189 is 90% of what number

Answer: 50

Step-by-step explanation: hope this helpss

The total length of the fence is 24 meters. Then the total cost of the fence will be £30.72.

Given that:

Rate, r = £1.28 per metre

The length of the fence is calculated as,

P = 10 + 6 + 8

P = 24 meters

Then the total cost of the fence will be calculated as,

Total cost = P x r

Total cost = 24 x £1.28

Total cost = £30.72

The total length of the fence is 24 meters. Then the total cost of the fence will be £30.72.

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The missing diagram is given below.

write the sum 6 8 10 12 14 16 18 20 22 24 using sigma notation.

The sum 6 8 10 12 14 16 18 20 22 24 using sigma notation with the lower limit of summation as 1 is given as: ∑(2n + 4) = 6 + 8 + 10 + 12 + 14 + ...

The sum 6 8 10 12 14 16 18 20 22 24 using sigma notation is given below: First, we need to understand what is meant by Arithmetic Progression (AP). An arithmetic progression (AP) is a sequence of numbers in which the difference between any two successive terms is constant. This constant difference is called the common difference. The formula for the nth term of an arithmetic progression is given as: an = a + (n - 1)d

where a is the first term, d is a common difference, and n is the term number. Now, to write the sum 6 8 10 12 14 16 18 20 22 24 using sigma notation, we first need to find the common difference. The common difference, d = 8 - 6 = 2We can now write the series using the nth term formula:6, 6+2, 6+2+2, 6+2+2+2, ...6, 8, 10, 12, ...The nth term of this series is given as: an = a + (n - 1)d= 6 + (n - 1)2= 2n + 4Now, we can write the sum using sigma notation as:

∑(2n + 4) where the lower limit of summation depends on which term we want to stop at. For example, if we want to stop at the 5th term (i.e. the sum of the first 5 terms), then the lower limit of summation would be 1. Therefore, the sum would be: ∑(2n + 4) = (2(1) + 4) + (2(2) + 4) + (2(3) + 4) + (2(4) + 4) + (2(5) + 4)= 6 + 8 + 10 + 12 + 14= 50

So, the sum 6 8 10 12 14 16 18 20 22 24 using sigma notation with the lower limit of summation as 1 is given as: ∑(2n + 4) = 6 + 8 + 10 + 12 + 14 + ...

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Answer:

x = 100

Step-by-step explanation:

This problem can be solved if you ignore line DC.

We know that angle FED + angle DEB = angle FEB = 100

Now, if you ignore line DC, you realize that FEB and AEG are vertical angles(opposite angles of 2 intersecting lines). This means that FEB is actually congruent to AEG.

So therefore:

x = AEG = FEB = 100

Answer:

joe mama

Step-by-step explanation:

The value of angle 1 in the parallelogram is given as 26 degrees

Let us call the vertices of the angles as ∠A, ∠B, ∠C and ∠D

we have ∠ A represented as 1 and 2

∠B as 128

∠C as 3 and 4

∠D is unnamed

Using the property of parallelogram, we can see that

∠ A is opp ∠C hence they are equal

∠B = ∠D = 128 because they are opposite

Another property says that the sum of adjacent angles in a parallelogram are = 180 degrees they are supplementary

such that

∠ A + 128 = 180

∠ A = 180 - 128

∠ A = 52 degrees

∠ A is made up of two angles 1 and 2 that are equal

hence 52 / 2

= 26

Proof: the sum of internal angle in a parallelogram is 360 degrees

∠ A = ∠ C = 56 degrees because they are opposite

56 + 56 + 128 + 128

= 360 degrees

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Hello!

To solve this exercise, we must use the formula below:

Let's rewrite the information contained in the exercise as ordered pairs:

• (x1, y1) = (2002, 23,400)

• (x2, y2) = (2006, 27,800)

Knowing it, we can replace the values in the formula and solve it:

The rate is 1100 people per year.

Answer:A

Step-by-step explanation:

Answer:

Similar!

Step-by-step explanation:

Hope this helps!

A Treaty is important because it settled downs the global issues with diplomatic approach.

A treaty is an agreement between two countries with the set of rules defining the responsibilities and obligations for the countries.

Some issues which are not only important for the country but also for the issues which need attention globally.  

A Treaty can be made for any purpose. It is stabilizes the relationship between two countries in a diplomatic manner without the unnecessary loss of resources and valuable human life.

A Treaty is a long term solution for the problems.

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one angstrom, symbolized as å, is 10-10 m, so

1 cm^3 = 10^24 angstrom^3

The angstrom, sometimes known as a ångström, is a metric length unit equal to 10^(-10)m, or one ten billionth of a metre, one hundred millionth of a centimeter, 0.1 nanometer, or one hundred picometres. The Swedish alphabet letter serves as its symbol. The Swedish physicist Anders Jonas Angström is commemorated by the unit's name.

The length of an object is measured in centimeters, which are metric units of measurement. The abbreviation is cm.

100 centimeters make up a meter.

One centimeter is equal to ten millimeters.

so one angstrom is 10^-10 m, or 10^-8 cm, so there are 10^8 angstroms in 1 cm.

