13. Curtis investigated the motion and forces of his dog pulling a wagon. He recorded his data in a table. Which conclusion can be supported by the evidence shown in the table?
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1 point
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A. The forces in entries 1 and 3 are balanced because the wagon is not turning.
B. The forces in entries 2 and 3 are unbalanced because there is a change in motion.
C. The forces in entries 1 and 2 are balanced because there is no change in speed.
D. Only entry 2 has unbalanced forces because there is a change in direction.

The period of motion is simple hormonic motion and the maximum speed of the particle is 0.0031s

(a) Simple harmonic motion is defined as "the motion of a mass on a spring when it is subject to the linear elastic restoring force given by Hooke's Law (F=-Kx). The motion experimented by the particle is sinusoidal in time and demonstrates a single resonant frequency".

(b) The equation that describes the simple harmonic motion is given by =

= X = Acos(ωt + θ)     [1]

And taking the first and second derivate of the equation (1) we obtain the velocity and acceleration function respectively.

For the velocity:

= V = dx/dt = -Aωsin(ωt + θ)        [2]

For the acceleration:

= A = dv/dt =  -Aω²cos(ωt + θ)           [3]

As we can see in equation [3] the acceleration would be maximum when the cosine term would be -1 and on this case:

= Aω² = 8x10³ m/s²

Since we know the amplitude A=0.002m  we can solve for ω like this:

= ω = √ (8000/0.002)

= ω = 2000 rad

And we with this value we can find the period with the following formula;

= T = 2π/ω = 0.0031s

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The complete question:

A 10 g particle undergoes SHM with an amplitude of 2.0 mm and a maximum acceleration of magnitude 8.0 multiplied by 103 m/s2, and an unknown phase constant ?.(a) What is the period of the motion?1 s(b) What is the maximum speed of the particle?

Answer:

first answer is 70 newtons the second answer is f = 250N

Answer:

How far from a point charge of +2.4x 10-6C must a test charge be placed to measure a field of 360 N/C? E-AV = 400 V = 2X104 N/C d =( 0.020 m 7.)

Explanation:

Answer:

1. A hiking

2. C

3. B

4. D

5. E

To find the tension in the cord, we can use the equation for wave speed and the given information about the distance and time it takes for the wave to travel between the supports. The tension in the cord is approximately 343 N.

The speed of a wave in a string can be calculated using the equation v = √(F/μ), where v is the wave speed, F is the tension in the cord, and μ is the linear mass density of the cord. Linear mass density (μ) is given by the equation μ = m/L, where m is the mass of the cord and L is its length.

In this case, the wave travels a distance of 8.1 m in a time of 0.80 s. Therefore, the wave speed can be calculated as:

v = d/t = 8.1 m / 0.80 s = 10.125 m/s

Now, we need to find the linear mass density (μ) of the cord. The mass of the cord is given as 0.45 kg, and the length of the cord is 8.1 m. Hence,

μ = m/L = 0.45 kg / 8.1 m = 0.0556 kg/m

Using the wave speed and linear mass density, we can rearrange the equation v = √(F/μ) to solve for F (tension):

F = v^2 * μ = (10.125 m/s)^2 * 0.0556 kg/m ≈ 343 N

Therefore, the tension in the cord is approximately 343 N.

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Answer:

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The magnitude of the total electric field at the origin is calculated to be 1.37 x 10^5 N/C.

The first step in solving this problem is to calculate the electric field at the origin due to each point charge individually using the formula E=kq/\(r^{2}\), where k is the Coulomb constant, q is the charge, and r is the distance from the charge to the origin. Then, we can use the principle of superposition to add the electric field vectors from each point charge together to find the total electric field at the origin. The magnitude of the total electric field at the origin is calculated to be 1.37 x \(10^{5}\) N/C.

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Answer:

2

Explanation:

Answer:

Explanation:

For free body diagram see attached sheet .

W is weight of steel girder acting at the middle point of its length . T is tension in the cable .

OB = √ ( 12² - 2² )

= 11.83 m .

OC = 11.83 / 2 = 5.915 m

Taking moment of tension T and weight W about point O

W x OC = T x OB

22 x 5.915 = T x 11.83

T = 22 x 5.915 / 11.83

= 11 kN

Considering forces acting in vertical direction and equating forces in opposite direction

T + R = W

R = W - T

= 22 - 11 = 11 KN

So force of grinder on the ground = R

= 11 KN.

Answer:

161.28m

Explanation:

The resultant is calculated using the formula

R² = dx²+dy²

R = √dx²+dy²

From the diagram. dx = 101cos60°+85

dx = 101(0.5) + 65

dx = 50.5 + 85

dx = 135.5m

For the vertical component dy

dy = dsin theta

dy = 101 sin 60

dy = 101(0.8660)

dy = 87.47

R = √135.5²+87.47²

R = √18,360.25+7,651.0009

R = √26,011.2509

R = 161.28m

Hence the magnitude of the sum of the vectors is 161.28m

Answer:

The sum of the two vectors is 161.278 m.

Explanation:

Given;

vector, B = 101 m inclined at angle 60⁰

vector, A = 85 m inclined at angle 0⁰

Y-component of the vectors;

\(R_y = 101(sin \ 60^0) + 85(sin \ 0^0) =87.466 \ m\)

X-component of the vectors;

\(R_x = 101(cos \ 60^0) + 85(cos \ 0^0)\\\\R_x = 50.5 + 85 = 135.5 \ m\)

Sum of the two vectors;

\(R = A+ B\\\\R = \sqrt{R_y^2 + R_x^2} \\\\R = \sqrt{87.466^2 \ + \ 135.5^2} \\\\R = \sqrt{26010.55} \\\\R = 161.278 \ m\)

Therefore, the sum of the two vectors is 161.278 m.

The radius of curvature (R) of the convex security mirror can be calculated by using the mirror formula is found to be 2.40 m.

We can use the mirror formula, which relates the object distance (p), image distance (q), and focal length (f) of a spherical mirror as follows:

1/f = 1/p + 1/q

For a convex mirror, the focal length is negative, so we can write:

1/f = -1/p + 1/q

We also know that the magnification (M) of an image formed by a spherical mirror is given by:

M = -q/p

where a negative sign indicates that the image is inverted.

Using the given information, we can write:

M = -q/p = 0.26 and p = 3 m

Substituting these values in the magnification equation, we get:

q = M × p = 0.26 × 3 m = 0.78 m

Now, using the mirror formula, we can solve for the focal length as follows:

1/f = -1/p + 1/q = -1/3 m + 1/0.78 m

Simplifying this expression, we get:

1/f = -0.447 + 1.282

1/f = 0.835

Therefore, the focal length of the convex mirror is:

f = 1/0.835 m ≈ 1.20 m

The radius of curvature (R) of the mirror is twice the focal length, so we have:

R = 2f ≈ 2 × 1.20 m ≈ 2.40 m

Therefore, the radius of curvature of the convex security mirror is approximately 2.40 meters.

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A positively charged object would attract negative charges from the electroscope, reducing the positive charge on the top plate and causing the foil leaves to move closer together. Option C

When an electroscope is given a positive charge, the foil leaves will separate due to the repulsion between the like charges. When an object is brought near the top plate of the electroscope, it will influence the distribution of the charges on the electroscope, causing the foil leaves to either move closer or further apart.
If the foil leaves separate even further, it means that the object brought near the electroscope is causing the top plate of the electroscope to become even more positively charged. This would happen if the object has a negative charge, as the negative charges on the object would attract positive charges from the electroscope and cause them to accumulate on the top plate, further separating the foil leaves.
Therefore, we can conclude that the object is negatively charged, option (C). This is because a positively charged object would attract negative charges from the electroscope, reducing the positive charge on the top plate and causing the foil leaves to move closer together. If the object was electrically neutral, it would have no effect on the electroscope and the foil leaves would remain the same distance apart.
Option (D) is incorrect because it suggests that any charged object could cause the foil leaves to separate even further, regardless of the type of charge. Option (E) is also incorrect because an uncharged object would have no effect on the electroscope and the foil leaves would remain the same distance apart. So, option C is correct.

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The apparent weight of a 72 kg passenger at the lowest point of a circle is 0 N (weightless).

The apparent weight of an object is the force exerted on it by a supporting surface. Apparent weight is determined by the gravitational force acting on an object and the normal force acting on it. In the case of a passenger at the lowest point of a circle, the normal force is equal to the gravitational force, thus the apparent weight is 0 N. At the lowest point of a circle, the gravitational force and the normal force acting on an object are in the same direction, and the gravitational force is acting in the opposite direction of the normal force, so the two forces cancel out each other, resulting in an apparent weight of 0 N. The passenger will feel weightless.

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The rise in the water's temperature, given that 18200 joules was transferred to the 100.0 g of water is 43.5 °C

Heat transferred I related to temperature rise by the following formula:

Q = MCΔT

Where

With the above formula, we can determine the temperature rise as illustrated below.

The following data were obtained from the question:

Q = MCΔT

18200 = 100 × 4.184 × ΔT

18200 = 418.4 × ΔT

Divide both sides by 418.4

ΔT = 18200 / 418.4

ΔT = 43.5 °C

Thus, we can conclude from the above calculation that the temperature rise of the water is 43.5 °C

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Answer:

Electrolytic manganese dioxide (EMD) is used in zinc-carbon batteries together with zinc chloride and ammonium chloride. EMD is commonly used in zinc manganese dioxide rechargeable alkaline (Zn RAM) cells also. For these applications, purity is extremely important.

Explanation:

hope this helps...

Answer:

Without the ability to measure, it would be difficult for scientists to conduct experiments or form theories. Not only is measurement important in science and the chemical industry, but it is also essential in farming, engineering, construction, manufacturing, commerce, and numerous other occupations and activities.

Explanation:

Make sure to edit so you're not copy-writed and if this was helpful could I please get brain-list

Let's calculate the equivalent resistances on both circuits.

On Diagram A we have a series connection of the resistors. The equivalent resistance will be the sum of all resistances:

\(R_{eq}=1+1+1\\\\\boxed{R_{eq}=3\Omega}\)

On diagram B we have a parallel connection of the resistors. The reciprocal of the equivalent resistance will be the sum of the reciprocals of all the resistances:

\(\frac{1}{R_{eq}} = \frac{1}{1} +\frac{1}{1} +\frac{1}{1} \\\frac{1}{R_{eq}}=3\\\\\boxed{R_{eq}=\frac{1}{3}}\)

Therefore, the larger resistance occurs on diagram A.

For the current, recall

\(V=IR\)

Where \(I\) stands for current \(R\) is the resistance and \(V\) is the voltage. Rearranging the equation we have

\(I = \frac{V}{R}\)

We can see that the larger the resistance, the smaller the current gets. So the larger current must happen in the diagram with smaller resistance. Therefore, the larger current occurs on diagram B.

Glad to help, wish you great studies ;)

Mark brainliest if you deem the answer worthy

Answer:

Net force

Explanation:

Bruh, easy question

Answer:

I'm pretty sure it's called Astronomy

Explanation:

Hope this helps:)...if not then sorry for wasting your time and may God bless you:)

Answer: Astronomy

Explanation: Astronomy is objects we can see with our eyes, like the Sun , the Moon , the planets, and the stars . It also includes objects we can only see with telescopes or other instruments, like faraway galaxies and tiny particles.

I hope this helps ;o o;

The energy of nuclear fission is released as kinetic energy of the fission products and fragments, and as electromagnetic radiation in the form of gamma rays; in a nuclear reactor, the energy is converted to heat as the particles and gamma rays collide with the atoms that make up the reactor and its working fluid, ...

Given,

The mass is m=1200kg

Height is h=14 m

Power is P=9kW

We know

Energy per unit time is power.

Thus,

P=mgh/t

where t is the time.

Thus,

The time is 18.312 sec.

Answer: That is not a question.

Explanation: It is a random jumble of letters. It also has no question mark.

No option , The curler apply to the stone to bring it up to speed is  42.85 N.

F = 20*3/1.4 = 42.85 N

3 *3 = 2*u*9.8*40

u = 0.0114

Despite their similarities, distance and displacement have very different meanings, as do speed and velocity. Speed, a scalar quantity, describes "how quickly an object is travelling." You can think of speed as the rate at which an object travels a distance. An object moving quickly has a high speed and travels a fair distance in a brief period of time. In contrast, a slow-moving object travels a comparatively short distance in the same amount of time because of its low speed. Zero speed refers to an object that is completely stationary.

[Speed = Distance Time] is the general formula for calculating an object's speed. The SI speed unit is m/s.

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The two resistors in parallel behave like 3 ohms.

I = V / R

Current = 12/3 = 4 Amps

The wavelength of a 650.00 Hz sound in air at room temperature and pressure, where the velocity of sound is 344 m/s, is approximately 0.529 m.

Sound waves travel through a medium by creating compressions and rarefactions. The wavelength of a sound wave is the distance between two consecutive points that are in phase, such as two compressions or two rarefactions. To calculate the wavelength, we can use the formula: wavelength = velocity of sound / frequency.

In this case, the frequency of the sound is 650.00 Hz, and the velocity of sound in air at room temperature and pressure is 344 m/s. Plugging these values into the formula, we get: wavelength = 344 m/s / 650.00 Hz = 0.529 m.

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Answer:

true

Explanation:

Yes, GPS stand-alone approach with vertical guidance provided by WAAS-equipped receivers makes it a precision approach.

The precision approach is defined as an instrument approach and landing with a minimum descent altitude (MDA) of less than 250 feet for aircraft with category I approach speeds. These approaches are either vertically guided, horizontally guided, or both. The following are the types of precision approaches:

ILS (Instrument Landing System), GLS (Global Navigation Satellite System Landing System), MLS (Microwave Landing System), GBAS (Ground Based Augmentation System), and WAAS GPS (Wide Area Augmentation System).

The Wide Area Augmentation System (WAAS) is a set of ground-based stations that correct the GPS signal. WAAS provides an accurate, reliable GPS signal for flight planning and navigational purposes. The system corrects errors in GPS satellite signals caused by atmospheric interference, satellite clock drift, and ephemeris errors, resulting in a more precise GPS signal.

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