13. The great pyramid was attributed to whose King of Egypt?​

Answer:

5 m/s

Explanation:

hope it helps:) u're welcome

The velocity of the duck must be 15 m/s towards the east which is explained below.

The force on a moving charge with some velocity under a magnetic field is given by:

F = qv×B

here q is the charge on the object

v is the velocity of the object

B is the magnetic field

v×B gives the direction of the force

B is towards the north, and Force is directed upwards, then velocity v should be towards the east.

3×10⁻¹¹ = 4×10⁻⁸× v × 5×10⁻⁵

v = 15 m/s

Learn more about magnetic force:

https://brainly.com/question/10353944?referrer=searchResults

Power = (work done) / (time to do the work)

Power = (750 joules) / (75 seconds)

Power = 10 joules/second

Power = 10 watts

Answer:

I’m pretty sure it’s C, the particles slip past each other

Explanation:

In a solid, particles are tightly packed, have strong attractive forces so as to keep the particles tightly packed, vibrate in place, and don’t slip past each other

Answer:

Zeros that follow non-zero numbers and are also to the right of a decimal point are significant.

Explanation:

For example:

0.300 has 3 significant figures.

5.400 has 4 significant figures.

Answer:

Neodymium (Nd)

Explanation:

An element is made up of atom, which contains three subatomic particles namely; proton, electron, and neutron. In a neutral atom, the number of protons determines the atomic number of that element and the atomic number of an element is the identity of that element in the periodic table.

Hence, a change in the proton number of an element means a change in the atomic number and ultimately a change of that element. In this question, Europium (Eu) element with atomic number, 63, loses three protons. This means that that atom now has 60 protons, which denotes the atomic number of another element called Neodymium (Nd).

Therefore, Europium (Eu) element has become Neodymium (Nd) due to loss of protons.

Assuming an inductor is connected to a 180-v ac line and the inductor has an induced voltage of 120 v, there are 60 volts available to push the current through the wire resistance of the coil.

To determine the voltage that pushes the current through the wire resistance of the coil, you'll need to consider the voltage across the inductor and the applied voltage from the AC line. Given that the induced voltage across the inductor is 120 V and the AC line voltage is 180 V, you can calculate the voltage across the wire resistance by using the formula:

Voltage across wire resistance = AC line voltage - Induced voltage across the inductor

Voltage across wire resistance = 180 V - 120 V = 60 V

So, there are 60 volts available to push the current through the wire resistance of the coil.

More on voltage: https://brainly.com/question/29009908

#SPJ11

Answer:

Static stretching.

Explanation:

It is static stretching because it is a form of stretching which u can do actively for a period of time and you hold position for about 30 to 60 seconds which allow the muscles and connective tissues to lengthen. It is done after work out with out movement in order to loosen up muscles so as to gain flexibility.

The ratio of the potentials of these surfaces is 1.2,

Option choice C is correct.

The potential at any point on an equipotential surface is constant.

Since both spheres are equipotential surfaces, the potential at the center of sphere A is equal to the potential at any point on sphere A, and likewise for sphere B.
The potential at the center of sphere A due to the point charge is given by the formula

V = kq/r,

where k is the Coulomb constant,

q is the charge,

and r is the distance from the charge to the point.

In this case,

V = kq/RA.
The potential at the center of sphere B due to the point charge is given by the same formula,

but with r = RB.

So V = kq/RB.
Taking the ratio of these two potentials, we get:
VA/VB = (kq/RA)/(kq/RB)
VA/VB = (RB/RA)
VA/VB = 0.0012/0.0010
VA/VB = 1.2.

Option choice C is correct.

For similar question on potentials.

https://brainly.com/question/14306881

#SPJ11

Answer:

""gravity. the force that pulls on objects and causes acceleration if the objects are not balanced by an opposing force. speed. distance traveled per unit time. Newton's Second Law of Motion.""

Explanation:

Answer:

59, 720 Joules

Explanation:

\(q = mc(t2 - t1) + m(lf) + mc(t2 - t1)\)

first term=ice to 0 degrees

second term=water to ice

third term-water to 30 degrees

\(q = 0.12 \times 2100 \times 20 + 0.12 \times 3.36 \times {10}^{5} + 0.12 \times 4200 \times 30\)

\(q = 59720 \: joules\)

Explanation:

1a. Free body diagram of a projectile accelerating downward in the presence of air resistance:

Free body diagram of a projectile accelerating downward in the presence of air resistance

b. Free body diagram of a crate being pushed across a flat surface at constant speed:

Free body diagram of a crate being pushed across a flat surface at constant speed

2a. Weight of the bag of sugar on the moon:

Weight = mass x acceleration due to gravity

On the moon, acceleration due to gravity is one-sixth of that on Earth, so

Weight on the moon = 2.0 kg x (1/6) x 9.81 m/s^2 = 3.27 N

b. Weight of the bag of sugar on Jupiter:

On Jupiter, acceleration due to gravity is 2.64 times that on Earth, so

Weight on Jupiter = 2.0 kg x 2.64 x 9.81 m/s^2 = 51.6 N

3a. To hold the block in equilibrium, the horizontal force must balance the component of the weight force that acts parallel to the incline. The weight force is given by:

Weight = mass x gravity

Weight = 3.0 kg x 9.81 m/s^2 = 29.43 N

The component of the weight force parallel to the incline is given by:

Force_parallel = Weight x sin(50.0o)

Force_parallel = 29.43 N x sin(50.0o)

Force_parallel = 22.58 N

Therefore, the magnitude of the horizontal force required to hold the block in equilibrium is 22.58 N.

b. The normal force on the block is equal in magnitude and opposite in direction to the component of the weight force that acts perpendicular to the incline. This is given by:

Force_perpendicular = Weight x cos(50.0o)

Force_perpendicular = 29.43 N x cos(50.0o)

Force_perpendicular = 22.52 N

Therefore, the magnitude of the normal force on the block is 22.52 N.

However, the electric field in the centre of the two plates will equal the total of the two electric fields generated by the plates and will be directed from the left plate to the right plate.

The electric fields E is a vector quantity that exists at all points in space. The electric field at a given point represents the force that would be exerted on a unit positive test charge if it were placed there.

The electric field is associated with the electric force that operates on any charge. E with a vector on top equals the start fraction, F with a vector on top divided by q equals the end fraction.

Newtons/coulomb, N/C N/Cstart text, N, slash, C, end text are the dimensions of an electric field. The electric force may be expressed in terms of an electric field, F, with a vector on top, equaling q, E, with a vector on top.

Learn more about Electric fields here:

https://brainly.com/question/15800304

#SPJ4

Answer:

Work, in physics, refers to the measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement.

Hey there!

Work is defined as the the force which gets applied to an object in order to displace (move) it. For example, you work in order to walk up & down the stairs. For this, you need to apply force as well. So, work done = force × distance.

Hope it helps!

Answer:

Yes

Explanation:

The hanging mass will be 0.101 kg.

The formula for calculating the mass of a hanging wire is given as;

m = (π/4) * [(ρL² /Y) * ΔL + L * Δρ]

where; m is the mass of the hanging weight,

            ρ is the density of the wire,

            L is the length of the wire,

            Y is Young's modulus of the wire,

           ΔL is the extension of the wire and

         Δρ is the change in the density of the wire.

In this case,

ρ = 7.86 x 10³ kg/m³L

  = 2.9 mD

  = 0.48 mm

  = 0.48 x 10⁻³ m

  = 4.8 x 10⁻⁴ mY

  = 2.0 x 10¹¹ N/m²ΔL

  = 1.4 x 10⁻³ m

Let US calculate the mass of the wire;

A = (π/4) * D²A

    = (π/4) * (4.8 x 10⁻⁴)²A

    = 1.80955737 x 10⁻⁷ m²ρL

    = 7.86 x 10³ kg/m³ * 2.9m

    = 22.794 kg Y

   = 2.0 x 10¹¹ N/m²m_wire

   = ρLA / Lm_wire

   = 7.86 x 10³ kg/m³ * 1.80955737 x 10⁻⁷ m² / 2.9m

  = 4.9091761 x 10⁻⁴ kg

Let's calculate the mass of the hanging weight using the mass formula.

m = (π/4) * [(ρL² /Y) * ΔL + L * Δρ]

m = (π/4) * [(7.86 x 10³ * 2.9² / 2.0 x 10¹¹) * 1.4 x 10⁻³ + 2.9 * 4.8 x 10⁻⁴]

m = 0.100615775 kg

Therefore, the hanging mass will be 0.101 kg.

Learn more about Young's modulus from the given link.

https://brainly.com/question/13257353

#SPJ11

Answer: C. They are regions in which strong magnetic fields make it difficult for fresh supplies of hot, ionized gas to reach the photosphere

Explanation:

Sunspots appear dark because they are regions in which strong magnetic fields make it difficult for fresh supplies of hot, ionized gas to reach the photosphere.

Sunspots are typically cooler than their surroundings. For example, the temperature of a large sunspot can be about 4,000 Kelvin which is lower than the temperature of the photosphere around it which is about 5,800 Kelvin.

Answer:

rubber

Explanation: because its the only insulator

The mass of baking soda required that will have a volume of 30 mL is  66 g.

The mass of a substance can be determined if the volume and the density of the substance are known.

The mass of a substance is related to the density and the volume of the substance by the following equation:

mass = density * volume

Considering the data provided about the baking soda:

volume of baking soda required = 30.0 mL

density of baking soda = 2.20 g/mL

Hence, mass of baking soda will be;

mass of baking soda = 2.20 g/mL * 30.0 mL

mass of baking soda = 66 g

Lear more about mass and density at: https://brainly.com/question/1354972

#SPJ1

The net force on the box perpendicular to the floor is

∑ F[perp] = F[normal] - mg = 0

where mg is the weight of the box. Then

F[normal] = mg = 147 N

so that

F[friction] = 0.3 F[normal] = 44.1 N

The net force parallel to the floor is

∑ F[para] = F[applied] - F[friction] = ma

where a is the acceleration of the box. Then

F[applied] = (15 kg) a + 44.1 N

Then the work done by the applied force is

W[applied] = ((15 kg) a + 44.1 N) (1 m) = (15a + 44.1) J

We can't find the exact amount of work without any more information. If the box is pulled with constant speed, then a = 0 so the work would be 44.1 J.

Answer:

A. Both open and close

Explanation:

just took the test

LOL diagrams are indeed a means to show how the electricity is collected in the system or process at different points in time as well as any changes in the system's overall energy.

Scientists refer to energy as the ability to work. Human civilization is feasible because people have learned how to change energy from one type to another and then use it to complete activities. There are many different kinds of energy, including electrostatic, chemical, nuclear, acoustical, light, heat, musculoskeletal, electrical, as well as nuclear energy.

Modern medical technologies, automobiles, computers, and a plethora of things are all fueled by energy. Particularly urgent is the need for affordable, reliable energy in rising economies. It might even save a person's life.

To know more about energy visit:

https://brainly.com/question/6572753

#SPJ4

Answer:

m/s

km/h

mph (mi/h)

Explanation:

These should be it

Answer:

kilometers per hour (km/h), meter per second (m/s) and miles per hour (mph).

Explanation:

Velocity and speed are calculated using the same units

The net force on the charge at A should be zero, the charge q should be negative, since the charges at B and C are negative. Therefore, the charge q should be -2.25 μC placed at the midpoint M of side BC.

What is Charge?

In physics, charge refers to a fundamental property of matter that describes how it interacts with electric and magnetic fields. All matter is made up of atoms, which in turn are composed of positively charged protons, negatively charged electrons, and neutral neutrons. Charge is carried by the electrons and protons in an atom, and it is measured in coulombs (C).

To keep the charge at point A in equilibrium, the net force on it due to the other charges should be zero. This means that the net force due to charges at B and C should balance each other out.

Let's assume that the charge q is placed at the midpoint M of side BC. We need to find the magnitude and sign of q such that the net force on the charge at A is zero.

Let's first calculate the distance between A and M. Since the triangle is equilateral, all sides are equal to 20 cm.

AM = BC/2 = 10 cm

Now, we can calculate the force on the charge at A due to the charge q at M using Coulomb's law:

F(AM) = k * (2q) / AM^2

where k is the Coulomb's constant.

Similarly, we can calculate the forces on the charge at A due to the charges at B and C:

F(AB) = k * (2 * (-3)) / AB^2

F(AC) = k * (2 * (-3)) / AC^2

Since the triangle is equilateral, AB = AC = 20 cm.

Now, let's consider the x-component of the net force on the charge at A. Since the charges at B and C are symmetrically placed with respect to the y-axis passing through A, the y-component of their forces will cancel out. Therefore, we only need to consider the x-component of their forces:

Fx(net) = F(AM) * cos(60) + F(AB) + F(AC)

where cos(60) = 1/2 is the cosine of the angle between the vectors AM and F(AM).

Since the net force on the charge at A should be zero, we have:

Fx(net) = 0

Substituting the values of F(AM), F(AB), F(AC), and cos(60), we get:

k * (2q) / AM^2 - k * 6 / AB^2 - k * 6 / AC^2 = 0

Simplifying this equation, we get:

2q = 9/2

Therefore, the magnitude of the charge q that needs to be placed at the midpoint M of side BC is:

|q| = 9/4 = 2.25

Since the net force on the charge at A should be zero, the charge q should be negative, since the charges at B and C are negative. Therefore, the charge q should be -2.25 μC placed at the midpoint M of side BC.

Learn more about Charge from given link

https://brainly.com/question/18102056

#SPJ1

Answer:

do human activity for the

Answer:

The mass flow rate of water from the tank can be found using the Bernoulli's equation which states that the total energy of a fluid remains constant along a streamline. Applying Bernoulli's equation between the surface of the water in the tank and the orifice at the bottom, neglecting the height difference, we get:

P/ρ + gh + 1/2 * V^2 = P₂/ρ + 1/2 * V₂^2

where P is the pressure at the surface of the water in the tank, ρ is the density of water, g is the acceleration due to gravity, h is the height of the water surface above the orifice, V is the velocity of water at the surface of the water in the tank, P₂ is the pressure at the orifice, and V₂ is the velocity of water at the orifice. Since the orifice is at the bottom of the tank, h is zero, and V₂ is the velocity of water discharging from the orifice, which can be calculated using the continuity equation:

A₁V = A₂V₂

where A₁ is the cross-sectional area of the tank, and V is the velocity of water at the surface of the water in the tank.

Combining these equations and solving for the mass flow rate, we get:

m_dot = A₂ * sqrt(2 * ρ * (P - P₂))

Now, if a pipe of area A₂ and length H/2 is attached to the orifice, the velocity of water at the end of the pipe will be different than the velocity of water discharging from the orifice. We can use the Bernoulli's equation again between the orifice and the end of the pipe to calculate the velocity of water at the end of the pipe:

P₂/ρ + 1/2 * V₂^2 = P₃/ρ + gh + 1/2 * V₃^2

where P₃ is the pressure at the end of the pipe, and V₃ is the velocity of water at the end of the pipe. Again, neglecting the height difference, we get:

P₂/ρ + 1/2 * V₂^2 = P₃/ρ + 1/2 * V₃^2

Since the pipe is attached to the orifice, the pressure at the end of the pipe is atmospheric pressure Po, and the velocity of water at the end of the pipe can be calculated using the continuity equation:

A₂V₂ = A₃V₃

where A₃ is the cross-sectional area of the pipe.

Combining these equations and solving for the increase in mass flow rate, we get:

Δm_dot = A₃ * sqrt(2 * ρ * (P₂ - Po))

To find the pressure at point C for the two cases, we need to apply the Bernoulli's equation between the surface of the water in the tank and point C. Neglecting the height difference again, we get:

P/ρ + 1/2 * V^2 = Pc/ρ + 1/2 * Vc^2

where Pc is the pressure at point C, and Vc is the velocity of water at point C. For the first case, where the pipe is not attached to the orifice, we can assume that the velocity of water at point C is negligible, i.e., Vc = 0. Solving for Pc, we get:

Pc = P - 1/2 * ρ * V^2

For the second case, where the pipe is attached to the orifice, we can assume that the velocity of water at point C

Answer:

v devided by m  and answer is 0.1

Explanation:

v

m