Answer:
B = 12800 grams or 12kg 800 grams.
Step-by-step explanation:
Let the two puppies be A and B respectively.
Translating the word problem into an algebraic expression, we have;
A + B = 22kg 300g
A = 9kg 500g
Conversion;
1 Kilograms = 1000 grams.
9kg 500g = 9*1000 + 500 = 9500 grams
22kg 300g = 22*1000 + 300 = 22300 g
Substituting into the above formula, we have;
9500 + B = 22300
B = 22300 - 9500
B = 12800 grams or 12kg 800 grams
Ali, Basti and Cian stand at three points A, B and C respectively. Suppose that the measure of angle ABC is 50 degrees , the measure of angle BAC is 60 degrees and Ali is exactly 150 ft away from Basti. Find the distance between Basti and Cian.
The distance between Basti and Cian is approximately 138.2 ft. Option D
To find the distance between Basti and Cian, we can use the Law of Sines, which relates the lengths of sides to the sines of their opposite angles in a triangle.
Let's label the points: A, B, and C. Ali is at point A, Basti is at point B, and Cian is at point C.
Given:
Angle ABC = 50 degrees (angle opposite side AC)
Angle BAC = 60 degrees (angle opposite side BC)
Ali is 150 ft away from Basti (side AB)
We want to find the distance between Basti and Cian, which is side BC.
Using the Law of Sines, we have:
BC/sin(50) = AB/sin(60)
Substituting the known values:
BC/sin(50) = 150/sin(60)
To find BC, we can rearrange the equation:
BC = (150/sin(60)) * sin(50)
Using a calculator to evaluate the expression:
BC ≈ 138.2 ft
Option D is correct.
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Help??? Pleaseeeeee???
Answer:
its B
Step-by-step explanation: trust me but also you can graph it and it will show the points
Which of the following is in standard form of quadratic?
Answer:
I think C and D options can be correct
Step-by-step explanation:
PLEASE MARK ME BRAINLIEST IF MY ANSWER IS CORRECT PLEASE
Answer:
I think C and D options can be correct
Step-by-step explanation:
How much water is in a empty glass that is 10 centimeters high and has a diameter of 5 cm
PLEASE HELP ON QUESTION ASAP !
hi ! I really need help understanding paragraph and I've also added a question about paragraph by me down below . Would like explanation in simple words.
If answers correct I'll rate you five stars a thanks and maybe even brainliest
Paragraph I needed help understanding:
If two or more cells are connected together side by side, the voltage across them is sum of the voltage of each cell. This is because both cells are pushing same way.
My Question about paragraph:
If the sum lets say was 4.5v would every individual cell be worth 4.5 as it says in question ' voltage across them is the sum of voltage of each cell ' or are they each a different value? And how would we be able to find value?.
a) angle of line of From a point O in the school compound, Adeolu is 100 m away on a bearing N 35° E and Ibrahim is 80 m away on a bearing S 55° E. (a) How far apart are both boys? (b) (c) What is the bearing of Adeolu from point O, in three-figure bearings? What is the bearing of Ibrahim from point O, in three figure bearings? A boy walks 5 km due North and then 4 km due East. (a) Find the bearing of his current posi- tion from the starting point. (b) How far is the boy now from the start- ing point? A boy runs 200 m on a bearing of 230°.
a) Angle of line of sightFrom a point O in the school compound, Adeolu is 100 m away on a bearing N 35° E and Ibrahim is 80 m away on a bearing S 55° E. (a) How far apart are both boys? (b) (c) What is the bearing of Adeolu from point O, in three-figure bearings? What is the bearing of Ibrahim from point O, in three-figure bearings?The angle of the line of sight of Adeolu from the point O is given by:α = 90 - 35α = 55°.The angle of the line of sight of Ibrahim from the point O is given by:β = 90 - 55β = 35°.a) By using the Sine Rule, we can determine the distance between Adeolu and Ibrahim as follows:$
\frac{100}{sin55^{\circ}} = \frac{80}{sin35^{\circ}
100 sin 35° = 80 sin 55°=57.73 mT
herefore, both boys are 57.73 m apart. b) The bearing of Adeolu from the point O can be determined as follows:OAN is a right-angled triangle with α = 55° and OA = 100. Therefore, the sine function is used to determine the side opposite the angle in order to determine AN.
Thus:$$sin55^{\circ} = \frac{AN}{100}$$AN = 80.71 m.
To find the bearing, OAD is used as a reference angle. Since α = 55°, the bearing is 055°.