1 cm^3 = 1 cm 1 cm * 1 cm

1 cm^3 = 10^8 10^8 10^8 angstrom^3

1 cm^3 = 10^24 angstrom^3

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Answer:

10

Step-by-step explanation:

So lets say y=100

Then the equation would be 100=5x+50

If you do the linear equation it is x=10

The first derivative of the function y = e^x at x = 5 can be estimated using centered difference approximations. The resulting approximate values for the first derivative are 148.4131 (O(h^2)) and 148.4132 (O(h^4

For O(h^2), the centered difference formula for the first derivative is:

f'(x) ≈ (f(x + h) - f(x - h)) / (2h)

Substituting x = 5 and h = 0.1 into the formula, we get:

f'(5) ≈ (f(5 + 0.1) - f(5 - 0.1)) / (2 * 0.1)

      = (e^(5 + 0.1) - e^(5 - 0.1)) / (2 * 0.1)

      ≈ (e^5.1 - e^4.9) / 0.2

Calculating this expression yields the approximate value of the first derivative with O(h^2) as 148.4131.

For O(h^4), the centered difference formula for the first derivative is:

f'(x) ≈ (-f(x + 2h) + 8f(x + h) - 8f(x - h) + f(x - 2h)) / (12h)

Substituting x = 5 and h = 0.1 into the formula, we get:

f'(5) ≈ (-f(5 + 0.2) + 8f(5 + 0.1) - 8f(5 - 0.1) + f(5 - 0.2)) / (12 * 0.1)

      = (-e^(5 + 0.2) + 8e^(5 + 0.1) - 8e^(5 - 0.1) + e^(5 - 0.2)) / 1.2

      ≈ (-e^5.2 + 8e^5.1 - 8e^4.9 + e^4.8) / 1.2

Calculating this expression yields the approximate value of the first derivative with O(h^4) as 148.4132.

Centered difference approximations are numerical methods used to estimate derivatives of a function. The O(h^2) formula for the first derivative is derived from Taylor series expansions and provides an approximation with an error term proportional to h^2. The O(h^4) formula is an improvement over the O(h^2) formula and has an error term proportional to h^4.

To estimate the first derivative at x = 5 for h = 0.1 using the O(h^2) formula, we evaluate the function at x + h and x - h, and then divide the difference by 2h. This gives us the slope of the tangent line at x = 5, which approximates the first derivative. The same process is followed for the O(h^4) formula, but it involves evaluating the function at x + 2h, x - 2h, and using appropriate coefficients to calculate the weighted average.

In this case, for both O(h^2) and O(h^4), the function y = e^x is evaluated at x = 5 + h, 5 - h, 5 + 2h, and 5 - 2h, with h = 0.1. The difference between function values at these points is divided by the corresponding factor to obtain the approximation for the first derivative.

The resulting approximate values for the first derivative are 148.4131 (O(h^2)) and 148.4132 (O(h^4

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The probability of Thuy rolling a 4 exactly 2 times is 1/6 × 1/6 × 5/6 × 5/6 × 5/6 × 5/6 × 5/6 × 5/6 = 5⁵/6⁷

We know that:

Thuy rolls a number cube 7 times,

so the total outcomes are: 6.

Also, it is asked to find the probability of rolling a 4 exactly 2 times.

So it could be done by the method that:

1/6 × 1/6 × 5/6 × 5/6 × 5/6 × 5/6 × 5/6 × 5/6,

where 1/6 denotes the probability of rolling a 4 and 5/6 denotes the probability of rolling a number other than 4

therefore we know that, the probability of rolling a 4 exactly 2 times is 1/6 × 1/6 × 5/6 × 5/6 × 5/6 × 5/6 × 5/6 × 5/6 = 5⁵/6⁷

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Around 433.63 would be the correct answer

Certify Completion Icon Tries remaining: 3 A high school has 52 players on the football team. The summary of the players' weights is given in the box plot. The median weight of the players on the football team is 160 pounds.

The box plot shows that the median weight of the players is the middle value of the distribution. In this case, the median weight is halfway between the 26th and 27th players, which is 160 pounds.

The box plot also shows that the minimum weight of the players is 150 pounds and the maximum weight is 212 pounds. The interquartile range, which is the range of the middle 50% of the data, is 20 pounds.

In conclusion, the median weight of the players on the football team is 160 pounds. This means that half of the players on the team weigh more than 160 pounds and half of the players weigh less than 160 pounds.

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We can conclude that gcd(a, b) divides 15 if and only if there exist integers s and t such that as + bt = 15.

If there are integers s and t such that as + bt = 15, then we can conclude that gcd(a, b) divides 15. This is known as Bézout's identity, which states that for any two integers a and b, there exist integers s and t such that as + bt = gcd(a, b).

To see why this is true, consider the set of all linear combinations of a and b, that is, the set {ax + by : x, y are integers}. This set contains all multiples of gcd(a, b) since gcd(a, b) divides both a and b.

Therefore, gcd(a, b) is the smallest positive integer that can be expressed as a linear combination of a and b.

Now, if as + bt = 15, then 15 is a linear combination of a and b, which means that gcd(a, b) divides 15.

Conversely, if gcd(a, b) divides 15, then we can find integers s and t such that as + bt = gcd(a, b), and we can scale this equation to obtain as' + bt' = 15, where s' = (15/gcd(a, b))s and t' = (15/gcd(a, b))t.

Therefore, we can conclude that gcd(a, b) divides 15 if and only if there exist integers s and t such that as + bt = 15.

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Answer:

\(81 {d}^{4} {e}^{7} \)

Step-by-step explanation:

Use properties of degrees:

1. When multiplying different degrees on one term, the degree indicators must be multiplied, for example:

\(( { {x}^{2}) }^{3} = {x}^{2 \times 3} = {x}^{6} \)

2. When dividing like terms (with the same base) with different degrees, the degree indicators must be subtracted, for example:

\( \frac{ {x}^{5} }{ {x}^{2} } = {x}^{5 - 2} = {x}^{3} \)

3. When squaring a negative term in parentheses, the minus is eliminated, for example:

\(( { - 3x})^{2} = 9 {x}^{2} \)

.

\( \frac{ {(( { - 3d})^{2} \times {e}^{4} )}^{3} }{ {9d}^{2} \times {e}^{5} } = \frac{729 {d}^{6} \times {e}^{12} }{9 {d}^{2} \times {e}^{5} } = 81 {d}^{4} \times {e}^{7} \)

Answer:

y = -x + 9

Step-by-step explanation:

Slope = -1

Y-intercept = (0, 9)

Answer: i would say the answer is 90 degrees

Step-by-step explanation:

The area of a circle is 36π, so the correct option of this question is c.

The space across a circle through the center.

To determine the area of the circle by the formula.

Area = πr², where r is the radius of a circle.

Given:

The diameter of a circle is 12.

To find the the area of a circle.

Radius = diameter/2 = 1/2 = 6

Area = πr² =π6×6= 36π

Therefore, the area of a circle is 36π.

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You will require 3 1/3 cups of flour for 2 cups of peanuts.

The ratio is defined as a relationship between two quantities, it is expressed as one divided by the other.

For 5 cups of flour, a recipe calls for 3 cups of peanuts.

Let x cups of flour, a recipe calls for 2 cups of peanuts.

As per the situation, we can write the ratio would be as:

5 cups of flour : 3 cups of peanuts = x cups of flour : 2 cups of peanuts

⇒ 5/3 = x/2

Cross-multiplying and we get

⇒ x = 10/3

⇒ x = 3 1/3

Thus, you will require 3 1/3 cups of flour.

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The image of the transformation is missing so i have attached it;

Answer:

Option C - The transformation is not isometric because the lengths did not remain the same.

Step-by-step explanation:

Transformation means that it preserves the length of  the original figure which means that it is a distance preserving transformation.

Now, from the image of the question attached, the two figures can be said to be isometric if they are congruent.

Now, for the figure displaying the transformation we can see that the size of the original figure has changed.

We can see that the figure is dilated by a scale factor of 2 as each of the sides of the polygon which is a trapezoid is increased by a factor of 2.

Due to the fact that the lengths of sides of the original figure and transformed figure are are not same, we can say that the lengths are not preserved.

Thus, the transformation is not isometric because the lengths did not remain the same.

Answer:

C : It is not isometric because the side lengths did not remain the same.

Credits go to the person above me.

;)

Step-by-step explanation:

EDGE 2021

Answer:

(-1, -2.5)

Step-by-step explanation:

(3, 0) is the midpoint between (2, 2) and (4, -2)

(-5, -5) (3, 0) the midpoint between these two points is

(-5 + 3) / 2 = -1, (-5 + 0) / 2 = -2.5

We are given the dot-plots of sixth-grade test scores and seventh-grade test scores.

Let us first find the median of the two test scores.

Recall that the median is the value that divides the distribution into two equal halves.

Sixth Grade Geograph Test Scores:

From the dot-plot, we see that 11 is the median test score since it divides the distribution into two equal halves.

Median = 11

Seventh Grade Geograph Test Scores:

From the dot-plot we see that 13 is the median test score since it divides the distribution into two equal halves.

Median = 13

Therefore, the median score of the seventh-grade class is 2 points greater than the median score of the sixth-grade class.

Now let us find the interquartile range which is given by

Seventh Grade Geograph Test Scores:

The upper quartile is given by

At the 10th position, we have a test score of 13

The lower quartile is given by

At the 3rd position, we have a test score of 11

So, the interquartile range is

Sixth Grade Geograph Test Scores

The upper quartile is given by

At the 9th position, we have a test score of 10

The lower quartile is given by

At the 3rd position, we have a test score of 8

So, the interquartile range is

So, the IQR is the same as the difference between medians.

Therefore, the median score of the seventh-grade class is 2 points greater than the median score of the sixth-grade class. The difference is the same as the IQR

Hence, the correct answer is option B

Answer:

the smallest prime factor of 52 is 2

Step-by-step explanation:

What is the smallest prime that is a factor of 52?

52 = 4*13, or 52 = 2*2*13.  So the smallest prime factor of 52 is 2.