19. what is the empirical formula for C36H9?

The standard reduction potential of the Cr³+/Cr electrode is -0.46V. None of the option is correct.

To determine the standard reduction potential of the Cr³+/Cr electrode, we can use the Nernst equation, which relates the standard reduction potential to the cell potential under non-standard conditions. The Nernst equation is given by:

E = E° - (0.0592/n) * log(Q)

where E is the cell potential, E° is the standard reduction potential, n is the number of electrons transferred in the half-reaction, and Q is the reaction quotient.

In this case, we have the standard potential of the cell as −0.60V. We know that the standard reduction potential of the Sn/Sn²+ electrode is -0.14V. Therefore, the reduction potential of the Cr³+/Cr electrode can be calculated as:

E = -0.60V - (-0.14V)

E = -0.60V + 0.14V

E = -0.46V

Therefore, the standard reduction potential of the Cr³+/Cr electrode is -0.46V.

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Answer:

Robert Delaunay's Homage to Blériot (1914) was inspired by the first flight across the English channel.

Answer: A

Explanation:

it had wings that flapped, similar to birds' wings.

55.03 moles of KCI are produced when 6743 grams of \(KClO_{3}\) decomposes

To determine the number of moles of KCl produced when 6743 grams of \(KClO_{3}\) decomposes, we need to use the concept of molar mass and the balanced chemical equation.

First, let's calculate the molar mass of \(KClO_{3}\)

The molar mass of potassium (K) is approximately 39.10 g/mol.

The molar mass of chlorine (Cl) is approximately 35.45 g/mol.

The molar mass of oxygen (O) is approximately 16.00 g/mol.

So, the molar mass of \(KClO_{3}\) is:

(39.10 g/mol) + (35.45 g/mol) + (3 * 16.00 g/mol) = 122.55 g/mol.

Now, we need to calculate the number of moles of \(KClO_{3}\):

Number of moles = Mass / Molar mass

Number of moles = 6743 g / 122.55 g/mol = 55.03 mol.

According to the balanced chemical equation:

2\(KClO_{3}\) -> 2 KCl + 3 O2,

we can see that for every 2 moles of \(KClO_{3}\), we obtain 2 moles of KCl.

Therefore, the number of moles of KCl produced will be equal to the number of moles of \(KClO_{3}\) since the ratio is 1:1. Thus, 55.03 moles of KCl will be produced.

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Answer:

This is because, Kelvins and Celcius degrees both agree at fixed points i.e; the lower fixed point and upper

The two functional groups that the aminoacid has according to the picture are amine and carboxyl.

In chemistry and related areas, a functional group can be defined as a group of atoms bonded in a specific molecule that can affect the was the molecule reacts or the specific behavior of it.

In the case of the molecule presented, which is an amino acid, two functional groups can be identified:

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NaCl as a limiting reactant ⇒ true

Given

1.2 g NH₄HCO₃

0.75 g NaCl

63.0075 g NaHCO₃

Required

The limiting reactant

Solution

Reaction

NH₄HCO₃ + NaCl ⇒NH₄Cl + NaHCO₃

mol NH₄HCO₃ :

= 1.2 g : 79,056 g/mol

= 0.015

mol NaCl :

= 0.75 : 58.5

= 0.013

NaCl as a limiting reactant(smaller mol)

a)possesses a negative charge - electron

b)has no charge - neutron

c)has a mass slightly less than that of a neutron - proton

d)has a charge equal to, but opposite in sign from, that of an electron - proton.

What has a negative charge?

Electrons have a negative charge. The charge on the proton and electron are exactly the same size but opposite. Neutrons have no charge. Since opposite charges attract, protons and electrons attract each other.

What are the four properties of neutrons?

Neutrons are neutral particles – with no net electric charge.

Neutrons have a non-zero magnetic moment.

Free neutrons (outside a nucleus) are unstable and decay via beta decay.

Is a neutron's mass slightly less than a proton's?

The mass of a neutron is slightly greater than the mass of a proton, which is 1 atomic mass unit (AMU).

Is the charge of an electron opposite to the charge of a proton?

Electrons and protons have equal and opposite charges. The magnitude of this charge is 1.6×10−19 Coulomb.

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Answer:

How do amoeba respire.

Define Diffusion.

Answer:

The mass, CO2 and CO3 from the limestone sample is discussed below in details.

Explanation:

(A) mass loss of sample of limestone after 20 min

= 0.8437g-0.5979g = 0.2458 g

From the given reaction of limestone, 2 mol of the sample gives 2 moles of CO 2.

Therefore  

184.4 g ( molar mass of limestone) gives2× 44 g of carbon dioxide.

