12. In the last three months mr sharma lost 11\2 kg gained 9\4 kg and then lost 15\4 kg. if he now weigh 95 kg, how much did me sharma weigh to begin with ?
(a)100 kg (b)102kg
(c) 106.5. (d) 104kg
​

Answer: c) The line shows a change in speed if its angle changes.

I'm not sure

Explanation:

Answer:

They weight the same, they're both 1 kilogram

The weight of the given objects is the same since they have equal mass.

The weight of an object is the gravitational pull of earth on the object. Weight is vector quantity because it varies from place to place due to difference in acceleration due to gravity.

W = mg

W = 1 x 9.8

W = 9.8 N

W = mg

W = 1 x 9.8

W = 9.8 N

Thus, the weight of the given objects is the same since they have equal mass.

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The correct statement among the given options is b. The image could be real or virtual, depending on how far the object is past the focal point.

This statement accurately describes the behavior of a lens. When an object is placed beyond the focal point of a lens, a real and inverted image is formed on the opposite side of the lens.

This situation corresponds to a real image. However, if the object is placed between the lens and its focal point, the image formed is virtual, upright, and on the same side as the object.

Thus, depending on the object's position relative to the focal point, the image can be either real or virtual.

The image being erect or inverted (option c) and the image always being on the opposite side of the lens from the object (option d) are incorrect statements.

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Answer:

1, decrease

Explanation:

At higher altitudes, air pressure is lower. When atmospheric pressure is lower, such as at a higher altitude, it takes less energy to bring water to the boiling point. Less energy means less heat, which means water will boil at a lower temperature at a higher altitude.

Answer:

D

Explanation:

Answer:

Left is deciamled to the right \(x_{123}\)

Explanation:

Answer:

approximately 5.76 × 10^−7 meters, or 576 nanometers

Explanation:

The location of bright fringes in a double slit experiment is given by the formula:

d * sin(θ) = m * λ

where:

d is the slit separation,

θ is the angle at which the fringe occurs,

m is the order of the fringe (m = 0 for the central maximum, m = 1 for the first bright fringe, m = 2 for the second bright fringe, and so on), and

λ is the wavelength of the light.

We're looking for the wavelength of the light, and we're given that d = 2.02 × 10^−6 m, θ = 16.5°, and m = 1 (since we're looking at the first bright fringe).

Rearranging the formula to solve for λ gives us:

λ = d * sin(θ) / m

We need to make sure that we're working in radians, as that's what the trigonometric functions in most programming and calculation tools expect. There are π radians in 180 degrees, so to convert from degrees to radians, we multiply by π/180. This gives us θ = 16.5° * π/180 = 0.2873 radians.

Substituting the given values into the formula gives us:

λ = (2.02 × 10^−6 m) * sin(0.2873) / 1

λ ≈ 5.76 * 10^-7 m

So the wavelength of the light is approximately 5.76 × 10^−7 meters, or 576 nanometers (since 1 m = 10^9 nm).

The frequency of a wave is the number of cycles it completes in a given period of time, and it can be calculated using the following equation: frequency = velocity/wavelength. In the case of this wave, the frequency is 0.1 Hz (or 10 cycles/second).

frequency = 20 m/s/200 m = 0.1 Hz
The frequency of a wave that travels at 20 m/s with a wavelength of 200 meters is 0.1 Hz.What is frequency?Frequency is the number of occurrences of a periodic event per unit of time. It is commonly used to determine the number of occurrences of a specific event in a given period of time.

The frequency equation is:f = v/λwhere:f is the frequency of the  v is the velocity of the wave (m/s)λ is the wavelength of the wave (m)Using the formula given above:f = v/λwherev = 20 m/sλ = 200 metersf = 20/200f = 0.1 HzTherefore, the frequency of the wave is 0.1 Hz.

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Answer:

Explanation:

i believe a if not c

Answer:

It is not still true that the average velocity of the particle is equal to half the sum of the initial and final velocities when the acceleration of the particle is not constant

Explanation:

The motion of a particle under constant acceleration, 'a', is be given by the following kinematic equations;

v² = u² + 2·a·s

v = u + a·t

Where;

v = The final velocity of the particle

u = The initial velocity of the particle

a = The acceleration of the particle

s = The distance through which the particle travels

t = The time of motion of the particle

By simplifying the above equation, we have;

v² - u² = 2·a·s

(v² - u²)/(2·a) = s

(v - u) × (v + u)/(2 × a) = s

((v - u)/a) × ((v + u)/2) = s

From v = u + a·t, we have;

t = (v - u)/a

∴ ((v - u)/a) × ((v + u)/2) = t × ((v + u)/2) = s

∴ ((v + u)/2) = s/t

The average velocity = (Total distance traveled by the particle) ÷ (The time of travel of the particle)

∴ The average velocity = s/t = ((v + u)/2) = Half the sum of the initial and final velocity

However, it is not still true that the average velocity of the particle is equal to half the sum of the initial and final velocities when the acceleration of the particle, 'a', is not constant, as the velocity time graph is no longer a straight line graph and the distance traveled by the particle, 's', which is the area under the velocity time graph, 'A', (given by the sum of area of the triangle and the rectangle given by the area under straight line graph for constant velocity) cannot be given directly by the product of the time and the average velocity.

The rotational kinetic energy of a flywheel increases by 80% when its rotational speed increases by 40%. This is because the rotational kinetic energy of a flywheel is directly proportional to the square of its angular velocity.

The rotational speed of a flywheel increases by 40%. The percentage increase in its rotational kinetic energy is approximately 96.8%. Suppose the initial rotational speed of the flywheel is n1 and the initial rotational kinetic energy is K.E.1. After the speed of the flywheel is increased by 40 percent, the new speed is n2 = n1 + 0.4n1 = 1.4n1.

Then the new kinetic energy K.E.2 of the flywheel is given by K.E.2 = (1/2)I(n2^2)where I is the moment of inertia of the flywheel.Since n2 = 1.4n1, we have \(K.E.2 = (1/2)I(1.96n1^2) = 0.98I(n1^2).\).

Therefore, the percentage increase in the rotational kinetic energy of the flywheel is approximately 96.8%.

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If a charge +Q is placed inside a hollow isolated conductor that is originally neutral and the charge does not touch that conductor at any time, the option C) Both the inner and outer surfaces will remain neutral is correct.

In an isolated conductor, charges are free to move. When a positive charge +Q is placed inside the conductor, the charges in the conductor redistribute themselves in order to reach electrostatic equilibrium. However, since the charge does not touch the conductor, it cannot induce any charge redistribution on the inner or outer surfaces.

Therefore, option C) both the inner and outer surfaces of the conductor will remain neutral, and no charge will be induced on them. The charges inside the conductor will redistribute themselves in a way that cancels out the electric field inside the conductor, but this redistribution will not affect the surfaces.

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Answer:7.056 m/s²

Explanation: Resultant force = g - μmg

ma = g - μmg

a = g(1 - 2μ) / 2

a = 7.056 m/s²

The net force on particle q2 can be calculated by finding the net electric force acting on it. The net electric force acting on a particle is the vector sum of the forces exerted by all the other charges on it.

The electric force between two charges q1 and q2 is given by Coulomb's law: F = k * (q1 * q2)/r^2, where k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between them.

The force on particle q2 due to q1 will be:

F1 = k * (q1 * q2) / (0.980m)^2

The force on particle q2 due to q3 will be:

F2 = k * (q2 * q3) / (0.750m)^2

The net force acting on q2 will be the vector sum of F1 and F2.

Keep in mind, q1 and q3 have opposite charges, so they attract each other, while q2 has the same charge as q1, so they repel each other.

Note: The unit of charge is Coulomb (C), but in this problem you are given the charges in microCoulomb (uC) so you need to convert it to Coulomb.

Answer:

if u have to find mass then it always constant everywhere that is 100kg but if u have to find weight then it 1/6 of earth .

Explanation:

16.6666

Answer:

50.09 km/h

Explanation:

Given that an airplane flying due north at 90 km/h is being blown due west. The planes total velocity is 103 km/ hr north west.

What is velocity of the wind ?

The wind velocity can be calculated by using pythagorean theorem.

From the question,

Resultant Velocity R = 103 km/h

Plane velocity P = 90 km/h

Wind velocity W = ?

W^2 = R^2 - P^2

Substitutes all the parameters into the formula

W^2 = 103^2 - 90^2

W^2 = 10609 - 8100

W^2 = 2509

W = sqrt ( 2509 )

W = 50.09 km/h

Therefore, the velocity of the wind is 50.09 km/h

The given circuit is shown below:Given circuitThe current, I, is given as follows:

\($$I = \frac{V_{1} - V_{2}}{3 \Omega}$$Using KCL at node B:$$\frac{V_{1} - V_{B}}{2 \Omega} + \frac{V_{1} - V_{2}}{3 \Omega}\)

\(= 0$$$$\frac{V_{1} - V_{B}}{2} + \frac{V_{1} - V_{2}}{3}\)

\(= 0$$$$\frac{3V_{1} - 3V_{B} + 2V_{1} - 2V_{2}}{6}\)

\(= 0$$$$5V_{1} - 5V_{B} + 3V_{1} - 3V_{2}\)

\(= 0$$\)Rearranging the above equation:

\($$5V_{1} - 5V_{B} = 3V_{2} - 3V_{1}$$$$10V_{1} - 10V_{B}\)

\(= 6V_{2} - 6V_{1}$$$$16V_{1} - 10V_{B} - 6V_{2}\)

\(= 0$$Using KCL at node C:$$\frac{V_{B} - V_{C}}{4 \Omega} - \frac{V_{C}}{5 \Omega}\)

\(= 0$$$$\frac{V_{B} - V_{C}}{4} - \frac{V_{C}}{5}\)

\(= 0$$$$5V_{B} - 5V_{C} - 4V_{C}\)

\(= 0$$$$5V_{B}\)

\(= 9V_{C}$$Substituting the above equation in (2):$$16V_{1} - 10 \cdot \frac{9}{5}V_{B} - 6V_{2}\)

\(= 0$$$$16V_{1} - 18V_{B} - 6V_{2} = 0$$$$8V_{1} - 9V_{B} - 3V_{2}\)

\(= 0$$\)We know that the voltage across the 5 Ω resistor is given by:

\($$V_{C} = -4I$$$$V_{C}\)

\(= -4\frac{V_{1} - V_{2}}{3}$$Substituting in (3):$$8V_{1} - 9V_{B} - 3V_{2}\)

\(= 0$$$$8V_{1} - 9V_{B} - 3\cdot-4\frac{V_{1} - V_{C}}{3} = 0$$$$8V_{1} - 9V_{B} + 4V_{1} - 4V_{C} = 0$$$$12V_{1} - 9V_{B} - 4V_{C} = 0$$$$4V_{C}\)

\(= 3V_{B} - 4V_{1}$$$$4\left(-4\frac{V_{1} - V_{2}}{3}\right) = 3V_{B} - 4V_{1}$$$$-\frac{16}{3}V_{1} + \frac{16}{3}V_{2} = 3V_{B} - 4V_{1}$$$$-\frac{4}{3}V_{1} + \frac{16}{3}V_{2} = 3V_{B}$$$$-4V_{1} + 16V_{2}\)

\(= 9V_{B}$$\)We have obtained three equations from KCL at node B, KCL at node C and the voltage across the 5 Ω resistor. We can solve these equations simultaneously to obtain the unknown node voltages.'

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The new volume of the gas will remain the same.

The new volume of the gas can be obtained by using the combined gas equation as illustrated below:

P₁V₁ / T₁ = P₂V₂ / T₂

(PV) / T = (2P × V₂) / 2T

Cross multiply

T × 2P × V₂ = PV × 2T

2PT × V₂ = 2PVT

Divide both side by 2PT

V₂ = 2PVT / 2PT

V₂ = V

Thus, the new volume will remain the same

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The ultraviolet (UV) radiations in the stratosphere are primarily absorbed by a layer of gas called the ozone layer.

The ozone (O3) molecules in the ozone layer have the ability to absorb UV radiation, particularly in the UV-C and most of the UV-B regions of the electromagnetic spectrum. When UV radiation interacts with ozone molecules, it can cause the breaking and reformation of ozone bonds, resulting in the absorption of UV energy.

This absorption process is important because it prevents a significant amount of UV radiation from reaching the Earth's surface. It acts as a protective shield against harmful UV rays that can have detrimental effects on living organisms, including increased risk of skin cancer, cataracts, and damage to marine ecosystems.

It's important to note that not all UV radiation is absorbed by the ozone layer. Some UV-B and a majority of UV-A radiation reach the Earth's surface, but they are less harmful compared to the shorter wavelength UV-C radiation that is almost entirely absorbed by the ozone layer.

Hence, The ultraviolet (UV) radiations in the stratosphere are primarily absorbed by a layer of gas called the ozone layer.

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Some common everyday uses for electromagnetic waves are Wireless local area networks (Wi-Fi), cell phones, radio broadcasting, cooking, and even cancer treatment.

EM waves, or electromagnetic waves, are generated when an electric field and a magnetic field cause vibrations. Radio waves, microwaves, infrared, visible, ultraviolet, X-rays, and gamma rays are the seven different types of electromagnetic waves.

There are numerous applications for radio waves, including media broadcasting, wireless communication, radio telescopes, etc. Microwaves are utilized widely in wireless networks, satellite and spacecraft communications, microwave radio relay networks, medical treatment, remote sensing, particle accelerators, radio astronomy, and spectroscopy, among other applications. Infrared wavelengths enable us to track and monitor the temperature patterns of the Earth. They are also utilized for thermal imaging and remote digital device controls. X-rays are renowned for their use in medical imaging. Gamma radiations are created by nuclear processes, nuclear decay, and star explosions, among other phenomena.

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As an interstellar cloud of hydrogen gas shrinks in size, its temperature increases due to the principle of conservation of energy.

When the cloud contracts, gravitational potential energy is converted into thermal energy. The gravitational force pulling the gas inward does work on the gas particles, increasing their kinetic energy and causing them to move faster. As the particles move faster, collisions between them become more frequent and more energetic, resulting in an overall increase in temperature. This process is governed by the ideal gas law, which states that the pressure of a gas is directly proportional to its temperature when the volume is held constant. As the interstellar cloud contracts, its volume decreases, leading to an increase in pressure. According to the ideal gas law, this increase in pressure is accompanied by an increase in temperature.

Therefore, as the interstellar cloud of hydrogen gas shrinks in size, its temperature increases as gravitational potential energy is converted into thermal energy through the increase in kinetic energy of the gas particles.

FULL QUESTION: As an interstellar cloud of hydrogen gas shrinks in size, its temperature increases,

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Answer:

i think a

Explanation:

Shuffling your feet across the floor as you walk is an example of charging by friction. The correct option is A.

The force preventing sliding against one another of solid surfaces, fluid layers, and material components is known as friction.

There are various kinds of friction: Two solid surfaces in touch are opposed to one another's relative lateral motion by dry friction.

Frictional force is the force produced when two surfaces slide against and touch each other.

The surface texture and amount of force needing them together have the biggest an impact on these forces. The amount of frictional force is influenced by the object's position and angle.

As an illustration of how charge is transferred via friction, consider walking over a carpet.

Thus, the correct option is A.

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Explanation:

A lightning rod (US, AUS) If lightning hits the structure:-

It will preferentially strike the rod and be conducted to ground through a wire.

Instead of passing through the structure, where it could start a fire or cause electrocution.

The parts of a lightning protection system are air terminals (lightning rods or strike) and all of the connectors and supports to complete the system.

When Lorraine puts the tennis ball in the container of olive oil, it will float on the surface of the oil because the density of the tennis ball (970 kg/m³) is less than the density of the olive oil (900 kg/m³).

Density is a measure of the mass of a substance per unit volume. It is an important physical property of matter and is used to identify substances, compare the same substances in different states, and measure the concentration of substances in solutions. Density is expressed in terms of grams per cubic centimeter or pounds per cubic foot. Density is also a fundamental concept in the study of fluid mechanics, since the density of a fluid determines its pressure and its behavior when acted upon by external forces.

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Answer:

25 feet

Explanation:

Car brakes must stop a car moving at 20m/h within 25 feet

According to standard guidelines, the required stopping distance for a car traveling at 20 miles per hour must be within approximately 20 feet.

It's important to note that this estimate assumes ideal road and weather conditions, as well as a properly functioning braking system.

Actual stopping distances can vary depending on factors such as vehicle condition, road conditions (e.g., wet or icy surfaces), tire grip, driver reaction time, and other variables.

The required stopping distance for a car traveling at 20 miles per hour must be within approximately 20 feet.

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Based on law of conservation of energy, the logs burnt completely and all the masses converted into smoke and ashes.

The law of conservation of energy states that energy can neither be created nor destroyed but can be converted from one form to another.

That is energy can be converted from one form into and cannot be destroyed. Examples of various energy conversion process include the following;

The energy conversion that took place when Rodriguez family roasted marshmallows over a campfire one night include;

chemical energy of logs -----> heat ------> light

wood + oxygen ------> ashes + smoke

Thus, only ashes remain after the camp fire because the log of woods reacted with oxygen and burnt into ashes.

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Randall is correct in stating that the force on the string has a magnitude equal to the product of the charges, q, divided by the square of the length of the string, L.

This is described by Coulomb's Law, which relates the force between two charged objects to the product of their charges and the inverse square of the distance between them. On the other hand, Tilden's statement about the tension in the string being equal to the product of the charges is incorrect.

Tension in the string is not directly related to the charges but is instead a result of the forces exerted by the charged spheres on the string itself.

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Answer: Echolocation

Explanation:

Solution,

We know that,

\(f = ma \\ \frac{f}{m} = a \\ \frac{1000}{100} = a \\ 10 = a\)

Therefore,

Acceleration produced will be 10m/s².