Answer:
The correct answer is bones just took test
Explanation:
if the sum of all the forces acting on a moving object is zero, the object will:
Answer:
continue moving with constant velocity
Explanation:
what is the speed of a point on the earth's surface located at 2/5 of the length of the arc between the equator and the pole, measured from equator? (hint: what is the radius of the circle in which the point moves?)
The speed of the given point on earth's surface is 428 m/s
Speed of point on earth's surface:A point located 1/4 of the length of the arc between the equator and the pole has an angle:
(1/4) × 90° = 22.5°
Since the arc angle of the line joining the equator and the pole is 90°
So the angle between the line joining the center and the given point, and the line joining center and the pole is Φ = 90° - 22.5° = 67.5°
Now,
Sin Φ = (radius of the point)/(radius of the earth)
Sin 67.5 = radius of the point/(6.37 × 10⁶)
Radius of the point:
r = 6.37 × 10⁶ × 0.9239 = 5.885 × 10⁶ m
Speed of the point on the globe is v = 2πr/(24 hours)
2πr = 2π × 5.885 × 10⁶ = 3.6977 × 10⁷ m
So the speed of the point is :
v = 3.6977 × 10⁷/24
v = 1.541 × 10⁶ m/h
v = 428 m/s
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Which of the following scenarios does NOT
represent acceleration?
changing direction
slowing down
moving at a constant velocity
opeeding up
Which of the following actions will always decrease voltage?
A. Decreasing resistance and increasing current
B. Increasing resistance and decreasing current
C. Decreasing resistance and keeping current constant
D. Increasing resistance and keeping current constant
Answer:
D. Increasing resistance and keeping current from A P E X :))
Explanation:
The decreasing resistance and keeping current constant leads decreasing in voltage option (C) is correct.
What is voltage?Voltage is the force applied by the power source to charged electrons in a conducting loop, allowing them to perform tasks such as igniting light.
As we know according to the ohm's law:
V = IR
Where 'V' is the volatge,
'I' is the current.
'R' is the resistance.
If we assume 'I' is constant
Then V∝R
As the resistance increases the voltage increases and vice versa.
Thus, the decreasing resistance and keeping current constant leads decreasing in voltage option (C) is correct.
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terms used to measure motion
Answer:
velocity term
Explanation:
Answer:velocity term
Explanation:
the total energy of a system is 300j. if the potential energy is 40j what is the kinetic energy if the object started 300m above the ground?
Answer:
43.3 m/s.
Explanation:
Assuming the potential energy is due to the gravitational potential energy, we can use the conservation of energy to find the kinetic energy:
Total energy = Potential energy + Kinetic energy
Kinetic energy = Total energy - Potential energy
Kinetic energy = 300 J - 40 J = 260 J
However, we need to know the mass of the object to convert the kinetic energy to velocity. We can use the potential energy to find the mass:
Potential energy = mgh
40 J = m(9.81 m/s^2)(300 m)
m = 0.137 kg
Now we can use the kinetic energy to find the velocity:
Kinetic energy = (1/2)mv^2
260 J = (1/2)(0.137 kg)v^2
v^2 = (2*260 J) / 0.137 kg
v = 43.3 m/s (rounded to one decimal place)
Therefore, the kinetic energy is 260 J and the velocity of the object when it reaches the ground is 43.3 m/s.
un litro de un gas es calentado a presión constante desde 20°C hasta 60°C que volumen final ocupará dicho gas?
Answer:
Final volume, V2 = 3 Litres
Explanation:
Given the following data;
Initial volume, V1 = 1 litre
Initial temperature, T1 = 20°C
Final temperature, T2 = 60°C
To find the final volume, we would use Charles' law;
Charles states that when the pressure of an ideal gas is kept constant, the volume of the gas is directly proportional to the absolute temperature of the gas.
Mathematically, Charles is given by;
V1/T1 = V2/T2
Making V2 as the subject formula, we have;
V1T2 = V2T1
V2 = (V1T2)/T1
Substituting into the formula, we have;
V2 = (1 * 60)/20
V2 = 60/20
Final volume, V2 = 3 Litres
suppose you lift a stone that has a mass of 5.9 kilograms off the floor onto a shelf that is 0.5 meters high. how much work have you done?
Work done to lift the stone of mass 5.9 kg is 28.91 J.
The work done through pressure is made of the displacement and the component of the carried-out force of the object inside the direction of displacement. whilst we push a block with a few pressure ' F ' the body movements with a few accelerations, paintings are carried out. paintings executed is written as W = F.
