1.
10
122°
x
19
As a law of cosine

ANSWER

28.285 units

EXPLANATION

We are given the square EFGH and we need to find the perimeter.

The perimeter of a square is given as:

P = 4 * L

P = 4L

where L = length of the side of the square

To find the length of the side of the square, we have to find the distance between a pair of adjacent vertices of the square.

Let us pick E(0, 5) and F(5, 0).

The distance between the two points is:

where (x1, y1) = (0, 5)

(x2, y2) = (5, 0)

Therefore, the length of the square (distance between the two points) is:

Therefore, the perimeter of the square is:

P = 4 * 7.071

P = 28.284 units

(5^0)(g^6)h^−1

=\(\frac{g6}{h}\)

Answer:

1/16

Step-by-step explanation:

1/2×1/2×1/2×1/2...............

Answer and Explanation: The conditions when the net force and the net torque are zero are called static equilibrium.

Answer:

A and C

Step-by-step explanation:

A is equivalent to the expression because it just expanded the equation more a bit. It's distributed, but not solved. Like 3.2 (4p +8.5) is the same as 3.2 (4p) + 3.2 (8.5) since in both 3.2 is being distributed or multiplied by both numbers.

C is equivalent to the expression because it simplified the expression more. 3.2 times 4p is 12.8p. 3.2 times 8.5 is 27.2. The expression cannot be simplified.

Hope I helped! :)

Answer: the answer is b

Step-by-step explanation:

Answer:

8 and 4

Step-by-step explanation:

\(\left\{\begin{array}{ccc}y=2x&(1)\\3x+4y=22&(2)\end{array}\right\)

Put (1) to (2):

\(3x+4(2x)=22\\3x+8x=22\\11x=22\qquad|\text{divide both sides by 11}\\\boxed{x=2}\)

Substitute the value of x to (1):

\(y=2\cdot2\\\boxed{y=4}\)

Solution:

\(\huge\boxed{\left\{\begin{array}{ccc}x=2\\y=4\end{array}\right}\)

Answer:

Step-by-step explanation:

Explanation: There is nothing known as opposite in algebra. If you mean additive inverse it is 34 and if you mean multiplicative inverse or reciprocal it is −43 . multiplicative inverse, also called reciprocal, is the number which when multiplied with the number results in 1 , the multiplicative identity element.

Answer:

The opposite of 3/4 would be 4/3, simplified would be 1 1/3.

Step-by-step explanation:

Using the segment addition postulate, we can find that the value of x is 18.

Explanation: The segment addition postulate states that for three points A, B, and C on a line, if B is between A and C, then AB + BC = AC. In this case, we have three points on a line: E, F, and G, and we are given the lengths of two line segments, EF and FG. Using the segment addition postulate, we can set up the following equation:

EF + FG = EG

Substituting the given values, we get:

(7x+9) + (3x+4) = 143

Simplifying the equation, we get:

10x + 13 = 143

Subtracting 13 from both sides, we get:

10x = 130

Dividing both sides by 10, we get:

x = 13

Therefore, the value of x is 13.

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The amount of juice the cup can hold given that the cup has diameter of 8 centimeters and a height of 12 centimeters is 602.88 cm³

To know the amount of juice the cup can hold, we shall obtain the volume of the cup.

We shall use the formula for obtaining volume of cylinder to obtain the volume of the cup. Details below:

Volume = πr²h

Volume = 3.14 × 4² × 12

Volume = 3.14 × 16 × 12

Volume = 602.88 cm³

Thus, we can conclude from the above calculation that the amount of juice the cup can hold is 602.88 cm³

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Answer: S and T.

Step-by-step explanation:

I watched a video on how to do this just to answer, so it might not be right LOL. But since the angles are the same if you draw them from each other they both show the angles are equal which means the lines are parallel.

a. Present value of $400 per year for 14 years at 14%: $2,702.83
b. Present value of $200 per year for 7 years at 7%: $1,155.54
c. Present value of $400 per year for 7 years at 0%: $2,800
d. Present value of $400 per year for 14 years at 14% (annuity due): $2,943.07
  Present value of $200 per year for 7 years at 7% (annuity due): $1,233.24
  Present value of $400 per year for 7 years at 0% (annuity due): $2,800

To find the present values of the ordinary annuities, we can use the formula for the present value of an annuity:

PV = PMT * [(1 - (1 + r)^(-n)) / r]
Where:
PV = Present value
PMT = Payment per period
r = Interest rate per period
n = Number of periods

a. $400 per year for 14 years at 14%:
PV = $400 * [(1 - (1 + 0.14)^(-14)) / 0.14]

≈ $2,702.83

b. $200 per year for 7 years at 7%:
PV = $200 * [(1 - (1 + 0.07)^(-7)) / 0.07]

≈ $1,155.54

c. $400 per year for 7 years at 0%:
Since the interest rate is 0%, the present value is simply the total amount of payments over the 7 years:
PV = $400 * 7

= $2,800

d. Reworking previous parts assuming they are annuities due:
For annuities due, we need to adjust the formula by multiplying it by (1 + r):

a. Present value of $400 per year for 14 years at 14%:
PV = $400 * [(1 - (1 + 0.14)^(-14)) / 0.14] * (1 + 0.14)

≈ $2,943.07

b. Present value of $200 per year for 7 years at 7%:
PV = $200 * [(1 - (1 + 0.07)^(-7)) / 0.07] * (1 + 0.07)

≈ $1,233.24

c. Present value of $400 per year for 7 years at 0%:
Since the interest rate is 0%, the present value remains the same:
PV = $400 * 7

= $2,800

In conclusion:
a. Present value of $400 per year for 14 years at 14%: $2,702.83
b. Present value of $200 per year for 7 years at 7%: $1,155.54
c. Present value of $400 per year for 7 years at 0%: $2,800
d. Present value of $400 per year for 14 years at 14% (annuity due): $2,943.07
  Present value of $200 per year for 7 years at 7% (annuity due): $1,233.24
  Present value of $400 per year for 7 years at 0% (annuity due): $2,800

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ANSWER:

140

EXPLANATION:

Given:

We can go ahead and simplify as seen below;

Therefore the answer is 140

To summarize, we have found that any root of the equation e² - x = 6 lies within the interval [1.4, 1.389].

To find an interval [a, b] that contains a root of the equation e² - x = 6, we can rearrange the equation as x = e² - 6. We can then proceed to find bounds for x algebraically.

First, let's consider the exponential term e². The value of e is approximately 2.71828, so e² ≈ 7.389. Therefore, we can say that e² is greater than 7.

Next, we subtract 6 from e², giving us x = 7.389 - 6 = 1.389. Thus, x is greater than 1.389.

Combining the two inequalities, we have x > 1.389.

Therefore, we can conclude that any root of the equation e² - x = 6 will be greater than 1.389.

To find a tight bound, we can choose a value slightly larger than 1.389, such as 1.4. So, we can set a = 1.4.

Now, we need to find an upper bound. Since the equation is quadratic in nature, it will have two solutions. To find the upper bound, we can solve the equation and take the larger root.

e² - x = 6

x = e² - 6

To find the larger root, we need to calculate e² and subtract 6:

x = 7.389 - 6 = 1.389

Therefore, any root of the equation will be less than 1.389.

To summarize, we have found that any root of the equation e² - x = 6 lies within the interval [1.4, 1.389].

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complete question:

Consider the equation e² - x = 6. (a) Find an interval [a, b] which contains a root of this equation. Briefly illustrate algebraically why this is so. (Suggestion: Provide a tight bound with justification).

Answers to both subparts are shown:

So, (A) fraction of the game Tim wins:

Then, the fraction will be:

(B) Games Tim wins in 30 games.

So, a number of games won:

Therefore, answers to both subparts are shown:

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The correct question is shown below:

(A) tim played 20 games of draughts he won 16 of those games.what fraction of the game did he win

b) he played 30 more games he had then 68% of all his games how amny of 30 games did he wi

Answer:

y = - 9x + 14

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)

with (x₁, y₁ ) = (- 4, 50 ) and (x₂, y₂ ) = (5, - 31 )

m = \(\frac{-31-50}{5-(-4)}\) = \(\frac{-81}{5+4}\) = \(\frac{-81}{9}\) = - 9 , then

y = - 9x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (5, - 31 )

- 31 = - 9(5) + c = - 45 + c ( add 45 to both sides )

14 = c

y = - 9x + 14 ← equation of line

The amount of money in Iris's checking account can be modeled by a linear function of the form:

y = mt + b

where y is the amount of money in the account, t is the time (measured in years), m is the rate of interest, and b is the initial amount in the account.

In this case, we have m = 0.04 (since the interest rate is 4% per year) and b = 180 (since that's the initial amount in the account). Therefore, the linear function that models the amount of money in Iris's checking account at any time t is:

y = 0.04t + 180

For example, if t = 5 (years), then the amount of money in Iris's checking account is 0.04 * 5 + 180 = 198 dollars.

Answer:

\(\frac{2^{5} }{6^{5} } =2^{5} 6^{-6}\)

\(=2^5\times (2^{-5} 3^{-5} )\)

\(=2^{5-5} 3^{-5}\)

\(=2^{0} 3^{-5}\)

\(=3^{-5}\)

\(OAmalOHopeO\)

Answer:

B(3^-5) and D(2^5*6^-5)

Step-by-step explanation:

I put the expression in to the calculator and put the answers into the calculator and just picked the ones that matched

Answer:

The mean is lower than the median which is lower than the mode.

Step-by-step explanation:

Answer:

i dont know

Step-by-step explanation:

they got nick popkes

The given values for E(X) and E(Y) and simplifying, we found that E(2X+3Y+4) is equal to 25. correct option is a) 25

Using the linearity of expectation, we can find the expected value of 2X+3Y+4 as follows:

E(2X+3Y+4) = E(2X) + E(3Y) + E(4)

Since E(X) = 3 and E(Y) = 5, we have:

E(2X) = 2E(X) = 2(3) = 6

E(3Y) = 3E(Y) = 3(5) = 15

E(4) = 4

E(2X+3Y+4) = E(2X) + E(3Y) + E(4) = 6 + 15 + 4 = 25

Therefore, the answer is (a) 25, which we found by applying the linearity of expectation and using the given values of E(X) and E(Y). The linearity of expectation tells us that the expected value of a sum of random variables is equal to the sum of their individual expected values,

which is how we were able to break down E(2X+3Y+4) into E(2X), E(3Y), and E(4). By plugging in the given values for E(X) and E(Y) and simplifying, we found that E(2X+3Y+4) is equal to 25.

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Answer:

Your Perimiter is 42

Step-by-step explanation:

Distance from 7,5 to -7,5 is 14

Distance from -7,5 to -7,-2 is 7

Then we double both those numbers as it is a rectangle

2l + 2w = Per...

28 + 14 = 42

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If the growth rate of bacteria at any time is proportional to the number of bacteria present at t then the population after 20 weeks will be 403.42\(x_{0}\) in which \(x_{0}\) is the initial population.

Given that the growth rate of bacteria at any time t is proportional to the number present at t and triples in 1 week.

We are required to find the number of bacteria present after 10 weeks.

let the number of bacteria present at t is x.

So,

dx/dt∝x

dx/dt=kx

1/x dx=k dt

Now integrate both sides.

\(\int\limits {1/x} \, dx\)=\(\int\limits{k} \, dt\)

log x=kt+log c----------1

Put t=0

log \(x_{0}\)=0 +log c    (\(x_{0}\) shows the population in beginning)

Cancelling log from both sides.

c=\(x_{0}\)

So put c=\(x_{0}\) in 1

log x=kt+log \(x_{0}\)

log x=log \(e^{kt}\)+log \(x_{0}\)

log x=log \(e^{kt}x_{0}\)

x=\(e^{kt}x_{0}\)

We have been given that the population triples in a week so we have to put the value of x=2\(x_{0}\) and t=1 to get the value of k.

2\(x_{0}\)=\(e^{k} x_{0}\)

2=\(e^{k}\)

log 2=k

We have to now put the value of t=20 and k=log 2 ,to get the population after 20 weeks.

x=\(e^{20log 2}\)\(x_{0}\)

x=\(e^{0.30*2}\)\(x_{0}\)

x=\(e^{6}x_{0}\)

x=403.42\(x_{0}\)

If the growth rate of bacteria at any time is proportional to the number of bacteria present at t then the population after 20 weeks will be 403.42\(x_{0}\) in which \(x_{0}\) is the initial population.

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The given question is incomplete as the question incudes the following:

Calculate the population after 20 weeks.

Sport stars play a vital role in the entertainment value of contemporary sports, captivating audiences and sustaining relevance.

The course topic chosen is "Sport Stars as Entertainers". In the realm of contemporary sports, it is often argued that for a sport to remain relevant, it must be entertaining. This viewpoint emphasizes the role of sport stars in captivating audiences and sustaining interest in the sport. Let's analyze this perspective through two sporting examples: basketball and soccer.

In basketball, players like Michael Jordan and LeBron James have not only displayed exceptional athletic abilities but also entertained fans with their captivating performances. Their gravity-defying dunks, breathtaking passes, and clutch performances have elevated the sport's entertainment value and made it globally popular.

Similarly, in soccer, players like Cristiano Ronaldo and Lionel Messi have not only showcased extraordinary skills but also mesmerized fans with their creativity, agility, and goal-scoring prowess. Their individual brilliance and intense rivalry have heightened the entertainment factor in the sport, drawing millions of viewers worldwide.

These examples illustrate how sport stars play a crucial role in making their respective sports entertaining. Their exceptional talents, competitive spirit, and ability to deliver extraordinary performances enhance the overall appeal and keep the sports relevant in the contemporary landscape.

In conclusion, sport stars as entertainers have a significant impact on the relevance of contemporary sports. Their charisma, skills, and captivating performances contribute to the entertainment factor, attracting and retaining fans' interest.

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Answer:

Step-by-step explanation:

How to solve your problem

5+6−3=12

Combine like terms

5

+

6

−

3

=

1

2

{\color{#c92786}{5m}}+6{\color{#c92786}{-3m}}=12

5m+6−3m=12

2

+

6

=

1

2

(B) The p-esteem is more prominent than 0.05 yet under 0.10, in this manner there is no proof of a tremendous distinction in mean hunt times on the two sites.

The p-value that was derived from the data and the significance level (alpha) that was selected for the test must be compared in order to determine the correct response.

Since the importance level isn't given in the inquiry, we'll expect a typical worth of 0.05, which is much of the time utilized in speculation testing.

A two-sample t-test can be used to test the hypothesis that the two websites have significantly different mean search times. The test statistic and its corresponding p-value can be calculated using the sample means, standard deviations, and sample sizes.

The appropriate degrees of freedom are used to calculate the p-value using statistical software or a calculator.

In this instance, we reject the null hypothesis if the calculated p-value falls below the significance level (alpha) of 0.05, assuming that the conditions for inference are satisfied. In any case, if the p-esteem is more noteworthy than or equivalent to 0.05, we neglect to dismiss the invalid speculation.

Since the importance level isn't unequivocally referenced in the inquiry, we'll expect to be alpha = 0.05.

The correct response is, as a result of this:

B) The p-esteem is more prominent than 0.05 yet under 0.10, in this manner there is no proof of a tremendous distinction in mean hunt times on the two sites.

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Answer:

u=1

Step-by-step explanation:

6x2u+12+7u+3=6u+30-2u=19u+15=4u+30=19u=4u+15

\(6(2u +2)+ 7u+3 = 6(u+5) -2u\\\\\implies 12u +12 +7u+3 = 6u+30-2u\\\\\implies 19u +15 = 4u +30\\\\\implies 19u -4u = 30 -15\\\\\implies 15u = 15\\\\\implies u =\dfrac{15}{15} =1\)

Answer:

1) 245 x 20 remander2/13 = 4940

2) square root of 58 - 29 + 38

= 8.19

Step-by-step explanation:

245 x 20 remander2/13= 245* 20 2/13

245 x 20 remander2/13= 245 * 262/13

245 x 20 remander2/13= (245*262)/13

245 x 20 remander2/13 =64190/13

245 x 20 remander2/13= 4937.69

245 x 20 remander2/13 = 4940

square root of 58 - 29 + 38

= √(58-29+38)

square root of 58 - 29 + 38

= √(96-29)

square root of 58 - 29 + 38

= √(67)

square root of 58 - 29 + 38

= 8.185

square root of 58 - 29 + 38

= 8.19