10/5+10-9x11 using pemdas

Answer:

mP = 35

Step-by-step explanation:

QR = 80

QS = 150

The measure of the angle formed by a secant and a tangent intersecting in the exterior of a circle is half the difference between the measures of the intercepted arcs.

This means that (150-80)/2 = mP

mP = 35 degrees

Hope this helps!

Answer:

A

Step-by-step explanation:

Answer:

A) y=0.5x+10 C) 17.5 dollars (don't forget your units)

Step-by-step explanation:

a) 0.5 is the price paid per song, or x, and 10 is the price that does not change for a month, so we can say that y=0.5x+10

c) to download 15 songs, we substitute x by 15

y=0.5(15)+10

y=7.5 + 10

y=17.5

and for b, im sorry but I cannot graph here.

Answer:

9/2 but you have to simplify it

Step-by-step explanation:

Answer:

x=16

Step-by-step explanation:

the angles of a triangle always add up to 180 so we have x+2 + 7x+2 + 3x = 180. subtract 4 from both sides and add up at the x to get 11x = 176. divide by 11 to get x=16

This gives us a total of 1,583,616 ft-lbs of work required to pump the water out of the pool.

Amount is a numerical value that refers to the total sum of money or other type of payment due. It is used to quantify the size of a transaction, the cost of goods or services, or any other type of financial transaction. Amounts can be expressed in a variety of different currencies, and they can be negative (owing) or positive (owed).

To calculate the amount of work required to pump all the water from the rectangular swimming pool into a drain at the top edge, we must first calculate the volume of the water in the pool. Volume is calculated by multiplying the length, width, and depth of the pool, which in this case is 20 ft x 20 ft x 8 ft = 3,200 cubic ft. Since the pool is filled to 1 ft below the top, the volume of water is 3,200 ft3 - 20 ft3 = 3,180 ft3.

Next, we must calculate the weight of the water, which is the volume multiplied by the weight density of water (62.4 lb/ft3). The weight of the water in the pool is 3,180 ft3 x 62.4 lb/ft3 = 197,952 lbs.

Finally, to calculate the amount of work required to pump the water from the pool into a drain at the top edge, we must multiply the weight of the water (197,952 lbs) by the height of the drain (8 ft). This gives us a total of 1,583,616 ft-lbs of work required to pump the water out of the pool.

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The top of the ladder touches a height of 8 feet on the wall. To determine how high on the wall the top of the ladder touches, we can use the Pythagorean theorem.

In this case, the ladder forms the hypotenuse of a right triangle, and the base of the wall and the height on the wall form the other two sides.

Let's denote the height on the wall as 'h'. According to the problem, one end of the ladder is 6 feet from the base of the wall, so the base of the triangle is 6 feet.

We can set up the equation using the Pythagorean theorem:

\((6)^2 + (h)^2 = (10)^2\)

Simplifying the equation:

36 + \(h^2\) = 100

\(h^2\) = 100 - 36

\(h^2\)= 64

Taking the square root of both sides:

h = √64

h = 8

Therefore, the top of the ladder touches a height of 8 feet on the wall.

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The product of vectors a and b is approximately 5.292.

To find the product of two vectors a and b, we need to use the dot product formula which is a · b = |a| |b| cosθ, where |a| and |b| are the magnitudes of vectors a and b, and θ is the angle between them.
In this case, we are given that |a| = 2 and |b| = 7, and the angle between a and b is 2/3. We can use this information to find cosθ as follows:
cosθ = cos(2/3) ≈ 0.378
Now, we can substitute the values into the formula:
a · b = |a| |b| cosθ
a · b = 2 * 7 * 0.378
a · b ≈ 5.292
Therefore, the product of vectors a and b is approximately 5.292.

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Answer:

(7, 2).

Step-by-step explanation:

The median from A intersects BC at it's midpoint.

To find the midpoint of BC:

This is (x1, y1) where x1 = (sum of the x_values of B and C) / 2)  and where y1

= (sum of the y_values of B and C) / 2)

This is (2+12)/2,  (1 + 3)/2

= (7, 2).

The range of the function y = 2sin(x) is the set of all possible values that the function can take. The range of the function y = 2sin(x) is [-2, 2].

In trigonometry, the sine function can be defined as the ratio of the length of the opposite side to that of the hypotenuse in a right-angled triangle. The sine function, sin(x), has a range between -1 and 1, inclusive. When we multiply the sine function by 2, as in the case of y = 2sin(x), the range is expanded.

Multiplying the range of sin(x) [-1, 1] by 2 gives us the range of 2sin(x), which is [-2, 2].

Therefore, the range of the function y = 2sin(x) is [-2, 2].

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Step 1. We label the points to Find the slope of the line.

The points we have are (4,1) and (2,3), we label them as follows:

Step 2. Use the slope formula to find the slope "m":

Substituting our values:

Solving the operations:

Step 3. Now that we have the slope, we use the point-slope equation to find the equation of the line.

The point-slope equation is:

Substituting the values of m, x1, and y1:

now we solve this equation for y by using the distributive property on the right side of the equation:

Add 1 to both sides:

Step 4. Change to function notation.

To do this, we change "y" for "f(x)":

Answer:

The value of x is 6 when the equation is √x+2= x-4.

Given that,

The equation is

√x+2= x-4

The value of x must be determined.

Equations are mathematical expressions with two algebraic expressions on either side of the equals (=) sign. It shows that the expressions written on the left and right sides have an equal relationship. A mathematical statement known as an equation is one that uses the word "equal to" between two expressions with the same value.

Take the equation,

√x+2= x-4

√x=x-4-2

√x=x-6

√x-x=-6

x=6

Therefore, The value of x is 6 when the equation is √x+2= x-4.

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The following are the zeros for the function h (x) = x2 + 3x - 8: - x= -4 and x=2.

Given a collection of inputs X (domain) and a set of potential outputs Y (codomain), a function is more technically defined as a set of ordered pairings (x,y) where xX and yY with the caveat that there can only be one ordered pair with the same value of x. The function notation f:XY can be used to express that f is a function from X to Y.

The function's zero is a value of x that makes it equal to zero. In other words, the equation f(x) = 0 leads to a zero.

By putting h(x) equal to zero and figuring out x, we may determine the zeroes for the function h(x) = x2 + 3x - 8.

h(x) = x² + 3x - 8 = 0

We may factor the left side of the equation to find x:

x² + 3x - 8 = (x-2)(x+4) = 0

We set each factor to zero and solve for x to discover the zeroes:

x-2 = 0 or x+4 = 0

x = 2 or x = -4

Consequently, the function's zeros are x = 2 and x = -4.

So, A is the right response. x = -4 and x = 2

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The complete question is

What are the zeros of the function h (x) = x² + 3x - 8?

A. x = -4 and x = -2

B. x= -8 and x = 2

C. x = -2 and x = 8

D. x = 2 and x = 8

Answer:

angles 1 and 3 are 100 degrees and 2 is 80 degrees

The bug changes direction at t = 4. This can be answered by the concept of velocity.

To determine when the bug changes direction, we need to find when its velocity changes sign from positive to negative. From the graph, we see that the bug's velocity is positive for t < 4 and negative for t > 4. Therefore, the bug changes direction at t = 4.

To verify this, we can look at the behavior of the bug's velocity as it approaches t = 4. From the graph, we see that the bug's velocity is increasing as it approaches t = 4 from the left, and decreasing as it approaches t = 4 from the right. This indicates that the bug is reaching a maximum velocity at t = 4, which is when it changes direction.

Therefore, the bug changes direction at t = 4.

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Answer:

Step-by-step explanation:

OB = 10 cm

OA = OC = Radius = 4 cm

COS <AB = OA/OB = 4/10 = 2/5 =

COS< COB = OC/OB = 4/10 = 2/5

=> <AOC = <AOB + <COB

=> <AOC = Cos-¹(2/5) + Cos-¹(2/5)

=> <AOC = 2 Cos-¹(2/5)

=> <AOC = 2 * 66.42

=> <AOC = 132.84°

if D is in minor arc then length of arc ADC. = ( 132.84°/360°) 2π = 9.274 cm

if D is in major arc then length of arc ADC. = ((360° -132.84°)/360°) 2π = 15.859 cm

The expression to describe how many more seconds Tatenda spends than Ciara spends mowing lawns during 444 weeks is:

(444 weeks) * (7 days/week) * (24 hours/day) * (60 minutes/hour) * (60 seconds/minute) * (Tatenda's mowing time per second - Ciara's mowing time per second)

To calculate the total time in seconds that Tatenda spends more than Ciara mowing lawns during 444 weeks, we need to convert the time units and multiply them together.

First, we convert 444 weeks to days:

444 weeks * 7 days/week = 3108 days

Then, we convert days to hours:

3108 days * 24 hours/day = 74616 hours

Next, we convert hours to minutes:

74616 hours * 60 minutes/hour = 4476960 minutes

After that, we convert minutes to seconds:

4476960 minutes * 60 seconds/minute = 268617600 seconds

Finally, we multiply the total seconds by the difference in mowing time per second between Tatenda and Ciara.

During 444 weeks, Tatenda spends 268,617,600 seconds more than Ciara mowing lawns. This expression takes into account the number of weeks, days, hours, minutes, and seconds, as well as the difference in their mowing time per second.

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Substituting these values back into equation (i), we get D = 4(3) = 12. There are 3 nickels, 12 dimes, and 3 quarters in the collection.

Let's assume the number of nickels is N, the number of dimes is D, and the number of quarters is Q. From the given information, we can deduce three equations:

(i) D = 4N (since there are 4 times more dimes than nickels),

(ii) N + D + Q = 18 (since there are 18 coins in total), and

(iii) 5N + 10D + 25Q = 290 (since the total value of the coins is 290 cents or $2.90).

To solve these equations, we can substitute the value of D from equation (i) into equations (ii) and (iii).

Substituting D = 4N into equation (ii), we get N + 4N + Q = 18, which simplifies to 5N + Q = 18.

Substituting D = 4N into equation (iii), we get 5N + 10(4N) + 25Q = 290, which simplifies to 45N + 25Q = 290.

Now we have a system of two equations with two variables (N and Q). By solving these equations simultaneously, we find N = 3 and Q = 3.

Substituting these values back into equation (i), we get D = 4(3) = 12.

Therefore, there are 3 nickels, 12 dimes, and 3 quarters in the collection.

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Answer:

Opposite

------------------------------------

Answer:

4,4,5,7,10

Step-by-step explanation:

this can be

4,4,5,7,10

5 is in the middle because 5 is median

4 appeared thrice cause it is the mode

and 10 is just there to give us our mean 6 because it is only 30/5 that gives 6 so we have to find 5 numbers whose sum gives 30

Answer:

The 5 numbers can be: 4, 4, 5, 8, 9.

Step-by-step explanation:

In 4, 4, 5, 8, 9.     5 is the median (The middle number).

The mode is 4 because 4 is the most repeated number.

(4+4+5+8+9)/5 is equal to 30/5 which equals 6. So, 6 is the mean.

Hope this helps! :)

Answer:

The probability that the customer finds exactly one defective light bulb among the eight purchased is approximately 0.042 or 4.2%.

Step-by-step explanation:

To find the probability that the customer finds exactly one defective light bulb among the eight they purchased, we can use the formula for combinations and probability.

1. Calculate the number of ways to choose one defective light bulb and seven non-defective light bulbs: -

Number of ways to choose 1 defective light bulb:

C(5,1) = 5! / (1! * (5-1)!) = 5

Number of ways to choose 7 non-defective light bulbs:

C(45,7) = 45! / (7! * (45-7)!) = 453,024

2. Multiply the number of ways together: -

5 (number of ways to choose 1 defective) * 453,024 (number of ways to choose 7 non-defective) = 2,265,120 (total ways to choose exactly 1 defective and 7 non-defective light bulbs)

3. Calculate the total possible ways to choose any 8 light bulbs from the 50 available: - C(50,8) = 50! / (8! * (50-8)!) = 53,907,800

4. Divide the favorable outcomes (exactly 1 defective and 7 non-defective) by the total possible outcomes: -

Probability = 2,265,120 (favorable outcomes) / 53,907,800 (total outcomes) ≈ 0.042

Therefore, the probability that the customer finds exactly one defective light bulb among the eight purchased is approximately 0.042 or 4.2%.

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The correct set of possible results would be (0, 1, 0, 0), (1, 2, 1, 0) and (1, 2, 0, 1).

Your approach seems to be correct, but there seems to be a minor mistake in your final list of possible solutions. Let's go through the steps to clarify.

Given the initial conditions z=t=0, you obtained a partial solution (0,1,0,0).

Next, you solved the homogeneous equations for z=1 and t=0, which resulted in a solution (1,1,1,0).

Similarly, solving the homogeneous equations for z=0 and t=1 gives another solution (1,1,0,1).

To find the general solution, you combine the partial solution with the solutions obtained in the previous step, using parameters a and b.

(0,1,0,0) + a(1,1,1,0) + b(1,1,0,1)

Expanding this expression, you get:

(0+a+b, 1+a+b, 0+a, 0+b)

Simplifying, you obtain the following set of solutions:

(0, 1, 0, 0)

(1, 2, 1, 0)

(1, 2, 0, 1)

Therefore, the correct set of possible results would be:

(0, 1, 0, 0)

(1, 2, 1, 0)

(1, 2, 0, 1)

Note that (0, 1, 1, 1) is not a valid solution in this case, as it does not satisfy the initial condition z = 0.

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The most reasonable method for assigning each participant to a design in order to obtain the most precise comparisons between the two designs without systematic bias would be to use the method of randomly assigning participants to the designs.

This helps ensure that any potential confounding variables or biases are evenly distributed between the two groups, leading to more accurate and reliable results.

Option C, where participants pick a ball from a bag, and Option D, where participants flip a coin, both involve randomization and are valid methods of assignment. Randomization helps eliminate any potential bias in the assignment process and ensures that the groups are comparable.

Option A, where participants rate their experience and are assigned accordingly, may introduce bias because participants with more experience may have different expectations or preferences that could influence their responses.

Option B, where designs are assigned based on the order of arrival, may introduce confounding variables if there are any systematic differences in the characteristics or behaviors of participants based on their arrival order.

Therefore, Option C (randomly assigning participants by picking balls from a bag) or Option D (randomly assigning participants by flipping a coin) would be the most reasonable methods for assigning participants to the designs in order to obtain precise comparisons without systematic bias.

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The volume of the solid of revolution is -6π or we can write it as 6π with a negative sign indicating that the solid is inverted or turned inside out.

we need to use the formula:

where a and b are the limits of integration and f(x) is the function being revolved around the axis.

In this case, the region bounded by f(x)=(4−x)^(-1/3) and the x-axis on the interval [0,4) is being revolved around the y-axis.

we have:

the volume of the solid of revolution is:

Simplifying the integral:

This integral can be evaluated using various integration techniques, such as substitution or integration by parts.

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We are given the function f(t) = 6t^2(t - 3) defined on the interval (0, 3]. We need to compute the odd and even periodic extensions, denoted as Fodd and Feven respectively, of this function at specific values.

To compute the odd and even periodic extensions, we first need to define the odd and even extensions of the function f(t) outside the interval (0, 3].
For the odd extension, we reflect the function f(t) about the y-axis, resulting in Fodd(t) = -f(-t) for t < 0.
For the even extension, we reflect the function f(t) about the y-axis and extend it periodically, resulting in Feven(t) = f(-t) for t < 0 and Feven(t) = f(t - 6k) for t > 3, where k is an integer.
Now, let's compute the values:
Fodd(0.1) can be found by evaluating -f(-0.1), substituting -0.1 into f(t) = 6t^2(t - 3).
Fodd(-0.5) can be found by evaluating -f(0.5), substituting 0.5 into f(t) = 6t^2(t - 3).
Fodd(4.5) can be found by evaluating f(4.5), substituting 4.5 into f(t) = 6t^2(t - 3).Fodd(-4.5) can be found by evaluating -f(-4.5), substituting -4.5 into f(t) = 6t^2(t - 3).
Similarly, we can compute the values for the even periodic extension:
Feven(0.1) can be found by evaluating f(0.1).
Feven(-0.5) can be found by evaluating f(-0.5).
Feven(4.5) can be found by evaluating f(4.5).
Feven(-4.5) can be found by evaluating f(-4.5).By substituting the given values into the respective extension functions, we can compute the values Fodd(0.1), Fodd(-0.5), Fodd(4.5), Fodd(-4.5), Feven(0.1), Feven(-0.5), Feven(4.5), and Feven(-4.5).

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