1 g of sample gives 88/184.4 g of carbon dioxide

Hence 0.2458 g sample gives

= 88/184.4 × 0.2458 g = 0.117 g carbon dioxide

(B) mole of CO 2 lost = weight/ molar mass

= 0.117 g / 44 g/mol =0.0027 mole

(C). 1 mol of limestone contain 2 mol of carbonate ion

From the reaction we know that carbonate ion of limestone is converted into carbondioxide

Hence lost carbonate ion = 0.2458 g

(D) we know that

1 mol limestone contain 1mol CaCO​​​ 3

Hence in sample present CaCO​​​ 3

= 1mole / 184.4 g × 0.8437 g= 0.00458 mol CaCO​​​3

Answer:

Signal noise will reduce the information in the transmitted signal.

Explanation:

Signal noise is the most likely factor that will reduce the information in a transmitted signal because:

The number of moles of carbondioxide that will be produced in the combustion of methane is 3 moles (option D).

Stoichiometry refers to the study and calculation of quantitative (measurable) relationships of the reactants and products in chemical reactions (chemical equations).

According to this question, methane undergoes combustion in air to produce carbondioxide and water. Methane is the limiting reactant because the other reactant is oxygen of the air which is always present in excess.

Based on the chemical equation given above, 1 mole of methane produces 1 mole of carbondioxide.

This means that 3 moles of methane will produce 3 moles of carbondioxide.

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The amount of 0.303N NaOH needed to neutralize a 13.0 ml sample of acid is 37,3 ml. Acid is 0.823N normal, according to the standard.

The idea of neutralization, according to which an acid reacts with a base to create salt and water. By comparing the molarity of the base to the amount of base needed for neutralization, it is possible to calculate the molarity of the acid. Once the molarity and the acid's valence (or charge) have been multiplied, the acid's normalcy can be determined.

By deducting the volume of NaOH (37.3 ml) from the volume of the acid sample in Step 1, you can calculate the amount of acid that was utilized in the neutralization procedure (13.0 ml).

Consequently, 13.0 ml to 37.3 ml

= -24.3 ml

Use the equation moles = normality x volume to determine the number of moles of acid that were used in the process.

Consequently, moles equal 0.303N x -24.3 ml.

= -7.33 moles

Determine the acid's normality by multiplying the volume by the formula normalcy = moles.

As a result: normalcy = -7.33 moles / 13.0 ml

= -0.823N

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By using the ideal gas law and Avogadro's number, we find that there are approximately 6.72 × 10^22 molecules of CO2 in 2.5 L at STP.

To determine the number of molecules of CO2 in 2.5 L at STP (Standard Temperature and Pressure), we can use the ideal gas law and Avogadro's number.

Avogadro's number (N_A) is a fundamental constant representing the number of particles (atoms, molecules, ions) in one mole of substance. Its value is approximately 6.022 × 10^23 particles/mol.

STP conditions are defined as a temperature of 273.15 K (0 °C) and a pressure of 1 atmosphere (1 atm).

First, we need to convert the volume from liters to moles of CO2. To do this, we use the ideal gas law equation:

PV = nRT,

where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

Since we have STP conditions, we can substitute the values:

(1 atm) × (2.5 L) = n × (0.0821 L·atm/(mol·K)) × (273.15 K).

Simplifying the equation:

2.5 = n × 22.4149.

Solving for n (the number of moles):

n = 2.5 / 22.4149 ≈ 0.1116 moles.

Next, we can calculate the number of molecules using Avogadro's number:

Number of molecules = n × N_A.

Number of molecules = 0.1116 moles × (6.022 × 10^23 particles/mol).

Number of molecules ≈ 6.72 × 10^22 molecules.

Therefore, there are approximately 6.72 × 10^22 molecules of CO2 in 2.5 L at STP.

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The oxidation number of reactant Fe is 0 while the  oxidation number of iron in the product is +3

The term redox reaction implies a reaction in which there is an increase in the oxidation number of a specie and the decrease in the oxidation number of another specie.

Now we have the answers as follows;

1) The oxidation number of reactant Fe is 0

2) The oxidation number of reactant oxygen is 0

3) The oxidation number of iron in the product is +3

4) The oxidation number of oxygen in the product is -2

5). Iron is oxidized in the reaction

6) Oxygen is reduced in the reaction

7) The oxidizing agent in this case is the oxygen atom

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The mass of \(O_2\) needed to produce 8.65 x \(10^{23\) atoms of silver is 22.96 grams.

In the given balanced equation, it is stated that 2 moles of \(Ag_2O\) produce 4 moles of Ag and 1 mole of \(O_2\).

