12) a ball is thrown upward with an initial velocity of 20.0 m/s. what maximum height does the ball reach?

The telescope that allowed astronomers to discover most of the planets found with the transit method was called the Kepler mission.

Through only this one telescope, Kepler, astronomers have found thousands of extrasolar planets, or exoplanets, since its inception. Most of them are planets with diameters ranging from Earth's to Neptune's (which is four times the size of Earth). Where Kepler was directed for the first four years of its mission, in an area of the constellation Cygnus roughly the size of the palm of a hand held at arm's length, many of these planets were found.

According to the NASA Exoplanet Archive, as of November 2020, Kepler was credited with finding 2,392 exoplanets, with 2,368 candidate planets still awaiting confirmation.

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Field strength is 0.03234 N/kg. The formula to determine the field strength is given by:

F = mg Here, F is the field strength, m is the mass, and g is the gravitational field strength.

Substituting the values given: Weight = 0.96 N Mass = 3.3 g = 0.0033 kg = 9.8 m/s² Therefore, F = mg = 0.0033 kg × 9.8 m/s² = 0.03234 N the field strength is the gravitational force acting on a unit mass. It is measured in newtons per kilogram. The field strength is an expression of the strength of a gravitational field. In this case, the mass of the object is 3.3 g, which can be converted to kilograms by dividing by 1000.

The weight of the object is given as 0.96 N. Using the formula

F=mg, where m is the mass and g is the gravitational field strength, we can calculate the field strength as 0.03234 N/kg.

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Answer:

the moment of inertia with the arms extended is Io and when the arms are lowered the moment

I₀/I > 1    ⇒   w > w₀

Explanation:

The angular momentum is conserved if the external torques in the system are zero, this is achieved because the friction with the ice is very small,

           L₀ = L_f

           I₀ w₀ = I w

          w =\(\frac{I_o}{I}\) w₀

where we see that the angular velocity changes according to the relation of the angular moments, if we approximate the body as a cylinder with two point charges, weight of the arms

          I₀ = I_cylinder + 2 m r²

where r is the distance from the center of mass of the arms to the axis of rotation, the moment of inertia of the cylinder does not change, therefore changing the distance of the arms changes the moment of inertia.

If we say that the moment of inertia with the arms extended is Io and when the arms are lowered the moment will be

        I <I₀

        I₀/I > 1    ⇒   w > w₀

therefore the angular velocity (rotations) must increase

in this way the skater can adjust his spin speed to the musician.

Answer:

Spring cannot return to its original, since a part of its deformation is plastic, not elastic.

Explanation:

Physically speaking, stress is equal to the axial force divided by effective transversal area of spring. In addition, springs have usually a linear relationship between stress and strain in elastic region, since they are made of ductile materials. Axial force is directly proportional to axial stress, which is also directly proportional to axial strain.

Then, if force is greater than force associated with elastic limit of the spring, then spring cannot return to its original, since a part of its deformation is plastic, not elastic.

Answer:

4200N

Explanation:

Force = acceleration × mass

f=3.5×1200

f=4200

B. The best classification for fossilized burrows dug by ancient clams is Trace Fossils.

A trace fossil, is a type of fossil record of biological activity but not the preserved remains of the plant or animal itself.

Some of trace fossils include the following;

Thus, the best classification for fossilized burrows dug by ancient clams is Trace Fossils.

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Let's call the length of the race track as "x".

To solve for "x", we can use the formula:

\(\implies\text{ Time} = \dfrac{\text{ Distance}}{\text{ Speed}}\)

Since the race ends in a tie, we know that Jan and Mary both took the same amount of time to run the race. Let's call this time "t".

\(\implies \text{ Time} = \dfrac{\text{ Distance}}{\text{ Speed}}\)

\(\implies t = \dfrac{x - 25}{7.5}\)

\(\implies\text{ Time} = \dfrac{\text{ Distance}}{\text{ Speed}}\)

\(\implies t = \dfrac{x}{8.0}\)

Since both expressions represent the same time, we can set them equal to each other and solve for "x":

\(\implies \dfrac{x - 25}{7.5} = \dfrac{x}{8.0}\)

Multiplying both sides by 60 (the least common multiple of 7.5 and 8.0) to get rid of the decimals:

\(\implies 8(x - 25) = 7.5x\)

\(\implies 8x - 200 = 7.5x\)

\(\implies 0.5x = 200\)

\(\implies x = 400\)

\(\therefore\) The length of the race track is 400 meters.

\(\blue{\overline{\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad}}\)

I think its "a dropped penny sinks at the bottom of a pond". Because, non-contact force is a force that you don't touch, like gravity or weight, that falls but you didn't drop it on purpose nature did or gravity itself did.

Answer:

Explanation:

2) From F=ma

Force =15×40=600N or kgm/s2

3)From the same equation making acceleration the subject of the formula will give

a=f÷m

=24÷4=6m/s2

4)m=f÷a

=45÷15=3kg

The wall is positively charged, whereas it is negatively charged. If a woollen fabric is not used to massage it, it will not do so. When the sand was drawn inside the balloon, the same thing occurred.

Positive charges pull away from negative charges. The balloon will attract the wool fabric if it is not touched since it contains an equal balance of negative and positive charges. Both balloons will reject one another when they are brushed with the wool cloth because they both receive negative charges.

Positive and negative particles make up the water. Because positive and negative ions are attracted to one another, when you bring the balloon near the water, the positively charged water molecules will pull the water in the direction of the negatively charged balloon.

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Answer:

The answer is B extrapolation

The process of predicting values that extend beyond the range of data points is called extrapolation, so option B is correct.

Extrapolation is a method of estimating a variable's value outside the original observation range using the relationship between the variable and another variable.

Extrapolation is comparable to interpolation in that it yields estimates between known observations, but extrapolation is more imprecise and more likely to yield meaningless findings. If identical approaches are assumed to be applicable, extrapolation may also refer to the extension of a method.

Creating a tangent line at the end of the known data and extending it past that point is known as linear extrapolation. Only when utilized to extend the graph of a roughly linear function or not too far beyond the existing data will linear extrapolation yield good results.

Therefore, the process of predicting values that extend beyond the range of data points is called extrapolation.

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Answer:

i) The extension of the cable can be calculated using the formula:

ΔL/L = F/(A*Y)

where ΔL is the extension in length, L is the original length, F is the tension force, A is the cross-sectional area of the cable, and Y is the Young's modulus of steel.

First, we need to calculate the cross-sectional area of the cable:

A = πr^2 = π(0.02m)^2 = 0.00126 m^2

Now we can calculate the extension:

ΔL/L = 400N/(0.00126m^2 * 2.0×10^11 N/m^2) = 1.5873×10^-6

ΔL = (1.5873×10^-6)(7m) = 1.11×10^-5 m

So the cable has to be extended by 1.11×10^-5 m under this tension.

ii) The work done in producing this extension can be calculated using the formula:

W = (1/2)FΔL

where W is the work done, F is the tension force, and ΔL is the extension in length.

Substituting the given values:

W = (1/2)(400N)(1.11×10^-5 m) = 2.22×10^-3 J

Therefore, the work done in producing this extension is 2.22×10^-3 J.

Explanation:

Answer:

he invs them

Explanation:

its common sense

Answer:

He invs them.

Explanation:

The speed with which a wave travels on this piano string is approximately 537.3 m/s.

To find the speed with which a wave travels on the piano string, we can use the equation:

v = √(T/μ)

where v is the speed of the wave, T is the tension in the string, and μ is the mass per unit length of the string.

Plugging in the values given, we get:

v = √(1300 N / 4.50 10-3 kg/m)

Simplifying this expression, we get:

$v = \sqrt{2.89 \times 10^5 \text{ m}^2/\text{s}^2}$

Evaluating this expression, we get:

v = 537.3 m/s

Therefore, the speed with which a wave travels on this piano string is approximately 537.3 m/s.

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The approximate number of wavelengths of light that can travel in one direction within a retroreflecting bead that has a diameter of 5 ×\(10^-^5\) m is 167.

This calculation is based on the formula n = L/λ, where n is the number of wavelengths, L is the length of the object, and λ is the wavelength of light. To calculate the wavelength of light, we use the formula c = λf, where c is the speed of light and f is the frequency of light.

In this problem, we are given the diameter of the retroreflecting bead, which is assumed to be spherical. Therefore, its length is equal to its diameter, which is 5 × \(10^-^5\)m. We are also given the speed of light, which is 3 × \(10^8\) m/s, and an approximation of the frequency of light, which is \(10^1^5\) Hz.

Using the formula c = λf, we can solve for the wavelength of light:

λ = c/f = (3 ×\(10^8\) m/s)/\((10^1^5\)Hz) = 3 ×\(10^-^7\)m

Finally, we can use the formula n = L/λ to calculate the approximate number of wavelengths of light that can travel in one direction within the retroreflecting bead:

n = L/λ = (5 ×\(10^-^5\) m)/(3 ×\(10^-^7\) m) = 166.67 ≈ 167

Therefore, the approximate number of wavelengths of light that can travel in one direction within a retroreflecting bead that has a diameter of 5 ×\(10^-^5\) m is 167.

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Answer:

Friction

Explanation:

As the skateboarder goes down the ramp, potential energy is converted to kinetic energy. Because of friction, some of the energy in the system is converted to heat energy. Once the kinetic energy is converted to heat, the energy cannot be converted back to the potential or kinetic energy in the system.

Blue light having a frequency of 6.481 x 10¹⁴ Hz has a wavelength of around 462.2 nm in a vacuum.

The wavelength of blue light can be determined using the equation λ = c/ν, where λ is the wavelength, c is the speed of light in a vacuum, and ν is the frequency of the light.

Plugging in the given frequency of 6.481 x 10¹⁴ Hz and the speed of light, which is approximately 3 x 10⁸ m/s, we get:

λ = (3 x 10⁸ m/s)/(6.481 x 10¹⁴ Hz)

λ ≈ 462.5 nm

Therefore, the wavelength of blue light with a frequency of 6.481 x 10¹⁴ Hz is approximately 462.5 nm.

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1. The contribution u2q to the electric potential energy of the system is determined by the interaction between the charge 2q and the other charges in the system. It is a measure of the energy required to bring the charge 2q from infinity to its position in the system,

taking into account the electric potential at every point along the way. This contribution can be calculated using the formula U = kqQ/r, where k is the Coulomb constant, q and Q are the charges, and r is the distance between them.

2. The total electric potential energy Utot of the system is the sum of the contributions from all the charges in the system. It can be calculated by adding up the individual potential energies of each charge pair in the system, using the formula U = kqQ/r. Alternatively, it can be calculated using the formula U = qV, where q is the total charge of the system and V is the electric potential at the location of the system. This formula takes into account the energy required to bring all the charges in the system to their positions, relative to an arbitrary reference point.

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Answer:

the force pulls each other cause its just physics

Answer:

animal and plant

Explanation:

1st is animal

mitochondria

cell membrane

nucleus

endoplasmic reticulum

golgi body

plant cell

cell wall

cell membrane

chloroplast

nucleus

vacuole

endoplasmic reticulum

mitochondria

golgi body

Answer:

The fringes are 4.7*10^-7 m apart, such that they are adjacent.

Explanation:

Using the formula for adjacent fringes given a single slit:

Δ\(x=\frac{(Wavelength)(Distance between slit and screen)}{Width}\)

Δ\(x=\frac{(590/10^{9})(1.90) }{(2.30)}\)

Δ\(x=0.000000487 m\)

Hope this helps!

The distance between the first-order and second-order dark fringes on the screen will be 4.874 × 10⁻⁵ cm.

Given:

wavelength, λ = 590 nm = 590 × 10⁻⁹ m

Distance between the slit and screen, D = 1.90 m

Width of slit, d = 2.30 m

Calculation:

We know that the distance between two slits is given as:

Δx = λD / d

where  λ is the wavelength of light

           D is the distance between the slit and screen

           d is the width of the slit

Applying values in the above equation we get:

Δx = (590 × 10⁻⁹ m)(1.90 m) / (2.30 m)

    = 4.874 × 10⁻⁷ m

    = 4.874 × 10⁻⁵ cm

Therefore, the distance between the first- and second-order dark fringes on the screen will be 4.874 × 10⁻⁵ cm.

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The time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

The cooling law is given by:

$$\frac{dQ}{dt}=-k(T-T_0)$$

where Q is the heat in the object, t is the time taken, T is the temperature of the object at time t, T0 is the temperature of the environment and k is a constant known as the cooling constant.

We need to find the time it takes for the coffee to reach a drinking temperature of 73°C given that its initial temperature is 93°C.

Therefore, we need to find the time it takes for the coffee to cool down from 93°C to 73°C when placed in a room temperature of 18°C.

Let’s assume that the heat energy that is lost by the coffee is equal to the heat energy gained by the environment. We can express this as:

dQ = - dQ where dQ is the heat energy gained by the environment.

We can substitute dQ with C(T-T0) where C is the specific heat capacity of the object.

We can rearrange the equation as follows:

$$-\frac{dQ}{dt}=k(T-T_0)$$

$$-\frac{d}{dt}C(T-T_0)=k(T-T_0)$$

$$\frac{d}{dt}T=-k(T-T_0)$$

The differential equation above can be solved using separation of variables as follows:

$$\frac{d}{dt}\ln(T-T_0)=-k$$

$$\ln(T-T_0)=-kt+c_1$$

$$T-T_0=e^{-kt+c_1}$$

$$T=T_0+Ce^{-kt}$$

where C = e^(c1).

We can now use the values given to find the specific value of C which is the temperature difference when t=0, that is, the temperature difference between the initial temperature of the coffee and the room temperature.

$$T=T_0+Ce^{-kt}$$

$$73=18+C\cdot e^{-0.09t}$$

$$55=C\cdot e^{-0.09t}$$

$$C=55e^{0.09t}$$

$$T=18+55e^{0.09t}$$

We can now solve for the value of t when T=93 as follows:

$$93=18+55e^{0.09t}$$

$$e^{0.09t}=\frac{93-18}{55}$$

$$e^{0.09t}=1.3636$$

$$t=\frac{\ln(1.3636)}{0.09}$$

Using a calculator, we can find that the time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

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The ratio v1/v2 of the speed of the comet at position 1 to the speed at position 2 will be the ratio of the angular velocity.

Comets are frozen leftovers from the formation of the solar system composed of dust, rock, and ices.

It should be noted that the tangential speed can alternatively be represented as;

\(\rm v_t= r\frac{d\theta}{dt}\)

where,

θ  is the comet's position angle with respect to some given direction.

The amount dθ/dt is known as angular speed

The ratio v1/v2 of the speed of the comet at position 1 to the speed at position 2 IS;

\(\rm \frac{v_1}{v_2} = \frac{\frac{d \theta_1}{dt_1} }{\frac{d \theta_2}{dt_2} } \\\\\ \frac{v_1}{v_2} =\frac{\omega_1}{\omega_2}\)

Hence,the ratio v1/v2 of the speed of the comet at position 1 to the speed at position 2 will be the ratio of the angular velocity.

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\(\text{Density,}\\\\~~~~~~~~\rho = \dfrac mV\\\\\\\implies V = \dfrac m{\rho}\\\\\\\implies V = \dfrac{7 \times 10^{-3}~ \text{kg}}{\tfrac{5.6 \times 10^{-3}~ \text{kg}}{ 10^{-6} ~\text{m}^3} }\\\\ \\\implies V = \dfrac{7 \times 10^{-3}~ \text{kg}}{5.6 \times 10^{-3} \times 10^6~~ \text{kg}~ \text{m}^{-3}}\\\\\\ \implies V = 1.25 \times 10^{-6}~ \text m^3\\\\\\\implies V =0.00000125~ \text m^3\\\\\text{Hence the volume of the coin is 0.00000125}~ \text m^3\)

Answer:

6 cm hoặc 0,06m

Explanation:

\(F=k\frac{q_{1} q_{2} }{r^{2} }\)

nên \(q_{1} q_{2} =\frac{F.r^{2} }{k}\)

Ban đầu:

\(F_{1} =k\frac{q_{1} q_{2} }{r^{2} }=2,7\)

---> \(q_{1} q_{2} =\frac{2,7.r^{2} }{k}\)

Lúc sau:

\(F_{2} =k\frac{q_{1} q_{2} }{(r+0,12)^{2} }=0,3\)

---->\(q_{1} q_{2} =\frac{0,3.(r+0,12)^{2} }{k}\)

Suy ra:

\(2,7.r^{2} = 0,3.(r+0,12)^{2}\)

Giải pt đc 2 nghiệm là 0,06 và -0,03

loại nghiệm âm được 0,06m

Both the process of rubbing two sticks together to cause a fire and the explosion caused by radioactive atoms involve the release of energy.

The friction between the two matchsticks generates heat, which can ignite the surfaces of the matchsticks and cause combustion and a fire. In this example the energy released appears as heat and light. Nuclear decay, which occurs in the case of radioactive atoms, is a process in which unstable atomic nuclei undergo spontaneous changes and release energy in the form of radiation. A chain reaction that results in a sudden release of energy and an explosion may be triggered under specific circumstances, as in a nuclear reactor or nuclear weapon.

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1. The direction of the magnetic field at the center of the loop is perpendicular to the plane of the loop and follows the right-hand rule.

The right-hand rule states that if you curl the fingers of your right hand in the direction of the current flow in a loop, your thumb will point in the direction of the magnetic field at the center of the loop. The magnetic field lines are circular and perpendicular to the plane of the loop.

2. The expression for the magnitude of the magnetic field at the center of the arc can be calculated using the formula for the magnetic field due to a circular loop of wire. The expression is given by: B = (μ₀ * I) / (2 * r), where B is the magnetic field, μ₀ is the permeability of free space, I is the current in the loop, and r is the radius of the arc.

The magnetic field at the center of the arc formed by the right-angle bend in the wire can be calculated using the formula for the magnetic field due to a circular loop of wire. The magnetic field strength is directly proportional to the current in the loop (I) and inversely proportional to the radius of the arc (r). The permeability of free space (μ₀) is a constant value. By plugging in the values of current and radius, the expression for the magnitude of the magnetic field at the center of the arc can be determined.

3. The force per unit length between two parallel wires carrying current can be calculated using the formula: F/L = (μ₀ * I₁ * I₂) / (2 * π * d), where F/L is the force per unit length, μ₀ is the permeability of free space, I₁ and I₂ are the currents in the wires, and d is the distance between the wires.

The force per unit length between two parallel wires carrying current can be calculated using the formula above. The force is directly proportional to the product of the currents in the wires (I₁ and I₂) and inversely proportional to the distance between the wires (d). The permeability of free space (μ₀) is a constant value.

4. The force between two parallel wires depends on the direction of the currents. If the currents are in the same direction, the force is repulsive, and if the currents are in opposite directions, the force is attractive.

The direction of the currents in the two parallel wires determines the direction of the magnetic fields around the wires. When the currents flow in the same direction, the magnetic fields around the wires interact and result in a repulsive force between the wires. When the currents flow in opposite directions, the magnetic fields interact differently and result in an attractive force between the wires.

5. To find the current in the other wire when two parallel wires separated by a distance carry a force per unit length, the formula can be rearranged to solve for the current in the second wire, I₂ = (F/L) * (2 * π * d) / (μ₀ * I₁), where I₂ is the current in the second wire, F/L is the force per unit length, d is the distance between the wires, μ₀ is the permeability of free space, and I₁ is the current in the first wire.

By rearranging the formula for the force per unit length between two parallel wires, the current in the second wire (I₂) can be calculated. The force per unit length (F/L), the distance between the wires (d), and the current in the first wire (I₁) are known quantities, and the permeability of free space (μ₀) is a constant value.

6. If the direction of one current in the two parallel

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The net work done by gravity on the ball is also zero.
The net work done by gravity on the ball during experiment 2 can be calculated using the work-energy principle. When the subject lifts the ball a vertical distance d1, the work done by gravity is negative (since the force of gravity opposes the displacement). When the ball is lowered a greater vertical distance d2, the work done by gravity is positive (as the force of gravity acts in the same direction as the displacement).
The work done by gravity can be calculated using the formula: W = m * g * d,

where W is the work done, m is the mass of the ball, g is the acceleration due to gravity, and d is the vertical distance.
For lifting the ball (d1): W1 = -m * g * d1
For lowering the ball (d2): W2 = m * g * d2
To find the net work done by gravity, add these two values:
Net work done by gravity = W1 + W2 = (-m * g * d1) + (m * g * d2)
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