2. A piece of alloy has a measured mass of 86g in air and 73 g when immersed in water. Find its
(a) volume
(b) density​

Answer:

A. Extracting mineral resources with modern mining equipment removes fertile topsoil.

Explanation:

Mining is defined as the process that involves the extraction of valuable minerals from large amounts of waste rock.

Progress in engineering has affected the natural environment and mining is one of the best examples of this. The use of modern mining equipment removes fertile topsoil and highly influences the fertility of the soil.  It is hard to reconstruct topsoil and modern mining equipment continuously damaging soil fertility.

Hence, the correct answer is "A. Extracting mineral resources with modern mining equipment removes fertile topsoil."

Answer:

a

Explanation:

a pex

Answer:

The trachea divides into a left and right bronchus inside the lungs. These further separate into bronchioles, The tiniest bronchioles have tiny air sacs at their ends. They are known as alveoli. Thus, option B is correct.

Explanation:

What is the role of trachea and alveoli?

The trachea splits into the right and left principal bronchi at the mediastinum at the level of the fifth thoracic vertebra.

The bronchi split off into progressively smaller channels before coming to an end in tiny air sacs known as alveoli.

During this process, oxygen diffuses from the alveoli to the blood through the alveolar walls' capillaries (small blood vessels).

Hemoglobin in red blood cells absorbs oxygen as it enters the bloodstream.

Therefore, trachea and alveoli in the respiratory system  work together to allow gas exchange.

The dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.

Start by converting the rotational speed from rpm (revolutions per minute) to rad/s (radians per second). Since 1 revolution is equal to 2π radians, we can use the conversion factor:

Angular speed (ω) = (1100 rpm) × (2π rad/1 min) × (1 min/60 s)

ω ≈ 115.28 rad/s

The moment of inertia (I) is given as 2.0 × 10^-7 kg⋅m².

Use the formula for rotational kinetic energy:

Rotational Kinetic Energy (KE_rot) = (1/2) I ω²

Substituting the given values:

KE_rot = (1/2) × (2.0 × 10^-7 kg⋅m²) × (115.28 rad/s)²

Calculate the value inside the parentheses:

KE_rot ≈ (1/2) × (2.0 × 10^-7 kg⋅m²) × (13274.28 rad²/s²)

KE_rot ≈ 1.331 × 10^-3 J

Round the result to the proper number of significant figures, which in this case is three, as indicated by the given moment of inertia.

KE_rot ≈ 4.8 × 10^-4 J

Therefore, the dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.

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Answer:

θ = 720º

Explanation:

Let's use the rotational kinematics relations for this exercise, remember that all angles must be given in radians.

Let's reduce the magnitudes to the SI system

         θ = 2 rev (2π rad / 1 rev) = 4π rad

we assume that the pulley has a radius r

linear and angular coordinates are related

         y = θ r

let's calculate

         y = 4π r

to convert the distance in angles to radians

        θ = y / r

        θ = 4π

let's change this angle to degrees

        π rad = 180º

         θ = 4π rad (180º /π rad)

         θ = 720º

The required electric field strengths are calculated to be E₁ = E₃ = 112.88 × 10³ N/C, E₂ = 0.

Length of the two glass rods is given as, L = 17 cm = 0.17 m

Charge on them = 16 nc = 16 × 10⁻⁹ C

Distance between the rods is given as 4 cm = 0.04 m.

Electric charge due to a single glass rod can be given by,

E = Q/ (2π ε₀ r L) ----(1)

(1) can be used to determine E₁, E₂, E₃ because the points lie within the two rods hence the net electric field produced will be equal to the difference in electric fields produced.

E₁ = Q/ (2π ε₀ r L) × [1/0.01 - 1/0.03]

⇒ (16 × 10⁻⁹)/(2× 3.14× 8.85 × 10⁻¹² × 0.17) × (66.67)

⇒  (16× 66.67 × 10³)/(9.45) = 112.88 × 10³ N/C

Let us find E₂,

E₂ = Q/ (2π ε₀ r L) × [1/0.02 - 1/0.02] = 0

And E₁ = E₃.

Thus, E₁ = E₃ = 112.88 × 10³ N/C, E₂ = 0.

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Answer:

18

Explanation:

I'm pretty sure I got it right

The box accelerates to the right due to the applied force of 35 N in the +x direction.

Newton's second law states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass. In this case, the net force acting on the box is 35 N in the +x direction, and its mass is 15 kg. Therefore, we can calculate the acceleration using the formula:

acceleration = net force / mass

acceleration = 35 N / 15 kg = 2.33 m/s² (rounded to two decimal places)

Since the box is not accelerating up or down, we can conclude that the force applied is only causing the box to accelerate in the horizontal direction.

Other forces such as gravity and friction are not considered in this scenario. Thus, the 15 kg box will experience an acceleration of approximately 2.33 m/s² in the +x direction due to the applied force of 35 N.

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Answer:

6m/s

Explanation:

We know that ,

\(\longrightarrow \) 2as = v² - u²

\(\longrightarrow \) 2 * 3m/s² * 6m = v² - (0)²

\(\longrightarrow \) v² = 36m²/s²

\(\longrightarrow \) v = √36 m²/s²

\(\longrightarrow \) v = 6m/s

Explanation:

kE =1/2mv²

1/2(0.6×(3m/s)²

1/2(0.6×9m/s)

2.7J I think this is the answer

The average kinetic energy of the toy car is 2.7 J.

The energy of the body by the virtue of its motion is known as the kinetic energy of the body. It is defined as the product of half of mass and square of the velocity.

Given data;

Mass of car is,m= 600 g = 0.6 kg

d is the distance travelled = 6 m

T is the time travelled = 2 sec

The velocity of the car is found as;

v  = d /t

V = 6m / 2 sec

V = 3 m/sec

KE =1/2mv²

KE = 1/2 × 0.6 kg ×( 3 m/sec )²

KE = 2.7 J

Hence, the average kinetic energy of the toy car is 2.7 J.

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The spring constant, k will be 18 N/m.The ratio of force to one unit of displaced length is known as the spring constant.

Spring constant is defined as the ratio of force per unit displaced length.

Given data;

Mass of  block,m=0.250 k

Amplitude,A = 0.125 m

Velocity,V=3.00 m/

Spring constant,K=?

The formula for the spring constant when the spring is oscillate at the given amplitude A:

\(\rm K = \frac{V_{max}^2 m}{A} \\\\ K = \frac{3.0 \times 0.250}{0.125} \\\\ K=18 \ N/m\)

Hence, the spring constant, k will be 18 N/m

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Answer:

the object's mass is 50 kg

Explanation:

We use Newton's second law to solve for the mass:

F = m * a , then   m = F / a

In our case, the acceleration is the gravitational acceleration on the planet, and the force is the weight of the object on the planet. So we get:

m = w / a = 650 N / 13 m/s^2 = 50 kg

Then, the object's mass is 50 kg.

Answer:

Antonie van Leeuwenhoek

Explanation:

The diameter and the radius of the field that Victoria ran around would be = 80m and 40m respectively.

The total distance covered by Victoria = 750meters

The number of time she ran around the field = 3

Therefore the circumference of the field = 750/3 = 250m

The formula for the circumference of circle = 2πr

That is ;

250 = 2×3.14 ×r

make r the subject of formula;

r = 250/ 6.28

r = 39.8 = 40 cm

Therefore the diameter = 2×40 = 80m

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Astronomers can learn important details about the atmosphere, surface temperature, and size of transiting planets.

A transiting planet that is the size of a brown dwarf often only dims the brightness of Sun-like stars by a few percent or less. The transit technique has been used to find the majority of known exoplanets. When a planet passes in front of an observer and a star, it is said to be transiting. Transits in our solar system can be seen from Earth as Venus or Mercury pass in front of the Sun. The atmosphere of a transiting exoplanet can be seen backlit by the star when it passes its host star. As exoplanets pass in front of and behind their stars, one can do further atmosphere observations.

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Answer: the angular velocity of a particle at the Earth's surface is approximately 7.27 x 10^-5 rad/s, and the linear velocity of the particle is approximately 464.1 m/s.

Explanation:

The density of the oil when the water and oil are mixed is 661kg/m³.

From the information illustrated, water and then oil are poured into a U-shaped tube, open at both ends and they then come to equilibrium.

It was stated that suppose that H = 25.7 cm and h = 8.72 cm. It should be noted that the pressure ends at the one of the opening is the atmospheric pressure, therefore the gauge pressure will be:

∆P = pgh

This will be illustrated as:

(0.257)P = (1000) × (0.257 - 0.0872)

0.257P = 169.8

Divide

P = 169.8 / 0.257

P = 661kg/m³

The density is 661kg/m³.

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Answer:

0.043 m upwards

Explanation:

The mass of the bullet, \($m_1$\) = 0.013 kg

Mass of the ballistic pendulum, \($m_2$\) = 3 kg

Velocity of the bullet, \($v_1$\) = 320 m/s

Therefore, from the law of conservation of momentum, we get

\($m_1v_1+m_2v_2=m_1v_1^1+m_2v_2^1$\)

\($(0.013 \times 320)+(3 \times 0) = \left(0.013 \times \frac{320}{0}\right) + (3 \times v_2^1)$\)

\($3 \times v_2^1=2.774$\)

\($v_2^1=0.92 \ m/s$\)

Therefore the required height to rise the block is given by :

\($(v_2^1)^2-v_2^2=2gh$\)

\($h=\frac{(v_2^1)^2-v_2^2}{2g}$\)

\($h=\frac{(0.92)^2-0}{2(-9.81)}$\)

\($h=-0.043 \ m$\)

Therefore, the block moves upwards for 0.043 meters.      

Answer:

From 0.75 to 1.25 hours

Explanation:

Given

See attachment for graph

Required

Point where they didn't move

This means that we identify the point where the distance didn't change.

Given that the distance is plotted on the y-axis, we simply check for the end points of any horizontal line on the graph

The horizontal line on the graph represents 30km and the time interval is: 0.75 to 1.25 hours.

Hence, (c)  is correct

The object distance of the lens is 10 cm and the image distance of the lens is 30 cm.

The object and image distance formed by the lens is calculated by applying the following lens formula.

v + u = 40 ------- (1)

v/u = 3 ------------ (2)

v = 3u

Substitute v into equation (1);

3u + u = 40

4u = 40

u = 40/4

u = 10 cm

The image distance = 3u

= 3 x 10 cm

= 30 cm

Thus, the object distance is 10 cm and the image distance is 30 cm.

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Answer:

a)    F_net = 6.48 10⁻¹⁸ ( \(\frac{1}{x^2} + \frac{1}{(0.300-x)^2}\) ),   b) x = 0.15 m

Explanation:

a) In this problem we use that the electric force is a vector, that charges of different signs attract and charges of the same sign repel.

The electric force is given by Coulomb's law

         F =\(k \frac{q_2q_2}{r^2}\)

Since when we have the two negative charges they repel each other and when we fear one negative and the other positive attract each other, the forces point towards the same side, which is why they must be added.

          F_net= ∑ F = F₁ + F₂

let's locate a reference system in the load that is on the left side, the distances are

left side - electron       r₁ = x

right side -electron     r₂ = d-x

let's call the charge of the electron (q) and the fixed charge that has equal magnitude Q

we substitute

          F_net = k q Q  ( \(\frac{1}{r_1^2}+ \frac{1}{r_2^2}\))

          F _net = kqQ  ( \(\frac{1}{x^2} + \frac{1}{(d-x)^2}\) )

let's substitute the values

          F_net = 9 10⁹  1.6 10⁻¹⁹ 4.50 10⁻⁹ ( \(\frac{1}{x^2} + \frac{1}{(0.30-x)^2}\) )

          F_net = 6.48 10⁻¹⁸ ( \(\frac{1}{x^2} + \frac{1}{(0.300-x)^2}\) )

now we can substitute the value of x from 0.05 m to 0.25 m, the easiest way to do this is in a spreadsheet, in the table the values ​​of the distance (x) and the net force are given

x (m)        F (N)

0.05        27.0 10-16

0.10          8.10 10-16

0.15          5.76 10-16

0.20         8.10 10-16

0.25        27.0 10-16

b) in the adjoint we can see a graph of the force against the distance, it can be seen that it has the shape of a parabola with a minimum close to x = 0.15 m

Answer:6

Explanation:$’n

The total uncertainty in the mass measurement is ± 0.3 g.

Uncertainty as used here means the range of possible values within which the true value of the measurement lies.

So uncertainty in measurement describes the range of possible errors that may result from a given measurement carried out.

The uncertainty in the measurement of  1 g , 2 g , 5 g and 10 g pieces is given as ± 0.1 g

The uncertainty in the measurement of  20 g , 50 g and 100 g pieces is given as ± 0.2 g

The total uncertainty in the mass measurement is calculated as;

the total uncertainty in the mass = ± 0.1 g + ± 0.2 g = ± 0.3 g

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Answer:

a.) 25.8 degree

b.) 44.1 degree

c.) 55.5 degree.

Explanation:

Given that the

Wavelength (λ) = 0.138 nm

Spacing d = 0.285 nm

Using the formula dtan Ø = n(λ)

Where n = number of diffraction maximum observed

1.) For the first diffraction maximum,

Substitute the values into the formula where n = 1

0.285 × 10^-9 × tanØ = 1 × 0.138 × 10^-9

Tan Ø = 0.138/0.285

Tan Ø = 0.4842

Ø = tan^-1(0.4842)

Ø = 25.84 degree

2.) For the second diffraction maximum

Where n = 2

0.285 × 10^-9 × tanØ = 2× 0.138 × 10^-9

Tan Ø = 0.276/0.285

Tan Ø = 0.9684

Ø = tan^-1(0.9684)

Ø = 44.1 degree

3.) For the third diffraction maximum

Where n = 3

0.285 × 10^-9 × tanØ = 3 × 0.138 × 10^-9

Tan Ø = 0.414/0.285

Tan Ø = 1.4526

Ø = tan^-1(1.4526)

Ø = 55.5 degree

Answer:

please mark me as brainliest I'm begging u

Explanation:

The behavior of an object that has been charged is dependent upon whether the object is made of a conductive or a nonconductive material. Conductors are materials that permit electrons to flow freely from particle to particle. An object made of a conducting material will permit charge to be transferred across the entire surface of the object. If charge is transferred to the object at a given location, that charge is quickly distributed across the entire surface of the object. The distribution of charge is the result of electron movement. Since conductors allow for electrons to be transported from particle to particle, a charged object will always distribute its charge until the overall repulsive forces between excess electrons is minimized. If a charged conductor is touched to another object, the conductor can even transfer its charge to that object. The transfer of charge between objects occurs more readily if the second object is made of a conducting material. Conductors allow for charge transfer through the free movement of electrons

Answer:

\(Velocity=\frac{dx}{dt}\)

Explanation:

Remember that instantaneous velocity is just a measure to know the velocity that any object has at any point given in time, so we just need to know the distance it has travel, which would be the change in position, and the time it took that change in position to occurr, this means distance by time, so we just divide dx by dt and we have the solution for instantaneous velocity.

If a change in position as denoted by \(dx\) and \(dt\) change in time, the instantaneous velocity will be given by,

\(v = \dfrac {dx}{dt}\)

\(v = \dfrac {dx}{dt}\)

Where,

\(v\) - instantaneous velocity

\(dt\)   - change in distance (position)

\(dt\)- change in time

Therefore, if a change in position as denoted by \(dx\) and \(dt\)change in time, the instantaneous velocity will be given by,

\(v = \dfrac {dx}{dt}\)

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A- When preparing breakfast, Lola undergoes the following physical changes: Butter the bread and fries the bacon. oranges are squeezed for orange juice

Butter the toast: The heat of the toast causes the butter to gently melt when Lola spreads it on the bread. This is a physical modification because it only modifies the butter's and toast's physical characteristics, not their chemical makeup.

Fry bacon: When Lola fries the bacon, the heat melts the fat and denatures and coagulates the proteins, giving the bacon a crispy quality. This is likewise a physical modification because it only modifies the bacon's physical characteristics, not its chemical makeup.

Oranges are squeezed to produce orange juice. The juice is drawn from the orange cells and separated from the pulp when Lola squeezes oranges.

A physical alteration is one in which just the substance's physical characteristics, such as shape, size, colour, or state, are altered. The substance's chemical makeup remains unchanged. The butter, bacon, and orange are all enduring physical modifications in the activities that Lola completes because they simply alter their physical characteristics without altering their chemical makeup. For instance, altering the physical qualities of things without altering their chemical makeup includes melting butter and bacon and extracting the juice from an orange.

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The work-energy theorem states that the change in the kinetic energy of an object will be equal to the net work done on the object.

Mathematically, it can be expressed as;

ΔKE = W

Where; ΔKE represents the change in kinetic energy of the object,

W represents the net work done on the object.

This theorem states that when work is done on an object, it results in a change in its kinetic energy. If work is done on an object, its kinetic energy increases, and if work is done by an object, its kinetic energy decreases.

This theorem is a fundamental principle in physics that relates the concepts of work and energy, and it is often used to analyze the motion and behavior of objects in various physical systems.

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6.6% is the percentage of bottle speed to ball entry velocity.

What is the simple definition of velocity?

Velocity is defined as: The rate of change of the object's position in any direction. Velocity is measured as the ratio of distance traveled and time traveled. Velocity is a scalar quantity because it has only direction and not magnitude.

What are the some examples of speed?

If you know the distance an object travels in a given time, you can find the speed of the object. For example, if a car travels 70 miles in one hour he travels 70 miles per hour (miles per hour).

Why measure speed?

Measuring movement speed can be very useful in saving time. A speedometer is used to measure speed of an car. An odometer is useful for measuring mileage.

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Answer:

Δt = 0.315s

Explanation:

To calculate the time difference, in which both fans hear the batterstrike, you first calculate the time which takes the sound to travel the distances to both fans:

\(t_1=\frac{d_1}{v_s}\)

\(t_2=\frac{d_2}{v_s}\)

d1: distance to the first fan = 18.3 m

d2: distance to the second fan = 127 m

vs: speed of sound = 345 m/s

You replace the values of the parameters to calculate t1 and t2:

\(t_1=\frac{18.3m}{345m/s}=0.053s\\\\t_2=\frac{127m}{345m/s}=0.368s\)

The difference in time will be:

\(\Delta t =t_2-t_2=0.368s-0.053s=0.315s\)

Hence, the time difference between hearing the sound at the location s of both fans is 0.315s