2. What will be the extension of this spring if the load is a) 4N and b) 75 g?

Answers

Answer 1

Answer:

6

Explanation:

just add


Related Questions

A 0.0272 kg arrow is fired with a velocity of 87.3 m/s from a 0.0245 kg bow. Determine the equivalent impulse value imparted on the arrow. (hint: you can also use newton's third law of motion)* A.2.37 Ns
B.3.11 Ns
C.113.5 Ns
D.214.2 Ns​

Answers

The equivalent impulse value imparted on the arrow is 2.37 Ns,

option A

What is the impulse imparted?

The equivalent impulse value imparted on the arrow can be determined using the equation for impulse, which is given by;

Impulse = force x time.

Since the arrow is moving with a constant velocity, the time during which the force is applied can be determined using the principle of conservation of momentum. The change in momentum of the arrow-bow system is equal to the impulse applied to the arrow, and the force applied to the arrow is equal to the recoil force experienced by the bow.

The initial momentum of the arrow-bow system is equal to the mass of the arrow times its velocity. The final momentum of the arrow-bow system is equal to the mass of the bow times its recoil velocity.

The change in momentum of the arrow-bow system is given by:

Δp = pf - pi = (m_bow * v_recoil) - (m_arrow * v_arrow)

The impulse applied to the arrow is equal to the change in momentum of the arrow-bow system:

impulse = Δp = (m_bow * v_recoil) - (m_arrow * v_arrow)

Using the given masses and velocities, we can calculate the impulse:

impulse = (0.0245 kg) * (87.3 m/s) - (0.0272 kg) * (87.3 m/s) = 2.37 Ns

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A cylinder of gas has a frictionless but tightly sealed piston of mass M. A small flame heats the cylinder, causing the piston to slowly move upward. For the gas inside the cylinder, what kind of process is this?

Answers

Answer:

isobaric

Explanation:

According to the attached figure, the process would be isobaric as the gas would be expanded at the time when it maintains the constant pressure

The ideal gas law derives

PV = nRT

As the flame is there at the bottom side so atoms or molecules of gas would get heat up slowly also their temperature would be increased. Thus in the case when piston would not be permitted to move so the pressure would rise having maintaining the constant volume and after this the process could be isochronic but in the given case, the piston would be permitted to move slowly upward so that there is a rise in the volume. However, the gas particles would be adjust themselves in order to maintain constant pressure so the given process represent isobaric  

A cylinder of gas has a frictionless but tightly sealed piston of mass M. A small flame heats the cylinder,

Why are some areas in Europe seeing a partial solar eclipse while others are observing a total solar eclipse?

plz answer ASAP

Answers

Answer:

Objects between the source and observer produce possible shadows known as the umbra and the penumbra.

The umbra is a totally shadowed area, no light travels directly from the source to the observer.

The penumbra is a partially shadowed are where some of the source light travels directly to the observer an some of the source light is blocked from the observer (the object blocking the light is not a point object).

The question apparently refers to the differences seen by the observers.

If an object has a mass of 47 kg and it is moved 27 meters in 60 seconds, how much power was used?

Answers

Answer: 207 W

Explanation: I assumed here that the object is moved vertically. If that is the case, the work done on the object is equal to its change in gravitational potential energy:

where

m = 47 kg is the mass of the object

g = 9.8 m/s^2 is the acceleration of gravity

is the change in height

Substituting,

Now we can calculate the power used, which is given by

Hope this helps I'm sorry if i'm wrong but I tried :(

If an object has a mass of 47 kg and it is moved 27 meters in 60 seconds, how much power was used?

Find distance between two object of radius 6 cm and 2 cm

Answers

The distance between two objects of radius 6 cm and 2 cm is zero

To find the distance between two objects with radii of 6 cm and 2 cm, we need to consider the center-to-center distance between the objects and subtract the sum of their radii.

Let's denote the radii of the objects as r1 = 6 cm and r2 = 2 cm.

The distance between the centers of the objects can be represented as d = r1 + r2. Adding the radii ensures that we account for the space occupied by both objects.

