To find the number when 28 is the geometric mean of 13 and that number, we'll use the formula for the geometric mean: √(a * b) = GM, where a and b are the two numbers, and GM is the geometric mean. In this case, a = 13, GM = 28.
Step 1: Substitute the given values into the formula:
√(13 * b) = 28
Step 2: Square both sides to get rid of the square root:
(√(13 * b))^2 = 28^2
13 * b = 784
Step 3: Divide both sides by 13 to isolate b:
b = 784 / 13
b ≈ 60.31
So, the other number is approximately 60.31 when rounded to the nearest hundredth. In summary, 28 is the geometric mean of 13 and 60.31, as √(13 * 60.31) ≈ 28.
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Two parachutists jump at the same time from two different planes as part of an aerial show. The height h1of the first parachutist in feet after t seconds is modeled by the function h1 = -16t2 + 5000. The height h2 of the second parachutist in feet after t seconds is modeled by the function h2 = -16t2 + 4000.
a. What is the parent function of the two functions given? b. Describe the transformations needed to obtain the graph of h1 from the parent
function.
c. Which parachutist will reach the ground first?
a. The parent function of the two given functions is h(t) = -16t².
b. To obtain the graph of h1 from the parent function, we need to vertically shift it upwards by 5000 units since the maximum height reached by the first parachutist is 5000 feet.
c. The second parachutist will reach the ground first.
The parent function of the two given functions is h(t) = -16t². This function represents the height of an object in free fall without considering initial velocity or air resistance. The coefficient -16 represents the acceleration due to gravity, and t² represents the square of time.
To obtain the graph of h1 from the parent function, we need to apply a vertical transformation. The function h1 = -16t²+ 5000 represents the height of the first parachutist. By adding 5000 to the parent function, we shift the graph upward by 5000 units. This shift accounts for the initial height from which the first parachutist jumps, which is 5000 feet.
c. To determine which parachutist will reach the ground first, we need to find the time when each of their heights is equal to zero. For the first parachutist, we set h1 = 0 and solve for t:
-16t² + 5000 = 0
t² = 312.5
t = ±17.68 seconds
Since time cannot be negative, we take the positive solution and find that the first parachutist will reach the ground after approximately 17.68 seconds.
For the second parachutist, we set h2 = 0 and solve for t:
-16t² + 4000 = 0
t² = 250
t = ±15.81 seconds
Again, taking the positive solution, we find that the second parachutist will reach the ground after approximately 15.81 seconds.
Therefore, the second parachutist will reach the ground first.
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What is the additive inverse of the elevation 21.9
Answer: In mathematics, the additive inverse of a number is the number that, when added to the original number, results in zero.
Step-by-step explanation: The additive inverse of 21.9 can be found by simply negating the value, which means changing the sign from positive to negative, or vice versa. Therefore, the additive inverse of 21.9 is -21.9, because 21.9 + (-21.9) = 0.
is 1.27 a irrational number or rational number
Rational
Step-by-step explanation:
Show that repeating decimal 1.27 is a rational number
Answer:
I believe it is a rational number.
Listed below are the budgets (in millions of dollars) and the gross receipts (in millions of dollars) for randomly selected movies. Construct a scatterplot, find the value of the linear correlation coefficient r, and find the P-value using alphaequals0.05. Is there sufficient evidence to conclude that there is a linear correlation between budgets and gross receipts? Do the results change if the actual budgets listed are $65 comma 000 comma 000, $89 comma 000 comma 000, $51 comma 000 comma 000, and so on? Budget (x) 65 89 51 35 204 98 85
The data Given is incomplete, question with exactly similar data could not be found. However, similar questions with different data are numerous. Using one of this questions to take you through the solution to your question :
.
Question :
Listed below are the budgets (in millions of dollars) and the gross receipts (in millions of dollars) for randomly selected movies. Construct a scatterplot, find the value of the linear correlation coefficient r, and find the P-value using alpha = 0.05. Is there sufficient evidence to conclude that there is a linear correlation between budgets and gross receipts? Do the results change if the actual budgets listed are $61,000,000, $92,000,000, $48,000,000, and so onBudget(x) 61 92 48 36 135 58 93Gross(y) 69 62 53 58 627 144 42
a. What are the null and alternative hypotheses?i) H_0: rho = 0, H_1: rho < 0
ii) H_0: rho = 0, H_1: rho notequalto 0
iii) H_0: rho notequalto 0, H_1: rho = 0
iv) H_0: rho = 0, H_1: rho > 0
b. Construct a scatterplot. Choose the correct graph below.
c. The linear correlation coefficient r is.
d. The test statistic t is.
e. The P-value is.
Answer:
Pvalue > α ; Hence, we fail to reject the null.
Step-by-step explanation:
When testing for correlation :
Correlation Coefficient r is always between - 1 and 1. The alternative is always the opposite of the null. To claim that correlation exists, the r will not be equal to 0, because 0 means no correlation.
1.)
H_0: rho = 0,
H_1: rho notequalto 0
2.)
Given the data :
Budget(x) : 61 92 48 36 135 58 93
Gross(y) : 69 62 53 58 627 144 42
Scatter plot is attached below
3.) The linear correlation Coefficient as obtained using technology is 0.751 ; which depicts a strong positive correlation
4.)
Test statistic :
T = r / √(1 - r²) / (n - 2)
r² = 0.751² = 0.564
T = 0. 751 / √(1 - 0.564) / (7 - 2)
T = 0.751 / 0.2952964
T = 2.543
E.)
Using the Value from Tscore calculator :
Pvalue(2.543, 5) ; two tailed
Pvalue = 0.0517
At α = 0.05;
Pvalue > α ; Hence, we fail to reject the null. there is no sufficient evidence to conclude that there is a linear correlation between budgets and gross receipts.
What are the coordinates of the midpoint A(5, 8) and B(-1, -4)
Answer:
(2, 2)Step-by-step explanation:
Given points
A(5, 8) and B(-1, -4)Midpoint formula
x = (x1+x2)/2 = (5 - 1)/2 = 2y = (y1 + y2)/2 = (8 - 4)/2 = 2Midpoint is (2, 2)
A researcher wants to set up a regression equation where Y is a function X. Evaluate the researcher’s options given the following scenarios: (3)
i. Y is I(0); X is I(0)
ii. Y is I(2); X is I(0)
iii. Y is I(1); X is I(1); and the error term is I(0).
The appropriate regression model depends on the stationarity properties of both the dependent and independent variables, as well as the error term. The researcher can use a standard OLS regression model with first-order differencing of both Y and X.
In the first scenario, both Y and X are I(0), which means they are stationary time series. In this case, the researcher can perform a standard linear regression analysis, as the stationary series would lead to a stable long-run relationship. The answer from this model will be reliable and less likely to suffer from spurious regressions. In the second scenario, Y is I(2) and X is I(0). This implies that Y is integrated of order 2 and X is stationary. In this case, the researcher should first difference Y twice to make it stationary before performing a regression analysis. However, this approach might not be ideal as the integration orders differ, which can lead to biased results.
In the third scenario, Y and X are both I(1) and the error term is I(0). This indicates that both Y and X are non-stationary time series, but their combination might be stationary. The researcher should employ a co-integration analysis, such as the Engle-Granger method or Johansen test, to identify if there is a stable long-run relationship between Y and X. If co-integration is found, then an error correction model can be used for more accurate predictions.
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When using different data algorithms, why is it fundamentally important to understand why they are being used?
When one is using different algorithms it is important to know why they are being used because
It can help to write perfect codesIt can help in enhancing data accuracyIt can reduce the coding cost What is meant by algorithm?This is the term that is used to refer to the set of rules which are followed especially when it comes to making computations or solving other problems that are computer based.
They help in the following ways. When one is using different algorithms it is important to know why they are being used because
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If log, yé, then evaluate the expression when I = 5 Show all steps.
Y = 25
=4
Z =
Find the area of each figure. Round your answer to 2 decimal places if required.
(Use π = 3.14)
The values areas are:
Figure 1 = 69.81 in²
Figure 2 = 192.50 ft²
Figure 3 = 153.50 yd²
Figure 4 = 296.00 in²
Figure 5 = 126.00 ft²
Figure 6 = 26.30 ft²
Area of Compound ShapesThis exercise requires your knowledge about the area of compound shapes. For solving this, you should:
Identify the basic shapes;Calculate your individual areas;Sum each area found.The steps and solutions for each given figure are presented below.
STEP 1 - Calculate the area for the figure 1The figure 1 is composed by a rectangle and a semicircle. Therefore, you should sum the area of these geometric figures.
Area of rectangle - \(A_{rectangle}=l.w\), where:
l= length (12 in)and w=width (5 in).
\(A_{rectangle}=l.w=12*5=60 in^{2}\)
Area of semicircle- \(A_{semicircle}=\frac{Area circle}{2}=\frac{\pi*r^{2} }{2}\), where:
r= radius ( \(\frac{w}{2} =\frac{5}{2} =2.5\)) and π = 3.14
\(A_{semicircle}=\frac{Area circle}{2}=\frac{\pi*2.5^{2} }{2}=9.81 in^{2}\)
Therefore, \(A_{fig1}= 60 + 9.81=69.81 in^{2}\).
STEP 2 - Calculate the area for the figure 2The figure 2 is composed by a parallelogram and a trapezoid. Therefore, you should sum the area of these geometric figures.
Area of parallelogram - \(A_{parallelogram}=b.h\), where:
b= length of the base (11 ft)and h=height (7 ft).
\(A_{parallelogram}=b.h=11*7=77ft^{2}\)
Area of trapezoid - \(A_{trapezoid}=\frac{(a+b)*h}{2}\), where:
a= long base (20-7=13 ft ), b = short base (8 ft) and height (11 ft)
\(A_{trapezoid}=\frac{(a+b)*h}{2}=\frac{(13+8)*11}{2}=\frac{21*11}{2}=\frac{231}{2}=115.50\)
Therefore, \(A_{fig2}= 77+ 115.5=192.50 ft^{2}\).
STEP 3 - Calculate the area for the figure 3The figure 3 is composed by a triangle and a trapezoid. Therefore, you should sum the area of these geometric figures.
Area of triangle - \(A_{triangle}=\frac{b*h}{2}\), where:
b= length of the base (19 yd) and h=height (7 yd).
\(A_{triangle}=\frac{b*h}{2} =\frac{19*7}{2} =\frac{133}{2}= 66.5 yd^{2}\)
Area of trapezoid - \(A_{trapezoid}=\frac{(a+b)*h}{2}\), where:
a= long base (19 yd ), b = short base (10 yd) and height (13-7=6 yd)
\(A_{trapezoid}=\frac{(a+b)*h}{2}=\frac{(19+10)*6}{2}=\frac{29*6}{2}=29*3=87 yd^2\)
Therefore, \(A_{fig3}= 66.5+ 87=153.50 yd^{2}\).
STEP 4 - Calculate the area for the figure 4The figure 4 is composed by two rectangles. Therefore, you should sum the area of these geometric figures.
Area of rectangle 1 - \(A_{rectangle}=l.w\), where:
l= length (16+5=21 in)and w=width (8 in).
\(A_{rectangle}=l.w=21 *8=168 in^{2}\)
Area of rectangle 2 - \(A_{rectangle}=l.w\), where:
l= length (16 in)and w=width (5 in).
\(A_{rectangle}=l.w=16*8=128 in^{2}\)
Therefore, \(A_{fig4}= 168+ 128=296.00 in^{2}\).
STEP 5 - Calculate the area for the figure 5The figure 5 is composed by a square and a parallelogram. Therefore, you should sum the area of these geometric figures.
Area of square - \(A_{square}=l^2\), where:
l= length (9 ft).
\(A_{square}=l^{2}=9^2=81 ft^{2}\)
Area of parallelogram - \(A_{parallelogram}=b.h\), where:
b= length of the base (9 ft)and h=height (14-9=5 ft).
\(A_{parallelogram}=b.h=9*5=45ft^{2}\)
Therefore, \(A_{fig5}= 81+ 45=126.00 ft^{2}\)
STEP 6 - Calculate the area for the figure 6The figure 5 is composed by a triangle and a semicircle. Therefore, you should sum the area of these geometric figures.
Area of triangle - \(A_{triangle}=\frac{b*h}{2}\), where:
b= length of the base (6 yd) and h=height (4 yd).
\(A_{triangle}=\frac{b*h}{2} =\frac{6*4}{2} =\frac{24}{2}= 12 yd^{2}\)
Area of semicircle- \(A_{semicircle}=\frac{Area circle}{2}=\frac{\pi*r^{2} }{2}\), where:
r= radius ( \(\frac{6}{2} =3\)) and π = 3.14
\(A_{semicircle}=\frac{Area circle}{2}=\frac{\pi*3^{2} }{2}=14.3 yd^{2}\)
Therefore, \(A_{fig6}= 12+ 14.3=26.3 yd^{2}\)
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To find out the y-intercept of the line that is
parallel to y = 0.5x - 2, what should you do?
Since the parallel line goes through the point (3,
0) substitute 3 for x and 0 for y and solve for b,
the y-intercept.
You cannot solve it because you do not know
what x and y are for the parallel line.
Since the parallel line goes through the point (3,
0) substitute 0 for x and 3 for y and solve for b,
the y-intercept.
You cannot solve it because you do not know what x and y are for the parallel line. which is the correct answer would be option (B).
We have to find out the y-intercept of the line that is parallel to y = 0.5x - 2,
As per the given options,
Since the parallel line goes through point (3, 0) substitute 3 for x and 0 for y and solves for b, the y-intercept.
This is not the correct answer.
You cannot solve it because you do not know what x and y are for the parallel line.
This is the correct answer.
Since the parallel line goes through the point (3, 0) substitute 0 for x and 3 for y and solve for b, the y-intercept.
This is not the correct answer.
Therefore, You can't solve it since you don't know what the parallel line's x and y coordinates are.
Hence, the correct answer would be option (B).
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In a survey of 2276 adults, 746 say they believe in UFOs.
Construct a 99% confidence interval for the population proportion of adults who believe in UFOs.
Explanatory Answer:
To construct a confidence interval for the population proportion of adults who believe in UFOs, we can use the following formula:
CI = p ± zsqrt(p(1-p)/n)
where:
CI is the confidence interval
p is the sample proportion
z* is the critical value from the standard normal distribution for the desired confidence level
n is the sample size
In this case, the sample proportion is p = 746/2276 = 0.3275. The sample size is n = 2276.
To find the critical value z* for a 99% confidence level, we can look up the value in a standard normal distribution table or use a calculator. The critical value for a 99% confidence level is approximately 2.576.
Substituting these values into the formula, we get:
CI = 0.3275 ± 2.576sqrt(0.3275(1-0.3275)/2276)
Simplifying the expression inside the square root, we get:
CI = 0.3275 ± 0.0225
Therefore, the 99% confidence interval for the population proportion of adults who believe in UFOs is:
CI = (0.305, 0.350)
This means that we are 99% confident that the true proportion of adults who believe in UFOs is between 0.305 and 0.350.
what are the minors of this matrix?
The minors of the given matrix are:
6 -24 60
-93 0 -93
6 10 -27
We have,
To find the minors of a matrix, we calculate the determinants of each of the 2x2 submatrices formed by removing one row and one column from the original matrix.
Given the matrix:
-5 8 5
4 -1 0
6 9 -6
Let's calculate the minors:
- For the element in the first row, the first column (-5):
Remove the first row and first column to obtain the submatrix:
-1 0
9 -6
The determinant of this 2x2 submatrix is (-1 x -6) - (0 x 9) = 6.
Therefore, the minor for the element -5 is 6.
- For the element in the first row, second column (8):
Remove the first row and second column to obtain the submatrix:
4 0
6 -6
The determinant of this 2x2 submatrix is (4 x -6) - (0 x 6) = -24.
Therefore, the minor for the element 8 is -24.
- For the element in the first row, third column (5):
Remove the first row and third column to obtain the submatrix:
4 -1
6 9
The determinant of this 2x2 submatrix is (4 x 9) - (-1 x 6) = 54 + 6 = 60.
Therefore, the minor for the element 5 is 60.
- For the element in the second row, first column (4):
Remove the second row and first column to obtain the submatrix:
8 5
9 -6
The determinant of this 2x2 submatrix is (8 x -6) - (5 x 9) = -48 - 45 = -93.
Therefore, the minor for the element 4 is -93.
- For the element in the second row, second column (-1):
Remove the second row and second column to obtain the submatrix:
-5 5
6 -6
The determinant of this 2x2 submatrix is (-5 x -6) - (5 x 6) = 30 - 30 = 0.
Therefore, the minor for the element -1 is 0.
- For the element in the second row, third column (0):
Remove the second row and third column to obtain the submatrix:
-5 8
6 9
The determinant of this 2x2 submatrix is (-5 x 9) - (8 x 6) = -45 - 48 = -93.
Therefore, the minor for the element 0 is -93.
- For the element in the third row, first column (6):
Remove the third row and first column to obtain the submatrix:
-1 0
9 -6
The determinant of this 2x2 submatrix is (-1 x -6) - (0 x 9) = 6.
Therefore, the minor for the element 6 is 6.
- For the element in the third row, second column (9):
Remove the third row and second column to obtain the submatrix:
-5 5
4 -6
The determinant of this 2x2 submatrix is (-5 x -6) - (5 x 4) = 30 - 20 =
Therefore, the minor for the element 9 is 10.
- For the element in the third row, third column (-6):
Remove the third row and third column to obtain the submatrix:
-5 8
4 -1
The determinant of this 2x2 submatrix is (-5 x -1) - (8 x 4) = 5 - 32 = -27.
Therefore, the minor for the element -6 is -27.
Thus,
The minors of the given matrix are:
6 -24 60
-93 0 -93
6 10 -27
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A can do 1/3 of a work in 5 days and B can do 2/5 of the work in 10 days. In how many days can both A and B together do the work?.
Answer:
9.375 days
Step-by-step explanation:
Let d be the number of days the do 1 work(job). The speed A can do the job is (1/3)/(5)=1/3 × 1/5=1/15. The speed B can do the job is (2/5)/(10)=2/5 × 1/10=2/50=1/25. (These speeds have units work per 1 day)
So the amount of work done in d days for A is 1/15×d=d/15 and that same amount of days B does 1/25×d=d/25 work.
We are trying to figure out when they ddo 1 work together.
We need to solve
d/15+d/25=1
Multiply both sides by 75=least common multiple of 15 and 25.
75d/15+75d/25=75
Reducing:
5d+3d=75
Combine like terms:
8d=75
Divide both sides by 8:
d=75/8
d=9.375
A(n) ______ line is a line that relates points on the line with numbers.
Answer:
A number line is a line that relates points on line with numbers :)
The Number line is a line that relates points on the line with numbers.
What is Number line?Number line is a horizontal line where numbers are marked at equal intervals one after another form smaller to greater.
We have to given that;
A line that relates points on the line with numbers.
Now,
We know that;
Number line is a line where numbers are marked at equal intervals one after another form smaller to greater.
Hence, Number line is a line that relates points on the line with numbers.
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Convert 1 000 mcg to mg
1,000 mcg (micrograms) is equal to 1 mg (milligram).
Micrograms (mcg) and milligrams (mg) are both units of measurement for mass (weight) in the metric system. The prefix "micro" means one millionth, so one microgram is equal to one millionth of a gram.
A milligram is one thousandth of a gram. To convert mcg to mg, divide the number of mcg by 1,000. So, 1,000 mcg / 1,000 = 1 mg. This means that there are 1,000 mcg in 1 mg. It is important to note that 1mg is 1000 times larger than 1mcg.
This conversion is simple but it is important to be careful when measuring medication and dosage to avoid errors and ensure safety, always consult with a doctor or pharmacist.
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WILL MARK BRAINLIEST
Answer:
1 sample
Step-by-step explanation:
There is only one sample given for 20%
Answer:
the answer would be
b) 1 sample
In the figure, ABC is mapped onto XYZ by a 180° rotation. Angle B corresponds to which angle in XYZ?
Answer:
x
Step-by-step explanation:
the altitude a (in feet) of a plane t minutes after liftoff is given by a =1200t+60. how many minutes after liftoff is the plane at an altitude of 27000 ft
Answer:
21,000-600 = 20,400
20,400/3400 = 6
t = 6
21,000=3,400(6)+600
21,000=20,400+600
21,000=21,000
34.00
*6
__
204.00
3,400*6=20,400
Step-by-step explanation:
pls brainlies
Answer:
We are going to solve for t if a is 27,000 (ft).
27000-60=1200t + 60-60
26,940=1200t
Divide each side by 1200
22.45=t (minutes)
Together donkey and Shrek can make 7 cupcakes in 12 mins. Shrek can make 2 cupcakes in 8 mins. How long will it take Donkey to make 3 cupcakes
1. What plane is parallel to plane HGK?*
plane ABG
plane EFK
plane BAD
plane BCH
I need help...thanks !
Answer:
The answer should be BAD
Step-by-step explanation:
They are all parallel from each other and will never touch
PLEASE HELP LOL
What is the missing perfect square?
25, 36, 49, _____, 81, 100
A)50
B)58
C)60
D) 64
Answer:
The answer is D. 64 because after 49 it is 64 (8*8=64 and 7*7=49)
Step-by-step explanation:
Answer:
64
Step-by-step explanation:
Find the slope of the line through the points (-2,5) and (-6,-3)
Answer:
slope = 2
Step-by-step explanation:
Calculate the slope m using the slope formula
m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)
with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (- 6, - 3)
m = \(\frac{-3-5}{-6+2}\) = \(\frac{-8}{-4}\) = 2
washington high school's head tennis coach, ms. racket, runs a tennis camp for middle school students every summer. the students bring their own lunches, but ms. racket provides them with snacks.there is a proportional relationship between the number of students who enroll in ms. racket's tennis camp, x, and the total number of snacks she buys, y.what is the constant of proportionality? write your answer as a whole number or decimal.snacks per student
The constant of proportionality is comes out to be 3.
What is constant of proportionality?When two variables are proportional to one another, their relationship can be expressed as y = kx or y = k/x, where k defines how the 2 factors are related to one another. The above k is recognized as the proportionality constant.
The proportionality constant is the constant value of the ratio of two proportional quantities. When the ratio or product of two varying quantities yields a constant, they are said to be in a proportional relationship. The proportionality constant's value is determined by the type of proportion between both the two given quantities: direct variation or inverse variation.Now according to the question.
The proportionality constant denotes the ratio of the words x and y.
It is found by dividing Δy by Δx.
Δy/Δx = (y₂ - y₁)/(x₂ - x₁)
Consider two values from the table;
y₂ = 39 ; x₂ = 13
y₁ = 30 ; x₁ = 10
Substituting the values in the formula;
Δy/Δx = (39 - 30)/(13 - 10)
Δy/Δx = 9/3
Δy/Δx = 3
Therefore, the value of constant of proportionality is 3.
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The complete question is -
Washington high school's head tennis coach, Ms. racket, runs a tennis camp for middle school students every summer. the students bring their own lunches, but Ms. racket provides them with snacks. there is a proportional relationship between the number of students who enroll in Ms. racket's tennis camp, x, and the total number of snacks she buys, y. what is the constant of proportionality? write your answer as a whole number or decimal. snacks per student.
X Y
10 30
13 39
14 42
21 63
List the sample space for rolling a fair eight-sided die.
S = {1}
S = {8}
S = {1, 2, 3, 4, 5, 6}
S = {1, 2, 3, 4, 5, 6, 7, 8}
The sample space for rolling a fair eight-sided die is {1, 2, 3, 4, 5, 6, 7, 8}.
We have to find the sample space for rolling a fair eight-sided die.
The sample space for rolling a fair eight-sided die consists of all the possible outcomes of a single roll of the die.
As the die has eight sides numbered from 1 to 8, the sample space can be represented as:
S = {1, 2, 3, 4, 5, 6, 7, 8}
Therefore, the sample space for rolling a fair eight-sided die is {1, 2, 3, 4, 5, 6, 7, 8}.
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A. A plant treats an ore containing Pyrite (FeS2), Arsenopyrite (FeAss) and chalcopyrite (CuFeS2). After ore upgrading and analysis, the Arsenic (As), Copper (Cu) and Iron (Fe) concentration in the concentrate were 9.6%, 13.5% and 63.3% respectively. What is the concentration of pyrite, arsenopyrite, chalcopyrite in the concentrate? (Molar masses of As, Cu, Fe and Sare 74.92 g/mol, 63.55 g/mol, 55.85 g/mol and 32.07 g/mol respectively). (15 marks) B. 150 tph of material is subjected screening to separate the oversize from the undersize materials. If the cut-point size for the feed, oversize and undersize are 0.3, 0.85 and 0.15 respectively, calculate the recovery of oversize and undersize materials. Also determine the overall screen efficiency. (15 marks) C. Calculate how many kg of magnetite must be added to 1L of water to make a slurry with a pulp density of 1.9 g/cm3. Assume density of magnetite is 5.2g/cm3
A. The concentration of pyrite, arsenopyrite, and chalcopyrite in the concentrate is:
- Pyrite (FeS2): 2.268 mol
- Arsenopyrite (FeAsS): 0.128 mol
- Chalcopyrite (CuFeS2): 0.212 mol
B. The recovery of oversize materials is 80%, the recovery of undersize materials is 20%, and the overall screen efficiency is 100%.
C. Approximately 0.9 grams of magnetite must be added to 1 L of water to make a slurry with a pulp density of 1.9 g/cm3.
A. To find the concentration of pyrite, arsenopyrite, and chalcopyrite in the concentrate, we need to calculate the amount of each mineral present based on their respective concentrations of arsenic (As), copper (Cu), and iron (Fe).
First, let's assume we have 100 grams of the concentrate. From the given concentrations, we can calculate the weight of each element in the concentrate as follows:
- Arsenic (As): 9.6% of 100 g = 9.6 g
- Copper (Cu): 13.5% of 100 g = 13.5 g
- Iron (Fe): 63.3% of 100 g = 63.3 g
Now, we need to convert the weight of each element to moles by dividing it by its molar mass:
- Arsenic (As): 9.6 g / 74.92 g/mol = 0.128 mol
- Copper (Cu): 13.5 g / 63.55 g/mol = 0.212 mol
- Iron (Fe): 63.3 g / 55.85 g/mol = 1.134 mol
Since pyrite (FeS2) contains 2 moles of iron (Fe) for every 1 mole of sulfur (S), the concentration of pyrite can be calculated as:
- Pyrite (FeS2): 2 * 1.134 mol = 2.268 mol
Similarly, arsenopyrite (FeAsS) contains 1 mole of arsenic (As), 1 mole of iron (Fe), and 1 mole of sulfur (S), so the concentration of arsenopyrite can be calculated as:
- Arsenopyrite (FeAsS): 0.128 mol
Chalcopyrite (CuFeS2) contains 1 mole of copper (Cu), 1 mole of iron (Fe), and 2 moles of sulfur (S), so the concentration of chalcopyrite can be calculated as:
- Chalcopyrite (CuFeS2): 0.212 mol
Therefore, the concentration of pyrite, arsenopyrite, and chalcopyrite in the concentrate is:
- Pyrite (FeS2): 2.268 mol
- Arsenopyrite (FeAsS): 0.128 mol
- Chalcopyrite (CuFeS2): 0.212 mol
B. To calculate the recovery of oversize and undersize materials, as well as the overall screen efficiency, we need to consider the feed, oversize, and undersize materials' cut-point sizes.
The recovery of oversize materials is the percentage of material larger than the cut-point size that passes through the screen. In this case, the cut-point size for oversize is 0.85. If the oversize material passing through the screen is 120 tph, we can calculate the recovery as:
- Recovery of oversize = (120 tph / 150 tph) * 100 = 80%
The recovery of undersize materials is the percentage of material smaller than the cut-point size that passes through the screen. In this case, the cut-point size for undersize is 0.15. If the undersize material passing through the screen is 30 tph, we can calculate the recovery as:
- Recovery of undersize = (30 tph / 150 tph) * 100 = 20%
The overall screen efficiency is the percentage of material passing through the screen compared to the total feed. If the total feed is 150 tph and the material passing through the screen is 150 tph, we can calculate the overall screen efficiency as:
- Overall screen efficiency = (150 tph / 150 tph) * 100 = 100%
C. To calculate the amount of magnetite required to make a slurry with a pulp density of 1.9 g/cm3, we need to use the density of magnetite and the volume of water.
Given:
- Density of magnetite = 5.2 g/cm3
- Pulp density = 1.9 g/cm3
- Volume of water = 1 L
First, we need to determine the mass of water by multiplying the volume by its density:
- Mass of water = Volume of water * Density of water = 1 L * 1 g/cm3 = 1000 g
Now, let's assume we need x grams of magnetite. The total mass of the slurry will be the sum of the mass of water and the mass of magnetite:
- Total mass of slurry = Mass of water + Mass of magnetite = 1000 g + x g
Since the pulp density is given as 1.9 g/cm3, the volume of the slurry can be calculated as the total mass of the slurry divided by the pulp density:
- Volume of slurry = Total mass of slurry / Pulp density = (1000 g + x g) / 1.9 g/cm3
Since the volume of slurry is given as 1 L, we can equate the volume equation to 1 L and solve for x:
- (1000 g + x g) / 1.9 g/cm3 = 1 L
- 1000 g + x g = 1.9 g/cm3 * 1 L
- x g = 1.9 g/cm3 * 1 L - 1000 g
- x g = 1.9 g - 1000 g
- x g = 0.9 g
Therefore, approximately 0.9 grams of magnetite must be added to 1 L of water to make a slurry with a pulp density of 1.9 g/cm3.
In summary:
A. The concentration of pyrite, arsenopyrite, and chalcopyrite in the concentrate is:
- Pyrite (FeS2): 2.268 mol
- Arsenopyrite (FeAsS): 0.128 mol
- Chalcopyrite (CuFeS2): 0.212 mol
B. The recovery of oversize materials is 80%, the recovery of undersize materials is 20%, and the overall screen efficiency is 100%.
C. Approximately 0.9 grams of magnetite must be added to 1 L of water to make a slurry with a pulp density of 1.9 g/cm3.
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There are white, blue, and red boats in a marina. Three-fourths of the boats in the marina are white,4/7
of the remaining boats are blue, and the rest are red. If there are 9 red boats, how many boats are in the marina?
The solution is 84 boats
The total number of boats in the marina is 84 boats
What is an Equation?
Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.
It demonstrates the equality of the relationship between the expressions printed on the left and right sides.
Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.
Given data ,
Let the total number of boats in the marina be A
Now , the value of A is
And , the number of boats in the marina that are white = ( 3/4 ) A
So , the remaining boats = A - ( 3/4 ) A
The remaining boats = ( 1/4 ) A
And , 4/7 of the remaining boats are blue
So , substituting the values in the equation , we get
The number of boats in the marina that are blue = 4/7 ( ( 1/4 ) A )
The number of boats in the marina that are blue = ( 1/7 ) A
And ,
The remaining number of boats are red
So , the remaining number of boats = A - ( number of boats in the marina that are white + number of boats in the marina that are blue )
Substituting the values in the equation , we get
Number of boats in the marina that are red = A - ( 3/4 A + 1/7 A )
Number of boats in the marina that are red = A - ( 25/28 ) A
Number of boats in the marina that are red = ( 3/28 ) A
Now , There are 9 red boats , so substituting the value in the equation ,
Number of boats in the marina that are red = 9 = ( 3/28 ) A
On simplifying the equation , we get
( 3/28 ) A = 9
Multiply by 28 on both sides of the equation , we get
3A = 9 x 28
Divide by 3 on both sides of the equation , we get
A = 3 x 28
A = 84 boats
Therefore , the value of A is 84 boats
Number of red boats = 9 boats
Number of white boats = ( 3/4 ) A = 3/4 x 84 = 63 boats
Number of blue boats = ( 1/7 ) A = 1/7 x 84 = 12 boats
Total number of boats = 9 + 12 + 63 = 84 boats
Hence , The total number of boats is 84 boats
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Which of the following ratios are part of the ROI formula?
The ratios involved in the ROI formula are the net profit and the investment cost.
The ROI (Return on Investment) formula includes the following ratios:
Net Profit: The net profit represents the profit gained from an investment after deducting expenses, costs, and taxes.
Investment Cost: The investment cost refers to the total amount of money invested in a project, including initial capital, expenses, and any additional costs incurred.
The ROI formula is calculated by dividing the net profit by the investment cost and expressing it as a percentage.
ROI = (Net Profit / Investment Cost) * 100%
Therefore, the ratios involved in the ROI formula are the net profit and the investment cost.
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Solve for the value of t.
Answer: t =
(2t-4)
(5t+2)°
Submit Answer
Answer:
-2 is the answer
Step-by-step explanation:
In the down question i.e (5t+2)° answer is one as anything to the power zero is one so we have fond the value of 5 is one t is one and 2 is also one
By putting the value of t
we have ,
(2t-4)
=(2x1-4)
=2-4
= -2
What is 2.49 x 10-2 written in standard form?
Answer:
2.29×10^1
Step-by-step explanation:
2.49 multiply with 10 and then minus with 2 and you will get 22.9 if you want it in standard form the answer will be 2.29×10^1
independent variable was contact plates placed on the tile for less than 5 seconds. the standardized variables were the length of time plates were on the tiles. the control was the inoculating floor tiles for five days in chicken broth. the dependent variable was the plates placed on the tile for more than 5 seconds.
Their experimental design was Independent variable was contact plates placed on the tile for less than 5 seconds. Option D is the correct answer.
The independent variable is the factor that is being manipulated by the experimenter. In this case, the experimenter is manipulating the length of time the plates are on the tiles. The dependent variable is the factor that is being measured by the experimenter. In this case, the experimenter is measuring the amount of bacteria on the plates.
The control is a group of subjects that are not exposed to the independent variable. In this case, the control group is the floor tiles that have been inoculated with chicken broth. The control group is used to compare the results of the experimental group, which is the group of plates that have been dropped on the tiles.
The standardized variables are the factors that are kept the same for both the experimental group and the control group. In this case, the standardized variables are the type of food, the surface of the tiles, and the temperature of the room. These factors are kept the same so that the only difference between the two groups is the length of time the plates are on the tiles.
This experimental design is a well-controlled experiment because the experimenter has taken steps to ensure that the only difference between the two groups is the length of time the plates are on the tiles. This will allow the experimenter to make accurate conclusions about the effect of the independent variable on the dependent variable. Option D is the correct answer.
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The following question may be like this:
The Myth busters conducted an experiment to test the five second rule. Which of the following represented their experimental design?
The standardized variables were the length of time plates were on the tiles. The control was the inoculating floor tiles for five days in chicken broth. The dependent variable was the plates placed on the tile for more than 5 seconds. Independent variable was contact plates placed on the tile for less than 5 seconds.