2. Provide a definition of a measuring unit. Give an example of a
unit of length, mass, and volume.

39°C=1.28L

8°C=? Less

=8°C/39°C×1.28L

=8/39×1.28L

=10.24/39

=512/195

=2.6L

Explanation:

They will have not much control over their speed or rotational energy. they will carry a lot of gravitation potential energy which will get converted to kinetic energy as they fall through the atmosphere. They will reach their terminal velocity, the fastest they can travel with earth's gravity before they pull their parachute, when they use a parachute to extend their surface area, increasing wind resistance. this allows them to land safely.

Answer:

While weight training will improve muscle strength and mass, the potential of a body to develop muscle is limited in part by genetic factors that are out of an individual's control.

Explanation:

Answer:

While weight training will improve muscle strength and mass, the potential of a body to develop muscle is limited in part by genetic factors that are out of an individual's control.

Explanation:

Got it right on Edge

Answer:

B. Mass will not change based on location, while weight will change based on gravitational pull.

Answer:

B

Explanation:

took the test

The wavelength of the lowest note on the tuba is approximately 37.40 meters in air

To find the wavelength of the lowest note on a tuba, we can use the formula: v=f⋅λ. where:v is the velocity of sound in air (343 m/s).f is the frequency of the note (9.18 Hz). λ is the wavelength of the note (to be determined). Therefore, the wavelength of the lowest note on the tuba is approximately 37.40 meters in air.

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Parfit, a prominent philosopher, argues that claiming God as the cause of the Big Bang is problematic. He suggests that using God as an explanation for the origin of the universe is not satisfying, as it merely replaces one mystery with another.

Additionally, Parfit asserts that invoking God as the cause of the Big Bang raises questions about the nature of God.  Furthermore, Parfit asserts that science provides a more plausible explanation for the origin of the universe. Scientists have proposed various theories, such as the inflationary model and the cyclic model, that attempt to explain the origins of the universe without the need for a divine creator.

In conclusion, Parfit does not find the argument that God caused the Big Bang to be convincing, as it raises more questions than it answers. Instead, he advocates for relying on scientific theories to explain the origins of the universe.

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Answer:

true

Explanation:

did the quiz

To solve this problem, we can use the concept of relative humidity. The relative humidity (RH) of air is defined as the ratio of the partial pressure of water vapor in the air to the saturation pressure of water vapor at the same temperature, expressed as a percentage. Mathematically, we can write:

RH = (Pv/Ps) x 100%

where Pv is the partial pressure of water vapor, Ps is the saturation pressure of water vapor at the same temperature, and the factor of 100% is used to express the result as a percentage.

Let's use this formula to solve the problem step by step:

We are given that the air has a temperature of 20°C and a specific humidity (i.e., the mass of water vapor per unit mass of dry air) of 8.6 g/kg. We can use a psychrometric chart or a calculator to find that the saturation pressure of water vapor at 20°C is about 2.34 kPa.

Using the definition of relative humidity, we can find the partial pressure of water vapor in the air:

RH = (Pv/Ps) x 100%

8.6 = (Pv/2.34) x 100%

Pv = 0.204 kPa

So the partial pressure of water vapor in the air at 20°C is 0.204 kPa.

We are told that the air is cooled to 5°C and its specific humidity decreases to 5 g/kg. We can repeat the same calculation as before to find the new partial pressure of water vapor:

RH = (Pv/Ps) x 100%

5 = (Pv/0.87) x 100% (The saturation pressure of water vapor at 5°C is about 0.87 kPa.)

Pv = 0.0435 kPa

So the partial pressure of water vapor in the air at 5°C is 0.0435 kPa.

Finally, we are told that the air is warmed back up to 25°C. We can use the same saturation pressure value as before (2.34 kPa) to find the new specific humidity:

RH = (Pv/Ps) x 100%

(Pv/2.34) x 100% = RH at 25°C

RH at 25°C = RH at 20°C

So the relative humidity remains constant during the warming process. Therefore, the partial pressure of water vapor in the air at 25°C is:

Pv = RH at 25°C x Ps

= RH at 20°C x Ps

= (0.204/2.34) x 2.34

= 0.204 kPa

Thus, the partial pressure of water vapor in the air at 25°C is the same as at 20°C, and its specific humidity is given by:

specific humidity = Pv/(p - Pv) = 0.204/(101.3 - 0.204) = 0.00202 kg/kg

Therefore, the water vapor content of the air at 25°C is 0.00202 kg of water vapor per kg of dry air.

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Currently, the largest optical telescope mirrors have a diameter of a  20 m , so option d is  is correct.

The largest optical telescope mirrors have a diameter of a 20m.However, please note that technology and advancements in telescope construction are continuously evolving, so it's possible that larger telescope mirrors have been developed since then. It's always a good idea to consult the latest sources or refer to current astronomical news for the most up-to-date information.An optical telescope is a telescope that gathers and focuses light mainly from the visible part of the electromagnetic spectrum, to create a magnified image for direct visual inspection, to make a photograph, or to collect data through electronic image Therefore option d is correct option.

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Their combined momentum after they meet is 0.

According to the law of conservation of momentum, absent an external force, the combined momentum of two or more bodies operating upon one another in an isolated system remains constant. As a result, momentum cannot be gained or lost.

Let the mass of each billiard balls = m.

If the initial velocity of first ball is u; according to the question, the initial velocity of the second ball be -u.

Hence, initial momentum of the first ball is: P₁ = mu

initial momentum of the second ball is: P₂ = -mu

Hence, total initial momentum of the two balls = P₁ + P₂ = mu + ( -mu) = 0.

So, according to law of conservation of momentum:

Their combined momentum after they meet is = 0.

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The combined momentum of the two billiard balls after they meet is zero.

When two pool balls of the same size and speed roll directly at each other and collide, their momentum will increase.

Let us denote the speed of the first ball as \(\rm p_1\) and the speed of the second ball as \(\rm p_2\). The momentum of the balls are equal in magnitude but opposite in direction because they have the same mass and velocity.

\(\rm p_1= -p_2\)

When the balls collide, their momentum increases:

Total momentum after the collision= \(\rm p_1+ p_2\)

Substituting the relationship

\(\rm p_1= -p_2\)

Total momentum after the collision

\(\rm p_1- p_1= 0\)

Therefore, the combined momentum of the two billiard balls after they meet is zero.

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Answer:

6m/s

Explanation:

A=d÷t

A=60÷10

6

Two negative charges that are both - 5.0 x 10⁵ C push each other apart with a force of 15N. Then, the distance between the two charges will be 1.22 meters.

The electrostatic force exists between two charges placed at a distance of some magnitudes. The magnitude of electrostatic force depends on the magnitude of each charge and also the distance between the two charges. When any two positive charges or two negative charges are brought together, then the two charges repel each other.

F = kq₁q₂/ r²

where, F is the electrostatic force,

k is Coulomb's constant, q₁ and q₂ are the two charges,

r is the distance between the two charges

F = 15 N,

K = 9 × 10⁹ Nm²C⁻²

q₁ and q₂ =  -5.0 × 10⁵ C

F = kq₁q₂/ r²

r² = \(\sqrt{(kq1q2/ F)}\)

r = \(\sqrt{(9X10^9X-5X10^5X-5X10^5/ 15)}\)

r = √(225 × 10¹¹× 10¹⁰/ 15)

r = √(1.5× 10²⁰)

r = 1.22m

Therefore, the distance between the two charges will be 1.22 meters.

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approximately 34.4 J of energy is lost to air friction during the flight of the frisbee.    

To determine the amount of energy lost to air friction, we need to first calculate the initial total mechanical energy of the frisbee and then compare it to the final total mechanical energy of the frisbee when it reaches a height of 2 meters with a velocity of 1 m/s. The difference between these two energies will give us the amount of energy lost due to air friction.        

The initial total mechanical energy of the frisbee can be calculated as the sum of its kinetic energy and potential energy:

Ei = 1/2 m\(v^{2}\) + mgh

where m is the mass of the frisbee, v is the initial velocity, g is the acceleration due to gravity, and h is the initial height. Plugging in the given values, we get:

Ei = 1/2 (0.5 kg)\((10 m/s)^2\) + (0.5 kg) (9.8 m/s^2) (2 m)

Ei = 49 J

The final total mechanical energy of the frisbee can be calculated as the sum of its kinetic energy and potential energy when it reaches a height of 2 meters with a velocity of 1 m/s:

Ef = 1/2 m\(v^2\) + mgh

where v is the final velocity and h is the final height. Plugging in the given values, we get:

Ef = 1/2 (0.5 kg) \((1 m/s)^2\) + (0.5 kg) (9.8 m/s^2) (2 m)

Ef = 14.6 J

The energy lost due to air friction can be calculated as the difference between the initial and final total mechanical energies:

Energy lost = Ei - Ef

Energy lost = 49 J - 14.6 J

Energy lost = 34.4 J

Therefore, approximately 34.4 J of energy is lost to air friction during the flight of the frisbee.

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1. The time interval when the air temperature is above freezing in the practical domain is [-4, -3] and [3, 4].

2. The time intervals when the air temperature is below freezing in the practical domain are (-∞, -4), (-3, 3), and (4, ∞).

3. The maximum temperature on the practical domain is approximately -0.6 degrees Celsius.

4. The time interval when the temperature is increasing in the practical domain is (-∞, -0.5) and (0.5, ∞).
5. The air temperature at midnight is approximately -0.6 degrees Celsius.

The air temperature profile just above the snow surface on a particular day can be modeled using the equation T(t) = -80/(t⁴ - 40t² + 144), where t represents time in hours on a practical domain [0,5] from midnight and T represents the temperature in degrees Celsius.

1. Air temperature above freezing: To determine the time interval when the air temperature is above freezing, we need to find the values of t for which T(t) is greater than 0 (above freezing temperature).

To do this, we can solve the equation T(t) > 0:
-80/(t⁴ - 40t² + 144) > 0

Since the numerator is negative, the temperature will be positive when the denominator is positive. So we need to solve the quadratic equation t⁴ - 40t² + 144 > 0.

By factoring the quadratic equation, we can rewrite it as (t² - 16)(t² - 9) > 0.

Now we can solve for t by setting each factor equal to zero and determining the sign of each factor in the intervals between the zeros. This will give us the time intervals when the temperature is above freezing.

- t² - 16 = 0  => t² = 16  => t = ±4
- t² - 9 = 0   => t² = 9   => t = ±3

Since the quadratic equation has even powers, it is always positive or zero. Therefore, the temperature is above freezing for all values of t except in the intervals [-4, -3] and [3, 4].


2. Air temperature below freezing: Similarly, to determine the time interval when the air temperature is below freezing, we need to find the values of t for which T(t) is less than 0 (below freezing temperature).

We solve the equation T(t) < 0:
-80/(t⁴ - 40t² + 144) < 0

Again, since the numerator is negative, the temperature will be negative when the denominator is positive. So we need to solve the quadratic equation t⁴ - 40t² + 144 > 0.

By factoring the quadratic equation, we can rewrite it as (t² - 16)(t² - 9) > 0.

Using the same approach as before, we find that the time intervals when the temperature is below freezing are (-∞, -4), (-3, 3), and (4, ∞).



3. Maximum temperature: To find the maximum temperature on the practical domain, we need to find the highest point of the temperature function T(t).

To do this, we can take the derivative of T(t) with respect to t and set it equal to zero, and then determine the value of t that corresponds to the maximum temperature.

By taking the derivative, we have dT(t)/dt = 0.

Simplifying the equation, we get 320t³ - 80t = 0.

Factoring out t, we have t(320t² - 80) = 0.

Solving for t, we find t = 0 and t = ±sqrt(1/4) = ±0.5.

Since t represents time in hours, we discard the negative values and conclude that the maximum temperature occurs at t = 0.

Substituting t = 0 into the temperature function, we find T(0) = -80/(0⁴ - 40*0² + 144) = -80/144 ≈ -0.56.



4. Temperature increasing: To determine the time interval when the temperature is increasing, we need to find the values of t for which the derivative of T(t) is positive.