Substituting the values, we have d = 6 cm + 2 cm = 8 cm.

Now, to find the actual distance between the objects, we subtract the sum of their radii from the center-to-center distance:

Distance = d - (r1 + r2) = 8 cm - (6 cm + 2 cm) = 8 cm - 8 cm = 0 cm.

The resulting distance is 0 cm, indicating that the objects are in direct contact with each other. This means that their surfaces are touching. When the distance between two objects is zero, it implies that they are overlapping or in physical contact. In this case, since the distance is equal to 0 cm, the two objects are touching each other, with their surfaces coming into contact.

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t: The toy car is given a push away from the origin and released. It continues to move with a constant velocity. Sketch the force g 0' after the car is released. A cart is moving toward the right and speeding up, as shown in the diagram below. Draw arrows above the cart representing the magnitudes and directions of the net (combined) forces you think are needed on the cart at t = 0 s, t = 1 s, etc., to maintain its motion with a steadily increasing velocity. Assume that the cart is already moving at t_1. Explain the reasons for your answers. If the positive direction is toward the right, what is the sign of the force at t = 2 s in Question

Answers

The car will move at a constant speed once it is unleashed, as is assumed. Hence, there is no acceleration. Newton's second law states that a straight line along zero will appear on the graph if F=ma=m(0)=0, F=0.

Acceleration is the rate at which an object changes its velocity. It is a vector quantity, which means it has both magnitude and direction. The standard unit of acceleration is meters per second squared (m/s²).

Acceleration can be caused by forces such as gravity, friction, and electromagnetism. When a force acts on an object, it causes a change in the object's motion, resulting in acceleration.

The relationship between acceleration, velocity, and time is described by the equation a = (v_f - v_i) / t, where a is acceleration, v_f is final velocity, v_i is initial velocity, and t is time.

The effects of acceleration can be seen in everyday experiences, such as feeling pushed back into your seat when a car accelerates or feeling weightless during freefall. Understanding acceleration is important in fields such as physics, engineering, and transportation.

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A uniform rod of mass 3.40×10−2 kg
and length 0.430 m
rotates in a horizontal plane about a fixed axis through its center and perpendicular to the rod. Two small rings, each with mass 0.250 kg
, are mounted so that they can slide along the rod. They are initially held by catches at positions a distance 5.30×10−2 m
on each side from the center of the rod, and the system is rotating at an angular velocity 35.0 rev/min
. Without otherwise changing the system, the catches are released, and the rings slide outward along the rod and fly off at the ends.

Answers

We can use the conservation of angular momentum to address this issue. We may translate the initial angular velocity of the system, which is 35.0 rev/min, to radians per second.

Is it possible for a homogeneous rod with mass m and length l to revolve in the vertical plane around a straight horizontal axis?

A homogeneous rod with a mass of m and a length of l is capable of rotating in the vertical plane around a straight horizontal axis that is at point H.

Can a 1.25 m uniform rod rotate around a horizontal?

A homogeneous rod of 1.25 m in length has a rotational potential about an axis that passes through O in a vertical plane. a consistent disc of same mass and diameter same as.

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Which statement is true regarding the waves shown?
A)
Doubling the frequency of the bottom waves by will cause it to match the
top waves.
B)
Cutting the frequency of the bottom waves in half will cause it to match
the top waves
C)
There is no way to match the bottom and top waves to the same frequency.
D)
Decreasing the frequency of the top waves by half will cause it to match
the bottom waves.

Answers

Answer:

The correct answer is B)

Cutting the frequency of the bottom waves in half will cause it to match top waves.

Explanation:

USATESTPREP

Cutting the frequency of the bottom waves will cause it to match the top waves. So the correct option is B.

What are waves?

A propagation of disturbance, from one point to another point is called a wave. Waves are either mechanical or non-mechanical. Electromagnetic waves are non-mechanical waves.

The mechanical waves cannot travel without a medium e.g sound waves. Non-mechanical waves do not require a medium to travel, this means that they can even travel through a vacuum.

Waves are of two types. Transverse waves and longitudinal waves.

If the direction of propagation of wave is perpendicular to the direction of movement of particles of the medium, it results in a transverse wave.

If the direction of propagation of wave is parallel to the direction of movement of particles in a medium, it results in a longitudinal wave.

Five properties of waves are amplitude, frequency, wavelength, time period and speed.

Maximum displacement from the mean position is the amplitude. The number of vibrations in a fixed point in unit time is the frequency. The distance between two identical points is the wavelength. Time taken by a wave to pass through a point is the time period and the distance travelled between particular points in a unit of time is the speed.

Therefore the correct option is B.

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What causes the difference in the angle of the sun on the Earth's surface throughout the year?

Answers

Answer:

The axis is tilted and points to the North Star no matter where Earth is in its orbit. Because of this, the distribution of the Sun's rays changes. ... It also means that the angle at which sunlight strikes different parts of Earth's surface changes through the year.

Explanation:

Pls sub to bdoggaming if this helped

Let to the right be the positive direction.
A 25.8 g marble sliding to the right at 21.0
cm/s overtakes and collides with a 12.4 g
marble moving in the same direction at 13.8
cm/s. After the collision, the 12.4 g marble
moves to the right at 23.9 cm/s.
Find the velocity of the 25.8 g marble after
the collision.
Answer in units of cm/s. Answer in units
of cm/s.

Answers

The final velocity of the 25.8 g marble after the collision is 16.15 cm/s.

What is the velocity of the 25.8 g marble after the collision?

The velocity of the 25.8 g marble after the collision is calculated as follows;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

where;

m₁ is the mass of 25.8 g marblem₂ is the mass of 12.4 g marbleu is their initial speedsv is their final speeds

The final velocity of the 25.8 g marble after the collision is calculated as;

( 25.8 x 21 ) + ( 12.4 x 13.8 ) = ( 12.4 x 23.9 ) + ( 25.8v )

712.92 = 296.36 + 25.8v

25.8v = 416.56

v = 416.56 / 25.8

v = 16.15 cm/s

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8. A graph of a car's motion is shown below

Answers

From the graph of the motion of the car, the deceleration of the car is -1.5 m/s².

What is motion?

Motions is defined as the change in the position of a body.

There are several forms of motion that a body can undergo, they include:

translational motion - this is motion along a straight lineCircular or rotational motion - this is motion of a body in a circular pathOscillatory motion - this is a periodically repeating motion of a bodyRandom motion - this is the haphazard motion of a body.

Considering the motion graph of the car as shown, the car undergoes a translational motion in a straight path. The car changes its speed over time.

Between O and A, the speed of the car increases steadily, and this part is known as acceleration.

Between A and, the car moves with constant speed.

Between B and C, the speed of the car steadily decreases which is known as deceleration.

deceleration= change in speed/ change in time

The deceleration of the car = (0 - 30) / (50 - 30)

The deceleration of the car =-1.5 m/s²

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Complete question:

A graph of a car's motion is shown below. What is the deceleration of the car from B to C​?

8. A graph of a car's motion is shown below

Describe the phenomenon of lightning?​

Answers


Lightning is a naturally occurring electrostatic discharge during which two electrically charged regions in the atmosphere or ground temporarily equalize themselves, causing the instantaneous release of as much as one gigajoule of energy.

The velocity time graph of an object mass 50 g is shown in figure study graph and answer
1)calculate force acting on object in time interval 0-3 seconds
2)calculate the force acting on the object in the time interval 6-10 seconds 
3)Is there any time interval in which no force acts on object.Justify

The velocity time graph of an object mass 50 g is shown in figure study graph and answer1)calculate force

Answers

1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

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Compare the rate of loss of heat from a metal sphere at 827°C with the rate of loss of heat from the same sphere at 427°C,if the temperature of the surrounding is 27°C​

Answers

Answer:

The rate of heat loss from the metal sphere at 827°C is twice the rate of heat loss from the same sphere at 427°C.

Explanation:

The rate of heat loss from an object can be determined using Newton's law of cooling, which states that the rate of heat loss is proportional to the temperature difference between the object and its surroundings. Mathematically, this is expressed as...     

\(Q = k \Delta T\)

Where...

"Q" is the heat loss/gain"k" is the constant of proportionality which is the cooling constant "ΔT" is the change in temperature

\(\hrulefill\)

For the sphere at 827°C:

\(\Delta T_1= 827\°C - 27\°C \\\\\Longrightarrow \boxed{\Delta T_1=800\°C}\)

For the sphere at 427°C:

\(\Delta T_2= 427\°C - 27\°C \\\\\Longrightarrow \boxed{\Delta T_2=400\°C}\)

Assuming that the cooling constant k remains constant, we can compare the rates of heat loss.

\(\dfrac{Q_1}{Q_2} =\dfrac{\Delta T_1}{\Delta T_2}\\\\\Longrightarrow \dfrac{Q_1}{Q_2} =\dfrac{800\textdegree C}{400\textdegree C} =\boxed{2}\)

Thus, the rate of heat loss from the metal sphere at 827°C is twice the rate of heat loss from the same sphere at 427°C when the temperature of the surroundings is 27°C.

The earth has a vertical electric field at the surface,pointing down, that averages 102 N/C. This field is maintained by various atmosphericprocesses, including lightning.
What is the excess charge on the surface of the earth? inC

Answers

Answer:

\(q = -461532.5 \ C\)

Explanation:

From the question we are told that

     The  electric filed is  \(E = 102 \ N/C\)  

Generally according to Gauss law

=>   \(E A = \frac{q}{\epsilon_o }\)

Given that  the electric field is pointing downward  , the equation become

    \(- E A = \frac{q}{\epsilon_o }\)

Here   \(q\) is the excess charge on the surface of the earth

          \(A\) is the surface  area of the of the earth which is mathematically represented as

     \(A = 4\pi r^2\)

Where r is the radius of the earth which has a value \(r = 6.3781*10^6 m\)

 substituting values

    \(A = 4 * 3.142 * (6.3781*10^6 \ m)^2\)

    \(A =5.1128 *10^{14} \ m^2\)

So

   \(q = -E * A * \epsilon _o\)

Here \(\epsilon_o\) s the permitivity of free space with value

          \(\epsilon_o = 8.85*10^{-12} \ m^{-3} \cdot kg^{-1}\cdot s^4 \cdot A^2\)

substituting values

     \(q = -102 * 5.1128 *10^{14} * 8.85 *10^{-12}\)

     \(q = -461532.5 \ C\)

WILL REWARD 20 more pts once solved

4) If you have a diverging lens with a focal length of -15 cm and it produces an image that is 9
cm from the lens, what is the height of the image if the object was 4,5 cm tall?
b) Draw a ray tracing diagram of the situation below (label all points in cm) :

Answers

Explanation:

step 1. a diverging lens is "concave" on both side and always has a negative focal length

step 2. so 1/f = 1/s + 1/s' where f is the focal length, s is the object location, and s' is the image location (f, s, s' are all on the left side of the lens)

step 3. 1/-15 = 1/s + 1/-9 (image is virtual (negative))

step 4. 3/-45 = 1/s + 5/-45

step 5. s = 22.5cm (object is 22.5cm from lens)

step 6. s'/s = 9/22.5 ÷ 0.4 (magnification)

step 7. if the object is 4.5cm then the image is 4.5(0.4) = 1.8cm tall.

b. Density and relative density.​

b. Density and relative density.

Answers

Explanation:

density, mass of a unit volume of a material substance. The formula for density is d = M/V, where d is density, M is mass, and V is volume. Density is commonly expressed in units of grams per cubic centimetre.

The relative density of a substance is defined as the ratio of the density of that substance to the density of water at 4oC. It is also defined as the ratio of the mass of substance to the mass of equal volume of water at 4oC. i.e., R.D. = Mass of the substance / mass of an equal volume of water at 4oC

Given the list of items, select all that are considered to be matter:
music
heat
air
dreams
water
gasoline
love
bacteria
thoughts

Answers

From the given list of items, examples of matter include, heat, air, water, gasoline, and bacteria.

What is matter?

Matter is a substance made up of various types of particles that occupies physical space and has inertia.

A matter must have mass and occupy space.

Examples of matter include the following;

heatairwatergasolinebacteria

Thus, from the given list of items, examples of matter include, heat, air, water, gasoline, and bacteria.

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PLEASE HELP ME!!!1

Differentiate between the distance and displacement for an object that started at point A and traveled as shown to point B.


Distance: _____ units and Displace: _____ units to the left.

PLEASE HELP ME!!!1Differentiate between the distance and displacement for an object that started at point

Answers

"Distance" here is the total distance traveled along the red path (see attached) from point A to point B. Just count how many how sides of each square in the grid are touched by the path. Then distance = 24 units.

"Displacement" is the net distance covered by moving from point A to point B, or the length of the green path. So displacement = 2 units to the right. Of course, your question seems to ask for the displacement in terms of units to the left, in which you could say -2 units to the left.

PLEASE HELP ME!!!1Differentiate between the distance and displacement for an object that started at point

An object of 31.3 kg is at rest. You apply a constant force to this object and the object moves a distance of 103 m in 13 s. find the acceleration produced by your force.

Answers

The acceleration produced by your force is determined as 1.22 m/s².

What is the acceleration of the object?

The acceleration of the object is the rate of change of its velocity with time.

Apply the following kinematic equation to solve the acceleration of the object.

s = vt + ¹/₂at²

where;

s is the distance travelled by the objectv is the initial velocity of the object = 0t is the time of motion of the objecta is the acceleration of the object

s =  ¹/₂at²

103 =  ¹/₂a(13)²

103 = 84.5a

a = 103/84.5

a = 1.22 m/s²

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why does liquid candle wax flow but solid candle wax does not?

Answers

Answer:

Because the matter in solid objects doesn't move

Explanation:

Logic

Velocity problem 3: How far away can you run away from a lion if you travel at 3 m/s west and
you have only 15 seconds?

Answers

Answer Explanation:

d = vt

You will be 3(15) = 45 m west of where you began.

As we do not know where the lion is to begin with, it's hard to say where we will end up relative to it.

A 17-kg

piece of metal displaces 2.8 L

of water when submerged. what is its density?

Answers

Answer: Density = 6071.428571 kg/m³

Explanation: Given that mass m=17 kg

volume displaced v=2.8L

We know that

density = mass/volume

Here density=17kg/2.8L

Also 1L=1000m³ Hence

density=17kg/2.8×10⁻³m³

           =6071.428571 kg/m³

The net force on a box F as a function of the vertical position y is shown below.
What is the work done on the box from y=0 to 6.0m?

The net force on a box F as a function of the vertical position y is shown below.What is the work done

Answers

The work done on the box from y=0 to 6.0m is 120 J.

To calculate the work done on the box from y=0 to 6.0m, we need to find the area under the force vs. position graph over that interval.

First, we can find the work done from 0 m to 2 m. Since the force is constant at 40 N over this interval, the work done is simply:

W = F * d = 40 N * 2 m = 80 J

From 2 m to 6 m, the force is constant at -20 N, so the work done is:

W = F * d = (-20) N * 4 m = -80 J

Note that the negative sign indicates that the work is done by the box on the force (since the force is in the opposite direction of the displacement).

Therefore, the total work done on the box from y=0 to 6.0m is:

W_total = 80 J - 80 J = 0 J

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A lightbulb manufacturer makes bulbs with different "color temperatures," meaning that the spectrum of light they emit is similar to a blackbody with that temperature. Assuming the emitting areas of the filaments in two bulbs with color temperatures of 2,000 K and 4,000 K are the same, which of the two is the brighter?

