1 pointWhat is the name for the compound below? *H:O:H0 Нhydrogen dioxidedihydrogen dioxidedihydrogen oxidehydrogen oxideWhich one is it

Answer:

The correct answer is - A. 12.5 gram.

Explanation:

Given:

The initial amount of sample = 400 gram

the half-life cycle = 3 days

after 15 days remain value = ?

Solution:

The number of half-lives in 15 days = 15/3

= 5 half-lives

the remaining amount of sample after one half-life 3 days = 400/2 = 200

the remaining amount of sample after 2nd half-life or 6 days= 200/2 = 100

the remaining amount of sample after 3rd half-life or 9 days= 100/2 = 50

the remaining amount of sample after 4th half-life or 12 days= 50/2 = 25

the remaining amount of sample after 5th half-life or 15 days= 25/2 = 12.5 gram

Thus, the correct answer is = 12.5 g.

Answer:

True

Explanation:

Answer:

6.1 ×10^-19 J

Explanation:

From E= hc/λ

h= planks constant = 6.6×10^-34 Js

c= speed of light = 3×10^8 ms^1

λ= wavelength = 325 nm

E= 6.6 × 10^-34 × 3×10^8/325 × 10^-9

E= 0.061 × 10^ -17 J

E= 6.1 ×10^-19 J

Answer:

CnH2n+2

Explanation:

Alkane have double and two atoms of hydrogen than carbon atoms

Like C4H10

n = 4

CnH2n+2

C4H2×4+2

C4H10

The factor that would help to determine the distance of the ship from the fish would be  The amount of time it takes the sound waves to travel to the fish and back to the boat​.

This is the term that is used to refer to the total distance that would be traveled by a wave in a given cycle. The distance is usually calculated by the use of lambda. The use of Sonar would have to be determinant on the sound that is being heard.

We would have to check the way that the sound would have to come from the ship and then the way that it would have to be go back to the given boat that is used to report and find the school of fisn.

Hence we would say that The factor that would help to determine the distance of the ship from the fish would be  The amount of time it takes the sound waves to travel to the fish and back to the boat​.

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Answer:

7.9 × 10⁻⁹ M

Explanation:

Step 1: Given data

pH of the ocean: 8.1

Step 2: Calculate the concentration of hydronium ions

We will use the definition of pH.

pH = -log [H⁺] = -log [H₃O⁺]

[H₃O⁺] = [H⁺] = antilog -pH

[H₃O⁺] = antilog -8.1 = 7.9 × 10⁻⁹ M

Since [H₃O⁺] < 10⁻⁷ M, the solution is basic.

dolphin and whales use echolocation

Answer:

if the pH of a solution is 2.0 that means the solution would be acidic.

Explanation:

The society with the least negative effects on the environment is probably the one with a small population, traditional farming methods, no access to contemporary technology, and self-sufficient food production.

This is due to the fact that their way of living is less dependent on modern infrastructure and technology, both of which have a negative impact on the environment. Additionally, their agricultural methods are probably more environmentally friendly and sustainable.

The environmental effects of the other societies on the list would all be greater. Because of the use of fossil fuels and the production of products that require a lot of resources, a big, industrialized society with high levels of consumption would have a significant carbon footprint.

It would still take a lot of resources to maintain its infrastructure and create products in a less populous, highly industrialized society with moderate consumption levels, which would have a negative effect on the environment.

Given that the size of the population alone would necessitate significant resource consumption and infrastructure development, a big population with moderate industrialization and consumption levels would also have a big effect on the environment.

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Answer:

ok, here is your answer

Explanation:

AI-generated answer

To find the mass of oxygen that reacted, we need to use the Law of Conservation of Mass, which states that in a chemical reaction, the mass of the reactants equals the mass of the products.

First, we need to find the number of moles of hydrogen that reacted:

Molar mass of hydrogen (H₂) = 2.016 g/mol

Number of moles of H₂ = mass/molar mass = 46.2 g/2.016 g/mol = 22.92 mol

Next, we need to use the balanced chemical equation to find the number of moles of water produced:

hydrogen + oxygen → water

2H₂ + O₂ → 2H₂O

From the equation, we can see that for every 2 moles of H₂, 1 mole of O₂ is required to produce 2 moles of H₂O. Therefore, the number of moles of O₂ required to produce 22.92 moles of H₂O is:

Number of moles of O₂ = 1/2 x 22.92 mol = 11.46 mol

Finally, we can find the mass of oxygen that reacted by using its molar mass:

Molar mass of oxygen (O₂) = 32.00 g/mol

Mass of oxygen = number of moles x molar mass = 11.46 mol x 32.00 g/mol = 366.72 g

Therefore, the mass of oxygen that reacted is 366.72 g.

Answer:

pH of the acid

Explanation:

114.5 g is the total mass of the beaker .

Total mass of beaker=53.10g+5.348g+ 56.1g

Total mass=114.5 g

Mass is used in physics to specific inertia, a fundamental function of all remember. basically, it's far a mass of rely's resistance to changing its course or pace in response to the software of a force.

The exchange that an applied force produces is smaller the extra mass a body has. The kilogram, the unit of mass within the international machine of gadgets, corresponds to 6.62607015 1034 joule seconds using Planck's consistent (SI). One joule is produced by way of multiplying one kilogram by means of one rectangular meter per 2d.

The kilogram is decided by genuine measurements of Planck's regular on account that the second one and the meter have formerly been described in phrases of other bodily constants.

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The concentration (molarity) of the final NaCl solution is 175 M.

To find the concentration (molarity) of the final NaCl solution, we can use the equation:

M1V1 = M2V2

Where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume.

In this case, we have an initial NaCl solution with a concentration of 2.5 M and a volume of 350 mL (0.350 L). We are diluting this solution to a total volume of 5.0 mL (0.005 L).

Plugging these values into the equation, we have:

(2.5 M) * (0.350 L) = M2 * (0.005 L)

Simplifying the equation:

0.875 = 0.005 * M2

Dividing both sides by 0.005:

M2 = 0.875 / 0.005

M2 = 175M

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Answer:Make sure vyour formatting is clear and easy to understand. Remember, it’s all about helping others understand the answer.

Explanation:

Make sure your formatting is clear and easy to understand. Remember, it’s all about helping others understand the answer.

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The steps I performed:

Earth orbits the sun in a predictable pattern. The pattern of Earth's seasons depend on how much sunlight reaches different areas of Earth as the planet moves around around the sun. It is the earth sun model which shows that the earth circles the sun once a year. So revolution is responsible for it.

Earth has a nearly circular orbit around the sun, Earth also rotates around its north-south axis, an imaginary line passing through earth from pole to pole. Every place on the planet gets 12 hours of light and 12 hours of dark each day.

The temperature conditions on the planet change depending on the distance from the sun. There are colder temperatures at the poles and warmer temperature at the equator.

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To calculate the pH of the solution obtained by mixing HCl and NaOH, we need to consider the neutralization reaction between the two compounds. The reaction between HCl (hydrochloric acid) and NaOH (sodium hydroxide) produces water (H₂O) and forms a salt (NaCl).

Given:

Volume of HCl solution (V₁) = 40 cm³

Concentration of HCl solution (C₁) = 0.2 M

Volume of NaOH solution (V₂) = 30 cm³

Concentration of NaOH solution (C₂) = 0.1 M

1. Determine the moles of HCl and NaOH used:

Moles of HCl = Concentration (C₁) × Volume (V₁)

Moles of HCl = 0.2 M × 0.04 L (converting cm³ to L)

Moles of HCl = 0.008 mol

Moles of NaOH = Concentration (C₂) × Volume (V₂)

Moles of NaOH = 0.1 M × 0.03 L (converting cm³ to L)

Moles of NaOH = 0.003 mol

2. Determine the limiting reagent:

The stoichiometry of the reaction between HCl and NaOH is 1:1, meaning that they react in a 1:1 ratio. Whichever reactant is present in a smaller amount will be the limiting reagent.

In this case, NaOH is present in a smaller amount (0.003 mol), which means it will be fully consumed during the reaction.

3. Determine the excess reagent and its remaining moles:

Since NaOH is the limiting reagent, we need to find the remaining moles of HCl.

Moles of HCl remaining = Moles of HCl initially - Moles of NaOH reacted

Moles of HCl remaining = 0.008 mol - 0.003 mol

Moles of HCl remaining = 0.005 mol

4. Calculate the concentration of HCl in the resulting solution:

Volume of resulting solution = Volume of HCl solution + Volume of NaOH solution

Volume of resulting solution = 0.04 L + 0.03 L

Volume of resulting solution = 0.07 L

Concentration of HCl in the resulting solution = Moles of HCl remaining / Volume of resulting solution

Concentration of HCl in the resulting solution = 0.005 mol / 0.07 L

Concentration of HCl in the resulting solution ≈ 0.071 M

5. Calculate the pH of the resulting solution:

pH = -log[H⁺]

pH = -log(0.071)

Using logarithm properties, we can determine the pH value:

pH ≈ -log(0.071)

pH ≈ -(-1.147)

pH ≈ 1.147

Therefore, the pH of the solution obtained by mixing 40 cm³ of 0.2 M HCl and 30 cm³ of 0.1 M NaOH is approximately 1.147.

