10+10 what is the answer

The probability of choosing a subcommittee of 3 members with no graduate students is 0.2, or 20%.

The number of possible subcommittees that contain only undergraduate students can be calculated by choosing 3 members from the 4 undergraduate students. This can be done in

(4 choose 3) = 4 ways.

The total number of possible subcommittees of three students that can be formed from the 6 members of the committee can be calculated by choosing 3 members from the 6 students. This can be done in

(6 choose 3) = 20 ways.

Therefore, the probability that there will be no graduate students on the subcommittee is:

Number of subcommittees with only undergraduate students / Total number of possible subcommittees

= 4 / 20

= 1/5

= 0.2

So, the probability of choosing a subcommittee of 3 members with no graduate students is 0.2, or 20%.

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Answer:

B. 10

Step-by-step explanation:

While doing construction O and P are joined then

OQ = OR

<QOR = 80°

<QPR = <QOR /2 ( INSCRIBED ANGLE IS HALF OF THE CENTRAL ANGLE STANDING ON SAME ARC)

<QPR = 80°/2

<QPR = 40°

SO

< QPO = X

<RPO = 30°

<QPO + <RPO = < QPR

X + 30° = 40°

X = 40° - 30°

X = 10°

hope it helps

The lines shown in the drawing are:

A. DC

C. ED

D. DA

In the drawing above, several lines are shown. To identify the lines, look out for the points that run from one axis to the next one. Given the diagram, the lines given are DC, ED, and DA. The person viewing the diagram can easily spot the ends of the lines.

Note that lines tend to run from one end to another. BC is not a line shown in this table because there is no clear-cut way of linking up the two points. So, option B is not included.

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Answer:

6

Step-by-step explanation:

Let the number be x.

1/3 × 12 = 2/3 × x

Multiply.

12/3 = 2/3x

4 = 2/3x

Multiply both sides by 3/2.

4 × 3/2 = x

12/2 = x

x= 6

Answer:

1/3 of 12 = 2/3 of 6

Step-by-step explanation:

1/3 · 12 = 2/3 · x

12/3 = 2x/3

Multiply 3 on both sides.

12 = 2x

12 ÷ 2 = x

6 = x

The exact value of cos 240° is -1/2. To find the exact value of cos 240° using a double-angle identity, we can use the double-angle formula for cosine .

cos(2θ) = 2cos^2(θ) - 1

Let's substitute θ = 120° into the formula:

cos(2 * 120°) = 2cos^2(120°) - 1

Simplifying the expression:

cos(240°) = 2cos^2(120°) - 1

Now, let's find the value of cos(120°). We know that cos(120°) = -1/2, so we can substitute that value in:

cos(240°) = 2cos^2(120°) - 1

          = 2(-1/2)^2 - 1

          = 2(1/4) - 1

          = 1/2 - 1

          = 1/2 - 2/2

          = -1/2

Therefore, the exact value of cos 240° is -1/2.

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Answer:

225 x 0.15 = 33.75 profit

Step-by-step explanation:

Answer:

Profit:  Rs 33.75

Step-by-step explanation:

His profit was 15% of Rs 225, which comes to 0.15(Rs 225), or Rs 33.75

The temperature at a given chirp rate can be determined from a linear regression model as follows;

a. The linear regression model is; T = 4.1484·C - 166.1

b. At 72 °F the chirp rate is approximately 57 chirps per minute

At 90 °F the chirp rate is approximately 62 chirps per minute

A linear regression model, models a relationship between variables using a linear approach

a. The data given the values of the temperatures at a  given chirp rate per minute is used to create the attached scatter plot.

From the scatter plot, a trend line is drawn using the Add Chart Element, within the Chart Tools, Design Menu.

From the Format Trendline window, The Display Equation on chart check box is selected, to show the trend line equation.

The trendline equation that is the linear regression model for chirp rate as a function of time is; y = 4.1484·x - 166.1

Where, y = T, and x = C, we have; T = 4.1484·C - 166.1

b. If the temperature, T, is 72 °F, we have;

T = 72 °F

72 = 4.1484·C - 166.1

\(C = \dfrac{72+166.1}{4.1484} \approx 57\)

If the temperature is 90 °F, the chirp rate is calculated as follows;

T = 90 = 4.1484·C - 166.1

\(C = \dfrac{90+166.1}{4.1484} \approx 62\)

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Answer:

(8/3, ∝)

Step-by-step explanation:

Definition

The Mean Value Theorem states that for a continuous and differentiable function \(f(x)\) on the closed interval [a,b], there exists a number c from the open interval (a,b) such that \(\bold{f'(c)=\frac{f(b)-f(a)}{b-a}}\)

Note:

A closed interval interval includes the end points. Thus if a number x is in the closed interval [a, b] then it is equivalent to stating a ≤ x ≤ b.

An open interval does not include the end points so if x is in the open interval (a, b) then a < x < b

This distinction is important

The function is \(y = f(x)=\ln\left(3x-8\right)\)

Let's calculate the first derivative of this function using substitution and the chain rule

Let

\(u(x) = 3x-8\\\\\frac{du}{dx} = \frac{d}{dx}(3x-8) = \frac{d}{dx}(3x) - \frac{d}{dx}8 = 3 - 0 =3\\\\\)

Substituting in the original function f(x), we get

\(y = ln(u)\\\\dy/du = \frac{1}{u}\)

Using the chain rule

\(\frac{dy}{dx}=\frac{dy}{du}.\frac{du}{dx}\)

We get

\(\frac{dy}{dx}=\frac{1}{u}3=\frac{1}{3x-8}3=\frac{3}{3x-8}\)

This has a real value for all values of x except for x = 8/3 because at x = 8/3, 3x - 8 = 0 and division by zero is undefined

Now \(ln(x)\) is defined only for values of x > 0. That means 3x-8 > 0 ==> 3x > 8 or x > 8/3

There is no upper limit on the value of x for ln(x) since ln(x) as x approaches ∝ ln(x) approaches  ∝ and  as x approaches ∝ 3/(3x-8) approaches 0

So the interval over which the mean theorem applies is the open interval (8/3, ∝)

At x = 8/3 the first derivative does not exist

Graphing these functions can give you a better visual representation

The solution to the initial value problem \(y'(x) = 10x^4 - 4x^{-5}, y(1)=0, is y(x) = 2x^5 + x^{-4} - 3\).

To solve the initial value problem \(y'(x) = 10x^4 - 4x^{-5}, y(1)=0\), we will integrate y'(x) to find y(x): 1. Start with \(y'(x) = 10x^4 - 4x^{-5}\). 2. Integrate both sides with respect to x:
\(y(x) = ∫(10x^4 - 4x^{-5}) dx\).

3. Apply the power rule for integration:
  \(y(x) = (10/5)x^5 + (4/(-4))x^{-4} + C\), where C is the constant of integration.

4. Simplify: \(y(x) = 2x^5 + x^{-4} + C\)

5. Use the initial condition y(1) = 0 to find C:
  \(0 = 2(1)^5 + (1)^{-4} + C => C = -3\).
6. Plug C back into \(y(x): y(x) = 2x^5 + x^{-4} - 3.\)

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The given statement is false.

While both the algebraic and spreadsheet approaches to linear programming aim to optimize a linear objective function subject to linear constraints, the steps involved in the two methods are different. Therefore given statement is false.

In the algebraic approach, the problem is formulated mathematically using linear equations and inequalities. The objective function and constraints are written in terms of decision variables, and the system of equations is solved using techniques such as the simplex method or graphical method.

In the spreadsheet approach, the problem is set up in a spreadsheet using cells to represent decision variables and constraints. The objective function is entered as a formula, and constraints are entered as inequalities. The solver tool is used to find the optimal solution.

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The solution to the given boundary-value problem is y(x) = 2sin(pi*x) + x, where y(0) = 0 and y(1) = y'(1) = 0.

To solve the given boundary-value problem, we first write the differential equation in standard form

y'' + 7y = 7x

Next, we find the general solution of the homogeneous equation y'' + 7y = 0

The characteristic equation is r^2 + 7 = 0, which has roots r = ±√(7)i. Thus, the general solution of the homogeneous equation is

y_h(x) = c₁*cos(√(7)x) + c₂sin(√(7)*x)

where c₁ and c₂ are constants to be determined by the initial conditions.

Now, we find a particular solution of the non-homogeneous equation y'' + 7y = 7x

A particular solution of the non-homogeneous equation is y_p(x) = Ax + B, where A and B are constants. Substituting this into the differential equation, we get

0 + 7(Ax + B) = 7x

Solving for A and B, we get A = 1 and B = 0. Thus, a particular solution of the non-homogeneous equation is y_p(x) = x.

Therefore, the general solution of the given differential equation is

y(x) = c1*cos(√(7)x) + c2sin(√(7)*x) + x

Using the first initial condition y(0) = 0, we get

c1 = 0

Using the second initial condition y(1) = 0, y'(1) = 0, we get

c₂sin(√(7)) + 1 = 0

c₂sqrt(7)*cos(√(7)) = 0

Since c₂ cannot be zero, the second equation gives us cos(sqrt(7)) = 0, which implies sqrt(7) = (2n+1)*pi/2 for some integer n. Thus, the possible values of √(7) are

√(7) = pi/2, 3pi/2, 5pi/2, ...

Therefore, the general solution of the differential equation that satisfies the boundary conditions is

y(x) = (2/n)sin(npi*x) + x, where n is an odd integer.

In particular, the solution satisfying the given initial conditions is

y(x) = (2/1)sin(pix) + x = 2sin(pi*x) + x

Hence, the solution of the problem is y(x) = 2sin(pi*x) + x, where y(0) = 0 and y(1) = y'(1) = 0.

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The total cashback you will get back is\($ 49.75}\)

The Given, original price \($=\$ 50$\) Sales fax\($=9.5 \%$\\\)

For first sale

                 \(\begin{aligned}\text { Price of item } & =\$ 50 \\\text { sales tax } & =+\$ 4.75 \\10 \% \text { discount } & =\frac{-\$ 5}{\$ 49.75}\end{aligned}\)

A sale is a transaction between two or more parties that involves the exchange of tangible or intangible goods, services, or assets for money. In some cases, assets other than cash are paid to a seller.

In the financial markets, a sale can also refer to an agreement that a buyer and seller make regarding a financial security, its price, and specific arrangements for its delivery.

Regardless of the context, a sale is essentially a contract between a seller of a particular good or service and a buyer who is willing to pay for that good or service.

for second Sale:-

There is no tax

So price\($=\$ 50$\)

For third sale: - Buy 3 and get 1 half of

\(\begin{aligned}\text { Price }=50 \times 3 & =\$ 150 \\\text { Sales tax }= & +\$ 14.25 \\\text { Discount } & =\frac{-\$ 25}{\$ 139.25}\end{aligned}\)

So, price of 1 piece \($=\$ 46.42$\)

for fourth Sale; - Buy anything over \(\$40\) and get \($\$ 5$\) gift card.

\(& \text { Price }=\$ 50 \\& \text { sales tax }=+\$ 4.75 \\& \text { Gift card }=\frac{-\$ 5}{\$ 49.75}\end{aligned}\)

Therefore, the cashback you will get back is \($ 49.75}\)

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10^2 = 100

7.4 × 10^2 = 7.4 × 100 = 740

We know that the cyclicity power (a^n) of 17 is 4.

\(\sf \longmapsto\bigg( \dfrac{17}{4}\bigg) = 1\)

\(\sf \longmapsto17^{(17/4)}\)

\(\sf \longmapsto17 {}^{} \)

\(\sf \longmapsto7(last \: digit )\)

The solution to the equation does not exist

From the question, we have the following parameters that can be used in our computation:

2x - 3 = 0

2x - 3 = 3

Also from the question, we understand that the graph is given as

3 = 0

The above equation is false, and cannot be represented on a graph

This is so because 0 and 3 do not have the same value

Similarly, we have 2x - 3 = 0 and 2x - 3 = 3

By substitution, the equations becomes

0 = 3

Hence, the equation has no solution

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Complete question

Graph of 3=0

Solve the equation 2x - 3 = 0 and 2x - 3 = 3 graphically

The steady-state response is given by the expression below;x = X1sin(ωt − α)We know that; For a damped system with sinusoidal forcing, the steady-state amplitude is given by;X1 = (F0/m) / [(ωn2 − ω2)2 + (2ζωnω)2]0.5To find the phase angle α, we use;tan α = 2ζωnω / (ωn2 − ω2)

Hence, α = tan-1 [2ζωnω / (ωn2 − ω2)]Given ζ = 0.5, ωn = 13 rad/s and ω = 3.1 rad/s, Substituting in the expressions above;X1 = (150/1) / [(13² − 3.1²)² + (2 × 0.5 × 13 × 3.1)²]0.5 = 0.1062 rad

Substituting again;α = tan-1 [2 × 0.5 × 13 × 3.1 / (13² − 3.1²)] = 71.688° = 71.688°Therefore, α = 71.688° to 3 decimal places.

