1. Which expression is equivalent to 60m 2n6 for all values of m and n where the 5m-on-2 expression is defined? A. 12mns 12n B D. 55m?n mo​

Answer:

I believe it to be 1000 cars. Please look at solution to check if I did it the way your problem wants you to do it.

Step-by-step explanation:

Since Chevy needs to make 5,000,000 in profits, earns 25,000 per car, and had invested 20,000,000, we can set an equation with x being the number of cars:

5,000,000 = 25,000x -20,000,000

Notice how 20,000,000 is negative. This is because chevy starts with a negative amount of money (as they just spent it) and are wanting to earn it back. Anyway, lets solve this.

25,000,000=25,000x

x=1,000

we can see that chevy needs to sell more than 1000 cars to make a profit, however I'm unsure of the 25,000 part. This answer is assuming that they make 25,000 profit for each car.

The half of the number is 4.5 .

Given in question as  14 is subtracted from 6 times a number.

Let us suppose a number is x.

First find 6 times of a number = 6*x.

6 times can be defined as x + x + x + x + x + x = 6*x.

We have to subtract from 6 times a number.

14 is subtracted from 6 times a number means 6x - 14.

After subtracting 14 is left.

So 6x - 14 = 40.

Add 14 both side of equal sign.

6x-14+14 = 40+14.

6x = 54.

x = 54/6.

x = 9.

Half of the number x is 9/2 = 4.5.

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The answers to the questions involving trigonometry are: 90, BC/AB ÷ BC/AB = 1, g = 6.5, <I = 62 degrees, h= 13.8, 12.0, x = 6.8, x = 66.4, 160.6, The pole = 6.7

Trigonometric ratios are special measurements of a right triangle, defined as the ratios of the sides of a right-angled triangle.  There are three common trigonometric ratios: sine, cosine, and tangent

For page 3 question 3,

a) <A + <B = 90 since <C = right angle

b) SinA = BC/AB and CosB = BC/AB

The ratio of the two angles BC/AB ÷ BC/AB = 1

I notice that the ratio of sinA and cosB gives 1

b) The ratio of CosA and SinB will give

BC/AB ÷ BC/AB

= BC/AB * AB/BC = 1

For page 5 number 3

Tan28 = g/i

g/12.2 = tan28

cross multiplying to have

g = 12.2*tan28

g = 12.2 * 0.5317

g = 6.5

b) the angle I is given as 90-28 degrees

<I = 62 degrees

To find the side h we use the Pythagoras theorem

h² = (12.2)² + (6.5)²

h² = 148.84 +42.25

h²= 191.09

h=√191.09

h= 13.8

For page 6

1) Sin42 = x/18

x=18*sin42

x = 18*0.6691

x = 12.0

2) cos28 = 6/x

xcos28 = 6

x = 6/cos28

x [= 6/0.8829

x = 6.8

3)  Tan63 = x/34

x = 34*tan63

x= 34*1.9526

x = 66.4

4) Sin50 123/x

xsin50 = 123

x = 123/sin50

x = 123/0.7660

x =160.6

5)  Sin57 = P/8

Pole = 8sin57

the pole = 8*0.8387

The pole = 6.7

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Answer:

4. 3/10

Step-by-step explanation:

I believe it would be answer 4 because there are 10 coins in all and 3 pennies, making the ratio 3:10

Answer:

y = -2/3x + 1/3

Step-by-step explanation:

2x + 3y = 1

3y = -2x + 1

y = -2/3x + 1/3

To sketch:

Pretend x is 3. y would be -1 2/3.

Now that you have this point, draw through the point (0, 1/3).

There ya go

The predicted value of the car in the year 2009 is $6,232.

First we need to use the formula for exponential decay:

V(t) = V0 × e^(-rt)

Where

We know that the car was purchased in 2000 for $27,600, and that its value in 2004 was $8,300. Therefore, we can use these values to solve for the rate of decay:

$8,300 = $27,600 × e^(-r x 4)

e^(-4r) = 0.3

Taking the natural logarithm of both sides:

-4r = ln(0.3)

r = -0.3567

Now that we have the rate of decay, we can use the same formula to predict the value of the car in 2009, which is 9 years after the initial purchase:

V(9) = $27,600 × e^(-0.3567 x 9) = $6,232

Therefore, the predicted value of the car in the year 2009 is $6,232.

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Meta-analysis is a research technique that involves systematically reviewing and statistically synthesizing data from multiple studies on a particular research question or topic.

The goal of meta-analysis is to provide a comprehensive summary of the existing evidence by combining the results of individual studies, which may have produced conflicting or inconclusive findings.

Meta-analysis typically involves a systematic search for relevant studies, followed by an evaluation of their quality and an extraction of relevant data. The data from the studies are then combined using statistical methods to produce an overall effect size estimate, such as a mean difference or odds ratio.

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The expression 4^n+3 x 16^n - 8^3n cannot be solved for n

from the question, we have the following parameters that can be used in our computation:

4^n+3 x 16^n - 8^3n

The question implies that we solve for n

This in other words mean that we determine the solution for n

The given parameter is an expression (not an equation or an inequality)

To solve for a variable, the given parameter must be an equation or an inequality

Hence, the value of n cannot be determined or it has infinite many solutions

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Answer:

make it the same except the letter b

Step-by-step explanation:

Answer:

the last one.

Step-by-step explanation:

The most appropriate inference procedure for the researchers to use to analyze the results is a matched-pairs t-interval for a population mean difference.

A matched-pairs t-interval for a population mean difference is suitable for this study because it involves comparing the pretest and posttest scores of the same individuals.

The researchers are interested in determining whether there is a significant difference in the number of correct answers before and after the adult reading program.

By using a matched-pairs t-interval, the researchers can analyze the mean difference in scores and determine the range within which the true population mean difference is likely to fall. This inference procedure takes into account the paired nature of the data, accounting for individual differences and increasing the precision of the estimate.

It is important to use this procedure as it considers the correlation between the pretest and posttest scores for each individual, providing a more accurate assessment of the program's effectiveness.

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Answer:

in 3.04 years the will give required intrest

The Goblin Girt take 15 minutes to count the coins in the bag alone if Goblin Gryh can count the coins in a bag in 10 minutes. If goblin Girt counts with him, they can count all the coins in 6 minutes.

Fraction number consists of two parts, one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.

Let's suppose the Goblin Girt take x minutes to count the coins in the bag alone.

Then we can frame an equation to find the value of x:

\(\rm \dfrac{1}{x}+\dfrac{1}{10}=\dfrac{1}{6}\)

\(\rm \dfrac{1}{x}=- \dfrac{1}{10}+\dfrac{1}{6}\)

\(\rm \dfrac{1}{x}=\dfrac{1}{15}\)

x = 15 minutes (reciprocal on both sides)

Thus, the Goblin Girt take 15 minutes to count the coins in the bag alone if Goblin Gryh can count the coins in a bag in 10 minutes. If goblin Girt counts with him, they can count all the coins in 6 minutes.

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The median of the following set of numbers  (18, 26, 29, 18, 44) is 26. The correct option to this question is option A

To find median of the following sequence (18, 26, 29, 18, 44) we will arrange them in ascending order

                            18 , 18 , 26 , 29 , 44   . . . . . .  . . . .(1)

Since the number of terms is odd we will apply the formula

                     Median  = \(\frac{(n+1)}{2} th\) term . . . . . . .(2)

       Here n = number of terms

As per question the n = 5

Therefore putting in equation 2 we get

                      Median = \(\frac{(5+1)}{2} th\) term

                      Median = \(\frac{6}{2} th \\\)  term

                      Median = 3 term

Hence the third term from the sequence ( shown in 1 ) we get the median that is 26

Hence the median of the following set of numbers (18, 26, 29, 18, 44) is 26 .

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The median is:

26

Explanation:

First, we will arrange the numbers from least to greatest.

18, 26, 29, 18, 44

Rearrange

18, 18, 26, 29, 44.

Now, the median is the number in the middle, which is 26.

The equation of the line that passes through the points (-8, 9) and (2, -6) is y = (-3 / 2)x - 3.Given two points (-8, 9) and (2, -6). We are supposed to find the equation of the line that passes through these two points.

We can find the equation of a line that passes through two given points, using the slope-intercept form of the equation of a line. The slope-intercept form of the equation of a line is given by, y = mx + b,Where m is the slope of the line and b is the y-intercept.To find the slope of the line passing through the given points, we can use the slope formula: m = (y2 - y1) / (x2 - x1).Here, x1 = -8, y1 = 9, x2 = 2 and y2 = -6.

Hence, we can substitute these values to find the slope.m = (-6 - 9) / (2 - (-8))m = (-6 - 9) / (2 + 8)m = -15 / 10m = -3 / 2Hence, the slope of the line passing through the points (-8, 9) and (2, -6) is -3 / 2.

Now, using the point-slope form of the equation of a line, we can find the equation of the line that passes through the point (-8, 9) and has a slope of -3 / 2.

The point-slope form of the equation of a line is given by,y - y1 = m(x - x1)Here, x1 = -8, y1 = 9 and m = -3 / 2.

Hence, we can substitute these values to find the equation of the line.y - 9 = (-3 / 2)(x - (-8))y - 9 = (-3 / 2)(x + 8)y - 9 = (-3 / 2)x - 12y = (-3 / 2)x - 12 + 9y = (-3 / 2)x - 3.

Therefore, the equation of the line that passes through the points (-8, 9) and (2, -6) is y = (-3 / 2)x - 3. Thus, the answer is (-3/2)x - 3.

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Answer:

The factored form is,

\((4a^2+2a+1)(4a^2-2a-1)\)

Step-by-step explanation:

We have,

\(16a^4-4a^2-4a-1\\factoring,\\We\ can \ write \ 16a^4 \ as \ (4a^2)^2\\Also,\\then we have,\\(4a^2)^2-(4a^2+4a+1)\\Now, 4a^2 + 4a + 1 \ is \ a \ perfect \ square,\\4a^2 + 4a + 1 = (2a)^2 + 2(2a) + 1\\= (2a + 1)^2\\so, we \ have,\\(4a^2)^2 - (2a + 1)^2\\\)

Using the difference of square formula,

\(x^2 - y^2 = (x+y)(x-y)\\with,\\x = 4a^2,\\y = 2a+1,\\we \ get,\\(4a^2+2a+1)(4a^2-2a-1)\)

Which is the factored form,

Both of these eigenvectors are scalar multiples since their multiplication by a scalar does not change their direction.

Given, the SDE is as follows:

\($$d X_t = \left( {\begin{array}{*{20}{c}} { - 2}&0\\ 0&{ - 3} \end{array}} \right)X_t d t + \left( {\begin{array}{*{20}{c}} 1&0\\ 0&1 \end{array}} \right)d {B_t}$$\)

The underlying 2 × 2 matrix of this SDE is diagonalizable.

A matrix is diagonalizable if it is similar to a diagonal matrix.

The matrix must have n linearly independent eigenvectors for this to happen. And, if the eigenvectors of a matrix are linearly independent, then the matrix is diagonalizable.

The SDE's matrix is diagonalizable since it has two linearly independent eigenvectors.

The matrix is a 2 x 2 matrix, and hence there are two eigenvalues of this matrix.

Eigenvalues of the matrix = [-2, -3]

All the eigenvectors of the underlying matrix of the SDE are scalar multiples.

Yes, all the eigenvectors of the underlying matrix of the SDE are scalar multiples.

To know whether all the eigenvectors are scalar multiples, the eigenvectors of the matrix can be calculated.

The eigenvectors of the matrix are given as follows:

\($$\begin{array}{l}\left( {\begin{array}{*{20}{c}} { - 2}&0\\ 0&{ - 3} \end{array}} \right)\left( {\begin{array}{*{20}{c}} {{v_1}}\\ {{v_2}} \end{array}} \right) = \lambda \left( {\begin{array}{*{20}{c}} {{v_1}}\\ {{v_2}} \end{array}} \right)\\ \Rightarrow \left\{ {\begin{array}{*{20}{c}} { - 2{v_1} = \lambda {v_1}}\\ { - 3{v_2} = \lambda {v_2}} \end{array}} \right.\end{array}$$\)

If we solve for v1 and v2 for different eigenvalues, we get two different eigenvectors as follows:

Eigenvector1\($$\left( {\begin{array}{*{20}{c}} 1\\ 0 \end{array}} \right)$$Eigenvector2 $$\left( {\begin{array}{*{20}{c}} 0\\ 1 \end{array}} \right)$$\)

Both of these eigenvectors are scalar multiples since their multiplication by a scalar does not change their direction.

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According to the Laffer Curve, when the tax rate is 100 percent, tax revenue will be zero.

This is because if the tax rate is 100 percent, then there is no incentive for individuals to work, invest, or engage in any economic activity since they will not be able to keep any of their earnings. As a result, the total tax base will be zero, and the government will not be able to collect any tax revenue.

On the other hand, if the tax rate is zero, tax revenue will also be zero since there will be no tax collected. Therefore, the Laffer Curve suggests that there is an optimal tax rate that maximizes tax revenue, and this rate is somewhere between 0 percent and 100 percent.

The exact rate at which tax revenue is maximized will depend on various factors, such as the elasticity of the tax base, the level of government spending, and the structure of the tax system.

The Laffer Curve is often used to argue for tax cuts, particularly for high-income earners, as a way to stimulate economic growth and increase tax revenue. However, the validity of the Laffer Curve has been the subject of debate among economists, and its actual shape and position are difficult to determine empirically.

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(a) The values of Q1 as 2 and Q3 as 35.

(b) The dataset was arranged in ascending order, and since the total number of observations (n) is odd (13), the median was found to be the middle value, which is 5.

(c) The upper adjacent value was determined by adding 1.5 times the IQR to Q3, resulting in 87.5.

(d) The box plot of the data is illustrated below.

(a) Finding Q1 and Q3:

To determine Q1 and Q3 from the given dataset, we can start by arranging the data in ascending order: 0, 2, 3, 4, 4, 5, 6, 7, 35, 2677, 33478.

Next, we count the total number of observations (n) which is 13 in this case. We use the following formulas to calculate the position of Q1 and Q3:

Q1 = (1 * n) / 4

Q3 = (3 * n) / 4

Substituting the value of n into the formulas:

Q1 = (1 * 13) / 4 = 3.25 (approximately)

Q3 = (3 * 13) / 4 = 9.75 (approximately)

Now, we need to identify the values in the dataset that correspond to these positions. For Q1, we take the value at the position immediately below 3.25, which is 2. For Q3, we take the value at the position immediately below 9.75, which is 35.

Therefore, the values of Q1 and Q3 for the given dataset are 2 and 35, respectively.

(b) Finding the Median:

The median represents the middle value of a dataset when it is arranged in ascending or descending order. If the dataset has an odd number of observations, the median is the middle value itself. If the dataset has an even number of observations, the median is the average of the two middle values.

Arranging the given dataset in ascending order: 0, 2, 3, 4, 4, 5, 6, 7, 35, 2677, 33478.

Since the total number of observations (n) is odd (13), the median will be the middle value. In this case, the middle value is the 7th observation, which is 5.

Therefore, the median for the given dataset is 5.

(c) Finding the Adjacent Values:

Adjacent values, also known as whiskers in a boxplot, indicate the minimum and maximum values within a certain range. The range is determined using the interquartile range (IQR), which is the difference between Q3 and Q1.

For the given dataset, the IQR is calculated as follows:

IQR = Q3 - Q1 = 35 - 2 = 33

The adjacent values are determined by extending the whiskers 1.5 times the IQR below Q1 and above Q3.

Lower adjacent value = Q1 - 1.5 * IQR

Upper adjacent value = Q3 + 1.5 * IQR

Substituting the values:

Lower adjacent value = 2 - 1.5 * 33 = -47.5

Upper adjacent value = 35 + 1.5 * 33 = 87.5

Therefore, the adjacent values for the given dataset are -47.5 and 87.5.

(d) Determining the Correct Modified Boxplot:

To determine the correct modified boxplot, we need additional information or options to compare against the given dataset. Unfortunately, the options are not provided in your question. Please provide the options or any additional information related to the modified boxplot so that I can assist you further in choosing the correct one.

Remember, the boxplot is a graphical representation of the dataset using its quartiles, median, adjacent values, and outliers, if any. It provides a visual summary of the distribution and identifies any potential outliers or extreme values.

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The length of the chord located 0.7 cm from the centre of a circular ring with a 2.5 cm radius is approximately 3.5 cm.

To calculate the length of the chord, we can use the following formula:

Chord Length = 2 x √(r^2 - d^2)

Where r is the radius of the circular ring and d is the distance between the chord and the centre of the circle.

In this case, r = 2.5 cm and d = 0.7 cm. Plugging these values into the formula, we get:

Chord Length = 2 x √(2.5^2 - 0.7^2) ≈ 3.5 cm (rounded to the nearest tenth)

Therefore, the length of the chord is approximately 3.5 cm. This hidden watermark technique is a simple but effective security measure that can help prevent counterfeiting or tampering with important documents. By incorporating a unique and difficult-to-replicate watermark, the jewellery company can protect its brand identity and ensure the authenticity of its official documents.

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Answer:

3. is infinitely many solutions because the answer is 0=0

Step-by-step explanation:

3) 6x+4=6x+4

0=0

Answer:

-27

Step-by-step explanation:

-3 x -3=9

9 x -3= -27

Answer:

-27

Step-by-step explanation:

Answer:

Step-by-step explanation:

a) sum of angle on the straight line TRW is 180.

Given <TRS = 2x+10

<SRW = x-10

<TRS+<SRW = 180

2x+10+x-10 = 180

3x = 180

x = 180/3

x = 60°

<TRV = 180°-(2x+10)

Substitute x = 60° into the expression

<TRV = 180-(2(60)+10)

<TRV = 180-(120+10)

<TRV = 180-130

<TRV = 50°

2) From the diagram attached <MHJ= <LHK (oppositely directed angle)

Given

<MHJ= x+15

<LHK = 2x-20

Substitute the given data into the formula to get x

x+15= 2x-20

x-2x = -15-20

-x = -35

x = 35°

Next is to get the measure of <MHJ

<MHJ = x+15

<MHJ = 35+15

<MHJ = 50°

Step-by-step explanation:

The answer is

\(10x - 80.8\)

Answer:

18 students took the bus to school.

Step-by-step explanation:

If 1/4 of the students walked, that leaves 3/4 of the students who did not walk. That leaves 22.5 students. Out of these students 22.5, 4/5 of them take the bus, and 4/5 of 22.5 is 18.

They sold 4971 day passes and 4686 weekend passes.

Let's start by defining our variables:
- Let d be the number of day passes sold
- Let w be the number of weekend passes sold
From the problem, we know that:
- The price of a day pass is 94, so the total revenue from day passes is 94d
- The price of a weekend pass is 106, so the total revenue from weekend passes is 106w
- The total ticket sales for the festival were 963,990, so we can write an equation: 94d + 106w = 963990
We also know that "They sold 285 more day passes than weekend passes", so we can write another equation: d = w + 285
Now we can substitute the second equation into the first equation to get rid of one of the variables:
94d + 106w = 963990
94(w + 285) + 106w = 963990
94w + 26790 + 106w = 963990
200w = 937200
w = 4686
So they sold 4686 weekend passes. To find out how many day passes were sold, we can use the second equation:
d = w + 285
d = 4686 + 285
d = 4971
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Answer:

C.¿Cuanto dinero hay al cabo de n anos

The negative regulation is the type of regulation in which the transcription of a gene is prevented by the binding of a repressor protein to the DNA, which blocks the binding of RNA polymerase to the promoter region.

The gene expression regulator illustrated in the picture below is an example of what kind of regulation?

The gene expression regulator illustrated in the picture below is an example of the negative regulation. It is known as the trpR Repressor R.

How does it get that name and how does it work?

The TrpR protein is an allosteric protein that binds to the Tryptophan (Trp) molecule. It plays an important role in the regulation of gene expression, as it controls the transcription of the trp operon.

The Trp operon is a cluster of genes that are involved in the synthesis of the amino acid tryptophan. In the absence of tryptophan, the trpR protein is inactive.

However, when tryptophan is present, it binds to the TrpR protein and changes its shape. This change in shape activates the TrpR protein, which then binds to the trp operator region of the DNA.

Binding of the TrpR protein to the trp operator region prevents RNA polymerase from binding to the promoter region, thereby inhibiting the transcription of the trp operon.

Gene expression is regulated in both prokaryotes and eukaryotes, but the mechanisms of regulation differ between the two.

Negative regulation is the type of regulation in which the transcription of a gene is prevented by the binding of a repressor protein to the DNA, which blocks the binding of RNA polymerase to the promoter region.

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The gene expression regulator illustrated in the picture, known as trpR repressor, is an example of negative regulation. It is named after the trp operon, a set of genes involved in tryptophan biosynthesis in bacteria, where this regulator is commonly found.

The trpR repressor works by binding to a specific DNA sequence called the operator region, which is located near the trp operon genes. This binding occurs in the presence of tryptophan, the end product of the trp biosynthesis pathway. When tryptophan levels are high, it binds to the trpR repressor, causing a conformational change that enables it to bind to the operator region of the trp operon DNA.

By binding to the operator region, the trpR repressor physically obstructs the RNA polymerase from transcribing the genes in the trp operon. This prevents the synthesis of enzymes involved in tryptophan biosynthesis. As a result, the production of tryptophan is reduced or halted when there is already an adequate amount available in the cell.

The negative regulation exerted by the trpR repressor is based on the principle of feedback inhibition. When the end product (tryptophan) accumulates, it acts as a co-repressor and binds to the repressor, leading to the repression of its own biosynthesis. This mechanism ensures that the cell only produces tryptophan when it is needed, preventing wasteful energy expenditure.

In summary, the trpR repressor exemplifies negative regulation by binding to the operator region of the trp operon genes in the presence of tryptophan. This binding inhibits the transcription of genes involved in tryptophan biosynthesis, allowing the cell to regulate its production according to its needs.

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To find the derivative of the given expression using Part 1 of the Fundamental Theorem of Calculus, we can follow these steps:

Step 1: Identify the function to be differentiated.

Let's denote the function as F(x) = ∫[0 to x] \(2t^4\) * √(9 - 3u) / \((1 + x^4)\) du.

Step 2: Apply the Fundamental Theorem of Calculus.

According to Part 1 of the Fundamental Theorem of Calculus, if F(x) = ∫[a to x] f(t) dt, then F'(x) = f(x).

In our case, we have F(x) = ∫[0 to x] \(2t^4\)* √(9 - 3u) / (1 + \(x^4)\)du.

So, the derivative of F(x) with respect to x is F'(x) = \(2x^4\) * √(9 - 3x) / (1 + \(x^4).\)

Therefore, the derivative of the given expression is \(2x^4\)* √(9 - 3x) / (1 + \(x^4).\)

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Answer:  Graph D (bottom right corner)

======================================================

Explanation:

The equation y = 3x+3 is in slope intercept form y = mx+b

m = 3 = slope

b = 3 = y intercept

In this case, both the slope and y intercept are the same (though in general they tend not to be).

The positive slope value means the line goes uphill as you move from left to right. The positive y intercept means the diagonal line crosses the y axis somewhere above the horizontal x axis. Specifically, it crosses the y axis at y = 3

Graph D is the only graph that has such a line on it. Graphs A, B and C have the positive slope line where they have a negative y intercept, so we can rule them out.

You can use graphing tools such as Desmos or Geogebra to help confirm this answer. You could also make a table of values, and plot each point, to form the lines. Two points is the minimum amount needed to form any line.

Answer:

Step-by-step explanation:

Answer:

See picture attached below.

Step-by-step explanation:

To graph the system, graph each line separately.

y = 3x + 3 ha slope 3 and y-intercept 3.

Start at 3 on the y-axis and mark a point. Then from this point move up 3 units and to the right 1 unit. Mark a point and connect.

y=-x - 3 has slope -1 and y-intercept -3.

Start at -3 on the y-axis and mark a point. Then from this point move down 1 unit and to the right 1 unit. Mark a point and connect.

This graph is represented in the picture attached.

...............................................................................................................................................

Which graph represents the following system of equations?

y = 3x + 3

y = –x – 3

...............................................................................................................................................

y=x−8

​y=12x−5​

...............................................................................................................................................

Graph of 2 lines that intersect at one point. Both lines are solid. One line passes through (-2,2) and (0,3) and is shaded below the line.

y < = 1/2x + 3...(-2,2)                y < = 1/2x + 3....(0,3)

2 < = 1/2(-2) + 3                        3 < = 1/2(0) + 3

2 < = -1 + 3                                3 < = 0 + 3

2 < = 2 (correct)                        3 < = 3 (correct)

The other line passes through points (0,1) and (1,-2) and is shaded above the line.

y > = -3x + 1...(0,1)            y > = -3x + 1...(1,-2)

1 > = -3(0) + 1                   -2 > = -3(1) + 1

1 > = 0 + 1                         -2 > = -3 + 1

1 > = 1 (correct)                 -2 > = -2 (correct)

...............................................................................................................................................

we have

using a graph tool

see the attached figure

The solution of the system is the shaded area

we know that

The line is solid

The line passes through points  and  and is shaded above the line.

The line is solid

The line passes through points  and  and is shaded below the line

The two lines intersect at one point

therefore

the answer is the option

B) Graph of two lines that intersect at one point. Both lines are solid. One line passes through points negative 2, 2 and 0, 3 and is shaded below the line. The other line passes through points 0, 1 and 1, negative 2 and is shaded above the line.