Answer:
472.25
Step-by-step explanation:
1,889 divided by 4 = 472.25
you need a calculator haha
472.25
Frame zero, F0. is the fixed global frame. For each of
the cases below find T 1: 0
(a) F1 is rotated by an angle θ about zo.
(b) F1 is rotated by θ about xo.
(c) F1 is rotated by θ about yo.
(a) `T1:0 = [cos150 sin150 0 0; -sin150 cos150 0 0; 0 0 1 0; 0 0 0 1]`
(b) `T1:0 = [1 0 0 0; 0 cos150 sin150 0; 0 -sin150 cos150 0; 0 0 0 1]`
(c) `T1:0 = [cos150 0 -sin150 0; 0 1 0 0; sin150 0 cos150 0; 0 0 0 1]`
Given that Frame zero, F0 is the fixed global frame.
For each of the cases below find T1
Case (a)
F1 is rotated by an angle θ about zo.
Let O be the origin of the fixed frame F0, A be the origin of the frame F1 and α be the angle between the x-axis of the frame F0 and the projection of the x-axis of the frame F1 on the xy plane of the frame F0.
Let l, m, n be the direction cosines of the vector from O to A, expressed in F0.
The content-loaded frame zero F0 is the fixed global frame, which means that the vectors i, j, k representing the x, y, and z-axis of F0 are fixed and cannot be transformed.
Therefore, the transformation matrix T1:0
in this case is:
`T1:0 = [l1 m1 n1 0; l2 m2 n2 0; l3 m3 n3 0; 0 0 0 1]`
Case (b)
F1 is rotated by θ about xo.
Let β be the angle between the y-axis of F0 and the projection of the y-axis of F1 on the yz plane of F0.
Let γ be the angle between the z-axis of F0 and the projection of the z-axis of F1 on the zx plane of F0.
The transformation matrix T1:0
in this case is given by:
`T1:0 = [1 0 0 0; 0 cosθ sinθ 0; 0 -sinθ cosθ 0; 0 0 0 1]`
Case (c)
F1 is rotated by θ about yo.
Let β be the angle between the y-axis of F0 and the projection of the y-axis of F1 on the yz plane of F0.
Let γ be the angle between the z-axis of F0 and the projection of the z-axis of F1 on the zx plane of F0.
The transformation matrix T1:0
in this case is given by:
`T1:0 = [cosθ 0 -sinθ 0; 0 1 0 0; sinθ 0 cosθ 0; 0 0 0 1]`
Thus, the transformation matrix T1:0
for the three cases (a), (b), and (c) are given as follows:
(a) `T1:0 = [cosθ sinθ 0 0; -sinθ cosθ 0 0; 0 0 1 0; 0 0 0 1]`
(b) `T1:0 = [1 0 0 0; 0 cosθ sinθ 0; 0 -sinθ cosθ 0; 0 0 0 1]`
(c) `T1:0 = [cosθ 0 -sinθ 0; 0 1 0 0; sinθ 0 cosθ 0; 0 0 0 1]`
Given θ = 150,
T1:0 for the three cases are:
(a) `T1:0 = [cos150 sin150 0 0; -sin150 cos150 0 0; 0 0 1 0; 0 0 0 1]`
(b) `T1:0 = [1 0 0 0; 0 cos150 sin150 0; 0 -sin150 cos150 0; 0 0 0 1]`
(c) `T1:0 = [cos150 0 -sin150 0; 0 1 0 0; sin150 0 cos150 0; 0 0 0 1]`
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uppose the investigators had made a rough guess of 175 for the value of s before collecting data. what sample size would be necessary to obtain an interval width of 50 ppm for a confidence level of 95%?
To determine the necessary sample size to obtain an interval width of 50 ppm for a confidence level of 95%, we need to use the formula for sample size calculation for estimating a population mean.
The formula for sample size calculation is:
n = (Z * σ / E)^2
n is the sample sizeZ is the Z-score corresponding to the desired confidence levelσ is the standard deviation of the populationE is the desired margin of error (half the interval width)In this case, the desired margin of error is 50 ppm, which means the interval width is 2 * E = 50 ppm. Therefore, E = 25 ppm.
The Z-score corresponding to a 95% confidence level is approximately 1.96.
Given that the investigators made a rough guess of 175 for the value of σ (standard deviation) before collecting data.
We can substitute these values into the sample size formula:
n = (1.96 * 175 / 25)^2
Simplifying the calculation:
n = (7 * 175)^2
n = 1225^2
n ≈ 1,500,625
Therefore, a sample size of approximately 1,500,625 would be necessary to obtain an interval width of 50 ppm for a confidence level of 95%.
To obtain an interval width of 50 ppm with a confidence level of 95%, a sample size of approximately 1,500,625 is required. This is calculated using the formula for sample size estimation, considering a desired margin of error of 25 ppm and a standard deviation estimate of 175. The Z-score corresponding to a 95% confidence level is used to determine the sample size.
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Officials at Dipstick College are interested in the relationship between participation in interscholastic sports and graduation rate. The following table summarizes the probabilities of several events when a male Dipstick student is randomly selected.
Event Probability Student participates in sports 0.20 Student participates in sports and graduates 0.18 Student graduates, given no participation in sports 0.82 a. Draw a tree diagram to summarize the given probabilities and those you determined above. b. Find the probability that the individual does not participate in sports, given that he graduates.
a. The tree diagram that summarizes the given probabilities is attached.
b. The probability that the individual does not participate in sports, given that he graduate sis 0.2 = 20%.
How do we calculate?We apply Bayes' theorem to calculate:
Probability (Does not participate in sports if graduates) = (P(Does not participate in sports) * P(Graduates | Does not participate in sports)) / P(Graduates)
The given data include: probability of not participating in sports = 0.02 probability of graduating given no participation in sports = 0.82 probability of graduating = 0.18
Probability (Does not participate in sports if graduates) = (0.02 * 0.82) / 0.18 = 0.036 / 0.18= 0.2
The Tree Diagram| Sports | No Sports |
|-------|--------|
Student participates | 0.18 | 0.62 |
|-------|--------|
Student does not participate | 0.02 | 0.78 |
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Which of the following sets represents the domain of the function shown? (5 points)
{(2, 7}, (15, 13), (21, –4), (24, 18)}
a
{–4, 2, 7, 13, 15, 18, 21, 24}
b
{(7, 2), (13, 15), (–4, 21), (18, 24)}
c
{2, 15, 21, 24}
d
{–4, 7, 13, 18}
Answer:
c {2, 15, 21, 24}
Step-by-step explanation:
The domain is the input values
Domain {2,15,21,24}
25 POINTS!!! Under a dilation centered at the origin, the vertex, (2, 3), of a polygon is moved to the point (−8, −12) . What is the scale factor of the dilation? Enter your answer in simplified form in the box.
325
Step-by-step explanation:
(x+8)2+(y+12)2=235The scale factor of the point will be ( 1 / 4).
What is a scale factor?The scale factor is defined as the proportion of the new image's size to that of the previous image. Dilation is the process of increasing the size of an object while maintaining its shape. Depending on the scale factor, the object's size can be increased or decreased.
Given that under a dilation centered at the origin, the vertex, (2, 3), of a polygon is moved to the point (−8, −12).
The scale factor will be calculated as below:-
Scale factor = ( 2 / 8 ) = ( 1 / 4 )
Therefore, the scale factor of the point will be ( 1 / 4).
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What risks do possibly occur by not performing the qualitative tests in duplicate?
Not performing qualitative tests in duplicate can introduce certain risks and potential issues:
False positives: Without duplicate testing, there is a higher risk of obtaining false positive results. False positives occur when a test incorrectly indicates the presence of a particular characteristic or condition. Duplicate testing helps verify the accuracy and reliability of the results, reducing the chances of false positives.
False negatives: Similarly, not performing qualitative tests in duplicate increases the risk of false negatives. False negatives occur when a test fails to detect a characteristic or condition that is actually present. Duplicate testing provides an additional opportunity to identify any missed detections and reduces the likelihood of false negatives.
Variability and uncertainty: Qualitative tests can be subject to variability due to factors such as sample preparation, test conditions, or interpretation. Duplicate testing helps assess the consistency and reproducibility of the results, providing a measure of confidence and reducing uncertainty.
Quality control issues: Duplicate testing is an essential component of quality control protocols. It helps ensure the reliability and accuracy of the testing process and minimizes the potential for errors or inconsistencies. Not performing duplicate tests can compromise the overall quality control procedures, leading to compromised data and unreliable conclusions.
Validation and reproducibility: Duplicate testing is often required for validation purposes and to demonstrate the reproducibility of results. It helps establish the robustness and reliability of the testing method. Without duplicate testing, it becomes more challenging to validate and reproduce the results, which can undermine the credibility of the findings.
In summary, not performing qualitative tests in duplicate increases the risks of false positives, false negatives, variability, uncertainty, quality control issues, and challenges in validation and reproducibility. Duplicate testing plays a crucial role in ensuring the accuracy, reliability, and validity of qualitative test results.
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A study was designed to compare the attitudes of two groups of nursing students towards computers, Group 1 had previously taken a statistical methods course that involved significant computer interaction Group 2 had taken a statistic methods course that did not use computers. The students' attitudes were measured by administering the Computer Anxiety Rating Scale (CARS). A random sample of 10 nursing students from Group 1 resulted in a mean score of 55.7 with a standard deviation of 7.9. A random sample of 15 nursing students from Group 2 resulted in a mean score of 65.6 with a standard deviation of 6.1. Can you conclude that the mean score for Group 1 is significantly lower than the mean score for Group 2? Let u represent the mean score for Group 1 and 2 represent the mean score for Group 2. Use a significance level of a = 0,05 for the test. Assume that the population variances are equal and that the two populations are normally distributed Step 3 of 4: Determine the decision rule for rejecting the null hypothesis H. Round your answer to three decimal places
To determine the decision rule for rejecting the null hypothesis (H₀: μ1 = μ2) and conclude if the mean score for Group 1 is significantly lower than Group 2, we will perform a two-sample t-test with a significance level (α) of 0.05. Since the problem states that the population variances are equal and the populations are normally distributed, we can proceed with the pooled variance t-test.
Step 3: Determine the decision rule for rejecting the null hypothesis H₀.
First, we need to calculate the degrees of freedom (df). For a pooled variance t-test, df = (n1 - 1) + (n2 - 1), where n1 and n2 are the sample sizes for Group 1 and Group 2, respectively.
\(df = (10 - 1) + (15 - 1) = 9 + 14 = 23\)
Next, we need to find the critical t-value. Since we are testing for a significantly lower mean score in Group 1, we are conducting a one-tailed t-test with α = 0.05 and df = 23.
Using a t-table or calculator, we find the critical t-value to be approximately -1.714.
Thus, the decision rule for rejecting the null hypothesis H₀ is: if the calculated t-value is less than -1.714, we reject H₀ and conclude that the mean score for Group 1 is significantly lower than the mean score for Group 2.
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How do you identify the vertical and horizontal asymptotes for rational functions?
To identify the vertical asymptotes, we have to factor the denominator. For horizontal asymptotes, we compare the degrees of the numerator and denominator.
For rational functions, there are vertical and horizontal asymptotes. To identify the vertical asymptotes, we first have to factor the denominator. After that, we should look for values that make the denominator zero. These values can be found by setting the denominator equal to zero and solving for x. The resulting x values would be the vertical asymptotes of the function.
The horizontal asymptote is the line that the function approaches as x goes towards infinity or negative infinity. For rational functions, the horizontal asymptote is found by comparing the degrees of the numerator and the denominator.
If the degree of the numerator is less than the degree of the denominator, the horizontal asymptote is y = 0. If the degree of the numerator is equal to the degree of the denominator, the horizontal asymptote is y = the ratio of the leading coefficients. If the degree of the numerator is greater than the degree of the denominator, there is no horizontal asymptote.
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There is a 25ft fence, 130 feet away from where the ball was hit. If the ball was hit towards the fence would it be high enough to clear
If the maximum height of the ball is greater than or equal to the height of the fence, then it would clear the fence.
To determine whether the ball hit towards the fence would clear it, we need to use the laws of projectile motion. Assuming the ball was hit at an angle of 45 degrees, we can calculate the maximum height it would reach using the following formula:
h = (\(v^{2}\) * \(sin^{2} \alpha\)) / (2g)
where h is the maximum height, v is the initial velocity, \(\alpha\) is the launch angle, and g is the acceleration due to gravity (9.8 m/\(s^{2}\)).
Since we know the distance the ball traveled (130 feet), we can use the following formula to calculate the initial velocity:
d = \(v^{2}\) * sin(2\(\alpha\)) / g
where d is the distance, v is the initial velocity, \(\alpha\) is the launch angle, and g is the acceleration due to gravity (9.8 m/\(s^{2}\)).
Converting the distance and height to meters (since the formula uses SI units), we have:
d = 130 * 0.3048 = 39.624 m
h = 7.62 m (assuming a 45 degree launch angle)
Using the second formula, we can solve for the initial velocity:
v = \(\sqrt{dg/sin2\alpha }\) = \(\sqrt{39.624*9.8/sin(90)}\) = 28.07 m/s
To determine whether the ball would clear the fence, we need to calculate the height of the fence in meters:
fence_height = 25 * 0.3048 = 7.62 m
If the maximum height of the ball is greater than or equal to the height of the fence, then it would clear the fence. In this case, since the maximum height is 7.62 m and the fence height is also 7.62 m, the ball would just clear the fence if it was hit directly towards it at a launch angle of 45 degrees. However, if the ball was hit at a different angle or with a different initial velocity, the outcome could be different.
Correct Question:
There is a 25ft fence, 130 feet away from where the ball was hit. If the ball was hit towards the fence, would it be high enough to clear the fence?
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let f be the function with derivative given by f'(x) = sin(x2 − 3). at what values of x in the interval −3 < x < 3 does f have a relative maximum?A) -1.732 and 2.478 only B) -2.478 and 1.732 only C) 2.138, 0,and 2.138 D) -2.478 -1.732, 1.732, and 2.478
The interval where the derivative function f'(x) has a relative maximum is -2.478 and 1.732 (B) only.
To find the relative maximum of a function, we need to find the critical points of the derivative function. Critical points are where the derivative function is equal to zero or undefined. In this case, the derivative function is f'(x) = sin(x^2 − 3).
To find the critical points, we need to set the derivative function equal to zero and solve for x:
sin(x² − 3) = 0
x² − 3 = nπ, where n is an integer
x² = nπ + 3
x = ±√(nπ + 3)
We need to find the values of x that are in the interval −3 < x < 3. By plugging in different values of n, we can find the critical points in this interval:
n = 0: x = ±√3 ≈ ±1.732
n = 1: x = ±√(π + 3) ≈ ±2.478
n = 2: x = ±√(2π + 3) ≈ ±2.915 (not in the interval)
So the critical points in the interval are -2.478, -1.732, 1.732, and 2.478.
To determine which of these are relative maximums, we need to look at the sign of the derivative function on either side of the critical points. If the derivative function changes from positive to negative at a critical point, then that point is a relative maximum.
At x = -2.478, the derivative function changes from positive to negative, so this is a relative maximum.
At x = -1.732, the derivative function changes from negative to positive, so this is not a relative maximum.
At x = 1.732, the derivative function changes from positive to negative, so this is a relative maximum.
At x = 2.478, the derivative function changes from negative to positive, so this is not a relative maximum.
Therefore, the values of x in the interval −3 < x < 3 where f has a relative maximum are -2.478 and 1.732.
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A ship propeller can travel forward or backward with a function such as f(x)= 5sin(x)+4x-5 depending on the distance the ship takes.
works as. As the initial value, x-1=2 and x0=1.8, the distance that the propeller makes astern
Find its value using the secant method.
\(x_n+1 = x_n - f(x_n) * ((x_n - x_{n-1}) / (f(x_n) - f(x_{n-1})))\)Using the secant method with initial values x-1 = 2 and x0 = 1.8, the distance that the ship propeller makes astern is approximately -1.863.
The secant method is an iterative numerical method used to approximate the root of a function.
In this case, we want to find the distance that the ship propeller makes astern, which corresponds to finding the root of the function
f(x) = 5sin(x) + 4x - 5.
The secant method starts with two initial values,\(x_{-1}\) and \(x_{0}\), and iteratively improves the approximation using the formula:
\(x_n+1 = x_n - f(x_n) * ((x_n - x_{n-1}) / (f(x_n) - f(x_{n-1})))\)
Given the initial values x-1 = 2 and x0 = 1.8, we can apply the secant method to approximate the root.
First iteration:
\(x_1 = x_0 - f(x_0) * ((x_0 - x_{-1}) / (f(x_0) - f(x_{-1})))\)
= 1.8 - (5sin(1.8) + 4(1.8) - 5) * ((1.8 - 2) / ((5sin(1.8) + 4(1.8) - 5) - (5sin(2) + 4(2) - 5)))
≈ -1.855
Second iteration:
\(x_2 = x_1 - f(x_1) * ((x_1 - x_0) / (f(x_1) - f(x_0)))\)
= -1.855 - (5sin(-1.855) + 4(-1.855) - 5) * ((-1.855 - 1.8) / ((5sin(-1.855) + 4(-1.855) - 5) - (5sin(1.8) + 4(1.8) - 5)))
≈ -1.863
After the second iteration, we obtain an approximate value of -1.863 for the distance that the ship propeller makes astern.
Therefore, using the secant method with initial values x-1 = 2 and x0 = 1.8, the distance that the propeller makes astern is approximately -1.863.
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Donna bought 4 oranges for $.76. At the same rate what
would 9 oranges cost?
Answer:
4 oranges for $.76 --> 1 orange for $.19
Cost of 9 oranges --> 9·$.19 = $1.71
the side length of square a is (2x 1) meters. the side length of square b is 2 meters longer than that of square a. find the difference in the area of the squares.
The difference in the area of the square 'a' and 'b' as per given side-length is equal to 8 ( x + 1 ) square meters.
Side length of square 'a' = (2x + 1) meters
Side length of square 'b' = ( 2x + 1 + 2 ) meters
= ( 2x + 3 ) meters
Area of a square 'a' = ( side length )²
= ( 2x + 1 )²
Area of a square 'b' = ( side length )²
= ( 2x +3 )²
Difference in the area of the squares = ( 2x +3 )² - ( 2x +1 )²
= ( 2x + 3 -2x -1 )( 2x + 3 + 2x + 1 )
= ( 2 ) ( 4x + 4 )
= 8 ( x + 1 )
Therefore, the difference in the area of the given squares is equal to 8 ( x + 1 ) square meters.
The side length of square 'a' is (2x + 1) meters. The side length of square 'b' is 2 meters longer than that of square a. find the difference in the area of the squares.
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combine like terms for 13x + 18 - 3x
Answer:
10x + 18
Step-by-step explanation:
Like terms are terms with the same amount of the same variable.
In this case, set the expression:
13x - 3x + 18
Combine like terms. Subtract 13x with 3x:
(13x - 3x) + 18
10x + 18
10x + 18 is your answer.
~
Answer:
The answer is 10x + 18
Step - by - step - explanation :
Let's simplify step by step.
13x + 18 - 3x
= 13x + 18 + - 3x
Combine like terms :
= 13x + 18 + - 3x
= ( 13x + - 3x ) + ( 18 )
= 10x + 18
Which describes the slope of the line in the graph.
A)
zero
B)
positive
C)
negative
D)
undefined
Answer:
A . the slope is positive
Step-by-step explanation:
PLEASE HELP WILL MARK BRAINLIEST
Answer:
B Cosine
Step-by-step explanation:
sin A = BC/12
cos A = 5/12
tan A = BC/5
carla believed that her teammates on the track team were faster than she was, so she began putting in extra practices in order to become just as fast as them. this is an example of . a. compensation b. rationalization c. regression d. displacement please select the best answer from the choices provided a b c d
Carla's behavior of putting in extra practices to become faster can be seen as an example of (Option A.) compensation. This is because she is trying to make up for her perceived lack of speed by working harder to become as fast as her teammates.
Carla began putting in extra practices in order to become just as fast as them. This is an example of: Option A. CompensationCarla's behavior of putting in extra practices to become faster can be seen as an example of compensation. This is because she is trying to make up for her perceived lack of speed by working harder to become as fast as her teammates.
By engaging in extra practices, Carla is attempting to compensate for her lack of speed and improve her performance. This is different from rationalization, which is the act of making excuses for one's behavior, or from regression, which is the act of reverting to a younger age in response to a stressful situation.
Finally, displacement is the act of redirecting one's emotions or anger onto another person or object.
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please help me i don't get this and im dum
Answer:
The answer is 1.
Step-by-step explanation:
What is a definition of Domain of a function in math?
Which are points on the graph of y = 1. 5 ⌈x⌉? Select three options (–4. 5, –2. 5) (–0. 8, 0. 5) (7. 9, 9. 5) (4. 5, 6) (1. 3, 3. 5).
To check which point is lying on the given graph, we can just put the values in the equation in input x, and see if y comes out same as that specified y ordinate of the given point.
The points that lie on the graph of y = 1. 5 ⌈x⌉ are:
(–4. 5, –2. 5), (7. 9, 9. 5) and (1. 3, 3. 5)
Given that:The graph is of y = 1. 5 + ⌈x⌉
Evaluating output for all points' abscissa:Point (-4.5, -2.5):Putting x = -4.5, we get:
\(y = 1.5 + \lceil{x}\rceil\\y = 1.5 + \lceil -4.5 \rceil\\y = 1.5 + -4 = -2.5\)
The specified point too has y ordinate as -2.5, thus, this point lies on the graph of given function.
Point (0.8, 0.5):Putting x = 0.8, we get:
\(y = 1.5 + \lceil{x}\rceil\\y = 1.5 + \lceil 0.8 \rceil\\y = 1.5 + 1 = 2.5\)
But specified point's y ordinate is 0.5, thus, this point doesn't lie on the graph of given function.
Point (7.9, 9.5):Putting x = 7.9, we get:
\(y = 1.5 + \lceil{x}\rceil\\y = 1.5 + \lceil 7.9 \rceil\\y = 1.5 + 8 = 9.5\)
The specified point too has y ordinate as 9.5, thus, this point lies on the graph of given function.
Point (4.5, 6):Putting x = 4.5, we get:
\(y = 1.5 + \lceil{x}\rceil\\y = 1.5 + \lceil 4.5 \rceil\\y = 1.5 + 5 = 6.5\)
But specified point's y ordinate is 6, thus, this point doesn't lie on the graph of given function.
Point (1.3, 3.5):Putting x = 1.3, we get:
\(y = 1.5 + \lceil{x}\rceil\\y = 1.5 + \lceil 1.3 \rceil\\y = 1.5 + 2 = 3.5\)
The y ordinate of given point too is 3.5, thus, this point lies on the graph of given function.
Thus, the points (–4. 5, –2. 5), (7. 9, 9. 5), (1. 3, 3. 5) lie on the given graph.
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the product of four and a number is negative twelve
Answer:
4x=-12
Step-by-step explanation:
Let a number = X
So
The product of four and a number is negative twelve
4x=-12
Someone help
y-2=-2(x + 2)
y-15=3(x-5)
y-9=3(x-4)
y+2=-2(x-2)
Answer:y = -0.5x - 0.5
Step-by-step explanation:Simplify the equation for line 1 to get it into our y = mx + b format:2(x - 4y - 2 = 0-4)y = 2(x + 2Divide each side of the equation by -4 to isolate y:-4)y-4= 2(x + 2-4=y = -0.5x - 0.5
\( \frac{1 - \cos {}^{4} ( \beta ) }{ \sin {}^{4} ( { \beta }^{} ) } = 1 + 2 \cot {}^{2} ( \beta ) \)
Please Prove This Problem By Doing in LHS side. I try my best but i couldn't solve this. so please solve it.
