terms of acceleration and initial and final velocity, it is expressed as:
\(v^2= u^2+ 2as\) (We can use 'g' in place of 'a' in the presence of the gravity)
Where, v= final velocity
u= initial velocity
s= Displacement
a= Acceleration or g= Acceleration due to gravity which is expressed as 9.8\(m/s^2\)
For above given information,
u= 0m/s
a=g= 9.8\(m/s^2\)
Δs= ( Final displacement - Initial displacement)= (0-119)= -119m
\(v=\sqrt{0+2*9.8*-119} \\v= \sqrt{-2332.4}\)
\(v= -48.29m/s\)
When an object is in free fall, we assume its velocity to be negative due to the downward direction.
Thus, rock will reach the ground with the velocity of 48.29m/s.
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it is possible for an excited hydrogen atom to return to the ground state by the emission of a single photon. regardless of the initial excited state, this electron transition produces a spectral line in which region of the electromagnetic spectrum?
1. ultraviolet
2. infrared
3. visible light
4. radio waves
Answer:
1. Ultraviolet
Explanation:
This is called the Balmer series. Transitions ending in the ground state (n = 1) are called the Lyman series, but the energies released are so large that the spectral lines are all in the ultraviolet region of the spectrum.
It is possible for an excited hydrogen atom to return to the ground state by the emission of a single photon. Regardless of the initial excited state, this electron transition produces a spectral line in ultraviolet region of the electromagnetic spectrum. The correct option is 1.
What is electromagnetic spectrum?An electromagnetic spectrum is the spectrum consisting of the colors of radiation of a white light with different wavelengths.
It is possible for an excited hydrogen atom to return to the ground state by the emission of a single photon.
The transitions which ends in the ground state (n = 1) are termed as Lyman series. Energy released is large in amount so that the spectral lines fall in the ultraviolet region of the spectrum.
Thus, regardless of the initial excited state, this electron transition produces a spectral line in ultraviolet region of the electromagnetic spectrum. The correct option is 1.
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Q7. What caused the early materials to clump together?
A) heat
B) explosions C) pressure
D) gravity
Answer:
C. pressure
because heat expands and so does explosions and gravity is just gravity.
(b) if one micrometeorite (a sphere with a diameter of 1.30 10-6 m) strikes each square meter of the moon each second, how many years would it take to cover the moon to a depth of 1.20 m? (hint: consider a box on the moon 1.00 m on a side and 1.20 m deep, and find how long it will take to fill the box.)
The time required to cover the Moon to a depth of 1.20 meters with micrometeorites.
To find out how long it would take to cover the Moon to a depth of 1.20 meters with micrometeorites, we can calculate the volume of the Moon and then divide it by the volume of one micrometeorite. Let's break down the calculation step by step:
Calculate the volume of the Moon:
The average radius of the Moon is approximately 1.737 ×10⁶ meters. Using the formula for the volume of a sphere, V = (4÷3)πr³, we can calculate the volume of the Moon.
\(V_{moon}\) = (4÷3)π(1.737 × 10⁶)³
Calculate the volume of one micrometeorite:
The diameter of the micrometeorite is given as 1.30 ×10⁽⁻⁶⁾ meters, which means the radius is half of that.
\(r_{meteorite}\) = (1.30 × 10⁽⁻⁶⁾)÷2
Using the formula for the volume of a sphere, V = (4÷3)πr₃, we can calculate the volume of one micrometeorite.
\(V_{meteorite}\) = (4÷3)π((1.30 × 10⁽⁻⁶⁾)÷2)³
Calculate the number of micrometeorites needed to fill the Moon:
To find the number of micrometeorites required to fill the Moon, we divide the volume of the Moon by the volume of one micrometeorite.
\(N_{meteorites}\) = \(V_{moon}\) ÷ \(V_{meteorite}\)
Calculate the time to fill the Moon:
Since one micrometeorite strikes each square meter of the Moon each second, we can equate the number of micrometeorites needed to fill the Moon to the number of seconds it would take.
Time = \(N_{meteorites}\) ÷ (1 m²/s)
Convert seconds to years:
Finally, we convert the time in seconds to years by dividing by the number of seconds in a year (assuming 365.25 days in a year and 24 hours in a day).
\(Time_{years}\) = Time ÷ (365.25 days/year × 24 hours/day × 3600 seconds/hour)
Performing these calculations will give us the time required to cover the Moon to a depth of 1.20 meters with micrometeorites.
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Why is it colder in winter than summer? Give two reasons.
Answer:
Actually, the sun goes a bit down, like it's not all the way up as to summer. How I know is that you actually can go online maybe search for some videos and see proof, I don't really know how to explain it.
Explanation:
Reason #1: If you check, go out for 12 hours and see, I think the sun is a little down.
Reason #2:
The earth’s axis is tilted.
From a Brainly user of this question for more info:
The Earth is NOT farther away from the sun in USA Winter, and NOT closer to the sun in USA Summer. In 2021, we will be NEAREST to the sun on January 2, and FARTHEST from the sun on July 5 !
NEAREST to the sun next Saturday.
FARTHEST from the sun next July 5.
Using the Bohr model, what is the energy in joules of the photon produced when an electron in a He* ion moves from the orbit with n = 5 to the orbit with n = 2?
The energy of the photon produced when an electron in a He* ion moves from the orbit with n = 5 to the orbit with n = 2 is approximately 7.65 x 10^(-19) joules.
According to the Bohr model of the atom, the energy of an electron in a particular orbit is given by the equation:
E = -13.6 * (Z^2 / n^2) eV
Where:
E is the energy of the electron in electron volts (eV),
Z is the atomic number of the nucleus (in this case, Z = 2 for helium),
n is the principal quantum number of the orbit.
To calculate the energy difference between two orbits, we can subtract the energy of the initial orbit from the energy of the final orbit:
ΔE = E_final - E_initial
For the initial orbit with n = 5, the energy can be calculated as:
E_initial = -13.6 * (2^2 / 5^2) eV
= -13.6 * (4 / 25) eV
= -13.6 * 0.16 eV
= -2.176 eV
For the final orbit with n = 2, the energy can be calculated as:
E_final = -13.6 * (2^2 / 2^2) eV
= -13.6 * (4 / 4) eV
= -13.6 eV
Now, we can calculate the energy difference:
ΔE = E_final - E_initial
= (-13.6 eV) - (-2.176 eV)
= -11.424 eV
To convert the energy difference to joules, we can use the conversion factor: 1 eV = 1.602 x 10^(-19) joules.
ΔE_joules = ΔE * (1.602 x 10^(-19) joules/eV)
= (-11.424 eV) * (1.602 x 10^(-19) joules/eV)
= -18.307 x 10^(-19) joules
Since energy cannot be negative, we take the absolute value of ΔE_joules:
|ΔE_joules| = 18.307 x 10^(-19) joules
Therefore, the energy in joules of the photon produced when an electron in a He* ion moves from the orbit with n = 5 to the orbit with n = 2 is approximately 7.65 x 10^(-19) joules.
The energy of the photon emitted when an electron in a He* ion transitions from the orbit with n = 5 to the orbit with n = 2 is approximately 7.65 x 10^(-19) joules.
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HELP PLEASE IMMEDIATILY !!!!!!
- Determine the force required to accelerate a block of ice with a mass of 3.5 kg from 0 to 8 m/s2.
- Determine the acceleration that a cart with a mass of 25 kg experiences when it is being pulled with a force of 50 Newtons.
- Determine the mass of a block of ice that is accelerated to 6 m/s2 by a force of 3 Newtons.
- What is a free body diagram and what information does it contain?
Answer all of them please
The force required to accelerate the block is 28 N.
The acceleration of a cart with a mass of 25 kg and applied force of 50 N is 2 m/s².
The mass of a block of ice that is accelerated to 6 m/s2 by a force of 3 Newtons is 0.5kg.
A free body diagram is a sketch of forces acting on an object. It consists of the applied force, weight of the object, frictional force and normal reaction.
Force required to accelerate the blockThe force required to accelerate the block is calculated as follows;
F = ma
F = 3.5 kg x 8 m/s²
F = 28 N
Acceleration that cartThe acceleration of a cart with a mass of 25 kg and applied force of 50 N is calculated as follows;
a = F/m
a = 50/25
a = 2 m/s²
Mass of the block of iceThe mass of a block of ice that is accelerated to 6 m/s2 by a force of 3 Newtons is calculated as follows;
m = F/a
m = 3 N / 6 m/s²
m = 0.5 kg
What is a free body diagram?A free body diagram is a sketch of forces acting on an object. It consists of the applied force, weight of the object, frictional force and normal reaction.
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A net force of 1 newton causes an object to accelerate at a rate of 5.0 meters per second per second. What is the mass of the object?
The mass of the object is equal to 0.2 Kg when it accelerates at 5.0 m/s².
What is acceleration?Acceleration of an object can be defined as the rate at which the object changes its velocity w.r.t. time. The acceleration can be expressed as the second derivative of position w.r.t. time and is a vector parameter.
The force exerted on an object is equal to the multiplication of the mass (m) and acceleration (a) according to Newton's 2nd law of motion.
F = ma
And, a = F/m
The mass and acceleration have an inverse relationship.
Given, the net force acting on an object, F = 1 N
The object is accelerating at a rate, a = 5.0 m/s²
The mass of the object can be determined by using the given information as follows:
m = F/a
m = 1/ 5.0
m = 0.2 Kg
Therefore, the mass of the object is equal to 0.2 Kg.
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