The paintings executed by using pressure are defined to be manufactured from the aspect of the force in the path of the displacement and the significance of this displacement. formula. work can be calculated by multiplying pressure and Distance within the course of force as follows. W = F × d.
Work is achieved whenever a pressure actions something over a distance. you can calculate the strength transferred, or work carried out, by multiplying the pressure via the space moved in the route of the pressure.
Calculation:-
mass = 5.9
g = 9.8 m/s
f = 0.5 m
work done = mgh
= 5.9 × 9.8 × 0.5 J
= 28.91 J
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Sample Problem EAn electric space heater is connected across a 120 V outlet. The heater dissipates 1320 W of power in the form of electromagnetic radiation and heat. Calculate the resistance of the heater.
The resistance of the heater is 10.3 ohms.
The power (P) dissipated by the electric space heater is given by the formula P = V²/R, where V is the voltage across the heater and R is the resistance of the heater. In this case, the power is given as 1320 W and the voltage is given as 120 V. So we can rearrange the formula to solve for the resistance: R = V²/P. Substituting the given values, we get R = (120 V)² / 1320 W = 10.3 ohms. Therefore, the resistance of the heater is 10.3 ohm
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Describe the relationship between kinetic energy and speed and give an example of how changing and object speed would affect its kinetic energy
Answer:
I'm not sure
Explanation:
I have had that question to Uchida c r go crew in to go be
what is the magnitude of the force provided by the third rope, in terms of θ ? A. FABCos(θ) B. 2FABCos(θ) C. 2FABSin(θ) D.FABSin(θ)
the magnitude of the force provided by the third rope, in terms of θ is 2FABCos(θ) (Option B)
What is geometry problem?Geometry problems refer to mathematical problems that involve the study of spatial relationships, shapes, sizes, and positions of objects in two or three-dimensional space. The goal of solving geometry problems is to find unknown information about a given geometric figure or to prove a theorem based on given information.
The reason behind magnitude of the force provided by the third rope is that the boat is pulled to the left in a horizontal direction by the forces' cosine component. To balance the other two ropes, a third rope can be attached from A to F.
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Complete question:
A boat owner pulls her boat into the dock shown, where there are six bollards to which to tie the boat. She has three ropes. She can tie the boat from the boat's center (A) to any of the bollards (B through G) along the dotted arrows shown.
Suppose the owner has tied three ropes: one rope runs to A from B, another to A from D, and a final rope from A to F. The ropes are tied such that FAB=FAD
What is the magnitude of the force provided by the third rope, in terms of θ?
1000 people rolled dies simultaneously What is the probability that the first 100 will get 6 on a dice
5. How much force would it take to push another, larger friend who has a mass of 70g
to accelerate at the same rate of 4 m/s²?
280N(Newton) of force would it take to push another, larger friend who has a mass of 70g to accelerate at the same rate of 4 m/s².
What is Force?
A force is an influence that has the power to alter an object's motion. A force can cause an object with mass to accelerate when it changes its velocity, for as when it moves away from rest. An obvious way to describe force is as a push or a pull.
A force is a vector quantity since it has both magnitude and direction. It is calculated using the newton SI unit (N). Force is denoted by the letter F.
Force = Mass * Acceleration
= 70 g * 4
= 280 Newton.
Therefore, 280N(Newton) of force would it take to push another, larger friend who has a mass of 70g to accelerate at the same rate of 4 m/s².
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Given a 10 pF air-filled capacitor, you are asked to convert it to a capacitor that can store up to 6.2 µJ with a maximum potential difference of 570 V. What must be the dielectric constant of the material that you should you use to fill the gap in the air capacitor if you do not allow for a margin of error?
The dielectric constant of the material that should be used to fill the gap in the air capacitor is approximately 2.231.
