12 students is what percent of 60 students?

Answer:

a rigt angle is a total of 90 degrees so subtratct 51 from 90 and you get 39 degrees.

The easiest way is to transform this equation to intercept form of straight line.

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Intercept form of straight line:

where \(a\) is the x intercept - where the graph intersects the x axis, and \(b\) is the y intercept - where the graph intersects the y axis.

\(\\\)

Given that,

\(2y + x = 20\)

\( \longrightarrow \: \dfrac{2}{20}y + \dfrac{x}{20} = 1\)

\( \longrightarrow \: \dfrac{x}{20} + \dfrac{y}{10} = 1\)

On comparing with \(\dfrac{x}{a}+\dfrac{y}{b}=1,\) we get,

Hence, the graph shall cut the x axis and y axis at 20 and 10 respectively. This information is enough to plot the graph.

\(\\\)

Graph: Refer to the attachment.

Based on the given information, the second brand, Cola, is the more affordable option in terms of cost per milliliter compared to Co Fizz.

To determine which brand of cola is more expensive, we need to compare the cost per unit volume for each brand.

For the first brand, Co Fizz, a pack contains 4 bottles, and each bottle has a volume of 500 ml. The cost of the pack is $2.50. Therefore, the total volume in a pack is 4 * 500 ml = 2000 ml. To find the cost per milliliter (ml), we divide the total cost by the total volume: $2.50 / 2000 ml = $0.00125 per ml.

For the second brand, Cola, a pack contains 10 bottles, and each bottle has a volume of 330 ml. The cost of the pack is $2. Therefore, the total volume in a pack is 10 * 330 ml = 3300 ml. To find the cost per milliliter (ml), we divide the total cost by the total volume: $2 / 3300 ml ≈ $0.000606 per ml.

Comparing the two brands, we can see that the cost per milliliter for Co Fizz is $0.00125, while the cost per milliliter for Cola is approximately $0.000606.

Since the cost per milliliter for Co Fizz is higher than the cost per milliliter for Cola, it can be concluded that Co Fizz is more expensive in terms of price per unit volume.

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The absolute functions |3x - 1| - |2x + 5 - (5 - x)| = 0,  |2(x + 1) - 4| - 4| = |2 - 2(2 - x)|, |(x - 2) / 4| - 1/3 = x and 1/2|x - 3| - 1 = |x - 3| + 2 have solutions of 1/6, 1, 2/15 and no solutions respectively

An absolute value function is a function in algebra where the variable is inside the absolute value bars. This function is also known as the modulus function and the most commonly used form of the absolute value function is f(x) = |x|, where x is a real number. Generally, we can represent the absolute value function as, f(x) = a |x - h| + k, where a represents how far the graph stretches vertically, h represents the horizontal shift and k represents the vertical shift from the graph of f(x) = |x|. If the value of 'a' is negative, the graph opens downwards and if it is positive, the graph opens upwards.

In the questions given;

1) |3x - 1| - |2x + 5 - (5 - x)| = 0

x = 1/6

2) |2(x + 1) - 4| - 4| = |2 - 2(2 - x)|

x = 1

3) |(x - 2) / 4| - 1/3 = x

x = 2 / 15

4) 1/2|x - 3| - 1 = |x - 3| + 2

The equation has no solution

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Answer: 20

Step-by-step explanation:

The value of angle Y (m∠Y) in the given parallelogram is determined as 112⁰.

The value of angle Y is determined by applying the principle of a quadrilateral for the given parallelogram as shown below.

The adjacent angles of a parallelogram are supplementary, that is they add up to 180 degrees, while the opposite angles are equal or congruent.

From the given diagram angle W = angle Y (opposite angles)

angle W + angle Z = 180 (adjacent angles )

angle W = 180 - angle Z

angle W = 180 - 68

angle W = 112

Therefore, angle Y (m∠Y) = 112⁰.

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An example of a one-to-one function that is an isomorphism between sets P and Q is the function f: P -> Q defined as f(x) = 2x, where P and Q are the sets of integers.

An example of a one-to-one function that is an isomorphism between sets P and Q is the function f: P -> Q defined as f(x) = 2x, where P and Q are the sets of integers.

This function is one-to-one because for every element x in P, there is a unique element 2x in Q. It is onto because every element y in Q has a preimage x in P such that f(x) = y (e.g., y/2 = x).

Furthermore, this function preserves the group structure between P and Q, as it satisfies the properties of an isomorphism. In this case, the group structure is addition, and the function f preserves addition: f(x + y) = 2(x + y) = 2x + 2y = f(x) + f(y) for all x, y in P.

Therefore, the function f: P -> Q defined as f(x) = 2x is an example of a one-to-one function that is an isomorphism between sets P and Q.

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Answer:

Lol, okay Bob will get $42,069 if he posts all his memes! Man, where can I get a job like that?!

14,023 x 3 = 42,069

Answer:

42,069

Step-by-step explanation:

nice

Answer:

f(x) = 1/x

Step-by-step explanation:

The corrected question is:

Suppose f is the function that satisfies  

f'(x)= - f²(x)  

for all x in its domain, and  

f(1) = 1  

f(x)= ?

Given:

f'(x) = -(f(x))²

This can be written as:

df/dx = -f²

The equation becomes:

-df/f² = dx

Integrating the above equation on both sides we get:

1/f = x + c     where c is constant

So

f(x) = 1/(x+c)

Now given that:

f(1) = 1  

Solving this for c we get:

f(1) = 1 = 1/(1 + c)

1 = 1/ 1+c  

1 = 1 + c

c = 1 - 1

c = 0

Now put this value of c in f(x) = 1/(x+c)

f(x) = 1/(x+0)

f(x) = 1/(x)

f(x) = 1/x

Hence

f(x) = 1/x

Answer:

1/6

Step-by-step explanation:

6 sides. 1 face with number 1. 1/6

Answer:

The answer is 120

Answer: Yes, it is a function

Step-by-step explanation:

For the given polynomial the roots can't have multiplicity, and the polynomial is:

p(x) = (x - 2)*(x - 3)*(x - 5).

Here we know that we have a cubic polynomial (of degree 3) with the following zeros:

2, 3, and 5.

Can any of the roots have multiplicity?

No, because a cubic polynomial can have at maximum 3 zeroes, and here we already have 3.

Now let's get the polynomial

Remember that a cubic polynomial with zeros a, b, and c can be written as:

p(x) = (x - a)*(x - b)*(x - c)

Then the polynomial in this case is:

p(x) = (x - 2)*(x - 3)*(x - 5).

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Step-by-step explanation:

\( \frac{2}{3} \times \frac{99}{1} = 66 \: kg\)

Answer:

Here’s all the answers

Answer:

Step-by-step explanation:

67

Alijah's taxable income puts him in the first tax bracket, over $8,350 but not surpassing $33,950. Hence, his tax due is a base of $835 plus 15% of the income that exceeds $8,350. This results in a total tax payable of $850. Option B is the correct answer.

Alijah's taxable income falls within the first bracket of the tax table given, being over $8,350 but not over $33,950.

This bracket requires him to pay a tax of $835.00 plus 15% of the amount over $8,350.

He has a surplus of $100 over the $8,350 threshold (i.e., $8,450 - $8,350), and 15% of $100 equals $15.

Therefore, the total tax he owes would be the fixed amount of $835.00 plus the $15.00 calculated, which sums up to $850.00.

Thus, looking at the provided options, option B ($850.00) would be the correct answer.

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To multiply 3/4 by 16/9, you can multiply the numerators (top numbers) together to get the new numerator, and multiply the denominators (bottom numbers) together to get the new denominator. Then, simplify the resulting fraction if possible.

So,

(3/4) x (16/9) = (3 x 16) / (4 x 9)

= 48/36

= 4/3

Therefore, 3/4 multiplied by 16/9 is equal to 4/3.

Answer:

d) 1/12

Step-by-step explanation:

Answer:

$58

Step-by-step explanation:

Here, n = 80

Therefore,

$(0.10n + 50) =$[(0.10×80)+50] = $(8.00+50) = $58.00

Answer:

$58

Step-by-step explanation:

Algebraically, the amount of money the insurance company will pay, represented as P, is equal to the total value of the stolen items (2b + t) minus the deductible (d).

Let's denote the amount of money the insurance company will pay as P. In this scenario, if the value of the stolen items is greater than the deductible, the insurance company will cover the loss, and Ron will receive compensation for the stolen items.

The total value of the stolen items can be calculated by adding the value of the bicycles (2b) and the value of the tools (t). So, the total value of the stolen items is 2b + t.

If the total value of the stolen items is greater than the deductible (d), then the insurance company will pay the difference between the total value and the deductible. Mathematically, this can be represented as:

P = (2b + t) - d

Therefore, algebraically, the amount of money the insurance company will pay, represented as P, is equal to the total value of the stolen items (2b + t) minus the deductible (d).

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Answer:

Step-by-step explanation:

Hello

Please what’s the explanation to get the answer (2+2) ² (2+3)³

we use PEMDAS

Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right).

(2 + 2)² + (2 + 3)³ =

4² + 5³ =

16 + 125 =

141

the answer is in the picture

#carry on learning

Using the radius of the Ferris wheel and the angle between the two positions, the time spent on the ride when they're 28 meters above the ground is 12 minutes

The radius of the Ferris wheel is 30 / 2 = 15 meters.

The highest point on the Ferris wheel is 15 + 4 = 19 meters above the ground.

The time spent higher than 28 meters is the time spent between the 12 o'clock and 8 o'clock positions.

The angle between these two positions is 180 degrees.

The time spent at each position is 10 minutes / 360 degrees * 180 degrees = 6 minutes.

Therefore, the total time spent higher than 28 meters is 6 minutes * 2 = 12 minutes.

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Answer:

\(\displaystyle y' = \frac{5x^2 + 3}{3(1 + x^2)^\bigg{\frac{2}{3}}}\)

General Formulas and Concepts:

Pre-Algebra

Algebra I

Algebra II

Calculus

Derivatives

Derivative Notation

Derivative Property [Multiplied Constant]:                                                              \(\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)\)

Derivative Property [Addition/Subtraction]:                                                            \(\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]\)

Basic Power Rule:

Derivative Rule [Chain Rule]:                                                                                       \(\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)\)

Logarithmic Derivative:                                                                                                \(\displaystyle \frac{d}{dx} [lnu] = \frac{u'}{u}\)

Implicit Differentiation

Step-by-step explanation:

Step 1: Define

Identify

\(\displaystyle y = x\sqrt[3]{1 + x^2}\)

Step 2: Rewrite

Step 3: Differentiate

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Implicit Differentiation

Book: College Calculus 10e

Answer:

Step-by-step explanation:

The correct option that indicates the quadrant that contains the translation of the shaded figure is the option B

B. III

A translation is a transformation in which the size, relative position of the points on the pre-image, are preserved but the location of the pre-image changes to obtain the image.

The shape of the shaded figure is an L-shape

The geometric figure in quadrant II and IV are a reflection of the shaded figure, across the y-axis and across the x-axis, respectively which is not a translation transformation.

The geometric figure in quadrant III can be obtained from the shaded figure by a translation 4 units to the left and 5 units downwards, which can be expressed as <-4, -5>, which is a translation transformation, therefore;

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Answer:

Parallelogram ABCD was translated to parallelogram A'B'C'D'. ... When ΔRST is translated 4 units down, what is the coordinate of T'? ... C.​ ​7 units left and 5 units down. B. 7 units right and 5 units up. D. ... If the triangle DOG with coordinates (2, 2), (2, 10), (8, 6) is translated six units left and three units.

Step-by-step explanation:

x=5

steps

they are vertical angles

they are equal

4x+90=110

4x=20

x=5

Answer:

Step-by-step explanation:

9900

The 0.0035 hr⁻¹ first-order degradation rate constant in the 40 °C, 1.0 mg/ml solution, where R = 1.987 cal/mol/degree and 2,000 cal/mol activation energy indicates;

a. The rate constant for first-order degradation of N₂O₂ at room temperature is approximately 4.12595 × 10⁻² hr⁻¹

A first order reaction is one that has a rate that varies linearly with the concentration of one reactant

The given parameters are;

Temperature of the solution = 40°C

T₁ = 40 °C + 273.15 = 313.15 K

The rate constant, K₁ = 0.00351 hr⁻¹

Concentration of the solution = 1.0 mg/ml

Activation energy, Eₐ = 2000 Cal/mol

R = 1.987 cal/mol/degree

The formula by which the rate constant can be found is presented as follows;

\(log\dfrac{k_2}{k_1} =\dfrac{E_a}{2.303\times R} \times \dfrac{T_2-T_1}{T_1\cdot T_2}\)

a. Room temperature = 25 °C

T₂ = 25 °C + 273.15 = 298.15 K

Therefore;

\(log\dfrac{k_2}{0.00351} =\dfrac{2000}{2.303\times 1.987} \times \dfrac{313.15-298.15}{313.15 \times 298.15}\)

\(k_2=0.00351 \times 10^{\left(\dfrac{2000}{2.303\times 1.987} \times \dfrac{313.15-298.15}{313.15 \times 298.15}\right)} \approx 4.12595\times 10^{-2}\)

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