1)A 25 kg air compressor is dragged up a rough incline from r⃗ 1=(1.3ı^+1.3ȷ^)m to r⃗ 2=(8.3ı^+2.6ȷ^)m, where the y-axis is vertical. How much work does gravity do on the compressor during this displacement?
2)A 25 kg box sliding to the left across a horizontal surface is brought to a halt in a distance of 55 cm by a horizontal rope pulling to the right with 16 N tension.How much work is done by tension?How much work is done by gravity?
Answers
As for the work done by gravity, in this case, it is zero because the box is sliding horizontally on a horizontal surface, and gravity does not do any work in this direction. Therefore, the total work done by tension is 8.8 Joules.
What is the work done by gravity?To calculate the work done by gravity on the air compressor during its displacement up the incline, we need to determine the change in gravitational potential energy.
The gravitational potential energy (PE) of an object is given by the equation \(PE = mgh\), where m is the mass of the object, g is the acceleration due to gravity, and h is the change in height.
Given:
Mass of the air compressor, \(m = 25 kg\)
Acceleration due to gravity, \(g = 9.8 m/s^2\) (assuming Earth's gravity)
Initial position, \(r⃗ = (1.3ı^ + 1.3ȷ^) m\)
Final position, r⃗\(2 = (8.3ı^ + 2.6ȷ^) m\)
Change in height, h = Final y-coordinate - Initial y-coordinate \(= y2 - y1 = 2.6 m - 1.3 m = 1.3 m\)
Therefore, the work done by gravity on the air compressor is:
\(W = \Delta PE = mgΔh = 25 kg * 9.8 m/s^2 * 1.3 m = 318.5 J\) (rounded to one decimal place)
So, the work done by gravity on the air compressor during its displacement up the incline is approximately 318.5 Joules.
The work done by tension can be calculated using the equation \(W = Fd\), where F is the force applied and d is the displacement.
Given:
Tension force, \(F = 16 N\) (in the opposite direction of displacement)
Displacement, \(d = 55 cm = 0.55 m\)
Therefore, the work done by tension is:
\(W = Fd = 16 N \times 0.55 m = 8.8 J\)
Therefore, As for the work done by gravity, in this case, it is zero because the box is sliding horizontally on a horizontal surface, and gravity does not do any work in this direction. the work done by tension is \(8.8\) Joules.
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Related Questions
Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in another 1 minute. What are Joseph's average speeds and velocities in jogging (a) from A to B and (b) from A to C?
Answers
Answer:
Explanation:
(a) It is given that Joseph jogs on a straight road of 300m in a time interval of 2 minutes and 30 seconds, which is equal to 150seconds. Therefore, when Joseph jogs from point A to point B, he covers a distance of 300m in time of 150seconds. Hence, his average speed is 300m/150s=2ms^−1. Since it is a straight road and he jogs in a single direction in this case, his displacement is equal to 300m. Since it is a straight road and he jogs in a single direction in this case, his displacement is equal to 300m.
Hence, his average velocity is 300m/150s=2ms^−1
(b) Then it is given that he turns back and points B and jogs on the same road but in the opposite direction for a time interval for 1 minute and covers a distance of 100m.If we consider the whole motion of Joseph, i.e. from point A to point C, then he covers a total distance of 300m+100m=400m. And he covers this total distance in a time interval of 2.5min+1min=3.5min=210s.
Therefore, his average speed for this journey is 400m210s=1.9ms−1.
For the same journey is displacement is equal to the distance between the points A and C,i.e. 300m−100m=200m.
Hence, his average velocity for this case is 200m/210s=0.95ms^−1
At the instant r=1. 5m, the 5 kg disk is given a speed of v=5m/s, perpendicular to the elastic cord.
Determine the speed of the disk at the instant r=1. 2m. The disk slides on the smooth horizontal plane. Neglect its size. The cord has an unstretched length of 0. 5 m.