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Answer:

Juan uso mayor cantidad de témpera.

Step-by-step explanation:

Para comparar fracciones que tienen distintos denominadores, como en este caso, es conveniente encontrar fracciones equivalente a las fracciones dadas, donde ambas tengan el mismo denominador. Dos fracciones son fracciones equivalentes cuando representan la misma parte de la unidad.

En este caso, para comparar las fracciones 3/5 y 3/4, obtienes que el mínimo común múltiplo entre los denominadores que es 20 (el denominador común se puede obtener multiplicando ambos denominadores o calculando el m.c.m) y amplificas cada una de las fracciones para que tengan el mismo denominador.

Entonces:

\(\frac{3}{5} =\frac{3*4}{5*4} =\frac{12}{20}\)

\(\frac{3}{4} =\frac{3*5}{4*5} =\frac{15}{20}\)

Cuando dos o más fracciones tienen igual denominador, es mayor la que tiene mayor numerador. Entonces en este caso podes observar 15/20 es mayor. Como 3/4 es una fracción equivalente a 15/20, entonces 3/3 es una fracción mayor. Por lo que es posible decir que Juan uso mayor cantidad de témpera.

Esto también se puede observar en la representación de la imagen adjunta, donde se divide en 1/4 y 1/5 y se encuentra pintado la cantidad usada por Juan y Mariana. En ese caso se puede ver que el área pintada es mayor en el caso de 3/4, la cantidad usada por Juan.

At point A, we have z = 15. Using the chain rule of differentiation, we have:

dz/dt = ∂z/∂x * ∂x/∂t + ∂z/∂y * ∂y/∂t

where ∂ represents partial differentiation.

From the given equation, we can find that:

x = tu^2v

y = u + tv

Taking partial derivatives with respect to t:

∂x/∂t = u^2v

∂y/∂t = v

Now, let's find the partial derivatives of z with respect to x and y:

∂z/∂x = (∂f/∂x) = 2x

∂z/∂y = (∂f/∂y) = v

At point A(1,1,3), we have:

x = tu^2v = 3

y = u + tv = 4

Solving for u and v, we get:

u = 1

v = 1

Therefore, at point A, we have:

∂x/∂t = u^2v = 1

∂y/∂t = v = 1

Using the given information, we have:

∂z/∂x * ∂x/∂t + ∂z/∂y * ∂y/∂t = -2

Substituting the values of the partial derivatives and solving for dz/dt, we get:

2x * ∂x/∂t + v * ∂y/∂t = -2

2(3)(1) + (1)(1) = 7

Therefore, dz/dt = 7 at point A.

Now, using the given formula, we have:

z = dz/dy * y

Taking the partial derivative of z with respect to y, we get:

dz/dy = ∂z/∂y = v = 3

Substituting the value of v at point A, we get:

z = 3y = 3(u + tv) = 15

Therefore, at point A, we have z = 15.

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Answer:

\(\frac{d^3}{c^5}\)

Step-by-step explanation:

using the rules of exponents

\(\frac{a^{m} }{a^{n} }\) = \(a^{(m-n)}\)

\(a^{-m}\) = \(\frac{1}{a^{m} }\)

given

\(\frac{c^9d^{-7} }{c^{14d^{-10} } }\)

= \(\frac{c^{9} }{c^{14} }\) × \(\frac{d^{-7} }{d^{-10} }\)

= \(c^{(9-14)}\) × \(d^{(-7-(-10))}\)

= \(c^{-5}\) × \(d^{(-7+10)}\)

= \(\frac{1}{c^{5} }\) ×  d³

= \(\frac{d^{3} }{c^{5} }\)

Answer:

1.5 cups of sugar

Step-by-step explanation:

Given:

-You need a 1/4 cup of sugar for 3 cups of Kool-Aid

-You need to find the amount of sugar you need for 18 cups of liquid

Solution:

You need to find how many recipes you need

3x = 18

So x = 6

Now you need to multiply 1/4 by 6 to find the amount of sugar

That would be 6/4 which is 1.5

So you need 1.5 cups of sugar for 18 cups of Kool-Aid

Answer:

W(2) = 5

Step-by-step explanation:

Because when you look at the graph, the y value is 5 when the x value is 2.

Answer:

w(2) = 5

Step-by-step explanation:

by using rise over run to find the slope easily, you get a slope of 4 and an equation of w(x) = 4x - 3, -3 being the y-intercept

to calculate w(2):

w(2) = 4(2) - 3

w(2) = 8 - 3

w(2) = 5

or you could just look at when y is 2 and see that the corresponding x value is 5 but i wanted to provide a longer explanation in case :)

Answer:

-4

Step-by-step explanation:

9-8=1

1x-2=-2

-2x2=-4

Answer:

$45

Step-by-step explanation:

300/100 = $3 = 1%

$3 x 5 = $15 = 5%

$15 x 3 years = $45

Answer:

h = 440.94 feet

Step-by-step explanation:

It is given that,

An architect is standing 370 feet from the base of a building, x = 370 feet

The angle of elevation is 50°.

We need to find the approximate height of the building. let it is h. It can be calculated using trigonometry as follows :

\(\tan\theta=\dfrac{P}{B}\\\\\tan\theta=\dfrac{h}{x}\\\\h=x\tan\theta\\\\h=370\times \tan50\\\\h=440.94\ \text{feet}\)

So, the approximate height of the building is 440.94 feet

Answer:

48 + 30m

Step-by-step explanation:

The perimeter of a hexagon is 6 times its side length.

6(8 + 5m)

= 48 + 30m (Distributive property)

Answer:

Your answer is x = 24 , y =8√3

Step-by-step explanation:

Sorry for late answer actually I was preparing for my exams. ❤

The required value of the variable is given as x = 24 and y = 8√3. Option C is correct.

Given that,
To determine the value of the variable x and y using trigonometric operators.

These are the equation that contains trigonometric operators such as sin, cos.. etc.. In algebraic operations.



Here,
sin30 = y / 16√3
16√3 / 2 = y
y = 8√3
Now,
cos30 = x / 16√3
√3 / 2 × 16√3 = x
x = 24

Thus, the required value of the variable is given as x = 24 and y = 8√3. Option C is correct.

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Answer:

The fraction of the factor of 17.5 which is due to differences in capital per person is approximately 4.375, and the fraction due to differences in TFP is approximately 13.125.

Step-by-step explanation:

Based on the given information, we know that one-fourth (1/4) of the differences in per capita GDP across countries are due to differences in capital per person, and three-fourths (3/4) are due to differences in TFP.

Now, let's calculate the fractions for the United States and Kenya, given that the United States is 17.5 times richer than Kenya.

Let's represent the fraction due to differences in capital per person as "f_capital" and the fraction due to differences in TFP as "f_TFP".

Given:

f_capital = 1/4

f_TFP = 3/4

The factor of difference in wealth = 17.5

We need to determine the fractions of this factor of 17.5 that are due to each component.

The fraction due to differences in capital per person (f_capital) can be calculated as:

f_capital = (1/4) / (1/4 + 3/4)

f_capital = (1/4) / (4/4)

f_capital = 1/4

The fraction due to differences in TFP (f_TFP) can be calculated as:

f_TFP = (3/4) / (1/4 + 3/4)

f_TFP = (3/4) / (4/4)

f_TFP = 3/4

Now, to determine the fraction of the factor of 17.5 that is due to each component, we multiply each fraction by the factor:

Fraction due to differences in capital per person = f_capital * factor

= (1/4) * 17.5

= 4.375

Fraction due to differences in TFP = f_TFP * factor

= (3/4) * 17.5

= 13.125

Therefore, the fraction of the factor of 17.5 that is due to differences in capital per person is approximately 4.375, and the fraction due to differences in TFP is approximately 13.125.

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Correct Question:

That about one-fourth of the differences in per capita GDP across countries were due to differences in capital per person and about three-fourths were due to differences in TFP. Carry out this, calculation for Kenya. The United States is 17.5 times richer than Kenya; what fraction of this factor of 175 is due to differences in capital per person and what fraction is due to differences in TFP?

The domain is; x ≥ 0

The range is; w(x) ≤ 4

The transformed function is given as:

w(x) = -\((3x^{\frac{1}{2} })\)

Rewriting the function, by applying the law of fractional exponents:

w(x) = -(√3)x - 4

The domain of a function is the set of all input values that make the function defined.

The function is undefined when the value of x under the root sign is less than zero because the square root of a negative number is complex.

Hence, the domain exists when x has a value greater than or equal to 0.

Therefore, the domain is; x ≥ 0

The range of a function is the set of all output values that makes the function defined.

Hence, the range exists when y is lesser than or equal to minus 4 because a value of y greater than -4, makes the function and domain undefined.

Therefore, the range is;

w(x) ≤ 4

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