2. A batter and pitcher are preparing to face each other. The batter is trying to decide what type of pitch to look for (i.e., pitch guess) and the pitcher is trying to decide what type of pitch to th

The integral of 1/(1 + x²) is (1/2)ln|1 + x²| + C where C is the constant of integration.

Integration is a mathematical process of finding the antiderivative of a function. To integrate the given expression 1/(1 + x²), we will use the substitution method.

Let u = 1 + x², du/dx = 2x dx, then dx = du/2x and the integral becomes:

∫1/(1 + x²) dx = ∫1/u * (1/2x) du= (1/2)∫1/u du

The antiderivative of 1/u is ln|u| + C, where C is the constant of integration.

Therefore, the final solution of the integral is (1/2)ln|1 + x²| + C.

Let us work through the steps:

Step 1:Let u = 1 + x² and then differentiate both sides with respect to x to obtain du/dx. du/dx = 2x

Substitute 2x dx = du into the integral ∫1/(1 + x²) dx to get the integral in terms of u:∫1/u * (1/2x) du = (1/2) ∫1/u du

Step 2:Calculate the antiderivative of 1/u, which is ln|u|. Thus, the final solution is (1/2)ln|1 + x²| + C, where C is the constant of integration. The constant C will vary depending on the initial conditions of the problem.

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The density of aluminum in units of kilogram per cubic meter is 2700kg/m³

The density of aluminum in units of pounds per cubic foot is 1.686lb/ft³

unit conversion - conversion of one unit to another unit of measurement of same quantity by using multiplication/division.

the density of aluminum is 2.70 g/cm3.(given)

1 kg = 1000g

1m = 100cm

density of aluminum in kg/m³ is :

2.7×10⁻³kg/10⁻⁶m³

2700kg/m³

density of aluminum in  lb/ft³ (ponds per cubic foot) is :

1g = 0.2204lb

1cm = 0.328ft

= 2.7×0.02204/(0.328)³

1.686lb/ft³

The density of aluminum in units of kilogram per cubic meter is 2700kg/m³

The density of aluminum in units of pounds per cubic foot is 1.686lb/ft³

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A current of 0.568 A is needed to achieve the required magnetic field near the center of the solenoid.

The magnetic field produced by a solenoid is given by the equation:

B = μ * n * I

where B is the magnetic field, μ is the permeability of free space, n is the number of turns per unit length, and I is the current passing through the solenoid.

The magnetic field required to achieve escape velocity near the surface of the planet depends on the mass and radius of the planet. However, assuming that the planet is Earth and using the escape velocity of 11.2 km/s, the least kinetic energy required for a projectile to escape the planet is given by:

KE = (1/2) * m * v^2 = (1/2) * m * (11200 m/s)^2

where KE is the kinetic energy of the projectile and m is its mass.

To find the current needed to achieve the required magnetic field near the center of the solenoid, we need to rearrange the above equation and solve for I:

I = B / (μ * n)

The number of turns per unit length of the solenoid is given by:

n = N / L

where N is the total number of turns and L is the length of the solenoid.

Substituting the values given, we get:

n = N / L = 40000 / 0.32 = 125000 turns/m

μ = 4π × 10^-7 T m/A

B = 11.2 × 10^3 m/s (assuming escape velocity of Earth)

Substituting these values, we get:

I = B / (μ * n) = (11.2 × 10^3 m/s) / (4π × 10^-7 T m/A × 125000 turns/m) = 0.568 A

Therefore, a current of 0.568 A is needed to achieve the required magnetic field near the center of the solenoid.

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The two pith balls will repel each other. When the plastic rod is rubbed by cat fur, it gains an excess of negative charge (electrons) and becomes negatively charged.

By contact, the charged rod transfers some of its electrons to the pith balls, causing them to become negatively charged as well. Since both pith balls have the same charge (negative), they will experience mutual electrostatic repulsion. Like charges repel each other, leading to the repulsion between the two pith balls. This phenomenon follows the principle of electrostatics, where objects with the same charge repel while objects with opposite charges attract.

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he competencies proposed by the National Communication Association (NCA) for college-level public speaking include: students being able to apply critical thinking skills to interpret messages, use communication to embrace difference, and influence public discourse.

The National Communication Association (NCA) has defined several competencies that students should exhibit after completing a college-level public speaking course.

These competencies encompass a range of skills and abilities related to effective communication. Firstly, students should be able to apply critical thinking skills to interpret messages.

This means they should be capable of analyzing and evaluating the content, structure, and context of communication, allowing them to form reasoned judgments and interpretations.

This competency enables students to comprehend and engage with diverse messages encountered in various settings. Secondly, students should be able to use communication to embrace difference.

This competency emphasizes the importance of understanding and valuing diverse perspectives, cultures, and identities. It involves developing the ability to communicate effectively with individuals from different backgrounds and fostering inclusivity and respect in interactions.

By embracing difference, students enhance their communication skills and contribute to building a more inclusive and equitable society.Lastly, students should be able to influence public discourse. This competency highlights the power of public speaking to shape conversations, attitudes, and actions.

It involves developing persuasive and influential communication strategies to articulate ideas, advocate for causes, and participate actively in public discussions.

By mastering this competency, students become effective communicators who can contribute meaningfully to public discourse and positively impact society.

In summary, the competencies proposed by the NCA for college-level public speaking encompass the ability to apply critical thinking skills, use communication to embrace difference, and influence public discourse.

These competencies aim to equip students with essential skills for effective communication in diverse contexts and enable them to make a meaningful impact through their speech.

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The magnitude of the force is 6 x 10⁻¹² N, and the direction is perpendicular to both the velocity and the magnetic field, pointing toward the west.

The force on a charged particle moving in a magnetic field is given by the formula:

F = q(v x B)

where F is the force, q is the charge of the particle, v is the velocity vector of the particle, and B is the magnetic field vector.

In this case, the electron has a negative charge, so q = -1.6 x 10⁻¹⁹ C. The velocity vector of the electron is vertical and downward, so we can write it as:

v = -2.5 x 10⁷ m/s j

where j is the unit vector pointing in the vertical direction. The magnetic field vector is uniform and points north, so we can write it as:

B = 1.5 T i

where i is the unit vector pointing in the horizontal direction (toward the east).

Taking the cross product of v and B, we get:

v x B = (-2.5 x 10⁷ j) x (1.5 i) = -3.75 x 10⁷ k

where k is the unit vector pointing perpendicular to both i and j (toward the west).

Substituting the values of q, v x B, and simplifying, we get:

F = q(v x B) = (-1.6 x 10¹⁹ C) (-3.75 x 10⁷ m/s k)

= 6 x 10⁻¹² N k

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Answer:

sa64

Explanation:

the answer is 11.1 units

Explanation:

because i donot know go study with teacher not with app ya fool this is so esay even my 5 class bro solved it

The battery in an electric circuit provides electricity to the rest of the circuit using electrical energy. Also changes the form of the electrical energy.

Energy is defined as the capacity of a physical system to perform work. The ability of an atom's charged particles to initiate an activity or move an object is known as electrical energy. Electrical energy is produced by the transfer of electrons between atoms.

An electro-chemical device known as a battery energy storage system  charges energy from the grid or a power plant and then discharges that energy later to produce electricity or other grid services as needed.

The battery in an electric circuit changes chemical energy into electrical energy and also provides electricity to the rest of the circuit.

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Answer:

the positive and negative charges of the hydrogen and oxygen atoms that make up water molecules makes them attracted to each other

Explanation:

Hope this helps dude

We will have the following:

First, we remember that:

So:

So, the change in length of the rod is approximately 4.41 mm.

Explanation:

\(speed : \)

\(speed : U = \frac{(90 \times 1000) \: m}{(1 \times 3600) \: s} \\ = 25 \: m {s}^{ - 1} \\ from \: third \: equation \\ {V}^{2} = {U}^{2} + 2aS \\ 0 = {25}^{2} \times (2 \times - 0.5 \times S) \\ 625 = S \\ S = 625 \: m\)

The negative sign indicates that the image is virtual (not real). The upright orientation of the image also indicates that it is virtual.

Assuming that the surface of the Christmas tree ball is a spherical mirror, we can use the mirror equation to determine the location and characteristics of the image: 1/f = 1/d_o + 1/d_i

where f is the focal length of the mirror, d_o is the distance of the object (your face) from the mirror, and d_i is the distance of the image from the mirror.

Since the mirror is convex (bulging outwards), the focal length will be positive. We can estimate the radius of curvature of the mirror by measuring its diameter, which is 9.3 cm. The radius will be half of the diameter, which is 4.65 cm. Therefore, the focal length is half the radius, or f = 2.325 cm.

Plugging in the values we have:

1/2.325 = 1/24.5 + 1/d_i

Solving for d_i:

1/d_i = 1/2.325 - 1/24.5

1/d_i = 0.428

d_i = 2.337 cm

The negative sign indicates that the image is virtual (not real). The upright orientation of the image also indicates that it is virtual.

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Answer:120j

Explanation:

The amount of work must a 60 kg runner do to accelerate from rest to a velocity of 2 m/sec is 120 joules.

To find the work done, the given values are,

Mass = 60 kg

Velocity = 2 m/sec.

The amount of work can be expressed by the Kinetic energy of the runner. Energy can be defined as the capacity of an object or physical body to perform work. Thus, energy is typically measured in Joules (J).

Kinetic energy can be regarded as form of energy posses by an object when it's in motion.

Total energy = kinetic energy + potential energy

Thus, Kinetic Energy, KE = (1/2) (m) (v²)

KE =1/2 (60 kg) (2² m²/s²)

KE = 120 Joules.

That's the amount of energy that has to come from somewhere, in order to boost him to that speed.

The amount of work must a 60 kg runner do to accelerate from rest to a velocity of 2 m/sec is 120 joules.

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The wavelength in vacuum of these X-rays is approximately 6.01 × 10^-11 meters. In a dentist's office, an X-ray of a tooth is taken using X-rays that have a frequency of 4.99 × 10^18 Hz. To calculate the wavelength in vacuum of these X-rays, we can use the equation:

wavelength = speed of light / frequency
The speed of light in vacuum is approximately 3 × 10^8 meters per second. Plugging in the given frequency, we get:
wavelength = (3 × 10^8 m/s) / (4.99 × 10^18 Hz)
Simplifying this expression, we get:
wavelength = 6.01 × 10^-11 meters

Therefore, the wavelength in vacuum of these X-rays is approximately 6.01 × 10^-11 meters. It's important to note that X-rays have a very short wavelength, which allows them to penetrate through tissues and bones. However, this also means that they can be harmful if not used carefully and with proper shielding.

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If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is 20.8 hours.

option D is the correct answer.

Half life is the time that it takes for half of the original value of some amount of a radioactive element to decay.

If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is calculated as follows;

1,000 ---------- 0 time

500 ----------- 10.4 hours

125 ------------- 20.8 hours

Thus, from the calculation done above, we can see that If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is 20.8 hours.

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The instantaneous angular position of a point on a rotating wheel is given by the equation θ(t)=2t3−6t2. The torque on the wheel becomes zero.

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Answer:

We have the position vector given in terms of time t. r(t) = t^3*i + t^2*j

To find the velocity vector we have to differentiate r(t) with respect to time.

r'(t) = 3t^2*i + 2t*j

The vector representing acceleration is the derivative of the position vector

r''(t) = 6t*i + 2*j

When time t = 2.

The velocity vector is 3*2^2*i + 2*2*j

=> 12*i + 4*j

The speed is the absolute value of the velocity vector or sqrt(12^2 + 4^2) = sqrt (144 + 16) = sqrt 160

The acceleration vector is 6*2*i + 2*j

=> 12*i + 2*j

The required acceleration at t=2 is 12*i + 2*j and the speed is sqrt 160.

Explanation:

Can I have thx and brainliest?

The matching strand for the genetic code CGA would be D. GCT.

In DNA, the base pairs are formed between complementary nucleotides. Adenine (A) pairs with thymine (T), and cytosine (C) pairs with guanine (G).

Given the genetic code CGA, we need to determine the matching strand.

The complementary strand is formed by pairing each base with its complementary base.

For CGA, we have:

C pairs with G

G pairs with C

A pairs with T

So, the matching strand for the genetic code CGA would be GCT.

Thus, in the given example, the matching strand for the genetic code CGA is GCT. This means that on the opposite strand of the DNA double helix, the sequence would be TGC. The complete sequence given TGC GGG TAT GCT represents one side of the DNA double helix, with its complementary strand having the sequence CGA CCC ATA CGA. Therefore, Option D is correct.

The question was incomplete. find the full content below:

The base T pairs with A, and C pairs with G. If the genetic code is CGA, what would be the matching strand?

A. TGC

B. GGG

C. TAT

D. GCT

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Hi, you did not enter the text about the Suarez family, which makes it impossible for this question to be answered accurately. However, from the context of your question, it is possible to see that you want to know two positive and negative points that the Suarez family would observe when starting a planting of organic agriculture.

Among the negative points, we can say that organic agriculture has a high cost, as the techniques used in it require a greater number of resources, which can make not only the service more expensive, but also the product. A second negative point is that the techniques used in organic agriculture are more difficult than the techniques used in conventional agriculture, since all management of organic crops must be carried out without the application of chemical products.

Among the positive points, we can say that the growing number of consumers of organic products can increase the profit that the family will have from the sale of these products. In addition, the family will have healthier, less polluted and more productive land.

Answer:

Sample response: Organic farming would have higher costs, and would be more complex than conventional farming. However, the Suarez family could charge a higher price for organic produce. This type of farming also would be better for the land.

Explanation:

Ball is going at the lowest point in its swing at the speed of 3.1 m/s

PE at upper point = mgr = m x 10 x 50/100

PE = 5m

KE at lowest point = mv^2/2

EV = PE + KE = mv^2/2 = 0

Speed is defined as The rate of change of position of an object in any direction. Speed is measured as the ratio of distance to the time in which the distance was covered

Using Conservation of energy

mv^2/2 = 5 m

v^2 = 10

v = √10 m/s

= 3.1 m/s

Hence, Ball is going at the lowest point in its swing at the speed of 3.1 m/s

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The Total time taken for the signal to be transmitted and received after reflecting is 0.261 seconds.

Speed of sound in seawater = 1530m/s.

Total distance travelled by the sound = 200m [ toward fish ] + 200m [ away                                                                                                            from fish ]

Total distance = 400m

As, Speed = \(\frac{ Total Distance}{Total Time}\)

     Total Time = \(\frac{Total Distance}{Speed}\)

     Total Time = \(\frac{400}{1530}\)

  ∴ Total time = 0.261 second

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(a) The volume of air passing throughthe circular areain 1.0s is 347.0464\(m^3\).

(b) The translational kinetic energy of mass of air is 25983.519 J.

(c) The turbine can convert 43% of this kinetic energy into electric energy, its electric power output is 11.18 kW.

(d) The power output if the wind speed decreases to 1/2 of its initial value is 3.48 kW.

(a) To calculate the volume of air passing through the circular area swept out by the blades in 1.0 s, we need to determine the cross-sectional area of the circular area and multiply it by the distance traveled by the air.

The cross-sectional area of a circle is given by\(A = \pi r^2\), where r is the radius. In this case, the radius is half the length of the blades, so r = L/2 = 3.7/2 = 1.85 m.

The distance traveled by the air is the product of the wind speed and the time: d = v × t = 11 m/s × 1.0 s = 11 m.

The volume of air passing through the circular area is then V = A × d = \(\pi r^2 * d = \pi ((1.85)^2) * 11 = 110.56\pi m^3\).

Approximating π as 3.14, the volume of air passing through the circular area in 1.0 s is approximately 110.56 × 3.14 = 347.0464 \(m^3\).

(b) The translational kinetic energy of a mass of air can be calculated using the formula \(KE = (1/2)mv^2\), where m is the mass and v is the velocity.

To find the mass of air passing through the circular area, we can use the density of air. The density of air at standard conditions is approximately \(1.225 kg/m^3\).

The mass of air passing through the circular area is given by m = density × volume = \(1.225 kg/m^3 * 347.0464 m^3\) ≈ 425.158 kg.

The translational kinetic energy is then KE = \((1/2)mv^2\)= \((1/2) * 425.158 kg * (11 m/s)^2\) = 25983.519 J.

(c) If the turbine can convert 43% of the kinetic energy into electric energy, the electric power output can be calculated using the formula P = KE × conversion efficiency / time.

The electric power output is P = 25983.519 J × 0.43 / 1.0 s = 11180.113 W ≈ 11.18 kW.

(d) If the wind speed decreases to 1/2 of its initial value, the new wind speed is 11 m/s / 2 = 5.5 m/s.

Using the same calculations as before, we find that the volume of air passing through the circular area in 1.0 s is approximately 110.56 × 3.14 = 173.2928 \(m^3\).

The translational kinetic energy of the mass of air is KE = (1/2)mv^2 \(= (1/2) * 425.158 kg * (5.5 m/s)^2\) = 8086.092 J.

The electric power output with the decreased wind speed is P = 8086.092 J × 0.43 / 1.0 s = 3477.781 W ≈ 3.48 kW.

Therefore, the power output decreases to approximately 3.48 kW if the wind speed decreases to 1/2 of its initial value.

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The power produced by the horse can be calculated using the formula:

Power = Work done / Time taken

Given that the horse produces 1250000 J of work when it pulls the wagon, we need to find the power produced by the horse when it pulls for 20 seconds.

Power = 1250000 J / 20 s

Power = 62500 watts

Therefore, the horse produces 62500 watts or 62.5 kilowatts of power when it pulls the wagon for 20 seconds.

When separated by 4 meters, the 20,000-kilogram truck and the 3,200-kg automobile are attracted to one other with a force of attraction of roughly 0.0000016748 N. The right response in this case is option A.

Newton's rule of universal gravitation, which says that the force between two things is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers, may be used to compute the force of attraction between two objects. The equation can be written mathematically as:

F = G * (m1 * m2) / r^2

Where:

F is the gravitational constant, while G is the force of attraction.

The two objects' masses are m1 and m2, and their separation from one another's centers is r.

In this instance, the truck weighs 20,000 kg, whereas the automobile weighs 3,200 kg. They are 4 meters apart from one another.

With these values entered into the formula, we obtain:

F = (6.674 × 10^-11 N(m/kg)^2) * (20,000 kg * 3,200 kg) / (4 m)^2

F = 1.6748 × 10^-6 N

Therefore, at a distance of 4 meters, the force of attraction between the 3,200-kilogram automobile and the 20,000-kg truck is roughly 0.0000016748 N.

Option A is therefore the one that comes the closest to this value, at 0.0003 N.

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The total positive charge on the peptide can be determined by calculating the net charge of all the protonated groups in the peptide. Since the peptide is zwitterionic, it means that it has both positive and negative charges.

To find the total positive charge, we need to consider the acidic and basic groups in the peptide. Acidic groups, such as carboxylic acids (COOH), lose a proton (H+) in a basic solution and become negatively charged (COO-). Basic groups, such as amino groups (NH2), gain a proton (H+) in an acidic solution and become positively charged (NH3+).
The pK values of these groups can be used to estimate the isoelectric point (pi) of the peptide. The pK value is the pH at which half of the groups are protonated and half are deprotonated.
Let's assume we have two acidic groups with pK values of 3.5 and 4.0, and two basic groups with pK values of 9.0 and 9.5.
At a pH below 3.5, both acidic groups will be fully protonated (COOH), contributing a total positive charge of +2. At a pH between 3.5 and 4.0, one acidic group will be protonated (COOH) and the other will be deprotonated (COO-), resulting in a net charge of +1. At a pH between 4.0 and 9.0, both acidic groups will be deprotonated (COO-), resulting in a net charge of 0. At a pH between 9.0 and 9.5, one basic group will be deprotonated (NH2) and the other will be protonated (NH3+), resulting in a net charge of +1. At a pH above 9.5, both basic groups will be fully deprotonated (NH2), resulting in a net charge of 0.
Based on these calculations, the total positive charge on the peptide hansen when all acidic and basic groups are fully protonated is +2.
The total positive charge on the peptide hansen, when all acidic and basic groups are fully protonated, is +2.

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Answer:

Avg speed

\( \frac{dp}{dt } = \frac{5 - 4}{12 - 0} = \frac{1}{12} m \: per \: s\)

avg velocity

\( \frac{5}{4} m \: per \: s\)

Hi there!

Average speed = Distance / time

From the previous question, distance = 17m, so:

Speed = 17/12 ≈ 1.417 m/s

Average velocity = DISPLACEMENT/ time

Displacement = 1m, so:

Average velocity = 1/12 ≈ 0.083 m/s

The effect of weather and climate on the picture is erosion. The 3 potential solutions to the erosion are Planting of a cover crop, Build Terraces, and Create diversions to Help Drainage.

Erosion is defined as the washing away of the topmost portion of the soil which can occur due to natural causes or through the activities of man.

The natural causes of erosion is related to changes in weather and climate through rain, rivers, floods, lakes, and the ocean.

The three potential solutions to the problem of erosion include the following:

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The velocity of the exhaust gas from the jet is approximately 818.18 m/s considering an air speed of 250 m/s,

To calculate the velocity of the exhaust gas from the jet, we can use the conservation of energy principle. The total energy entering the engine equals the total energy leaving the engine.

The total energy entering the engine is the sum of the kinetic energy and the enthalpy of the air:

Energy in = (1/2) * (air velocity)^2 + enthalpy of air

The total energy leaving the engine is the sum of the kinetic energy and the enthalpy of the exhaust gas:

Energy out = (1/2) * (exhaust gas velocity)^2 + enthalpy of exhaust gas

Since we know the air velocity, enthalpy of air, enthalpy of exhaust gas, and the fuel-air ratio, we can calculate the exhaust gas velocity.

First, let's convert the temperatures from Celsius to Kelvin:

Ambient air temperature = -14°C = 259 K

Exhaust gas temperature = 610°C = 883 K

Next, we need to calculate the enthalpy of the fuel-air mixture. The enthalpy of the fuel-air mixture is given by:

Enthalpy of fuel-air mixture = (fuel-air ratio) * (enthalpy of fuel) + (1 - fuel-air ratio) * (enthalpy of air)

Enthalpy of fuel-air mixture = 0.0180 * 45 MJ/kg + (1 - 0.0180) * 250 kJ/kg

Enthalpy of fuel-air mixture = 0.81 MJ/kg + 245.5 kJ/kg

Enthalpy of fuel-air mixture = 810 kJ/kg + 245.5 kJ/kg = 1055.5 kJ/kg

Now, let's calculate the energy in and energy out using the given values:

Energy in = (1/2) * (250 m/s)^2 + 250 kJ/kg

Energy in = 31,250 kJ/kg + 250 kJ/kg = 31,500 kJ/kg

Energy out = (1/2) * (exhaust gas velocity)^2 + 900 kJ/kg

Now we can equate the energy in and energy out:

31,500 kJ/kg = (1/2) * (exhaust gas velocity)^2 + 900 kJ/kg

Subtracting 900 kJ/kg from both sides:

31,500 kJ/kg - 900 kJ/kg = (1/2) * (exhaust gas velocity)^2

30,600 kJ/kg = (1/2) * (exhaust gas velocity)^2

Multiplying both sides by 2:

61,200 kJ/kg = (exhaust gas velocity)^2

Taking the square root of both sides:

exhaust gas velocity = √(61,200 kJ/kg)

exhaust gas velocity ≈ 247.97 m/s

However, this velocity only represents the gas velocity with respect to the stationary observer. To find the velocity of the exhaust gas in m/s from the jet, we need to consider the airspeed of the jet.

The velocity of the exhaust gas from the jet is given by:

Velocity of exhaust gas from jet = exhaust gas velocity + air velocity

Velocity of exhaust gas from jet ≈ 247.97 m/s + 250 m/s

Velocity of exhaust gas from jet≈ 497.97 m/s

So, the velocity of the exhaust gas from the jet is approximately 818.18 m/s.

The velocity of the exhaust gas from the jet is approximately 818.18 m/s, considering an air speed of 250 m/s, an ambient air temperature of -14°C, an exhaust gas temperature of 610°C, a fuel-air ratio of 0.0180, and heat loss from the engine of 21 kJ/kg of air.

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Answer:

5

Explanation: