1. randy burgarner earns a gross monthly salary of $3,600.00. to date, he has earned a total of $14,400.00. what is this month's social security tax withholding? what is this month's medicare tax withholding?

Using the binomial distribution, it is found that there is a:

a) 0.3439 = 34.39% probability he will receive at least one upgrade during the next two weeks.

b) 0.8671 = 86.71% probability that in a set of 20 flights, Sam will be upgraded 3 times or fewer.

For each flight, there are only two possible outcomes, either he receives an upgrade, or he dos not. The probability of receiving an upgrade in a flight is independent of any other flight, hence, the binomial distribution is used to solve this question.

Binomial probability distribution

\(P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}\)

\(C_{n,x} = \frac{n!}{x!(n-x)!}\)

The parameters are:

An airline claims that there is a 0.10 probability that a coach-class ticket holder who flies frequently will be upgraded to first class on any flight, hence \(p = 0.1\).

Item a:

He takes 4 flights, hence \(n = 4\).

The probability is:

\(P(X \geq 1) = 1 - P(X = 0)\)

In which:

\(P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}\)

\(P(X = 0) = C_{4,0}.(0.1)^{0}.(0.9)^{4} = 0.6561\)

Then:

\(P(X \geq 1) = 1 - P(X = 0) = 1 - 0.6561 = 0.3439\)

0.3439 = 34.39% probability he will receive at least one upgrade during the next two weeks.

Item b:

20 flights, hence \(n = 20\).

The probability is:

\(P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)\)

Then:

\(P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}\)

\(P(X = 0) = C_{20,0}.(0.1)^{0}.(0.9)^{20} = 0.1216\)

\(P(X = 1) = C_{20,1}.(0.1)^{1}.(0.9)^{19} = 0.2702\)

\(P(X = 2) = C_{20,2}.(0.1)^{2}.(0.9)^{18} = 0.2852\)

\(P(X = 3) = C_{20,3}.(0.1)^{3}.(0.9)^{17} = 0.1901\)

\(P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.1216 + 0.2702 + 0.2852 + 0.1901 = 0.8671\)

0.8671 = 86.71% probability that in a set of 20 flights, Sam will be upgraded 3 times or fewer.

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Answer:

1 pint=32    1 quart=64    1 gallon=256

Step-by-step explanation:

A Gantt chart is indeed a specialized chart type. Basic chart types include bar charts, line charts, and pie charts, which are commonly used for visualizing data. Specialized chart types, such as Gantt charts, serve more specific purposes.

Yes, there are indeed basic chart types as well as specialized chart types. Basic chart types include things like bar graphs, line graphs, and pie charts, while specialized chart types are designed for more specific purposes, such as organizational charts, flowcharts, and Gantt charts.

In particular, a Gantt chart is a specialized chart type that is commonly used in project management to help visualize the tasks, milestones, and dependencies involved in a project. It is designed to show a timeline of when each task or activity needs to be completed, as well as how long it will take and what resources will be needed.

Overall, while basic chart types are great for general data visualization purposes, specialized chart types like Gantt charts can be incredibly useful for specific tasks or industries, and can help users to more effectively communicate and manage complex information.

A Gantt chart is indeed a specialized chart type. Basic chart types include bar charts, line charts, and pie charts, which are commonly used for visualizing data. Specialized chart types, such as Gantt charts, serve more specific purposes. A Gantt chart is designed for project management and helps visualize a project's timeline, tasks, and progress, making it easier to manage and allocate resources.

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Answer:

  572π ft² ≈ 1797 ft²

Step-by-step explanation:

You want the surface area of a cylinder with radius 11 feet and height 15 feet.

The formula for the area of a cylinder is ...

  A = 2πr(r +h) . . . . . . . radius r, height h

For the given radius and height, the area is ...

  A = 2π(11 ft)(11 +15 ft) = 572π ft² ≈ 1797 ft²

The area of the cylinder is about 1797 square feet.

The population of Pakistan is calculated as; 1.82 × 10⁸

The parameters for the population are;

Japan Population; J = 1.30 × 10⁸

Brazil Population; B = 1.95 × 10⁸

Now, the ratio of J:B = x : x + 5

Thus;

(1.30 × 10⁸)/(1.95) × 10⁸ = x/(x + 5)

Solving this gives x = 10

Now, we are told that;

J:P = x : x + 4

Where P is pakistan population

Thus;

(1.30 × 10⁸)/P = 10/(10 + 4)

(1.30 × 10⁸)/P = 10/14

P = 14(1.30 × 10⁸)/10

P = 1.82 × 10⁸

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When we plot the inequality y > 1 -3x on the graph, then we get the following graph.

Inequality:

Inequality defines the non equal relationship of the expression. While we plot the graph for the inequality either we get the shade region in above or below the line of the graph instead of making the straight line.

Given,

Here we have the inequality y> 1 - 3x.

Now, we have to find in which of the given graph is associated with the given inequality.

To find the exact graph of the given inequality y > 1 - 3x.

First, we have to make the given inequality into standard form, for that we have to rewrite the given inequality as follows:

y > - 3x + 1

Now, We have to plot it one the graph using the graphing calculator, then we get the graph like the following.

While we looking into the graph of the inequality we have identified that, it can't includes the origin and the shaded region will be placed above the line of the graph.

Therefore, option (d) is is correct one.

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The approximate length of a side of the rhombus is 10.67 cm.

A rhombus is a quadrilateral with all sides of equal length.

The diagonals of a rhombus bisect each other at right angles.

Let's label the length of one diagonal as d1 and the other diagonal as d2.

In the given rugby-shaped figure, the length of d1 is 14 cm, and the length of d2 is 12 cm.

Since the diagonals of a rhombus bisect each other at right angles, we can divide the figure into four right-angled triangles.

Using the Pythagorean theorem, we can find the length of the sides of these triangles.

In one of the triangles, the hypotenuse is d1/2 (half of the diagonal) and one of the legs is x (the length of a side of the rhombus).

Applying the Pythagorean theorem, we have \((x/2)^2 + (x/2)^2 = (d1/2)^2\).

Simplifying the equation, we get \(x^{2/4} + x^{2/4} = 14^{2/4\).

Combining like terms, we have \(2x^{2/4} = 14^{2/4\).

Further simplifying, we get \(x^2 = (14^{2/4)\) * 4/2.

\(x^2 = 14^2\).

Taking the square root of both sides, we have x = √(\(14^2\)).

Evaluating the square root, we find x ≈ 10.67 cm.

Therefore, the approximate length of a side of the rhombus is 10.67 cm.

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Answer:

3x^2 - 17x + 24

Step-by-step explanation:

(x – 3)(3x – 8)

3x^2 + (-8x) + (-9x) + 24

3x^2 - 17x + 24

The domain of f(x, y) is a closed and bounded region, hence by the Extreme Value Theorem, absolute maximum and minimum values exist.

To find them, we first check for critical points by setting the partial derivatives equal to zero:

fx = 2x = 0, so x = 0

fy = -2y = 0, so y = 0

The only critical point is (0, 0). We also need to check for extreme values on the boundary of the domain.

On the curve x = 0, we have f(0, y) = -y^2 - 23, which has a maximum value of -20 at y = 0 and a minimum value of -24 at y = ±1.

On the curve x = 3, we have f(3, y) = 9 - y^2 - 23, which has a maximum value of -14 at y = 0 and a minimum value of -30 at y = ±1.

On the curve y = ±1, we have f(x, ±1) = x^2 - 21, which has a maximum value of 2 at x = ±√21 and a minimum value of -19 at x = 0.

Therefore, the absolute maximum value of f(x, y) is 2, which occurs at (±√21, ±1), and the absolute minimum value of f(x, y) is -30, which occurs at (3, ±1).

(b) The domain of g(x, y) is y > 0 and y < 1, which is an open and unbounded region. Therefore, the absolute maximum and minimum values may not exist. However, we can still find critical points by setting the partial derivatives equal to zero:

gx = y = 0, so y = 0

gy = x - 4y^3 = 0, so x = 4y^3

The only critical point is (0, 0), but it is not in the domain of g(x, y). Therefore, there are no critical points to consider.

(c) The domain of h(x, y) is the unit circle centered at the origin, which is a closed and bounded region. Hence, by the Extreme Value Theorem, absolute maximum and minimum values exist. To find them, we first find critical points by setting the partial derivatives equal to zero:

hx = 2x = 0, so x = 0

hy = 2y + r = 0, so y = -r/2

Substituting y = -r/2 into the equation of the circle x^2 + y^2 = 1, we get x^2 + r^2/4 = 1, or x = ±√(1 - r^2/4). Thus, the critical points are (±√(1 - r^2/4), -r/2).

We also need to check for extreme values on the boundary of the domain (the unit circle). Since the unit circle is a closed and bounded region, by the Extreme Value Theorem, the absolute maximum and minimum values of h(x, y) on the unit circle occur at either the critical points or at the endpoints of the boundary.

At the endpoints of the boundary, we have h(1, 0) = 23, which is the maximum value, and h(-1, 0) = 25, which is the minimum value.

At the critical points, we have h(±√(1 - r^2/4), -r/2) = 22 + r^2/4, which

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Answer:

njf39rjdksowbeudnfbxksne fjfkfmejens

Answer:

a) 3 x 20 = 60

b) -2x20 = -40

question c and d are unclear as we do not know how many questions were wrong and how many were not answered.

Sorry but I hope that helped

Answer:

a)  60 points

b)  0 point

c)  22 points

d)  -11 points

Step-by-step explanation:

a)  20 * 3 = 60 points (all answered correct)

b)   0 point (Minimum score if you don't answer any of the questions)

c)  10 * 3 = 30 points

    (14 - 10)  * -2 = -8 points

    right minus wrong =  30 - 8 = 22 points  

d)  5 * 3 = 15 points

    (18 - 5) * -2 = -26 points

    right minus wrong = 15 - 26 = -11 points

Answer:

35.4

is the answer to this question

Answer:

5 5/7

Step-by-step explanation:

Convert it to fractions:

30/7 and 4/3

Now multiply.

120/21

Simplify it:

5 5/7

The reliability function is a useful tool for modeling the probability of failure of a system over time. And the probability of failure within 400 hours is approximately 14%.

The reliability function is a common tool used to model the probability of failure of a system over time. In this case, we will use an exponential distribution to model the failure rate of a light bulb.

Assuming an exponential distribution, a particular light bulb has a failure rate of 0.002. The failure rate is the average number of failures per unit of time. The exponential distribution has the property that the probability of failure is proportional to the length of time the system has been in operation.

The reliability function for an exponential distribution is given by R(t) = e^(-λt), where λ is the failure rate. The reliability function gives the probability that the system will still be functioning after t units of time.

So, the probability of failure within 400 hours is given by 1 - R(400), where R(400) is the reliability function evaluated at 400 hours.

1 - R(400) = 1 - e^(-0.002 * 400) = approximately 0.14

So, the probability of failure within 400 hours is approximately 14%.

By assuming an exponential distribution, the reliability function is given by R(t) = e^(-λt), where λ is the failure rate. In this case, the reliability function can be used to calculate the probability of failure within a given time period, such as 400 hours for the light bulb.

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Isotope 24 Na with a half-life of 15 hours and a sample mass of 2 grams, the formula: m(t) = m₀ * e^(-kt) where m(t) is the mass of the sample at time t, m₀ is the initial mass, e is the base of the natural logarithm, k is the decay constant, and t is the time elapsed. Therefore, the rate of decrease in mass after 5 hours is: (2 g - 1.29 g) / 5 hours ≈ 0.14 g/hour


We can model the decay of the Sodium-24 isotope using the exponential decay formula, which includes the terms isotope, mass, and half-life.

Let M(t) represent the mass of the isotope at time t. The exponential decay formula is:
M(t) = M₀ * e^(-λt)

where M₀ is the initial mass (2 grams), e is the base of the natural logarithm (approximately 2.718), λ is the decay constant, and t is the time in hours.

First, we need to find the decay constant λ using the half-life (15 hours). The relationship between λ and half-life is:

λ = ln(2) / half-life

So, λ = ln(2) / 15 ≈ 0.0463.

Now we have our decay equation:

M(t) = 2 * e^(-0.0463t)

To find the rate of decrease in mass after 5 hours, we need to find the derivative of M(t) with respect to t:

dM(t)/dt = -0.0463 * 2 * e^(-0.0463t)

After 5 hours, we can calculate the rate of decrease by substituting t = 5 into the derivative equation:
dM(5)/dt = -0.0463 * 2 * e^(-0.0463 * 5) ≈ -0.0804 g/h

So, after 5 hours, the mass of the Sodium-24 isotope is decreasing at a rate of approximately 0.0804 grams per hour.

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Therefore , the solution of the given problem of area comes out to be The poster is 4 feet tall.

Calculating how much space would be needed to entirely enclose the object's exterior will reveal its overall size. The surroundings is considered when selecting a comparable product with a tubular form. The surface area of anything determines its overall dimensions. The number of sides connecting a cuboid's four trapezoidal shapes determines how much water it can contain.

Here,

Let's write the rectangle poster's height as h feet.

The following formula determines the area of a rectangle: Area equals Length x Width

In this instance, we are informed that the poster's area is 22 square feet and its width (or base) is 5 1/2 feet.

=> 22 = h × 5 1/2

=> 22 ÷ 5 1/2 = h

=> 5 1/2 = 11/2

=> 22 ÷ 11/2 = h

When multiplying by a fraction, we must flip the numerator and denominator to get the reciprocal:

=> 22 ÷ 11/2 = h

=> 22 × 2/11 = h

=> 44/11 = h

When we simplify the fraction, we obtain:

=> h = 4

The poster is therefore 4 feet tall.

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Step-by-step explanation:

the given data is

tanθ = 2.773 and 0<θ<π/2

this implies θ = tan inverse(2.773)

⇒ θ =  70.16°

Therefore, sinθ = sin70.16° = 0.9406

similarly,cosθ =  cos70.16° = 0.3393

therefore, values of sinθ and cosθ are  0.9406 and 0.3393 respectively.

Answer:

\($\lim_{x \to 0} \frac{2\cos(x)+1}{\sin^2 (x) } = \infty$\)

and the limit does not exist

Step-by-step explanation:

We are given the following limit

\($ \lim_{x \to 0} \frac{\sin(2x)+\sin(x)}{\sin^3 (x)} $\)

We can't just merely consider

\($ \lim_{x \to 0} f(x)=g(x) $\)

and then solve

\($ \lim_{x \to 0} \frac{\sin(2x)+\sin(x)}{\sin^3 (x)} = \frac{\sin(0)+\sin(0)}{\sin^3 (0)} =\frac{0}{0} =0$\)

This is an indeterminate form. Wrong.

=========================================

We have the identity

\(\sin(2x) = 2\sin(x)\cos(x)\), therefore we can substitute it in the limit

\($ \lim_{x \to 0} \frac{\sin(2x)+\sin(x)}{\sin^3 (x)} = \lim_{x \to 0} \frac{2\sin(x)\cos(x)+\sin(x)}{\sin^3 (x)} $\)

then

\($ \lim_{x \to 0} \frac{2\sin(x)\cos(x)+\sin(x)}{\sin^3 (x)} = \lim_{x \to 0} \frac{\sin(x)(2\cos(x)+1)}{\sin^3 (x)} = \boxed{ \lim_{x \to 0} \frac{2\cos(x)+1}{\sin^2 (x)} }$\)

Now, differently from the first case,

we have \(2\cos(x)+1 \longrightarrow 3\) as \(x \longrightarrow 0\) because \(\cos(0)=1\)

On the other hand,  \(\sin^2(x)\longrightarrow 0\) as \(x \longrightarrow 0\) because \(\sin(0)=0\)

In fact,

\($\lim_{x \to 0} \frac{2\cos(x)+1}{\sin^2 (x) } = \lim_{x \to 0} \frac{1}{\sin^2 (x) }\cdot (2\cos(x)+1) = \infty \cdot 3 = \infty $\)

__________

\( \: \)

Answer in the picture.

The significant figures are the digits of the number that provide information about the measurement that number represents.

In this case, all the digits has to be included because all of them are giving information about the measurement.

The solution to the given system is (-30, 80)

The solution to the given system of the equation of line is the point where both lines intersect.

From the given diagram, we can see that the lines intersect at a coordinate point (x, y)

The location of these coordinate point on the xy-plane is (-30, 80). Hence the solution to the given system is (-30, 80)

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Answer:

The answer is (30,90)

Step-by-step explanation:

the reason is because it says to round to the nearest tenth the numbers not rounded is 32.6 and 86.6

Answer:

x = -2.75

Step-by-step explanation:

:D

14 - 3 = 11

11 / -4 = -2.75

Answer:

80.95

Step-by-step explanation:

Percentage increase = \(\frac{New Value - Old Value}{Old Value}\) *100

=> (38-21)* 100/21 = 80.9523%

The answer round it to the nearest 100th = 80.95%

Answer:

Answer A=48

Step-by-step explanation:

Took the test got it right.

The expression (2w - 2)³ × (8w⁶) is equivalent to :

64w⁹ - 64w⁶ - 192w⁸ + 192w⁷.

Given is the expression as -

(2w - 2)³ × (8w⁶)

The given expression is -

(2w - 2)³ × (8w⁶)

{2(w - 2)}³ × (8w⁶)

8(w - 1)³ × (8w⁶)

(a+b)³ = a³ - 3a²b + 3ab² - b³

So, on expanding, we will get -

8(w³ - 1 - 3w² + 3w) x (8w⁶)

(8w³ - 8 - 24w² + 24w )(8w⁶)

64w⁹ - 64w⁶ - 192w⁸ + 192w⁷

Therefore, the expression (2w - 2)³ × (8w⁶) is equivalent to :

64w⁹ - 64w⁶ - 192w⁸ + 192w⁷.

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The best guess for the mean score for all the Georgia students would be 1050 number here.

Given that:

The mean score for a random sample of Georgia students is 1050.

Assuming,

1) X-bar = 42; µ = 44; standard deviation (sigma) = 10; N = 64. Calculate the standard error.

1) The standard error is computed as:

\(\sigma_{\bar X} = \frac{\sigma}{\sqrt{n}} = \frac{10}{\sqrt{64}} = 1.25\)

2) You know that X-bar = 42, mu = 44, sigma-sub-X = 10, and N = 64, Calculate z-obtained.

2) The Z-value is computed as:

\(Z = \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{N}}} = \frac{42- 44}{\frac{10}{\sqrt{64}}} = -1.6\)

3) The mean score on most IQ tests is 100 with a standard deviation of 15. If Sally has a score of 110 on an IQ test, what is her z-score.

3) The Z -score here is computed as:

\(Z = \frac{X -\mu}{\sigma} = \frac{110-100}{15} = 0.6667\)

The best point estimate for the population mean score is equal to the sample mean which is 1050 in this case. Therefore the best guess for the mean score for all the Georgia students would be 1050 here.

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The equations y = 2/3x - 7 and 2x - y = -15 have one solution due to their intersection at a single point. Graphing these lines, we can find the point of intersection at (6, -1). This is because there is only one set of values for the variables that satisfy both equations. This is the required explanation for the existence of one solution in these systems.

1. Solution:
We have two equations:

y = 2/3x - 7 ----(1)

2x - y = - 15 ----(2)

Let us graph these two lines using their respective slope and y-intercept:Graph for equation 1

:y = 2/3x - 7 => y-intercept is -7 and slope is 2/3.

Using this slope we can plot other points also. Using slope 2/3, we can move 2 units up and 3 units right from y-intercept and plot another point. Plotting these points and drawing a line passing through them, we get the first line as shown below:

graph{2/3*x-7 [-11.78, 10.25, -14.85, 9.5]}

Graph for equation 2:2x - y = -15 => y-intercept is 15 and slope is 2.

Using this slope we can plot other points also. Using slope 2, we can move 2 units up and 1 unit right from y-intercept and plot another point. Plotting these points and drawing a line passing through them, we get the second line as shown below:graph{2x+15 [-6.19, 11.79, -9.04, 17.02]}

Let us find the point of intersection of these two lines. From the graph, it is seen that the lines intersect at the point (6, -1). Now we need to verify this by substituting these values into the two equations:For first equation:

y = 2/3x - 7

=> -1 = 2/3*6 - 7

=> -1 = 4 - 7

=> -1 = -3 which is true. For second equation: 2x - y = -15 => 2*6 - (-1) = -15 => 12 + 1 = -15 => 13 = -15 which is false. Hence (6, -1) is not the solution for this equation. Therefore there is no solution for this equation.2. Explanation:
When a system of equation has one solution, it means that the two or more lines intersect at a single point. That is to say, there is only one set of values for the variables that will satisfy both equations.For example, let's take a system of equation:y = 2x + 1y = -x + 5The above system of equation can be solved by equating both equations to find the value of x as shown below:2x + 1 = -x + 5 => 3x = 4 => x = 4/3Now, substitute the value of x into one of the above equations to find the value of y:y = 2x + 1 => y = 2(4/3) + 1 => y = 8/3 + 3/3 => y = 11/3Therefore, the solution of the above system of equation is (4/3, 11/3).

This system of equation has only one solution because both lines intersect at a single point. Hence this is the required explanation.The following are three different systems of equation that have one solution:1. y = 3x - 5; y = 5x - 7.2. 3x - 4y = 8; 6x - 8y = 16.3. 2x + 3y = 13; 5x + y = 14.The above systems of equation have one solution because the lines intersect at a single point.

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To set up this study as a formal hypothesis test, the null hypothesis (H0) would be that the average age of first childbirth among mothers at community colleges (CBC) is equal to the national average of 26 years old.

The alternative hypothesis (Ha) would be that the average age of first childbirth among CBC mothers is lower than the national average.
The next step would be to collect a random sample of CBC students who are mothers and determine their average age at first childbirth. This sample would be used to calculate the sample mean.
Once the sample mean is obtained, it can be compared to the national average of 26 years old. If the sample mean is significantly lower than 26, it would provide evidence to reject the null hypothesis in favor of the alternative hypothesis, supporting the student's hypothesis that the average age of first childbirth among CBC mothers is lower than the national average.
The student plans to conduct a hypothesis test to determine if the average age of first childbirth among mothers at CBC is lower than the national average.

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Answer:

There are a total of 70 cows in the herd.

Step-by-step explanation:

Represent the total number of cows by c.  Then 0.20c = 14, and

c = 14/0.20 = 70.

There are a total of 70 cows in the herd.

Step-by-step explanation:

If sine theta is 3/5, taking the sine inverse will give you 36.87°.

4tan theta is 4 × tan36.87 = 3

3sin theta = 3 × sin36.87 = 1.8

6cos theta is 6× cos36.87 = 4.8

Therefore, it becomes 3 + 1.8 - 4.8 = 4.8 - 4.8

The answer is 0

Answer:

\( \boxed{\sf 0} \)

Given:

\( \sf sin \theta = \frac{3}{5} \)

To Find:

\( \sf 4tan \theta + 3sin \theta - 6cos \theta\)

Step-by-step explanation:

\(\sf As \ we \ know, \\ \sf sin 37 \degree = \frac{3}{5} \\ \\ \sf \therefore \ sin \theta = sin 37 \degree \\ \\ \sf \implies \theta = 37 \degree\)

\(\sf \implies tan \theta = \frac{3}{4} \\ \\ \sf \implies cos \theta = \frac{4}{5}

\)

\(\sf So, \\ \sf \implies 4tan \theta + 3sin \theta - 6cos \theta \\ \\ \sf Putting \ the \ values \ of \ tan \theta , sin \theta \ and \ cos \theta \ respectively: \\ \sf \implies ( 4 \times \frac{3}{ 4}) + (3 \times \frac{3}{5}) - (6 \times \frac{4}{5} ) \\ \\ 4 \times \frac{3}{ 4} = 3: \\ \sf \implies \boxed{3} + (3 \times\frac{3}{5}) - (6 \times \frac{4}{5} ) \\ \\ \sf 3 \times 3 = 9: \\ 3 + \frac{\boxed{9}}{5} - (6 \times \frac{4}{5} ) \\ \\ \sf 6 \times 4 = 24: \\ \sf 3 + \frac{9}{5} - \frac{\boxed{24}}{5} \\ \\ \sf Put \ 3 + \frac{9}{5} - \frac{24}{5} \ over \ the \ common \ denominator \ 5: \\ \sf \implies 3 \times \frac{5}{5} + \frac{9}{5} - \frac{24}{5} \\ \\ \sf \implies \frac{15}{5} + \frac{9}{5} - \frac{24}{5} \\ \\\sf \implies \frac{15 + 9 - 24}{5} \\ \\ \sf 15 + 9 = 24: \\ \sf \implies \frac{\boxed{24} - 24}{5} \\ \\ \sf 24 - 24 = 0: \\ \sf \implies \frac{\boxed{0}}{5} \\ \\ \sf \implies 0 \)

Factor of the expression 18n - 30 using the greatest common factor of the terms is A 6(3n - 5)

Greatest common factor, as the name implies, is greatest among all common factors among the quantities given.

We can factorize the quantities in smallest relative factors possible (one level of factors over which all quantities can form themselves), and collect as many common factors as we could. Those will together compose GCF(Greatest common factor).

We are given that  the expression 18n - 30

WE need to find Factor of the expression 18n - 30 using the greatest common factor of the terms.

then;

18n - 30

18 = 6 x 3

30 = 6 x 5

Factor out the common part;

6(3n - 5)

Therefore, the correct option is A

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