1. With one exception, each of the following units can be used to express mass. What is the exception?A) newtonB) slugC) gramD) Nâ¢s2/mE) kilogram

Answer:

The book's inertia causes it to continue moving.

Inertia can be defined as the tendency of an object such as a book to continue in its state of motion or remain at rest, unless it is acted upon by an external force.

Explanation:

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The angular acceleration vector of a 10-kg cylindrical shell of 2-m radius rotating about a central axis subjected to the force f depends on the direction of the force and cannot be determined solely from the given information.

The angular acceleration of an object is defined as the rate of change of its angular velocity and is a vector quantity that points along the axis of rotation. To calculate the angular acceleration vector, we need to know the direction and magnitude of the force applied to the cylindrical shell, as well as its moment of inertia.

The moment of inertia of a cylindrical shell of radius R and mass M rotating about its central axis is given by I = 0.5MR². Once we know the moment of inertia and the net torque acting on the object, we can calculate the angular acceleration vector using the formula τ = Iα, where τ is the net torque and α is the angular acceleration.

Therefore, more information is needed to determine the direction of the angular acceleration vector.

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Your adult son lets them into the house and tells them they can search it.

A homeowner has the same opinion as a seeker. The police, without a warrant, may also knock at the front door and ask the homeowner if the police can seek the home. If the homeowner has the same opinion, the quest can be performed. The seek police can behavior has to now no longer exceed the scope of consent. For example, if the homeowner lets in a seek of simplest the eating room, simplest that room can be searched.

Searches with a warrant have to be moderately performed. In this approach, the police won't input right into a special residence in which crook pastime is present. To behavior a seek of every other home, a separate warrant is required. Once the police arrive at the home, the quest has to be performed moderately. The police have to usually knock at the door and announce their presence. Once the police input, they'll seek any region of the residence in which the proof of crook pastime can be found. This approach is that if a place can't in all likelihood include that proof, it can't be searched. For example, if the police suspect the robbery of a large,flat-display screen television, the police won't seek the kitchen cabinets to discover the television.

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A pair of electrons would have a lower energy when they are close together than when they are far apart.

The energy of an electron can change in various ways, including:

Absorption of photons: An electron can absorb a photon of light and transition to a higher energy level.

Collisions with other particles: An electron can collide with another particle and gain or lose energy.

Electric or magnetic fields: An electron can experience a change in energy when it moves through an electric or magnetic field.

Changes in the potential energy: The potential energy of an electron can change as it moves closer to or farther away from the nucleus of an atom.

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The magnitude of the acceleration of the body is approximately 1.802 m/s^2 when forces of magnitude 5 Newton and 4 Newton act on a body of mass 4.0 kg at a right angle to each other.

To determine the magnitude of the acceleration of a body when two forces act on it at a right angle, we can use the Pythagorean theorem and Newton's second law of motion.Newton's second law states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma). In this case, the net force is the vector sum of the two forces acting on the body.Using the Pythagorean theorem, we can find the magnitude of the net force. Let's call the force with magnitude 5 Newton as F1 and the force with magnitude 4 Newton as F2. The net force (Fnet) can be calculated as the square root of the sum of the squares of the individual forces: Fnet = sqrt(F1^2 + F2^2).Now we can substitute the net force into Newton's second law to find the acceleration (a). Rearranging the formula, we have a = Fnet / m.Plugging in the values, Fnet = sqrt(5^2 + 4^2) = sqrt(25 + 16) = sqrt(41) Newtons. The mass (m) is given as 4.0 kg.

Finally, the magnitude of the acceleration of the body is calculated as a = Fnet / m = sqrt(41) / 4.0 ≈ 1.802 m/s^2.

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Answer:B

Explanation:

Answer:

The answer is B.

Explanation:

edge2020

Answer:

From highest speed to lowest speed:

A, C, B

Explanation:

On a position time graph, the slope of a line would represent the velocity, since the rate of change represents how many meters traveled in the given time.

The larger the slope, the faster the velocity; the steeper the line, the faster the speed.

Since line B is negative, you know that velocity is negative so it automatically has the lowest speed.

Out of lines A and C, since A is steeper, you know that A has a faster speed.

In conclusion:

A is the fastest

C is the middle

B is the slowest

For the following:

The change in momentum of the body on striking the ground is equal to the initial momentum before firing vertically upward, which is p. Therefore, the answer is (b) p.

The temperature of a body depends upon the average kinetic energy of molecules. Therefore, the answer is (b) speed.

The distance moved by the force is equal to the product of the initial velocity ( V₀) and the time (1 sec) plus half the product of the force (F) and the square of the time (1 sec) divided by the mass (1 kg).

Therefore, the answer is (b) V₀ + F/2.

The total kinetic energy before the explosion is equal to the sum of the kinetic energies of the two pieces after the explosion.

Since the mass and velocity of one of the pieces, calculate its kinetic energy using the formula KE = (1/2)mv².

Therefore, the kinetic energy of the other mass is (b) 32J.

Foams and cotton clothes are used to absorb water because of their (c) capillary action. Capillary action refers to the ability of a substance to draw liquid into its small spaces or pores.

In a spectrum, red color is deviated to a lesser extent than all the other colors because its velocity is (b) less than all the other colors. The speed of light in a medium depends on the refractive index, which is different for different colors. Red light has a lower refractive index compared to other colors, causing it to be deviated to a lesser extent.

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Answer:

I believe it would be B.

Explanation:

When a object is in a gas or liquid form then take whatever the form of the container they are in is. Meaning they can change their volume depending on the container. Also a characteristic of gas and liquid is to take the shape of the container. This may be wrong but this is what I would choose

Answer: A is actually the correct answer. The guy who said B is wrong

Explanation: Gas and plasma both have Changing shape and changing volume

Explanation:

Its organism are one cell I think

Answer:

i'm pretty sure it's red.

Las respuestas a cada inciso son:

a) La resistencia equivalente de la "escalera" de resistores iguales de 125 Ω que se muestra en la figura adjunta es:

\(R_{t} = 341.7 \: \Omega\)

b) La corriente a través de cada uno de los tres resistores de la izquierda si se conecta una batería de 50.0 V entre los puntos A y B es:

a) En la imagen adjuntada correspondiente a la Figura 26-40, podemos observar que las resistencias 1, 2 y 3 están en serie, por lo tanto la ressitencia equivalente entre estas 3 es:

\( R' = R_{1} + R_{2} + R_{3} \)

De aquí en adelante tendremos presente que las todas las resistencias son iguales entre sí y por ende igual a 125 Ω. Las notaciones del 1 al 9 son para poder mostrar la resolución del problema.  

Entonces:

\( R' = 3R \)

Ahora, esta resistencia está en paralelo con la resistencia R₄, por lo tanto la resistencia equivalente entre estas dos es:

\( \frac{1}{R''} = \frac{1}{R'} + \frac{1}{R_{4}} = \frac{1}{3R} + \frac{1}{R} = \frac{4R}{3R^{2}} \)

\( R'' = \frac{3}{4}R \)

Luego, esta resistencia está en serie con las resistencias R₅ y R₆, por lo tanto:

\( R''' = R'' + R_{5} + R_{6} = \frac{3}{4}R + 2R = \frac{11}{4}R \)

Esta resistencia está ahora en paralelo con R₇, entonces:

\( \frac{1}{R''''} = \frac{1}{R'''} + \frac{1}{R_{7}} = \frac{4}{11R} + \frac{1}{R} = \frac{15R}{11R^{2}} \)

\( R'''' = \frac{11}{15}R \)

Finalmente, esta resistencis está en serie con las resistencias R₈ y R₉, por lo tanto la resistencia total es:

\(R_{t} = R'''' + R_{8} + R_{9} = \frac{11}{15}R + 2R = \frac{41}{15}R = \frac{41}{15}*125 \: \Omega = 341.7 \: \Omega\)

b) Para este inciso debemos usar la Ley de Kirchhoff, pues tenemos tres mallas. Supondremos que las corriente de cada malla fluiran en sentido horario, por lo tanto las ecuaciones de para cada malla serán:

Malla 1

Segun la ley de Ohm tenemos:

\(V-i_{1}R-i_{3}R=0\) (1)

Malla 2

\(-i_{2}R-i_{5}R-i_{2}R+i_{3}R=0\) (2)

Malla 3

\(-i_{4}R-i_{4}R-i_{4}R+i_{5}R=0\) (3)

Recordemos tambien que:

\(i_{1}=i_{2}+i_{3}\) (4)

\(i_{2}=i_{4}+i_{5}\) (5)

Lo que debemos hacer ahora es resolver el sistema de ecuaciones y encontrar los valore de las corrientes. Por lo tanto, los valores de las corrientes serán:

\(i_{1}=3/13\: A\)

\(i_{2}=4/65\: A\)

\(i_{3}=11/65\: A\)

\(i_{4}=1/65\: A\)

\(i_{5}=3/65\: A\)

Finalmente:

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The correct answer is e. None of the above alternatives gives a true statement. None of the statements in options a, b, c, and d are true when it comes to a modulus M over a ring R having a finite basis.

When a modulus M can be formed entirely from a finite set of elements, the modulus M is said to be finitely generated. M's finite basis does not, however, automatically imply that M is finitely generated. A basis is a set of linearly independent elements, and it might not be enough to produce all of the components of the modulus.

According to the assertion in option b, M must include nonzero items of nonzero order if it has a finite basis. This is untrue, though. The smallest positive number k, such that the element raised to the power of k equals the identity element, is referred to as the order of an element.

According to option c, every non-null element in a modulus with a finite basis has a null. Nevertheless, this claim is likewise untrue. It is possible for a modulus with a finite basis to have non-null elements without a null element.

According to option d, a ring R is a body, or a field, and only then can a modulus have a finite basis. However, this assertion is also untrue. Even though the ring R is not a field, a modulus can nonetheless have a finite basis. None of the given alternatives provides a true statement about a modulus M over a ring R having a finite basis.

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Answer: 25.1m

Explanation:

The expression of the initial potential energy when the ball is tossed upwards is given as followed

\(PE_{i}\)=mg\(PE_{i}= mgh_{0}\)

Here, m is the mass of the ball, g is the acceleration due to gravity and is the initial height.

The initial kinetic energy of the ball is:

\(KE_{i} =\frac{1}{2}mv^2\)

The final potential energy of the ball at the maximum height is given as:

\(PE_{f}=mgh_{max}\)

The final kinetic energy is at the maximum height is:

\(KE_{f} =0\)

Now you will use the conservation of energy princi\(h_{0}\)ple and substitute the equations into the expression below:

\(KE_{i}+PE_i=KE_f+PE_f\)

\(\frac{1}{2}mv^2+mgh_0=0+mgh_{max}\)

\(h_{max}=h_0+\frac{v^2}{2g}\)

Now substitute 9.81 m/\(s^{2}\) for g, 10m/s for v, and 20.0 m for \(h_{0}\) in the equation above.

h\(_{max}}=(20.0m)+\frac{(10m/s)^2}{2(9.81m/s^2}\)

which is equal to 25.1m

When a 905kg car travels around a circular track with a radius of 525 m and with the magnitude of the centripetal force is 2140 N, then car's tangential speed would be approximately 23.8 m/s.

The centripetal force acting on an object moving in a circular path is given by the formula Fc = m * v^2 / r, where Fc is the centripetal force, m is the mass, v is the tangential speed, and r is the radius of the circular path. Rearranging the formula, we have
v^2 = Fc * r / m
Substituting the given values, we have v^2 = (2140 N) * (525 m) / (905 kg). Solving for v, we find v ≈ 23.8 m/s. Therefore, the car's tangential speed is approximately 23.8 m/s.

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Answer:

LOL! couldnt be me either bestieeeee

Answer:

-_-

Explanation:

i dont know What was XD??

The velocity of the ball before and after collision as V₁ = 41m/s and V₂ = 37m/s respectively, and the mass of the ball as m.The velocity of the bat = 37m/s (opposite direction to the ball). Therefore, the relative velocity of the ball with respect to the bat, V = V₁ - V₂= 41 - 37 = 4 m/s.The coefficient of restitution (e) is defined as the ratio of the relative velocity of separation to the relative velocity of approach.e = V₂’ - V₁’ / V₁ - V₂, where V₂’ and V₁’ are the velocities of the ball and bat after collision.e = V₂’ / V₁ = (77 - 0.11m) / 37, V₂’ = (77 - 0.11m)  37 / 37 = 77 - 0.11m.

The velocity of the ball is u(m) = 77 - 6.87/m + 0.11m/s.Understanding:

Calculation:

Interpretation:

A ball with higher velocity can travel farther when hit with a bat. Therefore, it is always an advantage to use a heavier ball.u’(0.9) = 8.81 m⁻²/s, u’(1.5) = 5.60 m⁻²/sRate of increase of speed is u’(m).Answer:u’(0.9) ≈ 8.81 m⁻²/s, u’(1.5) ≈ 5.60 m⁻²/s.The rate at which this speed is increasing is u’(m).

Velocity is a foreign term that means speed. Speed ​​is the locking of an object every single unit of time. Acceleration or acceleration is the change in velocity in a certain unit of time. The acceleration of an object is caused by a force acting on the object, as explained in Newton's second law. The SI unit for acceleration is meters per second squared (m s−2). What is the difference between speed and pace? Velocity or speed is the quotient between the distance traveled and the time interval. Velocity or speed is a scalar quantity. Speed ​​​​or speed is the result of separation with an interval. Speed ​​or velocity is a vector quantity.

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So, to observe the red traffic light as yellow, the observer must approach the light with a speed of 0.148 times the speed of light.

When the observer approaches the red traffic light with a speed, the light appears shifted towards the blue end of the spectrum. The apparent frequency and wavelength shift is calculated using the Doppler effect equation.

The Doppler shift is given by the relation f′= f (v+vO)/c

where, f' is the observed frequency, f is the frequency of the wave, v is the speed of the observer, v O is the speed of the source and c is the speed of the wave.

For the red traffic light,

f= c/λ = 4.44 × 10^14 Hzλ

= 675 nm

For the yellow traffic light,

f = c/λ

= 5.22 × 10^14 Hzλ

= 575 nm

As we know that the light appears yellow when the red light shifts 575 nm.

Therefore, the observer should be approaching the light with a speed given by the relation as,

∆f/f = v/c⇒ ∆λ/λ

= v/c⇒ v

= c (∆λ/λ)

= c [(λ_0 - λ)/λ_0 ]

Where,λ is the wavelength of the shifted light (λ = 575 nm),λ0 is the wavelength of the unshifted light (λ0 = 675 nm)

Therefore,

v = c [(675 - 575)/675]⇒ v

= 0.148c

So, the observer must approach the red traffic light at a speed of 0.148 times the speed of light to observe it as yellow.

An observer, when approaching a red traffic light, experiences a shift in the light's wavelength towards the blue end of the spectrum. This apparent frequency and wavelength shift is given by the Doppler effect equation.

The Doppler shift can be expressed using the relation,

f′= f (v+vO)/c

where, f' is the observed frequency, f is the frequency of the wave, v is the speed of the observer,v O is the speed of the source and c is the speed of the wave.

The frequency and wavelength of the red and yellow traffic lights are,

f= c/λ

= 4.44 × 10^14 Hz,

λ = 675 nm and

f = c/λ

= 5.22 × 10^14 Hz,

λ = 575 nm.

Since we know that the light appears yellow when the red light shifts by 575 nm, the observer must be approaching the light with a velocity given by the following relation:

∆f/f = v/c⇒ ∆λ/λ

= v/c⇒ v

= c (∆λ/λ_0 ) where λ_0 is the wavelength of the unshifted light (λ_0 = 675 nm)

Therefore,

v = c [(675 - 575)/675]⇒ v

= 0.148c

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For a given potential difference, a bigger resistance means a smaller current through a component.

Resistance in an electrical circuit is a measure of the opposition to the flow of electric current. It is measured in units of ohms (Ω) and is represented by the symbol R in electrical equations.

The amount of resistance in a circuit can affect the amount of current flowing through it and the voltage across it. In a simple circuit, resistance is primarily determined by the materials used in the circuit, such as the wires and the components.

In a more complex circuit, resistance can also be affected by the design of the circuit, including the number of components and the way they are connected. The resistance determines the current in the circuit.

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Answer:

Summary notes really help and make sure to revise on past papers.Good luck

Explanation:

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The gravitational field of the bowling ball is approximately 3.22 x 10⁻⁵ N/kg.  The gravitational field of the bowling ball can be calculated using Newton's law of universal gravitation.

This law states that the gravitational force between two objects is proportional to the product of their masses and inversely proportional to the square of the distance between their centers. The formula for this is:
F = G * (m1 * m2) / r²

Here, F is the gravitational force, G is the gravitational constant (6.674 x 10⁻¹¹ N m²/kg²), m1 and m2 are the masses of the objects, and r is the distance between their centers.

To find the gravitational field (g) of the bowling ball, we can modify this formula:
g = G * m / r²

First, convert the mass (m) of the bowling ball to kilograms: 7200 g = 7.2 kg. Next, find the radius (r) of the ball: 21.6 cm = 0.216 m, so r = 0.108 m.

Now we can calculate the gravitational field:
g = (6.674 x 10⁻¹¹ N m²/kg²) * (7.2 kg) / (0.108 m)²
g ≈ 3.22 x 10⁻⁵ N/kg

The gravitational field of the bowling ball is approximately 3.22 x 10⁻⁵N/kg. This value is significantly weaker than Earth's gravitational field, which is about 9.81 N/kg.

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Answer:

NAFTA is the North American Free Trade Agreement was established to remove barriers between trading countries Canada, Mexico, and the U.S.

Explanation:

The U.S. electronics manufacturers were encouraged to move operations to Mexico by NAFTA

Answer:

The answer is . A 46.2g

The meaning of f∝e is that the extension is directly proportional to the force applied of a particular object from Hooke's law.

The extension for a particular spring and other elastic items is inversely proportional to the applied force. For instance, the extension doubles if the force does. This is effective up until the proportionality limit is reached.

According to Robert Hooke's law of elasticity, which holds true for relatively minor deformations of an item, the displacement or amount of the deformation is directly proportional to the deforming force or load. Hooke's law was first discovered in 1660.

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complete question :

What does this mean f∝e?

The velocity of the mass after the force has stopped acting is 14 m/s.

The velocity of an object is the speed at which the object is moving in a specified direction.

Momentum is related to velocity and mass by the formula:

The velocity of the mass after 8 seconds is first determined.

Change in linear momentum = (1/2 × 2 × 6) + (6 × 4) + (1/3 ×2 × 6) = 36 kgm/s

Initial momentum = 18 kg × 12 m/s = 216 kgm/s

Final momentum = 216 + 36 = 252 kgm/s

Final Velocity = final momentum/mass

Velocity = 252/18 = 14 m/s

After 8 seconds, the force stops acting.

Therefore, the velocity of the mass after the force has stopped acting is 14 m/s.

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The main difference between Cepheid variable stars and RR Lyrae stars is that Cepheids are larger and more luminous, with periods of variability ranging from a few days to several weeks, while RR Lyrae stars are smaller and less luminous, with shorter periods of variability ranging from half a day to a day and a half. Additionally,

Cepheids are typically found in younger populations of stars, while RR Lyrae stars are found in older populations. Cepheids also exhibit a more regular pattern of variability, whereas RR Lyrae stars show more irregular variations.

Cepheid variable stars are typically more massive, larger, and have longer pulsation periods than RR Lyrae stars. Cepheid variable stars have pulsation periods ranging from 1 to 100 days, while RR Lyrae stars have shorter periods, usually between 0.2 to 1 day. Additionally, Cepheids are generally younger stars with higher luminosities, while RR Lyrae stars are older and less luminous.

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The main difference between Cepheid variable stars and RR Lyrae stars is their period-luminosity relationship, brightness, and stellar population.

Cepheid variables have longer periods (typically 1-100 days) and are more luminous, while RR Lyrae stars have shorter periods (about 0.2-2 days) and are less luminous.

Additionally, Cepheid variables are typically found in younger stellar populations, whereas RR Lyrae stars are associated with older populations.

Summary: The main difference between Cepheid variables and RR Lyrae stars lies in their period-luminosity relationship, brightness, and the stellar populations they are found in.

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