Explanation:
That`s is the answer, just check
A student throws a 0.22 kg rock horizontally at 20.0 m/s from 10.0 m above the ground. Find the initial kinetic energy of the rock.
Answer:
44J
Explanation:
Given parameters:
Mass of rock = 0.22kg
Initial velocity = 20m/s
Distance moved = 10m
Unknown:
Initial kinetic energy of the rock = ?
Solution:
To solve this problem, we need to understand that kinetic energy is the energy due to the motion of a body.
It is mathematically expressed as;
Kinetic energy = \(\frac{1}{2}\) m v²
m is the mass
v is the velocity
Kinetic energy = \(\frac{1}{2}\) x 0.22 x 20² = 44J
The only major country that does not use the metric system
A.
France
B.
United States
C.
Russia
D.
England
Explain mantle convection.
Answer:
Mantle convection is the very slow creeping motion of Earth's solid silicate mantle caused by convection currents carrying heat from the interior to the planet's surface. The Earth's surface lithosphere rides atop the asthenosphere and the two form the components of the upper mantle.
Explanation:
The sky on Earth is blue because blue light is scattered through the atmosphere as the other colors of light pass through undisturbed. Which nebulae have something similar going on?
A. Emission nebulae
B. Dark nebulae
C. Reflection nebulae
D. Planetary nebulae
The sky on Earth is blue because blue light is scattered through the atmosphere as the other colors of light pass through undisturbed. Dark nebulae have something similar going on.
What is nebulae?Nebulae are interstellar dust and gas clouds that get backlighting from stars both inside and behind them. The clouds are illuminated by the photons from these stars that are dispersed throughout them. A nebula does not generate most of the light that appears to come from it; rather, it reflects and refracted light.
A dark nebula, also known as an absorption nebula, is a form of interstellar cloud, particularly a molecular cloud, that is so dense that it absorbs all of the light from objects behind it, including emission or reflection nebulae and background stars, at visible wavelengths.
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_et F be the radial force field F=xi+yj. Find the work done by this force along the following two curves, both which go from ( 0,0) to (4, 16). (Compare your answers!) A. If C
1
is the parabola: x=t,y=t
2
,0≤t≤4, then ∫
C
1
F⋅dr= B. If C
2
is the straight line segment: x=4t
2
,y=16t
2
,0≤t≤1, then ∫
C
2
F⋅dr=
To find the work done by the force field F along the given curves, we need to evaluate the line integrals of F⋅dr along each curve.
For the parabolic curve C1: x = t, y = \(t^2\), 0 ≤ t ≤ 4.
We parameterize the curve as r(t) = ti + \(t^2j\), where 0 ≤ t ≤ 4.
The differential of the position vector dr = dx i + dy j becomes dr = dt i + 2t dt j.
The dot product F⋅dr is given by F⋅dr = (xi + yj)⋅(dt i + 2t dt j) = (x dt) + (2ty dt).
Substituting the values of x and y from the parameterization, we have F⋅dr = (t dt) + (2t(\(t^2\)) dt) = (t + \(2t^3\)) dt.
Integrating F⋅dr over the curve C1, we get ∫C1 F⋅dr = ∫[0,4] (t + \(2t^3\)) dt.
For the straight line segment C2: x = \(4t^2\), y = \(16t^2\), 0 ≤ t ≤ 1.
We parameterize the curve as r(t) = \(4t^2i\) + \(16t^2j\), where 0 ≤ t ≤ 1.
The differential of the position vector dr = dx i + dy j becomes dr = (8t dt) i + (32t dt) j.
The dot product F⋅dr is given by F⋅dr = (xi + yj)⋅((8t dt) i + (32t dt) j) = (8tx dt) + (32ty dt).
Substituting the values of x and y from the parameterization, we have F⋅dr = (8t(\(8t^2\)) dt) + (32t(\(16t^2\)) dt) = (\(64t^3\) + \(512t^3\)) dt = (\(576t^3\)) dt.
Integrating F⋅dr over the curve C2, we get ∫C2 F⋅dr = ∫[0,1] (\(576t^3\)) dt.
To find the specific values of the line integrals, we need to evaluate the definite integrals.
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what are two factor that effect the force of gravitation
in a two coil system the mutual inductance depends on
The mutual inductance (M) in a two-coil system depends on the number of turns in each coil (N₁ and N₂), the permeability of the medium between the coils (µ), and the geometry of the coils.
Mutual inductance is a measure of the ability of one coil to induce an electromotive force (emf) in the other coil when a current changes in one of them. It depends on several factors.
First, the number of turns in each coil plays a role. The greater the number of turns, the stronger the magnetic field produced by the coil, resulting in a higher mutual inductance.
Second, the permeability of the medium between the coils is important. The permeability determines how easily magnetic flux lines pass through the medium. A higher permeability leads to stronger coupling between the coils and, consequently, higher mutual inductance.
Lastly, the physical arrangement and geometry of the coils affect the mutual inductance. The proximity and alignment of the coils influence the amount of magnetic flux linking them, thereby impacting the mutual inductance.
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If a flea can jump straight up to a height of 0.670 m, how long is it in the air?
If the flea jumps straight up to a height of 0.670 m, it will be in the air 0.74 s.
The time that the flea will be in the air is given by the sum of the rise time and the fall time, which are the same:
\( t_{t} = t_{r} + t_{f} = 2t \) (1)
Where:
\( t_{t} \): is the total time
\( t_{r} \): is the rise time = \( t_{f} \) (the fall time) = t
To calculate the rise time, and so the fall time, we can use the following equation:
\( v_{f} = v_{i} - gt \) (2)
Where:
\( v_{f} \): is the final velocity = 0 (at the maximum height)
\( v_{i}\): is the initial velocity
g: is the acceleration due to gravity = 9.81 m/s²
First, we need to find the initial velocity. We can use the equation:
\( v_{f}^{2} = v_{i}^{2} - 2gh \) (3)
Where:
h: is the maximum height = 0.670 m
Hence, the initial velocity is (eq 3):
\( v_{i} = \sqrt{2gh} = \sqrt{2*9.81 m/s^{2}*0.670 m} = 3.63 m/s \)
Now, the rise and fall time is (eq 2):
\( t = \frac{v_{i}}{g} = \frac{3.63 m/s}{9.81 m/s{2}} = 0.37 s \)
Finally, the total time is (eq 1):
\( t_{t} = (0.37*2) s = 0.74 s \)
Therefore, the flea is in the air 0.74 s.
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Describe what the sun would look like from earth if the entire photosphere were the same temperature as a sunspot?
The sun would look like from earth if the entire photosphere were the same temperature as a sunspot then wouldn't see anything from Earth but darkness
The lowest layer of the sun is the photosphere. It is the outer layer of the sun. It is the deepest region of the luminous object. It is composed of convection cells which are called granules . The Sun's photosphere has a temperature between 4,500 and 6,000 K
Sunspots are areas where the magnetic field is about 2,500 times stronger than Earth's, much higher than anywhere else on the Sun. Because of the strong magnetic field, the magnetic pressure increases while the surrounding atmospheric pressure decreases.
Sunspots tend to occur in pairs that have magnetic fields pointing in opposite directions. A typical spot consists of a dark region called the umbra, surrounded by a lighter region known as the penumbra.
The sunspots appear relatively dark because the surrounding surface of the Sun (the photosphere) is about 10,000 degrees F, while the umbra is about 6,300 degrees F. Sunspots are quite large as an average size is about the same size as the Earth.
If the photosphere were of the same temperature as the sunspot, then we wouldn't see anything from Earth but darkness. We were only able to see and recognize the sunspot because it is surrounded by the visible photosphere.
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You wish to date a hip bone fragment you found at a cave site.
You find a ratio of 1 14C atoms for every 31 14N atoms. How many
half- lives have elapsed?
To determine the number of half-lives that have elapsed, we need to compare the ratio of 14C to 14N atoms found in the hip bone fragment.
The ratio of 1 14C atom for every 31 14N atoms suggests that the hip bone fragment contains a smaller amount of 14C compared to the expected ratio found in a living organism. Since 14C undergoes radioactive decay with a half-life of approximately 5730 years, we can calculate the number of half-lives that have elapsed by observing how many times the ratio needs to double to reach the expected ratio.
In this case, if the expected ratio is 1:1, then the observed ratio of 1:31 would require five doublings to reach 1:1. Therefore, approximately five half-lives have elapsed since the death of the organism from which the hip bone fragment originated.
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A hiker tries to prepare a hard-boiled egg on the high slopes of Mount Everest. The base camp is located 5,300 meters above sea level. The hiker observes that the water begins to boil at 82⁰C, much lower than the 100⁰C needed to cook the raw egg. He hopes that just leaving the egg in the boiling water longer will let the egg cook. Will he have hard-boiled eggs for breakfast?
Answer: :’)
Explanation:
What is the current through and voltage across a capacitor after it is fully discharged?
a) I=0, V=0
b) I=0, V=max
c) I=max, V=0
d) I=max, V=max
The current through and voltage across a capacitor after it is fully discharged is zero. The correct answer is option a.
After a capacitor is fully discharged, the current passing through it is zero, as there is no charge left to flow. The voltage across the capacitor is also zero since all the stored charge has been released.
It's important to note that a fully discharged capacitor does not mean it has lost its ability to hold charge. The capacitor can be charged again by connecting it to a voltage source, which will cause charge to build up on its plates, resulting in a voltage across the capacitor and a current flowing into it.
The amount of current and voltage that the capacitor can hold depends on its capacitance value, which is measured in farads. Capacitors are commonly used in electronic circuits for various purposes, such as filtering, timing, and energy storage.
Therefore, option a : I=0, V=0. is the correct answer
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five words that comes to your mind whenever you hear the word energy
Answer: power, renewable, extinct, solar, wind
Would appreciate brainliest <3
Answer:
chemical
mechanical
electrical
nuclear
thermal
brainliest ?
find the kinetic energy of 5 litre of a gas at STP given standard pressure is 1.013 into 10 to the power 5 Newton per metre square
Answer:
1.52 kJ
Explanation:
Total kinetic energy in gas K = 3NkT/2 where N = number of molecules, K = Boltzmann constant and T = temperature.
Also from the ideal gas law, PV = NkT
substituting PV into K above
K = 3PV/2 where P = pressure = 1.013 × 10⁵ N/m² and V = volume of gas = 5 litres = 5 dm³ = 5 × 10⁻³ m³
K = 3 × 1.013 × 10⁵ N/m² × 5 × 10⁻³ m³/2
= 1519.5 J
= 1.5195 kJ
≅ 1.52 kJ
How did life evolve from nonliving matter?
Answer: it is proposes that in Earth's prebiotic history, simple organic matter was exposed to energy in the form of volcanoes and electrical storms
Explanation:
Describe how rational thinking and experiments contribuited to the devolpement of science
Rational thinking and experiments have played crucial roles in the development of science. Here's how they have contributed:
1. Rational thinking:
- Rational thinking involves using logical reasoning and critical analysis to understand phenomena and make sense of the world.
- It helps scientists formulate hypotheses and theories based on observations and evidence.
- By using rational thinking, scientists can identify patterns, relationships, and cause-effect relationships in their observations.
- Rational thinking enables scientists to develop logical explanations and predictions about natural phenomena.
2. Experiments:
- Experiments are controlled and systematic procedures that scientists use to test hypotheses and gather data.
- Through experiments, scientists can manipulate variables and observe the resulting effects.
- Experiments allow scientists to collect empirical evidence and objectively evaluate the validity of their hypotheses.
- The data obtained from experiments helps scientists make accurate conclusions and refine their theories.
- Experimentation provides a means to replicate and verify scientific findings, ensuring reliability and validity.
In summary, rational thinking provides the foundation for scientific inquiry, while experiments provide a structured and systematic approach to test hypotheses and gather empirical evidence. Together, they have significantly contributed to the development and advancement of science.
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I
10. The current in #9 is the current flowing out of the battery. Is the current returning into the
battery the same?
b. Is the current flowing into the first resistor the same?
c. Is the current flowing through the second resistor the same?
(You can check your answers by connecting the ammeter
first at the negative terminal of the battery, and then at
terminal C, and finally between B&C.)
a. Yes, by Kirchhoff's current law. b. Yes, in a series circuit, current is constant. c. Yes, in a series circuit, current is constant.
a. As per Kirchhoff's ongoing regulation, the ongoing streaming out of an intersection should be equivalent to the ongoing streaming into a similar intersection. In this manner, the current returning into the battery should be equivalent to the ongoing streaming out of the battery.
b. In a series circuit, the current is consistent all through the circuit. In this way, the ongoing streaming into the principal resistor should be equivalent to the ongoing streaming out of the battery and into the remainder of the circuit.
c. Since the circuit is in series, the ongoing should be consistent all through the circuit. Hence, the ongoing moving through the subsequent resistor should likewise be equivalent to the ongoing streaming out of the battery and into the main resistor.
To check these responses, an ammeter can be associated at various places in the circuit. In the event that the ammeter readings are something very similar at each point, it affirms that the current is to be sure a similar all through the circuit as anticipated by Kirchhoff's ongoing regulation.
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Which hand is negatively charged?
A
B
C
D
Answer:
B
b
b
b
b
b
b
b
b
b
b
b
b
b
b
bb
b
b
b
b
b
b
b
b
b
b
b
b
b
b
Answer:
B is the answer
Explanation:
i marked b on my test and got 100%
A basketball is dropped from rest from a height of 30 m. Which distance is closest to how far will it have fallen 2 seconds after it was dropped?
Answer:
10.38m
Explanation:
Using the equation of motion formula
∆S = ut+1/2at²
S2-S1 = ut+1/2gt²
u is the initial velocity
t is the time taken = 2secs
g is the acceleration due to gravity = 9.81m/s²
30-S1= 0(2)+1/2(9.81)2²
30- S1 = 0+4.905(4)
30 -S1 = 19.62
-S1 = 19.62-30
-S1 = -10.38
S1 = 10.38m
The distance closest to how far it should have fallen after 2secs is 10.38m
The relation between linear and angular acceleration is:
Answer:
α=atr
the relationship between linear accelaration and linear accelaration is proportional. The greater the angular acceleration is, the larger the linear (tangential) acceleration.
A ball is thrown directly upward with an initial speed of 72 m/s. How much time passes before the ball reaches the highest point it will ever reach
Answer:
7.35 seconds
Explanation:
The computation of the time passed prior to the ball reached to the highest point is as follows;
As we know that the acceleration because of gravity on earth is 9.8 m/s
As the ball is thrown directly in an upward direction with a speed of 72 m/s
So, the time passed prior to the ball reached to the highest point is
= 72 ÷ 9.8
= 7.35 seconds
Hence, the above represents the answer
Starting from rest, a sprinter reaches his top velocity in 3 seconds. He runs a distance of 24m in 3 seconds. What is his acceleration? (Assume his acceleration is uniform)
Answer:
\(a=5.34\ m/s^2\)
Explanation:
Given that,
Initial velocity of a sprinter, u = 0
He runs a distance of 24m in 3 seconds.
We need to find his acceleration. Let a be his acceleration. Using second equation of kinematics to find it.
\(s=ut+\dfrac{1}{2}at^2\\\\24=0+\dfrac{1}{2}a(3)^2\\\\a=\dfrac{24\times 2}{9}\\\\a=5.34\ m/s^2\)
So, the acceleration of the sprinter is \(5.34\ m/s^2\).
The acceleration of the sprinter from rest to his top speed is 5.33m/s²,
Given the data in the question
Since the sprinter starts from rest,
Initial velocity; \(u = 0\)Time taken; \(t = 3s\)Distance covered; \(s = 24m\)Acceleration; \(a = \ ?\)
To determine the acceleration of the sprinter, we use the second equation of motion:
\(s = ut + \frac{1}{2}at^2\)
Where s is distance covered, u is initial velocity, a is acceleration and t is time.
We substitute our given values into the equation
\(24m = [0 * 3s] + [\frac{1}{2} * a * (3s)^2]\\\\24m = \frac{1}{2} * a * 9s^2\\\\24m = a * 4.5s^2\\\\a = \frac{24m}{4.5s^2} \\\\a = 5.33m/s^2\)
Therefore, the acceleration of the sprinter from rest to his top speed is 5.33m/s²
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a ball on the end of a string is whirled around in a horizontal circle of radius 0.300 m. the plane of the circle is 1.00 m above the ground. the string breaks and the ball lands 1.90 m (horizontally) away from the point on the ground directly beneath the ball's location when the string breaks. find the radial acceleration of the ball during its circular motion.
The radial acceleration of the ball during its circular motion is approximately 59.4 m/s^2.
Centripetal acceleration, a = v^2 / r, where v is the speed of the ball and r is the radius of the circle.
The time it takes for the ball to reach the ground,
y = 1/2 g t^2
where y is the initial height of the ball (1.00 m), g is the acceleration due to gravity (9.81 m/s^2), and t is the time it takes for the ball to reach the ground.
t = sqrt(2y/g)
= sqrt(2 x 1.00 / 9.81)
≈ 0.45 s
Velocity, v = x/t
= 1.90 / 0.45
≈ 4.22 m/s
The radial acceleration of the ball during its circular motion can now be found using the equation,
a = v^2 / r
a = v^2 / r = (4.22)^2 / 0.300 ≈ 59.4 m/s^2
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A 0.5 mass is attached to a horizontal spring which undergoes SHM. The graph of EPE as a
A 0.5 mass is attached to a horizontal spring which undergoes SHM. The graph of EPE as a function of position for the system is shown below.
As we know, the restoring force of a spring is given by F = -kx Where F is the restoring force of the spring k is the force constant of the spring x is the displacement from the equilibrium position hence, the force constant of the spring can be calculated as follows; We know that the potential energy (EPE) stored in a spring is given by EPE = (1/2)kx²From the given graph, we can see that at x = 0.1 m, EPE = 0.5 JNow substituting the given values in the above equation, we get0.5 = (1/2)k(0.1)²k = 100 J/mHence, the force constant of the spring is 100 J/m.
A 0.5 kg mass is attached to a horizontal spring undergoing Simple Harmonic Motion (SHM). The graph of Elastic Potential Energy (EPE) as a function of time will show a sinusoidal pattern, indicating the continuous transfer of energy between kinetic and potential energy during the motion of the mass and spring.
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Read the case study. In your own words and in complete sentences answer the questions. Case Study 1 While preparing dinner Jane knocked a pan of boiling water onto herself. She suffered partial thickness burns to the anterior region of her legs. 1. What is partial thickness burns? 2. Jane loose sensation of the affected area? Why? 3. Using the Rule of Nines calculate the total body surface area percentage that is burned?
Partial thickness burns are burns that involve the top layer of skin and the layer below it.
Jane lost sensation in the affected area because the nerve endings may be affected in partial-thickness burns.
As per the Rule of Nines, each leg makes up 18% of the body surface, so the anterior region of both legs would account for 18% of 50% (half of the body surface) which equals to 9% of the body surface.
Using the Rule of Nines, the total body surface area percentage that is burned is calculated. It is a quick and easy way to calculate the area of the burn that is used to determine the degree of burn.
The rule of nines is a medical term used to evaluate the extent of burns on a patient's body. This rule estimates the amount of body surface area (BSA) that has been affected by burns. This technique is often used by healthcare professionals to predict a patient's fluid needs and to help guide treatment decisions. The Rule of Nines divides the body into 11 sections, each accounting for 9% of the body surface. The remaining 1% is accounted for by the perineum. The areas are head and neck, arms, chest, abdomen, upper back, lower back, buttocks, front of legs, and back of legs. In this case, Jane had suffered partial thickness burns to the anterior region of her legs.
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For an object of mass m and acceleration a, which equation can be used to
calculate the applied force on the object?
O
A. F =ma
m
B. F =
a
O
C. Fa"
a
D. F
m
SUM
Answer:
The equation for acceleration can be rewritten as B to calculate the net force acting on an object when its mass and acceleration are known.
Explanation:
I hope that helps! (B is the answer)
The equation for acceleration can be rewritten as B to calculate the net force acting on an object when its mass and acceleration are known.
What is Force?A push or pull that an object experiences as a result of interacting with another item is known as a force. Every time two items interact, a force is exerted on each of the objects.
The force is no longer felt by the two objects when the interaction ends. Only when there is interaction do forces actually exist.
Action-at-a-distance forces are those that happen even when the two interacting objects are not physically touching each other but are nevertheless able to push or pull against each other despite their physical separation.
Therefore, The equation for acceleration can be rewritten as B to calculate the net force acting on an object when its mass and acceleration are known.
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what type of acceleration is used to maintain slow forward motion or allow speed to increase gradually
The type of acceleration used to maintain slow forward motion or allow speed to increase gradually is called constant acceleration.
What is constant acceleration?This type of acceleration refers to a change in velocity that occurs at a constant rate over a period of time, in other words the acceleration is uniform.
For example, a car that is accelerating from a stop to a slow, steady speed would be experiencing constant acceleration. The speedometer in the car would show a gradual increase in speed, rather than a sudden jump.
This is different from non-uniform acceleration, where the rate of change in velocity is not constant. For example, a car accelerating rapidly from a stop to a high speed would be experiencing non-uniform acceleration, as the speedometer would show a rapid increase in speed.
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in three situations, a briefly applied horizontal force changes the velocity of a hockey puck that slides over frictionless ice. the overhead views of the figure indicate, for each situation, the puck’s initial speed vi, its final speed vf, and the directions of the corresponding velocity vectors. rank the situations according to the work done on the puck by the applied force, most positive first and most negative last.
The work done on the Puck by the applied force from the most positive to the most negative is c, b, a respectively.
According to Newton's second law of motion, the force applied to an object is directly proportional to the product of mass and acceleration of the object.
F = ma
\(F= \frac{mv}{t}\)
The force applied to an object increases with increases in the velocity of the object.
In the given diagram, the resultant velocity of the puck is calculated as follows;
Figure a:
\(\Delta v = v_f -v_i\\\\\Delta v = 5 - 6 = - 1 \ m/s\)
Figure b:
\(v = \sqrt{4^2 + 3^2} \\\\v = 5 \ m/s\)
Figure c:
\(\Delta v = 4 - (-2)\\\\\Delta v = 6 \ m/s\)
Thus, the work done on the Puck by the applied force from the most positive to the most negative is c, b, a respectively.
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Which waves are used in medicine?
______
A. Gamma and Microwaves
B. X rays and Gamma
C. X rays and Infrared
D. Radio waves and UltraViolet
Answer:
C
Explanation:
what is the equation for finding the net torque on a dipole? Why does the dipole exhibit a torque?
The equation for finding the net torque on a dipole is given by τ = p × E, where τ represents the torque, p is the dipole moment, and E is the electric field.
A dipole exhibits a torque because it consists of two opposite charges separated by a distance, and when placed in an electric field, these charges experience forces in opposite directions, causing a rotational effect or torque. The torque tends to align the dipole moment with the direction of the electric field, and the strength of the torque depends on the magnitude of the dipole moment and the electric field, as well as the angle between them.
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