10 sentences about computer parts.

Answer:

it would be a software problem.

Explanation:

this is because when your computer crashes, the software all "explodes" and resets.

Answer:

Start off with a greeting like Dear Sarah. Then you write a friendly body that tells about your home and describe it as much as you can and tell about what your bedroom theme is like and so on. Finally, top it off like a closing like Sincerely, Tessa.

Answer:

you start off by saying

Dear (name), talk about how your house is comforting and things like that... I hope thats what you were asking for.

The provided M-file translates a square horizontally and vertically using matrices, for a total of 30 iterations and an additional for loop.

Here is the modified M-file that brings the square to its original position using 30 iterations and a single additional for loop:

S = [0, 1, 1, 0, 0, 0, 0, 1, 1, 0; 0, 0, 1, 1, 0, 1, 0, 0, 1, 1; 1, 1, 1, 1, 1, 1, 1, 1, 1, 1];

% square in homogeneous coordinates

M1 = [1, 0, 0.4; 0, 1, 0; 0, 0, 1]; % first translating matrix

M2 = [1, 0, 0; 0, 1, 0.4; 0, 0, 1]; % the second translating matrix

M3 = [1, 0, -0.4; 0, 1, -0.4; 0, 0, 1]; % the third translating matrix

P = plot(S(1,:), S(2,:)); % plot the original square

axis square, axis([-1.14, 1.14, -1.14, 1.14]), grid on

for i = 1:30

   S = M1 * S; % calculate the translated square.

   set(P, 'xdata', S(1,:), 'ydata', S(2,:)); % plot the translated square

   pause(0.1)

end

for i = 1:30

   S = M2 * S; % calculate the translated square.

   set(P, 'xdata', S(1,:), 'ydata', S(2,:)); % plot the translated square

   pause(0.1)

end

for i = 1:30

   S = M3 * S; % compute the translated square

   set(P, 'xdata', S(1,:), 'ydata', S(2,:)); % plot the translated square

   pause(0.1)

end

In this modified version, a third translation matrix M3 is added to bring the square back to its original position. The first for loop translates the square horizontally to the right, the second for loop translates the square vertically up, and the third for loop translates the square diagonally down and left to its original position. Each loop iterates 30 times and updates the plot with a pause of 0.1 seconds between each iteration.

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Answer:

There is massive importance if you want to study information study.

It can help you understand the data, organize, and process the data, using which we can generate and share information.

Explanation:

It largely depends on your interest and requirement, but a better knowledge or clue about information systems may help analyze the data especially if you want to become a data scientist, machine learning, Artificial intelligence or deep learning, etc.

It can help you understand the data, organize, and process the data, using which we can generate and share information.

A great understanding of information systems may exponentially increase the productivity, growth, performance, and profit of the company.

Most Professions get exposed to information Systems no matter what their career objective is, as it may help in having better decision making based on the information they get through data.

So, yes!

There is a massive importance if you want to study information study.

The ICT trend that Andy can use to connect with his friends and relatives​ such that they can maintain face-to-face communication is video Conferencing.

ICT trends refer to those innovations that allow us to communicate and interact with people on a wide scale. There are different situations that would require a person to use ICT trends for interactions.

If Andy has family and friends abroad and wants to keep in touch with them, video conferencing would give him the desired effect.

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This requirement can be met by drafting a short text that says that the website is under construction. You could also specify the exact date when the site will be restored.

If you are still working on a website and do not want users to access the site, you should leave a message on the site that says that the website is still under construction.

The link to the website should directly lead to this message. In this space, you should also specify the date and time when the site will be restored.

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Answer:

In Java:

public static  int[] inputArray(){

   Scanner input = new Scanner(System.in);

   int[] alpha = new int[20];

   for(int i = 0;i<20;i++){

       alpha[i] = input.nextInt();

   }

   return alpha;}

public static  int[] doubleArray(int [] alpha){

   int[] beta = new int[20];

   for(int i = 0;i<20;i++){

       beta[i] = 2 * alpha[i];

   }

   return beta;

}

public static int[] copyAlphaBeta(int [] alpha, int [] beta){

   int [] AlphaBeta = new  int[10];

   for(int i = 0;i<5;i++){

       AlphaBeta[i] = alpha[i];

