If the mass of the suspended object is doubled, the acceleration of the block up theplane C) g(2tanθ - k sinθ).
Let's consider the given equation for the acceleration of the block up the plane:
a = g(sinθ - μcosθ)
where g is the acceleration due to gravity, θ is the angle of inclination of the plane, μ is the coefficient of friction, and k is the ratio of the mass of the suspended object to the mass of the block.
If we double the mass of the suspended object, then k becomes 2k, and the equation for the acceleration becomes:
a' = g(sinθ - 2kμcosθ)
We can rearrange this equation as follows:
a' = g(sinθ - k(2μcosθ))
a' = g(sinθ - k(2sinθcosθ/μ)cosθ)
a' = g(sinθ - 2tanθk sinθ)
Therefore, the acceleration of the block up the plane when the mass of the suspended object is doubled is g(2tanθ - k sinθ), which is option C.
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Use your knowledge of chemical reactions, metals, and acids to determine which one of the following procedures is the LEAST hazardous?
I WILL GIVE 100 POINTS PLUS BRAINLIST:)
Answer:
I would say metals
Ok so let's start off by saying that chemicals take a big part in our life, right? Nevertheless, many of these chemicals may, especially if not appropriately used, endanger our health and poison our environment. Some reactions may result in death and injury to people, damage to physical property, and severe effects on the environment.
Next, let's talk about metals.
Metals are often good conductors of electricity and heat, shiny and pliable. The metals we use day-to-day are converted from metallic ores to their final form. Toxic metals sometimes imitate the action of an essential element in the body, interfering with the metabolic process resulting in illness.
Last, acids.
Acids can react violently with water and are harmful in the presence of moisture in the mouth or eyes or in proximity with other aqueous solutions
I hope this helps :)
Answer:
metals i think
Explanation:
Which shows a 2 kg cart traveling at a constant speed in a horizontal circle of radius 3 m the magnitude of the centripetal force of the car is 24 N what is the speed of the cart
Answer:
6m/s
Explanation:
Centripetal force is expressed according to the formula;
F = mv²/r
m is the mass of the body
v s the speed of the cart
r is the radius
Given
M = 2kg
r = 3m
Force F = 24N
Substitute into the formula and get v
24 = 2v²/3
24×3 = 2v²
72 = 2v²
v² = 72/2
v² = 36
v =√36
v = 6m/s
Hence the speed of the cart is 6m/s
When solutes are added to water; its physicochemical properties (such as melting point; boiling point; and vapor pressure) are changed due to entropy effects (a change in the number of ways the system can organize itself) Which of these statements is true (there may be more than one)? Select one or more: a. The melting point of water increases b. The boiling point of water increases c. The vapor pressure increases d. The melting point of water decreases
When solutes are added to water, the following statements are true:
a. The melting point of water decreases: Adding solutes to water disrupts the regular arrangement of water molecules, making it more difficult for them to form the solid structure of ice. As a result, the melting point is lowered.
b. The boiling point of water increases: The presence of solute particles interferes with the water molecules' ability to escape the liquid phase and enter the gas phase. This means that more energy is required to boil the water, resulting in a higher boiling point.
c. The vapor pressure decreases: Due to the presence of solute particles, there are fewer water molecules available at the surface to evaporate, leading to a decrease in vapor pressure.
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Shown following are the names of several eras that are used to descried the history of the universe. Rank the eras from left to right in the order in which they occurred from first to last.
1. era of nucleosynthesis - fusion created helium nuclei
2. particle era - protons, neutrons both common
3. era of nuclei - H, He nuclei and electrons existed, but no neutral atoms
4. era of atoms - neutral atoms existed, but not stars
5. era of galaxies - stars and galaxies common
6. Planck era - all 4 forces operated as one
7.electroweak era - 3 forces operated: gravity, strong, electroweak
8. GUT era - strong, electroweak forces unite as GUT force
The Big Bang signified the beginning of the expansion of the universe from a singularity (or a region very close to one), a single point that was infinitely small, infinitely hot, and endlessly dense.
What eras that are used to the history of the universe?It is the era of the stars, galaxies, and life. Approximately 150 million years after the Big Bang, the universe entered this phase, which is predicted to last up to 86 billion years from now, when the cosmos will be able to celebrate its 100 billionth birthday.
Therefore, From first to last: Planck era, GUT era, electroweak era, particle era, era of nucleosynthesis, era of nuclei, era of atoms, era of galaxies
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As we study mass, volume, and density, we will compare the measurements of actual objects. Let's see how you do measuring mass. Download the activity worksheet to record your data. Begin by finding ten rectangular-shaped objects and measure the mass using a scale (any scale will do as long as it works). You can choose books, sandwiches, phones, pictures - as long as the shape is a rectangle. Then rank the objects from the one with the heaviest mass to the one with the lightest mass in the space provided. We will continue to measure, so once you are finished, continue with the lesson; but save your data worksheet - you'll need to complete the rest of the worksheet as we progress.
The mass of objects such as books, sandwiches, phones, pictures can be measured using a weighing balance scale.
What is the mass of an object?The mass of an object is defined as the scalar quantity of that object that shows the amount of matter that makes up the object.
Mass is called a scalar quantity as it doesn't require the direction of an object but only it's magnitude to be measured.
it is measured in Kilograms or Kg using a weighing balance scale.
The volume of an object is the relationship that exists between its height, length and width. That is, L×W×H.
The volume of the ten rectangular shaped objects given above can be measured once the height, length and width of the objects are known.
The density of the objects is the relationship that exists between the mass and the volume of the object. That is,
Density= mass/volume.
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How much work would have to be done by a force in moving an electron through a positive potentialdifference of 2.0 x 10^6V?
The work done by a force in moving an electron through a positive potential difference of 2.0 x 10^6V can be calculated using the formula W = q x V, where W is the work done, q is the charge of the electron (which is 1.6 x 10^-19 C), and V is the potential difference. Plugging in the values, we get:W = (1.6 x 10^-19 C) x (2.0 x 10^6V)
W = 3.2 x 10^-13 J
Therefore, the amount of work that would have to be done by a force in moving an electron through a positive potential difference of 2.0 x 10^6V is 3.2 x 10^-13 J.
To calculate the work done in moving an electron through a positive potential difference, you can use the following equation:Work (W) = Charge (q) × Potential Difference (V)
The charge of an electron (q) is approximately -1.6 × 10^-19 Coulombs, and the potential difference (V) given in the problem is 2.0 × 10^6 V.
W = (-1.6 × 10^-19 C) × (2.0 × 10^6 V)
W = -3.2 × 10^-13 Joules
The negative sign indicates that the work done is against the direction of the electric field. Therefore, the work required to move an electron through a positive potential difference of 2.0 × 10^6 V is 3.2 × 10^-13 Joules.
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Consider an uncharged, conducting hollow spherical shell. The electric field on the inside surface of the spherical shell is measured to be directed toward the inner shell wall and varies in magnitude over the spherical shell's inside surface. It is known that the only charge in the hollow cavity inside the spherical shell is a point charge with magnitude q. What is the sign of the charge q?
Answer:
The sign of charge q is negative.
Explanation:
This is because electric field lines usually emanate from positive charges and terminate at negative charges. The negative charge in the hollow cavity induces a positive charge on the inner shell wall of the hollow shell which in turn induces the negative charge q on the hollow spherical shell.
Since the induced electric charge on the inner wall is positive, the electric field lines from that charge terminates at the inner charge q. Since electric field lines terminate only at negative charges, q is negative.
Can you help me with this pls
Answer:
Can you help me with this pls
course: Electricity and magnetism
6.1B A current of 10 amp flows through a wire of 1 mm² cross section. If the density of charge carriers in the wire is 1027/m³, find the average drift velocity of the electrons.
The average drift velocity of the electrons is is approximately 6.25 x 10^6 m/s.
To find find the average drift velocity of the electrons, we have to make use of the drift velocity formula. The drift velocity formula is used to relate the average drift velocity of charge carriers in a conductor to the applied electric field. It is used to understand the motion of electrons when an electric current is flowing.
The drift velocity formula is:
\(I = nAvq\)
Where:
I is the current (in Amperes),
n is the density of charge carriers,
A is the cross-sectional area of the wire,
v is the average drift velocity of electrons,
q is the charge of an electron.
In this case, we have been given current as 10A, cross-sectional area of the wire is 1mm². The density of charge carriers in the wire is 1027/m³. So, by substituting all the given identities in the equation and rearranging the equation to find out "v", we get:
\(v = I / (nAq)\)
\(v = (10 A) / ((10^{27} /m^{3} ) * (1 * 10^{-6} m^{2}) * (1.6 * 10^{-19} C))\)
\(v = (10 A) / (1.6 * 10^{-12} A * m^{2} * C * 10^{27} /m^{3} )\)
\(v = 6.25 * 10^{6} m/s\)
Therefore, the average drift velocity of electrons in the wire is approximately 6.25 x 10^6 m/s.
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Answer:
Average drift velocity of the electrons is Approx. 6.25*10^6 m/s.
Given, Current= 10A
Cross sectional area = 1mm^2
Density of charge= 1027/m^3
Formula to find velocity= I/(nAq)
= 10/(1027*1*10^-6*1.6*10^-19)
=6.25*10^6m/s
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Which items in this image are electrically conductive? Check all that apply.
Answer: a and d
Explanation: A.) the power lines themselves
B.) the wooden pole that supports the lines
C.) the rubber soles on the worker’s boots
D.) the metal tools the worker uses
E.) the wooden ladder leaning against the lines
earth is located at one of the moon's orbit.target 1 of 6 2. according to kepler's second law, jupiter will be traveling most slowly around the sun when at .target 2 of 6 3. earth orbits in the shape of a/an blankaround the sun.target 3 of 6 4. the mathematical form of kepler's third law measures the period in years and the blankin astronomical units (au).target 4 of 6 5. according to kepler's second law, pluto will be traveling fastest around the sun when at blank.target 5 of 6 6. the extent to which mars' orbit differs from a perfect circle is called its
1. Earth is located at one focus of the Moon's orbit.
2. According to kepler's second law, jupiter will be traveling most slowly around the sun's aphelion
3. Earth orbits in the shape of a/an ellipse around the sun.
4. The mathematical form of Kepler's third law measures the period in years and the semimajor axis in astronomical units (AU).
5. According to Kepler's second law, Pluto will be traveling fastest around the Sun when at perihelion.
6. The extent to which Mar's orbit differs from a perfect circle is eccentricity.
What is kepler's second and third law?
Kepler's second law is a mathematical principle that states the distance between two objects in space is proportional to the square of their timescale of revolution. This means that as two objects orbit around each other, the further they will be from each other over time.
Kepler's Third Law is a scientific law that states the amount of time it takes for planets to orbit their star is inversely proportional to their distance from the sun.
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Yes! All orbiting objects adhere to Kepler's Second Law and other rules as well. Pluto moves more quickly when it is nearer the sun and less quickly when it is distant from it, much like every other object in our solar system.
What is Kepler's law of planetary motion?In astronomy, Johannes Kepler's laws of planetary motion, which were written between 1609 and 1619, define the paths taken by planets as they round the Sun. The laws altered Nicolaus Copernicus' heliocentric theory, substituting elliptical trajectories for circular orbits and epicycles, thereby explaining the variation in planetary velocities. According to the three laws:
A planet's orbit is an ellipse with the Sun as one of its two foci.Equal areas are covered over equal times by a line segment connecting a planet and the Sun.The semi-major axis of an orbital system is related to the square of the planet's orbital period.To know more about Kepler's law, visit:
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this for my previous question.. im so sorry
Answer:
the answer for the question is C
What is the connection of H ions at a ph=2?
Answer:
Explanation:
High concentrations of hydrogen ions yield a low pH (acidic substances), whereas low levels of hydrogen ions result in a high pH (basic substances). The overall concentration of hydrogen ions is inversely related to its pH and can be measured on the pH scale
the ball in the figure rotates counterclockwise in a circle of radius 3.39 m with a constant angular speed of 8.00 rad/s. at t = 0, its shadow has an x coordinate of 2.00 m and is moving to the right.
To determine the position of the shadow at a specific time, we can use the concept of angular velocity and the relationship between angular displacement and linear displacement.
Given:
Radius of the circle (r) = 3.39 m
Angular speed (ω) = 8.00 rad/s
Initial x-coordinate of the shadow (x) = 2.00 m The ball rotates counterclockwise, which means the shadow moves to the right initially. We can use the equation: x = r * cos(θ) At t = 0, the angular displacement (θ) is 0, and the x-coordinate of the shadow is 2.00 m. We can solve for θ using the inverse cosine function:
θ = cos^(-1)(x/r)
θ = cos^(-1)(2.00 m / 3.39 m)
Calculating the value of θ: θ ≈ 55.40 degrees. Since the ball rotates counterclockwise at a constant angular speed, we can determine the angular displacement at any given time using the equation: θ = ω * tmNow, let's find the angular displacement at t = 0. We substitute the values:θ = 8.00 rad/s * 0 s θ = 0 rad. Therefore, the shadow is initially at an angular displacement of 55.40 degrees, and the angular displacement remains 0 at t = 0.
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Your goal is to throw a ball as far as you can. You have a choice to throw a 1lb ball, 3lb ball, or a 5lb ball. Which ball would you pick and why? Use Newton's second law (formula) in your explanation.
Answer:
Obviously, the 5lb ball when thrown will go farther . Newton second law of motion F = mass x acceleration .
So the more the mass , the more force will be used to throw the ball.
Explanation:
a car is traveling at 10 m/s when the driver slams on the brakes. the car skids about a meter before stopping. if the car is moving at 20 m/s when the driver slams on the brakes, how far will it skid before stopping?
When the speed is 20 m/s, the car will skid 2.5 meters before coming to a stop.
Distance is a number that shows how far an object changes position. Speed is a quantity that shows how fast an object is moving. Time is the interval between two states/events, or it can be the duration of an event.
The formula for time is t = s : v
With
t is timev is speeds is the mileageOn this question:
s = 1 m, v = 10 m/s, t = ?
t = 1 : 10
t = 0.1 second
Then the stopping time of the car is 0.1 s
To calculate the distance traveled when the car stops at a speed of 20 m/s. The first step is to calculate the acceleration first
v1 = 20 m/s, v0 = 10 m/s, t = 0.1 s
a = (v1 – v0) /t
a = (20 – 10)/ 0.1
a = 10/0.1
a = 100m/s
Next, calculate the distance the car stops when the speed is 20 m/s
s = Vo. t + ½ at^2
s = 20. 0.1 + ½ (100) 0.1
s = 2 + 0.5
s = 2.5 meters
So, the car will skid before stopping is 2.5 m
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How much time is it required for a athlete to lift a 1200 Kg weights up 14m from the ground if he can only produce 9 Kw of power.
Given,
The mass is m=1200kg
Height is h=14 m
Power is P=9kW
We know
Energy per unit time is power.
Thus,
P=mgh/t
where t is the time.
Thus,
\(\begin{gathered} 9\times10^3=\frac{1200\times9.81\times14}{t} \\ \Rightarrow t=18.312 \end{gathered}\)The time is 18.312 sec.
A projectile is shot horizontally off the roof of a building with a speed of 45 m/s and falls to
the ground in 3.2 seconds.
a. What is the horizontal displacement of the projectile?
I
b. How high is the building?
I think that the awsand is 147.2 .
Who is the father of nuclear physics?
Answer: the father of the nuclear physics is Ernest Rutherford
Explanation:
please help its worth 10 points
no links please!
Answer:
which question
A block is released from rest at the top of a hill of height h. If there is negligible friction between the block and the hill, the block arrives at the bottom of the hill with speed v.
Answer:
v / √2
Explanation:
A blocked from rest at the top of a hill of height h it there is negligible friction between the block and the hill, the block arrives at the bottom of the hill with speed. The block is released from rest at the top of another hill with a rough surface and height h. if one-half of the initial mechanical energy of the block Earth System is lost due to friction as the block descends the hill, the block will reach the bottom of the hill with a speed of?
Solution:
For the first block block, its potential energy at the top of the hill when it is at rest is converted to kinetic energy after release with a velocity v.
The kinetic energy = (1/2)mv², where m is the mass of the block.
For the other block placed on the top of the rough hill, the mechanical energy (kinetic energy) is halved due to the roughness of the hill. If u is the speed of this block at the bottom of the hill then:
kinetic energy of block on the rough hill = (1//2)mu²
Hence:
(1//2)mu² = half of main system kinetic energy
(1//2)mu² = 1/2 * (1/2)mv²
mu² = (1/2)mv²
u² = (1/2)v²
u = √(v²/2)
u = v / √2
Hence the speed at the bottom of the rock of the block placed on the rough surface is v / √2
a. l1 =20 A and l2 =24 A
B. l1 = 20A and l2 = 12 A
C. l1 = 26 A and l2 = 12 A
D. l1 = 24 A and l2 = 8 A
Answer:
when u find out pls lmk! i have the same question and I've been stuck for a while lol
a stone is dropped from a high cliff. If it accelerates at a rate of 9.8 m/s^2. what is its velocity after 5 seconds? write the equation
Answer:
The velocity after 5 seconds is 49.05
Explanation:
Comment
This is an application question for a = (vf - vi)/t
a is the acceleration 9.81 m/s^2
vi is the starting speed ( of zero because the stone is dropped, not thrown).
vf is the final velocity after 8 seconds
t is the time
Solution
9.81 m/s^2 = (vf - vi)/t Substitute the givens
9.81 m/s^2 = (vf - 0)/5 Multiply both sides by 5
9.81 * 5 = 5* vf/5
vf = 49.05
you are flying at 0.97 c with respect to kara. at the exact instant you pass kara, she fires a very short laser pulse in the same direction you're heading.
The laser pulse will still be moving at the speed of light (c), while from Kara's perspective, it will appear to be moving slower due to your high relative velocity.
When you are flying at 0.97 times the speed of light (0.97c) with respect to Kara, and at the exact moment you pass her, she fires a very short laser pulse in the same direction as your motion, several things happen:
1. According to the principle of relativity, the speed of light is constant in all inertial reference frames.
Therefore, regardless of your motion, the laser pulse will always travel at the speed of light (c) relative to both you and Kara.
2. Since you are already moving at 0.97c, the speed of light relative to you will still be c.
This means that the laser pulse will not appear to be moving faster or slower to you due to your motion.
3. In Kara's frame of reference, the laser pulse will also be moving at the speed of light (c) relative to her.
Since you are moving away from her at 0.97c, the laser pulse will appear to be moving slower to her.
This phenomenon is known as time dilation.
In conclusion, from your perspective, the laser pulse will still be moving at the speed of light (c), while from Kara's perspective, it will appear to be moving slower due to your high relative velocity.
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How long does it take the principal to run to our classroom, if the distance is 125 meters, and he accelerates,
from rest, at a rate of 4 m/s^2?
answer
The kinematics to find the time to go from the office to the living room is: 2.81 s
Given Parameters
The distance x = 125 n The acceleration a = 4 m / s²To find
The timeKinematics allows us to find the relationships between the position, velocity and acceleration of bodies, let's use the relationship
x = v₀ t + ½ a t²
Where x is the position, v₀ the initial velocity, at acceleration and t the time
In this case, as he leaves the office, the initial velocity is zero.
x = ½ a t²
t = \(\sqrt{\frac{2x}{a} }\)
Let's calculate
t = \(\sqrt{\frac{2 \ 125}{4} }\)
t = 2.81 s
In conclusion, using the kinematics, we find that the time to go from the office to the classroom is: 2.81 s
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At one instant a heavy object in the air moving upward at 50 meters per second. One second later its speed in meters per second is approximately
a. 40 m/s
b. 50m/s
c. 60 m/s
d. 55 m/s
One second later its speed in meters per second is approximately a. 40 m/s.
Given that a heavy object is moving upward at 50 meters per second, we need to determine its speed one second later. To do this, we will consider the effects of gravity on the object's motion.
Gravity exerts a force on the object which causes it to decelerate. On Earth, the acceleration due to gravity is approximately 9.8 meters per second squared (m/s²) acting downwards. As the object is moving upwards, the gravitational force will reduce its speed by 9.8 m/s every second.
After one second, the object's speed will be reduced by 9.8 m/s. Therefore, the new speed can be calculated as follows:
Initial speed - deceleration due to gravity = New speed
50 m/s - 9.8 m/s = 40.2 m/s
Based on the available options, the closest approximation to the object's speed after one second is 40 m/s (option a).
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Which of these is not a major temperature scale?
A : Ohm
B : Kelvin
C : Celsius
D : Fahrenheit
ohms is not a major temperature scale
hey friend your answer is
I hope it will helpful for you
mark as brainest answer
thank you
The option that is not a major temperature scale is : ( A ) Ohm
Definition of ohm
Ohm is the unit used for the measurement of resistance in an electrical material, therefore is not a measurement which can be used on a temperature scale.
Kelvin, Celsius and Fahrenheit are all major temperature units that can be used on a temperature scale.
Hence we can conclude that the option that is not a major temperature scale is Ohm
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7. A complex arrangement of pulleys forms what is called the block in a block
and tackle. The rope used to lift the pulleys and the load is the tackle. A block
and tackle is used to lift a truck engine, which weighs nearly 7,406 N. The
force required to lift this weight using the block and tackle is 308.6 N. What is
the mechanical advantage of the block and tackle?
Answer:
24
Explanation:
Given parameters:
Load = 7406N
Effort = 308.6N
Unknown:
The mechanical advantage of the block and tackle system = ?
Solution:
Mechanical advantage is the ability of a simple machine to amplify or increase the force needed to do work.
Mathematically;
M.A = Output force / Input force
Output force = Load
Input force = Effort
M.A = 7406N / 308.6N = 24
The mechanical advantage is 24
A film with thickness t gives constructive interference for light with a wavelength in the film of λfilm. How much thicker would the film need to be in order to give destructive interference?
A. 2λfilm
B. λfilm
C. λfilm/2
D. λfilm/4
Light with a wavelength in the film's thickness t exhibits constructive interference.
What exactly is a damaging interference?
When two waves are entirely out of phase (a peak is located in the middle of two waves), destructive interference ensues. In other words, destructive interference occurs when two waves 180 degrees or radians apart from each other cancel each other out.
What causes waves to interfere destructively?
When two waves' maxima are 180 degrees out of phase, destructive interference happens: a positive displacement of one wave is precisely cancelled by a negative displacement of the other wave. The resultant wave has zero amplitude.
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a window-mounted air conditioner removes 3.5 kj from the inside of a home using 1.75 kj work input. how much energy is released outside and what is its coefficient of performance?
The amount of heat released outside is 3.5 kJ and the coefficient of performance is 2.
What is efficiency of a machine?The efficiency of the a machine or any device is the measure of effectiveness of the device. Efficiency describes how a machine converts input energy to output energy without wasting much of the input energy.
Mathematically, efficiency of a machine is given as;
E = output energy / input energy x 100%
The coefficient of performance (COP) of a heat pump, refrigerator or air conditioning system is a ratio of useful heating or cooling provided to work required.
The energy released outside = 3.5 kJ
COP = 3.5 kJ / 1.75 kJ
COP = 2
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