The coordinates of such remaining pairs are (-1, 3), (4, 3), and (-1, -7), respectively (4, -7) There isn't a third pair. The edges of such a square are its vertices.
The positions of both the remaining pairings were (-1, 3), (4, 3), and (-1, -7), respectively (4, -7)
The criteria are as follows:
\(E= (-1,-2)\)
\(F = (4, -2)\)
Measure the distance EF.
\(EF = \sqrt{(x_{1} -x_{2}) ^{2} +(y_{1} -y_{2})^{2}\)
We do indeed have:
\(EF= \sqrt{(-1-4)^{2} }(-2--2)^{2}\)
\(EF= \sqrt{25}\)
EF= 5
E and F's y-coordinates will gain 5 in total.
\(C = (-1, -2 +5)\)
\(C= (-1,3)\)
\(D = (4 -2 +5)\)
\(D=(4,3)\)
Add 5 less than E and F's y-coordinates.
\(C= (-1-2-5)\)
\(C=(-1,-7)\)
\(D= (4,-2-5)\)
\(D=(4,-7)\)
As a result, the coordinates for the additional pairings are (-1, 3), (4, 3), and (-1, -7), respectively (4, -7) No third pair is present.
When two or more curves, lines, or edges come together, it is called a vertex (plural: vertices or mostly including) in geometry. As a result of this description, vertices are the intersection of two planes that create an angles as well as the edges of polygon and polygonal.
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Please answer with explanation
Answer:
y = 2x + 1
Step-by-step explanation:
Line is passing through the points (-3, - 5) and (4, 9)
Slope of the line (m) \( =\frac{-5-9}{-3-4}=\frac{-14}{-7}=2\)
Equation of line in given as:
\(y - 9 = 2(x - 4) \\ \\ y - 9 = 2x - 8 \\ \\ y = 2x - 8 + 9 \\ \\ y = 2x + 1\)
which does not describe the equation
\( \sqrt{x = - 2} \)
Answer:
which of what ?
and the equation is not right. I don't know what you mean.
do you mean x = sqrt(-2) ?
all I can tell you just based on that assumption is that you can transform that into
\(x = \sqrt{2} \times i\)
you know,
\(i = \sqrt{ - 1} \)
but what else you might need is completely unclear.
According to the Federal Highway Administration 2003 highway statistics, the distribution of ages for licensed drivers has a mean of 44.5 years and a standard deviation of 17.1 years. Assuming the distribution of ages is normally distributed what percentage of the drivers are between the ages 17 and 56?
Assuming the distribution of ages is normally distributed, the percentage of the drivers that are between the ages 17 and 56 is 69.49%.
According to the Federal Highway Administration 2003 highway statistics, the distribution of ages for licensed drivers has a mean of 44.5 years and a standard deviation of 17.1 years.
To find the percentage of drivers between the ages of 17 and 56, we'll use the normal distribution properties.
Here are the steps:
1. Calculate the z-scores for both ages:
z₁ = (17 - 44.5) / 17.1 = -1.61
z₂ = (56 - 44.5) / 17.1 = 0.67
2. Use a standard normal distribution table (z-table) to find the area under the curve between z₁ and z₂:
P(z₁) = 0.0537
P(z₂) = 0.7486
3. Subtract the probabilities to find the percentage of drivers between 17 and 56 years old:
P(17 ≤ age ≤ 56) = P(z₂) - P(z₁)
= 0.7486 - 0.0537 = 0.6949
So, approximately 69.49% of the drivers are between the ages of 17 and 56.
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Express the following absolute value inequality as two inequalities.
|x+2|>1
Answer:
it can be either one of this
x<-3 or x > -1
Imagine a list of all 5-digit numbers that have distinct digits. For example, 70364 and 93145 are two such numbers on the list, while 80628 is not on the list since it repeats the digit 8. 1. How many numbers are listed? 2. How many numbers on the list use the digit 0 at least once?
Imagine a list of all 5-digit numbers that have distinct digits. For example, 70364 and 93145 are two such numbers on the list, while 80628 is not on the list since it repeats the digit 8. 1. There are 27,216 numbers are listed. 2. There are 15,120 numbers on the list that use the digit 0 at least once.
1. For the first digit, we have 9 choices (1-9), as 0 cannot be the leading digit.
For the second digit, we have 9 choices (0-9, excluding the digit used in the first position).
For the third digit, we have 8 choices (0-9, excluding the digits used in the first and second positions).
For the fourth digit, we have 7 choices (0-9, excluding the digits used in the first, second, and third positions).
For the fifth digit, we have 6 choices (0-9, excluding the digits used in the first, second, third, and fourth positions).
Using the counting principle, the total number of 5-digit numbers with distinct digits is:
9 × 9 × 8 × 7 × 6 = 27,216
Therefore, there are 27,216 numbers listed.
2. To find the number of numbers on the list that use the digit 0 at least once, we can analyse the cases where the digit 0 is present.
Case 1: 0 is in the first position
In this case, we have 1 choice for the first position (0) and then proceed as before, so we have:
1 × 9 × 8 × 7 × 6 = 3,024 possibilities.
Case 2: 0 is in one of the other four positions
In this case, we have 4 choices for the position of 0 (second, third, fourth, or fifth), and the remaining digits can be filled in with the available choices. Therefore, we have:
4 × 9 × 8 × 7 × 6 = 12,096 possibilities.
Adding the possibilities from both cases, we have a total of:
3,024 + 12,096 = 15,120 numbers on the list that use the digit 0 at least once.
Therefore, there are 15,120 numbers on the list that use the digit 0 at least once.
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Please help me with this problem:What are the solutions to this equation?(t+2)^2 = 36Enter your answers in the boxes.The solutions are t = ___ or t = ___.
Solution:
Given the equation;
\((t+2)^2=36\)Step 1: Take square root of both sides;
\(\begin{gathered} \sqrt{(t+2)^2}=\sqrt{36} \\ \\ t+2=\pm6 \end{gathered}\)Step 2: Subtract 2 from both sides;
\(\begin{gathered} t+2-2=-2\pm6 \\ \\ t=-2\pm6 \end{gathered}\)Step 3: Separate the answers;
\(\begin{gathered} t=-2-6,t=-2+6 \\ \\ t=-8,t=4 \end{gathered}\)ANSWER:
\(t=-8, t=4\)WILL GIVE BRAINLIEST. Need an answer ASAP!
Solve for x:
A) 2
B) 10
C) 6
D)12
Answer:
B) 10
Step-by-step explanation:
5x - 18 = 2x + 12
5x = 2x +30
3x = 30
x = 10
A circular running track is 1/2 mile long. Elena runs on this track completing each lap in 6 minutes how long will it take Elena to run 3 miles?
Answer:
36 mins
Step-by-step explanation:
0.5 miles/6 mins = 3 miles/x mins
In order to convert the ratio from 0.5 miles to 3 miles, 0.5 was multiplied by 6. Therefore, to keep the ratio the same, 6 minutes must also be multiplied by 6 to find x. This means the answer is:
3 miles/36 mins
1. What is the y-intercept
2. What is the slope of the line?
3. What is the equation in slope intercept form?
4. What is the missing value in the table?
2.
Slope: m = (y2 - y1) / (x2 - x1)
m = (8 - 0) / (6 - 2) = 8 / 4 = 2
The slope is 2.
1 and 3:
Using the slope, we have:
y = 2x + b
Plugging in the point (2,0), this becomes:
0 = 2(2)+b
0 = 4 + b
-4 = b
So now we have both the slope-intercept form:
y = 2x - 4
and the y-intercept (0,-4).
4: If x = 40, then y = 2(40) - 4 = 80 - 4 = 76
The missing value is 76.
Solve for the unknown angles. Justify your answers with steps (do not just provide answers)
Answer:
Angle XYV= 120 degrees
Step-by-step explanation:
Remember that interior angles in a quadrilateral= 360 degrees and angles on a straight line= 180 degrees
angleWXY + angleYXV =180 degrees (angles on a straight line)
hence, 3x + x= 4x, 4x=180
x=45
angleYXZ + angleXYV + angleYVZ + angleVZX = 360 degrees(angle sum of quadrilateral)
hence, x+ angleXYV + 3x + 60 = 360
4x + angleXYV = 360
sub x= 45
angleXYV = 360-4(45)
=120
Consider the following data for MRP. Develop the material requirements plan for item B and C, and answer questions below
MPS start:
End item Week 1 Week 2 Week 3 Week 4 Week 5 Week 6
A 120 80
Bill of materials:
End item A is made of 1 unit of item B.
Item B is made of 2 units of item C.
MRP-related information for each item:
Item Leadtime (weeks) Lot sizing Safety stock On-hand inventory Scheduled receiptsB 1 L4L 0 30 60 in
week 1
C 2 FOQ (50) 20 80 None
What is the gross requirement for item B in Week 3?
i. 0 unit
ii. 80 units
iii. 120 units
iv. 200 units
v. 240 units
The gross requirement for item B in Week 3 is 80 units.
The gross requirement for item B in Week 3, we need to calculate the demand for item B based on the bill of materials and the requirements for item A.
From the MPS (Master Production Schedule) provided, we can see that the gross requirement for item A in Week 3 is 80 units.
According to the bill of materials, item A requires 1 unit of item B. Therefore, the gross requirement for item B can be calculated by multiplying the gross requirement for item A by the quantity needed for item B in the bill of materials.
Gross requirement for item B = Gross requirement for item A × Quantity needed for item B in bill of materials
Gross requirement for item B = 80 units × 1 unit
Gross requirement for item B = 80 units
Therefore, the gross requirement for item B in Week 3 is 80 units.
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I need help.......,.......... ...... ..... .....
Answer:
its a
Step-by-step explanation:
i just did this
A Rhombus has all its internal angles equal. If one of the diagonals is 15cm ,
find the length of the the other diagonal and the area of the Rhombus?
The area of the rhombus is approximately 112.5 square centimeters.
In a rhombus, all internal angles are equal, so we know that the opposite angles are congruent.
Additionally, the diagonals of a rhombus bisect each other at right angles, forming four congruent right triangles.
Let's denote the length of one diagonal as 15 cm, and the lengths of the sides of the rhombus as a.
Using the Pythagorean theorem, we can find the length of the other diagonal.
Let's label it as d.
In each right triangle, the hypotenuse is the length of a side, which is a, and one leg is half the length of the diagonal, which is 15/2 = 7.5 cm.
Applying the Pythagorean theorem, we have:
a² = (7.5)² + (7.5)²
a² = 56.25 + 56.25
a² = 112.5
a = √112.5
a ≈ 10.61 cm
Thus, the length of each side of the rhombus is approximately 10.61 cm.
Since the diagonals of a rhombus are perpendicular bisectors of each other, the other diagonal (d) is equal to the square root of the sum of the squares of the two sides.
Hence:
d² = a² + a²
d² = 2a²
d = √(2a²)
d = √(2 \(\times\) 10.61²)
d ≈ √(2 \(\times\) 112.5)
d ≈ √225
d ≈ 15 cm
So, the length of the other diagonal is approximately 15 cm.
To find the area of the rhombus, we can use the formula:
Area = (diagonal₁ \(\times\) diagonal₂) / 2
Substituting the values, we get:
Area = (15 \(\times\) 15) / 2
Area = 225 / 2
Area = 112.5 cm²
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Write the equation of the line that passes through the points (−9,−7) and (−4,4). Put your answer in fully reduced point-slope form, unless it is a vertical or horizontal line.
Answer:
y + 7 = 11/5(x + 9)Step-by-step explanation:
Given points:
(-9, -7) and (-4, 4)Find the slope:
m = (4 - (-7)) / (-4 - (-9)) = 11/5Use one of the points and point-slope form:
y - y1 = m(x - x2)y - (-7) = 11/5(x - (-9))y + 7 = 11/5(x + 9)Slope
m=(4+7)/-4+9m=11/5Equation in point slope form
y-y1=m(x-x1)y+7=11/5(x+9)Can I get help for a worksheet I think it’s like two step equations integers
Answer:
can u attach the worksheet
Step-by-step explanation:
3.14 and round to nearest hundredth
Step-by-step explanation:
3.14 is rounded to the nearest 100th (4 is the hundredth position)
HELP AND HURRY PLEES
Answer:
PJ
Step-by-step explanation:
J is at -9 which is 9 away from 0
P is at -9 which is 9 away from 0
4^2x+3=64^x-7
4 raised to the power of 2x+ 3= 64 raised to the power of x-7
Solve for x
Answer:
hehe
Step-by-step explanation:
please
why
If you sell 175 shares of Michaels Flowers at $7.28 per share and 445 shares of Nanotech One at $10.80 per share, howmuch money will you receive, to the nearest dollar? Show work.
Let be "t" the total amount of money you will receive.
According to the information given in the exercise, you can sell each share of Michaels Flowers at $7.28. Since you sell 175 of them, you get:
\((7.28\text{ }dollars)(175)=1,274\text{ }dollars\)You also know that you can sell each share of Nanotech One at $10.80. Therefore, the amount of money you'll receive for these shares of Nanotech One, can be calculated by multiplying the price of one share by the 445 shares you will sell:
\((10.80\text{ }dollars)(445)=4,806\text{ }dollars\)Then, you can set up that:
\(\begin{gathered} t=1,274\text{ }dollars+4,806\text{ }dollars \\ t=6,080\text{ }dollars \end{gathered}\)The answer is: $6,080
Alex has two designs to build a chest. In each design, the chest is a rectangular prism. Chest A has dimensions of 5 feet ×3 feet ×214 feet . Chest B has dimensions of 4 feet ×312 feet ×3 feet . Part A How much space does each chest hold? Include units in your answers. Chest A has of space. Chest B has of space. Question 2 Part B How much material is needed to build each chest? Include units in answer. Chest A needs of material. Chest B needs of material.
Answer:
I like turtlesion:
Step-by-step explanation:
the answer is easy you take 2 + 2 + 2 + 2 + 2 + 2 + 2 and then you got8 twos so you kind of want to do that and add another number to the 8th and then got 82 there's a step-by-step explanation and this is not actually not the answer I just want to fool around with some people
A shirt at the store is being offered at a 5% discount. If the original price of the shirt is , which answer choice shows an expression that represents the discounted price of the shirt?
The expression that represents the discount price of the shirt is (option a) 0.95x
Discount:
Discount causes the product's selling price to drop, which increases its allure for the consumer. Price reduction has a psychological effect on the buyer, influencing them to make the purchase. The two discounts available are trade discounts and cash discounts.
Given,
The discount percentage of the shirt in a store = 5%
Original price of the shirt = x
We have to find the expression that represents the discount price of the shirt:
Discount price = (Original price × (100 - Discount percentage) / 100
Discount price = (x × (100 - 5)) / 100
Discount price = (x × 95) / 100
Discount price = 0.95x
That is, the expression that represents the discount price of the shirt is (option a) 0.95x.
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The question is incomplete. Completed question is given below:
A shirt at the store is being offered at a 5% discount. If the original price of the shirt is x, which answer choice shows an expression that represents the discounted price of the shirt?
1. 0.95x
2. 1.05x
3. 0.05x
4. x + 0.05
Evaluate // / Vx2+ y2 dV, where E is the region that lies inside the cylinder x2 + y2 = 16 and between the planes z =-4 and z = 6
The value of the integral is 640V. we integrate with respect to r:
∫0^4 10Vr^2 r dr = (10/4)(4^4)V = 640V
To evaluate the integral of Vx^2 + y^2 dV over the given region E, we can use cylindrical coordinates since the region lies inside a cylinder.
First, we need to determine the limits of integration for each variable. For z, the limits are -4 to 6, since the region is between the planes z=-4 and z=6. For the cylindrical coordinates, we know that x^2 + y^2 = r^2, so the cylinder can be represented by r = 4. Therefore, the limits for r are 0 to 4, and the limits for theta are 0 to 2π.
Substituting in the cylindrical coordinates into the integral, we get:
∫∫∫E Vr^2 r dz dθ dr
= ∫0^2π ∫0^4 ∫-4^6 Vr^2 r dz dr dθ
Since the integral does not depend on theta or z, we can evaluate them first. The integral with respect to z gives:
∫-4^6 Vr^2 r dz = 10Vr^2 r
Next, we integrate with respect to r:
∫0^4 10Vr^2 r dr = (10/4)(4^4)V
= 640V
Therefore, the value of the integral is 640V.
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Determine the discriminant for the quadratic equation -3=x2+4x+1. Based on the discriminant value, how many real number solutions does the equation have?
Discriminant = b2-4ac
0
1
2
12
Answer:
Step-by-step explanation:
3=x^2+4x+1
x^2 + 4x + 4 = 0
Discriminant = 4^2 - 4*1*4 = 0
There is one real root (multiplicity 2).
The quadratic equation is x² + 4x + 4 = 0 and the number of solution is 1
What is Quadratic Equation?A quadratic equation is a second-order polynomial equation in a single variable x , ax² + bx + c=0. with a ≠ 0. Because it is a second-order polynomial equation, the fundamental theorem of algebra guarantees that it has at least one solution. The solution may be real or complex.
The roots of the quadratic equations are
x = [ -b ± √ ( b² - 4ac ) ] / ( 2a )
where ( b² - 4ac ) is the discriminant
when ( b² - 4ac ) is positive, we get two real solutions
when discriminant is zero we get just one real solution (both answers are the same)
when discriminant is negative we get a pair of complex solutions
Given data ,
Let the quadratic equation be represented as A
Now , the value of A is
-3 = x² + 4x + 1
Adding 3 on both sides , we get
x² + 4x + 4 = 0
Now , ( b² - 4ac ) is the discriminant
So , 16 - 4 ( 4 ) = 0
0 = 0
when discriminant is zero we get just one real solution
Hence , the quadratic equation is solved
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Dylan bikes to his part-time job, which is 10 mi. from home. If he rides at a constant rate of 8 mph, how long will it take him to get to work?
A. 1.25 hr.
B. 2.6 hr.
C. 4.5 hr.
D. 10 hr.
Answer:
Step-by-step explanation:
D
Identify the angle pair as either corresponding angles, alternate interior angles, same side interior angles.Find the measure of each angle indicated.7)8)+71Angle TypeAngle Measure7
7) alternate interior angle, Angle measure = 71°
8) alternate interior angle, Angle measure = 90°
Explanation:
Using an illustration:
7) The angle type is alternate interior angle
Alternate interior angle angles are equal.
Hence, the angle measure which is represented with question mark = 71°
8) The angle type is alternate interior angle
Alternate interior angle angles are equal.
The square in red represents 90°
Hence, the angle measure which is represented with question mark is 90°
On a map, 0.5 inches represents 30 miles. If it is 2.5 inches from point A to point B on the map, what is
the actual distance in miles?
green eggs and ham find the area of the domain enclosed by the curve with parametric equations x = tsin t, y = cost, t ∈ [0, 2π].
The area of the domain enclosed by the curve with parametric equations x = tsin t, y = cost, t ∈ [0, 2π] is 2π + 2.
The parametric equations given are:
x = t sin t
y = cos t
To find the area of the domain enclosed by the curve, we can use the formula for the area of a region bounded by a curve given in parametric form:
A = ∫[a,b] y dx
where a and b are the limits of the parameter t that describe the domain of the curve.
In this case, we have:
a = 0
b = 2π
So, we need to compute:
A = ∫[0,2π] cos(t) (t sin(t)) dt
Using integration by parts with u = t and dv = sin(t) dt, we get:
A = [t cos(t)]|[0,2π] - ∫[0,2π] cos(t) dt + ∫[0,2π] sin(t) dt
The first integral evaluates to:
[t cos(t)]|[0,2π] = 2π
The second integral evaluates to:
∫[0,2π] cos(t) dt = [sin(t)]|[0,2π] = 0
The third integral evaluates to:
∫[0,2π] sin(t) dt = [-cos(t)]|[0,2π] = 2
Therefore, the area of the domain enclosed by the curve is:
A = 2π - 0 + 2 = 2π + 2
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If x represents a number, write an expression that represents a number 10 greater than x
Answer:
Step-by-step explanation:
10.An order is written 700mg of ampicillin PO, the drug is supplied is liquid form as1g/3.5ml how much of the liquid should be given?
5.25ml 2.55ml 6.25ml 2.45ml
11.The order state meperidine 75mg IM every 6hours PRN pain. The pharmacy sends you a vial that states 25mg/2ml.how many ml can the nurse give in 24 hours?
12.The order state to give the patient 0.75g of antibiotic PO every 4 hours for 7 days The drug comes in 250mg tables. How many tablets should the patient take? 2tab. 3tab .4tab. 15tab.
13.Order is written for 1000ml of normal saline to be administered IV over 10hours.Thedrop factor on the IV tubing is 15gtt/ml. what is the IV rate?
50ml/hr.at50gtt/min 100ml/hr.at 25gtt/min 100ml/hr.at 100gtt/min 100ml/hr. at 15gtt/min
14.a post operative order is written for 15gr of codeine every 4 hours PRN for pain. Each dose given will contain how much milligrams of codeine
15.Robitussin cough syrup 225mg.PO is ordered the bottle read 600mg in 1oz how much cough syrup 225mg PO is ordered the bottle read600mg in 1oz how much cough syrup should be given in ml's?
Where the above are given,
10. The nurse should give 2.45ml of the liquid medication.
11. The nurse can give 24ml of meperidine in 24 hours.
12. The patient should take 42 tablets of the antibiotic.
13. The IV rate is 100ml/hr at 1500gtt/min with a 15gtt/ml drip factor.
14. Each dose of codeine contains 15000mg.
15. The patient should be given 2.67oz (approximately) of the cough syrup.
What is the explanation for the above ?10. To determine how much of the liquid should be given, we can set up a proportion
1g/3.5ml = 700mg/x
Cross-multiplying,
1g * x = 700mg * 3.5ml
x = (700mg * 3.5ml) / 1g
x = 2450mg*ml/g
Therefore, the amount of liquid to be given is 2.45ml.
11. The order states meperidine 75mg IM every 6 hours PRN pain, and the pharmacy sends a vial that contains 25mg/2ml. To calculate how many ml can be given in 24 hours, we need to consider the frequency and duration.
In 24 hours, there are 24/6 = 4 doses to be given. Each dose contains 75mg of meperidine.
To find the volume (ml) of each dose, we can set up a proportion -
25mg/2ml = 75mg/x
25mg * x = 75mg * 2ml
x = (75mg * 2ml) / 25mg
x = 6ml
12. To calculate the number of tablets the patient should take, we need to consider the dosage and the duration.
Each tablet contains 250mg of the antibiotic.
To find the number of tablets for the total dosage, we can set up a proportion -
250mg/1 tab = 0.75g/x
250mg * x = 0.75g * 1 tab
x = (0.75g * 1 tab) / 250mg
x = 0.003 tab
Since we cannot take a fraction of a tablet, the patient should take 1 tablet every 4 hours for 7 days, resulting in a total of 1 * 6 * 7
= 42 tablets.
13. To determine the IV rate, we need to calculate the number of drops per minute.
The formula to calculate the IV rate in drops per minute (gtt/min) is -
IV rate (ml/hr) = Total volume (ml) / Total time (hr)
IV rate (gtt/min) = IV rate (ml/hr) * Drop factor (gtt/ml)
IV rate (ml/hr) = 1000ml / 10hr = 100ml/hr
IV rate (gtt/min) = 100ml/hr * 15gtt/ml =
1500gtt/min
Therefore, the IV rate is 100ml/hr at 1500gtt/min.
14. To determine the amount of milligrams of codeine in each dose, we need to convert grams to milligrams.
1 gram (g) = 1000 milligrams (mg)
15 grams (gr) = 15 * 1000mg = 15000mg
Therefore, each dose contains 15000mg of codeine.
15. To calculate how much cough syrup should be given in ml's, we can set up a proportion -
225mg/1oz = x ml/600mg
225mg * x = 1oz * 600mg
x = (1oz * 600mg) / 225mg
x = 2.67oz
Therefore, 2.67oz of cough syrup should be given in ml's.
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Hector is giving an oral presentation about baking
chocolate chip cookies.
How should Hector end his presentation?
O by explaining materials needed
O by asking if there are questions
Oby stating what he is teaching
Oby providing the steps in order
Answer:
asking if there are any questions