First, let's calculate the number of moles of Ag:

8.65 x \(10^{23\) atoms of Ag / (6.022 x \(10^{23\) atoms/mol) = 1.435 moles of Ag

Since 2 moles of  \(Ag_2O\) produce 1 mole of  \(O_2\), the number of moles of  \(O_2\) needed is half of the moles of  \(Ag_2O\).

Number of moles of  \(O_2\)= 1.435 moles of  \(Ag_2O\) / 2 = 0.7175 moles

Now, we'll use the molar mass of  \(O_2\) to find the mass:

Molar mass = 32.00 g/mol

Mass of  \(O_2\) = number of moles × molar mass

                   = 0.7175 moles × 32.00 g/mol = 22.96 g

Therefore, the mass of  \(O_2\) needed to produce 8.65 x \(10^{23\) atoms of silver is 22.96 grams.

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The amount of heat energy absorbed when 200 grams of water are heated from 20 C to 60 C is 33,440 Joules.

To find the amount of heat energy absorbed when 200 grams of water are heated from 20 C to 60 C, we can use the equation Q = mcAT.
First, we need to find the value of m, which is the mass of the water in grams. In this case, it is given as 200 grams.
Next, we need to find the value of AT, which is the change in temperature in degrees Celsius.

This can be calculated by subtracting the initial temperature from the final temperature, which gives us 60 C - 20 C = 40 C.
The specific heat capacity of water, C, is given as 4.18 Joules per gram per degree Celsius.
Now we can plug in the values into the equation:
Q = mcAT
Q = (200 g) x (4.18 J/g°C) x (40°C)
Q = 33,440 J
Therefore, the amount of heat energy absorbed when 200 grams of water are heated from 20 C to 60 C is 33,440 Joules.

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The vapor pressure at 85.0°C of a solution prepared by dissolving 0.300 mol of liquid dibromoethane the vapor pressure at 85.0°C of a solution prepared by dissolving 0.300 mol of liquid dibromoethane is 164.83 torr.

The term vapor pressure is defined as the tendency of a material to change into the vapour state, and it increases with temperature.

For calculating mole fraction of C₂H₄Br₂ as follows

X C₂H₄Br₂ = moles of C₂H₄Br₂ / moles of C₂H₄Br₂ + moles of C₃H₆Br₂

= 0.3 / 0.3 + 1.80

= 0.14

For calculating mole fraction of C₃H₆Br₂ as follows:

XC₃H₆Br₂ =  moles of C₃H₆Br₂ / moles of C₂H₄Br₂ + moles of C₃H₆Br₂

= 1.80 / 2.1

= 0.85

For calculating total vapor pressure as follows:

P total = [ ( 0.14 × 127) + (0.85 × 173) ]

= 17.78 + 147.05

= 164.83 torr

Thus, The vapor pressure at 85.0°C of a solution prepared by dissolving 0.300 mol of liquid dibromoethane the vapor pressure at 85.0°C of a solution prepared by dissolving 0.300 mol of liquid dibromoethane is 164.83 torr.

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The declaration that shows the correct conversion of 170°C to kelvins is 443 K. Thus, the correct option for this question is C.

The conversion of Celcius to kelvin required the utilization of the formula which is as follows:

Sterilization of surgical instruments at 170°C for 1.5 hours helps in the process of elimination of contaminated or unwanted impurities from the surface of the instruments in order to conduct error-free experiments.

According to the question,

The temperature of sterilization is = 170°C.

Now, it is required to convert 170°C into kelvin.

∴ Kelvin = 170°C + 273.15 = 443.15 ≅ 443 K.

Therefore, the declaration that shows the correct conversion of 170°C to kelvins is 443 K. Thus, the correct option for this question is C.

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Answer:

13.3 L

Explanation:

Step 1: Given data

Step 2: Convert P₁ to atm

We will use the conversion factor 1 atm = 1.01325 bar.

3.36 bar × (1 atm / 1.01325 bar) = 3.32 atm

Step 3: Calculate V₂

We will use the combined gas law.

P₁ × V₁/T₁ = P₂ × V₂/T₂

V₂ = P₁ × V₁ × T₂/T₁ × P₂

V₂ = 3.32 atm × 15.0 L × 350 K/298 K × 4.40 atm

V₂ = 13.3 L

Explanation:

H

|

H-C=C-C-OH

| | |

H H H

in this organic compound the functional groups are OH and alkene

prop-2-enol

since it has a double bond, alkene is the functional group. and also it has OH group so hydroxyl group also the other functional group

Answer:

FCC.

Explanation:

Hello,

In this case, since the density is defined as:

\(\rho =\frac{n*M}{Vc*N_A}\)

Whereas n accounts for the number of atoms per units cell (2 for BCC and 4 for FCC), M the atomic mass of the element, Vc the volume of the cell and NA the Avogadro's number. Thus, for both BCC and FCC, the volume of the cell is:

\(Vc_{BCC}=(\frac{4r}{\sqrt{3} } )^3=(\frac{4*0.1345x10^{-7}cm}{\sqrt{3} } )^3=2.997x10^{-23}cm^3\\\\Vc_{FCC}=(2\sqrt{2}r)^{3} =(2\sqrt{2} *0.1345x10^{-7}cm)^3=5.506x10^{-23}cm^3\)

Hence, we compute the density for each crystal structure:

\(\rho _{BCC}=\frac{n_{BCC}*M}{Vc_{BCC}*N_A}=\frac{2*102.9g/mol}{2.337x10^{-23}cm^3*6.022x10^{23}/mol} =14.62g/cm^3\\\\\rho _{FCC}=\frac{n_{FCC}*M}{Vc_{FCC}*N_A}=\frac{4*102.9g/mol}{5.506x10^{-23}cm^3*6.022x10^{23}/mol} =12.41g/cm^3\)

Therefore, since the density computed as a FCC crystal structure matches with the actual density, we conclude rhodium has a FCC crystal structure.

Regards.

Answer:

Orbiter

Explanation:

Space shuttles are made out of three main parts: rocket boosters, a fuel tank, and orbiter (the part that resembles an airplane

Balance the following chemical equations:

1. N2 + 3 H2 → 2 NH3

Ex: Synthesis reaction

2. 2 KClO3 → 2 KCl + 3 O2

Single Replacement reaction

3. 2 NaF + ZnCl2 → ZnF2 + 2 NaCl

Decomposition reaction

4. 2 AlBr3 + 3 Ca(OH)2 → Al2(OH)6 + 6 CaBr2

Double Replacement reaction

5. 2 H2 + O2 → 2 H2O

Combustion reaction

6. 2 AgNO3 + MgCl2 → 2 AgCl + Mg(NO3)2

Synthesis reaction

7. 2 Al + 6 HCl → 2 AlCl3 + 3 H2

Decomposition reaction

8. C3H8 + 5 O2 → 3 CO2 + 4 H2O

Combustion reaction

9. 2 FeCl3 + 6 NaOH → Fe2O3 + 6 NaCl + 3 H2O

Double Replacement reaction

10. 4 P + 5 O2 → 2 P2O5

Synthesis reaction

11. 2 Na + 2 H2O → 2 NaOH + H2

Single Replacement reaction

12. 2 Ag2O → 4 Ag + O2

Decomposition reaction

13. C6H12O6 + 6 O2 → 6 CO2 + 6 H2O

Combustion reaction

14. 2 KBr + MgCl2 → 2 KCl + MgBr2

Double Replacement reaction

15. 2 HNO3 + Ba(OH)2 → Ba(NO3)2 + 2 H2O

Double Replacement reaction

16. C5H12 + 8 O2 → 5 CO2 + 6 H2O

Combustion reaction

17. 4 Al + 3 O2 → 2 Al2O3

Synthesis reaction

18. Fe2O3 + 2 Al → 2 Fe + Al2O3

Single Replacement reaction

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Answer:

The Answer is 100.06c

Explanation:

GradPoint:)

Answer

A. the gain of electrons.

Explanation

Oxidation and reduction are complementary reactions. Oxidation is the process involving with loss of electrons or an increase in oxidation state by a molecule, atom, or ion while reduction is the process of gain of electrons or a decrease in oxidation state by a molecule, atom, or ion.

Hence, the correct answer to your question is option A. the gain of electrons.

Answer:

• Formula: ,Co,, Name: ,Cobalt,.

• Formula: ,C,, Name: ,Carbon,.

• Formula: ,Fe,, Name:, Iron,.

• Formula: ,Au,, Name: ,Gold,.

• Formula: ,KCl,, Name: ,Potassium chloride,.

• Formula: ,CS2,, Name: ,Carbon disulfide,.

• Formula: ,Si,, Name: ,Silicon,.

Explanation:

• Co is an element.

• Carbon is an element.

• Iron is an element.

• Au is an element.

• KCl is a compound with K and Cl. The name has the positive part first (Potassium) and the second part has the name of the negative part (chloride).

• CS2 is a compound with C and 2 S. The name has the number of each element, carbon is 1 so it is just Carbon, and there are 2 sulfurs (disulfide).

• Silicon is an element.

Answer:

Potassium oxide is a metal oxide with formula K2O. It is a potassium salt and a metal oxide.

Explanation: