Answer:
4
Step-by-step explanation:
7. The $5 gift cards are given away first. In
how many ways can these cards be given to 3
of the 9 volunteers? Is this a combination or a
permutation? Explain.
Answer choices:
a. 84; combination because the order does
not matter
b. 504; combination because the order
does not matter
C. 84; permutation because the winners
are chosen one at a time
d. 504; permutation because the winners
are chosen one at a time
Answer:
c
Step-by-step explanation:
En una circunferencia señalamos diez puntos. ¿Cuál es la diferencia entre el número de heptágonos y el de triángulos cuyos vértices son algunos de esos puntos?
Answer:
ok wirrudi 123 alf8 434 21 3dis w
The graph of a quadratic function with vertex (1,-1) is shown in the figure below. Find the domain and the range. Write your answers as inequalities, using or as appropriate. Or, you may instead click on "Empty set" or "All reals" as the answer.
The domain of the function is all real numbers and range is y ≥ -1.
Since the vertex is at (1,-1), the axis of symmetry is x = 1.
This means that the domain of the function is all real numbers.
To find the range, we need to consider the y-values of the graph. Since the vertex is the lowest point of the graph, the range must be all y-values greater than or equal to -1.
However, since the parabola opens upwards, there is no upper bound on the y-values.
Therefore, the range is given by y ≥ -1.
Hence, the domain of the function is all real numbers and range is y ≥ -1.
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what is the difference between random assignment and random selection
Random assignment and random selection are both important concepts in research methodology, but they refer to different processes.
Random selection refers to the process of selecting individuals or elements from a population to be included in a study. The goal of random selection is to ensure that the sample is representative of the larger population. This helps to increase the generalizability of the findings to the population as a whole. For example, if a researcher wants to study the academic performance of high school students in a particular city, they might use random selection to select a sample of students from different schools in that city. This helps to ensure that the sample represents the diversity of students in the population.
On the other hand, random assignment refers to the process of assigning participants to different groups or conditions in a study. The goal of random assignment is to minimize any pre-existing differences between the groups, making it more likely that any differences observed between the groups can be attributed to the independent variable being studied. For example, if a researcher wants to investigate the effectiveness of a new teaching method, they might randomly assign half of the participants to receive the new method and the other half to receive the traditional method. Random assignment helps to ensure that the groups are comparable at the start of the study, reducing the likelihood of confounding variables.
In summary, random selection is about selecting a representative sample from a population, while random assignment is about assigning participants to groups or conditions in a study. Both processes are important in research methodology to ensure accurate and reliable findings.
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Using the predicate symbols shown and appropriate quantifiers, write each English language statement asa predicate wff. (The domain is the whole world.)B(x): x is a ballR(x): x is roundS(x): x is a soccer ballc. All soccer balls are round.d. Some balls are not round.e. Some balls are round but soccer balls are not.f. Every round ball is a soccer ball.
c) The statement "All soccer balls are round" is equivalent to "For all x, if S(x) then R(x)" and it can be written in predicate wff as
\(\forall x\text{ (S(x)}\rightarrow R(x))\)d) The statement "Some balls are not round" is equivalent to "There exist some x such that B(x) and not R(x)", which can be written in predicate wff as
\(\mathfrak{\Im }x(B(x)\wedge\urcorner R(x))\)e) The statement "Some balls are round but soccer balls are not" is equivalent to "There exist x such that B(x) and R(x) and there exist x such that S(x) and not R(x)", can be written in prediacte wff as
\(\mathfrak{\Im }x(B(x)\wedge R(x))\wedge\mathfrak{\Im }x(S(x)\wedge\urcorner R(x))\)f) The statement "Every round ball is a soccer ball" is equivalent to "For all x, if R(x) then S(x)", can be written in prediacte wff as
\(\forall x(R(x)\rightarrow S(x))\)
what is the answer to this question? Please give me the short answer and long answer.
Answer:
Each triangle weighs 3 grams.
Step-by-step explanation:
On the left side, there are 6 squares (12 grams) 3 circles (9 more grams), and 2 triangles (2x grams).
On the right side, there are 3 squares (6 grams) 2 circles (6 grams), and 5 triangles (5x grams).
This makes the equation 21 + 2x = 12 + 5x.
Let's find x.
21 + 2x = 12 + 5x
Subtract 5x from both sides.
21 - 3x = 12
subtract 21 from both sides.
-3x = -9
Divide by -3.
x = 3.
Each triangle weighs 3 grams. Let's prove this.
21 + 2x = 12 + 5x
21 + 2(3) = 12 + 5(3)
21 + 6 = 12 + 15
27 = 27
Which scale can she use for the vertical axis such that the difference in the heights of the bars is maximized? a. 0-50 b. 0-40 c. 10-50 d. 25-40. e. 25-40.
The scale that she can use for the vertical axis to maximize the difference in the heights of the bars is option c, 10-50.
To maximize the difference in the heights of the bars, she needs to choose a scale that covers the range of values represented by the data while minimizing the unused space on the vertical axis.
Option a, 0-50, would cover the entire range of values but may result in a lot of unused space if the data values are relatively small.
Option b, 0-40, would restrict the range of values and may not fully represent the differences between the heights of the bars.
Option c, 10-50, is a suitable choice as it covers the range of values and allows for differentiation between the heights of the bars. It eliminates unnecessary empty space below 10, focusing on the relevant range of data.
Option d and e, 25-40, restrict the range even further and may not adequately capture the differences between the heights of the bars.
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What is 1/10 equal to
Answer:
in decimal form, it is 0.1 in percent form it is 10%
Step-by-step explanation:
Are all arithmetic sequences continuous?
young's modulus of nylon is 3.7 x 10^9 N/M^2. A force of 6.0 x 10^5N is applied to a 1.5-m lenght of nylon of cross sectional area 0.25 m^2.
(a) find the stress in the nylon.
(b) by what amount does the nylon stretch?
The answer to force being applied to Young's modulus of nylon is - The stress in the nylon is 1.6 x 10^8 N/m^2, and the amount by which the nylon stretches is 0.0649 m.
Let's start with part (a) of the question:
(a) To find the stress in the nylon, we can use the formula:
Stress = Force / Area
We are given the force as 6.0 x 10^5 N and the area as 0.25 m^2. So, plugging those values into the formula, we get:
Stress = 6.0 x 10^5 N / 0.25 m^2
Stress = 2.4 x 10^6 N/m^2
Therefore, the stress in the nylon is 2.4 x 10^6 N/m^2.
(b) Now, to find the amount by which the nylon stretches, we can use the formula:
Stress = Young's Modulus x Strain
We know the Young's Modulus of nylon as 3.7 x 10^9 N/m^2, and we need to find the strain. We can use the formula:
Strain = Extension / Original Length
We are given the original length of the nylon as 1.5 m. To find the extension, we need to use the formula:
Extension = Force / (Young's Modulus x Area)
Plugging in the values, we get:
Extension = 6.0 x 10^5 N / (3.7 x 10^9 N/m^2 x 0.25 m^2)
Extension = 0.0649 m
Therefore, the extension of the nylon is 0.0649 m. Now, we can find the strain as:
Strain = Extension / Original Length
Strain = 0.0649 m / 1.5 m
Strain = 0.04327
Finally, plugging the values into the formula for stress, we get:
Stress = Young's Modulus x Strain
Stress = 3.7 x 10^9 N/m^2 x 0.04327
Stress = 1.6 x 10^8 N/m^2
Therefore, the stress in the nylon is 1.6 x 10^8 N/m^2, and the amount by which the nylon stretches is 0.0649 m.
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As caixas de lajota que serão utilizadas em uma construção devem ser transportadas do depósito para a obra. Um caminhão carregado com 280 caixas de lajota conclui o trabalho em 5 viagens. No mínimo, quantas viagens seriam necessárias para concluir esse trabalho se fosse utilizado um caminhão com capacidade para transportar 395 caixas de lajota em cada viagem?
What is Legal Paper Size and Legal Paper Dimension?
The standard size for legal paper in North America and Canada is 8.5 inches by 14 inches.
The standard size for legal paper in North America and Canada is 8.5 inches by 14 inches. On the other hand, A4 paper, which measures 8.5 inches by 11 inches, is the standard legal paper size in Europe and the majority of other nations. Moreover, the legal-size bond paper is 8.5 inches x 14 inches.
Here are the legal size paper dimensions in different units; let's have a look.
Legal paper size in inches: 8.5 inches x 14 inches
Legal size paper in cm: 21.6cm x 35.6 cm
Legal paper size in mm: 216mm x 356mm
A4 Paper which is considered a legal paper size in Europe, etc., has the following dimensions in different units:
A4 paper dimensions in inches: 8.5 inches x 11 inches
A4 paper dimensions in cm: 216 x 279mm
A4 paper dimensions in mm: 21.6 x 27.9 cm
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You invest $20,000 in the stock market. The stock market then plummets
over the next few weeks. Each day, your investment loses half of its value. How
much will you have invested after 14 days? Write the geometric sequence
formula and show all of your work.
After 14 days, you will have approximately $2.4414 invested in the stock market.
The amount you will have invested after 14 days can be calculated using the geometric sequence formula. The formula for the nth term of a geometric sequence is given by:
an = a1 x \(r^{(n-1)\)
Where:
an is the nth term,
a1 is the first term,
r is the common ratio, and
n is the number of terms.
In this case, the initial investment is $20,000, and each day the investment loses half of its value, which means the common ratio (r) is 1/2. We want to find the value after 14 days, so n = 14.
Substituting the given values into the formula, we have:
a14 = 20000 x\((1/2)^{(14-1)\)
a14 = 20000 x \((1/2)^{13\)
a14 = 20000 x (1/8192)
a14 ≈ 2.4414
Therefore, after 14 days, you will have approximately $2.4414 invested in the stock market.
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The amount you will have invested after 14 days is given as follows:
$2.44.
What is a geometric sequence?A geometric sequence is a sequence of numbers where each term is obtained by multiplying the previous term by a fixed number called the common ratio q.
The explicit formula of the sequence is given as follows:
\(a_n = a_1q^{n-1}\)
In which \(a_1\) is the first term of the sequence.
The parameters for this problem are given as follows:
\(a_1 = 20000, q = 0.5\)
Hence the amount after 14 days is given as follows:
\(a_{14} = 20000(0.5)^{13}\)
\(a_{14} = 2.44\)
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1.What tool ensures greater accuracy by aligning the graduated scale with the edges or points to be measured
The tool that ensures greater accuracy by aligning the numbers scale with the edges or points to be measured is a Vernier caliper.
A Vernier caliper is a tool used to accurately measure small lengths, widths, and diameters with precision. It has two parts: an outer frame and a sliding vernier scale. The frame is used to place the object to be measured, while the vernier scale is moved along the frame to measure the object's length.
The graduations on the vernier scale are smaller than the main scale graduations, allowing for more precise measurements to be made. This makes the Vernier caliper a more accurate measuring tool than a standard ruler or tape measure.
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Pls answer i need this 19 points given
Answer:
48
Step-by-step explanation:
its correct believe it or not
In its standardized form, the normal distribution has which of the following properties?
O A. It has a mean of 0 and a standard deviation of 1
O B. It has a mean of 1 and a variance of 0
© C. It cannot be used to approximate discrete probability distributions
O D. It has an area equal to 0 5.
The answer is A. The normal distribution in its standardized form has a mean of 0 and a standard deviation of 1. This means that the distribution is centered around 0, and the spread of the data is determined by the standard deviation of 1. This is useful in statistical analysis because it allows us to compare data from different distributions on a standardized scale.
The normal distribution is a continuous probability distribution that is often used in statistical analysis. It is characterized by a bell-shaped curve and is symmetrical around its mean. In its standardized form, the normal distribution has been transformed to have a mean of 0 and a standard deviation of 1. This transformation is achieved by subtracting the mean of the distribution from each data point and dividing by the standard deviation. This standardization allows us to compare data from different normal distributions on a standardized scale.
The normal distribution has many properties that make it useful in statistical analysis. It is often used as a model for many real-world phenomena, such as the distribution of human height, IQ scores, and many others. The normal distribution is also useful because it is well understood and has many mathematical properties that make it easy to work with.
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Simon makes 30 cakes
he gaves 1/5 of cake sali
he gaves 10% of the 30 cakes to jane
Answer: Sali gets 6 cakes. Jane gets 3 cakes. Simon in the end keeps 21 cakes.
Step-by-step explanation: 1/5 of 30 is 6 so if Sali gets 1/5 then Sali should get 6 cakes. 10% of 30 is 3 so if Jane gets 10% then she should get 3 cakes. Sali and Jane together get 9 cakes so Simon has 21 cakes left.
mr. crandall has assigned a term paper due at the end of the semester. he would like to know the average length of the paper. the data below are the numbers of typed pages from a random sample of 10 term papers. what type of critical value is needed to create a 95% confidence interval for the population mean length of all term papers for this class?
There is a 95% chance that the mean length of all term papers lies between confidence limits (11.58,17.82) for the given data:
14, 20, 25, 10, 16, 8, 15, 12, 18, 9
We assume the length of paper has an approximately normal distribution.
Sample size = 10
The sample mean for the given data = 14.7
The standard deviation for the given data = 5.04
Critical value is obtained from standard normal distribution at the level of significance 0.05.
The critical value is 1.96.
The 95% confidence interval for the mean length of all term papers is calculated as follows:
P(14.7 - (1.96 x (5.04/√10)) < µ < 14.7 + (1.96 x (5.04/√10))) = 0.95
P(11.58 < µ < 17.82) = 0.95
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How do you solve a volume?
Volume of the rectangle is estimated as;
Volume = length x width x height
Define the term volume of the rectangle?A three-dimensional object's volume is a measurement of the amount of space it occupies. We'll look at the procedure for calculate a box's volume on this page.
The size of a box:
The volume of a cube or box can be determined if you understand how to multiply. A surface area of the a flat rectangle is equal to its length twice its width, however that was an earlier understanding for a flat, two-dimensional object.View the box illustration below:
As you can see, there are three dimensions to take into account when dealing with a box or other three-dimensional object: length, width, and height.
Thus, the volume is calculated using the formula length x width x height:
V = l x w x h
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PLEASE HELP!
1. Write an equation in slope
intercept form that passes
through (−1,2) and has a
slope of 2.
2.
Write the equation of the
line in slope intercept form
that contains the points
(4,−2) and (2,5).
Answer:
1.\(y=2x+4\)
2.\(y=1x+3\)
Step-by-step explanation:
Given the following questions:
Question one:
Point A = (-1, 2) = (x1, y2)
m = 2
To find the answer we will use the formula to find the slope intercept, substitute the values and then solve for b.
\(y=mx+b\)
\(m=2\)
\(x=-1\)
\(y=2\)
\(2=2(-1)+b\)
\(2\times-1=-2\)
\(2=-2+b\)
\(-2+2=0\)
\(2+2=4\)
\(4=b\)
\(b=4\)
\(y=2x+4\)
The slope intercept form of the line that passes through (-1, 2) and has a slope of 2 is "y = 2x + 4."
Question two:
Point A = (-1, 2) = (x1, y1)
Point B = (2, 5) = (x2, y2)
To find the slope intercept form we must first find the slope using the formula to calculate slope or rise over run.
\(m=\frac{y2-y1}{x2-x1}\)
\(m=\frac{5-2}{2--1}=\frac{3}{3}\)
\(3\div3=1\)
\(m=1\)
Now that we have the slope, we will use the formula for slope intercept, substitute the values, then solve for b.
\(y=mx+b\)
\(m=1\)
\(y=2\)
\(x=-1\)
\(2=1(-1)+b\)
\(1\times-1=-1\)
\(2=-1+b\)
\(-1+1=0\)
\(2+1=3\)
\(3=b\)
\(b=1\)
\(y=1x+3\)
The line that passes through the points (4, -2) and (2, 5) in slope intercept form is indeed "y = 1x + 3."
Hope this helps.
15° 13 8) X 35° Find the measure of the indicated 9)
ignore the stuff above
Answer:
The missing angle to this triangle is 55 degrees, x is 14.65, and the other missing length is 8.4.
Step-by-step explanation:
In a triangle, all of the angles sum up to 180 degrees. We are given it is a right triangle with another given angle of 35 degrees. 180 degrees - 90 degrees - 35 degress is 55 degrees. Now, we can use law of sines to find x. x / sin 90 degrees = 12 / sin 55 degrees. sin 90 degrees can be simplified to 1. x = 12 / sin 55 degrees. x = 14.65. By using the pythagorean theorem, we can find the last missing side, which is 8.4.
E
Find the lateral area for the regular pyramid.
O36√91 sq. units
O48 91 sq. units
O18√91 sq. units
8√91 sq. units
The lateral area for the regular pyramid is 18√91 sq. units
The base of the pyramid has a side length of 6 units
Hypotenuse of triangle is the lateral edge
base = 6 and height = 8
Lateral edge = 10
To find the slant height
The height of triangle with base 3 and hypotenuse 10 is Slant height
Slant height = √91
To find the area of single face
Area = bh/2
b = 6 and h = √91
Area = (6×√91)/2 = 3√91
To find the lateral area of pyramid
Lateral area = 6×face area = 6×3√91 = 18√91 square units
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Use combining like terms to simplify the expression: 7x+2−5x+4
Answer:
2x+6
Step-by-step explanation:
add the numbers:7x+6-5x
combine the like terms:7x+6-5x
2x+6
Find the measure of angle F
Answer:
∠ F = 80°
Step-by-step explanation:
The sum of the interior angles of a polygon is
sum = 180° (n - 2) ← n is the number of sides
Here n = 6 , then
sum = 180° × 4 = 720°
Sum the interior angles and equate to 720
7x + 7x + 4x + 7x + 7x + 4x = 720
36x = 720 ( divide both sides by 36 )
x = 20
Then
∠ F = 4x = 4 × 20° = 80°
a standing wave is set up in a pool 24 m long which contains six loops. what is the wavelength? a) 24 m b) 48 m c) 8 m d) 4 m
Two length of the same frequency and amplitude moving in opposite directions combine to form a standing wave, which appears to be stationary. Given that the pool in this instance is 24 m long and has six loops, the wavelength is 4 m.
Wavelength = Length of Pool / Number of Loops
24 m / 6 loops
= 4 m
Wavelength
= 4 m
Two waves of the same frequency and amplitude moving in opposite directions combine to form a standing wave, which appears to be stationary. A stationary wave pattern is produced when the two waves collide and interfere with one another. Six loops make up the 24 m-long pool in this instance. As a result, the standing wave's wavelength is equal to the pool's length divided by the number of loops, or 24 m / 6 = 4 m. This indicates that the standing wave's wavelength is 4 metres. Standing waves can be used to determine a wave's speed because they are equal to wavelength times frequency. Understanding how waves behave in various contexts, such as swimming pools, oceans, or other bodies of water, can be helped by this.
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Do you have an insatiable craving for chocolate or some other food? since many north americans apparently do, psychologists are designing scientific studies to examine the phenomenon. According to the survey, it was revealed that 97% of the women in the study acknowledged specific food cravings while only 67% of the men did. Assume that 600 of the respondents were women and 400 were men. Find and interpret the 90% confidence interval for the difference between the population proportions.
( .2597 , .3403 ) is confidence interval for the difference between the population proportions.
What does confidence interval mean?
Your estimate's mean plus and minus the range of that estimate's fluctuation is called a confidence interval. If you repeat your test, you can expect your estimate to fall between these numbers with a reasonable degree of certainty. In statistics, confidence is another word for probability.β₁ = x₁/n₁ = 582/600 = 0.97
β₂ = x₂/n₂ = 268/400 = 0.67
( β₁ - β₂) ± z √β₁( 1 -β₁ )/n₁ + β₂(1 - β₂)/n₂
= (.97 - .67 ) ± 1.645 √.97( 1 - .97)/600 + .97( 1 - .67)/400
= .30 ± 0.4336
= ( .2597 , .3403 )
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Which represents a quadratic function?
f(x) = -8x3 - 16x2 - 4x
f(x) = 3/4 x2 + 2x - 5
f(x) = 4/x2 - 2/x + 1
f(x) = 0x2 - 9x + 7
solve x/-5=-15 and i will give brainliest if right answers are
a. -45
b. 5
c. -5
d. 45
Answer:
if x divided by negative 5 equals negative 15, you multiply both sides by negative 5, leaving x = 75, which should be your answer
Step-by-step explanation:
c. at what points, if any, does f assume local maximum and minimum values
To determine the points where the function \(\(f\)\) assumes local maximum and minimum values, we need to find the critical points of the function by setting its partial derivatives equal to zero. by examining the signs of\(\(\cos y\) and \(\cos y\)\) at the critical points, we can determine the points where f
assumes local maximum and minimum values.
To find the critical points, we first calculate the partial derivatives of f with respect to x and y
\(\(\frac{\partial f}{\partial x} = e^x \cos y\) and \(\frac{\partial f}{\partial y} = -e^x \sin y\).\)
Setting these derivatives equal to zero, we have:
\(\(e^x \cos y = 0\) and \(-e^x \sin y = 0\).\)
From the equation\(\(e^x \cos y = 0\)\), we see that \(\(\cos y = 0\)\)which implies \(\(y = \frac{\pi}{2} + k\pi\)\) for integer k.
From the equation \(\(-e^x \sin y = 0\)\), we find that either \(\(e^x = 0\) or \(\sin y = 0\)\). However, \(\(e^x\)\) is always positive, so the only solution i s \(\(\sin y = 0\)\), which gives\(\(y = k\pi\)\) for integer k.
Next, we analyze the second-order partial derivatives:
\(\(\frac{\partial^2 f}{\partial x^2} = e^x \cos y\) and \(\frac{\partial^2 f}{\partial y^2} = -e^x \cos y\).\)
Evaluating these at the critical points, we find:
\(\(\frac{\partial^2 f}{\partial x^2}(x, y) = e^x \cos y\) and \(\frac{\partial^2 f}{\partial y^2}(x, y) = -e^x \cos y\).\)
By applying the Second Derivative Test, we can classify the critical points based on the signs of these second derivatives. If \(\(\frac{\partial^2 f}{\partial x^2}(x, y) > 0\) and \(\frac{\partial^2 f}{\partial y^2}(x, y) > 0\),\) we have a local minimum. If \(\(\frac{\partial^2 f}{\partial x^2}(x, y) < 0\) and \(\frac{\partial^2 f}{\partial y^2}(x, y) < 0\)\), we have a local maximum.
Therefore, by examining the signs of cos y and cos y at the critical points, we can determine the points where f assumes local maximum and minimum values.
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5. Original Price: $40 Sale Price: $30