1. What is the experimental probability of not landing on a 6?

2. What is the theoretical probability of not landing on a 6?

Answer:

a: 10% b: 25/100 c: 1/2

Step-by-step explanation:

Answer:

10% for A  25/100 For B 1/2 for C

Step-by-step explanation:

In statistics, there are various measures used to represent data. These measures include range, mean, variance, and standard deviation. Range is the difference between the largest and smallest value in a set of data.

The mean is the average of a set of data, calculated by summing the values and dividing by the total number of values.

Variance is a measure of the spread of data around the mean. It is calculated by finding the average of the squared differences from the mean. Standard deviation is the square root of variance.

It measures how much the data is spread out from the mean. It is also the most commonly used measure of dispersion.

The ages (in years) of a random sample of shoppers at a gaming store are 12, 17. 23, 13, 20, 16, 21, 16, 13, and 18.

RangeThe range is the difference between the highest value and the lowest value. To calculate the range, we subtract the smallest value from the largest value. Range = largest value - smallest valueRange = 23 - 12Range = 11

Therefore, the range is 11. MeanThe mean is the sum of the values divided by the total number of values.

To calculate the mean, we add up the values and divide by the total number of values.Mean = (12 + 17 + 23 + 13 + 20 + 16 + 21 + 16 + 13 + 18) / 10Mean = 169 / 10Mean = 16.9Therefore, the mean is 16.9.

VarianceVariance is a measure of the spread of data around the mean. It is calculated by finding the average of the squared differences from the mean.

To calculate the variance, we need to follow the below steps:

1. Find the mean of the data set.

2. Subtract the mean from each value in the data set.

3. Square each of these differences.

4. Add up all of the squared differences.

5. Divide the sum by the total number of values.

Variance = Σ(x - μ)² / nWhere:Σ = Summationx = Valueμ = Meann = Total number of valuesNow, we can calculate the variance.Variance = [(12 - 16.9)² + (17 - 16.9)² + (23 - 16.9)² + (13 - 16.9)² + (20 - 16.9)² + (16 - 16.9)² + (21 - 16.9)² + (16 - 16.9)² + (13 - 16.9)² + (18 - 16.9)²] / 10Variance = (17.61 + 0.01 + 36.00 + 13.69 + 9.61 + 0.81 + 16.81 + 0.81 + 11.56 + 1.21) / 10Variance = 5.7Therefore, the variance is 5.7. Standard DeviationThe standard deviation is the square root of variance. Standard deviation = √varianceStandard deviation = √5.7Standard deviation ≈ 2.4Therefore, the standard deviation is approximately 2.4.

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Answer:

Diameter14

Using the formulas

A=πr2

d=2r

Solving for A

A=1

4πd2=1

4·π·142≈153.93804m²

Step-by-step explanation:

The tangent vector  → \(r(t)=〈4cos(2t),4sin(2t),5t〉\), normal vector at t=0 is given by →N(0) = 〈-1,0,0〉, and binormal vector at t=0 is given by →\(B(0) = 〈0, -0.441, -0.898〉\)

The tangent vector, normal vector, and binormal vector of the given curve are as follows:

Given curve:

→ \(r(t)=〈4cos(2t),4sin(2t),5t〉\) at the point t=0

To find: Tangent vector, the Normal vector, and the Binormal vector (→T, →N and →B) at the point t=0

Tangent vector: To find the tangent vector of the given curve

→\(r(t)=〈4cos(2t),4sin(2t),5t〉\) at the point t=0,

we need to differentiate the equation of the curve with respect to t.t = 0, we have:

→\(r(t) = 〈4cos(2t),4sin(2t),5t〉→r(0) = 〈4cos(0),4sin(0),5(0)〉= 〈4,0,0〉\)

Differentiating w.r.t t:→\(r(t) = 〈4cos(2t),4sin(2t),5t〉 → r'(t) = 〈-8sin(2t),8cos(2t),5〉t = 0\),

we have:

→\(r'(0) = 〈-8sin(0),8cos(0),5〉= 〈0,8,5〉\)

Therefore, the tangent vector at t = 0 is given by

→\(T(0) = r'(0) / |r'(0)|= 〈0,8,5〉 / sqrt(89)≈〈0.000,0.898,0.441〉\)

Normal vector:To find the normal vector of the given curve

→\(r(t)=〈4cos(2t),4sin(2t),5t〉\)

at the point t=0, we need to differentiate the equation of the tangent vector with respect to t.t = 0, we have:

→\(T(0) = 〈0.000,0.898,0.441〉\)

Differentiating w.r.t t:

→\(T'(t) = 〈-16cos(2t),-16sin(2t),0〉t = 0\),

we have:

→\(T'(0) = 〈-16cos(0),-16sin(0),0〉= 〈-16,0,0〉\)

Therefore, the normal vector at t = 0 is given by

→\(N(0) = T'(0) / |T'(0)|= 〈-16,0,0〉 / 16= 〈-1,0,0〉\)

Binormal vector: To find the binormal vector of the given curve

→\(r(t)=〈4cos(2t),4sin(2t),5t〉\)

at the point t=0, we need to cross-product the equation of the tangent vector and normal vector of the curve.t = 0, we have:

→\(T(0) = 〈0.000,0.898,0.441〉→N(0) = 〈-1,0,0〉\)

The cross product of two vectors:

→\(B(0) = →T(0) × →N(0)= 〈0.000,0.898,0.441〉 × 〈-1,0,0〉= 〈0, -0.441, -0.898〉\)

Therefore, the binormal vector at t = 0 is given by→B(0) = 〈0, -0.441, -0.898〉

Hence, the tangent vector, normal vector, and binormal vector of the given curve at t=0 are as follows:

→\(T(0) = 〈0.000,0.898,0.441〉→N(0) = 〈-1,0,0〉→B(0) = 〈0, -0.441, -0.898〉\)

The given curve is

→\(r(t)=〈4cos(2t),4sin(2t),5t〉 at the point t=0.\)

We are asked to find the tangent vector, the normal vector, and the binormal vector of the given curve at t=0.

the tangent vector at t=0. To find the tangent vector, we need to differentiate the equation of the curve with respect to t. Then, we can substitute t=0 to find the tangent vector at that point. the equation of the curve Is:

→\(r(t) = 〈4cos(2t),4sin(2t),5t〉\)

At t = 0, we have:

→\(r(0) = 〈4cos(0),4sin(0),5(0)〉= 〈4,0,0〉\)

We can differentiate this equation with respect to t to get the tangent vector as:

→\(r'(t) = 〈-8sin(2t),8cos(2t),5〉\)

At t=0, the tangent vector is:

→\(T(0) = r'(0) / |r'(0)|= 〈0,8,5〉 / sqrt(89)≈〈0.000,0.898,0.441〉\)

Next, we find the normal vector. To find the normal vector, we need to differentiate the equation of the tangent vector with respect to t. Then, we can substitute t=0 to find the normal vector at that point.

At t=0, the tangent vector is:

→\(T(0) = 〈0.000,0.898,0.441〉\)

Differentiating this equation with respect to t, we get the normal vector as:

→\(T'(t) = 〈-16cos(2t),-16sin(2t),0〉\)

At t=0, the normal vector is:

→\(N(0) = T'(0) / |T'(0)|= 〈-16,0,0〉 / 16= 〈-1,0,0〉\)

Finally, we find the binormal vector. To find the binormal vector, we need to cross-product the equation of the tangent vector and the normal vector of the curve.

At t=0, we can cross product →T(0) and →N(0) to find the binormal vector.

At t=0, the tangent vector is:

→\(T(0) = 〈0.000,0.898,0.441〉\)

The normal vector is:

→N(0) = 〈-1,0,0〉Cross product of two vectors →T(0) and →N(0) is given as:

→\(B(0) = →T(0) × →N(0)= 〈0.000,0.898,0.441〉 × 〈-1,0,0〉= 〈0, -0.441, -0.898〉\)

Therefore, the tangent vector, normal vector, and binormal vector of the given curve at t=0 are:

→\(T(0) = 〈0.000,0.898,0.441〉→N(0) = 〈-1,0,0〉→B(0) = 〈0, -0.441, -0.898〉\)

The tangent vector of the given curve

→\(r(t)=〈4cos(2t),4sin(2t),5t〉\)

at the point t=0 is given by →\(T(0) = 〈0.000,0.898,0.441〉.\)

The normal vector at t=0 is given by →N(0) = 〈-1,0,0〉.

The binormal vector at t=0 is given by →B(0) = 〈0, -0.441, -0.898〉.

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Answer:

0.55

Step-by-step explanation:

45/100 = 0.45

1/2 = 0.50

Answer:

0.55 is the biggest

Step-by-step explanation:

45% can be converted to 0.45

1/2 is the same as 50%, so in decimal form, it is 0.50 (although no matter how many 0s you put at the end, it will still be the same, so this could effectively be 0.5.)

0.55 is already done for you, so there is nothing to do here.

Therefore, the biggest is 0.55

Answer:

See below

Step-by-step explanation:

If you consider an open circle, it would exclude the value with which we have circled when writing the inequality. Hence the only possible signs with in such an example can be a greater than sign ( > ) or less than sign ( < );

Let us take a look at an example to help. We are given a graph with an open circle on the number say 3. An arrow extends to the right of this number 3;

\(Inequality Sign - <,\\Inequality - x > 3,\\\)

Hope this helps!

The correct statement is: A. P(E) = 0.3. The probability of event E, denoted as P(E), is equal to 0.3.

To determine the correct answer, let's analyze the given information.

We know that events D and E are independent, which means that the occurrence of one event does not affect the probability of the other event happening.

Given:

P(D) = 0.6

P(D and E) = 0.18

Since events D and E are independent, the probability of both events occurring (P(D and E)) can be calculated as the product of their individual probabilities:

P(D and E) = P(D) * P(E)

Substituting the given values:

0.18 = 0.6 * P(E)

To find the value of P(E), we can rearrange the equation:

P(E) = 0.18 / 0.6

P(E) = 0.3

Therefore, the correct answer is A. P(E) = 0.3.

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Based on the graph, it looks like the only y-value not used by the graph is –6.

So, the range would be (-infty, -6) U (-6, infty).

Answer:

5/13

Step-by-step explanation:

Cos = opp/hyp

5 is opposite of angle R and 13 is the hypotenuse.

In general, given the condition p->q,

Therefore, in our case,

1)

2) Similarly, setting

Answer:

The increase as a percentage was 11.1%.

Step-by-step explanation:

The increase is $10.  The ratio of this increase to the original $90 is

$10

------- = 1/9

$90

Multiplying this by 100%, we get 11.1%.

The increase as a percentage was 11.1%.

The data described, the number of televisions in different households, is discrete.

discrete data consists of individual values that can be counted and are distinct from one another. In this case, the number of televisions is a discrete variable because it can only take on whole numbers, such as 0, 1, 2, 3, and so on. You cannot have a fractional or continuous number of televisions. Each household will have a specific count of televisions, and there is no intermediate value between each whole number. Additionally, the number of televisions is distinct for each household, meaning that it can differ from one household to another.

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Carolyn made an error in her work because she did not correctly distribute the negative in Step 3.

A system of equations is the given term math for two or more equations with the same variables. The solution of these equations represents the point of the intersection.

You can solve a system of equations by the adding or substitution methods. In the addition method, you eliminate a variable, on the other hand, in the substitution method you replace a variable for the other.

The question gives:3x-2y=7 (1)y=x+2The question shows that Carolyn applies the substitution method because she replaces the variable y (equation 2) in equation 1. See the given step 2.

3x – 2y = 7

3x – 2(x + 2) = 7

3x – 2x - 4 = 7 - here it is the mistake. (Carolyn did not correctly distribute the negative).

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Answer:

\( 2.58 \times {10}^{8} \)

Step-by-step explanation:

\(9.3. {10}^{7} - 3.4. {10}^{6} \\ = (27 \times 10 - 12) \times {10}^{6}\\ = (270 - 12) \times {10}^{6} \\ = 258 \times {10}^{6} \\ = 2.58 \times {10}^{6 + 2} \\ = 2.58 \times {10}^{8} \)

Answer: i don't know

Step-by-step explanation:

what is this

also i need points! sry

Answer:

28

Step-by-step explanation:

hope this helped

Answer:

0.00273            Smallest

27.3 × 10^-3

2.73 × 10^3

273 × 10^2        Largest

Answer:

The terms 1/15, n/30 mean that the buyer can take a 1% discount off the face value of the invoice if payment is made within 15 days (the discount period). After 15 days, the entire amount (net) of the invoice is due within 30 days.

Given that the payment was made during the discount period, we can calculate the amount of the discount using the original invoice amount:

Discount = 1% of $2,425.24 = $2,425.24 * 1/100 = $24.2524

Now, to calculate the amount due after the discount, subtract the discount from the original invoice amount:

Amount due after discount = $2,425.24 - $24.2524 = $2,400.9876

The question also states that $1,180.77 has already been paid. So, to calculate the remaining amount due, subtract the payment from the amount due after the discount:

Remaining amount due = $2,400.9876 - $1,180.77 = $1,220.2176

Therefore, a payment of approximately $1,220.22 will reduce the amount due on the invoice by $1,180.77, assuming the payment is made within the discount period.

9514 1404 393

Answer:

Step-by-step explanation:

The prime factorization of 1458 is ...

  1458 = 2·3^6

The exponent of 3 is even, but we need another factor of 2 to make the exponent of that factor even. You will get a perfect square by multiplying by 2.

  √(2·1458) = √2916 = 54

Multiplying by 2 will give the square of 54.

Answer

179

Step-by-step explanation:

190-11=179

Answer:

Step-by-step explanation:

try subtracting 11 from 190 to get your answer.

190-11 =189

Answer: a a a a. Aa

E s. Ss s

Step-by-step explanation:

s. S s s s. S s s s s

Answer:

D = 8

Step-by-step explanation:

3 down 2 to the right

This problem implies more cases to solve as well as the use of other formulas that we can use in the subject of free fall, if we read our exercise again, we will realize that we only have a height of 150 meters from where it is dropped freely a ball. To proceed to resolve, we collect the data.

Data:

h = 150 m

g = 9.8 m/s²

In order to obtain the distance traveled in 4 seconds, we can use the following formula:

\(\bf{\displaystyle h={{v}_{0}}t+\frac{g{{t}^{2}}}{2} }\)

Remember, that as it is a free fall, the initial speed is null, that is, zero. So the formula reduces:

\(\bf{\displaystyle h=\frac{g{{t}^{2}}}{2} }\)

We are going to place the 4 seconds in the “t” of time. Thus:

\(\bf{\displaystyle h=\frac{g{{t}^{2}}}{2}=\frac{\left( 9.8\frac{m}{{{s}^{2}}} \right){{\left( 4s \right)}^{2}}}{2} }\)

Carrying out the indicated operations:

\(\bf{\displaystyle h=\frac{g{{t}^{2}}}{2}=\frac{\left( 9.8\frac{m}{{{s}^{2}}} \right)16{{s}^{2}}}{2}=\frac{156.8m}{2}=78.4m }\)

That is to say that the height at 4 seconds is 78.4 meters.

For the velocity at 4 seconds, we use the following formula:

\(\bf{\displaystyle {{v}_{f}}={{v}_{0}}+gt}\)

Remember, that since there is no initial speed because it is free fall, then the formula is reduced:

\(\bf{\displaystyle {{V}_{f}}=gt }\)

Substituting our data and calculating:

\(\bf{\displaystyle {{v}_{f}}=gt=\left( 9.8\frac{m}{{{s}^{2}}} \right)\left( 4s \right)=39.2\frac{m}{s} }\)

So the speed at 4 seconds is 39.2 m/s.

Although it seems difficult to solve this section, it is not. It's very easy, let's remember that after 4 seconds it has traveled 78.4 meters and that the height from where the ball was dropped is 150 meters, so the difference is the amount that remains to reach the ground, that is:

\(\bf{\displaystyle {{h}_{T}}={{h}_{1}}+{{h}_{2}}}\)

It is as if we had:

\(\bf{\displaystyle 150=78.4+{{h}_{2}} }\)

Clearing "h2" what would be the distance to reach the ground.

\(\bf{\displaystyle {{h}_{2}}=150-78.4=71.6m }\)

In other words, we need to travel 71.6 meters to reach the ground.

Answer:

1/20

Step-by-step explanation:

x(whatever the amount was) -3/4= 1/4

1/4 - 1/5 = 1/20

THE PART

Answer:

4/20

Step-by-step explanation:

Since 3/4 & 1/5 don't have the same denominator you would multiply their denominators by each other top and bottom. You would get 3/4=15/20 & 1/5=4/20. Since you spent 15/20 of your money you would have 5/20 left. Now 1/5 of 5/20 is 1/20. So you would take 5/20 - 1/20 and you would have 4/20 of your money left.

I hope this helps:)

Answer:

Step-by-step explanation:

7/8 - 1/4 = 58 = 0.625

The height of the trapezoid is 98 units

The space enclosed by the boundary of a plane figure is called its area.

A trapeziod is a closed shape or a polygon, that has four sides, four corners/vertices and four angles

The area of a trapezoid is expressed as;

A = 1/2( a+b)h

where a and b are the bases length of the trapezoid.

245= 1/2 ( 14+21)h

490 = 35h

divide both sides by 35

h = 490/35

h = 98 units

Therefore the height of the trapezoid is 98 units

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Answer:

30 cm

Step-by-step explanation:

This question asks for the total distance travelled by both ants combined. Regardless of the direction they travelled, the ants' distance travelled together(13 + 17) is 30 centimeters total.

Hope this helps!

Answer:

Hence 27 cubes can be obtained.

Step-by-step explanation:

Volume occupied by one cube of side 2cm = 2*2*2 = 8cm^3

Volume of cube of side 6cm = 216cm^3

Number of cubes of side 2cm which would fit in a cube of side 6cm = 216/8 = 27 cubes