1. The circular wire loop is curved into a circle with diameter D(t)=Do +G t. where D(t) is the diameter at time t, Do is the initial diameter, and G is the rate it grows. [10 points] a. Derive a formula for the EMF induced in the wire as it grows. [5 points] b. The wire has a circular cross section with thickness To, The wire has resistivity p. Derive the formula for the current in the wire as a function of time. (Hint : you found its resistance in the homework for chapter 27 . Be careful to change the diameter rate from B in the previous problem to G in this problem). [3 points] c. Sketch a graph of I (t)

02222222222222222222222222222222

Explanation:

Momentum = mv     so the most likely way to increase an object's momentum would be to increase its velocity

Answer:

Explanation: Vi = 18k/hr   =  18 x 1000/3600  = 5/s

                      Vf = 54k/hr  =   54 x 1000/3600 = 15/s

                       S  =  5

                        a =   ?

                        t  =   ?

           BY USING NEWTON 3RD EQUATION OF MOTION

                        2aS= Vf^2-Vi^2

                           a =  Vf^2 - Vi^2/2S

                           a =   15^2 - 5^2/2(5)

                           a  =    20

           BY USING NEWTON  1st  EQUATION OF MOTION

                          Vf = Vi + at

                            t  =  Vf-Vi/a

                            t  =  15-5/20

                            t  =  10/20 = 1/2 sec = 0.5 sec

The acceleration of the car is 20 m/s²

This is the rate of change of velocity. To calculate the acceleration of the car, we use the formula below.

Formula:

Where:

Make a the subject of the equation

From the question,

Given:

Substitute these values above into equation 2

Hence, The acceleration of the car is 20 m/s².

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Answer:

\(0.842\ \text{lb ft}\)

\(0.1052\ \text{lb ft}\)

Explanation:

d = Diameter of wheel = 6 in

r = Radius = 3 in = \(\dfrac{3}{12}=0.25\ \text{ft}\)

t = Thickness = \(\dfrac{3}{4}=0.75\ \text{in}=\dfrac{0.75}{12}\ \text{ft}\)

w = Specific weight = \(425\ \text{lb/ft}^3\)

\(t_2\) = Time taken to slow down = 35 s

\(t_1\) = Time taken to reach operating speed = 5 s

\(\omega\) = Angular velocity = \(3450\times \dfrac{2\pi}{60}\ \text{rad/s}\)

Weight is given by

\(W=2\pi r^2tw\\\Rightarrow W=2\pi\times 0.25^2\times \dfrac{0.75}{12}\times 425\\\Rightarrow W=10.43\ \text{lbs}\)

Mass is given by

\(m=\dfrac{W}{g}\\\Rightarrow m=\dfrac{10.43}{32}\\\Rightarrow m=0.326\ \text{lb}\)

Moment of inertia is given by

\(I=\dfrac{mr^2}{2}\\\Rightarrow I=\dfrac{0.326\times 0.25^2}{2}\\\Rightarrow I=0.01019\ \text{lb ft}^2\)

Angular acceleration while slowing down is given by

\(\alpha_f=\dfrac{\omega}{t_2}\\\Rightarrow \alpha_f=\dfrac{3450\times \dfrac{2\pi}{60}}{35}\\\Rightarrow \alpha_f=10.32\ \text{rad/s}^2\)

Frictional moment is given

\(\tau_f=I\alpha_f\\\Rightarrow \tau_f=0.01019\times 10.32\\\Rightarrow \tau_f=0.1052\ \text{lb ft}\)

Frictional moment is \(0.1052\ \text{lb ft}\)

Angular acceleration while speeding up is given by

\(\alpha=\dfrac{\omega}{t_1}\\\Rightarrow \alpha=\dfrac{3450\times \dfrac{2\pi}{60}}{5}\\\Rightarrow \alpha=72.26\ \text{rad/s}^2\)

Motor torque is given by

\(\tau_m=\tau_f+I\alpha\\\Rightarrow \tau_m=0.1052+0.01019\times 72.26\\\Rightarrow \tau_m=0.842\ \text{lb ft}\)

Motor torque is \(0.842\ \text{lb ft}\).

