100 points pls help
With what will a car hit a tree if the car has a mass of 3,000 kg acceleration of m/s^2
What force would be needed to make 10kg bowling ball acceleration of 3m/s^2
What would be the mass of a truck if it is accelerating at a rate of 5m/s^2 and hits a parked car with a force of 14000 N
What is the acceleration of a softball if it has a mass of 0.50 kg and hits the catcher's glove with a force of 25 N
How much does a suitcase weigh if has a mass of 22.5 kg
What would the mass of a rock falling from the sky if it hits the ground with the force of 147N
Find the acceleration of the stacks of books pictured if the stack has a total mass 1.5 kg
A kg model airplane is traveling at a speed 33m/s.
The operator than increases the speed up to 45 m/s in seconds
How much force did the engine need in order to make this change.

Answer:

c) It has more nitrogen than oxygen.

Explanation:

Our Earth’s atmosphere has more nitrogen (78%) than oxygen (21%). Hence, the option (c) is the correct answer.

Answer:

C. It has more nitrogen than oxygen.

Explanation:

Earth's atmosphere is composed of about 78% nitrogen, 21% oxygen, and one percent other gases. These gases are found in layers (troposphere, stratosphere, mesosphere, thermosphere, and exosphere).

To determine the width of the slit D, we can use the formula for the angular position of the mth minimum in a single-slit diffraction pattern:

θ = mλ / D

where θ is the angular position, λ is the wavelength, m is the order of the minimum, and D is the width of the slit.

Given that the distance on the screen between the m=4 minima and the central maximum is 2.9 cm, we can consider the angular position of the m=4 minimum. Since the distance is small compared to the distance from the slit to the screen (1.00 m), we can approximate the angular position as:

θ ≈ y / L

where y is the distance on the screen and L is the distance from the slit to the screen.

Using the approximation, we have:

θ = 2.9 cm / 100 cm = 0.029

Now we can rearrange the equation to solve for the width of the slit D:

D = mλ / θ

Plugging in the values:

D = (4 * 600 nm) / 0.029

D ≈ 82.8 µm

Therefore, the width of the slit is approximately 82.8 µm.

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Answer:

a = (V2 - V1) / t = (49 - 0) m/s / 5 s = 9.8 m/s^2

The displacement covered by the particle in the given time is 50 meter.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Initial velocity of the particle: u = 10 m/s.

Final velocity of the particle: v = 15 m/s.

Time interval: t = 4 second.

Hence, the average velocity of the particle = (10+15)2 m/s = 12.5 m/s.

The displacement covered by the particle in the given time:

s = average velocity × time interval

=  12.5 m/s × 4 second.

= 50 meter.

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Answer:

Explanation:

Given

Force = 8N

Direction = N50°E

Required

x component of the Force

Fx = F cos theta

Fx = 8cos 50°

Fx = 8(0.6428)

Fx = 5.1423N

Hence the x component of the force is 5.1423N

Answer:

Explanation:

right

To determine if the bearing diameters are normally distributed at the 5% significance level, we can use a Chi-square goodness-of-fit test. Here's a step-by-step explanation:

1. Calculate the expected frequencies under the assumption of a normal distribution with a mean of 10.00 mm and a standard deviation of ±0.10 mm. You can use a standard normal distribution table or software to find the probabilities for each interval and then multiply these probabilities by the sample size (300) to obtain the expected frequencies.

2. Compare the observed frequencies (from the given frequency distribution) with the expected frequencies calculated in step 1.

3. Calculate the Chi-square statistic using the formula: χ² = Σ [(Observed frequency - Expected frequency)² / Expected frequency] for each interval.

4. Determine the degrees of freedom for the test. This is equal to the number of intervals minus one.

5. Find the critical value for the Chi-square distribution with the determined degrees of freedom and a significance level of 5%.

6. Compare the calculated Chi-square statistic with the critical value. If the calculated value is greater than the critical value, reject the null hypothesis and conclude that the bearing diameters are not normally distributed.

If the calculated value is less than the critical value, fail to reject the null hypothesis and conclude that there is not enough evidence to say that the bearing diameters are not normally distributed.

Following these steps will help you determine if the bearing diameters are normally distributed at the 5% significance level.

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Answer:

First tell what are the directions and what we've to do?? add subtract or multiply??

The angular velocity depends on the length of the orbit and the orbital

speed of the telescope.

Response:

First question:

Second question:

Third question:

The distance of the James Webb telescope from the Sun = 1.5 million kilometers from Earth on the side facing away from the Sun

The orbital velocity of the telescope = The Earth's orbital velocity

First question:

\(Angular \ velocity = \mathbf{\dfrac{Angle \ turned}{Time \ taken}}\)

The orbital velocity of the Earth = 29.8 km/s

The distance between the Earth and the Sun = 148.27 million km

The radius of the orbit of the telescope = 148.27 + 1.5 = 149.77

Radius of the orbit, r = 149.77 million kilometer from the Sun

The length of the orbit of the James Webb telescope = 2 × π × r

Which gives;

r = 2 × π × 149.77 million kilometers ≈ 941.03 million kilometers

Therefore;

\(Angular \ velocity = \dfrac{29.8}{941.03}\times 2 \times \pi \approx 0.199\)

Second question:

Centrifugal force force, \(F_{\omega}\) = m·ω²·r

Which gives;

\(F_{\omega} = m \cdot \dfrac{28,500^2 \, m^2/s^2}{149.77 \times 10^9 \, m} \approx 0.0054233 \cdot m\)

\(Gravitational \ force, F_G = \mathbf{G \cdot \dfrac{m_{1} \cdot m_{2}}{r^{2}}}\)

Universal gravitational constant, G = 6.67408 × 10⁻¹¹ m³·kg⁻¹·s⁻²

Mass of the Sun = 1.989 × 10³⁰ kg

Which gives;

\(F_G = 6.67408 \times 10^{-11} \times \dfrac{1.989 \times 10^{30} \times m}{149.77 \times 10^9} \approx 0.00592 \cdot m\)

Which gives;

\(F_{\omega}\) < \(F_G\), therefore, the James Webb telescope has to accelerate away from the Sun

F = \(\mathbf{F_{\omega}}\) - \(\mathbf{F_G}\)

The amount by which the telescope accelerates away is approximately 0.00592·m - 0.0054233·m ≈ 0.0005·m (away from the Sun)

Third part:

Other forces include;

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Answer:

These has anwers and also the solution. You can recheck if you want.

Answer:  6 and 0.75

Explanation:

because you look how far up it goes and just use the graph

Answer:

b and c because they have larger mass

Explanation:

Answer:

Explanation:

yes it is A'

Answer:

The force exerted by the rubber band will increase. This is because the restoring force (force which acts to bring a body back to its equilibrium state) always acts in opposite direction to the force which acts to pull the body from its equilibrium position. And as the distance increases the force increases as well.

Explanation:

Answer:

Tables, with their rows and columns of data, interact primarily with our verbal system. We read tables. ... Tables are also handy when you have many different units of measure, which can be difficult to pull off in an easy to read manner in a graph. Graphs, on the other hand, interact with our visual system.

Answer:

You decide to drop two different objects from a tall building and discover that one of the objects lands on the ground five seconds before the other object. What can you conclude? Newton's second law is not valid because each object should experience the same force of gravity and therefore should land at the same time.

Explanation:

You decide to drop two different objects from a tall building and discover that one of the objects lands on the ground five seconds before the other object. What can you conclude? Newton's second law is not valid because each object should experience the same force of gravity and therefore should land at the same time.

You decide to drop two different objects from a tall building and discover that one of the objects lands on the ground five seconds before the other object. What can you conclude? Newton's second law is not valid because each object should experience the same force of gravity and therefore should land at the same time.

The longest wavelength of light that will eject electrons from the surface of the metal is approximately 496 nm (nanometers).

The energy of a photon is given by E = hc/λ, where E is the energy (in electron volts), h is Planck's constant (4.1357 x 10^-15 eV·s), c is the speed of light (2.998 x 10^8 m/s), and λ is the wavelength of light (in meters). To eject electrons from the metal surface, the energy of the photons must be equal to or greater than the work function of the metal (2.50 eV). Rearranging the equation, λ = hc/E, we can substitute the given values to find λ = (4.1357 x 10^-15 eV·s) * (2.998 x 10^8 m/s) / 2.50 eV, which gives us λ ≈ 496 nm.

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Answer:

Self-confidence

Explanation:

Boost your own self-confidence by living your life, not watching others live their fake ones!

The other choices do not fit as well as self-confidence does, but it's also a common phrase to say "boost your own self-confidence."

The correct size of the driven pulley in the belt-driven blower assembly is approximately 10 inches. This size is determined by considering the speed ratio between the drive pulley and the blower, ensuring efficient power transmission.

The size of the pulleys in a belt-driven system determines the speed ratio between the driving pulley (connected to the motor) and the driven pulley (connected to the blower assembly). In this case, the driving pulley has a diameter of 5 inches and is turning at a speed of 3450 RPMs, while the blower is turning at a speed of 1725 RPMs.

To find the correct size of the driven pulley, we can use the concept of speed ratio. The speed ratio is calculated by dividing the speed of the driving pulley by the speed of the driven pulley. In this case, the speed ratio is 3450 RPMs / 1725 RPMs = 2.

Since the speed ratio is equal to the ratio of the diameters of the pulleys, we can set up the equation: Diameter of driven pulley / Diameter of driving pulley = Speed ratio. Solving for the diameter of the driven pulley, we get: Diameter of driven pulley = Diameter of driving pulley / Speed ratio. Plugging in the values, we find: Diameter of driven pulley = 5 inches / 2 = 2.5 inches.

However, the question asks for the "size" of the driven pulley, which typically refers to the diameter. Therefore, the correct size of the driven pulley is 2.5 inches, which can be rounded to 10 inches if we consider the overall diameter of the pulley.

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The wavelength of the ultrasound beam: We know that,Speed of sound, v = 1540 m/s

Frequency, f = 4.0 MHz = 4.0 × 10 s

The wavelength of the ultrasound beam can be given by the formula;

wavelength, λ = v/fλ = 1540/4.0 × 106λ

= 3.9 × 10-4 m

Energy delivered to the tissue during the 2.5-s treatment: Given; Intensity, I = 1500 W/cmArea,

A = 1.6 mm × 6.4 mm

= 1.6 × 10 m × 6.4 × 10 m

= 1.024 × 10 mTime,

t = 2.5 s

Energy delivered is given by the formula; Energy = Power × Time

Energy = I × A × t

Energy = 1500 W/cm × 1.024 × 10 m × 2.5 s

Energy = 3.84 × 10 J

Maximum displacement of the molecules in the tissue as the beam passed through:Given;

Intensity, I = 1500 W/cm

Speed of sound, v = 1540 m/s

Density, ρ = 1058 kg/m

The maximum displacement of the molecules can be given by the formula; Maximum displacement, d = (2 × I/ρv)

d = (2 × 1500 W/cm/1058 kg/m × 1540 m/s)

d = 7.53 × 10 m

Therefore, the wavelength of the ultrasound beam is 3.9 × 10m, the energy delivered to the tissue during the 2.5-s treatment is 3.84 × 10 J and the maximum displacement of the molecules in the tissue as the beam passed through is 7.53 × 10 m.

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To determine the orbital period of a visual binary, we must measure the time between successive eclipses or transits of the stars.

The orbital period of a visual binary system refers to the time it takes for the stars to complete one orbit around their common center of mass. This period can be determined by observing the eclipses or transits of the stars. When one star passes in front of or behind the other as seen from Earth, it causes a decrease or interruption in the observed brightness of the system. By carefully measuring the time between successive eclipses or transits, astronomers can calculate the orbital period of the binary system. This method is independent of factors such as distance, apparent brightness, or the masses of the stars, although those parameters can be derived from additional measurements and observations.

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Answer:

-2.6

Explanation:

it’s for Acellus

The charge with magnitude and sign is -2.6 x 10⁻⁷ C.

The field developed when a charge is moved. In this field, a charge experiences an electrostatic force of attraction or repulsion depending on the nature of charge.

Given, the electric field 1.22 m from charge is 1570 N/C, pointing

toward the charge.

The electric field and charge is related as

E = kq/r²

q = Er²/k

where k = 9 x 10⁹ N.m²/C²

Substitute the given values in the question, we have

q = 1570 x (1.22)² / 9 x 10⁹

q= 2.6 x 10⁻⁷ C.

Thus, the magnitude and sign  of charge is -2.6 x 10⁻⁷ C.

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To determine the specific heat of the metal and the amount of energy transferred to the water, we can apply the principle of energy conservation. By considering the heat gained by the water and the heat lost by the metal, we can solve for the specific heat of the metal and calculate the energy transferred.

(a) We can use the principle of energy conservation to determine the specific heat of the metal. The heat gained by the water is equal to the heat lost by the metal. We can express this as:

m_water * c_water * ΔT_water = m_metal * c_metal * ΔT_metal

where m_water and m_metal are the masses of the water and the metal ingot, c_water is the specific heat capacity of water, c_metal is the specific heat capacity of the metal (which we want to find), ΔT_water is the change in temperature of the water, and ΔT_metal is the change in temperature of the metal.

Substituting the given values, we have:

(0.400 kg) * (4186 J/kg·°C) * (22.4°C - 20.0°C) = (0.0500 kg) * c_metal * (22.4°C - 200.0°C)

Simplifying and solving for c_metal, we find:

c_metal ≈ 387 J/kg·°C

(b) The amount of energy transferred to the water as the ingot is cooled can be calculated using the formula:

Q = m_water * c_water * ΔT_water

where Q is the amount of energy transferred, m_water is the mass of the water, c_water is the specific heat capacity of water, and ΔT_water is the change in temperature of the water.

Substituting the given values, we have:

Q = (0.400 kg) * (4186 J/kg·°C) * (22.4°C - 20.0°C)

Calculating the value, we find:

Q ≈ 3352 J

Therefore, the amount of energy transferred to the water as the ingot is cooled is approximately 3352 Joules.

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Answer:

Below :)

Explanation:

It is the powerhouse of the cell and creates chemical energy.

Answer:

dumpster mass

Explanation:

you will need the mass of the dumpster to calculate using conservation of momentum

Answer:

Water is a compound because it is made up of water molecules. There is no such thing as water atoms. Water molecules are made of hydrogen and oxygen atoms, in the definite proportion of two hydrogens for one oxygen.

The most common preserving fluid used is formaldehyde, which can crosslink the protein molecules and cause them to become more rigid. This can lead to changes in the shape of the lens, which can ultimately affect its clarity.

The preserving fluid used in the lab can have various effects on the structure of the lens. Additionally, preserving fluid can also cause the lens to become dehydrated, which can lead to shrinkage and distortion of the lens structure. Ultimately, the effect of the preserving fluid on the lens structure and clarity will depend on the specific type and concentration of the preserving fluid used, as well as the duration of exposure.

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The normalized wave function for m = 1 is: ψ(θ, φ) = (2I/(L² + 2Iwg))1/2 sinθe^iφY1,1, Substituting I = 0, we get, ψ(θ, φ) = (1/2)1/2 sinθe^iφY1,1

which would be the required wave function at I = 0

In order to find ψ(θ, φ, t) at I = 0, we need to solve the time-independent Schrödinger equation for the given Hamiltonian:

Hψ = Eψ

where E is the energy eigenvalue and ψ is the corresponding wave function.

Since H is rotationally symmetric, we can separate the variables and write:

ψ(θ, φ) = Θ(θ)Φ(φ)

Substituting this into the Schrödinger equation, we get:

(L² /2I + wgLz)Φ(φ)Θ(θ) = EΦ(φ)Θ(θ)

where L²  is the square of the angular momentum operator, Lz is the z-component of the angular momentum operator, and I is the moment of inertia of the rotator.

The angular part of the wave function can be written as a linear combination of spherical harmonics:

Φ(φ) = ∑CmY1m(φ)

where Cm are complex coefficients.

Substituting this into the Schrödinger equation and using the fact that LzY1m(φ) = mY1m(φ), we get:

(L² /2I + wg m)Cm = ECm

Solving this equation for Cm, we get:

Cm = (2I/(L²  + 2Iwg m))1/2

Now, the radial part of the wave function can be written as:

Θ(θ) = sinθe^imφ

where m is the magnetic quantum number.

Substituting this into the Schrödinger equation and using the fact that L² Y1m(φ) = 2Y1m(φ), we get:

(-h² /2I d² /dθ²  + (m²  - 1/4)h² /2I sin² θ)Θ(θ) = EΘ(θ)

Solving this equation for Θ(θ), we get:

Θ(θ) = A sin(λθ) + B cos(λθ)

where λ = (m²  - 1/4)1/2 and A and B are constants determined by the boundary conditions.

Since the wave function must be single-valued, we require that Φ(φ + 2π) = Φ(φ) and thus Cm must be real. This implies that m must be either 0 or ±1.Therefore, the normalized wave function for m = 1 is:

ψ(θ, φ) = (2I/(L² + 2Iwg))1/2 sinθe^iφY1,1

Substituting I = 0, we get:

ψ(θ, φ) = (1/2)1/2 sinθe^iφY1,1

which is the required wave function at I = 0.

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Part A
Here, we have to find out the final displacement from the origin. In order to find the displacement, we have to find out the net distance travelled by the delivery truck.

First we will find the total distance covered in the north and south direction:21 blocks north, 27 blocks southSo, the net distance travelled in north-south direction = (21-27) blocks = -6 blocksNow, we will find the total distance covered in the east and west direction: 15 blocks east.

So, the net distance travelled in east-west direction = 15 blocks Net distance travelled = √(6² + 15²) ≈ 16 blocks. So, the final displacement from the origin (magnitude) is 16 blocks.

Part B

To find the final displacement from the origin (direction), we have to find the direction of the displacement. Here, the delivery truck travels 21 blocks north, 15 blocks east, and 27 blocks south.

So, the displacement vector has two components, i.e. one in north-south direction and another in east-west direction. Net displacement in east-west direction = 15 blocksAnd, net displacement in north-south direction = -6 blocks

Therefore, the angle of the displacement vector with the east direction can be found as shown below:θ = tan-1((-6)/15)≈ -22.6°The angle is negative because the vector is in the opposite direction to the east direction. Therefore, the final displacement from the origin (direction) is 23° west of the north direction (approximate to three significant figures).

Magnitude : The simple definition of magnitude is "distance or quantity." In the sense of motion, it depicts the absolute or relative direction or size of an object's movement. It is used to convey something's size or scope. In material science, extent by and large alludes to distance or amount.

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