16
please
Finding a Sequence's Formula In Exercises 13-26, find a formula for the nth term of the sequence. 13. The sequence 1,-1,1,-1,1.... 1's with alternating signs 16. The sequence 1, -1/4, 1/9,-1/16,1/25,.. Reciprocal

Answer:

Count the digits to the right of each decimal point three digits in this case. Move the decimal point three spaces in the total, starting at the right and moving left.

Answer:

30%

Step-by-step explanation:

To find a percentage of a number, take the part of the number and divide it by the whole, then multiply by 100%.

In this case:

6 / 20 = 0.3

0.3 * 100% = 30%

Answer:

47/330

Step-by-step explanation:

  100x = 14.242424...

-        x  = 0. 142424...

---------------------------------

   99x = 14.1

x = 14.1/99

x = 141/990

x = 47/330

If we arrive at the bus stop 5 minutes early , then the probability that the bus is more than 10 minutes late is 5/17 .

The time duration for taking the bus every morning is = 2 minutes early to 15 minutes late ;

We know that the Uniform Distribution has 2 bounds, "a" and "b"  ;

So , Probability of finding the value above x is : P(X > x) = (b-x)/(b-a) ;

In this case , the lower bound that is : a = -2 , and the upper bound : b = 15 ;

The probability that the bus is more than 10 minutes late , that is P(X > 10) ;

So , P(X > 10) = (15 - 10)/(15 -(-2)) = 5/17 .

Therefore , the required probability is 5/17 .

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Step-by-step explanation:

sorry that's all i know hehe

The length of an arc is given by the formula:

We are provided with the following;

Thus, we have:

Hence, the degree measure is 72 degrees

Answer: 36

Step-by-step explanation:

The probability of someone returning exactly 1 of the 3 packages can be calculated as:P(1 out of 3 packages is returned) = C(3, 1) × P(0 or 1 diskette is defective)¹ × (1 - P(0 or 1 diskette is defective))²P(1 out of 3 packages is returned) = C(3, 1) × (0.9043820371)¹ × (0.0956179629)²P(1 out of 3 packages is returned) = 0.2448700124Therefore, the required probability of someone returning exactly 1 of the 3 packages is 0.2448700124.

The given data from the question is that the company produces diskettes which have the probability of being defective as 0.01. The packages that are sold have a size of 10 and the guarantee says that there can be at most one defective diskette in the package. Now, the question is to find the probability of someone returning exactly 1 of the 3 packages that they have bought.  So, the given data can be summarized as:Given:Probability of the diskette being defective, p = 0.01Guarantee: At most one diskette in the package of size 10 is defective.Now, let's solve the problem using probability theory

Probability of 1 diskette being defective in a package of size 10 can be calculated as:P(defective) = p = 0.01P(non-defective) = 1 - p = 0.99Using the given guarantee, probability of at most one defective diskette in a package of size 10:P(0 or 1 diskette is defective) = P(0 defective) + P(1 defective)P(0 or 1 diskette is defective) = C(10, 0) × (0.99)¹⁰ + C(10, 1) × (0.99)⁹ × (0.01)P(0 or 1 diskette is defective) = 0.9043820371Using the above probability

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Answer:

2:3 I think

Step-by-step explanation:

Answer: 70

Step-by-step explanation: 21+21+14+14

Answer:

no

Step-by-step explanation:

Step-by-step explanation:

\( - 2 - - 5 \\ \)

\( \div - 3 - - 3\)

The given statements are correct or incorrect is given below:

1) Correct.

2) Correct.

3) Correct.

4) Correct.

5) Correct.

6) Incorrect.

7) Correct.

8) Correct.

9) Correct.

10) Incorrect.

Here, we have,

1) Correct. In a simple graphical method, a graph is plotted to show the relationship between water usage and population.

2) Correct. The pressure in a distribution system needs to be sufficient to allow for adequate hydrant flows in case of a fire.

3) Correct. The term "distribution system" refers to the infrastructure and facilities used to supply water from its source to the point of usage.

4) Correct. Brackish water is water that has a higher salinity level than fresh water and even higher than seawater.

5) Correct. Monthly variation in water usage can impact the design and capacity requirements of storage reservoirs.

6) Incorrect. Jordan is considered a "Water Scarce" country, as it faces significant challenges in terms of water availability and scarcity.

7) Correct. During a fire, a significant quantity of water needs to be supplied over an extended period, necessitating a high rate of hourly supply.

8) Correct. The Manning equation is commonly used in the design and evaluation of sanitary sewers.

9) Correct. If the diameter (d) is less than 200 mm, the pipe's final diameter (D) is set at 200 mm.

10) Incorrect. The diameter of the interceptor pipe is typically larger than the diameter of the lateral pipe. The interceptor pipe carries wastewater from multiple lateral pipes.

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The variable of the function f(x) = x⁵ + (x+3)². The value of f(x) is 9 when x = 0.

What is a function?

A function from a set X to a set Y assigns exactly one element of Y to each element of X. The set X is known as the function's domain, and the set Y is known as the function's codomain. Originally, functions were the idealization of how a varying quantity depends on another quantity.

Given function is f(x) = x⁵ + (x+3)².

The given table is:

x      -2         -1          0         1

f(x)    -31       ?            9       17

Putting x = -2 in the function f(x) = x⁵ + (x+3)²:

f(-2) = (-2)⁵ + (-2+3)²

f(-2) = -32 + 1

f(-2) = -31

Putting x = -1 in the function f(x) = x⁵ + (x+3)²:

f(-1) = (-1)⁵ + (-1+3)²

f(-1) = -1 + 2²

f(-1) = 3

Putting x = 0 in the function f(x) = x⁵ + (x+3)²:

f(0) = (0)⁵ + (0+3)²

f(0) = 0 + 3²

f(0) = 9

Putting x = 1 in the function f(x) = x⁵ + (x+3)²:

f(1) = (1)⁵ + (1+3)²

f(1) = 1 + 4²

f(1) = 17

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Answer:

x = 73

x ÷ 11 = 73 ÷ 11 = 6.636 or \(6\frac{7}{11}\) or  ( 6 remainder 7)

Step-by-step explanation:

1. In order to determine the value of x, we will first find a two-digit multiple of 9 that has a unit value of (2)

Multiples of 9 = 18, 27, 36, 45, 54, 63, 72, 81, ...

from the above, the multiple of 9 that has a unit value of '2' is 72 ( 7 tens and 2 units)

2. Next, we will add 1 to the multiple of 9 found in step 1 above, to create a unit value of '3'. This is because when the number is divided by 9, we want to have a remainder of 1, and when the number is divided by 10, and we want to have a remainder of 3

72 + 1 = 73 ( 7 tens and 3 units)

3. Finally, let us divide the number in step 2 above by 10

73 ÷ 10 = 7 remainer 3.

Now the number 73 satisfies the three conditions given in the question:

1) The number x is a two-digit number.

73 is a two-digit number  

2) When x is divided by 9, the remainder is 1.

73 ÷ 9 = 8 remainder 1

3) When x is divided by 10, the remainder is 3.

73 ÷ 10 = 7 remainder 3

∴ x = 73

x ÷ 11 = 73 ÷ 11 = 6.636 or ( 6 remainder 7)

By multiplying Equation 2 by 6, Yumiko ensures that the coefficient of "x" in both equations is 12, allowing her to add the equations and eliminate the "x" variable.

To eliminate a variable when adding the equations, Yumiko needs to multiply both sides of the other equation by a factor that will make the coefficients of one of the variables the same in both equations. Let's consider the system of equations:

Equation 1: 2x - 3y = 12

Equation 2: ax + by = c

Since Yumiko multiplied Equation 1 by 6, it becomes:

6(2x - 3y) = 6(12)

12x - 18y = 72

To eliminate the variable "x" when adding these equations, we need the coefficient of "x" in Equation 2 to be 12. Therefore, the factor by which Yumiko should multiply both sides of Equation 2 is 6.

6(ax + by) = 6(c)

6ax + 6by = 6c

Now, when we add Equation 1 and the modified Equation 2, the "x" terms will eliminate each other:

(12x - 18y) + (6ax + 6by) = 72 + 6c

(12x + 6ax) + (-18y + 6by) = 72 + 6c

(12 + 6a)x + (-18 + 6b)y = 72 + 6c

By multiplying Equation 2 by 6, Yumiko ensures that the coefficient of "x" in both equations is 12, allowing her to add the equations and eliminate the "x" variable.

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note the full question may be:

A carpenter is building a rectangular table with a length of 4 feet and a width of 3 feet. If the carpenter wants to increase the dimensions of the table by a factor of 2, what should be the new length and width of the table?

Answer:

15. 12, 16. 18

Step-by-step explanation:

a = pi*r^2

15) 36pi = pi*r^2 --> 36 = r^2 --> 6 = r --> 12 = d

16) 81pi = pi*r^2 --> 81 = r^2 --> 9 = r --> 18 = d

Answer:a. >

Step-by-step explanation:

Answer: y = 5/6x

Step-by-step explanation:

It is a direct variation.

Answer:percent increase in the puppy's weight = 75%

Step-by-step explanation:

Step 1

Percent Increase = New weight - Old weight/ old weight  x 100

New weight of Elijah's puppy =35 ounces

Old weight of Elijah's puppy = 20 Ounces

Step 2-- Solving

Percent Increase = (35-20)/ 20 x 100

15/20 x 100

=3/4 x 100

= 75%

when you flatten a spherical meatball into a hamburger, you increase its surface area while keeping the volume constant.

A sphere is a three-dimensional shape that has a curved surface. When you flatten a spherical meatball into a hamburger, you are essentially reshaping it into a flat, disk-like form. By doing so, you increase the area that is in contact with the cooking surface, such as a pan or grill. This larger surface area allows for more even cooking and browning.

However, the total amount of meat remains the same when you flatten the meatball. The volume of an object refers to the amount of space it occupies, and since the meatball is being flattened without adding or removing any meat, the volume remains constant. In other words, the flattened hamburger will have a larger surface area but the same amount of meat as the original spherical meatball.

So, when you flatten a spherical meatball into a hamburger, you increase its surface area while keeping the volume constant.

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When you flatten a spherical meatball into a hamburger, you decrease its volume and increase its surface area.

When a spherical meatball is flattened into a hamburger, its shape changes from a sphere to a flat disk. This transformation affects both the volume and surface area of the meatball.

The volume of a sphere is given by the formula V = (4/3)πr^3, where r is the radius of the sphere. The surface area of a sphere is given by the formula A = 4πr^2.

On the other hand, the volume of a disk (or a circle) is given by the formula V = πr^2, where r is the radius of the disk. The surface area of a disk is given by the formula A = 2πr.

When the meatball is flattened, its radius decreases, resulting in a smaller volume. The volume of the flattened meatball is less than the volume of the original spherical meatball.

However, the surface area of the flattened meatball increases. The surface area of the flattened meatball is greater than the surface area of the original spherical meatball.

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The correct answer is a) the probability of precipitation is 72%. and b)  the probability of precipitation is 2%.

The given formula to determine the probability of precipitation (PoP) is PoP = (C * A) * 100 percent where C represents the confidence that precipitation will occur somewhere in the forecasted area and A represents the percentage of the area that will receive measured precipitation if it occurs.

(a) If a forecaster expresses confidence that there is an 80% chance of precipitation in the forecasted area, and it is expected to produce measurable precipitation over 90% of the area, then the probability of precipitation is given as follows: PoP = (C * A) * 100 per cent C = 80%A = 90%PoP = (80% * 90%) * 100%

PoP = 72%.

Therefore, the probability of precipitation is 72%.

(b) If a forecaster expresses confidence that there is a 20% chance of precipitation in the forecasted area, and it is expected to produce measurable precipitation over 10% of the area, then the probability of precipitation is given as follows: PoP = (C * A) * 100 per cent C = 20%A = 10%PoP = (20% * 10%) * 100%PoP = 2%

Therefore, the probability of precipitation is 2%.

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Answer:

IM because they are the same!!

YOUR WELCOME

Step-by-step explanation:

Groups A, B, and C have means of 4, 6, and 8, respectively. There are 15 cases in total, with equal sample sizes in each group. Within is 120. 16-7. 16-4a, the value of omega-squared is 0.25.

What is omega-squared?

       In statistics, omega-squared is a measure of effect size that can be used for one-way ANOVA to determine how much variance is due to the treatment or independent variable. It is calculated by dividing the between-group variance by the total variance, which includes both the within-group and between-group variance.

       Omega-squared is used to determine the percentage of variance accounted for by a particular factor or treatment. It is represented as ω2 and ranges from 0 to 1, with higher values indicating a stronger relationship between the independent variable and the dependent variable.

       The formula for omega-squared is as follows:

                         ω2=SSBetween / SSTotalSSWithin

                              = SSTotal - SS Between

         Where SSTotal is the sum of squares for the total variance.SSBetween is the sum of squares between the groups, and within is the sum of squares within the groups.

     The given information is:

                       Mean of group A = 4Mean of group

                                                 B = 6Mean of group

                                                 C = 8Total cases

                                                    = 15SSWithin

                                                    = 120

             We can calculate the sum of squares between the groups as follows:

                        SSTotal = SSBetween + SSWithinSSTotal

                                      = (nA + nB + nC - 1) × (σA² + σB² + σC²)SSBetween

                                      = SSTotal - SS Within SS Between

                                      = (3 - 1) × (42 + 62 + 82) - 120SSBetween

                                      = 80 Next,

           we can calculate the total variance as:

                      SSTotal = SSWithin + SSBetweenSSTotal

                                    = 120 + 80SSTotal

                                     = 200

            Now, we can calculate omega-squared as follows:

                     ω2 = SSBetween / SSTotalω2

                           = 80/200ω2

                           =0.4

       Hence, the value of omega-squared is 0.25.

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Answer:

Answer is 235/45

Step-by-step explanation:

The required answer is the annual cost saved by shifting from the 500-bag lot size to the EOQ is $1,059.92.

Explanation:-

a. Economic order quantity (EOQ) is defined as the optimal quantity of inventory to be ordered each time to reduce the total annual inventory costs.

It is calculated as follows: EOQ = sqrt(2DS/H)

Where, D = Annual demand = 100 x 52 = 5200S = Order cost = $57 per order H = Annual holding cost = 0.30 x 10.75 = $3.23 per bag per year .Therefore, EOQ = sqrt(2 x 5200 x 57 / 3.23) = 234 bags. The average time between orders (TBO) can be calculated using the formula: TBO = EOQ / D = 234 / 100 = 2.34 weeks ≈ 2 weeks (rounded to nearest whole number).

Hence, the EOQ is 234 bags and the average time between orders is 2 weeks (approx).b. R is the reorder point, which is the inventory level at which an order should be placed to avoid a stockout.

It can be calculated using the formula:R = dL + zσL

Where,d = Demand per day = 100 / 5 = 20L = Lead time = 1 week (5 working days) = 5 day

z = z-value for 92% cycle-service level = 1.75 (from standard normal table)σL = Standard deviation of lead time demand = σ / sqrt(L) = 16 / sqrt(5) = 7.14 (approx)

Therefore,R = 20 x 5 + 1.75 x 7.14 = 119.2 ≈ 120 bags

Hence, the reorder point R should be 120 bags.c. An inventory withdraw of 10 bags was just made. Is it time to reorder?The current inventory level is 310 bags, which is greater than the reorder point of 120 bags. Since there are no open orders or backorders, it is not time to reorder.d. The store currently uses a lot size of 500 bags (i.e., Q = 500).What is the annual holding cost of this policy.

Annual ordering cost. Without calculating the EOQ, how can you conclude the lot size is too large?Annual ordering cost = (D / Q) x S = (5200 / 500) x 57 = $592.80 per year.

Annual holding cost = Q / 2 x H = 500 / 2 x 0.30 x 10.75 = $806.25 per year. Total annual inventory cost = Annual ordering cost + Annual holding cost= $592.80 + $806.25 = $1,399.05Without calculating the EOQ, we can conclude that the lot size is too large if the annual holding cost exceeds the annual ordering cost.

In this case, the annual holding cost of $806.25 is greater than the annual ordering cost of $592.80, indicating that the lot size of 500 bags is too large.e.

The annual cost saved by shifting from the 500-bag lot size to the EOQ can be calculated as follows:Total cost at Q = 500 bags = $1,399.05Total cost at Q = EOQ = Annual ordering cost + Annual holding cost= (D / EOQ) x S + EOQ / 2 x H= (5200 / 234) x 57 + 234 / 2 x 0.30 x 10.75= $245.45 + $93.68= $339.13

Annual cost saved = Total cost at Q = 500 bags - Total cost at Q = EOQ= $1,399.05 - $339.13= $1,059.92

Hence, the annual cost saved by shifting from the 500-bag lot size to the EOQ is $1,059.92.

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the answer is: 1/12

simple explanation is :50/100*1/6

a) The weight representing the 40th percentile is approximately 1130.0 pounds. b) The weight representing the 99th percentile is approximately 1355.2 pounds. c) The interquartile range (IQR) of the weights of these Angus steers is approximately 110.97 pounds.

a) To find the weight that represents the 40th percentile, we can use the mean and standard deviation provided. The 40th percentile corresponds to z = -0.253 (z-score for the 40th percentile).

Using the z-score formula:

z = (x - μ) / σ

Rearranging the formula to solve for x (weight), we have:

x = z * σ + μ

Substituting the values:

z = -0.253

σ = 84

μ = 1152

x = -0.253 * 84 + 1152

x ≈ 1130.012

Therefore, the weight representing the 40th percentile is approximately 1130.0 pounds.

b) Similarly, to find the weight that represents the 99th percentile, we use the z-score formula. The 99th percentile corresponds to z = 2.326.

x = z * σ + μ

x = 2.326 * 84 + 1152

x ≈ 1355.184

Therefore, the weight representing the 99th percentile is approximately 1355.2 pounds.

c) To find the interquartile range (IQR), we need to subtract the third quartile (Q3) from the first quartile (Q1). The IQR measures the range of values where the middle 50% of the data falls.

The z-scores corresponding to the first quartile (Q1) and third quartile (Q3) are -0.674 (25th percentile) and 0.674 (75th percentile), respectively.

Q1 = -0.674 * 84 + 1152

Q1 ≈ 1096.616

Q3 = 0.674 * 84 + 1152

Q3 ≈ 1207.584

IQR = Q3 - Q1

IQR ≈ 1207.584 - 1096.616

IQR ≈ 110.968

Therefore, the interquartile range (IQR) of the weights of these Angus steers is approximately 110.97 pounds.

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Answer:

a= -2

Step-by-step explanation:

Answer: a = -2

Step-by-step explanation: Provided in the attachment.

The solid that could have resulted in a two-dimensional cross section in the shape of a circle when cut by a plane parallel to its base is a right cylinder.

A right cylinder is a three-dimensional shape with two parallel circular bases connected by a curved surface. When a plane is passed through a right cylinder parallel to its base, the resulting cross section will always be a circle. This is because the cross section will intersect both bases along their circumferences, creating a circular shape.

On the other hand, a rectangular pyramid, right hexagonal prism, and right triangular prism would not result in a circular cross section when cut by a plane parallel to their respective bases. A rectangular pyramid would produce a cross section in the shape of a rectangle, a right hexagonal prism would produce a cross section in the shape of a hexagon, and a right triangular prism would produce a cross section in the shape of a triangle.

Therefore, the only solid that could have resulted in a circular cross section is a right cylinder.

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