Therefore, the bearing of Adeolu from the point O is N55°E. c) Similarly, the bearing of Ibrahim from the point O can be determined as follows:OBS is a right-angled triangle with β = 35° and OB = 80. Therefore, the sine function is used to determine the side opposite the angle in order to determine BS.
Thus:$$sin35^{\circ} = \frac{BS}{80}$$BS = 46.40 m.
To find the bearing, OCD is used as a reference angle. Since β = 35°, the bearing is 035°.Therefore, the bearing of Ibrahim from the point O is S35°E. A boy walks 5 km due North and then 4 km due East. (a) Find the bearing of his current posi- tion from the starting point.
(b) How far is the boy now from the start- ing point?The boy's position is 5 km North and 4 km East from his starting position. The Pythagorean Theorem is used to determine the distance between the two points, which are joined to form a right-angled triangle. Thus
:$$c^2 = a^2 + b^2$$
where c is the hypotenuse, and a and b are the other two sides of the triangle. Therefore, the distance between the starting position and the boy's current position is:$$
c^2 = 5^2 + 4^2$$$$c^2 = 25 + 16$$$$c^2 = 41$$$$c = \sqrt{41} = 6.4 km$$
Therefore, the boy is 6.4 km from his starting point. (a) The bearing of the boy's current position from the starting point is given by the tangent function.
Thus:$$\tan{\theta} = \frac{opposite}{adjacent}$$$$\tan{\theta} = \frac{5}{4}$$$$\theta = \tan^{-1}{\left(\frac{5}{4}\right)}$$$$\theta = 51.34^{\circ}$$
Therefore, the bearing of the boy's current position from the starting point is N51°E.
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What is the square root of .0169
Answer:
The square root of .0169 is 0.13
Angle of the Sun A 96-ft tree casts a shadow that is 120 ft long. What is the angle of elevation of the sun
Answer:
The angle of elevation of the sun is 39⁰
Step-by-step explanation:
Given;
height of the tree, h = 96 ft
length of the shadow, L = 120 ft
|
| 96ft
|
|
θ------------------------------------
120ft
Completing this triangle to cut across the top of the tree gives you a right angled triangle with θ as the angle of elevation of the sun.
Apply trig-ratio to determine the angle of elevation of the sun;
tanθ = opposite side / adjacent side
tanθ = 96 / 120
tanθ = 0.8
θ = tan⁻¹(0.8)
θ = 38.7⁰
θ = 39⁰
Therefore, the angle of elevation of the sun is 39⁰
In Problems 1–6, use the method of undetermined coefficients to find a general solution to the system x′1t2 =
Ax1t2 + f1t2, where A and f1t2 are given
Answer:hi
Step-by-step explanation:
ZA is opposite
B
A
A. BC
O O
B. AB
C. C
D. AC
E. ZA
F. AB and Ac
The solution is, angle A is opposite of BC.
What is an angle?It can be mentioned as, a figure which is formed by two rays or lines that shares a common endpoint is called an angle. The two rays are called the sides of an angle, and the common endpoint is called the vertex.
here, we have,
from the given figure, we get,
here, ABC is a triangle.
now, we have to find the side which is opposite to angle A.
so. we get,
Here, we want to get the side that is opposite of the angle marked A
Looking at the given triangle, we can see that the given angle is opposite the side labelled BC.
Thus, we can say that the angle marked A which lies on vertex A is opposite the side marked BC.
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Triangles WILL GIVE BRAINLIEST
Answer:
A
Step-by-step explanation:
A
Answer:
Q9 - Option 1---- A - 15.6 Square Units
Q10 --Option --- (B) RECTANGLE
Step-by-step explanation:
Q9 --
Analyze:we know area of triangle = 1/2 ab sin theta
Where theta is the angle included between sides A and side B
Calculate:A = 5.2
B = 7
theta = 121 degrees
Area:1/2 * 5.2 * 7 * sin 121 degrees = 15.6 Square Units
Conclusion
The area of the triangle is 15.6 Square Units
Q10 - The cross-section of a right cylinder which is perpendicular to its base is a RECTANGLEOption --- (B) RECTANGLE
Hope this helps!
An instructor asks students to rate their anxiety level on a scale of 1 to 100 (1 being low anxiety and 100 being high anxiety) just before the students take their final exam. The responses are shown below. Construct a relative frequency table for the instructor using five classes. Use the minimum value from the data set as the lower class limit for the first row, and use the lowest possible whole-number class width that will allow the table to account for all of the responses. Use integers or decimals for all answers.
48,50,71,58,56,55,53,70,63,74,64,33,34,39,49,60,65,84,54,58
Provide your answer below:
Lower Class Limit Upper Class Limit Relative Frequency
Answer:
The frequency table is shown below.
Step-by-step explanation:
The data set arranged ascending order is:
S = {33 , 34 , 39 , 48 , 49 , 50 , 53 , 54 , 55 , 56 , 58 , 58, 60 , 63 , 64 , 65 , 70 , 71 , 74 , 84}
It is asked to use the minimum value from the data set as the lower class limit for the first row.
So, the lower class limit for the first class interval is 33.
To determine the class width compute the range as follows:
\(\text{Range}=\text{Maximum}-\text{Minimum}\)
\(=84-33\\=51\)
The number of classes requires is 5.
The class width is:
\(\text{Class width}=\frac{Range}{5}=\frac{51}{2}=10.2\approx 10\)
So, the class width is 10.
The classes are:
33 - 42
43 - 52
53 - 62
63 - 72
73 - 82
83 - 92
Compute the frequencies of each class as follows:
Class Interval Values Frequency
33 - 42 33 , 34 , 39 3
43 - 52 48 , 49 , 50 3
53 - 62 53 , 54 , 55 , 56 , 58 , 58, 60 7
63 - 72 63 , 64 , 65 , 70 , 71 5
73 - 82 74 1
83 - 92 84 1
TOTAL 20
Compute the relative frequencies as follows:
Class Interval Frequency Relative Frequency
33 - 42 3 \(\frac{3}{20}\times 100\%=15\%\)
43 - 52 3 \(\frac{3}{20}\times 100\%=15\%\)
53 - 62 7 \(\frac{7}{20}\times 100\%=35\%\)
63 - 72 5 \(\frac{5}{20}\times 100\%=25\%\)
73 - 82 1 \(\frac{1}{20}\times 100\%=5\%\)
83 - 92 1 \(\frac{1}{20}\times 100\%=5\%\)
TOTAL 20 100%
Factor x^2 + 9x = -20
Answer:
(x +5) (x +4) = 0
Step-by-step explanation:
x^2 + 9x +20 = 0
x^2 + 4x + 5x +20 = 0
x(x + 4) + 5(x + 4) = 0
(x +5) (x +4) = 0
Answer:
see below
Step-by-step explanation:
x^2 + 9x = -20
x^2 + 9x + 20 = 0
factor the expression
(x + a)(x + b)
a + b = 9
a = 4
b = 5
ab = 20
rewrite the factor expression:
(x + 4) (x + 5)
x + 4 = 0 and x + 5 = 0
therefore,
x = -4
x = -5
Solve for r.
V = 4/3πr³
What is r equal to? (Hint: Notice that r is cubed, not squared.)
The value of r is equal to the cube root of (V * (3π/4)).
What is r equal to?To solve for r, we need to rearrange the equation to isolate r.Starting with:V = 4/3πr³Divide both sides by 4/3π:V * (3π/4) = r³Take the cube root of both sides:r = (V * (3π/4))^(1/3)So, the value of r is equal to the cube root of (V * (3π/4)).Note: The equation for the volume of a sphere is V = 4/3πr³, where r is the radius of the sphere.To learn more about volume of sphere refer:
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Addition Property of Equality:
If AB = CD, then AB + EF =
The Addition Property of Equality allows us to add EF to both sides of the equation without changing its truth, giving us AB + EF = CD + EF.
We have,
The Addition Property of Equality states that if we add the same quantity to both sides of an equation, the equation remains true.
In the given equation,
AB = CD, we can add the same quantity, EF, to both sides of the equation to obtain:
AB + EF = CD + EF
This is because if two quantities are equal, and we add the same amount to both of them, the result is still equal.
Therefore,
The Addition Property of Equality allows us to add EF to both sides of the equation without changing its truth, giving us AB + EF = CD + EF.
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6/10 + 5/100
is it
65/100 or 65/110 or 56/100 or 56/110
Answer:
65/100 that is the answer to this question
Which expression is equivalent to (5x + 2) + (4x - 3)?
A. 6x + 2
B. 7x + 1
C. 9x - 1
D. 11x - 3
E. 20x - 6
Answer:
C. 9x-1
Step-by-step explanation:
(5x+2)+(4x-3)
5x+2+4x-3
5x+4x+2-3
9x-1
GRAPHS EQUATIONS Domain: y = x2-1 Range: Domain: Range: Function? Function?
The expressi
\(y=x^2-1\)and we would like to know the domain and range of the function. Since for every x value we give to the equation the result will always be a real number the domain of this function is
\(\text{dom y=(-}\infty,\infty)\)Now to find the range of the function we solve the equation for x.
\(\begin{gathered} y=x^2-1 \\ x^2=y+1 \\ x=\pm\sqrt[]{y+1} \end{gathered}\)This root will only exist if
\(\begin{gathered} y+1\ge0 \\ y\ge-1 \end{gathered}\)Therefore the range of the function is:
\(\text{range y=}\lbrack-1,\infty)\)A group of cyclists recorded the distance they have traveled.
Draw a line plot and answer the questions below.
Name
Gina
Rey
Faye
Mark
John
James
Albert
William
Nathan
Kate
Mary
Risa
Paul
Abi
Joan
Distance in
miles
40 1/2
50
35 3/4
60
45
55 1/4
60
45
40 1/2
50
45
40 1/2
60
40 1/2
35 3/4
Title:
1. How many cyclists were there?
2. What was the longest distance traveled?
3. How many cyclists traveled less than 50 miles?
4. What was the most common distance traveled by
the cyclists?
5. How many more cyclists traveled 45 miles than
55 1/4 miles?
6. How many cyclists traveled more than 45 miles
A total of 7 Cyclists traveled more than 45 miles. 4 cyclists traveled 50 miles or more, and 3 cyclists traveled more than 54 1/4 miles.
A line plot is drawn with the cyclists' names plotted on the x-axis and their corresponding distances covered plotted on the y-axis.
The dots are then joined to form a line, revealing the relationship between the cyclist's names and their corresponding distance traveled. The cyclist names and their corresponding distances are given in the table below.
Name Distance (in miles) Gina 40 1/2 Rey 50 Faye 35 3/4 Mark 60 John 45 1/2 James 40 1/2 Albert 40 1/4 William 54 1/4 Nathan 40 Kate 40 1/4 Mary 60 Risa 40 Abi 35 3/4 Joan 50 1/2 1. The number of cyclists is 14. 2. The longest distance covered by a cyclist is 60 miles.
Mary and Mark both covered this distance.3. A total of 7 cyclists traveled less than 50 miles. 4. The most common distance traveled by cyclists is 40 1/2 miles. Gina, James, and Albert covered this distance. 5. 2 more cyclists traveled 45 miles than 55 1/4 miles. Only William traveled 55 1/4 miles, while John and James both traveled 45 1/2 miles.6.
A total of 7 cyclists traveled more than 45 miles. 4 cyclists traveled 50 miles or more, and 3 cyclists traveled more than 54 1/4 miles.
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Average movie prices in the United States are, in general, lower than in other countries. It would cost $78.50 to buy three tickets in Japan plus two tickets in Switzerland. Three tickets in Switzerland plus two tickets in Japan would cost $74.10. How much does an average movie ticket cost in each of these countries?
The average movie ticket cost in Switzerland and Japan each of these countries is 46.97.
Let's assume that the average cost of a movie ticket in Japan is x, and the average cost of a movie ticket in Switzerland is y.
According to the problem statement, we can write two equations based on the given information:
3x + 2y = 78.5 ...(1)
2x + 3y = 74.1 ...(2)
We can solve these equations simultaneously to find the values of x and y. Here's how:
Multiply equation (1) by 2 and equation (2) by 3, then subtract equation (1) from equation (2):
(2x + 3y) - 2(3x + 2y) = 74.1 - 2(78.5)
Simplifying this equation, we get:
-y = -109.3
Therefore, y = 109.3.
Now substitute y = 109.3 into either equation (1) or (2) and solve for x:
3x + 2(109.3) = 78.5
Simplifying this equation, we get:
3x = -140.9
Therefore, x = -46.97.
However, we cannot have negative ticket prices.
Therefore, the average cost of a movie ticket is 46.97.
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please help quick jk take all the time you need
Answer:
5: 0.09, 5/8, 70%, 0.80 6: 27 7: 72 8: 85 9: 16 10: a-20 b-60
Step-by-step explanation:
intercept from the lines
Answer:
I mean tbh its pretty easy
The y intercept is: (0, 2.5)
The x-intercept is: (3.5,0)
just look at the graph lol but if im
wrong sorry
Please awnser asap I will brainlist
Answer:
V = 180 (vans)
S = 90 (small trucks)
L = 40 (large trucks)
Step-by-step explanation:
Set up the variables: Let V represent the number of vans, S represent the number of small trucks, and L represent the number of large trucks.
Write the equations:
V + S + L = 310 (total number of vehicles)
V = 2S (twice as many vans as small trucks)
35,000V + 70,000S + 60,000L = 15,000,000 (total cost of the vehicles)
Substitute equation 2) into equation 1):
2S + S + L = 310
3S + L = 310
Simplify equation 3) by substituting V = 2S:
70,000S + 70,000S + 60,000L = 15,000,000
140,000S + 60,000L = 15,000,000
Set up a system of equations:
3S + L = 310
140,000S + 60,000L = 15,000,000
Eliminate L by multiplying equation 1) by 60,000:
60,000(3S + L) = 60,000(310)
180,000S + 60,000L = 18,600,000
Subtract equation 2) from the new equation:
(180,000S + 60,000L) - (140,000S + 60,000L) = 18,600,000 - 15,000,000
40,000S = 3,600,000
Solve for S:
S = 90
Substitute the value of S into equation 1) to solve for L:
3(90) + L = 310
270 + L = 310
L = 40
Substitute the values of S and L into equation 2) to solve for V:
V = 2S
V = 2(90)
V = 180
The final answer is:
V = 180 (vans)
S = 90 (small trucks)
L = 40 (large trucks)
Answer:
180 Vans 90 Small trucks and 40 Large trucks
Step-by-step explanation:
3.14 x 231?
Please help.I stuggle in mutiply decimals.
Answer:
725.34
Step-by-step explanation:
003.14
x
321.00
725.34
Answer:
725.34
Step-by-step explanation:
Think of the number '3.14' as 314 and use the long multiplication process to derive your answer.
Suppose that next year the U.S. will be in one of the following economic conditions: Boom, Moderate Growth, Recession, or Depression. The probability that each economic condition will occur, and that a jewelry store will earn profits within that broader economic condition are listed below:
Economic Condition Probability. Jewelry Store Profits
Boom 0.40 $400,000
Moderate Growth 0.30 $300,000
Recession 0.20 $100,000
Depression 0.10 -$500,000
The standard deviation of the jewelry store's profits next year is
How many commutes are exactly 68 minutes
Answer:
three
Step-by-step explanation:
stem. is the tens place and the leaf is the. ones place
so you want to find 68 so you look in the stem column and look for six
in the row there are 6 numbers which mean:
60, 61, 67, 68, 68, 68
as you can see there is three 68 there for the answer ths 3
A triangle has one length of 10 units and another of 6 units. Describe the possible lengths of the third side.
Answer:
Explanation:
Here, we want to get the possible lengths of the third side of the triangle
From the lengths principle for triangles, the sum of the lengths of two of the sides must be greater than the length of the third side
We have a length as 6 and the other as 10
Now, if we have 8 or 9, they can work for the triangle
This is because if we add 8 to 6, it is greater than 10. Also, if we add 9 to 6 it will be greater then 10
Consclusively, the length of the third side will be one which is less than the sum of the lengths of the initial two (10 + 6)
Also, if the length is added to 6, the sum will be greater than 10
what expression should be substituted for y in the equation 5x+2y=25 to solve the system of equations?
Answer:
y= 25
Step-by-step explanation:
y = 25 /2
Find the coordinates of the figure after the transformations. Translate the triangle 1 unit right and 5 units down. Then reflect the image in the y-axis.
The final image is the same as Translate 5 units down, and then reflect over the y axis.
What is Transformation?Transformation is the movement of a point from its initial location to a new location. Types of transformation are translation, reflection, rotation and dilation.
Translation is the movement of a point up, down, left or right.
Transformation is the movement of a point from its initial location to a new location.
The final image is the same as Translate 5 units down, and then reflect over the y axis.
Therefore the coordinates remains same as previous figure.
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Match the scatterplot with correlation coefficient. Write the letter of the scatterplot a/B/C/or D in the appropriate space for 0.341, 0.855, 0.999, -0.721?
The correlation coefficient for each scatter plot displayed is
A = 0.999B = -0.721C = 0.341D = 0.855The correlation coefficient gives the strength and direction of relationship between variables using values between -1 and 1 .
plot A has a very perfect association, hence the value 0.999 , Plot D also depicts a strong association with a well defined trendline . For plot B, the slope is negative, hence, the negative value in the coefficient.
Therefore, the type of correlation can be visually inferred from the graph.
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