2. What is the approximate wind speed in a tornado? Explain why tornado wind speeds are not considered in determining the design wind speed for a location.

The mass of block #2 when a 4 kg block on the left is pulled up by a falling second block on the right, and the acceleration is 3 m/s² is 5 kg.

Mass of block #1 (m1) = 4 kg

Acceleration (a) = 3 m/s²

Let the mass of block #2 be (m2).

The equation:

Acceleration (a) = Force (F) / Mass (m)

Mass of block #1 = 4 kg

Weight of block #1 = 4 kg × 9.8 m/s²

= 39.2 N

Weight of block #2 = m2 × 9.8 m/s²

As per Newton's second law,

Total force = mass × acceleration

For block #1,

Total force = Weight of block #1

For block #2,

Total force = Weight of block #2

Net force = (Weight of block #2 - Weight of block #1)

Net force = m2g - 39.2 (where g = 9.8 m/s²)

Also, net force = Total force / Total mass

Net force = (m1 + m2) a

= m2g - 39.2

We need to find the mass of block #2 (m2), after substituting values, it becomes(4 + m2) × 3

= m2 × 9.8 - 39.23m2 - 9.8m2

= 39.2 + 12m2

= 5 kg

Therefore, the mass of block #2 is 5 kg.

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The index of refraction of this substance is 1.296.

The index of refraction of a substance is a measure of how much the speed of light is reduced when it passes through that substance compared to its speed in a vacuum. It can be calculated using the formula:

index of refraction = speed of light in a vacuum / speed of light in the substance.

In this question, the distance traveled by light in the substance is given as 0.926 m, and the time taken is given as 4.00 ns. To find the speed of light in the substance, we need to divide the distance by the time:

speed of light in the substance = distance / time.

Now we can substitute the values given in the question:

speed of light in the substance = 0.926 m / 4.00 ns.

However, the speed of light is commonly expressed in meters per second (m/s), so we need to convert the time from nanoseconds to seconds. There are 1 billion nanoseconds in a second, so:

time in seconds = 4.00 ns / 1 billion.

Now we can substitute this value into the equation:

speed of light in the substance = 0.926 m / (4.00 ns / 1 billion).

Simplifying the equation, we can multiply the numerator and denominator by 1 billion:

speed of light in the substance = (0.926 m * 1 billion) / 4.00 ns.

Calculating this value, we get:

speed of light in the substance = 231.5 * 10^6 m/s.

Now we need to find the speed of light in a vacuum. The speed of light in a vacuum is approximately 3 * 10^8 m/s.

Finally, we can calculate the index of refraction using the formula mentioned earlier:

index of refraction = speed of light in a vacuum / speed of light in the substance.

Substituting the values, we get:

index of refraction = (3 * 10^8 m/s) / (231.5 * 10^6 m/s).

Simplifying the equation, we divide the numerator and denominator by 10^6:

index of refraction = 300 / 231.5.

Calculating this value, we find that the index of refraction of this substance is approximately 1.296.

So, the index of refraction of this substance is 1.296.

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i think "Barsaman Pun"

Explanation:

BARSAMAN PUN IS THE CURRENT ELECTRIC MINISTER OF NEPAL.

Answer:

have a greater mechanical advantage

Explanation:

this enables the mechanism to output a large amount of force compared to the force put into it due to ratio of the wheel and the axle therefore providing enough force to steer the rather heavy wheels while saving the driver some muscle power

Answer:

76 N north-east

Explanation:

V = √(44²+62²) = 76 N

I would say the answer is 3 because by falling technically the ball would be kind of moving in the air. Plus potential energy is when for example a soccer ball isnt moving

Answer:

friction doesn't let the desk move.

Explanation:

the law of motion states any object in motion should stay in motion.

Answer:

I think its false

Explanation:

It doesn't make sense that the doctor found it in her stool

The main factor that determines the stages of a star after the main sequence is the star mass. Depending on the mass, stars will develop as average stars -low mass- or giant stars -high mass-.

The star cycle is the sequence of changes that a star undergoes throughout its existence

Stars are born from the nebula, which is dust and gas particles condensation due to the gravity effect in the interstellar clouds.

These stellar clouds collapse and compose smaller regions, each of which later contracts and compose the stellar cores. This is a more advanced level of condensation.

Stelar cores are protostars that contract and increase their temperature until nuclear reactions occur. Hydrogen is converted into Helium and the new star gets born.

This new star is in its main sequence, which is the equilibrium point between gravity and nuclear fusion, which helps the star keeps stable as long as the fuel lasts.

Stars spend most of their lives in the main sequence until all hydrogen turns into helium and there is no more fuel left.

At this point, the star is a subgiant, and its core begins its contraction, increasing the star's temperature.

The star increases in size and luminosity, turning into a giant.

After the subgiant stage, the star enters a giant phase. The star can reach a size up to 100 times its current size.

When the core reaches a certain temperature, helium turns into carbon.

The following events depend on the star mass.

When average-sized stars run out of fuel, the red giant begins to disintegrate, losing its outer layers and exposing its core, which will become a white dwarf.

When fuel is over in the star, the gravitational collapse produces an explosion originating the supernova.

This neutron star is a celestial body that remains as a remnant after the explosion giving rise to a supernova.

In these cases, if the star core has a mass > 3 solar masses, the star collapses into a black hole.

In conclusion, the main factor that determines the stages a star follows after the main sequence is the star mass. Depending on the mass, stars will develop as average stars -low mass- or giant stars -high mass-.

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Answer:

electrons i think

Explanation:

The lowest energy level of a certain quantum harmonic oscillator is 5.00 ev. The energy of the next higher level of the quantum harmonic oscillator is 10.00 ev.

The energy levels of a quantum harmonic oscillator are quantized, meaning that they can only exist at certain discrete energy values. The energy difference between these levels is given by the equation E = (n + 1/2)hν, where E is the energy of the level, n is the quantum number, h is Planck's constant, and ν is the frequency of the oscillator.  

In this case, we know that the lowest energy level has an energy of 5.00 ev. Using the equation above, we can solve for the energy of the next higher level by plugging in n = 1 (since we are looking for the next level), h = 4.136 × 10^-15 eV·s (Planck's constant), and ν = ? (unknown frequency).

Solving for E, we get:
E = (1 + 1/2)hν
E = 3/2 hν
Since we don't know the frequency, we can't solve for E directly. However, we do know that the energy of the next level must be twice that of the lowest level (since the energy difference between levels is constant). Therefore, the energy of the next level is:
E = 2 × 5.00 ev
E = 10.00 ev

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Jamie is measuring Gary's response time, which is the time it takes for Gary to react to the fire alarm and start moving towards the exit.

It is a measure of the time it takes for a person to respond to a given stimulus, such as a fire alarm, and initiate a response. Response time is often studied in various fields, including psychology, neuroscience, and human factors engineering, as it can provide insights into cognitive and behavioral processes and performance. It can also be used to evaluate the effectiveness of warning signals and other safety measures in emergency situations.which is the time it takes for Gary to react to the fire alarm and start moving towards the exit.

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a) The magnetic field around a wire carrying current can be represented using concentric circles centered on the wire. The direction of the magnetic field lines can be determined using the right-hand rule: if you wrap your right hand around the wire with your thumb pointing in the direction of the current, your curled fingers will indicate the direction of the magnetic field.

b) To calculate the strength of the magnetic field, we can use the equation:

Force = Magnetic field strength × Current × Length

Plugging in the given values, we have:

0.55 N = Magnetic field strength × 6.8 A × 0.15 m

Solving for the magnetic field strength, we find:

Magnetic field strength = 0.55 N / (6.8 A × 0.15 m)

Calculating the numerical value, we can determine the strength of the magnetic field.

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From the information provided, the energy lost to friction if the motorcycle only gains an altitude of 21 m before coming to rest is approximately 65,954.64 J.

