10.name the following compound. a. 1-bromotoluene b. 2-bromonaphthalene c. 2-bromophenol d. 1-bromoanisole e. 2-bromoaniline

Answer:

the answer is c visible light

Answer:

Visible Light

Explanation:

So the actual lowest frequency would be radio waves, but since that is not a choice, it is C: Visible Light

The substance that is closely associated with the breakdown of the ozone layer is (C) Chlorofluorocarbons (CFCs).

CFCs are a type of synthetic chemicals that were widely used in refrigeration, air conditioning, and aerosol products before they were found to be harmful to the environment. CFCs contain chlorine, which is released into the atmosphere when these chemicals break down. When the chlorine molecules come into contact with ozone, they break it apart, causing a reduction in the ozone layer.

The ozone layer is important because it absorbs harmful UV rays from the sun, which can cause skin cancer and other health problems in humans and animals. The depletion of the ozone layer can also cause changes in weather patterns and harm plant growth.

In response to the negative effects of CFCs on the ozone layer, the international community came together to create the Montreal Protocol in 1987. This treaty phased out the production and use of CFCs and other ozone-depleting substances, leading to a gradual recovery of the ozone layer.

In conclusion, the correct option is (C) Chlorofluorocarbons (CFCs). It is important to continue to reduce the use of CFCs and other harmful chemicals in order to protect our planet and the health of all living beings.

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The relative atomic mass of gallium, given that it exists as two isotopes is 69.776 amu

From the question given above, the following data were obtained:

The relative atomic mass of the isotope can be obtained as illustrated below:

Relative atomic mass = [(Mass of A × A%) / 100] + [(Mass of B × B%) / 100]

Relative atomic mass = [(69 × 61.2) / 100] + [(71 × 38.8) / 100]

Relative atomic mass = 42.228 + 27.548

Relative atomic mass = 69.776 amu

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Lauric acid, 300 g

Benzoic acid, 30 g

Paper towels

Advance Preparation

It is important that you do the laboratory yourself beforehand. Time may be saved by pre-filling the test-tubes with about 25 g of lauric acid and having the hot and warm water baths ready. [NOTE: The mass of the lauric acid in the test-tubes must be determined to the nearest gram.]

A large net force of 280N  is required to accelerate a 2000 kg suv from rest with an acceleration of 0.14m/s2 .

According to Newton’s 2nd law of motion,  force is  equal to the change in momentum per change in time.Acceleration of an object depends on the mass of the object and the amount of force applied.

            Force=mass* acceleration

Here, mass is equal to 2000 kg and acceleration is equals to 0.14m/s/s.putting these values,

      F= ma

     F= 2000kg * 0.14 m/s2

        = 280 kg m/s2

        =280N

So, 280N of force is required.

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Explanation:

As the hydrocarbon chain length increases, viscosity increases. As the hydrocarbon chain length increases, flammability decreases. hydrogen in the fuels are oxidised, releasing carbon dioxide, water and energy. The boiling point of the chain depends on its length.

Hopefully this helps! :)

Explanation:

As the hydrocarbon chain length increases, viscosity increases. As the hydrocarbon chain length increases, flammability decreases. hydrogen in the fuels are oxidised, releasing carbon dioxide, water and energy. The boiling point of the chain depends on its length.

HFO-1234yf has been tested and found compatible with  PAG oil.
The correct answer is option A. PAG oil

PAG oil, or Polyalkylene Glycol, is a fully synthetic hygroscopic oil specifically designed for automotive air conditioner compressors. It is used in R-134a air conditioning systems to lubricate the compressor. When looking at PAG oil you will notice various numbers such as PAG46 or PAG100. These numbers refer to the viscosity of the oil, similar to 10W30 oil. In order to determine the correct PAG viscosity for your vehicle you will need to look up the specifications of your make and model of your vehicle either online or in the instruction manual.

Hence, HFO-1234yf is compatible with PAG oil. It is not compatible with mineral oil, hydraulic oil, or all of the items listed.

The correct answer is option A. PAG oil.
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Answer:

Si se usan 50 gramos de calcio y óxigeno, se obtienen 70 gramos de óxido de calcio.

Explanation:

Hola,

En este caso, la reacción llevada a cabo es:

\(2Ca+O_2\rightarrow 2CaO\)

De este modo si asumimos el ejemplo dado, 50 gramos de calcio, cuya masa atómica es 40 g/mol y 50 g de oxígeno, cuya masa atómica como gas diatómico es 32 g/mol, antes de calcular los gramos de óxido de calcio producidos, debemos identificar el reactivo límite. Así, calculamos las moles de calcio disponibles en 50 g:

\(mol_{Ca}^{disponible}=50gCa*\frac{1molCa}{40gCa} =1.25molCa\)

Y también las moles de calcio consumidas por los 50 g de oxígeno, utilizando su relación molar 2:1:

\(mol_{Ca}^{consumidas\ por\ O_2}=50gO_2*\frac{1molO_2}{32gO_2} *\frac{2molCa}{1molO_2} =3.125molCa\)

Por lo tanto, hay menos calcio disponible que el que consume el oxígeno, por lo que el calcio esel reactivo límite. Ahora, con este, calculamos los gramos de óxido de calcio, cuya masa molar es 56 g/mol, que se producen:

\(m_{CaO}=1.25molCa*\frac{2molCaO}{2molCa}* \frac{56gCaO}{1molCaO}\\ \\m_{CaO}=70gCaO\)

Esto quiere decir que de 50 gramos de oxígeno, solo 20 gramos reaccionan para formar 70 gramos de óxido de calcio.

Saludos!

Answer:

69.9 g of CaO will be produced. ≅ 70 g

Explanation:

First of all you need to make the reaction:

2Ca + O₂ → 2 CaO

Determine the moles of each reactant:

10 g Ca / 40.08 g/mol = 0.25 moles

4 g O₂ / 32 g/mol = 0.125 moles

There is no limiting reagent in this reaction, we can use both elements.

Ratio between Ca and CaO, is 2:2. For 0.25 moles of Ca I would make 0.25 moles of CaO. We convert the moles to mass:

0.25 mol . 56.08 g / 1mol = 14 g

Let's think when you have the same mass of reactant:

50 g Ca/ 40.08 g/mol = 1.24 moles

50 g O₂ / 32 g/mol = 1.56 moles

For 1 mol of oxygen I need 2 moles of calcium, so If I have 1.56 moles, I would need the double, 3.12. Notice that Ca is the limiting reagent (we need 3.12 moles of reactant, but we only have 1.24). Now we need to work with it. If 2 moles of Ca, makes 2 moles of CaO, then 1.24 moles, will produce the same amount of oxide. We finally convert the moles to mass: 1.24 mol . 56.08 g/mol = 69.9 g

Answer:

A open system

I think plz tell me if i'm wrong

Explanation:

Answer:

A- an Open System

Explanation:

The mass, in grams, of the sample of methanol is 64 grams.

Mass of any substance will be calculated by using their moles as:

n = W/M, where

W = required mass

M = molar mass = 32.0 g/mol

n = moles = 2 moles

Now we put all these value on the above equation to calculate the mass of methanol as:

W = (2mol)(32g/mol)

W = 64g

Hence, correct option is (4) i.e. 64 grams.

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The answer to this question is option D: 64 grams

Explanation: Got 90% on the quiz on edge and got this answer right

The relationship between electron orbits and light emission Bohr postulate is The energy difference between two electron orbits would equal the energy of an emitted photon.

The path is taken by an electron as it circles an atom's nucleus. An atomic orbital is just a function that describes the position and wave-like behavior of an electron within an atom in terms of both atomic theories as well as quantum mechanics. This function may be utilized to determine the likelihood of discovering any atom's electron in any particular area surrounding the nucleus.

The matter that is stimulated can emit light, and as we will demonstrate, excitation can occur from a wide range of sources.

Matter is composed of atoms and molecules, which emit light normally at specific energies. Either spontaneous or induced light emission is possible.

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Answer:

Carbon dioxide molecule

Answer:a , d ,e

Explanation:

jusy took quiz

the IV drip rate for administering Ringer's Lactate over 12 hours would be approximately 21 drops per minute (gtt/min).

To calculate the IV drip rate for administering Ringer's Lactate over 12 hours, we'll follow these steps:

Step 1: Determine the total number of drops required.

Step 2: Calculate the drip rate per minute.

Step 3: Convert the drip rate to drops per minute (gtt/min).

Let's begin:

Step 1: Determine the total number of drops required.

The order is to administer 1000 ml of Ringer's Lactate over 12 hours. Since we have 1 liter (1000 ml) of Ringer's Lactate available, the total number of drops required will be the same as the total volume in milliliters.

Total drops = 1000 ml

Step 2: Calculate the drip rate per minute.

To find the drip rate per minute, we'll divide the total number of drops by the duration in minutes.

12 hours = 12 * 60 = 720 minutes

Drip rate per minute = Total drops / Duration in minutes

Drip rate per minute = 1000 ml / 720 min

Step 3: Convert the drip rate to drops per minute (gtt/min).

Given that the infusion tubing is labeled 15 gtt per ml, we can use this information to convert the drip rate from milliliters per minute to drops per minute.

Drops per minute = Drip rate per minute * Infusion tubing label (gtt/ml)

Drops per minute = (1000 ml / 720 min) * 15 gtt/ml

Now we can calculate the solution:

Drops per minute = (1000 ml / 720 min) * 15 gtt/ml

Drops per minute ≈ 20.83 gtt/min

Rounding off to the nearest whole number:

Drops per minute ≈ 21 gtt/min

Therefore, the IV drip rate for administering Ringer's Lactate over 12 hours would be approximately 21 drops per minute (gtt/min).

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Answer:

184.113 g/mol

Explanation:  The atomic mass of Mg is 24.3 amu. The atomic mass of bromine is 79.9. Therefore, the formula weight of MgBr2 equals 24.3 amu + (2 × 79.9 amu), or 184.1 amu. Because a substance's molar mass has the same numerical value as its formula weight, the molar mass of MgBr2 equals 184.1 g/mol.

Answer:

The balanced equation is: 2AgNO₃ + MgCl₂ ------> 2AgCl + Mg(NO₃)₂

Explanation:

The law of conservation of mass states that in a normal chemical reaction, matter is neither created nor destroyed.

According to the law of conservation of mass, therefore, when a chemical reaction occurs, the mass of the products should be equal to the mass of the reactants. This implies that the amount of the atoms in each element in the chemical reaction remains the same before and after the reaction. A balanced chemical equation therefore,  is one that shows that the number of the atoms involved in the reactants side is equal to the number of atoms in the products side.

Considering the given reaction:

2AgNO₃ + MgCl₂ ------> 2AgCl + Mg(NO₃)₂

The amount in moles of each atom in the reaction is as follows;

Ag = 2 moles of atom on each side

N = 2 moles of atoms on each side

O = 6 moles of atoms on each side

Mg = 1 mole of atoms on each side

Cl = 2 moles of atoms on each side

Therefore, the above chemical equation is balanced.

Answer:

The equation is already balanced.

Explanation:

The molarity of the sucrose solution that contains 10.0 g of C₁₂H₂₂O₁₁ dissolved in 100.0 mL of solution is 2.91 M.

Molarity (M) is a unit of concentration that is defined as the number of moles of a solute per liter of solution (L). It is one of the most widely used units of concentration in chemistry, particularly in the field of analytical chemistry.

Molarity is calculated using the formula:

Molarity (M) = moles of solute (n) / volume of solution (V in L)

Moles of solute can be calculated using the formula:

n = mass of solute (m) / molar mass of solute (M)

The given information is,

Mass of solute (m) = 10.0 g

Molar mass of solute (M) = 342.34 g/mol

Volume of solution (V) = 100.0 mL

Convert the volume of solution from mL to L.

100.0 mL = 100.0 mL x (1 L / 1000 mL) = 0.1 L

Moles of sucrose = 10.0 g / 342.34 g/mol = 0.02917 mol

Molarity (M) = 0.02917 mol / 0.1 L = 0.2917 mol L-1 = 2.91 M

Therefore, the molarity of the sucrose solution is 2.91 M.

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Answer:

B. Dispose of pH paper in the trash.

C. Dump the cabbage indicator solution down the drain.

D. Ask your teacher to neutralize the acids and bases before disposal.

Explanation:

Safe disposal of waste means disposal of waste in such a way that it does not pose a threat to the environment.

When pH paper is properly disposed in the trash, it does not constitute any risk to the environment.

When a cabbage indicator solution is disposed down the drain it does not contaminate the environment. It moves directly into the sewers and is properly disposed.

When acids and bases are properly neutralized before disposal, they don't lead to acid or base contamination of the environment.

Answer:

wooden

Explanation:

Answer:

.

Explanation:

When one mole of ideal gas is compressed isothermally from 1 atm to 100 atm, the change in entropy is 19.14 J/mol K. This is because the entropy of a system increases when it is compressed isothermally.

Maxwell relations relate the partial derivatives of thermodynamic quantities. They can be used to calculate the change in entropy during the isothermal compression of one mole of an ideal gas from 1 atm to 100 atm.

In this case, we can use the following Maxwell relation:

\(\begin{equation}\Delta S = 1 \times 8.314 \frac{\text{J}}{\text{mol K}} \times \ln \left( \frac{100 \text{ atm}}{1 \text{ atm}} \right)\)

where:

S is the entropy

P is the pressure

T is the temperature

V is the volume

The partial derivative of pressure with respect to temperature at constant volume can be calculated using the ideal gas law:

\(\begin{equation}\frac{dP}{dT}_V = \frac{nR}{V}\)

where:

n is the number of moles of gas

R is the ideal gas constant

The change in volume can be calculated from the initial and final pressures and temperatures:

\(\begin{equation}dV = \frac{P_2 - P_1}{T}\)

where:

\(P_1\) is the initial pressure

\(P_2\) is the final pressure

Substituting these equations into the Maxwell relation, we get:

\(\begin{equation}dS = \frac{nR}{V} \cdot \frac{P_2 - P_1}{T}\)

We can then simplify this equation to get:

\(\begin{equation}\Delta S = nR \cdot \ln \left( \frac{P_2}{P_1} \right)\)

Plugging in the values for n, R, \(P_1\), and \(P_2\), we get:

ΔS = 1 * 8.314 J/mol K * ln(100 atm / 1 atm)

ΔS = 19.14 J/mol K

Therefore, the change in entropy when one mole of ideal gas is compressed isothermally from 1 atm to 100 atm is 19.14 J/mol K.

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1,6-hexanediamine is soluble in water but not in hexane due to the presence of polar amine groups in the molecule and its interaction with water molecules.

1,6-hexanediamine has the chemical formula H₂N(CH₂)₆NH₂. At each end of the molecule, there is an amine group (-NH₂) which exhibits polarity due to the difference in electronegativity between nitrogen and hydrogen atoms. This leads to the nitrogen atom having a partial negative charge (δ-) and the hydrogen atom having a partial positive charge (δ+).

Water molecules are polar as well, with oxygen having a partial negative charge (δ-) and the hydrogen atoms having a partial positive charge (δ+). This polarity allows for hydrogen bonding to occur between the amine groups of 1,6-hexanediamine and the water molecules.

Illustrating the interaction with four water molecules:

H₂O: δ- O -- H δ+
        ||
H₂O: δ- O -- H δ+             H₂N - (CH₂)₆ - NH₂             H δ+ -- O δ- H₂O
        ||
H₂O: δ- O -- H δ+

In this illustration, the vertical lines (||) represent the hydrogen bonds between the amine groups of 1,6-hexanediamine and the water molecules.

On the other hand, hexane is a non-polar solvent, meaning it lacks the necessary polarity and hydrogen bonding capability to effectively dissolve 1,6-hexanediamine. This results in 1,6-hexanediamine being insoluble in hexane.

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Answer:

20.0% w/v A

Explanation:

A 20.0 w/V...

The chemist has 642.4 millimoles of barium acetate in the solution.

To calculate the millimoles of barium acetate (Ba(C₂H₃O₂)₂) in the solution, we can use the formula:

moles = molarity × volume (in liters)

First, let's convert the volume from milliliters (mL) to liters (L):

440.0 mL ÷ 1000 = 0.440 L

Now we can substitute the given values into the formula:

moles = 1.46 M × 0.440 L

moles = 0.6424 mol (rounded to 4 decimal places)

To convert the moles to millimoles, we multiply by 1000:

millimoles = 0.6424 mol × 1000

millimoles = 642.4 mmol (rounded to 3 significant digits)

Therefore, the chemist has 642.4 millimoles of barium acetate in the solution.

It's important to note that the molarity (M) represents the number of moles of solute per liter of solution. By multiplying the molarity by the volume in liters, we can find the number of moles of solute. To convert moles to millimoles, we multiply by 1000. The result represents the millimoles of barium acetate present in the given volume of solution.

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Answer:

Oxidation takes place at anode

Reduction takes place at cathode

In the equation Zn has changed to Zn2+. This means oxidation number of Zn has increased from 0 to +2. So Zn is oxidised.

In CuSO4 , Cu2+ and SO4 2- ions are present.

Cu2+ has changed to Cu(s) meaning oxidation number of Cu has reduced from +2 to 0. So Copper is reduced.

So Copper rod is the cathode since it has been reduced and Zn rod is the anode because it has been oxidised.

Also electrons always move from anode to cathode so that also shows us Copper is the cathode

The pH value of the apple juice is 3.5 and The pH value of ammonia is: 8.5.

pH can be calculated using the following equation

pH = -log [H₃O⁺]

for apple juice the hydronium /hydrogen ion concentration is 0.0003

pH = -log (0.0003)

pH = 3.5

The pH value of the apple juice is 3.5

For ammonia

pH = -log (3.1 x 10⁻⁹)

pH = 8.5

The pH value of ammonia is: 8.5

NB: Not available in the option.

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Answer:

Examples include smokestacks, discharge pipes, and drainage ditches. Factories and power plants can be a source of point-source pollution, affecting both air and water. Smokestacks may spew carbon monoxide, heavy metal, sulfur dioxide, nitrogen dioxide, or “particulate matter” (small particles) into the air.

Answer:

Silver: 3

Strontium: 1

Technetium: 2

Answer:

1:Silver

2:Strontium

3:Technetium

Hope this helps!! Good Luck!!

The propagation step in the free radical chlorination of methane is:

∙CH₃ + Cl∙ → CH₃Cl

In the free radical chlorination of methane, the propagation step is a crucial part of the overall reaction mechanism. It involves the interaction between a methyl radical (∙CH₃) and a chlorine radical (Cl∙), resulting in the formation of chloromethane (CH₃Cl).

During the propagation step, the methyl radical (∙CH₃) and chlorine radical (Cl∙) combine to produce chloromethane (CH₃Cl). This reaction occurs through the abstraction of a hydrogen atom from methane by the chlorine radical, forming a new C-Cl bond and generating a new methyl radical. The overall reaction can be represented as follows:

∙CH₃ + Cl∙ → CH₃Cl

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Answer:

Because water can absorb a lot of heat without significant changes in temperature, it can prevent change in the temperature, and therefore pressure, of the compressed air.To maintain a constant temperature, we again pass the compressed air through the same chambers, this time letting it take up heat from the water