Answer:
Step-by-step explanation:
Select the formula reference in the last column of the table and enter the earnings per share for each year. (Round to the nearest cent, X.XX ) (Click the icon to view the formulas.) (a.) 365 days + Inventory turnover (b.) Annual dividend per share + Earnings per share (c.) Annual dividend per share + Market price per share (d.) (Cash including cash equivalents + Short-term investments + Net current receivables) + Total current liabilities (e.) Cost of goods sold + Average merchandise inventory (f.) Current assets - Current liabilities (g.) Gross profit ÷ Net sales revenue (h.) Market price per share of common stock + Earnings per share (i.) Net credit sales + Average net accounts receivables (i.) (Net income + Income tax expense + Interest expense) + Interest expense (k.) Net income + Net sales (1.) (Net income + Interest expense) + Average total assets (m.) (Net income - Preferred dividends) + Average common stockholders equity (n.) (Net income - Preferred dividends) + Weighted average-number of common shares outstanding (o.) Total current assets + Total current liabilities (p.) Total liabilities + Total assets (q.) Total liabilities + Total equity
Here is the table with the earnings per share (EPS) for each year, rounded to the nearest cent.
Year Net income Preferred dividends Shares outstanding EPS formula EPS
2020 $100,000 $0 100,000 (n) $1.00
2021 $120,000 $0 100,000 (n) $1.20
2022 $140,000 $0 100,000 (n) $1.40
How to explain the informationFormula reference: (n) = (Net income - Preferred dividends) / Weighted average-number of common shares outstanding
Here are the steps on how to calculate the EPS:
Calculate the net income after deducting preferred dividends.Calculate the weighted average number of common shares outstanding.Divide the net income after preferred dividends by the weighted average number of common shares outstanding.The EPS formula is a simple way to measure a company's profitability. It is calculated by dividing the net income after preferred dividends by the weighted average number of common shares outstanding. The higher the EPS, the more profitable the company is.
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¿Cuáles son los procedimientos a ambos lados de la igualdad que se deben realizar para calcular el valor de la incógnita x en la siguiente ecuación? 2x+5=7
Answer:
Los procedimientos que se deben realizar para calcular la incógnita x en la ecuación 2x+5=7 son:
El 5 que está sumando a la izquierda del igual, se pasa a restar a la derecha del igual.El 2 que multiplica a x a la izquierda del igual, se pasa a dividir a la derecha del igual.Step-by-step explanation:
Siguiendo los procedimiento descritos en la respuesta, para calcular el valor de la incógnita:
2x + 5 = 7Seguimos el primer paso: el 5 que está sumando a la izquierda del igual, se pasa a restar a la derecha del igual:
2x = 7 - 5Seguimos el segundo paso: el 2 que multiplica a x a la izquierda del igual, se pasa a dividir a la derecha del igual:
\(x=\frac{7-5}{2}\)Como puedes ver, así se despejaría la incógnita x y solo faltaría operar los datos en la ecuación para obtener la respuesta:
\(x=\frac{2}{2}\)\(x=1\)El resultado que nos daría la incógnita x sería 1. Podemos probar el resultado en la ecuación original para comprobar el resultado que obtuvimos:
2x + 5 = 72 *(1) + 5 = 72 + 5 = 77 = 7Así, identificamos que los procesos realizados fueron correctos.
Alexander stacked unit cubes to build the rectangular prism below. Use the rectangular prism to answer
Alexander stacked 16 unit cubes required to build the rectangular prism.
What is a prism?A three-dimensional solid object called a prism has two identical ends. It consists of equal cross-sections, flat faces, and identical bases. Without bases, the prism's faces are parallelograms or rectangles.
Here we need to find the number of cubes required to build the rectangular prism.
Here first we need to find how many cubes stack in the base layer
Number of unit cubes in the base layer = Number of cubes along the length * Number of cubes along the width
The number of unit cubes in the base layer = 2 * 4 = 8 cubes.
Total number of unit cubes in prism =Number of unit cubes in the base layer *Number of layers = 8 * 2 = 16 unit cubes
So, there are 16 unit cubes are required to build the rectangular prism.
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Complete question :
Alexander stacked unit cubes to build the rectangular prism below. Use the rectangular prism to answer the question.
How many cubes are required to build the rectangular prism?
Ms. Wells bought some bananas for $0.40 per pound and some oranges for $0.80 per pound. Her fruit purchase cost $8.00 and weighed 11.75 pounds. How many pounds of bananas did she buy?
A-2.375 pounds
B- 3.50 pounds
C- 8.25 pounds
D- 9.375 pounds
Answer: Let's assume Ms. Wells bought x pounds of bananas and (11.75 - x) pounds of oranges.
The cost of bananas is $0.40 per pound, so the cost of x pounds of bananas is 0.4x.
The cost of oranges is $0.80 per pound, so the cost of (11.75 - x) pounds of oranges is 0.8(11.75 - x).
The total cost of the fruit purchase is $8.00, so we can write:
0.4x + 0.8(11.75 - x) = 8
Simplifying this equation:
0.4x + 9.4 - 0.8x = 8
-0.4x = -1.4
x = 3.5
Therefore, Ms. Wells bought 3.5 pounds of bananas.
So the answer is (B) 3.50 pounds.
Step-by-step explanation:
The height of an object that is dropped from the top of a tower is given by the expression −16t2 + 441, where t is the time in seconds.
(a) Factor this expression.
(b) Use a spreadsheet to determine how many seconds it takes the object to fall to a height of 377 feet. (Use 0.5-second intervals for t.)
t = BLANK sec
i need this fast
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Part A)
The given expression is in the form y = -16t^2 + 441, which is a quadratic equation. A quadratic equation can be factored into the form (ax + b)(cx + d) = 0, where a, b, c, and d are constants.
To factor in the given expression, we can start by completing the square. To complete the square, we need to add and subtract the square of half of the coefficient of the x^2 term, which is (1/2)(-16) = -8. This gives us:
y = -16t^2 + 441 = (-16t^2 - 8t^2) + 441 = -24t^2 + 441
Now, we can rewrite the expression as follows:
y = -24t^2 + 441 = (-8t^2) + 441
To complete the square, we need to add and subtract (1/2)^2(-8)^2 = 16:
y = (-8t^2 + 16) + 425
This expression can be rewritten as:
y = (-8t^2 + 16) + (20t)^2
So the expression can be factored as:
y = (-8t + 4)(2t - 5) (this is the answer)
Part B)
To find the time it takes the object to fall to a height of 377 feet, we can set y equal to 377 and solve for t. Substituting the factored form of the expression into the equation and solving for t gives us:
377 = (-8t + 4)(2t - 5)
We can then solve this equation by setting each factor equal to 0 and solving for t. This gives us:
-8t + 4 = 0
2t - 5 = 0
Solving these equations separately gives us:
t = 1/2
t = 5/2
The time it takes the object to fall to a height of 377 feet is t = 1/2 seconds. (or 0.5 in decimal form)
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an architect sketches the plant plan for a park in graph paper, where each unit represents1 foot. the location of a fountain at the park is modeled by the equation of a circle, as shown. (x-13)^2+ (y+20)^2
=36 what is the diameter, in feet, of the fountain?
The length of the diameter of circle is 12 feet .
Given equation of circle,
(x - 13)² + (y + 20)² = 36
Now let us see the standard form of equation of circle,
Since, the equation of a circle is,
\({(x-h)^2} + (y - h)^2 = r^2\)
Where,
(h, k) is the center of the circle,
r = radius of the circle,
Comparing it with the standard form the values of h, k , r are:
Here,
(h, k) = (13, -20)
r² = 36
r = 6 units,
Now,
Diameter is double than that of radius.
So,
d = 2r
d = 12 feet
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a goat rancher has 25% of her cows aborting and many of the cows have arthrogryposis? what other lesion are you likely to see when you dissect the fetus that would lead to the limb deformities such as these
Arthrogryposis, also called arthrogryposis multiplex congenita (AMC), is a term used to describe a variety of conditions involving multiple joint contractures (or stiffness).
Arthrogryposis is a general or descriptive term for the development of non progressive contractures affecting one or more areas of the body prior to birth (congenitally). A contracture is a condition in which the joint becomes permanently fixed in a bent (flexed) or straightened (extended) position, completely or partially restricting the movement of the affected joint. When congenital contractures occur only in one body area which means it is not referred to as arthrogryposis but rather as an isolated congenital contracture. The most common form of an isolated congenital contracture is clubfoot. When arthrogryposis affects two or more different areas in the body, it may be referred to as arthrogryposis multiplex congenita (AMC).
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