#12: A train left Philadelphia at 8 AM on July 1st. It traveled
2,864 miles to Portland, Oregon, arriving at 9AM on July 4th.
What was the average rate of change of the train in miles per
hour?
Round to the nearest hundredth

Answer:

the anser and the

Step-by-step explanation:

Answer:

If im wrong just say but i think it B

Step-by-step explanation:

The number of gigabytes Bao can use while staying within her budget is 3.9 gigabytes.

From the information, plan, Bao pays a flat cost of $40.50 per month and $5 per gigabyte and she wants to keep her bill under $60 per month.

The inequality will be:

40.50 + 5g < 60

where g = number of gigabytes

40.50 + 5g < 60

5g < 60 - 40.50

5g < 19.50

g < 19.50 / 5

g < 3.9

Therefore, the number of gigabytes will be less than 3.9 g.

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Answer:

negative -14

Step-by-step explanation:

Answer:

A Negitive because it is the smaller number take away a bigger number

Step-by-step explanation:

Answer:

f(x)= -x^2-6x+7

Step-by-step explanation:

Since the graph opens downward the function for the parabola is going to be negative. This leaves us with two answers.

Now use the remaining possible equations and solve for the vertex.

Using  x= -b/2a to solve for the x value of the vertex plug in the values to solve.

a= -1 b= -6  c=7 so, since -6 is already negative plugging it in makes it positive -(-6)/2(-1) = 6/-2 = -3. So x equals negative 3.

Then plug in -3 into the equation to get the y-value.

- (-3)^2 - 6(-3) + 7 = -9 + 18 + 7 = 16 so this confirms the vertex for this equation is (-3,16) so the answer is -x^2-6x+7.

Hope this helped! :)

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

x=8

Step-by-step explanation:

Answer:

x=8

Step-by-step explanation:

Given :

1.36 is 17% of x

That means we can write,

\(1.36=\frac{(17)(x)}{100\\}\\13600=17x\\x=8\)

The value of x=8

The summary of the ruler placement postulate is given as:

This states that the points of a line can be matched and correspond to a set of points on the line and the set of real numbers,

Therefore, based on the fact that your question is incomplete, a general overview of the ruler placement postulate is given to give you a better understanding of the concept.

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Answer: You can measure the positive distance  between points A and B by using either point as zero

Step-by-step explanation:

Answer:

2-241x

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

A. $840

Step-by-step explanation:

multiply 1200 x .70  = 840

Answer:

A B E F

Step-by-step explanation:

-2 * -5 = 10

10 * 3 = 30

30 * -7 = -210

When children create an imaginary town with various blocks and figurines, they are learning through play and engaging in important cognitive and social development processes.

1. Imagination and Creativity: Building an imaginary town involves using their imagination and creativity to create a world of their own. This helps children develop their cognitive skills by coming up with ideas, planning and problem-solving.

2. Language and Communication: During play, children may engage in pretend conversations and storytelling, which helps enhance their language skills and vocabulary. They may also negotiate and cooperate with others, improving their social communication skills.

3. Fine Motor Skills: Manipulating blocks and figurines requires the use of fine motor skills. Children practice hand-eye coordination, dexterity, and control while building and arranging their town.

4. Social Skills: Collaborating with others in creating the town encourages teamwork, sharing, and turn-taking. Children learn to negotiate, compromise, and solve conflicts, promoting social and emotional development.

5. Cognitive Development: Creating an imaginary town involves categorization, spatial awareness, and problem-solving skills. Children learn to organize and categorize blocks, create different structures, and explore cause-and-effect relationships.

In conclusion, when children engage in creating an imaginary town with blocks and figurines, they develop various skills such as imagination, creativity, language, fine motor, social, and cognitive skills. Through this play activity, children learn and grow in multiple ways, contributing to their overall development.

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Answer:

2(18x - 3)

to answer questions like these, read the question literally. the answer will almost always be how the question looks like. hope this helps:)

Answer:

x=-5.5

Step-by-step explanation:

-3(x+4)=(-x-1)

1. Distribute

-3x+(-12)=-x-1

2. Simplify

-3x-12=-x-1

-2x-12=-1

-2x=11

x=-11/2

x=-5.5

Answer:

-11/2 or 5.5

Step-by-step explanation:

Answer:

Step-by-step explanation:

-d + 6 = 16

-d = 10

d = -10

the answer is b

At t = -7π/6, the values of the sine, cosine, and tangent functions are as follows: Sine: -1/2, Cosine: -√3/2,Tangent: 1/√3 or √3/3

To evaluate the sine, cosine, and tangent at t = -7π/6, we need to determine the corresponding values on the unit circle. In the unit circle, t = -7π/6 represents an angle in the fourth quadrant with a reference angle of π/6.

The sine function is positive in the second and fourth quadrants, so its value at -7π/6 is -1/2.

The cosine function is negative in the second and third quadrants, so its value at -7π/6 is -√3/2.

The tangent function is equal to sine divided by cosine. Since both sine and cosine are negative in the fourth quadrant, the tangent value is positive. Therefore, at -7π/6, the tangent is 1/√3 or √3/3.