   }

   int count = 5;

   for(int i = 15;i<20;i++){

       AlphaBeta[count] = beta[i];

       count++;

   }

   return AlphaBeta;

}

public static void printArray(int [] alpha){

   for(int i = 0;i<20;i++){

       System.out.print(alpha[i]+" ");

       if((i+1)%15 == 0){

           System.out.println(" ");

       }

   }

}

Explanation:

The inputArray is defined here

public static  int[] inputArray(){

   Scanner input = new Scanner(System.in);

This declares alpha array of 20 elements

   int[] alpha = new int[20];

The following iteration gets input from the user into the array

   for(int i = 0;i<20;i++){

       alpha[i] = input.nextInt();

   }

This returns the alpha array

   return alpha;}

The doubleArray is defined here. It takes the alpha array as its input parameter

public static  int[] doubleArray(int [] alpha){

This declares beta of 20 integers

   int[] beta = new int[20];

This populates beta by 2 * alpha[i]

   for(int i = 0;i<20;i++){

       beta[i] = 2 * alpha[i];

   }

This returns the alpha array

   return beta;}

The copyAlphaBeta array is defines here

public static int[] copyAlphaBeta(int [] alpha, int [] beta){

This declares AlphaBeta as 10 elements

   int [] AlphaBeta = new  int[10];

This populates the first 5 elements of AlphaBeta with the first 5 of alpha

   for(int i = 0;i<5;i++){

       AlphaBeta[i] = alpha[i];

   }

   int count = 5;

This populates the last 5 elements of AlphaBeta with the last 5 of beta

   for(int i = 15;i<20;i++){

       AlphaBeta[count] = beta[i];

       count++;

   }

This returns the AlphaBeta array

   return AlphaBeta;

}

The printArray is defined here. It takes the alpha array as its input parameter

public static void printArray(int [] alpha){

This iterates through alpha array

   for(int i = 0;i<20;i++){

This prints each element of the array

       System.out.print(alpha[i]+" ");

A new line is started after the 15th element

       if((i+1)%15 == 0){

           System.out.println(" ");

       }

   }

}

See attachment for complete program which includes the main

Answer:

me

Explanation:

yea not me

Explanation:

Solution :

1.

a). Candidate keys : \($B$\)

b). R is in \($2F$\) but not \($3NF$\)

c). C → \($D$\) and C → \($A$\), both causes violations of \($BCNF$\). The way to obtain the join preserving decomposition is to decompose \($R$\) into \($AC, BC$\) and CD.

2.

a). Candidate keys : \($BD$\)

b). \($R$\) is in \($1NF$\) but not \($2NF$\).

c). Both B → \($C$\) and D → \($A$\) cause \($BCNF$\) violations. The decomposition : \($AD $\), \($BC, BD$\) is \($BCNF$\) and lossless and the join preserving.

3.

a). Candidate keys : \($ABC, BCD$\)

b). R is in \($3NF$\) but not \($BCNF$\)

c).\($ABCD$\) is not in \($BCNF$\) since D → \($A$\) and \($D$\) is not a key. But if we split up the \($R$\) as \($AD,BCD$\) therefore we cannot preserve dependency \($ABC$\) → D. So there is no \($BCNF$\) decomposition.

4.

a). Candidate keys : \($A$\)

b). R is in \($2NF$\) but not \($3NF$\)

c). BC → \($D$\) violates \($BCNF$\) since \($BC$\) does not contain the key. And we split up R as in \($BCD, ABC$\).

5.

a). Candidate keys : \($AB, BC, CD, AD$\)

b). \($R$\) is in \($3NF$\) but not \($BCNF$\).

c). C → \($A$\) and D → \($B$\) both causes a violations. The decomposition into \($AC,BCD$\) but this will not preserve \($AB$\) → C and \($AB$\) → D, and \($BCD$\) is still not \($BCNF$\) because \($D$\) → \($B$\). So we need to decompose further into \($AC,BD,CD$\) However when we try to revive the lost functional dependencies by adding \($ABC$\) and \($ABD$\), we that these relations are not in \($BCNF$\) form. Therefore, there is no \($BCNF$\) decomposition.

Since you work at a print shop that produces marketing materials, and your manager asks you to install a new printer. The drivers that is best is PCL, because it can be used in the office to print physical document while the Postcript can only be used for online document or pdf and since it is office job, PCL is the best.

PCL use depends on the device. This indicates that certain printed data, typically graphical data like fill areas, underlines, or fonts, is created by the drivers for this language by using the printer hardware. As a result, the print job can be processed by the computer fast and effectively. The production and processing of page data must then be finished by the printer.

Note that If you typically print from "Office" programs in general, use the PCL driver. If you wish to print PDFs more quickly or use professional DTP and graphics tools for the majority of your printing, pick the PostScript driver.

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You can find in the photo. Good luck!

For instance, given a system of n processes (P₀, P₁, ....… Pₙ₋₁} with each process having critical section segment of code:

An operating system (OS) can be defined as a system software that's usually pre-installed on a computing device by the manufacturers, so as to manage random access memory (RAM), software programs, computer hardware and all user processes.

A critical section problem can be defined as a code segment in which all of computer processes access and make use of shared resources such as digital files and common variables, as well as performing write operations on these shared resources.

This ultimately implies that, a critical section problem can be used to design and develop a secured protocol followed by a group of computer processes, so that no other process executes in its critical section when another process has entered its critical section.

For instance, given a system of n processes (P₀, P₁, ....… Pₙ₋₁} with each process having critical section segment of code. The critical section problem would cause the processes to change shared resources, writing file, updating table, etc., so that when one process enters the critical section, no other process would be in its critical section.

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Example of critical section problem in the context of an operating system is when process A change the data in a memory location  and process C want to read the data from the same memory.

The critical section problem can be regarded as the problem  that involves the notification that one process is executing its critical section at a given time.

It should be noted that ,The critical section  can be seen in code segment  when there is access to shared variables .

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#include <iostream>

int main(int argc, char const* argv[]) {

   while(1) {

       std::cout << ">> "; int x; std::cin>>x;

       if(x<0) break;

       else if(x%2==0) {std::cout << "\nThis is even number.\n";}

       else std::cout << "\nThis is odd number.\n";

   }

   return 0;

}

MIS stands for Management Information System, which is a technology-based solution that assists organizations in making strategic decisions. It aids in the efficient organization of information, making it easier to locate, track, and manage. MIS is an essential tool that assists in the streamlining of an organization's operations, resulting in increased productivity and reduced costs.

It is critical for an MIS system to address the needs of any organization's structure. This implies that the information gathered through the MIS should be easily accessible to all levels of the organization. It must be capable of handling a wide range of activities and functions, including financial and accounting data, human resources, production, and inventory management.MIS systems must be scalable to meet the needs of a company as it expands.

The information stored in an MIS should be able to be shared across the organization, from the highest to the lowest level. This feature allows for smooth communication and collaboration among departments and employees, which leads to better decision-making and increased productivity.

Furthermore, MIS systems must provide a comprehensive overview of a company's operations. This implies that it must be capable of tracking and recording all relevant information. It should provide a real-time picture of the company's performance by gathering and analyzing data from a variety of sources. As a result, businesses can take quick action to resolve problems and capitalize on opportunities.

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Answer:

36 book

im sure it is correct

Answer:

36 boy

Explanation:

74-38

Answer: Set a Cache-Control header to 0 to prevent caching on client browsers. Set a Strict-Transport-Security header to 31536000 (1 year) to force the client to remember to only connect to the server with HTTP(S) secure. Lastly, set a Content Security Policy(CSP) HTTP header to tell the client what sources it can load scripts or images from and how to handle the execution of JS that is on the page which can allow to mitigate script injection.

Explanation:

Cache-Control is a server response header that controls how long a browser should have cache for before it becomes stale. Setting it 0 tells the browser that it should never cache.

Strict-Transport-Security is a server response header that tells the client that after the first initial visit; that the browser should remember to only connect to it via HTTPS for the time that was set by header.

Content Security Policy (CSP) is a policy and also a header that can be in the response of a server that explains to the browser the limitations of content that can be loaded. Examples include: images, videos, JS sources, etc. The policy can also tell the browser that only an ad analytics software should be the only script that can run thus mitigating any other scripts that may be injected onto the site.  

Answer:

age = 10

name = Cynthia

make an f string so the variables appear in the string. There are other ways to do this but I prefer f strings instead of using string concatenation. It causes problems adding 2 strings together most of the time.

print(f'Hi, {name} ! How are you? I know you are {age} old.')

Answer:

The TCP/IP protocol could only be used in universities, governments, and businesses. People around the world could not send data to one another.

Answer:

i think its C

Explanation:

Answer: Opera has its roots in Europe; the other styles are American

Explanation:

A port number which an end user or network administrator would open on a web server is either 80 or 8080.

In Computer technology, there are different types of server and these include the following:

In Computer networking, a web server can be defined as a type of computer (server) that is designed and developed to run websites and distribute webpages as they are being requested over the Internet by end users (clients).

By default, the port number "80" are typically opened by an end user or network administrator on a web server.

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The vectors stored as a set of instructions describing the coordinates for lines and shapes in a three-dimensional space form option C: a wireframe.

A wireframe may be a visual representation of a 3D question composed of lines and bends that interface a arrangement of focuses in a 3D space. It does not incorporate color or surface data  and is frequently utilized as a essential system for making more complex 3D models.

Subsequently, the right reply is choice (c) - a wireframe. option (a) - a bitmap realistic and alternative (b) - a zipped record are not tools as they are not related to the concept of 3D wireframes.

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The correct statement about Voice Over Internet Protocol (VoIP) is option B: callers can be screened even with blocked caller IDs.

VoIP is a technology that allows users to make voice calls using a broadband Internet connection instead of a traditional phone line. One of the advantages of VoIP is that it allows for more advanced call screening options, including the ability to screen callers even if they have blocked their caller ID. This feature can help users avoid unwanted calls from telemarketers or other unwanted callers.

Option A is incorrect because users typically do not experience busy lines with VoIP, as the technology allows for multiple calls to be made simultaneously. Option C is incorrect because VoIP does allow for voicemails to be received on the computer. Option D is also incorrect, as VoIP allows for call forwarding just like traditional phone lines.

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Answer:

DiffServ

Explanation:

The IP QoS which is fully known as QUALITY OF SERVICE mechanism that involves prioritizing traffic is DIFFERENTIATED SERVICES (DiffServ).

DIFFERENTIATED SERVICES help to differentiate ,arrange ,manage, control and focus on network traffic that are of great significance or important first before network that are less important or by their order of importance in order to provide quality of service and to avoid network traffic congestion which may want to reduce the quality of service when their is to much load on the network .

Answer:

Its A.

Explanation:

Took the exam review

Answer:

A

Explanation:

on edge

In computer programming, a variable is a storage location that holds a value or an identifier. A data type determines the type of data that can be stored in a variable. The data type of the following variable, name = "John Doe" is a string data type.

In programming, a string is a sequence of characters that is enclosed in quotes. The string data type can store any textual data such as names, words, or sentences.The string data type is used in programming languages such as Java, Python, C++, and many others. In Python, the string data type is denoted by enclosing the value in either single or double quotes.

For instance, "Hello World" and 'Hello World' are both strings.In conclusion, the data type of the variable name is string. When declaring variables in programming, it is important to assign them the correct data type, as it determines the operations that can be performed on them.

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Answer:

1024 bytes in a megabyte and there are 8000000 bits in a megabyte. They are different.

Explanation:

There are 8000000 bits and 1024 bytes in one megabyte. They are unique.

The megabyte is a multiple of the digital informational unit byte. The suggested unit sign for it is MB. The International System of Units unit prefix mega is a multiplier of 1000,000. As a result, one megabyte is equal to one million bytes of data.

About a million bytes make up a megabyte (or about 1000 kilobytes). Typically, a few megabytes might be required for a 10-megapixel digital camera photograph or a brief MP3 music clip.

1000000 bytes make up one megabyte (decimal). In base 10, 1 MB equals 106 B. (SI). 1048576 bytes make up a megabyte (binary). A megabyte can imply either 1,000,000 bytes or 1,048,576 bytes, according to the Microsoft Press Computer Dictionary. Apparently, Eric S.

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Electronic Controls Company it was founded on 1949 by J.Presper and John Mauchly

Answer: Electronic Controls Company

Explanation: The first computer company was Electronic Controls Company and was founded in 1949 by J. Presper Eckert and John Mauchly, the same individuals who helped create the ENIAC computer.

Hope this helps^^

Answer:

Network share

Explanation: