19. Jorge was driving at 20m/s. He accelerated at a rate of 2m/s² for 10s. How far did he travel during this time?

Answers

Answer 1

Jorge was driving at 20m/s. He accelerated at a rate of 2m/s² for 10s.

So he travel ---m during this time.

Jorge was driving at 20m/s, so speed = 20 units

He accelerated at a rate of 2m/s² so acceleration = 2 units

Time taken by Jorge is 10 units.

We know by Newton's 2nd equation of motion that

S= ut + (1/2)*a*t*t

where S is distance, a is acceleration, u is initial velocity and t is time.

So S=?

Time t = 10

Acceleration a =2

Initial Velocity u = 20

Hence distance travelled by Jorge is S=300 m

Thus Jorge travelled 300m during this time  at speed 20m/s accelerated at a rate of 2m/s² for 10s.

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Related Questions

840 inches to cm show work pls

Answers

1inche =2.54 cm so it is 840*2.54=2032 cm

A high-speed transmission medium that uses a protected string of glass to transmit beams of light.a. Trueb. False

Answers

A high-speed transmission medium that uses a protected string of glass to transmit beams of light.

Correct answer is, True.

This refers to fiber optic cables, which use glass or plastic fibers to transmit light signals at high speeds and are protected by a sheath or jacket., faster speeds, and resistance to electromagnetic interference.

This statement accurately describes fiber-optic cables, which are high-speed transmission mediums that use glass or plastic fibers to transmit light signals. Fiber-optic cables have several advantages over traditional copper cables, including higher bandwidth.

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an object is placed 171 cm to the left of a positive lens of focal length 150 cm. a positive lens, of focal length -100 cm is placed to the right of the first lens with a separation of 166 cm. calculate the position of the final image relative to the second lens. (report a positive number if the image is to the right of the second lens, and a negative number if it is to the left of the second lens. assume both lenses are thin spherical lenses).

Answers

The position of the final image relative to the second lens is approximately 1048.41 cm to the right of the second lens.

To solve this problem, we can use the lens formula and the concept of lens combinations.

Given:

Distance of the object from the first lens (u1) = -171 cm (since it is to the left)

Focal length of the first lens (f1) = 150 cm (positive, since it is a positive lens)

Focal length of the second lens (f2) = -100 cm (negative, since it is a negative lens)

Separation between the two lenses (d) = 166 cm

To calculate the position of the final image relative to the second lens, we need to find the distance of the image from the second lens (v2).

Using the lens formula for the first lens:

1/f1 = 1/v1 - 1/u1

Substituting the given values:

1/150 = 1/v1 - 1/(-171)

1/150 = 1/v1 + 1/171

Multiplying through by 150v1 * 171:

171v1 = 150 * 171 + 150v1

171v1 - 150v1 = 150 * 171

21v1 = 150 * 171

v1 = (150 * 171) / 21

v1 ≈ 1225 cm

Now, to find the distance of the image from the second lens (v2), we can use the lens formula for the second lens:

1/f2 = 1/v2 - 1/u2

Since the second lens is to the right of the first lens, the distance from the second lens to the image is the object distance for the second lens (u2), which is the distance between the lenses minus the distance of the first image from the first lens:

u2 = d - v1

u2 = 166 cm - 1225 cm

u2 ≈ -1059 cm

Substituting the given values:

1/(-100) = 1/v2 - 1/(-1059)

-1/100 = 1/v2 + 1/1059

Multiplying through by (-100) * (1059):

-1059 = -100 * 1059 + 100v2

-1059 + 105900 = 100v2

105900 - 1059 = 100v2

104841 = 100v2

v2 = 104841 / 100

v2 ≈ 1048.41 cm

Therefore, the position of the final image relative to the second lens is approximately 1048.41 cm to the right of the second lens.