Hence, the values are:

Sine: -1/2

Cosine: -√3/2

Tangent: 1/√3 or √3/3

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The value of the inequality is x > 6

Inequalities are defined as mathematical relations that makes a non-equal comparison between two numbers , elements or expressions.

They are also used to compare two numbers on the number line by their size.

It is an order relationship showing —greater than, greater than or equal to, less than, or less than or equal to

Given the expression;

|1.3x + 7.8| > 0

collect like terms

1. 3x > 0 + 7. 8

1.3x > 7. 8

Make 'x' the subject

Divide both sides by 1. 3

1. x/ 1. 3 > 7. 8/ 1. 3

x > 6

Thus, the value of the inequality is x > 6

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Answer:

Step-by-step explanation:

I have no clue wait until 3:00

As we proved that sin mt and cos nt are orthogonal for all positive integers m and n.

In this case, we are given the inner product (6) on the space c[0,2]. This means that for any two functions f(x) and g(x) in the space c[0,2], the inner product is defined as:

⟨f,g⟩ = 6 ∫₀² f(x)g(x) dx

where ∫₀² represents the integral of f(x)g(x) from 0 to 2.

⟨sin(mt),cos(nt)⟩ = 0

To do this, we can use trigonometric identities to express sin(mt) and cos(nt) in terms of exponentials:

sin(mt) = (\(e^{imt} - e^{-imt}\)) / (2i)

cos(nt) = (\(e^{int} - e^{-int}\)) / 2

where i is the imaginary unit, e is the base of the natural logarithm, and m and n are positive integers.

Substituting these expressions into the inner product formula, we obtain:

⟨sin(mt),cos(nt)⟩ = 6 ∫₀² (\((e^{imt} - e^{-imt})(e^{int} - e^{-int})\))/4i dx

Simplifying the integrand using exponential identities, we get:

⟨sin(mt),cos(nt)⟩ = 3 ∫₀² [\(e^{i(m+n)t} - e^{i(m-n)t} - e^{-i(m-n)t} + e^{-i(m+n)t}\)] dx

Since the integrand contains complex exponentials with different frequencies, the only way the integral can be non-zero is if the frequencies cancel out.

Therefore, the integral evaluates to zero, and we have shown that sin(mt) and cos(nt) are orthogonal under the inner product (6).

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Complete Question:

The space is c[0,2] with the inner product (6).

Show that sin mt and cos nt are orthogonal for all positive integers m and n.

200 is the mean absolute deviation. Therefore, choice three (200) is the right one.

The absolute difference between the predicted and actual values must be determined, added together, and divided by the total number of periods.

Forecasted values are as follows: 1,500 and 1,400

Values in actuality: 1,200 and 1,500

Absolute differences:

|1,500 - 1,200| = 300

|1,400 - 1,500| = 100

Now, we calculate the MAD:

MAD = (300 + 100) / 2 = 400 / 2 = 200

Therefore, 200 is the mean absolute deviation. Therefore, choice three (200) is the right one.

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Answer:

where is the graph?

Step-by-step explanation:

Answer:

Point D

Step-by-step explanation:

yes

1. The average rate of change from x-2 to x-10 is approximately -0.00485839844. 2. -60; on average, there was a loss of 60 each round.

The average pace at which a quantity changes over a specified period of time or input is known as the "average rate of change" in mathematics. Calculus and other mathematical disciplines frequently use it to examine the behavior of equations and functions.

Determine the change in function value (output) divided by the change in input (often represented by the variable x) to find the average rate of change of a function between two locations.

1. The given function is f(x) = 0.01(2)ˣ.

The rate of change us given as:

\((f(x_2) - f(x_1))/(x_2 - x_1)\)

Substituting the value we have:

average rate of change = \((0.01(2)^{(-10)} - 0.01(2)^{(-2))/(-10 - (-2))\)

= (0.01(1/1024) - 0.01(4))/(-8)

= (0.0009765625 - 0.04)/(-8)

= -0.00485839844

Hence, the average rate of change from x-2 to x-10 is approximately -0.00485839844.

2. For chess substituting the value of x₂ = 5 and x₁ = 1 in the rate change we have:

average rate of change = (16 - 256)/(5 - 1)

= -60

Hence, -60; on average, there was a loss of 60 each round.

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Answer:

The error is that should it be x + 10 = 25

3x - 2x = x, not 5x

Hope that helps!

-Sabrina

Step-by-step explanation:

Answer:

To write the equation in function form for the number of calls in each week by the mechanic, we can use the concept of linear reduction.

- Week 3 as the starting week (x = 0).

- Week 13 as the ending week (x = 10).

- (x1, y1) = (0, 391) (week 3, number of calls fixed in week 3)

- (x2, y2) = (10, 361) (week 13, number of calls fixed in week 13)

We can use these two points to determine the equation of a straight line in the form y = mx + b, where m is the slope and b is the y-intercept.

First, calculate the slope (m):

m = (y2 - y1) / (x2 - x1)

= (361 - 391) / (10 - 0)

= -3

Next, substitute the slope (m) and one of the data points (x1, y1) into the equation y = mx + b to find the y-intercept (b):

391 = -3(0) + b

b = 391

Therefore, the equation in function form to show the number of calls in each week by the mechanic is:

y = -3x + 391

- y represents the number of calls in each week fixed by the mechanic.

- x represents the week number, starting from week 3 (x = 0) and ending at week 13 (x = 10).

To find the volume of all pairs of vertices (s, t) in a directed graph G using an efficient Dijkstra-like algorithm, we can adapt the Dijkstra's algorithm with some modifications.

Here is the algorithm:

Initialize all vertices' volumes as negative infinity, except for the starting vertex s, which has a volume of 0.

vol(v) = -∞ for all v in G.V

vol(s) = 0

Create a priority queue Q to store vertices based on their volumes (minimum volume first). Initially, insert vertex s into Q.

While Q is not empty, do the following:

a. Extract the vertex u with the minimum volume from Q.

b. For each neighbor v of u:

Calculate the capacity of the path from s to v via u: cap(s, v) = min(cap(s, u), w(u, v)), where w(u, v) is the weight of the arc from u to v.

If cap(s, v) > vol(v), update vol(v) with cap(s, v) and insert v into Q if it's not already present.

After the algorithm finishes, the volumes vol(s, t) will represent the maximum capacity of paths from s to t for all vertices t in G.V{s}.

This modified Dijkstra-like algorithm finds the maximum capacity (volume) from s to all other vertices by considering all possible paths and updating the volume as we encounter smaller capacities along the way. By using a priority queue to extract the minimum volume vertex efficiently, the algorithm can run in O((|V| + |E|) log |V|) time complexity, where |V| is the number of vertices and |E| is the number of edges in the graph.

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The volume flow rate of the water passing through the pipe increases by a factor of 6.

Assuming that the initial cross sectional area of the pipe is A m² and the initial velocity of the water is V m/s, the water flow rate is:

= initial flow rate = area × velocity = AV m³/s

As the water speed doubles (2V m/s) and the pipe cross-sectional area triples (3A m²), the volume flow rate becomes:

Final flow rate = 2V × 3A = 6AV m³/s

As a result, the volume flow rate of the water moving through it multiplies by a ratio of six.

The basic equation for cases like these is

Q=AV,

where Q is the volume flow rate, A is the cross-sectional area occupied by the flowing material, and V is the average velocity of flow.

V is considered an average since not every component of a flowing fluid flows at the same rate. If you monitor the waters of a river moving slowly downstream at a consistent rate of gallons per second, you will see that the surface has slower currents here and faster currents there.

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The dependencies can be identified by observing the tuples. The dependencies that hold over relation schema S are X -> Z and Y -> Z.

The dependencies that hold over relation schema S can be identified by observing the tuples and seeing if there are any patterns in the values of the attributes. Dependencies occur when the value of one attribute determines the value of another attribute. In this case, we can observe the following dependencies:

X -> Z: The value of attribute X determines the value of attribute Z. This can be observed in the first two tuples, where X=2 and Z=4 in both cases.

Y -> Z: The value of attribute Y determines the value of attribute Z. This can be observed in the first and third tuples, where Y=3 and Z=4 in the first tuple, and Y=3 and Z=5 in the third tuple.

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The sum of the first 50 terms of the sequence is 2255. The nth term of the quadratic sequence is given by \(t_n = 2n^2 + 6n + 4\). The 23rd term of the sequence is 1354.

The first 50 terms of the sequence can be split into two alternating sequences: a geometric sequence with first term 1/2 and common ratio 1/2, and an arithmetic sequence with first term 4 and common difference 3. The sum of a geometric series is given by \(a_1(1-r^n)/(1-r)\), where \(a_1\) is the first term, r is the common ratio, and n is the number of terms. The sum of an arithmetic series is given by \(n/2(a_1+a_n)\), where n is the number of terms, \(a_1\)is the first term, and \(a_n\) is the nth term.

The nth term of the quadratic sequence is given by \(t_n = 2n^2 + 6n + 4\). To find the 23rd term, we can simply substitute n=23 into the equation. This gives us \(t_{23} = 2(23)^2 + 6(23) + 4 = 1354.\)

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The four uppercase letters of the alphabet in block style with rotational symmetry are H, I, O, and X. Rotational symmetry refers to the property of a figure or object that appears identical after being rotated around a central point by a certain angle.

In block style writing, letters are written with straight lines and sharp corners, creating a uniform and geometric appearance. H, I, O, and X are the only uppercase letters that have rotational symmetry and can be written in block style.

H has a rotational symmetry of 180 degrees, meaning it looks the same when rotated 180 degrees around its center point.

I has a rotational symmetry of 180 degrees as well, with the dot above the letter acting as its center point.

O has a rotational symmetry of 360 degrees, meaning it looks the same when rotated any number of degrees around its center point.

Lastly, X has a rotational symmetry of 180 degrees, with the intersection of the two lines acting as its center point.

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