1550-kg car rounds a circular turn of radius 145 m, toward the left, on a horizontal road. Its angular momentum about the center of the turn has magnitude 2.46 x 106 kg. m/s. Part A What is the direction of the car's angular momentum? away from the center of the turn vertically downward toward the center of the turn vertically upward Submit Previous Answers Correct Part B What is the speed of the car? Express your answer with the appropriate units. μΑ ? V= Value Units Submit Request Answer Part C What is the magnitude of the car's angular momentum about the center of the turn, once it's exited the turn and is on a straight stretch of the road? Express your answer with the appropriate units. μΑ ? Lfinal = Value Units

Blue giants are very massive stars, with masses of 10 to 30 times that of the Sun. They burn through their hydrogen fuel very quickly, lasting only a few million years.

During this time, they create a variety of heavier elements, including carbon, oxygen, neon, magnesium, and silicon.

When a blue giant dies, it can explode in a supernova, which releases even heavier elements into space. These elements can then be incorporated into new stars and planets, helping to create the building blocks of life.

Here is a table of some of the elements that are created by blue giants:

Element Atomic Number Created in Blue Giants

Carbon       6                                  Yes

Oxygen       8                                   Yes

Neon       10                                   Yes

Magnesium 12                              Yes

Silicon       14                                  Yes

It is important to note that the exact amount of each element that is created by a blue giant depends on its mass and its evolutionary stage. More massive blue giants will create heavier elements.

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Answer:

\(0.361\ \text{m}\)

Explanation:

\(f_s\) = Frequency of source = 375 Hz

\(\Delta f\) = Difference between the maximum and minimum sound frequencies = 2.75 Hz

v = Speed of sound in air = 343 m/s

T = Time period = 1.8 s

\(v_m\) = Maximum speed of the microphone

We have the relation

\(\Delta f=2f_s\dfrac{v_m}{v}\\\Rightarrow v_m=\dfrac{\Delta fv}{2f_s}\\\Rightarrow v_m=\dfrac{2.75\times 343}{2\times 375}\\\Rightarrow v_m=1.26\ \text{m/s}\)

Amplitude is given by

\(A=\dfrac{v_mT}{2\pi}\\\Rightarrow A=\dfrac{1.26\times 1.8}{2\pi}\\\Rightarrow A=0.361\ \text{m}\)

The amplitude of the simple harmonic motion is \(0.361\ \text{m}\).

Answer:

The sun and other stars consist of plasma. Plasma is also found naturally in lightning and the northern and southern lights. Human-made plasma is found in fluorescent lights, plasma TV screens, and plasma spheres

Explanation:

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The time taken by the boat to accelerate from zero to 90 km/hr over 1 km is 11.11 seconds, and the acceleration is 8.1 m/s2.

The problem has provided the initial speed of the boat as zero, and the final speed as 90 km/hr.

We need to find the time taken by the boat to accelerate from zero to 90 km/hr over 1 km.

We can use the formula of acceleration to solve this problem.

The formula is:

v = u + at

where, v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken

From the above formula, we can write:

90 = 0 + a * t

where acceleration is a, and time taken is t.

Therefore, a * t = 90...…..(1)

The boat has traveled 1 km, which is 1000 m.

We can use the formula of average speed to calculate acceleration.

The formula is:

v = d / t

where, v is the speed

d is the distance traveled

t is the time taken.

We can write this formula as:

t = d / v,

where distance traveled is d, and the speed is v.

Substituting the values in the above equation, we get:

t = 1000 / 90t = 11.11 seconds.

From equation 1, we get a = 90 / t,

substituting the value of t, we get:

a = 90 / 11.11

a = 8.1 m/s2

Therefore, the time taken by the boat to accelerate from zero to 90 km/hr over 1 km is 11.11 seconds, and the acceleration is 8.1 m/s2.

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Answer:

Minerals to Gemstones

Mineral Name Gemstone Name

Beryl Aquamarine, Beryl, Bixbite, Emerald, Goshenite, Heliodore, Morganite

Brazilianite Brazilianite

Chalcedony Agate, Aventurine, Bloodstone, Carnelian, Chrysoprase, Heliotrope, Jasper, Onyx, Sard

Chrysoberyl Alexandrite, Chrysoberyl

Answer:

The magnitude of swing's tension is 0.71 N.

Explanation:

Given;

mass of the ball, m = 18 g = 0.018 kg

angular speed of the ball, ω = 1 rev/s

radius of the motion, r = 1 m

Angular speed in rad/s is calculated as follows;

\(\omega = \frac{2\pi \ rad}{rev} \times \frac{1 \ rev}{s} \\\\\omega = 2 \pi \ rad/s\)

Linear speed of the ball, v;

v = ωr

v = 2π x 1

v = 2π  m/s

The magnitude of swing's tension is calculated as the centripetal force keeping the ball in circular motion.

\(F_c =T = \frac{mv^2}{r} \\\\T= \frac{0.018 \ \times (2\pi )^2}{1} \\\\T = 0.71 \ N\)

Therefore, the magnitude of swing's tension is 0.71 N.

The charge of a newly formed oxygen ion would be -2

Hope this helps :)

Answer:

4.43m/s

Explanation:

The centripetal acceleration is expressed as;

a = v²/r

v is the speed

r is the radius = 2.0m

centripetal acceleration = 9.8m/s²

Get the speed v;

v² = ar

v² = 2.0 * 9.8

v²= 19.6

v = √19.6

v = 4.43m/s

Hence the speed of the stone must be 4.43m/s

ANSWER: D. Rule of Law

is the answer

d. rule of law

rule of law .

Answer:

first one down second one up

Explanation:

Hello. You did not inform the experiment that Arthur is conducting, which makes it impossible for your question to be answered accurately. However, I will try to help you in the best possible way.

The hypothesis is an assumption that is made before the experiment is carried out. This hypothesis is formed with the observation of some phenomenon of nature where the researcher believes that two or more elements interact to form a result. In this case, the experiment is carried out to determine whether the assumption, that is, the hypothesis is false or true. In the event that an experiment determines that the hypothesis is false, two things may have occurred: (a) the experiment was set up, or analyzed incorrectly, (b) the elements tested have no relation to the observed phenomenon.

The orbiting body spends 25% of its time at a distance greater than the semimajor axis

In an elliptical orbit, the distance between the orbiting body and the central body varies with time. The semimajor axis is the longest distance between the two bodies, and it is also the average distance over one orbit.

The formula gives the length of an elliptical orbit:

L = 2πa√(1 - e^2)

in where e denotes the orbit's eccentricity and a denotes the semimajor axis. A circle has an eccentricity of 0, while an ellipse has an eccentricity of 1. (a parabola).

These are the formulas for the percentage of the orbit that is located on one side of the semimajor axis:

f = (1 - e) / 2

Therefore, the percentage of time that the orbiting body spends at a distance greater than the semimajor axis is:

100% x f = 100% x (1 - e) / 2

For example, if the eccentricity is 0.5, then the orbiting body spends 25% of its time at a distance greater than the semimajor axis:

100% x (1 - 0.5) / 2 = 25%

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The potential energy of the negative particle would be negative in this scenario. This is because the potential energy is a measure of the work that is done in moving a charged particle from one location to another in the presence of an electric field.

In this case, since both particles have negative charges, they will repel each other and the electric field between them is also repulsive.

As a result, it would require work to bring the negative particle closer to the stationary negative charge, and this work would be negative because it is being done against the repulsive electric field.

Therefore, the potential energy of the negative particle would be negative because it represents the amount of work that would be done by the electric field if the negative particle were to move from its current position to the position of the stationary negative charge.

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Explanation:

vertical force = 460,000 * sin(70) - 300,000

Fv = 187,717.75N

Explanation:

there are 8 groups of the periodic table

group number one is of the alkali metals

group number two use of the alkaline Earth metals

group number three is known as group (III)

group number for is known as group IV

group number V is known as group V group number six is known as group VI

group number seven is known as halogens

and group number eight is of the noble gases

the periodic table does not have 18 groups as the elements between group III and group IV all known as the transition metals.

In a car crash, things like crumple zones and air bags help by doing Reducing the momentum of the collision. Hence option B is correct.

because of crash peoples inside the car gets forced towards forward and they get impact on their body. when there is air bag in the car, When a car crashes, air bag gets swelled due to impact on crumble zone. Due to impact people forced forward inside the car and they gets collide on the swelled air bag where air bag reduces peoples momentum inside the bag. the force of impact gets absorbed by the air bag and people have less impact on their body.

hence option B is correct.

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Answer:

0.03s

Explanation:

Period of wave and its frequency are closely related. Period is the inverse of frequency.

The period of a wave is the time taken for a number of waves to pass through a particular point.

The frequency of a wave is the number of waves that passes through a point at a particular time.

So;

          f  = \(\frac{1}{T}\)  

f is the frequency

T is the period

   Period of the wave  = \(\frac{1}{30}\)   = 0.03s

Answer:

a

Explanation:

A changing electric field is induced by changing magnetic field.

The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field. Electric charges in motion create magnetic fields. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is travelling through a magnetic field. Tesla is the magnetic field intensity unit in the International System (SI) (T). The region around a magnet where the magnetic force manifests itself is known as the magnetic field. Electrical charges can move and create magnetic fields.

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kinetic energy is the force that needs to be dissipated in a collision.  The following statement is False.

Kinetic energy is not a force; it is a form of energy associated with the motion of an object. In a collision, kinetic energy is not the force that needs to be dissipated but rather a quantity that can be transferred or transformed during the collision. During a collision, forces act on the objects involved, causing them to change their motion. These forces can come from external sources or be generated internally due to interactions between the objects. The forces involved in a collision are responsible for altering the objects' velocities and momentum. Kinetic energy is related to the mass and velocity of an object and can be calculated using the equation:

Kinetic energy = (1/2) × mass × velocity^2

In a collision, the total kinetic energy of the system might change. Some collisions result in a transfer or transformation of kinetic energy between the objects involved, while in other cases, the total kinetic energy is conserved. The forces involved in a collision determine how the kinetic energy is distributed or dissipated. Energy can be transferred into other forms, such as heat, sound, or deformation of the objects involved, depending on the nature of the collision and the materials of the objects.

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Answer:

D

Explanation:

Answer:

D.

It reduces the rate at which electrons flow.

Answer:

The gravitational potential energy is 150J

Explanation:

P. E=mgh

=5*10*3

to find the modulus of elasticity MoE at 23% of moisture content based on the already given modulus of elasticity of 12% moisture content we need to consider a shrinkage behavior of material. the expected MoE comes out to be approximately \(6,836 N/mm².\)

given information:

Modulus of elasticity at 12% moisture content =7,920 N/mm²

resultant shrinkage or final shrinkage percentage FSP = 30%

To calculate the expected MoE at 23% moisture content we have the following equation:

MoE-23% =   \(MoE-12%\) \((1 - FSP (23 - 12) / (100 - 12))\)

MoE-23% = \(7,920 N/mm² × (1 - 0.30 × (23 - 12) / (100 - 12))\)

MoE-23% =\(7,920 N/mm² × (1 - 0.30 × 11 / 88)\)

MoE-23% = \(7,920 N/mm² × (1 - 0.1364)\)

MoE-23% = \(7,920 N/mm² × 0.8636\)

MoE-23% =  \(6,836 N/mm²\)

therefore the expected modulus of elasticity at 23% moisture content comes out to be approx \(6,836 N/mm²\).

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The solution to the calculation, rounded to the proper number of significant figures, is approximately 1654 J.

To find the solution to the calculation, we need to follow the rules of significant figures and perform the arithmetic operations step by step.

Subtract the given masses: (165.43 g - 78.15 g) = 87.28 g.

Calculate the temperature difference: (297.6 K - 292.8 K) = 4.8 K.

Multiply the mass difference by the specific heat capacity and the temperature difference:

(87.28 g) × (4.184 Jg^(-1) K^(-1)) × (4.8 K) = 1653.71776 J.

Round the result to the proper number of significant figures based on the given values.

The given values have the following significant figures:

165.43 g has 5 significant figures.

78.15 g has 4 significant figures.

4.184 Jg^(-1) K^(-1) has 4 significant figures.

297.6 K has 4 significant figures.

292.8 K has 4 significant figures.

Since we are multiplying and dividing, the result should have the same number of significant figures as the value with the fewest significant figures, which is 4.

Round the result to 4 significant figures: 1653.71776 J ≈ 1654 J.

Therefore, the solution to the calculation, rounded to the proper number of significant figures, is approximately 1654 J.

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Given that the radius of the circular path is r = 142 m and the coefficient of the friction is

The condition for the car to travel safely is

Frictional force = centrifugal force

Here, m is the mass of the car and the acceleration due to gravity is g = 9.8 m/s^2.

v is the maximum speed of the car.

The final equilibrium temperature (in °C) of the system when ice and water vapor are combined can be calculated using the principle of energy conservation and the specific heat capacities of ice and water.

To determine the final temperature, we can apply the equation:

(m₁ * c₁ * ΔT₁) + (m₂ * c₂ * ΔT₂) = 0

Where:

- m₁ is the mass of ice (22.0 kg)

- c₁ is the specific heat capacity of ice (2.09 J/g·°C)

- ΔT₁ is the change in temperature of ice (final temperature - 0.00 °C)

- m₂ is the mass of water vapor (4.80 kg)

- c₂ is the specific heat capacity of water (4.18 J/g·°C)

- ΔT₂ is the change in temperature of water (final temperature - 100.0 °C)

Solving for the final temperature, we find:

(22.0 kg * 2.09 J/g·°C * ΔT₁) + (4.80 kg * 4.18 J/g·°C * ΔT₂) = 0

Substituting the given values, we can solve for ΔT₁ and ΔT₂. Once we have those values, we can find the final temperature by adding ΔT₁ to 0.00 °C.

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Answer:

the equilibrant is equal in magnitude but opposite in direction.

Explanation:

In vector algebra, a resultant vector is a single vector that have the same effect as the effect of the net or algebraic sum of two or more vectors.

A resultant vector arises from finding the adding multiple vectors together.

When a group of vectors is replaced by a resultant vector, in order to keep the system of vectors at equilibrium, there is another vector which has the same magnitude as the resultant vector but acting in opposite direction to the resultant vector. This vector is called the equilibrant.

To an observer in New York State, the duration of daylight increases continuously from the winter solstice in December until the summer solstice in June.

After the winter solstice, which is the shortest day of the year, the days gradually become longer as we move towards spring and   the equinoxes in March and September, day and night are roughly equal in length. Following the spring equinox, the daylight hours become longer than the nighttime hours, resulting in a gradual increase in the duration of daylight. This continues until the summer solstice in June, which marks the longest day of the year.
It's important to note that while the overall trend is an increase in daylight duration, the rate of change varies throughout the year. During the transition seasons of spring and autumn, the rate of change is more balanced, while the rate of change is steeper around the solstices. This creates the distinct seasons and varying lengths of daylight experienced in New York State.

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6.5 m/s is the velocity of the boy when a 65.0-kg boy and 40.0-kg girl, both wearing skates, face each other at rest on a skating rink.

Mass of the boy, = 65kg

girl's mass given  , = 40 kg

Final velocity of the girl , = -4.00 m/s

By law of conservation of momentum

\(m_bv_ib+m_gv_ig=m_bv_fb+m_gv_fg\)

\(0=65kg(-4.0m/s)+40kgv_fg\)

\(v_fg=6.5m/s\)

When a body is travelling in a straight line, its velocity is the "rate of change of displacement with relation to time."Because it always has a direction, velocity is a vector. As a result, when the displacement to time ratio for linear velocity is determined, it provides both the direction and the magnitude.

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\(▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪\)

A solar flare is believed to occur when energy, stored in a twist in the solar magnetic field above a sunspot, is suddenly released.

According to the assertion, the sliding particle will dominate the downhill race between the rolling sphere, rolling cylinder, rolling hoop, and sliding particle.

Sliding friction is the resistance that any two items produce as they slide against one another. This friction, sometimes referred to as kinetic friction, is the force required to keep one surface moving along another.

Briefing : A sphere, a cylinder, and a hoop, all of mass M and radius R, are released from rest and roll down a ramp of height h and slopeθ. They are joined by a particle of mass M that slides down the ramp without friction.

for particle c = 0 where c is a constant that depends upon the object .

a=a (particle), rolling sphere c=2/5, a (cm) = 5/7a (particle) =0.71a (particle)

rolling cylinder ,c=1/2  ,a(cm)=2/3a (particle) =0.67a (particle), rolling hoop =0.50a (particle).

then we have ¹/₂ I cm ω² ₊¹/₂ Mv cm²=Mgh

ω=Vcm/R    ,   Icm = cMR²     where c is a constant that depends upon the object .

Mgh= ¹/₂(cMR²)(Vcm/R )+¹/₂M v cm² , therefore v cm =\(\sqrt2gh/\sqrt\ (1+c)\)

therefore , v(particle)>v(sphere)>v(cylinder)>v(hoop)

   and       a (particle)>a(sphere)>a(cylinder)>a(hoop).

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