1.using a venn diagram differentiate muscular strength from muscular endurance
2.list some benefits of having a good muscular endurance and how can you develop them

Answer:

The shape of the MASS vs ENERGY graph has a NON-LINEAR RELATIONSHIP.

Explanation:

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A graph of kinetic energy vs the mass of an object is non-linear.

Changes in the output are not proportional to changes in any of the inputs in a nonlinear connection.

When a linear connection is plotted on a graph, it produces a straight line; however, when a nonlinear relationship is plotted on a graph, it produces a curve.

When graphed, motion energy is proportional to the mass of the moving item, resulting in a linear connection, and it expands with the square of its speed, resulting in a non-linear relationship.

Hence a graph of kinetic energy vs the mass of an object is non-linear.

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The approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

To approximate the heat transfer through the air layer in the double-paned window, we can assume that the glass layers have a negligible impact on the heat flow. The heat transfer can be calculated using Fourier's Law of Heat Conduction, which states that the heat flow (Q) is proportional to the temperature difference (ΔT) and inversely proportional to the thickness (L) and thermal conductivity (k) of the material.

First, we need to calculate the effective thermal conductivity of the air layer due to its thickness and the thermal conductivity ratio between air and glass. Let's denote the thermal conductivity of air as k_air and the thermal conductivity of glass as k_glass. Since glass has a thermal conductivity roughly 36 times greater than air, we have k_glass = 36 * k_air.

Next, we calculate the effective thermal conductivity of the air layer as:

k_eff = (k_air * L_air) / (L_air + k_glass)

Substituting the given values, we have:

k_eff = (k_air * 0.0165 m) / (0.0165 m + 0.005 m) = 0.01309 * k_air

Now, we can calculate the heat flow per second through the air layer using the formula:

Q = (k_eff * A * ΔT) / L_air

Substituting the given values, we get:

Q = (0.01309 * k_air * 0.760 m^2 * 23.0 K) / 0.0165 m = 24.4 J/s

Therefore, the approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

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The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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The height of the 4 kilograms book with a gravitational potential energy of 98 Joules is approximately 2.5 meters.

Gravitational potential energy is simply the potential energy an object possessse in relation to another object due to gravity.

It is expressed as;

U = m × g × h

Given that:

Gravitational potential energy of the book U = 98 Joules

Mass of the book m = 4 kilograms

Acceleration due to gravity g = 9.8 m/s²

Height h = ?

Plug these values into the above formula and solve for height.

U = m × g × h

h = U / ( m × g )

h = 98  / ( 4 × 9.8 )

h = 98/39.2

h = 2.5 meters

Therefore, its height is 2.5 meters.

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Explanation:

Potential energy is a scalar quantity because it has only magnitude and no direction. Its ability to be negative does not affect its scalar nature.

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The mass of 5 cm³ of copper is 45 grams. This means that if we had a block of copper with a volume of 5 cm³, it would weigh 45 grams.

The density of copper is given as 9 g/cm³, which means that for every cubic centimeter (cm³) of copper, there is a mass of 9 grams (g). To find the mass of 5 cm³ of copper, we can use the following formula:

mass = density x volume

where mass is the mass of the object in grams, density is the density of the material in grams per cubic centimeter, and volume is the volume of the object in cubic centimeters.

Plugging in the values we have, we get:

mass = 9 g/cm³ x 5 cm³

mass = 45 g

Therefore, the mass of 5 cm³ of copper is 45 grams. This means that if we had a block of copper with a volume of 5 cm³, it would weigh 45 grams.

It is important to note that the density of a material is an important physical property that relates its mass to its volume, and is often used in calculations involving materials and objects of different shapes and sizes.

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A.  Light travels approximately 670,616,320 miles in an hour.

B.  Light travels approximately 16,094,718,080 miles in a day.

Light travels at a speed of 186,282 miles per second. To find out how far it travels in an hour, we can simply multiply this speed by the number of seconds in an hour:

Distance traveled in an hour = 186,282 miles/second x 3,600 seconds/hour = 670,616,320 miles/hour

Therefore, light travels approximately 670,616,320 miles in an hour.

To find out how far light travels in a day, we need to multiply the distance traveled in an hour by the number of hours in a day:

Distance traveled in a day = 670,616,320 miles/hour x 24 hours/day = 16,094,718,080 miles/day

Therefore, light travels approximately 16,094,718,080 miles in a day.

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Answer:

Speed, Vfx = 7.619 m/s

Explanation:

Vertical distance, Dx = 5.4m

Horizontal distance, Dy = 8m

Acceleration due to gravity, g = 9.8m/s²

Initial speed, Vix = 0m/s²

To find the speed, we would use the second equation of motion to find the time, t;

Dx = Vixt + ½gt²

Substituting into the equation, we have;

5.4 = 0(t) + ½(9.8)*t²

5.4 =  0 + 4.9t²

Rearranging the equation, we have;

4.9t² = 5.4

t² = 5.4/4.9

t² = 1.1020

Taking the square root of both sides;

t = 1.050 secs.

For the speed;

Dy = Vfxt

Vfx = Dy/t

Vfx = 8/1.050

Vfx = 7.619 m/s

Therefore, the speed of the pelican is 7.619 m/s

Answer:

20 kg

Explanation:

The kinetic energy (KE) of an object is given by:

KE = (1/2) * m * v^2

Where m is the mass of the object, and v is its velocity.

We can rearrange this formula to solve for the mass:

m = 2 * KE / v^2

Plugging in the values given:

m = 2 * 1000 J / (10 m/s)^2

m = 20 kg

Therefore, the mass of the Puffin flying at 10 m/s with 1000 J of KE is 20 kg.

Answer:

through direct contact

Explanation:

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Answer:

deformation : elastic deformation is reversed when the force is removed. inelastic deformation is not fully reversed when the force is removed – there is a permanent change in shape.

Explanation:

tysm

Answer:

The final temperature of the bullets is 327.3 ºC.

Explanation:

Let suppose that a phase change does not occur during collision and collided bullets stop at the end. We represent the phenomenon by the First Law of Thermodynamics:

\(K_{A, o} + K_{B, o}-K_{A}-K_{B}+U_{A,o} + U_{B,o}-U_{A}-U_{B} = 0\) (1)

Where:

\(K_{A,o}\), \(K_{A}\) - Initial and final translational kinetic energies of the 15-g bullet, measured in joules.

\(K_{B,o}\), \(K_{B}\) - Initial and final translational kinetic energies of the 7.75-g bullet, measured in joules.

\(U_{A,o}\), \(U_{A}\) - Initial and final internal energies of the 15-g bullet, measured in joules.

\(U_{B,o}\), \(U_{B}\) - Initial and final internal energies of the 7.75-g bullet, measured in joules.

By definitions of translational kinetic energy and sensible heat we expand and simplify the equation above:

\(\frac{1}{2}\cdot m_{A}\cdot (v_{A,o}^{2}-v_{A}^{2})+ \frac{1}{2}\cdot m_{B}\cdot (v_{B,o}^{2}-v_{B}^{2})+(m_{A}+m_{B})\cdot c\cdot (T_{o}-T) = 0\) (2)

Where:

\(m_{A}\), \(m_{B}\) - Masses of the 15-g and 7.75-g bullets, measured in kilograms.

\(v_{A,o}\), \(v_{A}\) - Initial and final speeds of the 15-g bullet, measured in meters per second.

\(v_{B,o}\), \(v_{B}\) - Initial and final speeds of the 7.75-g bullet, measured in meters per second.

\(c\) - Specific heat of lead, measured in joules per kilogram-Celsius degree.

\(T_{o}\), \(T\) - Initial and final temperatures of the bullets, measured in Celsius degree.

Now we clear the final temperature of the bullets:

\((m_{A}+m_{B})\cdot c \cdot (T-T_{o}) = \frac{1}{2}\cdot [m_{A}\cdot (v_{A,o}^{2}-v_{A}^{2})+m_{B}\cdot (v_{B,o}^{2}-v_{B}^{2})]\)

\(T-T_{o} = \frac{m_{A}\cdot (v_{A,o}^{2}-v_{A}^{2})+m_{B}\cdot (v_{B,o}^{2}-v_{B}^{2})}{(m_{A}+m_{B})\cdot c}\)

\(T= T_{o}+\frac{m_{A}\cdot (v_{A,o}^{2}-v_{A}^{2})+m_{B}\cdot (v_{B,o}^{2}-v_{B}^{2})}{(m_{A}+m_{B})\cdot c}\) (3)

If we know that \(T_{o} = 30\,^{\circ}C\), \(m_{A} = 15\times 10^{-3}\,kg\), \(m_{B} = 7.75\times 10^{-3}\,kg\), \(v_{A,o} = 295\,\frac{m}{s}\), \(v_{B,o} = 375\,\frac{m}{s}\), \(v_{A} = 0\,\frac{m}{s}\), \(v_{B} = 0\,\frac{m}{s}\) and \(c = 128\,\frac{J}{kg\cdot ^{\circ}C}\), then the final temperature of the collided bullets is:

\(T = 30\,^{\circ}C+\frac{(15\times 10^{-3}\,kg)\cdot \left[\left(295\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}\right]+(7.75\times 10^{-3}\,kg)\cdot \left[\left(375\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}\right]}{(15\times 10^{-3}\,kg+7.75\times 10^{-3}\,kg)\cdot \left(128\,\frac{J}{kg\cdot ^{\circ}C} \right)}\)

\(T = 852.534\,^{\circ}C\)

Given that found temperature is greater than melting point, then we conclude that supposition was false. If we add the component of latent heat of fussion, then the resulting equation is:

\(\frac{1}{2}\cdot m_{A}\cdot (v_{A,o}^{2}-v_{A}^{2})+ \frac{1}{2}\cdot m_{B}\cdot (v_{B,o}^{2}-v_{B}^{2})+(m_{A}+m_{B})\cdot c\cdot (T_{o}-T)-U = 0\) (4)

\(U=\frac{1}{2}\cdot m_{A}\cdot (v_{A,o}^{2}-v_{A}^{2})+ \frac{1}{2}\cdot m_{B}\cdot (v_{B,o}^{2}-v_{B}^{2})+(m_{A}+m_{B})\cdot c\cdot (T_{o}-T)\)

If we know that \(T_{o} = 30\,^{\circ}C\), \(T = 327.3\,^{\circ}C\), \(m_{A} = 15\times 10^{-3}\,kg\), \(m_{B} = 7.75\times 10^{-3}\,kg\), \(v_{A,o} = 295\,\frac{m}{s}\), \(v_{B,o} = 375\,\frac{m}{s}\), \(v_{A} = 0\,\frac{m}{s}\), \(v_{B} = 0\,\frac{m}{s}\) and \(c = 128\,\frac{J}{kg\cdot ^{\circ}C}\), then latent heat received by the bullets during impact is:

\(U =\frac{1}{2}\cdot (15\times 10^{-3}\,kg)\cdot \left[\left(295\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}\right] + \frac{1}{2}\cdot (7.75\times 10^{-3}\,kg)\cdot \left[\left(375\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}\right]+(15\times 10^{-3}\,kg+7.75\times 10^{-3}\,kg)\cdot \left(128\,\frac{J}{kg\cdot ^{\circ}C} \right) \cdot (30\,^{\circ}C-327.3\,^{\circ}C)\)\(U = 331.872\,J\)

The maximum possible latent heat (\(U_{max}\)), measured in joules, that both bullets can receive during collision is:

\(U_{max} = (m_{A}+m_{B})\cdot L_{f}\) (5)

Where \(L_{f}\) is the latent heat of fusion of lead, measured in joules per kilogram.

If we know that  \(m_{A} = 15\times 10^{-3}\,kg\), \(m_{B} = 7.75\times 10^{-3}\,kg\) and \(L_{f} = 2.45\times 10^{4}\,\frac{J}{kg}\), then the maximum possible latent heat is:

\(U_{max} = (15\times 10^{-3}\,kg+7.75\times 10^{-3}\,kg)\cdot \left(2.45\times 10^{4}\,\frac{J}{kg} \right)\)

\(U_{max} = 557.375\,J\)

Given that \(U < U_{max}\), the final temperature of the bullets is 327.3 ºC.

Answer:

261.84 N.

Explanation:

From the question given above, the following data were obtained:

Energy (E) = work (W) = 741 J

Distance (d) = 2.83 m

Force (F) =?

Work is simply defined as the product of force and the distance moved in the direction of the the force. Mathematically, it is expressed as:

Work (W) = Force (F) × distance (d)

W = F × d

Thus, we obtained the weight of the object using the above formula.

Work (W) = 741 J

Distance (d) = 2.83 m

Force (F) =?

W = F × d

741 = F × 2.83

Divide both side by 2.83

F = 741 / 2.83

F = 261.84 N

Since force and weight has the same unit of measurement i.e Newton (N), the weight of the object is 261.84 N

Answer:

Go to this site.

Not a link, a suggestion, quizlet

Explanation:

The kinetic energy of the flywheel after 1 minute of rotation, given that it has a mass of 50 and radius of 40 cm is 32.4 KJ (Option D)

We'll begin by obtaining the velocity of the flywheel. This is shown below:

v = at

v = 0.6 × 60

v = 36 m/s

Finally, we shall determine the kinetic energy of the flywheel. Details below:

KE = ½mv²

KE = ½ × 50 × 36²

KE = 25 × 1296

KE = 32400 J

Divide by 1000 to express in KJ

KE = 32400 / 1000

KE = 32.4 KJ

Thus, the kinetic energy is 32.4 KJ (Option D)

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The acceleration is 0, this means there is no net force acting on the diver as he comes to rest. The net force is equal to zero.

To determine the net force on the diver, we can use the equation of motion:

(Final velocity)² = (Initial velocity)² + 2 × acceleration × distance

The initial velocity is 0 since the diver is at rest on the diving board. The final velocity is also 0 since the diver comes to rest in the water. The distance fallen is 3.0 m.

We can solve for the acceleration using the given time:

0 = 0² + 2 × acceleration × 3.0

0 = 0 + 6.0 × acceleration

acceleration = 0 m/s²

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Answer:

1,143 N

Explanation:

m = 82 kg

d = 3 m

t = 0.55 s

Vf² = Vi² + 2ad

Vf² = 0 + 2(9.8 m/s²)(3 m) = 58.8 m²/s²

Vf = √58.8 m²/s² = 7.67 m/s

Use the Impulse Force equation:

FΔt = mΔv

F = (82 kg)(7.67 m/s) / (0.55 s) ≈ 1143 N

Answer:

Fp = 36 N

Fq = 58 N

Explanation:

Let the left end be the reference end with string p closest to it.

Let CCW moments be positive

Sum moments about p to zero

1(9.8)[2 - 1] + Fq[6 - 2] - 5(9.8)[8/2 - 2] - 1.5(9.8)[5 - 2] - 2(9.8)[7 - 2] = 0

                                                                              Fq[4] = 23.5(9.8)

                                                                                  Fq = 57.575 ≈ 58 N

Sum moments about q to zero

1(9.8)[6 - 1]  - Fp[6 - 2] + 5(9.8)[6 - 8/2] + 1.5(9.8)[6 - 5] - 2(9.8)[7 - 6] = 0

                                                                                                     Fp = 35.525 N

or

Sum vertical forces to zero

Fp + 57.575 - (9.8)(1 + 1.5 + 2 + 5) = 0

Fp = 35.525  ≈ 36 N

The statement" The direction of the force on the charge placed in the electric field is upward" is false because the direction of the force on a negative charge (-6 C) placed in an upward-directed uniform electric field of magnitude 24 N/C would be downward.

The direction of the force on a charged particle placed in an electric field is determined by the charge of the particle and the direction of the electric field. In this case, a charge of -6 C is placed in an electric field directed upward with a magnitude of 24 N/C.

The force on a charged particle in an electric field can be calculated using the formula:

F = q * E

Where F is the force, q is the charge of the particle, and E is the electric field.

Since the charge q in this case is negative (-6 C) and the electric field E is directed upward, we can substitute the values into the formula:

F = (-6 C) * (24 N/C)

F = -144 N

The negative sign in the force value indicates that the force is in the opposite direction to the electric field. Therefore, the force on the charge placed in the electric field is downward, not upward.

The force on a negative charge is always opposite to the direction of the electric field. This is because negative charges experience an attractive force towards positive charges, and electric fields are directed from positive charges to negative charges.

Therefore, the statement "The direction of the force on the charge placed in the electric field is upward." is false.

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Answer:

W = 6000 Joule

Explanation:

Work is defined as force times distance

W = F * d

We know that F = 15N, we just need the distance (d)

Imagine you have a square lawn with length of 10 m and width of 20m. So, we want to know the the distance you have to travel to cover every square meter of the lawn.

The width of the mower is only 50 cm = 0.5 m.

This means that you have to go back and forth 40 times to cover 20m (lawn width), with a distance of 10 m (lawn length). So,

d = 10 (meter) * 40 (times) = 400 meter

Therefore:

W = (15) * (400) = 6000 J

For the beam and loading shown below (a), (b), and (c),

(a) draw the shear and bending-moment diagrams,

(b) determine the maximum absolute values of the shear and bending moment.

(a)

Answer:

dissociation

Explanation:

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Answer:

Blank 1 (asteroids)

Blank 2 (Ceres)

Explanation:

Rocky metallic objects found between the orbits of Mars and Jupiter are asteroids The largest known of these is ceres.

Asteroids are stony elements that circle the Sun. Although asteroids circle the Sun in the same way as planets, they are considerably smaller.]

A dwarf planet located between Mars and Jupiter in the asteroid belt. Ceres was the first asteroid discovered, it was originally classed as a planet,

Rocky metallic objects found between the orbits of Mars and Jupiter are asteroids The largest known of these is ceres.

The correct option from the drop-down menu is asteroids and ceres.

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Answer:I

Explanation:

i

Transform the given information into points.

If the watermelon rolled from 0 to -3.0 m in 5 seconds, then the point is (5,-3).

If the watermelon stops after 5 seconds, then draw a horizontal line there because its position is constant.

Answer: Limestone Caves

Explanation: The most common feature that can be caused purely by chemical weathering is Karst Landscape, which can lead to caverns and sinkholes.

Answer:

If two bumper cars collide with a certain force, then they will move away from each other in opposite directions with the same force. This demonstrates Newton's third law, which states that for every action, there is an equal and opposite reaction.

Explanation:

Answer:

it is A

Explanation: