10. A 2.5 kg mass is attached to the end of a horizontal spring of spring constant 60 N/m and set into simple harmonic motion with an amplitude of 0.5 m. a. What is the maximum potential energy of the

Answer:

- 0.75 m

Explanation:

Using the graph as a reference point, the question is ;

What is the displacement of the elephant between 8s and 24s?

The displacement will be the sum of the slope of the graph within the given time.

From time 8s to 16s, the slope m will be;

Slope = (15 - 6) / (16 - 8)

Slope = 9 / 8

From time 16s to 24s

Slope = (15 - 0) / ( 16 - 24)

Slope = -15 / 8

Displacement = 9/8 - 15/8

Displacement = -6/8

Displacement = - 0.75 m

Answer:

displacement: -6m

distance: 24m

Explanation:

khan academy

Answer:

has different metrics that show people who don't understand once certain metric to have another way of doing it

The work done by the gas during expansion is 3.85 kJ (option A).

When a gas expands at a constant pressure, the work done by the gas is given by W = PΔV, where P is the constant pressure and ΔV is the change in volume.

Substituting the given values, we get W = (110 kPa)(65.0 L - 30.0 L) = 3.85 kJ.

Therefore, the correct option is A.

It's important to note that work done by a gas is positive when the gas expands, as in this case, and negative when the gas is compressed.

This is because work is done by the gas on the surroundings during expansion and by the surroundings on the gas during compression.

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Sunlight shining through a thin, cool gas produces an absorption line spectrum.

When white light passes through a thin, cool gas, some of the light is absorbed by the gas atoms, causing dark lines to appear in the spectrum known as an absorption spectrum. These dark lines represent the wavelengths of light that were absorbed by the gas. This type of spectrum is known as an absorption line spectrum. In the case of sunlight passing through Earth's atmosphere, the gases in the atmosphere absorb specific wavelengths of light, creating a series of dark lines in the spectrum. These dark lines are called Fraunhofer lines and are used to identify the chemical composition of the Sun and other stars.

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We have that for the question, Does a cat’s heart rate change while it is napping?

Cats heart rate do not increase while napping.

The range of heart beat of a cat is 140 and 220 bpm

From the Question we are asked

Does a cat’s heart rate change while it is napping.

The answer is NO

Cats heart rate do not increase while napping. Cat have a normal heart beat maximum of 220 beats per minute consistently.The range of heart beat of a cat is 140 and 220 bpm

Therefore

There is something with a cat with heart rate above this number.

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Answer:

19500kg

Explanation:

If you divide 195000N by 10

Answer:

Interpolation gives more accurate data or points compared to extrapolation.

Interpolation can be a little easier than extrapolation.

Interpolation does not require one to extend the already existing data points, where extrapolation requires elaboration of the pattern, curve, or line.

Extrapolation:

This is a statistical method used to predict unknown values for points outside the range of the recorded data. It is used to extend a known sequence of values beyond the sampled area

Extrapolation: with Extrapolation, we can be less confident with the unknown values derived using this method. The method includes values from outside the sampled area, which makes the predictions diverge away from the true values. In curve fitting, this method is not preferred.

Extrapolation:

the ability to retrieve negative answers is one characteristic that makes it unique for interpolation. This statistical method allows one to extend the values in the range either forward or backward. This technique of extending values is responsible for attaining the negative values.

Explanation:

To solve this we must be knowing each and every concept related to  sound waves. Therefore, a sound waves change as they spread out in a spherical pattern, they go up and down.

A sound is a type of energy or a vibration that moves through a material such as air or water. Sound may pass through with a gaseous medium as well. It is anything that is audible. The speed that sound varies depending on the medium.

A wave is a medium that transmits energy from one location to another. Waves are classified into three types: transverse waves, longitudinal waves, or surface waves. A sound waves change as they spread out in a spherical pattern, they go up and down.

Therefore, a sound waves change as they spread out in a spherical pattern, they go up and down.

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Answer:

yes if you can only install a magnetic force into the bar

Answer: 1.18

Explanation: The formula I used is:

f=1/(2pi) times the square root of k/m

F is the frequency, in this problem, 10 Hz.

K is the spring constant.

M is the mass.

So plugging everything in we would have:

10=1/(2pi)•sqrt x/0.00030

The answer I got was 1.18

In Chapter 2 section 2.21, it is stated that in a cathode ray tube, electrons pass from the cathode to the anode. This is because the cathode is negatively charged, while the anode is positively charged.

The flow of electrons is controlled by an electric field between the cathode and anode, which causes the electrons to move towards the anode. Therefore, the correct answer to the question is option B) electrons pass from the cathode to the anode.

In Chapter 2, Section 2.21, regarding a cathode ray tube, the correct answer is B) electrons pass from the cathode to the anode. The cathode emits electrons, which are attracted to the positively charged anode, resulting in the flow of electrons in the tube.

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Answer:

its B

Explanation:

You need a specific force to change the momentum of something.

Hope this helps!

The source of nutrition that Andrew should consume prior to the match to get the boost of energy he desires is carbohydrate.

Nutrition refers to the organic process by which an organism assimilates food and uses it for growth and maintenance.

There are 6 major classes of nutrients and they are as follows:

Among these classes of nutrients, carbohydrates provide the fastest source of energy in the body and hence, can be recommended for an athlete like Andrew who is preparing for a weight lifting endeavor.

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The frequency of oscillation for the spring system of part i is 0.719 Hz.

Explanation: The frequency of a system is a measure of the number of cycles it completes per second, which is proportional to the square root of the ratio of the spring constant to the mass of the system.

In this case, the spring constant is given as k=2.5 N/m and the mass of the system is given as m=0.35 kg. Plugging these values into the equation for frequency, we get frequency (f) = 1/2π * sqrt(k/m) = 1/2π * sqrt(2.5/0.35) = 0.719 Hz. This result can be rounded to three decimal places, giving us 0.719 Hz.

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Answer:

B) t = 1.83 [s]

A) y = 16.51 [m]

Explanation:

To solve this problem we must use the following equation of kinematics.

\(v_{f} =v_{o} -g*t\)

where:

Vf = final velocity = 0

Vo = initial velocity = 18 [m/s]

g = gravity acceleration = 9.81 [m/s²]

t = time [s]

Note: the negative sign in the above equation means that the acceleration of gravity is acting in the opposite direction to the motion.

A) The maximum height is reached when the final velocity of the ball is zero.

0 = 18 - (9.81*t)

9.81*t = 18

t = 18/9.81

t = 1.83 [s], we found the answer for B.

Now using the following equation.

\(y = y_{o} + v_{o}*t - 0.5*g*t^{2}\\\)

where:

y = elevation [m]

Yo = initial elevation = 0

y = 18*(1.83) - 0.5*9.81*(1.83)²

y = 16.51 [m]

We have demonstrated that (pω)ω∈Ω is the point mass function of some distribution, and that the random variable X has a point mass function PX equal to (pω)ω∈Ω.

In order to show that (pω)ω∈Ω is the point mass function of some distribution, we need to demonstrate that it satisfies the properties of a probability distribution.

a) Let's consider the properties of a probability distribution. Firstly, the values of pω must be non-negative for all ω ∈ Ω. This is true since pω is defined as the product of two non-negative values hω1 and hω2.

Secondly, the sum of probabilities over all possible outcomes must be equal to 1. In this case, we need to show that the sum of (pω)ω∈Ω over all possible ω in Ω is equal to 1. To do this, we can consider the sum:

Σ(pω)ω∈Ω = Σ(hω1 hω2)ω∈Ω

By the properties of the point mass function h, we know that Σhω1 = 1 and Σhω2 = 1. Therefore, the above expression becomes:

Σ(pω)ω∈Ω = Σ(hω1 hω2)ω∈Ω = 1 * 1 = 1

Thus, we have shown that (pω)ω∈Ω satisfies the properties of a probability distribution.

b) Now let's consider the random variable X(ω) = ω1 + ω2 and show that its point mass function PX is equal to (pω)ω∈Ω.

To calculate PX(x) = P({ω ∈ Ω : X(ω) = x}), we need to consider the event where the sum of the components ω1 and ω2 is equal to x. This can be expressed as:

{ω ∈ Ω : X(ω) = x} = {(ω1, ω2) ∈ Ω : ω1 + ω2 = x}

Now, notice that this event is equivalent to the event {ω1 = n, ω2 = x - n} for any fixed n. The probability of this event is given by pω1 pω2 = hω1 hω2, which matches the point mass function (pω)ω∈Ω.

By considering all possible values of n, we can cover all the cases for X(ω) = x, and therefore, we have shown that PX(x) is equal to (pω)ω∈Ω.

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Use that time in the time dilation calculation after v / c = L / sqrt( L^2 + c^2t^2 ) to velocity v. T'=T(1-v^2/c^2) ^ (1/2). then find v such that 2.66*10-8m/s, or around 0.89c, is obtained.

Time dilation is an actual phenomenon, not a thought experiment or a hypothetical idea like the Twin Paradox. The Hafele-Keating experiments from 1971, in which two atomic clocks were flown on opposing-direction airplanes, provided conclusive evidence of this.

A really fast starship is a time machine to the future because, thanks to Einstein, we are aware that time moves more slowly the faster you fly. Approximately 36 years on Earth are equal to five years on a ship moving at 99 percent the speed of light (2.5 years out and 2.5 years return).

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Take a look at the attachment below. As you can see, the figure demonstrates a 90 degree angle such that the surfaces are perpendicular, and hence are independent of the angle of incidence. You could say that this forms a part of a parallelogram -

The hypotenuse is the initial velocity of the cannonball (56.0m/s). The opposite side is the vertical component of the velocity and the adjacent side is the horizontal component of the velocity.

To determine the unknowns, we need to use trigonometry. Let's use theta to represent the angle at which the cannonball was launched. The vertical component of the initial velocity can be found using the equation:
Vsin(theta) = opposite side
Vsin(theta) = (56.0m/s)sin(theta)
The horizontal component of the velocity can be found using the equation:
Vcos(theta) = adjacent side
Vcos(theta) = (56.0m/s)cos(theta)
We can use these equations to solve for the unknowns. For example, if we wanted to find the angle at which the cannonball was launched, we could set the two equations equal to each other and solve for theta:
Vsin(theta) = Vcos(theta)
tan(theta) = opposite side/adjacent side
tan(theta) = (56.0m/s)sin(theta)/(56.0m/s)cos(theta)
tan(theta) = sin(theta)/cos(theta)
theta = tan^-1(sin(theta)/cos(theta))
Using a calculator, we find that theta is approximately 51.3 degrees. Therefore, the cannonball was launched at an angle of 51.3 degrees.  While the ultimate velocity of an object thrown upward will be zero, the final velocity of an object thrown downward will be twice as fast as the initial velocity. Due to the forces of gravity, when an object is thrown both upward and downward with the same initial velocity, the ultimate velocities will differ. The object thrown upward will have a negative ultimate velocity, while the thing thrown downhill will have a positive end velocity.

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The effective spring constant is 1.03 N/m, and the interatomic distance between the two hydrogen atoms is approximately 74.37 pm. The proton wavelength corresponding to the vibration transition is approximately 6.64 fm, and the frequency is approximately 7.43 x 10^13 Hz.

To estimate the effective spring constant (k) and the interatomic distance (r) between the two hydrogen (H2) atoms, we can use the relationship between the vibrational frequency (ν) and the rotational constant (B) of the molecule. The formula relating these parameters is:

ν = (1/2π) * sqrt(k/μ) - B

Where μ is the reduced mass of the H2 molecule. Rearranging the equation, we can solve for k:

k = (2πν)² * μ

Using the given vibrational frequency of 4401 cm⁻¹ and the rotational constant of 59.32 cm⁻¹, we can substitute these values into the equation to find the effective spring constant.

k = (2π * 4401)² * μ = 1.03 N/m

To find the interatomic distance, we can use Hooke's Law:

F = -k * Δx

Where F is the force and Δx is the change in position. At equilibrium, the force is zero, so we can rearrange the equation:

Δx = r = -F/k

Substituting the known values, we find:

r = -0/k = -0/1.03 = 0 pm

The negative sign indicates that the atoms are bound together and the interatomic distance is approximately 74.37 pm.

To calculate the proton wavelength (λ) corresponding to the vibration transition, we can use the de Broglie wavelength formula:

λ = h/p

Where h is the Planck constant and p is the momentum of the proton. The momentum can be calculated using the formula:

p = m * ν

Where m is the mass of the proton and ν is the vibrational frequency. Substituting the known values, we find:

p = m * ν = (1.67 x 10⁻²⁷ kg) * (4401 s⁻¹) = 7.35 x 10⁻²⁴ kg m/s

Substituting the values into the de Broglie wavelength formula, we get:

λ = h/p = (6.63 x 10^⁻³⁴J s) / (7.35 x 10⁻²⁴ kg m/s) = 6.64 fm

The frequency (f) corresponding to the vibration transition can be calculated using the equation:

f = ν

Substituting the known value, we find:

f = 4401 s⁻¹ = 7.43 x 10¹³ Hz

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Answer:

Yes labor is required therefor jobs like cashier, and other low skill labor jobs I'll not be required

Explanation:

Answer:

a law stating that electric current is proportional to voltage and inversely proportional to resistance.

Kepler's third law states that the square of the period of a planet's orbit around the sun is proportional to the cube of its average distance from the sun.

Kepler's third law, also known as the law of harmonies, is a mathematical relationship that describes the motion of planets around the sun. It states that the ratio of the cube of a planet's average distance from the sun to the square of its orbital period is constant for all planets in the solar system.

Mathematically, this can be expressed as T^2 = k*R^3, where T is the orbital period of the planet, R is its average distance from the sun, and k is a constant of proportionality. Kepler's third law is an important tool for astronomers to study and understand the dynamics of the solar system.

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The line of sight makes an angle of 80° with a vertical radio antenna, the electric field emitted by the antenna makes oscillated along a line which makes an angle of 10 degrees with your line of sight.

The line of sight and electric field of the antenna make an angle.

Therefore, we need to find out the angle which is formed by the electric field emitted by the antenna makes oscillated along a line, with your line of sight.

Supposed In triangle ABC, AC is a vertical antenna and BC is the line of sight.

Let angle BAC be 80 degrees.

EF is the electric field emitted by the antenna makes oscillated along a line.

Let angle CEF be the angle formed by the electric field emitted by the antenna makes oscillated along a line with your line of sight.

Hence, we need to find angle CEF.

Angle CEF = 90 - angle ACF = 90 - (80) = 10

Therefore, the electric field emitted by the antenna makes oscillated along a line which makes an angle of 10 degrees with your line of sight. The answer is 10 degrees.

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When a train applies the brakes, it is moving at a speed of 79 feet per second. It slows down until it stops at a steady pace of 0.8 feet per second per second. Give a decimal response. The train will need to halt on foot. Therefore, the answer is in decimal.

The vector quantity velocity (v), denoted by the equation v = s/t, quantifies displacement (or change in position, s), over the change in time (t). Speed (or rate, r) is a scalar number, denoted by the equation r = d/t, that quantifies the distance traveled (d) over the change in time (t). Thus, the Velocity of a moving object can be calculated by using the formula, v = Δs/Δt.

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solid iron can be made by the electrolysis of iron (ii) bromide aqueous solution, febr 2 (aq) 13.4 amperage is required to plate out 111.7 grams of fe(s) from a febr 2 (aq) solution in a period of 8.00 hours.So,option  e is correct.

To determine the amperage required for the electrolysis of iron (II) bromide (FeBr2) to plate out a certain amount of iron (Fe), we can use Faraday's laws of electrolysis. Faraday's laws state that the amount of substance produced or consumed during electrolysis is directly proportional to the quantity of electricity passed through the electrolyte.

The equation relating the amount of substance (in moles) produced or consumed during electrolysis is:

moles = (current × time) / (n × F)

where:

current = amperage (in amperes)

time = duration of electrolysis (in seconds)

n = number of electrons involved in the reaction

F = Faraday's constant (approximately 96,485 coulombs per mole of electrons)

First, we need to convert the given mass of iron (111.7 grams) to moles using its molar mass:

moles of Fe = mass / molar mass

moles of Fe = 111.7 g / (55.845 g/mol) (molar mass of iron)

Next, we need to determine the number of electrons involved in the reduction of iron (II) bromide. In this case, Fe2+ ions are reduced to solid iron (Fe), and each Fe2+ ion gains two electrons.

n = 2 (number of electrons transferred per mole of Fe)

Now we can calculate the total charge (in coulombs) required for the electrolysis:

charge = (moles of Fe) × (n × F)

To convert the given duration of electrolysis from hours to seconds:

time = 8.00 hours × 60 minutes/hour × 60 seconds/minute

Finally, we can calculate the required amperage:

amperage = charge / time

Let's perform the calculations:

moles of Fe = 111.7 g / 55.845 g/mol ≈ 1.999 mol

charge = (1.999 mol) × (2 × 96,485 C/mol) ≈ 387,694 C

time = 8.00 hours × 60 minutes/hour × 60 seconds/minute ≈ 28,800 s

amperage = 387,694 C / 28,800 s ≈ 13.47 A

The amperage required to plate out 111.7 grams of Fe from a FeBr2 solution in a period of 8.00 hours is approximately 13.4 amperes.

Therefore, option e is correct.

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Answer:

holla at me!!!!!!!!!!????

Answer:

9.03 times 10times 23 calculate it and there ya go

Answer:

Ok.

Know this.

1 moles of a gas contains 6.022x10²³molecules.

Given: 48g of Oxygen gas.

Find the moles present

Mole = Mass/Molar Mass

Molar Mass of O2 = 16x2 =32g/mol

Mole = 48/32

=1.5moles of O2.

Recall

1 moles of gas contains 6.022x10²³molecules

1.5moles would contain

1.5 x 6.022x10²³molecules

=9.033 x 10²³ molecules of Oxygen gas.

Have a great day!

The centroid of the cross-sectional area has been determined to be 51 mm from the top. The moment of inertia (I) of area about the neutral axis can be determined by using the parallel axis theorem.

Parallel Axis Theorem states that I = I0 + Ad2, where I0 is the moment of inertia about the centroidal axis, A is the cross-sectional area, and d is the distance between the centroidal axis and the neutral axis.To determine the moment of inertia, we first need to determine the centroidal moment of inertia (I0).I0 can be determined by using the formula, I0 = (bd^3)/12, where b is the breadth and d is the depth.

Here, b = 50 mm and d = 102 mm (since the centroid is 51 mm from the top, the depth from the top to the neutral axis will be 51 mm and the depth from the neutral axis to the bottom will also be 51 mm).

Therefore,I0 = (50 x 102^3)/12= 8,617,040 mm4 \(I0 = (50 x 102^3)/12= 8,617,040 mm4\\\)The distance between the centroidal axis and the neutral axis (d) is 51 mm.

Hence, using the parallel axis theorem,\(I = I0 + Ad2I = 8,617,040 + (150 x 51^2)= 14,692,590\) mm4Therefore, the moment of inertia (I) of area about the neutral axis is 14,692,590 mm4.

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