Strong acids and bases are 100% ionized in an aqueous solution.
Weak acids and bases are less than 100% ionized in an aqueous solution.
e.g.
Strong acid:
HCl (aq) ===> H+ + Cl- 100% ionized.
Strong Base:
NaOH (aq) ===> Na+ + OH-
These are some of strong acids and bases.
determine the electron geometry (eg) and molecular geometry (mg) of the carbon in hcn. (the carbon is in the middle. the h is bonded to the c and the n is bonded to the c.)
The electron geometry of HCN is linear geometry and molecular geometry of the carbon in HCN is linear geometry.
The lewis structure is as follows :
H - C ≡ N :
The number of the the valence electrons = 10 electrons
The carbon is the central atom. The HCN is the AX2 type of the molecule. The A is the central atom. X is the central atom. This type of the molecule has the linear electron geometry. There is no lone in the central atom, therefore the molecular geometry of the HCN is linear geometry.
Thus the both electron and the molecular geometry is linear.
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The highpoint of a wave is called a
Answer:
crest
Explanation:
Enrichment Activity 2: Identify the Dependent and Independent Variables
1.In a short bondpaper,draw the tables as shown below.Read and analyze the given situations and identify the Dependent. and independent Variables.Write your answer in its corresponding column.
Independent: Dependent:
2.Read carefully the sample situations.
3.Analyze,then determine the Dependent and independent variables.
4.Write your answers under each column.
the situations are in the picture
I hope the attached answer of image helps you.
By Benjemin
When a 17.9 mL sample of a 0.458 M aqueous nitrous acid solution is titrated with a 0.368 M aqueous potassium hydroxide solution, what is the pH after 33.4 mL of potassium hydroxide have been added
Answer:
pH = 12.90
Explanation:
THe reaction of HNO₃ with KOH is:
HNO₂ + KOH → KNO₂ + H₂O
That means 1 mole of nitrous acid reacts per mole of potassium hydroxide.
To solve this question, we need to find the moles of each reactant:
Moles HNO₂:
0.0179L * (0.458mol / L) = 0.00820 moles
Moles KOH:
0.0334L * (0.368mol / L) = 0.01229 moles
That means KOH is in excess. The moles in excess are:
0.01229 moles - 0.00820 moles = 0.00409 moles KOH = Moles OH⁻
The [OH⁻] is -Total volume = 17.9mL+33.4mL = 51.3mL = 0.0513L-:
0.00409 moles / 0.0513L =
0.0797M =[OH⁻]
pOH = -log[OH⁻] = 1.098
pH = 14 - pOH
pH = 12.90Which of these pairings with create an octet for each atom?
A. One aluminum atom and one oxygen atom
B. One magnesium and one chlorine
C. One magnesium and one oxygen
D. One potassium and one sulfur atom
Answer:
C) one magnesium and one oxygen
Select all correct statements dealing with electron affinity. a) In general the first electron affinity is: X(g) → X+(g) + e-b) It is the enthalpy change associated with the addition of an electron to a gaseous atom or ion.c) It is the enthalpy change associated with the removal of an electron from a gaseous atom or ion.d) In general the first electron affinity is: X(g) + e- → X-(g)
Option C and D are correct.
Explanations:What is electron affinity?Electron affinity is dfined as the energy required to remove en electron from a gaseous atom or molecule. An example of a gaseous atom loosing an electron is given as:
\(X(g)+e^-\rightarrow X^-(g)\)From the reaction, you can see that the gaseous element X looses an electron from its outershell to form an ion. This reaction is known as the first electron affinity.
Hence the correct statement dealing with electron affinity are:
• It is the enthalpy change associated with the, removal of an electron, from a gaseous atom or ion.
• In general the, first electron affinity, is:, X(g) + e- → X-(g)
which statement is true about the reaction shown by this chemical equation HCl + NaOH ------> NaCl + H2O
Answer:
A. It is exothermic
Explanation:
This reaction of acid and base represents synthesis reaction because new subsatnces are produced.
What is synthesis reaction?Synthesis reactions are reactions that occur when two different atoms combines to form a different molecule. A synthesis reaction can be represented by the equation i.e. A + B → C. In this equation, the A and B represent the reactants whereas the C represents the product.
So we can conclude that option C is the correct answer which is the synthesis reaction.
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(a) 1.42 light-years to miles (a light-year is an astronomical measure of distance—the distance traveled by light in a year, or 365 days; the speed of light is 3.00 × 108 m/s).
The value in mile is 8.35 * 10^12 miles.
What is conversion?It is often important to be able to convert values from one unit to another. This has always helped to make mathematical and physical computations much easier.
The conversion factor is often used to convert from one unit to another. It serves as bridge that would enable us to be able to convert quantities. The conversion factor has to be dimensionally correct.
Let us now convert 1.42 light-years to miles;
1.42 light years * 3.00 × 108 m/1 s * 1 mi/1609 m * 3600 s/1 hr * 24 hrs/1 day * 365 days/1 year
= 8.35 * 10^12 miles
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oxidation number of Ag in Ag2O
The oxidation number of Ag in Ag2O is +1.
In Ag2O, there are two silver atoms (Ag) and one oxygen atom (O). Oxygen is known to have an oxidation number of -2 in most compounds. Since the compound is neutral, the sum of the oxidation numbers of all the atoms must equal zero.
Therefore, the oxidation numbers of the two silver atoms must add up to +2 to balance out the -2 oxidation number of the oxygen atom. Since there are two silver atoms, each silver atom must have an oxidation number of +1 to yield a total oxidation number of +2 for the compound.
In Ag2O, the silver atoms lose one electron each to form Ag+ ions. This results in an oxidation number of +1 for each silver atom. The oxygen atom gains two electrons from the silver atoms to achieve a stable octet configuration, resulting in an oxidation number of -2 for the oxygen atom. The compound Ag2O is formed through the transfer of electrons, with each silver atom exhibiting an oxidation number of +1.
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What do scientists mean when they refer to population
population is the number of species living in a given area if this is regarding biology or earth studies :)
What is the molarity of calcium bicarbonate if 9.56 mL of 1.30 M HNO3 is required in a titration to neutralize 50.0 mL of a solution of Ca(HCO3)2?
Answer:
=> 0.12428 M
Explanation:
To begin, write down a balanced equation;
Ca(HCO3)2 + 2HNO3 => Ca(NO3)2 + 2H2O + 2CO2
Then calculate the number of moles contained in 9.56 mL of 1.30M HNO3
We know that molarity is contained in 1000mL
1000 mL = 1.30 moles
9.56 mL = ?
= (9.56 × 1.30)/1000
= 0.012428 moles
Mole ratio
Ca(HCO3)2 : HNO3
1 : 2
But, xmoles : 0.012428 moles
x = 1/2 × 0.012428
= 0.006214 moles
This moles is contained in 50 mL solution.
50 mL = 0.006214 moles
1000 mL = ?
= (1000 × 0.006214)/50
= 0.12428M
An object accelerates at 8 m/s2 when a force of 40 N is applied to it. What is the mass of the object
Answer:
f=ma
40=m*8
m=5kg
another object of same mass is added
=>m=5+5=10kg
f=10*8=80N
Explanation:
How are stars and comets different?
A. A star has a solid rock and gas surface, while a comet has tail of dust and gas.
B. A star has a tail of dust and gas, while a comet has a solid rock surface.
C. A star is made up of burning gases, while a comet is made up of ice, gases, rocks, and dust.
D. A star is made up of ice, rocks, and dust, while a comet is made up of burning gases.
2. How many moles are in 2.43 x 1024 particles of Carbon Monoxide
(CO)?
Answer:
= 14.63 × \(10^{45}\) particles.
Explanation:
According to Avogadro's priciple:
1 mole of any substance is 6.02 × \(10^{23}\) particles
∴ 2.43 x \(10^{24}\) moles × 6.02 × \(10^{23}\)
= 14.63 × \(10^{45}\) particles.
I hope this was clear and easy to understand.
How many particles are there in 0.057 moles of lithium bromide made
There are 3.44 x 10^{22} particles in 0.057 moles of lithium bromide.
What chemical compound is lithium bromide known by?The lithium bromide formula also known as the lithium monobromide formula or Bromo lithium formula is explored. It is a counterion bromide-based salt of lithium.
we have to use Avogadro's constant,
Avogadro's constant, is approximately equal to 6.022 x 10^{22} particles per mole.
we can use the following formula:
number of particles = moles x Avogadro's constant
Substitute the values,
number of particles = 0.057 moles x 6.022 x 10^{23} particles/mol
Simplifying the equation
number of particles = 3.44 x 10^{22} particles
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If you know the answer please tell me thank you.
(a) The balanced chemical equation of magnesium and dilute sulfuric acid is Mg + H₂SO₄ → MgSO₄ + H₂.
(b) The solution was filtered to remove the solid magnesium sulphate (MgSO₄) produced.
What is the balanced chemical reaction of magnesium and dilute sulfuric acid?The balanced chemical equation of magnesium and dilute sulfuric acid is given as;
Mg + H₂SO₄ → MgSO₄ + H₂.
During the reaction the fizzing that was observed was due to the production of hydrogen gas.
At the end of the reaction, magnesium sulphate (MgSO₄) will be formed, as well as hydrogen gas.
The magnesium sulphate (MgSO₄) formed is a solid, and filtration can be used to remove the solid magnesium sulphate (MgSO₄) formed.
Filtration is a separation technique used to separate a mixture of liquid and solid, so it will be the best separation technique to recover the produced magnesium sulphate (MgSO₄).
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The reaction between ethylene and hydrogen bromide to form ethyl bromide is carried out in a continuous reactor. The product stream is analyzed and found to contain 56.7 mol% C2H5Br and 10.3 mol% HBr. The feed to the reactor conains only ethylene and hydrogen bromide. Calculate the fractional conversion of the limiting reactant and the percentage by which the other reactant is in excess. If the molar flow rate of the feed stream is 265 mol/s, what is the extent of reaction
Answer:
Extent of reaction = 95.9 mol.
Fractional conversion of the limiting reactant = 0.846.
Percentage by which the other reactant is in excess = 25.2 %.
Explanation:
Hello.
In this case, for the undergoing chemical reaction:
\(CH_2=CH_2+HBr\rightarrow CH_3-CH_2Br\)
We can write the mole balance per species also including the extent of the reaction:
\(CH_2=CH_2:A\\\\HBr: B\\\\CH_3-CH_2-Br:C\)
\(x_AP=z_AF-\epsilon \\\\x_BP=z_BF-\epsilon \\\\x_CP=\epsilon\)
Considering that P is the flow of the outlet product. In such a way, writing the data we know, we can write:
\(0.33P=z_A*265-\epsilon \\\\0.103P=z_B*265-\epsilon \\\\0.567P=\epsilon\)
Whereas we can replace the C2H5Br mole balance in the others mole balances:
\(0.33P=z_A*265-0.567P \\\\0.103P=z_B*265-0.567P\\\\\\z_A*265-0.897P=0\\\\z_B*265-0.67P=0\)
By knowing that \(z_B=1-z_A\), we can write:
\(z_A*265-0.897P=0\\\\(1-z_A)*265-0.67P=0\\\\\\z_A*265-0.897P=0\\\\-z_A*265-0.67P=-265\)
Thus, solving for P and \(z_A\), we obtain:
\(z_A=0.572\\\\P=169.11mol\)
It means that the extent of the reaction is:
\(\epsilon=0.567P=0.567*169.11mol\\\\\epsilon=95.9mol\)
For the limiting reactant, due to the 1:1 mole ratio between the reactants, it is the one having the smallest flow rate:
\(F_A=0.572*265mol=151.58mol\\\\F_B=265mol-151.58mol=113.42mol\)
It means that the limiting reactant is B which is HBr, whose fractional conversion is:
\(X_B=1-\frac{0.103*169.11}{113.42mol}\\ \\X_B=0.846\)
Finally, the percentage by which the other reactant is in excess, corresponds to:
\(\% excess =(1-\frac{113.42mol}{151.58mol})*100\%\\ \\\%excess=25.2\%\)
Regards.
If there is sufficient water in the reaction system, how many grams of KOH can be produced from 22.2 g of K?
Answer: 31.9 g of KOH can be produced from 22.2 g of KOH
Explanation:
To calculate the moles :
\(\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}\)
\(\text{Moles of} K=\frac{22.2g}{39g/mol}=0.57moles\)
\(2K+2H_2O\rightarrow 2KOH+H_2\)
According to stoichiometry :
2 moles of \(K\) produce = 2 moles of \(KOH\)
Thus 0.57 moles of \(K\) will produce=\(\frac{2}{2}\times 0.57=0.57moles\) of \(KOH\)
Mass of \(KOH=moles\times {\text {Molar mass}}=0.57moles\times 56g/mol=31.9g\)
Thus 31.9 g of KOH can be produced from 22.2 g of KOH
PLEASE HELP I NEED THIS DONE IN LESS THEN 2 HOURS!!! ILL GIVE BRAINLIST PLEASE HELP <3
The law of conservation of matter states that matter can be neither created nor destroyed. Your friend shows you the following chemical equation:
CaCO3 -> CaO + CO2
He says that because the oxygen atoms are split between two different molecules in the products, the equation does not support the law of conservation of matter. Is your friend right? Explain your answer. Draw a model showing the number of each type of atom in the reactants and products. Use your model to explain your answer.
The two main postulates that was given by Antoine Lavoisier are, oxygen play an important role in combustion and the other is mass of the reactant and product is conserved. Therefore, the given statement is incorrect.
What is law of conservation of mass?According to Law of conservation of mass, mass can neither be created nor be destroyed. Mass can only be transformed from one form to another. The law of conservation of mass was given by Antoine Lavoisier.
Every reaction in nature follow the law given by Antoine Lavoisier that is mass is always conserved. To see law of conservation, we need to check only number of atoms not the splitting of atoms or element. So, the given statement is incorrect.
Therefore, the given statement is incorrect.
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write a balanced chemical equation for the decomposition of asprin
The balanced chemical equation for the decomposition of aspirin (acetylsalicylic acid) is:
\(2C_{9}H_{8}O_{4} (aspirin) → 2C_{7}H_{6}O_{3} (salicylic acid) + 2CO_{2} (Carbon dioxide) + H_{2}O (water)\)
In this reaction, the aspirin molecule breaks down into salicylic acid, carbon dioxide, and water. The reaction is typically catalyzed by heat or exposure to acidic or basic conditions.
Aspirin, or acetylsalicylic acid, contains ester functional groups that can undergo hydrolysis. Under suitable conditions, the ester bond in aspirin is cleaved, leading to the formation of salicylic acid, which is the primary decomposition product. Additionally, carbon dioxide and water are released as byproducts of the reaction.
The balanced equation shows that for every two molecules of aspirin, two molecules of salicylic acid, two molecules of carbon dioxide, and one molecule of water are formed. Understanding the decomposition of aspirin is important in pharmaceutical and chemical industries to ensure the stability and shelf-life of the compound, as well as to study its breakdown products and potential side reactions.
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What would be the final value for the enthalpy CO2+2h2o h =-1410 Kj
The final value for the enthalpy change of the formation of CO2 and 2H2O from their elements (C, H2, and O2) would be -1410 kJ per mole of CO2 and 2 moles of H2O formed.
The enthalpy change (ΔH) for the reaction CO2 + 2H2O → H2CO3 can be calculated by multiplying the stoichiometric coefficients of the balanced equation by the enthalpy values of the corresponding compounds involved in the reaction.
In the given reaction, the enthalpy change is -1410 kJ. However, it's important to note that this enthalpy change corresponds to a specific reaction and may not directly apply to the formation of CO2 and 2H2O from another reaction or process.
If we assume that the reaction is the formation of one mole of CO2 and two moles of H2O, we can say that the enthalpy change for this specific formation reaction is -1410 kJ.
Therefore, the final value for the enthalpy change of the formation of CO2 and 2H2O from their elements (C, H2, and O2) would be -1410 kJ per mole of CO2 and 2 moles of H2O formed.
It's worth mentioning that the enthalpy change can vary depending on the specific conditions (temperature, pressure, etc.) and the reactants involved in the reaction. Therefore, it's crucial to specify the conditions and reaction context when referring to enthalpy values.
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What concentration of CH3NH3Br is necessary to buffer a 0.18 M CH3NH2 solution at pH = 10.00?
(The Kb for CH3NH2 is 4.4 x 10 -4)
The concentration of the specie is obtained as 0.79 M.
What is the concentration?We know that a buffer is a solution that is resistant to changes in acidity and alkalinity. Now, we know that we have the following information;
pH = 10.00
Concentration of base = 0.18 M
Kb = 4.4 x 10 -4
Hence;
pOH = 14 - 10.00 = 4
pKb = -log( 4.4 x 10 -4) 3.36
Using the formula;
pOH = pKb + log [A-/AH]
4 = 3.36 + log[A-/0.18]
4 - 3.36 = log[A-/0.18]
Antilog(4 - 3.36) = [A-/0.18]
A- = Antilog(4 - 3.36) * 0.18
A- = 0.79 M
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Look at the diagram of a fuel cell below. A fuel cell with 2 vertical objects labeled A and B connected by an electrical wire through a circle with a M in it. There is an area between the two vertical objects labeled A, and substances flowing to, along, and away from the vertical objects and to the left and right. Which statement describes how electrons move if oxidation occurs on the left side of the cell and reduction occurs on the right side? Electrons move from left to right through Electrons move from right to left through A. Electrons move from left to right through M. Electrons move from right to left through M.
The electrons move from left to right through the circle labeled "M" to reach the cathode, where reduction takes place.
If oxidation occurs on the left side of the fuel cell and reduction occurs on the right side, the movement of electrons can be described as follows: Electrons move from left to right through the circle labeled "M."
In a fuel cell, the process of oxidation takes place at the anode (labeled A) where the fuel is oxidized, releasing electrons. These electrons then flow through the external electrical circuit, represented by the wire connecting objects A and B. The electrons reach the cathode (also labeled A) on the right side of the cell, where reduction occurs.The circle labeled "M" represents the membrane or electrolyte in the fuel cell. This membrane allows the transport of ions but blocks the movement of electrons. As a result, electrons cannot flow directly through the electrolyte but must travel through the external circuit.
This movement of electrons through the external circuit is what generates an electric current that can be used to power electrical devices or systems.
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Fatty foods become rancid due to the process of
Answer:
Fatty foods become rancid due to the process of rancidity
Can someone help me with this
Answer: A
Explanation:
Answer:
B
Explanation:
BBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB I LIKE B it's B though gl on the rest.
This is how manganese appears in the periodic table.
What is the arrow is pointing to?
period symbol of manganese
isotope symbol of manganese
group symbol of manganese
atomic symbol of manganese
Answer:d
Explanation:took the test
The arrow in the statement is likely pointing to the atomic symbol of manganese, which is the letter "Mn." Therefore, option (D) is correct.
In the periodic table, elements are organized based on their atomic number, which corresponds to the number of protons in the nucleus of an atom. Manganese has an atomic number of 25, indicating that it has 25 protons. The atomic symbol is a shorthand representation of the element's name, allowing for easy identification and reference.
Therefore, the arrow is pointing to the atomic symbol of manganese, "Mn," indicating its position in the periodic table and distinguishing it from other elements. The atomic symbol is a fundamental component of the periodic table, enabling scientists to communicate and study elements and their properties more efficiently.
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Gaseous acetylene (C2H2) reacts with oxygen gas to form gaseous carbon dioxide and gaseous water.
Gaseous acetylene reacts with oxygen gas to form gaseous carbon dioxide and gaseous water. The chemical equation of the reaction is \(2C_2H_2 (g) + 5O_2 (g)-- > 4CO_2 (g) + 2H_2O (g)\)
Chemical equationsThe chemical equation of a reaction is an expression that shows how the reactants combine to form the products using the chemical symbols for the components.
The reaction of gaseous acetylene with oxygen gas to form gaseous carbon dioxide and gaseous water can be analyzed and written as follows:
The chemical formula for gaseous acetylene = \(C_2H_2 (g)\)
The chemical formula for oxygen gas = \(O_2 (g)\)
The chemical formula for gaseous carbon dioxide = \(CO_2 (g)\)
The chemical formula for gaseous water = \(H_2O (g)\)
The overall equation for the chemical reaction with all the phases identified is then written as:
\(2C_2H_2 (g) + 5O_2 (g)-- > 4CO_2 (g) + 2H_2O (g)\)
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Gaseous acetylene (C2H2) reacts with oxygen gas to form gaseous carbon dioxide and gaseous water.
Express your answer as a chemical equation. Identify all of the phases in your answer.
A 14.579 g sample of CaCl2 was added to 28.016 g of K2CO3 and mixed in water. A 3.558 g yield of CaCO3 was obtained.
What is the limiting reagent?
Answer:
CaCl3 is the limited reagent
Explanation:
Hat is the answer for this
Answer:
C
Explanation:
Answer:
I think is A
Explanation:
Hope it helps
write the structural formula for 2-bromo-3-chloro-4,4-dimethylpentanal
Answer:
Br-CH2-CH(CH3)2-C(Cl)H-CH(CH3)2-CHO
Explanation:
The molecule has a total of 14 carbon atoms, 13 hydrogen atoms, and 1 bromine atom. The carbon atoms are arranged in a chain with a methyl group attached to the second carbon atom, a chlorine atom attached to the third carbon atom, and two methyl groups attached to the fourth carbon atom. The fifth carbon atom has a carbonyl group attached to it.
The molecule is an aldehyde, which means that it has a carbonyl group (C=O) at the end of the chain. The carbonyl group is polar, and the oxygen atom has a partial negative charge. The hydrogen atom has a partial positive charge. This polarity makes the aldehyde group susceptible to nucleophilic attack.
The bromine and chlorine atoms are both electrophilic, which means that they have a partial positive charge. This makes them susceptible to nucleophilic attack.
The methyl groups are non-polar and do not have any significant reactivity.
The molecule is a chiral molecule, which means that it has a mirror image that is not superimposable on itself. This is because the carbon atom with the carbonyl group is attached to four different groups.
The molecule is a liquid at room temperature and has a strong odor. It is used in a variety of products, including perfumes, flavorings, and plastics.