Given that the apparent weight of a passenger in an elevator is greater than his true weight, let's select the correct statement.

We have:

• Net force on the passenger when the elevator moves upward with an increasing speed:

ma = N - mg

Where mg is the weight of the passenger which acts downwards

N is the normal force which acts upwards.

• Apparent weight of the passenger:

N = mg + ma

Hence, we can see the apparent weight is greater than true weight.

• Also, when the elevator moves downward with a decreasing speed, the Net force is:

N = mg + ma

The elevator is speeding as it moves upward while it is slowing down when it is moving downward.

Therefre, the correct statement is that the elevator is speeding as it moves upward.

ANSWER:

b)The elevator is speeding as it moves upward.

The temperature of a substance is determined by the average kinetic energy of its particles, so Substance X and Substance Y have higher temperatures because their particles have more kinetic energy. The number of particles does not affect temperature. The correct options are (A) and (C).

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It will accelerate. A force of magnitude F exerted on an object of mass m applies an acceleration a according to

F = m a

Remember that force and accleration are vector quantities, so the object's acceleration would point in the same direction as the applied force. The other choices describe some possible outcomes, but

• it the object starts in motion, it can only stop moving if the force opposes the motion and acts in the opposite direction. The object would eventually stop, but only for an instant before changing direction and starting to move again. Consider a ball being thrown directly upward, reaching its highest point, then falling again.

• its speed (which is a scalar quantity) would only decrease if the object starts in motion and is slowed down. But if it starts at rest, its speed can only increase. Consider a ball being dropped from some height and gaining speed as it falls.

• its velocity will certainly change, but can only increase if the object is at rest, or if it's already in motion and the force points in the same direction.

Answer:

It will accelerate.

Explanation:

i go to K12

Answer:

Explanation:

Volume of inner core = 4/3 π R₁³

where R₁ is radius of inner core so R₁ = 1220 km

Volume of inner core = 4/3 π (1220 km )³

= 1764.4 x 10¹⁷ m³ - 4/3 π (1220 km )³

= 76.02 x 10⁸ x 10⁹ m³

= 76.02 x 10¹⁷ m³

Density = 13000 kg / m³

mass = volume x density

= 76.02 x 10¹⁷ x 13000

= 988.26 x 10²⁰ kg

Volume of outer  core = 4/3 π (3480 km )³ -  4/3 π (1220 km )³

= 1764.4 x 10⁸ km³ - 4/3 π (1220 km )³

= 1764.4 x 10⁸ x 10⁹m³ - 4/3 π (1220 km )³

= 1764.4 x 10¹⁷ m³ - 4/3 π (1220 km )³

= 1764.4 x 10¹⁷ m³ - 76.02 x 10¹⁷ m³

= 1688.38 x 10¹⁷ m³

density = 11100 kg /m³

mass of outer  core= 1688.38 m³ x10¹⁷ x  11100 kg /m³

= 18741 x 10²⁰ kg

Volume of outer mantle  =  4/3 π (6371  km )³ - 4/3 π (3480 km )³

= 10826 x 10¹⁷ m³- 1764.4 x 10¹⁷ m³

= 9062 x 10¹⁷ m³

density = 4400 kg /m³

mass of outer  core= 9062 x 10¹⁷ m³ x  4400 kg /m³

= 39872.8 x 10²⁰ kg

Total mass of the earth = 988.26 x 10²⁰ kg + 18741 x 10²⁰ kg +39872.8 x 10²⁰ kg

= 59602.06 x 10²⁰ kg .

Total volume = 4/3 π (6371  km )³

= 10826 x 10¹⁷ m³

Density = mass / volume

= 59602.06 x 10²⁰ kg /  10826 x 10¹⁷ m³

= 5505.45 kg / m³

B )

Mass = 5.974 x 10²⁴ kg

volume = Total volume = 4/3 π (6371  km )³

= 10826 x 10¹⁷ m³

density = 5.974 x 10²⁴ kg / 10826 x 10¹⁷ m³

= 5518.2 kg / m³

As you were holding the block down and in place, the spring exerted an upward force that balanced the downward push by your hand and its own weight. So this restoring force has a magnitude of R such that

R - 50 N - (3 kg) g = 0   =>   R = 79.4 N

As soon as you remove your hand, the block has acceleration a such that, by Newton's second law,

R - (3 kg) g = (3 kg) a   =>   a = (79.4 N - (3 kg) g) / (3 kg) ≈ 16.7 m/s^2

pointing upward.

The energy efficiency of the car is approximately 16.7%.

The energy efficiency of a car is the ratio of the useful work output (in this case, the kinetic energy of the car) to the total energy input (in this case, the energy released by burning the gasoline). The equation for energy efficiency is:

The useful work output can be calculated as the kinetic energy of the car using the equation:

where m is the mass of the car and v is its velocity.

Substituting the given values:

The total energy input is the energy released by burning 0.1 L of gasoline, which is:

Substituting these values into the equation for efficiency:

Therefore, the energy efficiency of the car is approximately 16.7%.

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Answer:

Unit of G = m³/kg s²

Explanation:

The force of gravitational attraction is represented by the equation.

\(F=G\dfrac{m_1m_2}{r^2}\)

F is the magnitude of the gravitational attraction on either body

m₁ and m₂ are the masses of the bodies, r is the distance between them. G is the gravitational constant.

We need to find the unit of G.

Rearranging the above formula for G.

\(G=\dfrac{Fr^2}{m_1m_2}\)

Putting units of F,m and r such that,

\(G=\dfrac{N\times m^2}{kg^2}\\\\\because N=kgm/s^2\\\\G=\dfrac{kg\times m\times m^2}{kg^2\times s^2}\\\\G=m^3/kgs^2\)

Hence, the correct option is (c) m³/kg s².

The approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

To approximate the heat transfer through the air layer in the double-paned window, we can assume that the glass layers have a negligible impact on the heat flow. The heat transfer can be calculated using Fourier's Law of Heat Conduction, which states that the heat flow (Q) is proportional to the temperature difference (ΔT) and inversely proportional to the thickness (L) and thermal conductivity (k) of the material.

First, we need to calculate the effective thermal conductivity of the air layer due to its thickness and the thermal conductivity ratio between air and glass. Let's denote the thermal conductivity of air as k_air and the thermal conductivity of glass as k_glass. Since glass has a thermal conductivity roughly 36 times greater than air, we have k_glass = 36 * k_air.

Next, we calculate the effective thermal conductivity of the air layer as:

k_eff = (k_air * L_air) / (L_air + k_glass)

Substituting the given values, we have:

k_eff = (k_air * 0.0165 m) / (0.0165 m + 0.005 m) = 0.01309 * k_air

Now, we can calculate the heat flow per second through the air layer using the formula:

Q = (k_eff * A * ΔT) / L_air

Substituting the given values, we get:

Q = (0.01309 * k_air * 0.760 m^2 * 23.0 K) / 0.0165 m = 24.4 J/s

Therefore, the approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

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The water flow rate from the faucet, assuming a steady flow, is approximately 0.0001608 cubic meters per second.

The phenomenon of a water stream "necking down" as it falls can be explained by the principle of conservation of mass. According to this principle, the flow rate of water remains constant throughout the system.

In the given figure, the water stream emerges from a faucet with an initial cross-sectional area of 1.8 cm² (Area one). As the water falls, it narrows down to a smaller cross-sectional area of 0.3 cm² (Area two) at a height of 25 cm.

To calculate the water flow rate assuming steady flow, we can use the formula:

Flow rate = A₁√(2gh) / A₁² - A₂²

Where A₁ and A₂ are the initial and final cross-sectional areas, respectively, g is the acceleration due to gravity, and h is the height of the water column.

Plugging in the given values, we have:

Flow rate = 1.8 cm² √(2 × 9.8 m/s² × 25 cm) / (1.8 cm²)² - (0.3 cm²)²

Converting the units to match, we get:

Flow rate = 0.018 m² √(2 × 9.8 m/s² × 0.25 m) / (0.018 m²)² - (0.003 m²)²

Simplifying the expression, we find:

Flow rate ≈ 0.0001608 m³/s

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a) It is the error present in the measuring instrument that causes it to register a value even when there is no input or output being measured.

b) An example of when you would have to allow for zero error is when using a measuring instrument like a vernier caliper or micrometer screw gauge.

a) Zero error refers to the deviation or discrepancy in the measurement instrument, where the indication or reading on the instrument is not zero when the quantity being measured is zero. In other words, it is the error present in the measuring instrument that causes it to register a value even when there is no input or output being measured.

Zero error can occur due to various reasons such as manufacturing defects, wear and tear, misalignment, or improper calibration of the instrument. It can be positive or negative, depending on whether the instrument reads higher or lower than the actual value.

b) An example of when you would have to allow for zero error is when using a measuring instrument like a vernier caliper or micrometer screw gauge. These instruments are commonly used to measure the dimensions of objects with high precision.

In a vernier caliper, for instance, zero error can occur when the jaws do not close perfectly when there is no object being measured. If the caliper shows a reading other than zero when the jaws are closed, it indicates the presence of zero error.

To obtain accurate measurements, the zero error needs to be accounted for and compensated. This can be done by adjusting the position of the zero on the scale or by subtracting the zero error value from the measured readings.

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Answer:

conduction I believe if not its convection

Answer: Conduction transfers energy from the spoon to the hot chocolate.

Explanation: Heated water molecules and steam rise in the beaker, carrying heat by convection.

Less reflective material is sprayed thickly in one-way glass, unlike a regular mirror, the glass is not entirely opaque. The glass reflects about half of the light that hits it while letting through about half of it.

An actual or hypothetical image is produced by a mirror, which is a reflecting surface that reflects light. A mirror reflects the identical image of a thing when it is held up in front of it. The incident rays originate from the object, and the image is made by the reflected rays. The intersection of the light beams determines whether the images are real or simulated. While virtual images are created when light beams from a point appear to diverge, real pictures are created when light rays actually cross.

We may establish the direction of the light as it moves to a specific location on a photograph of an object by using ray diagrams.

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The weight of child can be given as,

Substitute the known values,

Divide the value of force with the weight.

Thus, the force is 23.9 times the weight of child.

Answer:

45,000

Explanation:

Kg=1000

Therefore 45kg=45,000

Answer:

441 N

Explanation:

Edge 2021

The work done​  to the horizontal direction of displacements the body is 3200 joule.

A force must be applied and there must be movement in the force's direction for a work to be completed scientifically.

With that said, we may state that Work is the product of the force's component acting in the displacement's direction and its magnitude.

Applied force = 400 N

Displacement in the direction of force = 8 m

Hence, work done = 400 ×  Joule = 3200 joule.

Therefore, the work done​  to the horizontal direction of displacements the body is 3200 joule.

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According to Coulomb's law, the force of attraction or repulsion between 2 charged bodies is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. Thus, the following options are correct

b- decrease the charge on one object

d- increase the distance between the objects' centers

e- decrease the charge on both objects

w=225000 J  

E=225000 J  

P=9000 W  

P=22500 W

Ew=Fd=E  

P=E/t

The slope of the segment on the graph that corresponds to any given phase would represent the heat capacity at that phase.

Because of the constant slopes, there is little variation in the heat capacity as a function of temperature within a given phase.

In the case of a gas, a big slope results in a small heat capacity, whereas a small slope results in a large heat capacity.

In other words, the heat capacity decreases as the slope becomes steeper and vice versa.

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Answer:

sediment accumulation in a lake near a farm.

Explanation:

In Agriculture, there are various techniques adopted by farmers for the growth and development of their crops. An effective and efficient agricultural technique would have a significant impact on the level of productivity attained by the farmers and as such meeting the unending requirements or needs of the consumers.

There are various agricultural techniques used in farming and these includes;

I. Mixed farming.

II. Arable farming.

III. Pastoral farming.

IV. Bush fallowing.

V. Shifting cultivation.

VI. Nomadic herding.

VII. Subsistence farming.

Generally, these agricultural techniques adopted by farmers has an effect or impact on the environment where it is practiced.

For example, one of such effect on the environment is the accumulation of sediments in a lake near the farm. Thus, this could lead to the formation of new materials such as silt, sand, clay, organic debris, etc., inside the lake.

Answer:

sediment accumulation in a lake near a farm.

Explanation:

Waves are an essential part of the physical world, and they play a crucial role in our daily lives. Waves can be broadly categorized into two types: mechanical waves and electromagnetic waves. Mechanical waves require a medium to travel, such as sound waves, while electromagnetic waves do not need a medium and can travel through space, such as light waves. Both types of waves exhibit unique properties, including amplitude, frequency, wavelength, and speed.

Sound waves are mechanical waves that require a medium to travel, such as air or water. These waves are longitudinal, meaning they move in the same direction as the wave. They have properties such as amplitude, which is the magnitude of the wave, and frequency, which is the number of waves that pass through a point in a given amount of time. Sound waves have a wide range of frequencies, from low-frequency waves, such as the sound of a bass guitar, to high-frequency waves, such as a dog whistle.

Electromagnetic waves, on the other hand, do not require a medium to travel and can travel through a vacuum, such as space. These waves are transverse, meaning they move perpendicular to the wave. They also have properties such as frequency and amplitude. Electromagnetic waves have a wide range of frequencies, from radio waves used to transmit music to gamma rays used to treat cancer.

In our daily lives, waves play a significant role. For example, we use radio waves to listen to the radio, watch television, and make phone calls. We use microwaves to heat food quickly, and we use infrared waves to sense heat and motion in security systems. We also use visible light waves to see the world around us, and ultraviolet waves to help our bodies produce vitamin D.

In conclusion, waves are a fundamental aspect of the physical world and play a significant role in our daily lives. Whether it's listening to the radio, using Bluetooth in our cars, or making phone calls, waves are involved in almost everything we do. Understanding the properties of waves, including frequency, amplitude, and wavelength, is crucial in understanding how waves function and how they affect our daily lives.

Answer:

Difference between MeV and meV?

1 MV = 1000000 volts. 1 MeV stands for million electron volts. It is a unit of energy. 1 MeV = 1.60217653 x 10 13

Explanation:

hope this helps <3

Answer and Explanation:

A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.

However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing. Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body.

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A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.

However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing.

Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body

Answer:

The units of kinetic energy are mass times the square of speed, or kg⋅m2/s2 kg ⋅ m 2 /s 2. But the units of force are mass times acceleration, kg⋅m/s2 kg ⋅ m/s 2, so the units of kinetic energy are also the units of force times distance, which are the units of work

Explanation:

EDGE 2021

The arrows are drawn in the figure which shows gravitational forces on each person on earth.

Gravitational force is force of attraction between two masses. Gravitational force(F) between two bodies is directly proportion to the product of masses(m₁,m₂) of two bodies and inversely proportional to square of distance(r) between them. mathematically it is written as,

F∝ m₁.m₂

F ∝ 1/r²

F = G m₁,m₂÷r²

where G is gravitational constant, whose value is 6.6743 × 10⁻¹¹ m³ kg-1s⁻².

Force is expressed in Newton N in SI unit. its dimensions are [M¹L¹T⁻²].

This is analogous with coulomb's law which gives force between two charges.

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Answer: You take the biggest number and subtract it from the smallest number.

Explanation: Hope this helps.

Answer:

Subtract the minimum data value from the maximum data value to find the data range.

Explanation:

\(Hope\) \(this\) \(helps!\)