Step-by-step explanation:
11887249635951.291207505
Is the correct answer
Find the area of the region in blue.
Round to the nearest whole number.
Answer:
1696 m^2
Step-by-step explanation:
Using the area of the larger circle to minus the area of smaller one, so A = 2*pi*r^2. 24^2*pi - 6^2*pi = 540 pi = 1696 m^2
If 0° ≤ Θ≤ 360°, then find angle(s) Θ.
1) sec Θ = undefined
Answer:
The secant function is undefined for angles where the cosine function equals zero, because dividing by zero is undefined. Therefore, we need to find the values of Θ where cos Θ = 0.
The cosine function equals zero at 90° and 270° (or π/2 and 3π/2 in radians), so we have:
cos 90° = 0, cos 270° = 0
Therefore, the angles that satisfy sec Θ = undefined are:
Θ = 90° + 360°k, Θ = 270° + 360°k
where k is an integer (positive, negative, or zero) that allows us to generate all possible angles in the range 0° ≤ Θ ≤ 360°.
So, the solutions for Θ are:
Θ = 90° + 360°k, Θ = 270° + 360°k
where k is an integer.
Step-by-step explanation:
Either draw a full m-ary tree with 76 leaves and height 3, where m is a positive integer, or show that no such tree exists.
If and only if m is a divisor of 76, then there exists a full m-ary tree with 76 leaves and height 3. 1, 2, 4, 19, 38, and 76 are the divisors of the number 76.
One node at the root, 76 child nodes at the second level, and \(76^{2}\) = 5776 child nodes at the third level make up the 5776 + 76 = 5852 nodes of a full 1-ary tree with 76 leaves and height 3. As a result, there is no whole 1-ary tree with 76 leaves and a height of 3.
There would be one node at the root, 38 child nodes at the second level, and \(38^{2}\) = 1444 child nodes at the third level, making a total of 1444 + 38 = 1482 nodes in a full 2-ary tree with 76 leaves and height 3. As a result, there is a full 2-ary tree that is 3 in height and has 76 leaves.
There would be one node at the root, 19 child nodes at the second level, and \(19^{2}\) = 361 child nodes at the third level, for a total of 361 + 19 = 380 nodes in a full 4-ary tree with 76 leaves and height 3. As a result, there is a full 4-ary tree that is 3 in height and has 76 leaves.
A full 19-ary tree with 76 leaves and height 3 would have a single node at the root, four children at the second level, and four and a half children, or 16 at the third level, for a total of 16 + four and a half and twenty nodes. As a result, there is a full 19-ary tree that is 3 in height and has 76 leaves.
A full 38-ary tree would contain a single node at the root, two child nodes at the second level, and two and a half child nodes at the third level, for a total of four + two + six nodes. Consequently, there is a complete 38-ary tree that is 3 in height and has 76 leaves.
There would be one node at the root, one child node at the second level, and \(1^{2}\)= one child node at the third level, for a total of 1 + 1 = 2 nodes in a full 76-ary tree with 76 leaves and height 3. Consequently, there is a full 76-ary tree with 76 leaves and a height of 3.
As a result, for m = 2, 4, 19, 38, and 76, a full m-ary tree with 76 leaves and height 3 exists.
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what does 3½-1⅞ equal???
1. Findf(g(x))andg(f(x)). f(x) = 10x;g(x)=x+3 f(g(x)) = g(f(x)) = a. 10x +30 b. 10² +3 c. 10x +30 d. 11x +3 e. 10x +3
A function is a rule or connection in mathematics that pairs each element from one set, known as the domain, with a certain element from another set, known as the codomain. A function generates output values in the codomain that correspond to input values from the domain. The correct answer is option e.
Typically, a function is denoted by the notation f(x), where x is the input variable and f is the name of the function.
The given functions are; f(x) = 10x and g(x) = x + 3. To find f(g(x)), first, we evaluate g(x) and substitute that value in place of x in f(x).
We change g(x) into f(x) to discover f(g(x)):
The equation f(g(x)) = f(x + 3) = 10(x + 3) = 10x + 30
Consequently, f(g(x)) = 10x + 30.
We change f(x) into g(x) to discover g(f(x)):
g(f(x))=g(10x)=10x + 3
g(f(x)) is therefore equivalent to 10x + 3
Therefore, the right answer is e) 10x + 3
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Kelly's team won 85% of the games they played in a season. The team lost 12 games. How many games did Kelly's team win in the season?