Answers

Answer:

The bulb with higher temperature(4000 K) will be brighter

Explanation:

From the question we are told that

     The color temperature  for first bulb is  \(T_1 = 2000K\)

        The color temperature  for second bulb is  \(T_2 = 4000K\)

Generally the emission power of black body radiation is mathematically represented as

     \(E = \sigma T^4\)

Where  \(\sigma\) is the Stefan-Boltzmann constant  with a value \(\sigma = 5.67 * 10^{-8} W m^{-2} K^{-4.}\)

Now for \(T_1 = 2000K\)

      \(E_1 = 5.67*10^{-8} * (2000)^4\)

       \(E_1 = 907.2 \ W/m^2\)

At  \(T_2 = 4000K\)

       \(E_2 = 5.67*10^{-8} * 4000\)

        \(E_2 = 14515.2 \ KW/m^2\)

Looking at the result we got we see that  the emission power  for the higher temperature bulb is higher, this means that its power to emit in the visible spectrum range would be higher  

So the bulb with higher temperature will be brighter

       

Explain what the modern model of an atom looks like. Include the relative masses and volumes of the various parts of the atom.

Answers

How can the modern model of the nuclear atom be described?

Rutherford's atomic model became known as the nuclear model. In the nuclear atom, the protons and neutrons, which comprise nearly all of the mass of the atom, are located in the nucleus at the center of the atom. The electrons are distributed around the nucleus and occupy most of the volume of the atom.

.A car skid for 290 m. assuming that the car skidded to a stop with a constant
acceleration of -3.90 m/s2
, determine the speed of the car before it began to
skid

Answers

Answer:

The speed of the car before it began to skid is 47.56 m/s.

Explanation:

We can use kinematics to solve this problem.

We are given three known variables:

Δx = 290 ma = -3.90 m/s²v = 0 m/s (final velocity is 0 m/s because the car skids to a stop).

We can use this kinematic equation to solve for the initial velocity, v₀.

v² = v₀² + 2aΔx

Substitute the known variables into the equation.

(0)² = v₀² + 2(-3.9)(290)0 = v₀² - 22622262 = v₀²v₀ = 47.56 m/s

The speed of the car before it began to skid is 47.46 m/s.

What happens to the atomic number of an atom when the number of neutrons in the nucleus of that atom increases? a It decreases b It increases c It doubles d It remains the same

Answers

Answer:

It remains the same

Explanation:

It remains the same. This is because the number of protons doesn't change and the number of protons determines the atomic number.

Which set of changes is most likely to cause the current in an electrical circuit
to stay the same?
A. Decreasing voltage and keeping resistance constant
B. Increasing voltage and increasing resistance
C. Increasing voltage and keeping resistance constant
D. Keeping voltage constant and increasing resistance

Answers

Answer:

D: keeping voltage constant and increasing resistance.

Explanation:

The current in an electrical circuit is determined by Ohm's law, which states that the current is directly proportional to the voltage and inversely proportional to the resistance.

Mathematically, Ohm's law can be expressed as:

I = V/R

where I is the current, V is the voltage, and R is the resistance.

We need to make sure that the right-hand side of the equation remains constant to keep the current in the circuit the same. Therefore, we can look at each set of changes and see how they affect the right-hand side of the equation.

A. Decreasing voltage and keeping resistance constant:

If we decrease the voltage (V) and keep the resistance (R) constant, the right-hand side of the equation becomes smaller. This means that the current (I) will also decrease, so this set of changes will not cause the current to stay the same.

B. Increasing voltage and increasing resistance:

If we increase both the voltage (V) and resistance (R), the right-hand side of the equation can go either way, depending on which one increases more. However, in most cases, the current (I) will increase, so this set of changes will not cause the current to stay the same.

C. Increasing voltage and keeping resistance constant:

If we increase the voltage (V) and keep the resistance (R) constant, the right-hand side of the equation becomes larger. This means that the current (I) will also increase. Therefore, this set of changes will not cause the current to stay the same.

D. Keeping voltage constant and increasing resistance:

If we keep the voltage (V) constant and increase the resistance (R), the right-hand side of the equation becomes smaller. This means that the current (I) will decrease. Therefore, this set of changes is most likely to cause the current in an electrical circuit to stay the same.

So, the correct answer is D: keeping voltage constant and increasing resistance.

A heat engine is used to convert heat into which of the following?

Answers

What are the options?

Answer:

work

Explanation:

Other Questions
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