25. Spider-Man Spider-Man holds the bottom of an elevator with one hand.
With his other hand, he holds a spider cord attached to a 50-kg box of
explosives at the bottom of the cord. Determine the force that the cord
exerts on the box if (a) the elevator is at rest; (b) the elevator accelerates up
at 2.0 m/s2; (c) the upward-moving elevator's speed decreases at a rate of
2.0 m/s2; and (d) the elevator falls freely.

Explanation:

B. the motion of an object along a curved path

hope it helps.

Answer:

the orbit of a satellite around a central body

Explanation:

hope that helps :)

Answer:

weight, acceleration

Explanation:

weight = mass x gravity(meaning the direction of the mass)

acceleration = v-u/t

v-u is the change in velocity

Answer:

A) 1.4167 × 10^(-11) F

B) r_a = 0.031 m

C) E = 3.181 × 10⁴ N/C

Explanation:

We are given;

Charge;Q = 3.40 nC = 3.4 × 10^(-9) C

Potential difference;V = 240 V

Inner radius of outer sphere;r_b = 4.1 cm = 0.041 m

A) The formula for capacitance is given by;

C = Q/V

C = (3.4 × 10^(-9))/240

C = 1.4167 × 10^(-11) F

B) To find the radius of the inner sphere,we will make use of the formula for capacitance of spherical coordinates.

C = (4πε_o)/(1/r_a - 1/r_b)

Rearranging, we have;

(1/r_a - 1/r_b) = (4πε_o)/C

ε_o is a constant with a value of 8.85 × 10^(−12) C²/N.m

Plugging in the relevant values, we have;

(1/r_a - 1/0.041) = (4π × 8.85 × 10^(−12) )/(1.4167 × 10^(-11))

(1/r_a) - 24.3902 = 7.8501

1/r_a = 7.8501 + 24.3902

1/r_a = 32.2403

r_a = 1/32.2403

r_a = 0.031 m

C) Formula for Electric field just outside the surface of the inner sphere is given by;

E = kQ/r_a²

Where k is a constant value of 8.99 × 10^(9) Nm²/C²

Thus;

E = (8.99 × 10^(9) × 3.4 × 10^(-9))/0.031²

E = 3.181 × 10⁴ N/C

The lithosphere is the solid layer of Earth, the hydrosphere is the water-based part, and the atmosphere is the air, they work together to shape the biosphere.

The lithosphere is the soil part that composes the Earth's planet (i.e., the soil), the hydrosphere refers to oceans and all water bodies, while the atmosphere is the layer of air. These three layers interact with biotic factors to shape the biosphere.

In conclusion, the lithosphere is the solid layer of Earth, the hydrosphere is the water-based part, and the atmosphere is the air, they work together to shape the biosphere.

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Many of the properties of galaxies (including the galaxy color–magnitude diagram) indicate that there are fundamentally two types of galaxies. These groups divide into blue star-forming galaxies that are more like spiral types, and red non-star forming galaxies that are more like elliptical galaxies.

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Answer:

d) electrons removed.

Explanation:

Two insulators are electrically neutral, that is, the number of electrons and protons are equal. When one insulator is rubbed against another, electrons are removed from one of the insulators due their high mobility. The insulator which lost the electrons becomes positively charged while the one that gained the electron becomes negatively charged.

Therefore, when rubbing two insulators together, the one that gets a positive charge has had electrons removed.

Answer:

Assumption: there is no object between this point charge and the observer.

Explanation:

The electric field of a point charge is inversely proportional to the square of the distance from that point charge.

Let \(k\) denote Coulomb's constant (\(k \approx 8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-1}\).) Let the magnitude of that point charge be \(q\). At a distance of \(r\) from this charge, the electric field due to this charge would be:

\(\displaystyle E = \frac{k \cdot q}{r^{2}}\).

Convert the magnitude of the point charge in this question to standard units:

\(q = 1\; \rm nC = 10^{-9}\; \rm C\).

Apply that equation to find the magnitude of the electric field due to this point charge:

\(r = 1\; \rm m\):

\(\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(1\; \rm m)^{2}} \\ &\approx 9.0\; \rm N \cdot C^{-1}\end{aligned}\).

\(r = 2\; \rm m\):

\(\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(2\; \rm m)^{2}} \\ &\approx 2.2\; \rm N \cdot C^{-1}\end{aligned}\).

\(r = 3\; \rm m\):

\(\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(3\; \rm m)^{2}} \\ &\approx 1.0\; \rm N \cdot C^{-1}\end{aligned}\).

The direction of the electric field at a point is the same as the direction of a force from this field onto a positive point charge at this point.

Because the \((+1\; \rm nC)\) point charge here is positive, the electric field of this charge would repel other positive point charges. Hence, the electric field around this \((+1\; \rm nC)\!\) point charge at any point in the field would point away from this charge.

Answer:

Explanation:

Pressure will expand a gas, enlarging its volume and reducing its density and concentration of particles. Pressure will magnify a gas, developing its volume and multiplying its density and concentration of particles.

Increasing the pressure of a gas is exactly the same as increasing its concentration. If you have a given mass of gas, the way you increase its pressure is to squeeze it into a smaller volume. If you have the same mass in a smaller volume, then its concentration is higher.

a) The angle θ1 which the righthand cable makes with respect to the ceiling is  sin^(-1)(692 N / 530 N).

b) The angle θ2 which the left-hand cable makes with respect to the ceiling is  sin^(-1)(692 N / 570 N).

We may utilise the tension of the right-hand cable as well as its vertical and horizontal components to determine the angle 1. θ2 = sin^(-1)(692 N / 570 N).

We may apply the ideas of trigonometry and vector addition to address this issue.

a) The tension of the right-hand wire as well as its vertical and horizontal components can be used to determine the angle 1.

T1sin(1) calculates the vertical component of the right-hand cable's tension, which is equal to the object's weight (692 N).

T1sin(θ1) = 692 N

We may rearrange the equation to find 1:

θ1 = sin^(-1)(692 N / T1)

We can find 1 by substituting the given tension value, T1 = 530 N:

θ1 = sin^(-1)(692 N / 530 N)

b) Similarly, we can use the formula to determine the angle 2 the left-hand cable's tension and its vertical and horizontal components.

The vertical component of the left-hand cable's tension is given by T2sin(θ2), and it should also be equal to the weight of the object (692 N).

T2sin(θ2) = 692 N

To find θ2, we can rearrange the equation:

θ2 = sin^(-1)(692 N / T2)

Substituting the given tension value T2 = 570 N, we can solve for θ2:

θ2 = sin^(-1)(692 N / 570 N)

Calculating these angles using the given tension values will provide the answers in degrees.

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Para sa aking Mahal na Magulang

Tula ni Eden Diao Apostol

Ang buhay kong ito’y sa inyo nagmula

Pangalawa sa Diyos na s’yang lumikha

Utang ko sa inyo ang aking hininga

Minahal, hinubog ng inyong kalinga.

Mga sakripisyo’y sadyang hindi biro

Mula ng ako’y iniluwal sa mundo

Pag-ibig na iniukol sa ‘ki’y totoo

Pagmamahal ninyo’y nagsilbing lakas ko.

Ako’y tinuruan ng magandang asal

Sa gitna ng hirap ako’y pinag-aral

Upang ‘di mapariwara ang aking buhay

Diplomang natanggap sa inyo ini-alay.

Ngayon ang buhay ko ay sadyang kay-palad

Pangarap ko’y unti-unting natutupad

Ito’y bunga ng ‘nyong dakilang paglingap

Sa ‘king puso’y walang hanggang pasalamat.

Pagkalinga ng Magulang

Tula ni Laurence B. Reyes

Saking pag unlad baon ang inyong aral

Bilang papuri at sa inyo ay parangal

Ang walang katapusang pasasalamat

Ang pag ibig at karangalan ang dapat.

Sa aking pagmulat sa mundo ng kaligayahan

Kayo ang aking lagging nadadamhan

Sa aking paglaki dama pa rin ang aruga

Hindi ko makalimutan ang pagmamahal at aruga

Sa pag aaruga at pag aalaga

Sa pag ibig at iyong pagkalinga

Sadyang tinakda ng ating kapalaran

Patungo lamang sa tuwid na daan.

Ang pagbibigay ng natatanging aral

Ang inyong anak ay nabusog sa pangaral

Ang inyong pag ibig na para sa akin

Tanging kabutihan ang nais hatid.

Naging daan patungo sa kabutihan

Naging daan ng pag ibig sa tahanan

Kayo ang pundasyon, mabuting samahan

Maraming salamat sa pagmamahal.

Dependent variables should be plotted on the horizontal axis and independent variables on the vertical axis.

In general, the "Dependent variable" denoted by Y, is plotted on the vertical axis and the "Independent variable" denoted by X, is plotted on the horizontal axis.

To get a linear graph the relationship between the dependent(Y) and independent (X) variables should be,

Y= MX + C

where M is a constant which defines the "Slope" or steepness of the line and C is the constant which defines the position of the Line at the initial state (0, C)

For example, for plotting a linear graph of given slope 3 and passing from (0,4) the equation of the line would be in the form

Y=3X+4

where Y will be plotted vertically and X will be plotted horizontally.

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Answer:

A goal keepee catering the ball in time is answer

Answer:

Explanation:

If we ignore wind resistance, the time needed for the hay to drop from vertical rest is

t = √(2h/g) = √(2(300)/9.81) = 7.82 s

d = vt = 80.0(7.82) = 626 m before passing over the cow.

Acceleration is the rate of change of velocity, so if velocity is linear, the acceleration is the slope of its graph.

Here, the line passes through the points (0, 1) and (0.5, 3), so its slope is

(3 m/s - 1 m/s) / (0.5 s - 0 s) = (2 m/s) / (0.5 s) = 4 m/s²

Answer:The direction of the resultant can be determined by finding the angle that the resultant makes with either the north-south or the east-west vector. The diagram at the right shows the angle theta (Θ) marked inside the vector addition triangle. This angle theta is the angle that the resultant makes with west.

Explanation: Because i said

The shape of a line graph displaying temperature change over time before boiling is typically linear and increasing.

In a line graph showing the temperature change over time of a liquid before it starts to boil, the shape is generally linear and increasing.

This is because as heat is applied to the liquid, its temperature increases at a consistent rate.

During this phase, the heat energy is used to increase the kinetic energy of the molecules in the liquid, causing a rise in temperature.

Once the boiling point is reached, the graph may show a plateau, as the energy is then used to change the liquid's state rather than further increase the temperature.

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Answer:

Ohm's LawPower Revisited

An electron traveling through the wires and loads of the external circuit encounters resistance. Resistance is the hindrance to the flow of charge. For an electron, the journey from terminal to terminal is not a direct route. Rather, it is a zigzag path that results from countless collisions with fixed atoms within the conducting material. The electrons encounter resistance - a hindrance to their movement. While the electric potential difference established between the two terminals encourages the movement of charge, it is resistance that discourages it. The rate at which charge flows from terminal to terminal is the result of the combined effect of these two quantities.

Variables Affecting Electrical Resistance

The flow of charge through wires is often compared to the flow of water through pipes. The resistance to the flow of charge in an electric circuit is analogous to the frictional effects between water and the pipe surfaces as well as the resistance offered by obstacles that are present in its path. It is this resistance that hinders the water flow and reduces both its flow rate and its drift speed. Like the resistance to water flow, the total amount of resistance to charge flow within a wire of an electric circuit is affected by some clearly identifiable variables.

First, the total length of the wires will affect the amount of resistance. The longer the wire, the more resistance that there will be. There is a direct relationship between the amount of resistance encountered by charge and the length of wire it must traverse. After all, if resistance occurs as the result of collisions between charge carriers and the atoms of the wire, then there is likely to be more collisions in a longer wire. More collisions mean more resistance.

Second, the cross-sectional area of the wires will affect the amount of resistance. Wider wires have a greater cross-sectional area. Water will flow through a wider pipe at a higher rate than it will flow through a narrow pipe. This can be attributed to the lower amount of resistance that is present in the wider pipe. In the same manner, the wider the wire, the less resistance that there will be to the flow of electric charge. When all other variables are the same, charge will flow at higher rates through wider wires with greater cross-sectional areas than through thinner wires.