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What is the critical angle for glass when the refractive index is 1.45

Answers

Answer:43.6°

Explanation:

Refractive index=n=1.45

Critical angle=c

n=1/sinc

1.45=1/sinc

Cross multiply

1.45sinc=1

Divide both sides by 1.45

(1.45sinc)/1.45=1/1.45

sinc=0.6897

c=sin(inverse)(0.6897)

c=43.6°

Critical angle is 43.6°

why is a layer of pollution in the air more visible in winter than summer

Answers

Answer:

During winters the planetary boundary layer is thinner as the cooler air near the earth's surface is dense. The cooler air is trapped under the warm air above that forms a kind of atmospheric 'lid'. This phenomenon is called winter inversion

Explanation:

trong trường hợp nào các vật rơi tư do với cùng một gia tốc g ?

Answers

I don’t speak that language lol

Place a chair against a wall so it cannot be slid back. Have one student sit in the chair
with their feet flat in front of the chair. Place your thumb on their forehead and ask
them to stand up. Why does the student struggle to stand

Answers

We will see that the student struggles to stand because of the angle that his/her legs form and because of the downward force that your thumb makes.

Why does this make it harder to stand up?

First, think that when you stand up, your legs (and also your abdomen) are lifting a lot of weight. When the student is in the given situation two things happen.

1) The thumb in his/her head causes a downward force when the student tries to stand, making it harder for the legs and the abdomen to lift the weight.

2) By not allowing the chair to move, the student must make this force when his/her legs are forming a 90° angle, because of this angle the force needed to lift the weight is larger.

So for these two reasons, the student will struggle to stand.

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A wave along a guitar string has a frequency of 540 Hz and a wavelength of 2.5 meters. What is the speed of the wave?

Answers

I believe this is the answer try it out
A wave along a guitar string has a frequency of 540 Hz and a wavelength of 2.5 meters. What is the speed

what is the work done when a 400.n force is use to lift a 400.n object 3.5 meters strait up

Answers

Answer:

i think it's 1400

Explanation:

w = Force x displacement

w = 400 x 3.5

What is the maintenance of a consistent internal environment?

OA) mitosis

OB) meiosis

OC) homeostasis

OD) photosynthesis​

Answers

The correct answer is C. Homeostasis.

How are reflection and transmission wave interactions the same?

Answers

Reflection and refraction are both wave behaviors that occur when a wave that is traveling through a medium hits the boundary of that medium. Reflection and refraction both change the behavior of the wave by changing its direction and/or changing the speed at which it is traveling

What is the force of a 15kg car accelerating at 10m/s2?

Answers

Answer:

150 N

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

mass = 15 kg

acceleration = 10 m/s²

Force = 15 × 10 = 150

We have the final answer as

150 N

Hope this helps you

The mass of a newborn baby's brain has been found to increase by about 1.6 mg perminute. (a) How much does the brain's mass increase in one day?

Answers

ANSWER

2304 mg

EXPLANATION

The rate is given in mg per minute. To find how much the brain's mass increases in one day we have to find how many minutes are in a day.

Assuming that a day has 24 hours and 1 hour has 60 minutes:

\(24h\cdot\frac{60\min}{1h}=1440\min \)

One day has 1440 minutes. Then, in one day the brain's mass increases:

\(1.6mg/\min \cdot1440\min =2304mg\)

The newborn baby's brain's mass increases 2304 mg in one day.

what equation do you use to calculate force from work to distance

Answers

Answer:

Work can be calculated with this equation: Work = Force x Distance. The SI unit for work is the Newton meter (N m). One joule equals the amount of work that is done when 1 N of force moves an object over a distance of 1 m.

Explanation:

Los músicos de una sinfónica siempre ""calientan"" sus instrumentos de viento soplándolos antes de un concierto. ¿Para qué sirve esto?

Answers

El calentamiento del instrumento viento antes de un concierto asegura que todos los instrumentos estén afinados y existan un mejor sonido, debido al cambio de frecuencia del instrumentos por los cambios de velocidad del aire debido al cambio de temperatura

Los instrumentos musicales trabajan por procesos de resonancia, ya sean de cuerda o viento; en los instrumentos de viento la frecuencia que emites esta dada por la relación  

                   fₙ = \(n \ \frac{v_s}{2L}\)    n = 1, 2, 3, ...

Donde f es la frecuencia emitida, L la longitud del tubo n es una constante entera y v_s es la velocidad del sonido

La velocidad del sonido en el aire depende de la temperatura del aire, según la relacion          

               vs = vo + 0,6 T  

Donde v₀ es la temperatura del aire a 0ºC, v₀ = 331 m/s y T la temperatura en grados centígrados.

De esta dos expresiones podemos ver que la frecuencia que emite el instrumento de viento depende  de la temperatura del aire, además en los instrumentos con boquilla la frecuencia de resonancia de la boquilla también depende de la temperatura de la boquilla que por ser liviana cambia fácilmente.

En conclusión el calentamiento del instrumento antes de un concierto asegura que todos los instrumentos estén afinados y existan un mejor sonido, debido al cambio de frecuencia del instrumentos por los cambios de velocidad del aire debido al cambio de temperatura

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A person applies a 132 N force to a 83.3
kg sled resting on frictionless ice. At what
rate will the sled accelerate?​

Answers

Answer: 1.58 m/s^2

Explanation:

Given the following :

Applied force = 132 N

Mass of sled = 83.3 kg

Rate of acceleration of sled =?

F = mass × acceleration ( Newton's 2nd law of motion)

F = Net force

Inputing the values :

F = mass × acceleration

132 = 83.3 × acceleration

acceleration = 132 / 83.3

Acceleration = 1.5846338

Acceleration = 1.58 m/s^2

what has more momentum a large truck stopped at a stop sign or a motorcycle moving down the road.

Answers

I'm pretty sure it's"a motorcycle moving down the road."The truck isn't moving so the truck cannot have momentum.Momentum is basically "mass in motion."Please let me know if I am wrong.

True or False: (2 points) If a scientist finds evidence that contradicts a hypothesis, law, or principle, then it is their choice whether to change the hypothesis, law, or principle.​

Answers

Answer:

True

Explanation:

A hypothesis is an educated guess, it does not have to be right.

when light of wavelength 350 nm falls on a potassium surface, electrons are emitted that have a maximum kinetic energy of 1.31 ev. a) what is the work function of potassium? b) what is the cutoff wavelength of potassium? c) what is the threshold frequency for potassium?

Answers

a. The work function of potassium is 3.45 x \(10^{-19}\) J.

b. The cutoff wavelength of potassium is 573 nm.

c. The threshold frequency for potassium is 5.21 x \(10^{14}\) Hz.

a) To find the work function of potassium, we can use the equation:

the kinetic energy of the emitted electron = energy of the photon-work function

The energy of a photon can be calculated using the equation:

energy of a photon = Planck's constant x speed of light / wavelength

where Planck's constant = 6.626 x \(10^{-34}\) Joule seconds, and the speed of light = 3.00 x 10^8 m/s.

Substituting the given values, we get:

energy of a photon = (6.626 x \(10^{-34}\) J s) x (3.00 x \(10^8\) m/s) / (350 x \(10^{-9}\) m)

= 5.67 x \(10^{-19}\) J

Now, we can use the first equation to find the work function:

work function = energy of the photon - kinetic energy of the emitted electron

work function = (5.67 x \(10^{-19}\) J) - (1.31 eV x 1.60 x \(10^{-19}\) J/eV)

= 3.45 x \(10^{-19}\) J

Therefore, the work function of potassium is 3.45 x \(10^{-19}\) J.

b) The cutoff wavelength is the longest wavelength of light that can eject an electron from the metal surface. This occurs when the energy of the photon is just enough to overcome the work function of the metal.

Using the equation for the energy of a photon, we can rearrange it to find the cutoff wavelength:

energy of a photon = Planck's constant x speed of light / wavelength

wavelength = Planck's constant x speed of light/energy of a photon

Substituting the work function as the energy of the photon, we get:

cutoff wavelength = Planck's constant x speed of light / work function

cutoff wavelength = (6.626 x \(10^{-34}\) J s) x (3.00 x \(10^8\) m/s) / (3.45 x \(10^{-19}\) J)

= 573 nm

Therefore, the cutoff wavelength of potassium is 573 nm.

c) The threshold frequency is the minimum frequency of light that can eject an electron from the metal surface. This can be calculated using the equation:

threshold frequency = work function / Planck's constant

Substituting the given values, we get:

threshold frequency = 3.45 x \(10^{-19}\) J / 6.626 x 10^-34 J s

= 5.21 x \(10^{14}\) Hz

Therefore, the threshold frequency for potassium is 5.21 x \(10^{14}\) Hz.

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The iclicker student response system operates at a frequency of approximately 900 MHz (900x10^6 Hz). What is the approximate wavelength of the EM wave produced by the iclicker?

Answers

The approximate wavelength of the EM wave produced by the iclicker is 0.333 meters (or 33.3 centimeters).

The wavelength of an electromagnetic (EM) wave can be calculated using the formula:

wavelength = speed of light / frequency

where the speed of light is approximately 3x10^8 meters per second.

Using this formula, we can calculate the wavelength of the EM wave produced by the iclicker as:

wavelength = (3x10^8 m/s) / (900x10^6 Hz)

wavelength = 0.333 meters

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g in light of this result that you derive, if you read publications in field a and field b, which field's publications have higher chance to be true? field a. field b.

Answers

Field B may have a higher chance of having low statistical power and thus a higher rate of false positives.

The result suggests that scientific fields with low statistical power have a higher chance to have a high rate of false positives, indicating that their findings are less likely to be true.

On the other hand, Field A, which has a thorough background knowledge, a small community of researchers, and good ways of testing hypotheses, may have a higher likelihood of having a higher statistical power, resulting in a lower rate of false positives and more reliable publications. However, this is not to say that all publications in Field A are true, as individual studies can still have their limitations and potential biases. It is always important to critically evaluate the evidence and findings presented in scientific publications.

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A student throws a 0.22 kg rock horizontally at 20.0 m/s from 10.0 m above the ground. Find the initial kinetic energy of the rock.

Answers

Answer:

44J

Explanation:

Given parameters:

Mass of rock  = 0.22kg

Initial velocity  = 20m/s

Distance moved  = 10m

Unknown:

Initial kinetic energy of the rock  = ?

Solution:

To solve this problem, we need to understand that kinetic energy is the energy due to the motion of a body.

It is mathematically expressed as;

     Kinetic energy  = \(\frac{1}{2}\) m v²

m is the mass

v is the velocity

   Kinetic energy  =  \(\frac{1}{2}\) x 0.22 x 20²   = 44J

The period of a simple pendulum of length 1m on a massive planet is 1 sec. What is the acceleration due to gravity on that planet?

Answers

The period of a simple pendulum of length 1m on a massive planet is 1 sec. The acceleration due to gravity on that planet is 39.48 m/s^2.

A simple pendulum's period is given by:

T = 2π √(L/g)

Where T is the pendulum's period, L is its length, and g is the acceleration due to gravity.

In this scenario, the pendulum's period is one second and its length is one metre.

So, from above equation, we have:

1 = 2π √(1/g)

Squaring both sides, we get:

1^2 = (2π)^2 (1/g)

Simplifying, we get:

g = (4π^2)/1 = 39.48 m/s^2

Therefore, the acceleration due to gravity on the massive planet is 39.48 m/s^2.

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A 4.5 kg bucket of water is raised from a well by a rope. The acceleration of gravity is 9.81 m/s 2 . If the upward acceleration of the bucket is 4.9 m/s2 , find the force exerted by the rope on the bucket of water. Answer in units of N.

Answers

Answer:

The force exerted by the rope on the bucket of water is 66.195 N.

Explanation:

Given;

mass of the bucket, m = 4.5 kg

acceleration of gravity, g = 9.81 m/s²

upward acceleration of the bucket, a = 4.9 m/s²

The upward force applied on the bucket by the rope is calculated as;

F = ma + mg

F = m(a + g)

F = 4.5(4.9 + 9.81)

F = 4.5(14.71)

F = 66.195 N

Therefore, the force exerted by the rope on the bucket of water is 66.195 N.

if the velocity of a train starts from rest is 72km/h(20m/s) after 5 minutes, find out its acceleration and the distance travelled by the train in this time

Answers

Explanation:

Convert the time to seconds : 5minutes × 60 = 300seconds

Acceleration = Velocity / Time

Acceleration = 20m/s / 300s

Acceleration = 0.067m/s²

Distance = Velocity × Time

Distance = 20m/s × 300seconds

Distance = 6000m

Photos A and B both show the same field of view containing a star-forming molecular cloud. One of the photos was taken in visible light and the other in infrared light. Which one is the visible-light photo, and how do you know?

Answers

Hello. You did not present the photos to which the question refers, which makes it impossible for your question to be answered. However, I will try to help you in the best possible way.

Your question informs us that the photos are of a star-forming molecular cloud. The molecular cloud has dust, especially when the star is forming. In this case, we must keep in mind that in photos taken in visible light, the dust is able to appear, especially in space, where this dust would not reflect light, unlike the star in formation. In this case, we can conclude that in the case of the photo taken in visible light, we could see the molecular cloud as a dark spot, due to the dust. However, it would not be possible to view it in a photo taken with infrared light.

Which lists three organic biological molecules?

carbohydrates, salts, metals
salts, proteins, minerals,
proteins, lipids, carbohydrates
lipids, metals, minerals

Answers

Answer:

carbohydrates , minerals - lime coal

Answer:

its not b!!!!!!

Explanation:

What do you predict will happen to the brightness of the bulb as you turn the dial on the power supply and increase the voltage from zero? explain

Answers

As the voltage from the power supply is increased, the brightness of the bulb will also increase as a result of the increased flow of current through the filament, which causes it to emit more light.

How does increasing voltage affect the brightness of the bulb in the circuit?

I predict that the brightness of the bulb will increase as the voltage from the power supply is increased, because the increase in voltage will result in an increase in current flowing through the bulb, which will cause it to produce more light.

This is because the brightness of the bulb is directly related to the power dissipated in the bulb, which is equal to the product of the voltage across the bulb and the current flowing through it, according to the relationship P = VI. As the voltage increases, the current flowing through the bulb will also increase, resulting in a brighter bulb.

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The spectra of most galaxies show redshifts. This means that their spectral lines Group of answer choices always are in the red part of the visible spectrum. have wavelengths that are longer than normal. have a higher intensity in the red part of the spectrum. have wavelengths that are shorter than normal.

Answers

have a higher intensity in the red part of the spectrum

Because of the Doppler effect, the spectra of most galaxies show redshifts. This means that their spectral lines Group of answer choices always are in the red part of the visible spectrum

Most galaxies' spectra have been redshifted, which means that their spectral lines are now pushed away from their normal or rest wavelengths and towards longer wavelengths. When an object travels away from an observer, the Doppler effect causes the shift phenomenon.

The Big Bang hypothesis and the concept of the expanding universe, show that galaxies are moving away from us, observed from the redshift lines.

The waves' apparent wavelengths shift as a result, changing the color of light waves or the pitch of sound waves.

Hence, because of the Doppler effect, the spectra of most galaxies show redshifts. This means that their spectral lines Group of answer choices always are in the red part of the visible spectrum.

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I am a change in movement cause by unbalanced forces what am I?

Answers

If I am a change in momentum cause by unbalanced forces, then i am a force. force is change in a momentum.

Momentum is defined as product of mass and velocity of the body. It is denoted by letter p and it is expressed in kg.m/s. Mathematically p = mv. it discuss the moment of the body. body having zero mass or velocity has zero momentum. The dimensions of the momentum is [M¹ L¹ T⁻¹].

The rate of change of momentum is a force applied on it. this force is unbalanced force which is responsible for the motion of the object.

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