16. Who was the first modern chemist

Answer:

it would prob be planet y

The statement that is true for Sn2 reactions is displacement occurs with the inversion of configuration. Among all these statements only option d. is the correct answer.

The Sn2 mechanism is a concerted mechanism and goes with second-order kinetics. The kinetic of the reaction informs us about the rate and the reactants whose concentrations influence the rate of the reaction. The Sn2 reaction is a one-step reaction in which the incoming nucleophile invasions from the backside and removes the departing group from the molecule. All of this occurs simultaneously as the reaction is coordinated.

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The ΔG is 3.66 kJ.

To calculate the ΔG of a chemical reaction, it is necessary to use the ΔG formula and replace the values. Remember to convert the J into kJ before the calculation:

So, the ΔG of the reaction is 3.66 kJ.

Answer:12.9e-12g or in short 12.9pg

Explanation:as p=1e-12

In this question, we have volume and pressure, and the gas law that shows the relationship between these two is the Boyle's Law, which has the following formula:

P1V1 = P2V2

We have:

P1 = 885 mmHg, which is equal to 1.16 atm

V1 = 266 mL

P2 = ?

V2 = 444 mL

Now we add these values into the formula:

1.16 * 266 = 444*P2

P2 = 0.695 atm, this will be the new pressure, letter D

Answer:

Oxygen-16 has 8 protons and 8 neutrons, and a mass number of 16. Oxygen-17 has 8 protons and 9 neutrons, and a mass number of 17. Oxygen-18 has 8 protons and 10 neutrons, and a mass number of 18.

Explanation:

Answer:

The controlled variable of an experiment is the one thing that stays the same in an experiment.

Explanation:

An example would be : if I have two pennies, both dunked in water, but than I change one to be dunked in vinegar, the one dunked in water still is the constant or the controlled variable.

Answer: 4.5 moles

Explanation:

To understand how to solve this problem, you must understand the ratios written in this chemical equation.

The equation shows that 4 moles of Al forms 2 moles Al₂O₃. This creates the ratio 2:4 or \(\frac{2}{4}\)

To solve, you can set the two ratios to each other and cross multiply.

\(\frac{2}{4} = \frac{x}{9}\)

18 = 4x

x = 4.5 mol Al₂O₃

*both \(\frac{2}{4}\) and \(\frac{4.5}{9}\) can be simplified as \(\frac{1}{2}\), which verifies your answer*

The amount of volume of KOH solution that should be added to make 500mL of a 0.300M solution is 200mL.

The volume of a solution given the concentration can be calculated using the following expression;

CaVa = CbVb

Where;

According to this question, we are to calculate how many mL of a 0.75 M OH solution that should be added to a 500 mL flask to make 500 mL of a 0.300 M KOH solution.

0.75 × Va = 500 × 0.3

0.75Va = 150

Va = 150/0.75

Va = 200mL

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For Test One, phenotype ratio is Short fur : Long fur = 2 : 0; For Test Two, the phenotype ratio is Short fur : Long fur = 3 : 1; For Test Three, the phenotype ratios will be Short fur : Long fur = 0 : 2

For Test One:

Parent 1: FF (homozygous dominant for short fur)

Parent 2: Ff (heterozygous for short fur)

The Punnett square for this cross will give the following genotype ratios:

FF : Ff = 1 : 1

And the corresponding phenotype ratios will be:

Short fur : Long fur = 2 : 0 or 100% short fur

For Test Two:

Parent 1: Ff (heterozygous for short fur)

Parent 2: Ff (heterozygous for short fur)

The Punnett square for this cross will give the following genotype ratios:

FF : Ff : ff = 1 : 2 : 1

And the corresponding phenotype ratios will be:

Short fur : Long fur = 3 : 1 or 75% short fur and 25% long fur

For Test Three:

Parent 1: ff (homozygous recessive for long fur)

Parent 2: ff (homozygous recessive for long fur)

The Punnett square for this cross will give the following genotype ratios:

ff : ff = 1 : 0

And the corresponding phenotype ratios will be:

Short fur : Long fur = 0 : 2 or 100% long fur

For this investigation, the test variable is the breed of hamster and the outcome variable is the phenotype of the hamster.

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Answer:

They get more energy, so they vibrate!

Explanation:

number of moles used:

1/2 x 2.46 moles = 1.23

number of moles left:

2.46 - 1.23 = 1.23 moles

a) According to the balanced equation, for every 5 moles of Br that react, 3 moles of Br₂ are produced. Therefore, the rate of appearance of Br₂ will also be 3.5 × 10⁻¹ mol L⁻¹s⁻¹.

b) For every 6 moles of H⁺ that react, 3 moles of H₂O are produced. Therefore, the rate of appearance of H₂O will be half the rate of disappearance of H⁺, which is 1.75 × 10⁻¹ mol L⁻¹s⁻¹.

c) According to the balanced equation, for every 6 moles of H⁺ that react, 5 moles of Br and 1 mole of BrO₃⁻ are consumed. Therefore, the rate of disappearance of H⁺ will be (5/6) × 3.5 × 10⁻¹ mol L⁻¹s⁻¹, which is 2.92 × 10⁻¹ mol L⁻¹s⁻¹.

d) According to the balanced equation, for every 1 mole of BrO₃⁻ that reacts, 3 moles of Br₂ are produced. Therefore, the rate of disappearance of BrO₃⁻ will be (1/5) × 3.5 × 10⁻¹ mol L⁻¹s⁻¹, which is 7.0 × 10⁻² mol L⁻¹s⁻¹.

Depending on the type of reactants, their concentration, temperature, and other variables, chemical reactions proceed at varying speeds. We can comprehend and measure the rates of these reactions with the aid of kinetics.

In this issue, the rates of the various species contributing to the chemical reaction are to be determined.

By doing this, we can learn more about the variables that influence this reaction's rate and possibly improve the conditions for the creation of the desired goods more quickly or effectively.

We found that the rate of appearance of Br₂ is also 3.5 × 10⁻¹ mol L⁻¹s⁻¹, the rate of appearance of H₂O is 1.75 × 10⁻¹ mol L⁻¹s⁻¹, the rate of disappearance of H⁺ is 2.92 × 10⁻¹ mol L⁻¹s⁻¹, and the rate of disappearance of BrO₃⁻ is 7.0 × 10⁻² mol L⁻¹s⁻¹.

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Answer: 5.5 atm

Explanation:

Answer:

Pot holders are meant to protect your hand from the heat of the pot, and so it would need to be a poor conductor of heat in order to do its job correctly. Silicon dioxide is a solid at room temperature and methanol is a liquid.

Answer:

0.185 g

Explanation:

Answer:

Vitamin A deficiency can result from inadequate intake, fat malabsorption, or liver disorders.

The amount of heat required to raise the temperature of the 34.2 g sample of aluminum by 34 oC is 1043.52 J.

What is Temperature?

Temperature is a measure of the average kinetic energy of the particles in a substance. It is a physical property that determines the direction of heat flow between two objects or systems in contact with each other. Temperature is measured in degrees Celsius (°C) or Fahrenheit (°F), or in kelvin (K) in the International System of Units (SI).

The amount of heat (q) required to raise the temperature of a substance can be calculated using the formula:

q = m x c x ΔT

Where:

m = mass of the substance (in grams)

c = specific heat of the substance (in J/g oC)

ΔT = change in temperature (in oC)

Plugging in the values given:

m = 34.2 g

c = 0.9 J/g oC

ΔT = 34 oC

q = (34.2 g) x (0.9 J/g oC) x (34 oC)

q = 1043.52 J

Therefore, the amount of heat required to raise the temperature of the 34.2 g sample of aluminum by 34 oC is 1043.52 J.

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First, remember that:

When we put the electrons using the Aufbau Principle, something different happens after Argon element. At argon, the 3s and 3p levels are full, but rather than filling up the 3d levels next, the 4s level fills instead to give potassium (K) and then calcium (Ca). Only after that the 3d levels are filled. The elements in the Periodic Table which correspond to the d levels filling are known as d block elements.

ANSWER:

The definition of a transition metal is that:

A transition metal is one that forms one or more stable ions which have incompletely filled d orbitals.

Based in this definition, we notice that Zinc has the following electronic structure:

When Zinc forms ions, it always loses the two 4s electrons to give a +2 ion with the electronic structure Ar 3d10. As we can see, this ion has completely filled d orbitals, so it can't be considered as a transition metal since it doesn't meet the given definition.

Claim 1: Yes, there probably will be a lunar eclipse of the moon of Kepler-47c during a year.

Claim 2: No, there probably won't be a lunar eclipse of the moon of Kepler-47c during a year.

Kepler-47c is a moon orbiting Kepler-47 AB, a binary star system. This implies that the moon's light varies on a regular basis as it circles the two stars. These changes in light might result in a lunar eclipse.

Lunar eclipses occur when the moon passes through the Earth's shadow. While Kepler-47c circles two stars, it is still subject to Earth's gravitational pull and may pass into its shadow.

Lunar eclipses occur on a regular basis, with two to four eclipses occurring on average per year. Given the frequency of lunar eclipses, Kepler-47c is likely to see at least one lunar eclipse every year.

Evidence to support this claim 2:

Lunar eclipses occur when the moon passes through the Earth's shadow. While Kepler-47c is in the Earth's gravitational field, it is not on the same orbital plane as the Earth.

While Kepler-47c circles two stars, its orbit is not known to be stable. Variations in Kepler-47c's orbit may reduce the likelihood of a lunar eclipse.

While lunar eclipses are common, they are not uniformly distributed throughout the year. The locations and motions of the Earth, moon, and sun govern the timing and frequency of lunar eclipses.

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Answer:

Atomic radius decreases across a period and increases down a group. Across a period, effective nuclear charge increases as electron shielding remains constant. Down a group, the number of energy levels (n) increases, so there is a greater distance between the nucleus and the outermost orbital.

Explanation:

Answer:

Two positive aspects of using methane recapture systems are able to generate significant electricity. Another benefit is that the process of anaerobic digestion creates heat that can be used to warm buildings where animals are kept

Answer:  The correct answer is;

Two positive aspects of using methane recapture systems include lowering the impact on greenhouse gasses and the production of energy. Methane is a very potent greenhouse gas that is contributing to global warming. As a result, the recapturing process reduces the methane impacts of global warming by reclaiming and reusing the gas for other purposes. Recaptured methane can be stored and used to generate electricity or used as fuel to power updated vehicles and other engines on the farm. The overall benefits from this combination are reducing impacts causing global warming and lower the cost of electricity or fuel on the farm.

Explanation:  This answer has been confirmed correct.

Answer:

pH = 12.90

Explanation:

THe reaction of HNO₃ with KOH is:

HNO₂ + KOH → KNO₂ + H₂O

That means 1 mole of nitrous acid reacts per mole of potassium hydroxide.

To solve this question, we need to find the moles of each reactant:

Moles HNO₂:

0.0179L * (0.458mol / L) = 0.00820 moles

Moles KOH:

0.0334L * (0.368mol / L) = 0.01229 moles

That means KOH is in excess. The moles in excess are:

0.01229 moles - 0.00820 moles = 0.00409 moles KOH = Moles OH⁻

The [OH⁻] is -Total volume = 17.9mL+33.4mL = 51.3mL = 0.0513L-:

0.00409 moles / 0.0513L =

0.0797M =[OH⁻]

pOH = -log[OH⁻] = 1.098

pH = 14 - pOH

The statement which is true about both groundwater and surface water is that the  groundwater and the surface water together form a drainage basin​.

Ground water is the type of water which is present below the surface of rock and between spaces in soil pores .Thirty percent of the available fresh water is present in the form of groundwater.

Groundwater is discharged from the surface naturally in the form of springs and seeps and can also exist in the form of oases or wetlands.It is used for various purposes like for agriculture, municipal and industrial uses. They are used by constructing wells .

The study of movement and distribution of ground water is called hydrogeology or even groundwater hydrology.It is a cheaper source of water and is less prone to pollution as compared to surface water.

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The correct answer is B. 8 molecules \(SO_3\). Option B

In the given reaction:

S(s) + \(O_2\)(g) → \(SO_3\)(g)

The stoichiometric coefficient in front of the \(SO_3\)molecule is 8, which indicates that 8 molecules of \(SO_3\)are formed as a product. This coefficient represents the ratio of the number of molecules involved in the reaction.

Option A (8 atoms \(SO_3\)) is incorrect because it only mentions the number of atoms, not molecules. The stoichiometric coefficient does not represent the number of atoms, but rather the number of molecules.

Option C (80.07g \(SO_3\)) is incorrect because it mentions a specific mass. The stoichiometric coefficient does not directly represent the mass of the substance, but rather the relative amount of molecules involved in the reaction.

Option D (32 \(SO_3\)) is incorrect because it mentions a specific volume. The stoichiometric coefficient does not directly represent the volume of the substance, but rather the relative amount of molecules involved in the reaction.

Therefore, the correct way to describe the \(SO_3\)component in the reaction is option B: 8 molecules \(SO_3\). This represents the ratio of the number of molecules of \(SO_3\)that are produced in the reaction.

Option B

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Answer:

\(\huge\boxed{\sf v = 0.004\ m\³}\)

Explanation:

Mass = m = 4 kg

Density of water = 1000 kg/m³ (Standard)

Volume = v = ?

Density = m/v

1000 = 4 / v

1000 × v = 4

v = 4/1000

v = 0.004 m³

\(\rule[225]{225}{2}\)

To draw the Bohr-Rutherford diagram for fluorine-19, we begin by identifying the atomic number of fluorine, which is 9. This means that a neutral fluorine atom has 9 electrons.

The Bohr-Rutherford diagram represents the electron shells or energy levels of an atom, with each shell holding a certain number of electrons. The first shell holds a maximum of 2 electrons, while the second shell holds a maximum of 8 electrons.

Based on this information, we divide the 9 electrons of fluorine into the appropriate shells:

1. The first two electrons occupy the first shell (closest to the nucleus). This will completely fill the first shell.

2. The remaining 7 electrons occupy the second shell. However, since the second shell can hold a maximum of 8 electrons, one electron will be placed in each orbital (subshell) before the electrons are paired.

The electron configuration of fluorine-19, arranged in the Bohr-Rutherford diagram, can be represented as follows:

      1st shell: 2nd shell:

        (2) (7)

The numbers in parentheses indicate the number of electrons in each shell. In this case, the first shell has 2 electrons and the second shell has 7 electrons.

It is important to note that the Bohr-Rutherford diagram provides a simplified representation of the electron distribution and does not account for the more complex orbital arrangements. However, it provides a basic visual understanding of the electron configuration in an atom.

Briefly, fluorine-19 has a Bohr-Rutherford diagram with 2 electrons in the first shell and 7 electrons in the second shell, for a total of 9 electrons.

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Answer:

Sodium Sulfide

Explanation:

I looked it up