Determine the rate of shortening of the elastic cord at the instant r=1. 2m
Answers
The rate of shortening of the elastic cord at r = 1.2 m is 6.25 m/s. The rate of shortening of the elastic cord at r = 1.2 m is 0.208 m/s
\(KE_i\)= (1/2)mv² = (1/2)(5 kg)(5 m/s)² = 62.5 J
PE = (1/2)k(r - \(r_0\))²
(1/2)mv² = (1/2)k(r - \(r_0\))²
Solving for v, we get:
v = √(k/m)(r - \(r_0\))²)
At r = 1.2 m, the speed of the disk is:
v = √((k/5 kg)(1.2 m - 0.5 m)²) = 3.83 m/s
\(L_i = Iw_i =\)(1/2)mr²(0) = 0
\(L_i = L\)
0 = (1/2)mr_i²\(w_i\)= (1/2)\(mr_f\)²\(w_f\)
Solving for ω_f, we get:
\(w_f = (r_i/r_f)w_i\)
\(v_r = rw_f = (r_i/r_f)r_iw_i\)
Substituting the given values, we get:
\(v_r\) = (1.5 m/1.2 m)(1.5 m)(5 m/s)/(1.5 m) = 6.25 m/s
At r = 1.2 m, we have:
dl/dt = (1.2 m - 1.5 m) / √[(1.2 m - 1.5 m)² + (1.0 m)²] × (v/r) = -0.208 m/s
An elastic cord refers to a flexible material that can stretch and then return to its original shape and length when a force is applied and then removed. The behavior of an elastic cord can be described by Hooke's law, which states that the force applied to an elastic material is proportional to the amount of stretch or compression produced.
The elastic cord has many practical applications, such as in bungee jumping, where the cord is stretched and then allowed to contract rapidly, producing a thrilling and exciting experience. It is also used in medical devices, such as braces and orthotics, to provide support and compression to the affected area. The elasticity of the cord depends on the material used and the thickness of the cord. Rubber and latex are common materials used to make elastic cords due to their high elasticity and ability to stretch without breaking.
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As the volume of a gas increases, its pressure
(Assume all other factors are held constant).
Answers
What is the unit of a declinometer?
Answers
Answer
Clinometers measure both inclines and declines using three different units of measure: degrees, percentage points, and topo . Astrolabe is example of an inclinometer that was used for celestial navigation and location of astronomical objects from ancient times to the Renaissance.
f two connected points objects pass through the same set of three points, the shapes created by each may be different, depending on the order in which each object was plotted. true false
Answers
The given statement is true.
The order in which the points are plotted determines the shape of the object formed. For example, if two objects pass through the same set of three points, in one case the object could be a triangle and in another case it could be a line. The order of the points can change the type of shape that is created, so two connected objects passing through the same set of points can result in different shapes, depending on the order in which they were plotted.So, the statement "two connected points objects pass through the same set of three points, the shapes created by each may be different, depending on the order in which each object was plotted" is true.
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consider the direction of the work, w, done (the system does work on the surroundings). what is the sign of the work done, from the perspective of the system?
Answers
if the system does work on the surroundings, the sign of the work done is positive.
The sign of the work done from the perspective of the system depends on whether work is being done by the system or on the system.
If work is done by the system (work is positive), then the sign of the work done is positive. This means that the system is doing work on the surroundings.
If work is done on the system (work is negative), then the sign of the work done is negative. This means that work is being done on the system by the surroundings.
In summary, if the system does work on the surroundings, the sign of the work done is positive.
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Need help with these physic questions!
Answers
Explanation:
4.
Given: Δd = 4 + 2 + 1 = 7km, Δt = 32 + 22 + 16 = 70mins
Required: V
Equation: V = Δd/Δt
Solution: V = 7/70
= 0.1km/min
5. In an electric bell, electromagnet attracts________
towards itself.
Answers
Ans: It attracts iron armature
Friends tell you that on a recent trip their average velocity was +20 m/s. Is it possible that at any time during their trip their velocity was -20 m/s? Explain, and give an example to justify your answer. PLEASE HELP
Answers
Answer: Yes. Please find the answer in the explanation.
Explanation:
Yes. Since velocity is a vector quantity, that is, it has both magnitude and direction.
If the displacements covered are not of the same direction, the velocity will not also of the same direction.
Take for instance, if the velocity in a positive is 40 m/s and velocity in the opposite direction is - 20 m/s . Then, the resultant velocity will be 40 - 20 = 20 m/s
Therefore, it is possible that at any time during their trip their velocity was -20 m/s.
After traveling for 6.0 seconds, a runner reaches a speed of 12 m/s after starting
from rest. What is the runner's acceleration?
A. 2 m/s²
OB. 72 m/s²
C..5 m/s²
D. 6 m/s²
Answers
Answer:
A
Explanation:
accel = Δv / Δ t = 12/6 = 2 m/s^2
a racing car travels with a constant tangential speed of 75.0 m/s around a circular track of radius 625 m. find (a) the magnitude of the car's total acceleration and (b) the direction of its total acceleration relative to the radial direction.
Answers
The racing car travels with a constant tangential speed of 75.0 m/s around a circular track of radius 625 m are:
Constant Velocity , u = 75 m/s
Radius , r = 625 m
a) Total Acceleration = v^2/r
Total Acceleration = 75^2/(625)
Total Acceleration Acceleration = 9 m/s^2
The magnitude of the total acceleration is 9 m/s^2
b) Since the velocity is constant
The tangential acceleration is zero
The total acceleration is therefore the radial acceleration.
the direction of total acceleration relative to radial direction is zero
Acceleration is the name we give to the process of changing velocity. Velocity is speed and direction, so there are only two ways to accelerate. Either change speed, change direction, or change both
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which is true of Pluto?
A. Pluto has a moon that is about half it's size.
B. Pluto's orbit is shorter than than Saturn's.
C. Pluto orbits the sun every 2.5 earth years.
D. Pluto is only larger than Mercury.
Answers
Answer:d
Explanation:
Probably becuase it is further than Saturn
It takes like 70 years to go around the sun
And it is bigger than the moon
Answer: pluto has a moon that is about half of its size.
Explanation: just because
What are 2 laws of reflection
Answers
Answer:
The two laws of reflection are as follows: ... The incidenct ray, the reflected ray, and the normal to the reflecting interface at the point of incidence all lie in the same plane. 2. The angle of incidence equals the angle of reflection.
Vision is blurred if the head is vibrated at 29 {\rm Hz} because the vibrations are resonant with the natural frequency of the eyeball held by the musculature in its socket. If the mass of the eyeball is 7.5 {\rm g}, a typical value, what is the effective spring constant of the musculature attached to the eyeball? (2 sig figs in N/m)
Answers
This equation assumes that the eyeball is a simple harmonic oscillator and that the musculature acts as a linear spring. The frequency of the vibration (f) is equal to the natural frequency of the eyeball's oscillation and the mass (m) is the mass of the eyeball.
What is the frequency ?The frequency is the rate or number of occurrences of a particular event or phenomenon with respect to its occurrence within a given period of time. It is typically measured in cycles per second (hertz), or the number of times an event occurs in a given period of time. Frequency can also refer to the rate at which something is repeated, such as the number of times a sound is repeated in a given span of time. Frequency can also refer to the number of times a certain action is performed, such as the number of times a person visits a store in a given month.
The effective spring constant of the musculature attached to the eyeball is equal to the frequency squared (f^2) multiplied by the mass (m) divided by 4pi^2:
k = f^2 m / 4pi^2
k = (29 Hz)^2 (7.5 g) / (4(3.14)^2)
k = 0.395 N/m (2 sig figs)
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Equation \(\\k = 0.395 N/m (2 sig figs)\) assumes that the eyeball is a simple harmonic oscillator and that the musculature acts as a linear spring.
The frequency of the vibration (f) is equal to the natural frequency of the eyeball's oscillation and the mass (m) is the mass of the eyeball.
What is the frequency ?The frequency is the rate or number of occurrences of a particular event or phenomenon with respect to its occurrence within a given period of time. It is typically measured in cycles per second (hertz), or the number of times an event occurs in a given period of time. Frequency can also refer to the rate at which something is repeated, such as the number of times a sound is repeated in a given span of time. Frequency can also refer to the number of times a certain action is performed, such as the number of times a person visits a store in a given month.
The effective spring constant of the musculature attached to the eyeball is equal to the frequency squared (f^2) multiplied by the mass (m) divided by 4pi^2:
\(k = f^2 m / 4\pi^2\\k = (29 Hz)^2 (7.5 g) / (4(3.14)^2)\\k = 0.395 N/m (2 sig figs)\)
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Kayaks have been used for thousands of years to hunt and fish in Arctic regions. The total volume of a particular kayak is 285 litres (which is 0.285 m3). It has a mass of 75 kg. The man using it has a volume of 0.066 m3. When sitting in the kayak, half of man’s volume is inside the kayak. The density of the human body is about 1000 kg/m3.Calculate the density of the empty kayak.
Answers
Given,
The volucme of Kayak, V₁=0.285 m³
The mass of the Kayak when the man is sitting in it, m₁=75 kg
The volume of the man, V₂=0.066 m³
The density of the man, d=1000 kg/m³
The mass of the man inside the Kayak is given by,
\(m_2=V_2\times d\)On substituting the known values,
\(\begin{gathered} m_2=0.066\times1000 \\ =66\text{ kg} \end{gathered}\)The mass of the empty Kayak is,
\(\begin{gathered} M=m_1-m_2 \\ =75-66 \\ =9\text{ kg} \end{gathered}\)Given that only half of the volume of the man is inside the Kayak when he is sitting in it. Half of the man's volume which is outside the Kayak will be considered in the total volume of the Kayak when he is sitting in it. Thus we have to subtract half of his volume, which is outside the Kayak, while we calculate the density of the Kayak.
Thus the density of the empty Kayak is
\(\rho=\frac{M}{V_1-\frac{V_2}{2}}\)On substituting the known values,
\(\begin{gathered} \rho=\frac{9}{0.285-\frac{0.066}{2}} \\ =35.71kg/m^3 \end{gathered}\)Thus the density of the Kayak is 35.71 kg/m³
ocean acidification impacts corals in what major way?
Answers
Guidewords for the word “serpent” may be
a.
Serbia and service
c.
Seltzer and Saturday
b.
Seattle and section
d.
Solitude and second
THE CORRECT ONE IS A!!!!!!!!
Answers
Answer:
A. Serbia and service
Explanation:
A guide word is a word written on top of a page to indicate the first or last word entry on that page. For example in a dictionary, they indicate the alphabetical first and last words on the page.
In this example; the word ' serpent ' note the first three letters to guide you in the words that are on that page;
In this case : Serbia and Service.
the mass of the earth is 6 × 10²² kg and that of the moon is 7.4× 10²² Kg if the distance between the earth and moon is 3.84 × 10⁵ km . calculate the force of the earth exerted by it on the moon . Take G = 6.67×10¹¹ Nm² / kg²
Answers
Answer:
Force = 20.08 x 10⁴⁷ N
Explanation:
Given:
M1 = 6 × 10²⁴ kg (rectified)
M2 = 7.4× 10²² Kg
Radius r = 3.84 × 10⁵ km
G = 6.67×10¹¹ Nm² / kg²
Find:
Force
Computation:
F = GM1M2 / r²
Force = [(6 × 10²⁴)(7.4× 10²²)(6.67×10¹¹ )] / (3.84 × 10⁵)²
Force = [296.148 × 10⁵⁷] / [14.7456 × 10¹⁰]
Force = 20.08 x 10⁴⁷ N
The drawbridge then starts to rise. The dancer continues to stand on one leg. The drawbridge stops just at the point where the dancer is on the verge of slipping. What is the magnitude f of the frictional force now?.
Answers
The magnitude f of the frictional force now is F_f =n*μs.
Friction is the force resisting the relative motion of sturdy surfaces, fluid layers, and material factors sliding towards each specific. There are numerous styles of friction: Dry friction is a strain that opposes the relative lateral movement of two stable surfaces in touch.
Friction is the shape of contact pressure. It exists between the surfaces that are in touch. The frictional force relies upon the character of the floor in contact. The rougher the ground, the extra friction is involved. The frictional force is proportional to the urgent pressure, which is the burden of the body. it's miles impartial of the place of the touch.
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are you more likely to be able to walk at constant velocity
Answers
When you walk, you are more likely to be able to walk at a constant velocity. Your walking speed varies as you walk in real-life scenarios, but you aim to maintain a steady pace or velocity. This is how you can keep track of time and distance traveled.
When you walk at a constant velocity, you move forward with a steady speed and direction. The velocity is defined as the rate at which an object's position changes with respect to time. When you walk, you typically aim to move forward with a constant velocity, which is the speed at which you walk and the direction you walk. In certain situations, a constant velocity is ideal, such as when you are traveling long distances and want to arrive at your destination at a certain time. To ensure that you walk at a constant velocity, you need to maintain a steady pace by keeping your stride consistent and avoiding unnecessary stops or changes in direction. Walking with a constant velocity involves maintaining a steady speed and direction. It is possible to achieve this by maintaining a constant pace, keeping your stride consistent, and avoiding any unnecessary stops or changes in direction.
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a car travels at a constant speed of 20m/s and yet it does not have a constant velocity. explain how this could be
Answers
Answer:
HOPE THIS HELPS!!
Explanation:
Velocity is speed as well as distance mentioned.
The car is traveling at a constant speed of 20m/s but it may not be traveling in any particular direction. It would be taking many turns (left and right) or it would be moving in a circular manner.
So,it is at constant speed but not constant velocity.
please help!!
Kara is setting up a tee-shirt cannon for a community event. The angle of the cannon can be adjusted, but all projectiles leave the cannon at 25 meters per second. If Kara sets the angle of the cannon to be 20 degrees above horizontal, what will be the range of the projectiles?
Answers
The range of the shots(projectiles) will be around 131.65 meters when the point of the cannon is set to 20 degrees above level.
To decide the run of the shots, we have to calculate the horizontal distance that the shots will travel.
Ready to utilize the taking after kinematic condition to fathom for the run:
\(R = (v^2/g) * sin(2θ)\)
Where:
R = run
v = starting speed (25 m/s)
g = increasing speed due to gravity (9.81 m/s²)
θ = point of the cannon (20 degrees)
Substituting the given values into the condition, we get:
\(R = (25^2/9.81) * sin(2*20)\)
R = 131.65 meters
In this manner, the run of the shots will be around 131.65 meters.
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The graph below shows the decay of a radioactive isotope. The half life is 40 seconds - approximately, how many radioactive atoms remain after 2 half-lives?
a 15 atoms
b 8 atoms
c 5 atoms
d 0 atoms
the graph is the link
Answers
The number of radioactive atoms remaining after 2 half lives has elapsed, given the data is 8 atoms (Option C)
How to determine the radioactive atoms remainingThe amount of radioactive substance remaining is related to the number of half lives that has elapsed according to the following equation:
N = N₀ / 2ⁿ
Where
N is the amount remainingN₀ is the original amount at time zeron i s the number of half livesWith the above formula, we can obtain the radioactive atoms remaining. Details below
From the question given above, the following data were obtained:
Original amount of radioactive atoms (N₀) = 30 atomsNumber of half-lives (n) = 2 half livesRadioactive atoms remaining (N) = ?N = N₀ / 2ⁿ
N = 30 / 2²
N = 30 / 4
N = 8 atoms
Thus, the radioactive amount remaining is 8 atoms (Option C)
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If we interpret the large, angular rocks to have originated from the outcrop at the top of the hill, we are using __________ reasoning.
Answers
The reasoning which is in use when large, angular rocks are interpreted to have originated from the outcrop at the top of the hill is; Fossil succession
Fossil succession of rocksThe principle of fossil succession in characterized by the fact that fossil entities succeed one another upward through rock layers in a definite and determinable order.
On this note, any time period can be dated by its fossil content.
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Suppose you are testing a new amusement park roller coaster with an empty car with a mass of 100 kg. One part of the track is a vertical loop with a radius of 12.0 m. At the bottom of the loop (point A), the car has a speed of 25.0 m/s and at the top of the loop (point B), it has a speed of 8.00 m/s. As the car rolls from point A to point B, how much work is done by friction? Use 9.81 m/s2 for the acceleration due to gravity.
Answers
Answer:
Explanation:
Gain of kinetic energy + work done by friction = loss of potential energy
= 1 / 2 m ( 25² - 8² ) + work done by friction = m x 9.8 x ( 12 + 12 )
= .5 x 100 x ( 625 - 64 ) + work done by friction = 100 x 9.8 x 24
28050 + work done by friction = 23520
work done by friction = -4530 J
Explain why the total positive charge in every atom of an element is always the
same.
Answers
Answer:
When an atom has an equal number of electrons and protons, it has an equal number of negative electric charges (the electrons) and positive electric charges (the protons). The total electric charge of the atom is therefore zero and the atom is said to be neutral.
Explanation:
An atom has an equal quantity of positive and negative electric charges (the protons and electrons) when its electron and proton counts are equal (the protons). Since the atom has a total electric charge of zero, it is referred regarded as being neutral.
What is an atom?The atom is the smallest unit of matter that may be divided without resulting in electrically charged particles. Additionally, it is the tiniest substance with features like chemical elements. The atom is therefore the basic building block of chemistry.
Examine different electron arrangements in the electron shells that surround an atom's nucleus.
Examine different electron arrangements in the electron shells that surround an atom's nucleus. The rest is made up of a cloud of negatively charged electrons surrounding a positively charged nucleus made up of protons and neutrons. Compared to electrons, which are the lightest charged particles in nature, the nucleus is small and dense.
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What is the mathematical relationship between wavelength and velocity?
Answers
Answer:A wave has a wavelength λ, which is the distance between adjacent identical parts of the wave. The wave velocity and the wavelength are related to the wave's frequency and period by vw=λT or vw=fλ.
Explanation:
energy from the ocean waves is another form of what kind of energy?
Answers
Wave energy or wave power is a type of renewable energy derived from ocean waves. It belongs to the broader category of tidal energy.
The energy in the ocean waves is a form of concentrated solar energy that is transferred through complex wind-wave interactions.
Wave energy or wave power is a type of renewable energy derived from ocean waves. It belongs to the broader category of tidal energy, which includes a variety of sources of energy derived from ocean waves and tides. The kinetic energy of ocean waves is used to create wave energy, which is then transformed into electricity utilising various technologies such wave buoys, oscillating water columns, and submerged equipment. Being primarily influenced by wind patterns and the gravitational pull of the moon and sun, two naturally occurring phenomena, waves are regarded as a sustainable energy source.
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Two charged objects originally felt 12N of attraction. One charge is changed from to 3C to 6C and their distance changes from 15cm apart to 45cm apart. What is the new force of attraction ?
Answers
Given that,
Initial force, F = 12 N
First initial charge, q₁ = 3C
First new charge, q₁' = 6C
Initial distance, r = 15 cm
New distance, r' = 45 cm
To find,
The new force of attraction.
Solution,
The force between two charges is given by :
\(F=k\dfrac{q_1q_2}{r^2}\)
\(12=k\dfrac{3\times q_2}{15^2}\ ....(1)\)
Let F' is the new force.
\(F'=k\dfrac{q_1'q_2'}{r'^2}\)
\(F'=\dfrac{k\times 6\times q_2}{(45)^2}\ ...(2)\)
As q₂ is same in this case.
Dividing equation (1) and (2) :
\(\dfrac{F}{F'}=\dfrac{k\dfrac{3q_2}{15^2}}{\dfrac{k\times 6\times q_2}{45^2}}\\\\\dfrac{12}{F'}=4.5\\\\F'=\dfrac{12}{4.5}\\\\F'=2.67\ N\)
So, the new force of attraction is 2.67 N.
If water vapour at 200kPa and 150∘C is adiabatically compressed to 2500kPa and 250∘C at a mass flow rate of 4680 kg/h, calculate the power input to the compressor. Hint: Check the related tables in the appendix of textbook. Choose one of the following answers. a.438 kW b.234 kW c.145 kW d.112 kW
Answers
The correct option is a.438 kW. Adiabatic compression is a thermodynamic process where the compression is done so quickly that no heat exchange takes place between the system and surroundings. In order to calculate the power input to the compressor, the work done during the adiabatic compression of water vapor must be determined.
The work done is equal to the change in enthalpy, ΔH. The mass flow rate of the water vapor is 4680 kg/h. The enthalpy at point 1 is 3414 kJ/kg, while the enthalpy at point 2 is 4136 kJ/kg. At a pressure of 200 kPa and a temperature of 150 °C, the enthalpy of water vapor is 3414 kJ/kg, according to the steam table.
The power input to the compressor can be determined by dividing the work done by the time required to do it.P = W / tThe mass flow rate of water vapor is 4680 kg/h, which is equivalent to 1.3 kg/s. 3395520 J/s ÷ 1.3 kg/s = 2611963.08 J/kg. Therefore, the power input to the compressor is 2611963.08 J/kg or 2611.96 kW.
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