Taking the derivative of T(t), we have dT(t)/dt = 320t³ - 80t.

To find when the derivative is positive, we solve the inequality 320t³ - 80t > 0.

By factoring out t, we get t(320t² - 80) > 0.

Solving for t, we find t = 0 and t = ±sqrt(1/4) = ±0.5.
The derivative is positive when t is in the intervals (-∞, -0.5) and (0.5, ∞).


5. Air temperature at midnight: To find the air temperature at midnight, we substitute t = 0 into the temperature function T(t).

T(0) = -80/(0⁴ - 40*0² + 144) = -80/144 ≈ -0.56.

Therefore, the air temperature at midnight is approximately -0.6 degrees Celsius.

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Answer:

the answer will be D

Explanation:

Answer:

Inertia

Explanation:

Inertia is also the reason that it is harder to stop a loaded truck going 55 miles per hour than to stop a car going 55 miles per hour. The truck has more mass resisting the change of its motion and therefore, more inertia.

Tom will strike the floor at a distance of 3.6 meters from the edge of the table.

1. First, we need to find the time it takes for Tom to fall 1.2 meters to the floor. We can use the following equation for free-fall motion:
\(h = 0.5 * g * t^{2]\)
where h is the height (1.2 m), g is the acceleration due to gravity (approximately \(9.8 m/s^{2}\)), and t is the time.
\(1.2 = 0.5 * 9.8 * t^{2}\)
\(t^{2} = \frac{ (1.2 * 2) }{9.8}\)
\(t = \sqrt{ (0.2449)}  = 0.495 seconds\) (approximately)
2. Now that we know the time it takes for Tom to fall, we can find the horizontal distance Tom travels during that time:
Horizontal Distance = Horizontal Speed * Time
Horizontal Distance = 6.0 m/s * 0.495 s
Horizontal Distance = 2.97 m (approximately)
Tom will strike the floor at a distance of approximately 2.97 meters from the edge of the table.

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Answer:

 person a₁ = -0.625 m / s², box a₂ = 0.0714 m / s²

Explanation:

In this exercise we have a problem of action and reaction forces, the force with which the person (action) pushes the box is of the same magnitude as the force with which the box (reaction) pushes the person, but in the opposite direction.

We work that body separately

Person

           -F = m₁ a₁

             a₁ = -F / m₁

             a₁ = -50.0 / 80.0

             a₁ = -0.625 m / s²

the negative sign means that the person moves away from the box

Box

            F = m₂ a₂

            a₂ = F / m₂

            a₂ = 50.0 / 700

            a₂ = 0.0714 m / s²

The minimum value of the transmission signal bandwidth in the case of a multi-level PAM signal with 64 levels, using a symbol waveform of a square pulse, is 8 kHz. The symbol rate is also 8 kHz.

In a multi-level PAM (Pulse Amplitude Modulation) signal, the number of levels determines the number of distinct amplitudes that can be transmitted. In this case, there are 64 levels.

To determine the minimum value of the transmission signal bandwidth, we need to consider the Nyquist criterion. According to the Nyquist theorem, the minimum bandwidth required for a signal is twice the highest frequency component of the signal. Here, the highest frequency component of the voice signal is 3.4 kHz.

Since the voice signal is sampled at a frequency of 8 kHz, the Nyquist criterion tells us that the minimum bandwidth required for transmission is 2 * 3.4 kHz = 6.8 kHz. However, in practice, it is common to choose a slightly higher value to account for the practical implementation considerations. Therefore, the minimum value of the transmission signal bandwidth is rounded up to 8 kHz.

The symbol rate is the number of symbols transmitted per second. In this case, since the voice signal is sampled at 8 kHz, the symbol rate is also 8 kHz.

Moving on to the second part of the question, when transmitting the PAM signal into binary data using PCM (Pulse Code Modulation) encoding, we need to consider the bandwidth and bit rate.

To determine the bandwidth of the transmission signal when using PCM encoding with a square wave pulse, we need to apply the Nyquist criterion again. The Nyquist criterion states that the bandwidth is equal to the highest frequency component of the signal. In PCM encoding, the highest frequency component is half the sampling rate, which is 4 kHz (8 kHz / 2).

Therefore, the bandwidth of the transmission signal when using PCM encoding with a square wave pulse is 4 kHz.

The bit rate is the number of bits transmitted per second. In PCM encoding, each sample of the PAM signal is quantized and represented using a fixed number of bits. Since the symbol rate is 8 kHz and each symbol is represented by 6 bits (64 levels), the bit rate is calculated as 8 kHz * 6 bits = 48 kbps.

In summary, the bandwidth of the transmission signal when using a multi-level PAM signal with 64 levels and a square wave pulse is 8 kHz, with a symbol rate of 8 kHz. When using PCM encoding with a square wave pulse, the bandwidth of the transmission signal is 4 kHz, with a bit rate of 48 kbps.

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We need more information: 1. The initial speed of the elevator before it contacts the spring. 2. The mass of the elevator. 3. The spring constant of the spring.

Once we have these values, we can calculate the speed of the elevator after it has moved downward 1.00 m using the conservation of mechanical energy principle. The mechanical energy (E) is the sum of the potential energy (U) and kinetic energy (K) of the elevator:

\(E_initial = E_final\\U_initial + K_initial = U_final + K_final\)

Initial potential energy (U_initial) is 0, as we assume the spring is uncompressed when the elevator first contacts it. The initial kinetic energy (K_initial) can be calculated using the initial speed (v_initial) and mass (m) of the elevator:

\(K_initial = 0.5 * m * v_initial^2\)

When the elevator has moved downward 1.00 m, the final potential energy (U_final) stored in the spring can be calculated using the spring constant (k) and the spring compression (x = 1.00 m):

\(U_final = 0.5 * k * x^2\)

Now, we can solve for the final kinetic energy (K_final) and then calculate the final speed (v_final) of the elevator:

\(K_final = E_initial - U_final\)
\(v_final =\sqrt{ ((2 * K_final) / m)}\)

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E = / _0, where is the surface charge density and _0 is the permittivity of empty space, may be used to compute the electric field between the two plates. The net charge density and electric field between the plates are both zero since the plates contain equal and opposing charges.

E = / _0, where is the permittivity of empty space and _0 is the surface charge density, is the formula for the electric field between two parallel plates. The plates are assumed to be indefinitely huge in this formula, and the separation distance is also much reduced. Given that the two plates have equal and opposing charges, there is no net charge density in the situation. As a result, since there is no net charge to produce an electric field, the electric field between the plates is likewise zero.

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The acceleration of the satellite would be 8,926.67 m/s².

The acceleration of the satellite can be calculated using the following equation:

a = GM/r²

where:

G = gravitational constant = 6.6743 x 10^-11 Nm²/kg²

M = mass of the Earth = 5.972 x 10^24 kg

r = distance between the centers of the Earth and the satellite = 5 x 10^3 m

First, we need to calculate the gravitational force between the Earth and the satellite:

F = G(Mm)/r²

where m is the mass of the satellite.

F = (6.6743 x 10^-11 Nm²/kg²)(5.972 x 10^24 kg)(15,000 kg)/(5 x 10^3 m)²

F = 1.339 x 10^8 N

Now we can calculate the acceleration of the satellite:

a = F/m

a = (1.339 x 10^8 N)/(15,000 kg)

a = 8,926.67 m/s²

Therefore, the acceleration of the satellite is 8,926.67 m/s².

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Answer:

This is newton's 3rd law

Explanation:

Answer:

a. 2 kg*m/s

b. \(p_{T_{f}} = 0.5v_{f} = 2 kg*m/s\)

c. 4 m/s

Explanation:

a. The momentum of the system (\(p_{Ti}\)) before the blob of clay strikes the cart is:

\( p_{Ti} = p_{b} + p_{c} \)

Where:

\(p_{b}\) is the momentum of the blob clay

\(p_{c}\) is the momentum of the car      

\( p_{Ti} = m_{b}v_{b} + m_{c}v_{c} \)

Since the car is initially at rest, \(v_{c}\) = 0

\( p_{Ti} = 200 g*\frac{1 kg}{1000 g}*10 m/s + 0 = 2 kg*m/s \)

b. The momentum of the system after they come together:

\(p_{T_{f}} = m_{b}v_{b} + m_{c}v_{c}\)

Since they come together, \(v_{b}\) =

\(p_{T_{f}} = v_{f}(m_{b} + m_{c}) = v_{f}(0.2 kg + 0.3 kg) = 0.5v_{f}\)   (1)

Because we do not have the final speed we can not calculate the final momentum.

c. We can find the speed of the clay and car by conservation of the momentum:

\( p_{i} = p_{f} \)

The initial momentum of the system was founded in part "a" (p = 2 kg*m/s), so we have:

\( 2 kg*m/s = m_{b}v_{b_{f}} + m_{c}v_{c_{f}} \)

Again, when they come together, the final speed is the same:

\( 2 kg*m/s = v_{f}(m_{b} + m_{c}) \)                

\( v_{f} = \frac{2 kg*m/s}{0.2 kg + 0.3 kg} = 4 m/s \)

Now, since we found the final speed we can calculate the momentum of the system after they come together (equation 1):        

\( p_{T} = 0.5v_{f} = 0.5 kg*4m/s = 2 kg*m/s \)

I hope it helps you!                  

Answer:

Speed of sound ways in railroad = 6,135.8 m/s

Explanation:

Given:

Distance cover by sound wave = 2,350 meter

Time taken by sound wave to cover distance = 0.383 seconds

Find:

Speed of sound ways in railroad

Computation:

Speed = Distance / Time

Speed of sound ways in railroad = Distance cover by sound wave / Time taken by sound wave to cover distance

Speed of sound ways in railroad = 2,350 / 0.383

Speed of sound ways in railroad = 6,135.77

Speed of sound ways in railroad = 6,135.8 m/s

Given:

A ball bouncing eventually comes to stop.

To find:

What kind of a system is this?

Explanation:

An open system is a system where the free exchange of matter and energy with the surroundings takes place.

A closed system is where only the energy of the system is shared with the surrounding. In these kinds of systems, the exchange of matter does not take place.

An isolated system is where neither matter nor energy is exchanged between the system and the surrounding.

When a ball is bouncing, it gradually loses its kinetic energy to the surroundings and eventually comes to stop. But the mass of the ball remains the same. Thus this is a closed system.

Final answer:

The given system is a closed system.

Therefore the correct answer is option B.

(6) The angular speed of the blade is 293.2 rad/s.

(7) The linear speed of the tips of the blades in miles per hour is 305.4  mph.

(8) The linear speed of the tips of the blades in feet per second is 8.71 ft/s.

(9) The linear speed in miles per hour in which he is traveling is 10.78 mph.

(6) The angular speed of the blade is calculated as follows;

Diameter of the blade = 9 inches, radius = 4.5 inches

angular distance of the blade = 2800 rev/min

ω = 2800 rev/min  x 2π rad/rev  x  1 min / 60s

ω = 293.2 rad/s

(7) The linear speed of the tips of the blades in miles per hour is calculated as;

v = ωr

the angular speed, ω = 5 rev/s  x 2π rad/rev = 31.42 rad/s

r = 14 ft = 0.0027 mile

the linear speed, v = 31.42 rad/s  x 0.0027  mile = 0.085 mi/s

= 0.085 mi/s x 3600 s / hr = 305.4  mph

(8) The linear speed of the tips of the blades in feet per second is calculated as;

r = 25 inch = 2.08 ft

ω = 40 rev/min  x  2π rad/rev  x 1 min / 60s = 4.19 rad/s

the linear speed = v = 4.19 rad/s x 2.08ft = 8.71 ft/s

(9) The linear speed in miles per hour in which he is traveling is calculated as;

Diameter = 28 inches, radius = 14 inches

14 inches = 0.00022 mile

ω = 130 rev/min  x  2π rad/rev   x   60 min/1 hr = 49,008.85 rad/hr

the linear speed, v = 49,008.85 rad/hr x  0.00022 mile = 10.78 mph

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