We are given that;The capacitance of the air-filled capacitor (C1) = 10 p
FThe energy stored by the new capacitor(C2) = 6.2 µJ
The maximum potential difference(V) = 570 V
To determine the dielectric constant of the material that should be used to fill the gap in the air capacitor, we can use the formula;
Energy stored in a capacitor E = 1/2CV²Where,E = energy stored by capacitor
C = capacitanceV = potential difference
For the first capacitor E1 = 1/2 C1 V²
For the second capacitor E2 = 1/2 C2 V²We can rewrite the formula above as;
C = 2E/V²We want to find the capacitance of the second capacitorC2 = 2E2/V² = 2(6.2×10⁻⁶)/570²C2 = 2.391×10⁻¹⁴ FThe capacitance of the second capacitor (C2) is known, and we can find the dielectric constant of the material required by using the formula;C = (Kε₀A)/dWhere,C = capacitanceK = dielectric constantε₀ = permittivity of free space.A = area of the platesd = distance between the platesWe can rearrange the formula above to obtain the value of the dielectric constant;K = Cd/(ε₀A)K = (C2d)/(ε₀A)
From the formula, we know the value of C2, and we can find the value of d and A.We know that the capacitance of a parallel plate capacitor is given as;C = ε₀(K)A/d
We can rearrange the formula to obtain the value of d;d = ε₀KA/CC = ε₀(K)A/d2.391×10⁻¹⁴ F = (8.85×10⁻¹² F/m)(K)(A)/(d)We know the area of the plates of the capacitor and the capacitance, and we can find the value of d;
The area of the plates A = πr² = π(0.0025)² = 1.96×10⁻⁵ m²d = (8.85×10⁻¹² F/m)(K)(1.96×10⁻⁵ m²)/(2.391×10⁻¹⁴ F)d = 7.2186×10⁻⁵ m
We can now find the value of the dielectric constant using the formula;K = Cd/(ε₀A)K = (2.391×10⁻¹⁴ F)(7.2186×10⁻⁵ m)/[8.85×10⁻¹² F/m)(1.96×10⁻⁵ m²)]K = 2.231 (approx)
Therefore, the dielectric constant of the material that should be used to fill the gap in the air capacitor is approximately 2.231. .
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ASAP TWENTY POINTS What type of image is formed by a mirror if m = -0.4?
Answer:
OPTION (C)
Explanation:
m(magnification) = -0.4 means a real, inverted and diminished image is formed in front of the mirror.
when do magnets have the most potential energy
Answer:
Explanation:
Permanent magnets do have potential energy, stored in their magnetic field. That energy can be compared to the potential energy of some compressed spring. See the picture below, representing the magnetic field lines of a magnetized sphere : These lines are compressed inside the magnet.
a dragster starts from rest and accelerates down a track. each tire has a radius of 0.320 m and rolls without slipping. at a distance of 384 m, the angular speed of the wheels is 288 rad/s. determine (a) the linear speed of the dragster and (b) the magnitude of the angular acceleration of its wheels.
(a)Vt =r=(288)(0.32)=92.2m/s is a straightforward formula that may be used to calculate the dragster's linear speed at a distance of df = 384 m.
(b) We utilize the following two kinematic equations to determine the angular acceleration of the dragster's wheels during this time: delta theta = 1/2 at2 and wf = at.
By magnitude, what do you mean?Simply said, magnitude is "distance or amount." It shows the size or direction that an item travels in either an absolute or relative sense. It is a way of expressing something's size or scope.
What does magnitude example mean?Size is referred to as magnitude. A automobile is traveling more quickly than a bike, for instance, when it comes to speed. The extent of the car's speed in this situation.
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A barrel ride at an amusement park
starts from rest and speeds up to
0.520 rev/sec in 7.26 s. What is
the angular acceleration during
that time?
The angular acceleration of the barrel ride at the amusement park during the 7.26 seconds is approximately 0.450 radians/sec².
To determine the angular acceleration of the barrel ride, we need to use the following formula:
angular acceleration (α) = (ω_final - ω_initial) / t
where ω_final is the final angular velocity, ω_initial is the initial angular velocity, and t is the time taken.
In this case, the barrel ride starts from rest, so ω_initial is 0 rev/sec. The final angular velocity, ω_final, is given as 0.520 rev/sec. The time taken, t, is 7.26 seconds.
Before we plug the values into the formula, let's convert the final angular velocity from rev/sec to radians/sec. To do this, we use the conversion factor:
1 rev = 2π radians
So, ω_final = 0.520 rev/sec × 2π radians/rev ≈ 3.265 radians/sec
Now, let's calculate the angular acceleration:
α = (ω_final - ω_initial) / t
α = (3.265 radians/sec - 0 radians/sec) / 7.26 sec
α ≈ 0.450 radians/sec²
Therefore, the angular acceleration of the barrel ride during the 7.26 seconds is approximately 0.450 radians/sec².
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which group of the periodic table consists of elements that share similar properties and have 2 electrons in their outer shells
A. 1
B. 13
C. 14
D. 2
Answer: The correct answer is A.
Explanation:
Group 1 of the periodic table consists of elements that share similar properties and have 2 electrons in their outer shells. These elements are known as the alkali metals. They include elements such as lithium (Li), sodium (Na), potassium (K), and so on, all of which have a single electron in their outermost shell.
What was the kelly-bessemer process used for? reducing the speed for laying rail tracks mass producing train cars monopolizing the iron industry making high-quality steel
The kelly - bessemer process used for converting the iron metal to molten steel by injecting air into molten pig iron.
Molten steel (from an oxygen or electric arc furnace) is poured into a ladle that is brought to the inlet of a continuous casting machine, raised onto a turret, and poured into a tundish. This is a large vessel that ensures the continuous flow of hot metal through a submerged entry nozzle and into a water-cooled and vertical copper mould, where the solidification starts as an outer shell starts encasing a liquid core. Hydrogen is highly soluble in molten steel, including weld metal.
The partial pressure or concentration of hydrogen above the molten steel determines the equilibrium solubility. It is a really difficult process.
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the total energy of a 4 kg object moving at 2 m/s and potioned 5m above the ground
Answer:
u would need to calculate both K. E and P. E
Explanation:
for K. E use = (mv^2)/2
for P. E use = m×g×h ;
where g is acceleration due to gravity and it's value is 10m/s^2
use the hertzsprung-russell diagram to determine which condition describe each star use the arrows to help you locate the stars
The Hertzsprung-Russell (HR) diagram is a plot of luminosity versus temperature. HR diagrams are used to determine the age, distance, and relative size of stars. A typical HR diagram shows main sequence stars on the left side of the diagram, giant stars in the middle, and supergiant stars on the right side.
The location of stars on the HR diagram reveals a lot about the conditions of the star. For example, main sequence stars are stars that have reached a state of equilibrium between their inward pull of gravity and their outward radiation pressure. They are characterized by a stable core temperature and a stable rate of energy generation.
On the other hand, giant stars are stars that have exhausted the fuel in their core, causing the core to contract and heat up, while the outer layers expand and cool. This causes the star to move to the right on the HR diagram.
Supergiant stars are even larger than giant stars and have even cooler and more luminous outer layers. They are found on the upper right-hand corner of the HR diagram.
White dwarfs are stars that have exhausted all of their nuclear fuel and have contracted to a very small size. They are located on the lower left-hand side of the HR diagram.
Overall, the location of a star on the HR diagram provides a lot of information about the conditions of the star, including its size, temperature, and luminosity.
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determine the force in members dg, fg, and fh of the truss shown.
Unfortunately, as an AI language model, I cannot see the truss diagram you are referring to.
However, in general, to determine the force in members of a truss, one would use the method of joints or the method of sections.
The method of joints involves analyzing the forces acting at each joint of the truss and applying the equations of static equilibrium to determine the forces in each member.
This method can be time-consuming but is effective for small trusses with a limited number of joints.
The method of sections involves cutting the truss along a section and analyzing the forces acting on the cut section.
By applying the equations of static equilibrium, one can determine the forces in the members that intersect the section. This method is quicker but may not provide information on all the members of the truss.
Both methods require a good understanding of statics and equilibrium principles. It is essential to ensure that the truss is stable and that no member is under excessive stress.
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What is the work done if you push a tree with
50 N of force but the tree does not move?
Answer:
The work done is 0.
Explanation:
The reason no work is done is because the equation W = Fs.
W = work
F= force
s= displacement
In this scenario F = 50 and s= 0
Therefore.
W = 50(0)
W = 0
an object of mass 2.75 kg is moving with a velocity what is the angular momentum of the mass relative to the origin when it is at the location (1.50, -1.50. 1.50) m? (Express your answer in vector form.)
The angular momentum of the object relative to the origin is \((4.13 kgm^{2/s})i - (4.13 kgm^{2/s})j\)
The angular momentum of an object relative to the origin is given by the cross product of its position vector and its momentum vector. In this problem, we are given the mass of the object and its velocity, but we need to find its momentum and position vectors.The momentum of the object is given by p = mv, where m is the mass and v is the velocity. Since the mass is 2.75 kg and the velocity is not given, we cannot calculate the momentum directly. However, we know that the momentum is in the same direction as the velocity vector.To find the position vector of the object, we use the given coordinates (1.50, -1.50, 1.50) m. We represent this as a vector r = (1.50 m)i - (1.50 m)j + (1.50 m)k.Now, we can calculate the angular momentum L = r x p, where x represents the cross product. Since the momentum is in the same direction as the velocity, we can write p = mv = (2.75 kg)v. Taking the cross product of r and p, we get:\(L = r x p = [(1.50 m)i - (1.50 m)j + (1.50 m)k] * (2.75 kg)v= (4.13 kgm^{2/s})i - (4.13 kgm^{2/s})j\)Therefore, the angular momentum of the object relative to the origin is \((4.13 kgm^{2/s})i - (4.13 kgm^{2/s})j.\)For more such question on angular momentum
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calculate the average speed of a snake that moves 700 meters in 5 hours?
Please help if you can!
Answer:
Illuminated
Explanation:
I think but not sure
A sailboat moves north for a distance of 10.00 km when blown by a wind from the exact southeast with a force of . The sailboat travels the distance in 1.0 h. How much work was done by the wind? What was the wind’s power? Your response should include all of your work and a free-body diagram.
Given that the direction sailboat is north and the distance traveled is d = 10 km
The direction of the wind is southeast and the force is
\(F\text{ =2}\times10^4\text{ N}\)The sailboat travels the distance in time, t = 1 h
We have to find the work done by the wind and wind's power.
The diagram is shown below
The work done by the wind will be
\(\begin{gathered} W\text{ =Fdcos}\theta \\ =2\times10^4\times10\times10^3\times\cos (135^{\circ}) \\ =-1.414\times10^8\text{ J} \end{gathered}\)The power of the wind will be
\(\begin{gathered} P=\frac{W}{t} \\ =\frac{-1.414\times10^8}{1\times60\times60} \\ =-3.93\times10^4\text{ W} \end{gathered}\)
Using Kepler's 3rd law, how long will it take a new planet that is 3.68 x 107 km to travel around the Earth?
Answer:
Pls mark brainlist... A graph showing Kepler's 3rd law. ... Kepler's 3rd law is a mathematical formula. It means that if you know the period of a planet's orbit (P = how long it takes the planet to go around the Sun), then you can determine that planet's distance from the Sun (a = the semimajor axis of the planet's orbit).
Explanation:
The square of the orbital period of a planet is proportional to the cube of the semi-major axis of its orbit” That's Kepler's third law. In other words, if you square the 'year' of each planet, and divide it by the cube of its distance to the Sun, you get the same number, for all planets
There are actually three, Kepler's laws that is, of planetary motion: 1) every planet's orbit is an ellipse with the Sun at a focus; 2) a line joining the Sun and a planet sweeps out equal areas in equal times; and 3) the square of a planet's orbital period is proportional to the cube of the semi-major axis of its ..
T=2π√r3GME. For an ellipse, recall that the semi-major axis is one-half the sum of the perihelion and the aphelion.
Johannes Kepler proposed some laws based on the revolution of planets and according to his third law, the time taken for a new planet that is 3.68 x 107 km to travel around the Earth will be 0.121 years.
What is Kepler's third law?According to third law of Kepler, if the distance a travelled by a planet is expressed in astronomical unit and period of travel p in years then the relation between these two parameters is written as follows:
P²= a³
Kepler proposed that the planets in the solar system is revolving around the sun in an elliptical orbit and this is somewhat contradictory to the circular orbit model of Copernicus.
The distance of travel is given in 3.68 × 10⁷ km. One kilometer is 6.68 × 10⁻⁹ astronomical unit. Thus the given distance is 3.68 × 10⁷ × 6.68 × 10⁻⁹ = 0.2459 Au
Now, the time period P can be calculated as follows:
P² = (0.2459 Au)³
= 0.0145
p = 0.1249 years.
Therefore, according to Kepler's third law the time taken for a new planet that is 3.68 x 107 km to travel around the Earth will be 0.121 years.
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if two stars differ by 8 magnitudes, how many times greater is the flux from one star than the other?
Magnitude is a measure of the size or strength of a physical quantity or phenomenon. It is usually expressed in terms of a numerical value, usually on a logarithmic scale.
What is magnitude?The magnitude system is based on a logarithmic scale, where a difference of one magnitude corresponds to a brightness ratio of approximately 2.512.
This means that for each magnitude difference between two objects, the brighter object will have a flux that is 2.512 times greater than the dimmer object.
Magnitude is often used to describe the size of earthquakes, volcanic eruptions, floods, and other natural disasters, as well as the strength of stars, solar flares, and other celestial phenomena.
Magnitude is also used to describe the strength of the gravity and electromagnetic fields.
Therefore, a difference of 8 magnitudes corresponds to a brightness ratio of 2.512^8, which is approximately 400. This means that the flux from the brighter star will be 400 times greater than the flux from the dimmer star.
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