To calculate the energy lost to friction, we need to first determine the initial total mechanical energy of the motorcycle and the final total mechanical energy of the motorcycle after it has climbed to a height of 21 meters and come to rest. The difference between the initial and final energies will give us the energy lost to friction.

The initial total mechanical energy of the motorcycle is given by:

Ei = (1/2)mv² + mgh + 2(1/2)Iw²

where m is the mass of the motorcycle, v is its initial speed, h is the height it climbs, g is the acceleration due to gravity, I is the moment of inertia of the wheels, and w is their initial angular velocity.

We need to calculate the moment of inertia of each wheel:

I = (1/2)mr²

where m is the mass of the wheel and r is its radius. Substituting the given values, we get:

I = (1/2)(12 kg)(0.33 m)² = 0.6534 kg m²

The initial angular velocity of each wheel is not given, so we can assume that it is initially at rest (i.e., w = 0).

Substituting the given values into the equation for E, we get:

Ei = (1/2)(180 kg)(25 m/s)² + (180 kg)(9.81 m/s²)(36 m) + 2(1/2)(0.6534 kg m²)(0)²

= 101,812.44 J

The final total mechanical energy of the motorcycle is given by:

Ef = mgh

where m, g, and h are as before, and the speed and rotational energy of the wheels are both zero.

Substituting the given values, we get:

Ef = (180 kg)(9.81 m/s²)(21 m) = 35,857.8 J

The energy lost to friction is the difference between the initial and final energies:

Energy lost = Ei - Ef = 101,812.44 J - 35,857.8 J = 65,954.64 J

Question - Suppose a 180 kg motorcycle is heading toward a hill at aspeed of 25 m/s. The two wheels weigh 12 kg each and are each annular rings with an inner radius of 0.280 m and an outer radius of 0.330 m. Randomized Variables m 180 kg ˇ-25 m/s h 36 m. how much energy is lost to friction if the motorcycle only gains an altitude of 21 m before coming to rest?

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In the given setup, the image of the converging lens is formed 12 cm behind it, and the final image is formed 144/13 cm behind the diverging lens.

A) In the model shown in Fig.34.43b, where the lenses are separated by 8 cm, the image of the converging lens (f1=12 cm) is formed at a distance behind the converging lens. This distance can be determined using the lens formula:

1/f1 = 1/v1 - 1/u1,

where f1 is the focal length of the converging lens and u1 is the object distance.

Since the object is assumed to be at infinity (distant object), the object distance u1 is equal to infinity. Plugging these values into the lens formula, we get:

1/f1 = 1/v1 - 1/infinity.

As 1/infinity approaches zero, the equation simplifies to:

1/f1 = 1/v1.

Rearranging the equation, we find:

v1 = f1 = 12 cm.

Therefore, the image of the converging lens is formed at a distance of 12 cm behind the lens.

B) The image formed by the converging lens (v1 = 12 cm) serves as the object for the diverging lens. The object distance for the diverging lens (f2 = -12 cm) is equal to the image distance of the converging lens, which is 12 cm.

C) To determine the position of the final image, we can use the lens formula for the diverging lens:

1/f2 = 1/v2 - 1/u2,

where f2 is the focal length of the diverging lens and u2 is the object distance.

Substituting the given values, we have:

1/-12 = 1/v2 - 1/12.

Simplifying the equation, we find:

-1/12 = 1/v2 - 1/12.

Combining the fractions, we get:

-1/12 = (12 - v2) / (12v2).

Cross-multiplying and rearranging the equation, we find:

v2 = 144/13 cm.

Therefore, the final image is formed at a distance of 144/13 cm behind the diverging lens.

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Answer:

ntensive properties: A physical property that will be the same regardless of the amount of matter.

Explanation:

(a)The pressure at B is 0.1248 atm.

(b)The temperature at C is 727.1 K.

(c)The total work done by the gas in one cycle is -1979J

General calculation:

We can use the First Law of Thermodynamics to analyze the heat engine cycle:

ΔU = Q - W

where ΔU is the change in internal energy, Q is the heat added to the system, and W is the work done by the system. For a complete cycle, ΔU = 0, so:

Q = W

We can also use the ideal gas law to relate the pressure, volume, and temperature of the gas:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the absolute temperature.

(a)How to find the pressure at B segment?

To find the pressure at B, we can use the fact that the segment AB is an isothermal expansion. This means that the temperature remains constant, so:

PV = nRT

PB = (nRT)/(2V) = (2.00 mol)(0.0821 L·atm/mol·K)(600 K)/(2V) = (0.0821 L·atm/mol)(600 K)/V

Since the pressure at A is 5.00 atm, we can use the fact that the temperature is constant to find the volume at A:

PV = nRT

VA = (nRT)/P = (2.00 mol)(0.0821 L·atm/mol·K)(600 K)/5.00 atm = 197.76 L

Since the volume at B is twice the volume at A, we have:

VB = 2VA = 395.52 L

Substituting into the expression for PB, we get:

PB = (0.0821 L·atm/mol)(600 K)/395.52 L = 0.1248 atm

Therefore, the pressure at B is 0.1248 atm.

To find the temperature at C, we can use the fact that the segment BC is an adiabatic expansion. This means that no heat is added or removed from the system, so:

\(PV^\gamma\)= constant

where γ is the ratio of specific heats (for a monoatomic gas, γ = 5/3). We can use the fact that the volume at C is equal to the volume at A to find the pressure at C:

\(PAV^\gamma = PCV^\gamma\)

PC =  \(PA(V/A)^\gamma\) = 5.00 atm\((1/2)^(^5^/^3^)\) = 1.556 atm

Since the segment BC is adiabatic, the temperature changes but no heat is added or removed from the system. Using the ideal gas law, we can relate the pressure, volume, and temperature:

PV = nRT

TC = (PCVC)/(nR) = (1.556 atm)(197.76 L)/(2.00 mol)(0.0821 L·atm/mol·K) = 727.1 K

Therefore, the temperature at C is 727.1 K.

The total work done by the gas in one cycle is the sum of the work done in each segment of the cycle:

W = WAB + WBC + WCD + WDA

For segment AB, the work done is:

WAB = -QAB = -∫PdV = -nRT∫(1/V)dV = -nRT ln(VB/VA) = -(2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2) = -602 J

For segment BC, the work done is:

WBC = -QBC = -∫PdV = -nγRT∫(1/V)dV = -nγRT

We know that VB = 2VA and VC = 2VD, so we can express the ratio VB/VC in terms of VA/VD:

VB/VC = (2VA)/(2VD) = VA/VD

Substituting into the expression for WBC, we get:

WBC = -nγRT ln(VA/VD)

For segment CD, the work done is:

WCD = -QCD + PCDΔV = -nCpΔT + PCDΔV

where Cp is the specific heat at constant pressure, ΔT is the change in temperature, and ΔV is the change in volume. We know that the segment CD is isobaric, so ΔV = VB - VA = (2VA) - VA = VA. We can also use the ideal gas law to relate the pressure, volume, and temperature:

Substituting into the expression for WCD, we get:

WCD = -nCpΔT + (nRT/VD)VA = -nCp(TC - TD) + (nRT/VD)VA

For segment DA, the work done is:

WDA = -QDA + ΔU = -nCvΔT

where Cv is the specific heat at constant volume. We know that the segment DA is isovolumetric, so ΔV = 0. Using the First Law of Thermodynamics, we know that ΔU = 0 for a complete cycle, so:

QDA = -WDA = nCvΔT

Substituting into the expression for WDA, we get:

WDA = -nCvΔT

Adding up the work done in each segment, we get:

W = WAB + WBC + WCD + WDA

= -(2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2)- (2.00 mol)(5/3)(0.0821 L·atm/mol·K)(727.1 K) ln(VA/VD)- (2.00 mol)(Cp)(TC - TD) + (2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2)- (2.00 mol)(Cv)(TC - TA)

We know that Cp and Cv for a monoatomic gas are related by Cp = Cv + R, so we can express Cp in terms of Cv:

Cp = Cv + R = (3/2)R + R = (5/2)R

Substituting and simplifying, we get:

W = (2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2)- (2.00 mol)(5/3)(0.0821 L·atm/mol·K)(727.1 K) ln(VA/VD)- (2.00 mol)(5/2)(0.0821 L·atm/mol·K)(727.1 K)+ (2.00 mol)(5/2)(0.0821 L·atm/mol·K)(600 K)

W = -966.2 J - 4957 J - 7476 J + 5154 J

    = -1979 J

Therefore, the total work done by the gas in one cycle is -1979 J

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Answer:

f=1.5MHz or f=1500Hz

Explanation:

f=v/λ

3×10⁸/2×10-⁵

f=1500Hz

f=1.5MHz

Answer:

(a) The aspect of the upper string supporting the weight and the applied force

Student 1 is correct because the upper string is the source of support of the large weight and the force applied to the short string reacts at the support of the long string

(b) The aspect of Student's (2) reasoning that is correct is that the shorter piece of string will always break first, however, the statement is only true for sudden pull due to the increased force experienced by the shorter string from a more rapid change in momentum

(c) The aspect of Student 1's statement that is incorrect is the that the upper string will always break first

The aspect of Student 2's statement that is incorrect is the that the shorter piece of string will always break first

(d) A string will break when subject to a force equivalent to its breaking force. The force experienced by the string increases as the rate of pull (suddenness) increases and the suddenness increases inversely with the length of the string, as such the shorter lower string will break first from a sudden pull before the force of the pull is completely transmitted to the upper string. Whereby the lower string is slowly pulled, the force is evenly transmitted to the upper string which is then taking up the load of the weight and the applied force together and is likely to break first

Explanation:

The following information is provided in the problem: A sled with a weight of 19.7 kg is pulled with a force of 42.0 N at an angle of 43.0° across ground where μ₁ = 0.130. We need to find out the normal force that is exerted on the sled.

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Answer:

 u = - 40 ft / s

Explanation:

The Galilean relation for the relative velocity is

         v ’= v + u

where u is the speed between the two reference frames, v is the speed of the fixed system and v 'the speed of the mobile system.

In this case the truck has a speed with respect to the ground (fixed system) 0 m / s (it is stopped), the car has a speed with respect to the ground of v = 40 ft / s,

        u = v'- v

        u = 0 - 40

        u = - 40 ft / s

the speed perceived by the car if the system is fixed on it is -40 ft / s

To determine the resistance in SI units that you need to set the cycle ergometer to, given that you want to have a subject exercise at 125 watts with an RPM of 60 for 3 minutes, follow the steps below:

Step 1: Determine the energy used in Joules during the 3 minutes at 125 watts.

P = W / tWhere:

P = power (125 watts)t = time (3 minutes converted to seconds

= 3 × 60 = 180 seconds)

W = energy used in Joules (to be determined)

Substituting the given values:

P = W / t125

= W / 180W

= 125 × 180W

= 22,500 Joules

Step 2: Determine the work done (in Joules) per revolution (360 degrees).

Work done per revolution = energy used in Joules / number of revolutions per minute / 60

Where:number of revolutions per minute = RPM / 60

Substituting the given values:

Work done per revolution = 22,500 / (60 / 60) / 360

Work done per revolution = 22,500 / 1 / 360

Work done per revolution = 22,500 × 360

Work done per revolution = 8,100,000 Joules

Step 3: Determine the torque needed to perform one revolution (360 degrees) of the pedals in SI units (N-m).Torque = work done per revolution / (2 × π)

Where:

2 × π = 6.2832

Substituting the given values:Torque = 8,100,000 / 6.2832

Torque = 1,288,684.08 N-m

Step 4:

Determine the resistance (force) needed at the pedals in Newtons (N) to produce the required torque.Resistance = Torque / pedal radius

Where:pedal radius = 0.175 m (average for a cycle ergometer)

Substituting the given values:

Resistance = 1,288,684.08 / 0.175

Resistance = 7,358,971.89 N (Newtons)

Therefore, you would need to set the resistance to 7,358,971.89 N (Newtons) on the cycle ergometer to achieve the desired subject exercise at 125 Watts with an RPM of 60 for 3 minutes.

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To learn the equilibrium and temperature.

What is equilibrium?

When Newton's first law is true, the equilibrium state of an object is present. When all external forces (including moments) operating on an object in a reference coordinate system are equal, the object is said to be in equilibrium. The net effect of all external forces and moments acting on this object is zero as a result.

What is temperatue?

Temperature is a unit of measurement that can be expressed on a variety of scales, including Fahrenheit and Celsius. Temperature shows the direction of the spontaneous movement of heat energy, i.e., from a hotter body (one with a higher temperature) to a colder body (one with a lower temperature).

Their temperatures must be equal if two bodies are in thermal equilibrium.

As for coldness or warmth, we generally observe that metals feel colder while non metallic objects don't (i.e. comparatively they feel warmer than metals). This is due to the fact that metals are good conductor of heat. So when we touch a metallic body, heat flows from our body and is transferred to other points of the metal object. Since our body loses heat, we feel cold. In non metals, this conduction of heat from point of contact to other locations does not happen.

Therefore, the amount of heat loss from our body is much smaller. So we don't feel that cold.

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Answer:

the car you are in the cars have the same time frame and one covers more ground so on a possition time graph the slope will be greater

Answer:

33.3m

Explanation:

Recall that for a regular wave, the relationship between, wavelength, frequency  and velocity (speed) is given by :

v = fλ,

where:

v = velocity (speed) of the wave = 50m/s

f = frequency of the wave = 1.5 Hz

λ = wavelength (we are asked to find this)

simply substitute the given values into the equation:

v = fλ

50 = 1.5 λ,

λ = 50/1.5

λ = 33.3m

Answer:

(b) 1/sinƟ

Explanation:

A simple machine can be defined as a type of machine with no moving parts but can be used to perform work.

Basically, a simple machine allows for the transformation of energy into work. The six simple machines are; lever, wedge, pulley, screw, wheel and axle, and inclined plane.

Inclined plane is a simple machine set at an angle and then used to lift an object.

In Physics, the velocity ratio of a simple machine is calculated as a ratio of the distance moved by the effort to the vertical distance through which a load is raised.

Mathematically, the velocity ratio of an inclined plane of angle Ɵ, acting as a simple machine is given by the formula;

Velocity ratio (V.R) = 1/sinƟ

Basically, an increase in the angle of inclination (measured in degrees) of an inclined plane increases its velocity ratio.

Unfortunately, the information about trial 3 and the rate of reaction is missing in the given question. Without specific data or context,

The given question asks for the rate of reaction in trial 3 but does not provide the necessary information to calculate it. In order to determine the rate of reaction, specific data such as the change in concentration or the time taken for the reaction needs to be provided. Without this information, it is not possible to accurately determine the rate of reaction. The rate of reaction is a measure of how quickly reactants are converted into products and is influenced by factors such as temperature, concentration, and the presence of catalysts. Therefore, without the relevant data for trial 3, it is not possible to calculate or provide an answer regarding the rate of reaction in that specific trial.

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Answer:

3.27 meters

Explanation:

mark brainliest please

The height of the cliff will be 25.05 m. The height of the cliff is obtained by the Newton equation of motion.

The vertical distance between the object's top and bottom is defined as height. It is measured in centimeters, inches, meters, and other units.

The given data in the problem is;

Mass of diver(m)=90 kilogram

Time period(t)=2.26 sec

Initial velocity (u)=0 m/sec

The height attained by the cliff is;

\(\rm H = ut + \frac{1}{2}gt^2 \\\\ H=\frac{1}{2}gt^2\\\\ H= \frac{1}{2}(9.81)(2.26)^2\\\\ H= \frac{1}{2} \times 9.81 \times 5.1076 \\\\ H=25.05 \ m\)

Hence, the height of the cliff will be 25.05 m.

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