Answer:
The direction of the field is defined by the direction of the force it would put on a positive charge. So if it tells you that the force on a positive charge will be in the same direction as the field, but the force on a negative charge will be in the opposite direction.
Answer: F= qE
Explanation:
The electric field from a positive charge points away from the charge; the electric field from a negative charge points toward the charge. Like the electric force, the electric field E is a vector. F= qE If q is positive, the force is in the same direction as the field; if q is negative, the force is in the opposite direction as the field.
Which force keeps an object moving in a circle? centripetal force fluid friction inertia momentum
Answer:
Any object moving in a circle (or along a circular path) experiences a centripetal force. That is, there is some physical force pushing or pulling the object towards the center of the circle. This is the centripetal force requirement.
Explanation:
A physics student throws a ball straight up. The student catches the ball in exactly the same place from which it was released. The ball’s time of flight is T, and its maximum height above its release point is H. Neglect air resistance and assume up is the positive direction. Find the ball’s average velocity during the second half of its trip. (Hint: Your answer should only have the variables H and T in it.)
Answer:
The correct answer is H ÷ ¹/₂T
Explanation:
The formula for velocity is distance covered ÷ time.
Neglecting air resistance;
If the ball's time of overall time flight is T, the time it will take for the second half/return trip is ¹/₂T.
If the ball's maximum height above its released point is H, the height will also be the distance it covered for the second part of the trip since the student caught the ball in the exact same place the ball was thrown. Hence, the distance for the second half of the trip will be H.
Since velocity = distance/time
The average velocity during the second half of the trip will be = H ÷ ¹/₂T
If the length of a fixed cross-sectional area wire were increased, the resistance of the wire would: A. decrease. B. increase. C. remain the same.
If the length of a fixed cross-sectional area wire were increased, the resistance of the wire would the resistance of the wire also increases.
The correct answer is option B
If the length of a fixed cross-sectional area wire is increased, the resistance of the wire would increase. This relationship is governed by Ohm's law, which states that the resistance (R) of a wire is directly proportional to its length (L) and inversely proportional to its cross-sectional area (A).
Mathematically, resistance can be expressed as R = ρ * (L / A), where ρ is the resistivity of the material.
When the length of the wire is increased while keeping the cross-sectional area constant, the numerator in the equation (L) increases, resulting in a larger value for resistance. This means that the wire offers greater opposition to the flow of electric current.
The relationship between resistance and length can be intuitively understood by considering that a longer wire provides a longer path for the electrons to travel, resulting in more collisions with the wire's atoms or molecules, thus increasing resistance.
The resistance of a a wire with fixed length would increase if the cross-sectional area is increased.
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Sometimes scientists gather information that contradicts accepted theories or explanations. if the new information is replicated many times, the accepted theory that it contradicts will often be updated or modified to reflect the new information. based on this, it can be determined that scientific knowledge is durable in part because a. new information on accepted theories is never discovered. b. experiments are never performed more than once. c. scientists ignore information that contradicts accepted theories. d. it is open to change as new information is learned.
Scientists occasionally gather data that deviates from conventional ideas or interpretations. The widely held idea that the new information contradicts will frequently be revised or changed to take into account the new information if it is repeatedly verified.
Empirical evidence is the foundation of scientific knowledge. It is strong and lasting since it is the end product of all the prior study and testing that was done. But science also acknowledges that all of this information is a product of human endeavor and that it may contain numerous errors. Therefore, once a new idea is discovered and repeatedly confirmed, scientific knowledge is adaptable enough to take it into account and evolve.
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Why are chloroplasts found in plant cells but NOT in animal cells?
Answer:
Its is because plants dont get sugar from eating food so, they need chloroplast to make food with the help of sunlight.Whereas animal can get sugar from the food they eat.
A car with a velocity of 30 m/s accelerates uniformly at the rate of 2.0 m/s2 for 10 s. What is its final velocity?
HELPPPPPPPO
In the diagram, q1 = +6.60*10^-9 C and
q2 = +3.10*10^-9 C. Find the magnitude
of the total electric field at point P.
Explanation:
is this the full question?
Answer:
1258.46
Explanation:
Acellus
For this object, what color will you observe?
Answer:
blue
Explanation:
blue is the only color being reflected, meaning it's the only one that will be visible
In 2 - 3 sentences, explain the difference in Kinetic energy and Potential energy.
The main difference between Kinetic energy and Potential energy is that kinetic energy refers to movement while potential energy refers to storage.
What are Kinetic energy and Potential energy?Kinetic energy is a type of energy in motion or energy in movement such as a turbine (mechanical energy), while Potential energy refers to the energy that is stored to be used when required (e.g. chemical bonds of foods).
Therefore, with this data, we can see that Kinetic energy is used as movement, while Potential energy is stored to be used in the future.
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When a raceway is used for the support or protection of cables for fire alarm circuits, a bushing to reduce the potential for abrasion shall be placed at the location the cable emerge from the raceway.true or false?
True. When a raceway is used for the support or protection of cables for fire alarm circuits, a bushing to reduce the potential for abrasion shall be placed at the location the cable emerge from the raceway.
This is required by the National Electrical Code (NEC) to ensure the safety and reliability of the fire alarm system. The bushing helps to protect the cable from damage and abrasion that could cause a short circuit or other malfunction in the system.
It is important to follow all NEC requirements when installing fire alarm circuits to ensure the system operates as intended in the event of a fire.
When a raceway is used for the support or protection of cables for fire alarm circuits, a bushing should be placed at the location where the cable emerges from the raceway to reduce the potential for abrasion. This ensures cable integrity and proper functioning of the fire alarm system.
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Write down the method for the verification of Newton's second law of motion
We can verify the Newton's second law of motion mathematically by using the momentum impulse relation.
The rate of change of a body's momentum is directly proportional to the applied force and occurs in the direction in which the force operates, according to Newton's Second Law of Motion. where F is the applied force, M is the body's mass, and A is the resulting acceleration.
One way to state Newton's second law of motion is as follows:
Force is inversely correlated with change in momentum and time.
Now, F is directly proportional to mv-mu t or m(v-u) t [where (v-u) represents the acceleration, or change in velocity].
As a result, we discover that F is inversely proportional to m.
By using a constant k, this relationship F is directly proportional to ma can be transformed into an equation.
Thus, F=kma (where k is constant)
The preceding equation is now F=ma or Force= Mass*Acceleration because the value of k in SI units is 1.
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a moon orbits a planet with an elliptical orbit. at what point in the orbit is the kinetic energy of the moon the smallest?
In an elliptical orbit, the kinetic energy of an object is smallest at the point in the orbit where the object is at its farthest distance from the planet, also known as the apogee.
At this point, the object is moving the slowest and has the least kinetic energy. The gravitational potential energy of the object is at a maximum at this point, since the object is farthest from the planet and the gravitational pull is weakest. The total energy of the object remains constant as it moves along its elliptical orbit, but the distribution of energy between kinetic and potential energy changes as the object moves from perigee (the point of closest approach to the planet) to apogee and back.
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A ball is thrown up into the air with an initial velocity of 18 m/s. A) How high does the ball go? B) Calculate the time needed for the ball to reach its max height.
Answer:
B) t = 1.83 [s]
A) y = 16.51 [m]
Explanation:
To solve this problem we must use the following equation of kinematics.
\(v_{f} =v_{o} -g*t\)
where:
Vf = final velocity = 0
Vo = initial velocity = 18 [m/s]
g = gravity acceleration = 9.81 [m/s²]
t = time [s]
Note: the negative sign in the above equation means that the acceleration of gravity is acting in the opposite direction to the motion.
A) The maximum height is reached when the final velocity of the ball is zero.
0 = 18 - (9.81*t)
9.81*t = 18
t = 18/9.81
t = 1.83 [s], we found the answer for B.
Now using the following equation.
\(y = y_{o} + v_{o}*t - 0.5*g*t^{2}\\\)
where:
y = elevation [m]
Yo = initial elevation = 0
y = 18*(1.83) - 0.5*9.81*(1.83)²
y = 16.51 [m]
A 20.0g ball is attached to a 120cm long string and moves in a horizontal circle. The string exerts a force on the ball that is equal to 0.200N.
A resistor has a resistance of 120 12. How much current is in the resistor if there is a potential difference of 12.0V across the resistor?
A. 160 A
B. 0.43 A
C. 0.10 A
D. 2.3 A
Answer:
c 0.10
Explanation:
V=IR
12.0V=I x 120.12ohms
I=0.099
I= 0.10
18. a non-rotating frame of reference placed at the center of the sun is very nearly an inertial one. why is it not exactly an inertial frame?
A non-rotating frame of reference placed at the center of the sun is not exactly an inertial frame because of the influence of gravity.
Here, correct answer will be
This means that the frame of reference is not completely free from acceleration, and thus is not an inertial frame. The gravitational force of the sun also affects the motion of objects within the frame, as they will be pulled towards the sun in addition to the motion they already have.
This means that the motion of objects within the frame is not entirely predictable, as the gravitational force of the sun could affect the trajectory of objects within the frame. As such, the non-rotating frame of reference placed at the center of the sun is not an inertial frame.
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( ANSWER QUICK PLS NEED FAST ) What is the opposite force to pushing off the ground to jump?
A The ground pushing off your foot
B The ground pulling your foot down
C Gravity pulling your foot down
D Your leg pushing off your foot
ANSWER
A)
Explanation:
Due to normal force from ground
Answer:The ground pushing off your foot
Explanation:
If the thickness of an absorber is 1.5 cm and 36.45% of a beam is attenuated by the absorber, what is the half-value layer?
If the thickness of an absorber is 1.5 cm and 36.45% of a beam is attenuated by the absorber, The half-value layer is 0.51 cm.
The half-value layer (HVL) is a measure of the thickness of an absorber required to reduce the intensity of a beam to half its initial value. In this case, we are given that the absorber attenuates 36.45% of the beam.
To find the HVL, we can use the relationship between the percent attenuation and the thickness of the absorber. The HVL is the thickness at which the beam is attenuated to 50% or 0.5 of its initial intensity.
Since 36.45% of the beam is attenuated by the absorber, the remaining intensity is 100% - 36.45% = 63.55% or 0.6355 of the initial intensity.
We can set up the following equation:
0.5 = 0.6355^x
Solving for x, we find x ≈ 0.51.
Therefore, the half-value layer is approximately 0.51 cm, indicating that a thickness of 0.51 cm of the absorber is required to reduce the beam intensity to half its initial value.
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in order to measure the properties of a battery, several resistors are connected to the battery in series and the terminal voltage is measured. in the first case, the resistor has resistance r1
a)current through a battery I=ΔVJR b) emf of the battery using is e=I(r+R).
c) emf in terms of r. R and ΔV is e=ΔV/R(R+r).
Electricity, which is the flow of electrons, or current, over a wire, creates electric and magnetic fields, which are imperceptible zones of energy (also known as radiation).
Voltage is the force used to force the electrons through the wire, much like water is pushed through a pipe, creating an electric field. The electric field gets stronger as the voltage rises. Volts per metre (V/m) is a unit of measurement for electric fields. EMF, or electromagnetic fields, are the collective term for electric and magnetic fields. Radiation from electromagnetic sources produces the electric and magnetic forces found in EMFs. EMFs can be divided into two primary groups:
X-rays and gamma rays are examples of higher-frequency EMFs. These electromagnetic fields (EMFs) fall within the category of ionising radiation.
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If a motorcycle, a car, and a big rig are all moving with a velocity of 100 km/h, which vehicle has the greatest momentum? A motorcycle and rider. A small car. A large 18 wheeler truck.
Answer:
The big rig.
Explanation:
Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.
Mathematically, momentum is given by the formula;
\( Momentum = mass * velocity \)
In this scenario, a motorcycle, a car, and a big rig are all moving with a velocity of 100 km/h. Thus, the vehicle which has the greatest momentum is the big rig because its mass is intuitively or logically greater than that of the other vehicle.
Generally, momentum is directly proportional to the mass of a physical object or body.
Answer: A large 18 wheeler truck.
Explanation: Momentum is the measure of the motion of an object found by multiplying the object’s mass and velocity. Momentum is directly proportional to the object's mass and also its velocity. So, the greater an object's mass or the greater its velocity, the greater its momentum. Therefore, since the truck is bigger, it has the greatest mass. This means that the truck the greatest momentum. Correct on Edg 2020.
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After performing a long equation using the conservation of mechanical energy you get a final answer that is negative. What does this mean?
A. Because energy is scalar it means that the energy is less than 0.
B. Because energy is scalar it means that the energy was transferred somewhere else.
C. Because energy is a vector it means that the energy was destroyed in the opposite direction.
D. Because energy is scalar it means that the energy was destroyed.
Answer:
The correct option is D.
Explanation:
The energy is the capacity to do work.
There are several types of energies.
1. kinetic energy : it is due to the motion of the body.
2. Potential energy : It is due to the position or the configuration of the body.
3. Mechanical energy: The sum of the kinetic energy and the potential energy is called mechanical energy.
The energy is a scalar quantity.
According to the law of conservation of energy, the energy can not be created and cannot be destroyed, it can transformed from one form to another.
When we get the mechanical energy negative, it means the energy was destroyed in some other forms of energy.
A bowling ball is dropped off of the side of a building. Ignore the effects of air resistance. As the ball continues to fall freely, the kinetic energy of the ball.
The ball continues to fall, its kinetic energy will increase.
What is kinetic energy?Kinetic energy is the energy an object possesses due to its motion. It is the energy associated with an object’s speed and mass, and is the energy that an object has because of its movement. Kinetic energy can be converted into other forms of energy, such as heat, light, or sound. It can also be used to do work, such as moving objects or powering machines. Kinetic energy is a form of mechanical energy, which is energy that is associated with the motion or position of an object. Kinetic energy is related to the work done on an object, and it increases as the object’s speed increases. Kinetic energy can be calculated using the formula KE = ½mv2, where m is the mass of the object and v is the velocity of the object.
The kinetic energy of the ball will increase as it falls, because it is gaining speed due to gravity.
As it falls, it accelerates at a rate of 9.8 m/s^2, and its kinetic energy is equal to its mass multiplied by the square of its velocity.
Therefore, as the ball continues to fall, its kinetic energy will increase.
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How do astronomers measure the mass that the galaxy contains inside the orbit of the sun?.
The degree mass of many different spiral galaxies close by after which takes a median. They add up all the observations at 21-cm wavelengths because the mass of hydrogen gas is some distance greater than the mass in all of the stars.
Astronomers have four simple techniques to degree the hundreds of galaxies and clusters: rotation curves, random velocities, X-ray emission, and gravitational lensing. Rotation curves: In astronomy, we often infer loads from orbits.
Because it's impossible to weigh a galaxy virtually by way of searching at it tons less when the observer occurs to be inner of it, as is the case with our Milky way researchers deduce a galaxy's mass by means of analyzing the motions of celestial gadgets as they dance across the host galaxy, led by using its gravitational pull.
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Three beads are placed along a thin rod. The first bead, of mass m1 = 27 g, is placed a distance d1 = 1. 3 cm from the left end of the rod. The second bead, of mass m2 = 14 g, is placed a distance d2 = 1. 9 cm to the right of the first bead. The third bead, of mass m3 = 49 g, is placed a distance d3 = 3. 1 cm to the right of the second bead. Assume an x-axis that points to the right. A) write a symbolic equation for the location of the center of mass of the three beads relative to the left end of the rod, in terms of the variables given in the problem statement.
B) find the center of mass in centimeters relative to the left end of the rod
C) write a symbolic equation for the location of the center of mass of the three beads relative to the center bead in terms of the variables given in the statement problem
D) find the center of mass in centimeters relative to the middle bead
A. Symbolic equation for the location of the center of mass of the three beads relative to the left end of the rodIn order to find the center of mass, we need to use the formula:
\((M1x1 + M2x2 + M3x3) / M\\where\\M \\ =\\ m1 + m2 + m3M1 = m1M2 = \\m2M3 = m3x1 \\= d1x2 = d1 + d2x3 = d1 + d2 + d3\\\\Now, we have\\\\M1x1 + M2x2 + M3x3 = 27 × 0.013 + 14 × 0.032 + 49 × 0.062 \\= 0.1310M \\= m1 + m2 + m3 \\= 27 + 14 + 49 = 90\)
The location of the center of mass is given
\(asx = (M1x1 + M2x2 + M3x3) / M = 0.1310 / 90= 0.00146 cmB.\)
Find the center of mass in centimeters relative to the left end of the rodThe center of mass is located at a distance of 0.00146 cm relative to the left end of the rod.C. Symbolic equation for the location of the center of mass of the three beads relative to the center beadWe need to find the distance between the center bead and the center of mass.Let d = distance between center bead and the center of mass.
Find the center of mass in centimeters relative to the middle beadFrom the above equation in part C, we know
\(x2 + d = 0.1304\)
Let's calculate the distance between center bead and the center of mass,
\(d = x - x2 = 0.00146 cm\)
Now, we can find the center of mass in centimeters relative to the middle bead asx - x2 = 0.00146 cmThe center of mass is 0.00146 cm away from the middle bead.
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nilai x
Hitung
3^x2 x 3^5x
= 3^24
Answer:
x = - 8 atau 3
Explanation:
3ˣ² × 3⁵ˣ = 3²⁴
Penarikan:
Mᵃ × Mᵇ = Mᵃ⁺ᵇ
3ˣ² × 3⁵ˣ = 3ˣ²⁺⁵ˣ
Karena itu
3ˣ² × 3⁵ˣ = 3²⁴
3ˣ²⁺⁵ˣ = 3²⁴
x² + 5x = 24
Mengatur kembali
x² + 5x - 24 = 0
Pemecahan dengan faktorisasi
x² - 3x + 8x - 24 = 0
x (x - 3) + 8 (x - 3) = 0
(x + 8) (x - 3) = 0
x + 8 = 0 atau x - 3 = 0
x = - 8 atau x = 3
Karena itu,
x = - 8 atau 3
A chipmunk scampers about collecting in its checks safflower seeds that the birds dropped from the feeder hanging overhead. Initially, the little creature is at position vector r
1x
=3.49 m and r
1y
=−2.21 m. After filling up, it runs to the hole at position vector r
2x
=−1.23 m and r
2y
=4.27 m that leads to its underground nest. Find component Δr
x
of the chipmunk's displacement vector for this expedition. Δr
x
= Find component Δr
y
of the chipmunk's displacement vector for this expedition. Δr
y
= m
The component Δrₓ of the chipmunk's displacement vector is approximately -4.72 m, and the component Δrᵧ is approximately 6.48 m.
To find the components Δrₓ and Δrᵧ of the chipmunk's displacement vector, we need to calculate the change in position along the x-axis and y-axis, respectively.
The change in position (Δr) can be calculated by subtracting the initial position vector (r₁) from the final position vector (r₂):
Δr = r₂ - r₁
Given:
Initial position vector r₁ = (3.49 m, -2.21 m)
Final position vector r₂ = (-1.23 m, 4.27 m)
Δrₓ = r₂ₓ - r₁ₓ
Δrᵧ = r₂ᵧ - r₁ᵧ
Substituting the values:
Δrₓ = (-1.23 m) - (3.49 m)
Δrᵧ = (4.27 m) - (-2.21 m)
Calculating:
Δrₓ = -1.23 m - 3.49 m
Δrₓ = -4.72 m
Δrᵧ = 4.27 m + 2.21 m
Δrᵧ = 6.48 m
Therefore, the component Δrₓ of the chipmunk's displacement vector is approximately -4.72 m, and the component Δrᵧ is approximately 6.48 m.
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Inside most ball-point pens is a small spring that compresses as the pen is pressed against the paper. If a force of 0.1 N compresses the pen's spring a distance of 0.005 m, what is the spring constant of the tiny spring?
Answer:
20 N/m
Explanation:
From the question,
The ball-point pen obays hook's law.
From hook's law,
F = ke............................ Equation 1
Where F = Force, k = spring constant, e = compression.
Make k the subject of the equation
k = F/e........................ Equation 2
Given: F = 0.1 N, e = 0.005 m.
Substitute these values into equation 2
k = 0.1/0.005
k = 20 N/m.
Hence the spring constant of the tiny spring is 20 N/m
To predict whether a star will ultimately become a black hole, what is the key property of the star we should look at?.
A star will ultimately become a black hole when it collapses due to end of fuel.
Which star becomes a black hole?When a star burns through the last of its fuel, the object may collapse, or fall into itself. For smaller stars which are about three times the sun's mass, the new core will become a white dwarf but when a larger star collapses, it turns into a black hole.
So we can can conclude that a star will ultimately become a black hole when it collapses due to end of fuel.
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If the input force on the
chopsticks from the hand is 3 N, what is the output
force on the piece of food the chopsticks pick up?
The output force on the piece of food the chopsticks pick up is mechanical advantage times 3 N.
What is mechanical advantage?The force amplified by utilising a tool, mechanical device, or machine system is known as mechanical advantage. To achieve the desired output force amplification, the gadget trades off input forces against movement.
Mathematically:
mechanical advantage = output force/input force
Given that input force = 3 N.
Hence, output force = mechanical advantage × 3 N.
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Why are we unable to measure parallax shifts for most of the stars in the galaxy?
We are unable to measure parallax shifts for most stars in the galaxy because of two main reasons: the vast distances involved and the limitations of our measurement techniques.
Firstly, the distances to stars in the galaxy are incredibly large, ranging from a few light-years to thousands of light-years. Parallax is the apparent shift in a star's position when observed from different points in Earth's orbit. However, this shift becomes smaller as the distance to the star increases. For most stars, this parallax shift is too small to measure accurately with our current technology.
Secondly, our measurement techniques have inherent limitations. Even with advanced telescopes, there are practical constraints to measuring extremely small angles accurately. Atmospheric turbulence, instrumental errors, and the precision of our instruments all contribute to the challenges of measuring parallax shifts for distant stars.However, astronomers have developed alternative methods, such as spectroscopic parallax and the use of standard candles, to estimate distances to these stars indirectly. These methods rely on other observable properties of stars, such as their luminosity or spectral characteristics, to infer their distances.
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