Answer:
68 games
Step-by-step explanation:
According to the scenario, computation of the given data are as follows,
Games won = 85%
Game lost = 12
Here, 100% - 85% = 12
15% = 12
or 1% = 0.8
So, total games played (100%) = 80 games
Now, number of games won = Total games - Games lost
= 80 - 12
= 68 games
Hence, Kelly's team wins 68 games in the season.
-0.9y+4.4y-3.2y
I need it to be simplified!!!
Plz, help!
Answer:
0.3y
Step-by-step explanation:
-0.9y+4.4y=3.5y
3.5y-3.2y=0.3y
describe the error in finding the product (big ideas math)
Answer:
d
Step-by-step explanation:
you have to foil in situations like these, getting you
ksquared +4k+4k+16
2(k)(4) is the same thing as 4k+4k, which is what is missing from the answer
Greatest Common Factor
1. 18 and 54
2. 36 and 54
Least Common Multiple
1. 6 and 8
2. 12 and 18
Answer:
GCF
1.18
2.18
LCM
1.24
2. 36
Evaluate.
8 5/6 − (2 1/4 + 1 1/3)
Enter your answer in the box as a mixed number in simplest form.
Answer:5.25
Step-by-step explanation:
There are 8 times as many males as females on the maths course at university. What fraction of the course are female? Give your answer in its simplest form.
Answer:
⅑
Step-by-step explanation:
Let m represents number of males, and f represents number of females taking the maths course.
Given that number of males (m) taking the maths course is 8 times as much as number of females (f), total number of students taking the maths course (T).
Thus we can represent the information above with the following:
m = no. of males
f = no. of females
T = Total
m = 8f
T = m + f
Thus,
Total = 8f + f = 9f
==>The fraction of the course that are females = No. of females (f) ÷ Total no. of students (T)
= f/9f
Fraction of females in simplified form would be ⅑
A mom mixes 9 ounces of juice with 3 ounces of water.What percent of the drink is juice .
Answer:
33.3%
hope that helps
given that 2p x 8q = 2n , express n in terms of p and q
Answer:
n = p+3q
Step-by-step explanation:
2^p x 8^q = 2^n
Exponent rules
Rewriting 8 as 2^3
2^p x 2^3^q = 2^n
Using the rule a^b^c = a^(b*c)
2^p x 2^3q = 2^n
Using the rule a^b * a^c = a^(b+c)
2 ^(p+3q) = 2^n
Since the bases are the same, the exponents are the same
p+3q = n
Answer:
\( \sf \: p + 3q = n\)
Step-by-step explanation:
\(2^p*8^q=2^n\)
First, write 8^q as a power of 2.
\(2^p*8^q=2^n\\2^p*2^3^q=2^n\)
As all the bases are same, exponents are also equal.
Now add the powers.
∴ p + 3q = n
place the steps for locating an external cause code in order, with the first step on top.
The steps for locating an external cause code in order, with the first step on top are given below.
The StepsThe steps are as follows
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A scale model of the front view of Tony’s house is shown.
What is the minimum amount of paint needed for two coats?
A. 594 square centimeters
B. 297 square centimeters
C. 216 square centimeters
D. 81 square centimeters
The minimum amount of paint needed for two coats will be 297 square centimeters.
The shape is a combination of the rectangle and the triangle. Then the area of the shape is calculated as,
A = 1/2 x 18 x 9 + 18 x 12
A = 81 + 216
A = 297 square centimeters
Hence, the minimum amount of paint needed for two coats will be 297 square centimeters.
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\(\frac{bt7}{4} =9\)
Greetings from Brasil...
Isolating BT we get 36/7
3. Convert this rate (80km/hr) to a rate measured in m/s
if 5 crates of oranges weigh 200 pounds and each empty crate weighs 5 pounds, how many pounds of oranges are there in the five crates?
The five crates contain 175 pounds of oranges.
We know that the total weight of 5 crates of oranges and the empty crates combined is 200 pounds.
We also know that each empty crate weighs 5 pounds.
Assume that the weight of the oranges in the five crates is "w" pounds. So, the weight of the empty crates is 5 x 5 = 25 pounds.
To find the weight of the oranges, we subtract the weight of the empty crates from the total weight:
200 - 25 = 175 pounds.
Therefore, the weight of the oranges in the five crates is 175 pounds.
Hence, the five crates contain 175 pounds of oranges.
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How do you determine if something is a factor of a function?.
if the function is divided and we get the remainder of zero then it is said to be a factor of a function
According to the Remainder Theorem, by a factor x − an of that polynomial, then you will get a zero remainder. The point of the Factor Theorem is the turnaround of the Remainder Theorem: On the off chance that you synthetic-divide a polynomial by x = a and get a zero remainder, at that point not as it were is x = a, a zero of the polynomial(for the remainder theorem ) but x − a is additionally a factor of the polynomial according to of the Factor Theorem.
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Probability of first marriage among women. A National Center for Health Statistics (NCHS) brief report by the Centers for Disease Control and Prevention (CDC) in 2009 identified that about 6% of women in the United States mar- ried for the first time by their 18th birthday 50% married by their 25th birthday, and 74% married by their 30th birthday. Based on these data, what is the probability that in a family with two daughters, the first and second daughter will be married by each of the following ages? la) 18 years of age b) 25 years of age c) 30 years of age
The probability that both will be married before the age of 18 is 0.0036. The probability that both will be married by the age of 25 is 0.25. Finally, the probability that both will be married by the age of 30 is 0.5476.
According to the brief report by NCHS, approximately 6% of women in the United States married for the first time before their 18th birthday, and 50% of women married by their 25th birthday. 74% of women married by their 30th birthday.The probability of a family with two daughters marrying at different ages is asked in the question. The probability that both daughters will be married by the ages of 18, 25, and 30 will be determined
The question requires finding the probability that both daughters of a family will be married by the ages of 18, 25, and 30 respectively. Since each daughter's wedding is a separate event, the individual probability of a daughter marrying at a given age will be determined separately and then multiplied together to get the probability of both daughters being married at the given age. So, let's find the probabilities of each daughter marrying at a given age:
Probability of one daughter getting married by 18 years:
As per the brief report, 6% of women in the United States married before the age of 18.
Therefore, the probability of one daughter getting married before the age of 18 is 0.06
Probability of one daughter getting married by 25 years:
As per the brief report, 50% of women in the United States get married by the age of 25. Therefore, the probability of one daughter getting married by 25 years is 0.5.
Probability of one daughter getting married by 30 years:
As per the brief report, 74% of women in the United States get married by the age of 30. Therefore, the probability of one daughter getting married by 30 years is 0.74.
The probability of both daughters getting married at the same age is the product of each daughter's probability of getting married at that age.
The probability that both daughters will get married before the age of 18 is:
P(both daughters married at 18 years) = P(daughter1 married at 18) × P(daughter2 married at 18)= 0.06 × 0.06= 0.0036
The probability that both daughters will get married by the age of 25 is:
P(both daughters married at 25 years) = P(daughter1 married at 25) × P(daughter2 married at 25)= 0.5 × 0.5= 0.25
The probability that both daughters will get married by the age of 30 is:
P(both daughters married at 30 years) = P(daughter1 married at 30) × P(daughter2 married at 30)= 0.74 × 0.74= 0.5476
The probability that in a family with two daughters, both will be married before the age of 18 is 0.0036. The probability that both daughters will be married by the age of 25 is 0.25. Finally, the probability that both daughters will be married by the age of 30 is 0.5476.
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There are 3 black markers in a bin. Given the probability that a marker selected at random is black, how many markers are in the box? (use only the digits 0 - 9 to write the value. ).
There are total 18 markers in the box.
What is a expression? What is a mathematical equation? What is Probability?A mathematical expression is made up of terms (constants and variables) separated by mathematical operators. A mathematical equation is used to equate two expressions. Equation modelling is the process of writing a mathematical verbal expression in the form of a mathematical expression for correct analysis, observations and results of the given problem. The formula to calculate the probability of occurrence of an event 'A' can be written as -
P(A) = n(A)/n(S)
where -
n(A) = Number of outcomes favorable to event A.
n(S) = Total number of outcomes
Given is that there are 3 black markers in a bin. The probability that a marker selected at random is black is -
P(black marker) = 1/6
Assume that there are [x] markers in the box. Then, we can write -
P(black marker) = 3/x
1/6 = 3/x
x = 18
Therefore, there are total 18 markers in the box.
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a quadratic function is represented by g(x)=-2(x-5)^2+17 what is the equation for this function in standard form
PLS HELPP
Answer:
g(x) = - 2x² + 20x - 33---------------------------
Given function:
g(x) = -2(x - 5)² + 17This is the vertex form and the standard form is:
y = ax² + bx + cConvert the given equation into standard form:
g(x) = - 2(x - 5)² + 17 = - 2(x² - 10x + 25) + 17 = - 2x² + 20x - 50 + 17 = - 2x² + 20x - 33Answer:
The standard form of the given quadratic function is:
\(g(x)=-2x^2+20x-33\)
Step-by-step explanation:
The standard form of a quadratic function is f(x) = ax² + bx + c.
To write the given function in standard form, expand the brackets:
\(\implies g(x)=-2(x-5)(x-5)+17\)
\(\implies g(x)=-2(x^2-10x+25)+17\)
Apply the distributive law: m(a + b + c) = ma + mb + mc
\(\implies g(x)=-2x^2+20x-50+17\)
Add the numbers: -50 + 17 = -33
\(\implies g(x)=-2x^2+20x-33\)
Given y = 3x + 1 State the quadrants in which this graph is in. (Use the numbers 1-4)
Answer:
1, 2 and 3 (I, II and III)
Step-by-step explanation:
Since the slope is positive (3) in the equation y = 3x + 1, it means that the graph has a positive slope, meaning the line slopes up from left to right.
The y intercept is 1
the x intercept is:
0 = 3x + 1
x = 1/3
Therefore, the graph of y = 3x + 1 lies in quadrants I, II and III. Graph the equation to prove this.
In the year 2003, a company made $6.5 million in profit. For each consecutive year after that, their profit increased by 8%. How much would the company's profit be in the year 2007, to the nearest tenth of a million dollars?
Answer:
$8,580,000 (rounded) = $9,000,000
Step-by-step explanation:
Keep in mind, 2007 is four years after 2003.
So, 8(%) • 4 = 32(%)
Over the course of 4 years, the companies profits increased by a total of 32 percent.
(*Write 6.5m in standard form)
6,500,000 + 32% = $8,580,000
8,580,000 (rounded up) = 9,000,000
PLSSSS HELPPPPPPPPP MEEEEEEEEEEEEEE
=========================================================
Explanation:
Add up the first two frequencies to get 14+18 = 32
The table shows that the person rolled either a "1" or a "2" a total of 32 times, which is the amount of rolls getting less than "3".
This is out of the 200 rolls total.
32/200 = (8*4)/(8*25) = 4/25
In decimal form, this would be 4/25 = 0.16 which is exact.
What is the volume of a sphere with a diameter of 8.6 m, rounded to the nearest
tenth of a cubic meter?
Answer:
The volume of a sphere with a diameter of 8.6 m = 333.0 m^3
Step-by-step explanation:
What is the answer to this question?
What is the volume of this sphere?
Use ≈ 3.14 and round your answer to the nearest hundredth.
Radius = 8 mm
List all the ordered arrangements of 5 objects a, b, c, d, and e.
a. Choosing 2 at a time without repetition, but order counts.
b. Choosing 2 at a time without repetition, but order doesn't count.
c. Choosing 2 at a time with repetition. How many possible arrangements?
There are 5 * 5 = 25 possible arrangements. Some examples include aa, bb, cc, dd, ee, ab, ac, ad, ae, ba, bb, bc, bd, be, and so on.
a. Choosing 2 objects at a time without repetition and with order counting: The ordered arrangements of 5 objects (a, b, c, d, e) taken 2 at a time without repetition and with order counting are: ab, ac, ad, ae,
ba, bc, bd, be,
ca, cb, cd, ce,
da, db, dc, de,
ea, eb, ec, ed.
b. Choosing 2 objects at a time without repetition and without order counting: The unordered arrangements of 5 objects (a, b, c, d, e) taken 2 at a time without repetition and without order counting are: ab, ac, ad, ae,
bc, bd, be,
cd, ce,
de.
c.Choosing 2 objects at a time with repetition: In this case, we can choose any of the 5 objects for the first position, and any of the 5 objects (including repetition) for the second position.
Therefore, there are 5 * 5 = 25 possible arrangements. Some examples include aa, bb, cc, dd, ee, ab, ac, ad, ae, ba, bb, bc, bd, be, and so on.
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Simplify x + 6–3x – 8.
help me...
condition (0°≤A≤360°)
sin5A+sin3A=cos2A-cos6A
Answer:
this is your answer. i am not sure at all.
Answer:
Answer is in picture
Step-by-step explanation:
Hope it is helpful.....