A third variable that is known to affect the resistance to charge flow is the material that a wire is made of. Not all materials are created equal in terms of their conductive ability. Some materials are better conductors than others and offer less resistance to the flow of charge. Silver is one of the best conductors but is never used in wires of household circuits due to its cost. Copper and aluminum are among the least expensive materials with suitable conducting ability to permit their use in wires of household circuits. The conducting ability of a material is often indicated by its resistivity. The resistivity of a material is dependent upon the material's electronic structure and its temperature. For most (but not all) materials, resistivity increases with increasing temperature. The table below lists resistivity values for various materials at temperatures of 20 degrees Celsius.

s = 40m - 4m = 36m

W = F × s

= 10N × 36m = 360J

W = Work (J)

F = Force / weight (N)

s = distance (m)

Work done in physics is the product of force and displacement. The displacement for the object is 36 m and force acts on it is 10 N. Then the work done is 360 J.

Work done is the dot product of force acting on a body and the resultant displacement. When a force applied on an object results in a displacement from its position, the force is said to be work done.

Work done is a vector quantity thus, characterised by a magnitude and direction.  The common unit of work done is joule.

Given that force applied on the weight = 10 N

displacement occurred = 40 m - 4 m = 36 m

Work done = F . ds

ds = 36 m and f = 10 N

Then W = 10 N × 36m

             = 360 J.

Therefore, the work is required to lift a 10-newton weight from 4.0 meters to 40 meters above the surface of Earth is 360 J.

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Answer:

yes u can flag football has everything that pad football has so you can enlist on being offensive position but you have to play like you want that position

Explanation:

The statement that what matters in an experiment is asking the right questions and not necessarily finding the right answer potryas the importance of the scientific process and inquiry-based approach.

The aim of scientific study is to learn about and comprehend the natural world. This is accomplished through developing hypotheses, posing questions, carrying out experiments, and evaluating the outcomes. While getting the right response is critical, it's just as important to ask the right questions in the first place.

Asking the right questions helps to define the scope and objectives of the experiment and also  guides the researcher to focus on specific variables, design appropriate experiments, and gather relevant data.

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Using

V = Amplitude x angular frequency(omega)

But omega= 2πf

= 2πx875

=5498.5rad/s

So v= 1.25mm x 5498.5

= 6.82m/s

B. .Acceleration is omega² x radius= 104ms²

Answer:

a

  \(v _{max } = 6.82 \ m/s\)

b

 \(a_{max} = 37489.5 \ m/s^2\)

Explanation:

From the question we are told that

   The amplitude is \(A = 1.24 \ mm = 1.24 * 10^{-3} \ m\)

   The frequency is  \(f = 875 \ Hz\)

Generally the maximum speed is mathematically represented as

           \(v _{max } = A * 2 * \pi * f\)

=>        \(v _{max } = 1.24*10^{-3} * 2 * 3.142 * 875\)

=>        \(v _{max } = 6.82 \ m/s\)

Generally the maximum acceleration is mathematically represented as

       \(a_{max} = A * (2 * \pi * f)\)

=>      \(a_{max} = 1.24*10^{-3} * (2 * 3.142 * 875 )^2\)

=>       \(a_{max} = 37489.5 \ m/s^2\)

Answer:

Answer:

1hjkeiidjjishhhhbsvvvabzbzbshshshsjsjsjsjsjs

The total distance is 105 kilometers and the total displacement is 15 kilometers east. Option C

To calculate the total distance, we add the distances traveled in each leg of the journey: 60 kilometers (from A to B) + 45 kilometers (from B back to A) = 105 kilometers.

However, displacement refers to the change in position of an object in a straight line from its starting point to its ending point. In this case, since the boat starts and ends at the same point (A), the total displacement is zero.

Hence The total distance is 105 kilometers and the total displacement is 15 kilometers east.

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The correct answer is Option B. The statement "they have the same A-number but different Z-number" is true .

Atoms of the same element only differ because one of the atoms has more electrons, making it an ion.

This difference does not affect the mass of the atom, which is determined by the sum of its protons and neutrons, represented by the atomic mass or A-number.

The number of protons in an atom is called the atomic number or Z-number.

The Z-number of an element is unique to it. All the atoms of a given element have the same number of protons.

Thus, for example, all carbon atoms have six protons, making the Z-number of carbon 6.

However, different isotopes of an element can have different numbers of neutrons.

This means that they have a different atomic mass or A-number.

Therefore, they have the same A-number but different Z-number.

Therefore the correct Option is B.

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#1

\(\\ \rm\dashrightarrow P=VI\implies V=\dfrac{P}{I}\)

\(\\ \rm\dashrightarrow V=\dfrac{0.4\times 10^3}{33\times 10^{-3}}\)

\(\\ \rm\dashrightarrow V=0.012\times 10^{-6}\)

\(\\ \rm\dashrightarrow V=12mV\)

#2

\(\\ \rm\dashrightarrow R=\rho \dfrac{\ell}{A}\)

\(\\ \rm\dashrightarrow \rho =\dfrac{RA}{\ell}\)

\(\\ \rm\dashrightarrow \rho=\dfrac{86.3(0.4\times 10^6)}{69}\)

\(\\ \rm\dashrightarrow \rho=0.5\times 10^{6}\)

#3

Ohms law

\(\\ \rm\dashrightarrow R=\dfrac{V}{I}\)

\(\\ \rm\dashrightarrow R=\dfrac{7(10^3)}{6(10^{-6})}\)

\(\\ \rm\dashrightarrow R=1.167\times 10^9\Omega\)

Answer:

Carbohydrates are divided into four types: monosaccharides, disaccharides, oligosaccharides, and polysaccharides. Monosaccharides consist of a simple sugar; that is, they have the chemical formula C 6 H 12 O 6. Disaccharides are two simple sugars. Oligosaccharides are three to six monosaccharide units, and polysaccharides are more than six.

Answer:

  y/y₀ = 1/2 + v₀²/(2 g y₀)

Explanation:

         This in a kinematics exercise in a mention  

ball A.  

Since the ball is dropped, its velocity starts at zero, at the meeting point the equation is  

\(v_{A}^2\)= - 2 g (y₀-y)  

ball B  

v_{B}^2 = v₀² - 2 g y

we substitute  

               2v_{B}^2 = -2 g (y₀ -y)  

               v_{B}^2 = - g y₀ + 2g y  

              v_{B}^2 = v₀² - 2gy

we have a system of two equations with two unknowns, therefore it can be solved. Let's multiply-by -1 and add  

       0 = g y₀ + v₀² -2gy  

we clear the height  

      y = (g yo + v₀²) / 2g  

     y = yo / 2 + v₀² / 2g

In this exercise we assume that the height of the building is known and the initial velocity of ball B  

The fraction is

y/yo = 1/2 + v₀²/(2gyo)

The researcher did not find strong evidence to support the idea that job applicants with popular names are viewed more favorably than equally qualified applicants with less popular names.

It sounds like the researcher conducted an experiment to investigate whether job applicants with popular names are viewed more favorably than equally qualified applicants with less popular names.

Based on the information provided, the researcher found that the differences in the evaluations of the applicants by the two groups were not significant at the .001 level.

The factors that play an important role in the hiring process for a job:

(1) Qualifications and experience: Employers typically look for candidates who possess the necessary qualifications and experience for the job. This includes education, training, certifications, and work experience.

(2) Skills and abilities: Employers also consider a candidate's skills and abilities related to the job. These may include technical, interpersonal, communication, and problem-solving skills.

(3) Personal characteristics: Personal characteristics, such as motivation, work ethic, and adaptability, can also play a role in the hiring process. Employers may look for candidates who demonstrate a positive attitude, a willingness to learn, and the ability to work well with others.

(4) Fit with company culture: Companies may also consider whether a candidate fits with their company culture, values, and mission. This can include factors such as teamwork, creativity, and innovation.

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