Answer: 1.67 kg

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

\(Q=m\times c\times \Delta T\)

Q = Heat absorbed=\(4.31\times 10^1kJ\) = \(43100J\)   (1kJ=1000J)

m= mass of substance = ?

c = specific heat capacity = \(0.385J/g^0C\)

Change in temperature ,\(\Delta T=T_f-T_i=6.71\times 10^1^0C=67.1^0C\)

Putting in the values, we get:

\(43100J=m\times 0.385J/g^0C\times 67.1^0C\)

\(m=1670g=1.67kg\)   (1kg=1000g)

Thus the mass (in kg) of the copper sample is 1.67

The Molar concentration for the H2SO4 titrated against base is 8.55M.

Molar concentration=MV=0.90 x 19=17.1

Titrated against 2 mol base so dividing the molar concentration with 2 and finally getting required result.

New molar concentration=17.1/2=8.55M

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52 grams of carbohydrates at 4 calories per gram equal 208 calories. 4 grams of protein have 4 calories per gram, so 16 calories. 19 grams of fat have 171 calories (9 calories per gram).

Therefore,

52 grams × 4 calories per gram = 208 calories.

Protein: 4 grams × 4 calories per gram = 16 calories.

Fat: 19 grams ×  9 calories per gram = 171 calories

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The volume of 12 gas forms when 21 L Cl2 react at STP is 21 L.

To determine the volume of 12 gas (I assume you mean I2 gas) formed when 21 L of Cl2 reacts at STP (standard temperature and pressure), we need to use the ideal gas law equation.

The ideal gas law equation is given by:

PV = nRT

Where:

P = pressure

V = volume

n = number of moles

R = ideal gas constant

T = temperature

At STP, the pressure is 1 atm, and the temperature is 273.15 K.

From the balanced equation, we can see that the molar ratio between Cl2 and I2 is 1:1. So, if 21 L of Cl2 reacts, it will produce an equal volume of I2 gas.

Given that the volume of Cl2 is 21 L, we can assume the volume of I2 gas formed will also be 21 L.

Therefore, the volume of I2 gas formed is 21 L.

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Answer:

The identity of unknown substance is Barium.

Explanation:

The given compound has a formula of MCl2. And the percentage of chlorine in this compound is said to be 34.1 %. But, we know that the mass of chlorine in this compound is, 35.5*2 = 71 g

Therefore, if we let x be the total mass of the compound, then:

34.1% of x = 71 g

(0.341)x = 71 g

x = 71 g/0.341

x = 208.2 g

Hence, the mass of other atom M, must be:

M = x - 71 g

M = 208.2 g - 71 g

M = 137.2 g

Now, we look into periodic table in group II. We find that the element is Barium with atomic mass of 137 g.

The identity of unknown substance is Barium.

Barium forms a metal chloride whose percentage of chlorine is 34.1 %. The unknown substance is barium chloride.

We have a Group II metal chloride with a general formula MCl₂. The molar mass of Cl⁻ is 35.45 g/mol. The mass of 2 moles of Cl⁻ is:

\(2 mol Cl^{-} \times \frac{35.45g Cl^{-} }{1mol Cl^{-} } = 70.90g Cl^{-}\)

70.90 g represents 34.1% of 1 mole of MCl₂. The molar mass of MCl₂ is:

\(70.90gCl^{-} \times \frac{100gMgCl_2}{34.1gCl^{-} } = 208gMgCl_2\)

208 g of MCl₂ contains 70.90 g of Cl⁻. The mass of M²⁺ in 1 mole of MCl₂ is:

\(mMCl_2 = mCl^{-} + mM^{2+} \\\\mM^{2+} = mMCl_2 - mCl^{-} = 208g-70.9 g = 137.1 g\)

Barium has a molar mass of 137.3 g/mol, so M must be barium. The unknown substance is barium chloride.

Barium forms a metal chloride whose percentage of chlorine is 34.1 %. The unknown substance is barium chloride.

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The process of catalysis  which involves adding a catalyst  to a chemical reaction, increases the rate of the reaction.

Thus, Catalysts are not destroyed during the reaction and are unaffected by it. Very tiny amounts of catalyst are frequently sufficient when the reaction is swift and the catalyst recycles quickly; mixing, surface area, and temperature are key factors in reaction rate.

In order to regenerate the catalyst, it usually reacts with one or more reactants to produce intermediates that then give off the ultimate reaction product.

Homogeneous catalysis, in which all of the components are dispersed in the same phase as the reactant (often a gas or liquid), and heterogeneous catalysis, in which the components are not.

Thus, The process of catalysis  which involves adding a catalyst  to a chemical reaction, increases the rate of the reaction.

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Answer:D the pressure increases

Explanation:

Answer: D

Explanation:

the pressure increases

Answer:

a) What volume will it occupy with 2.60 moles?

V2 = V1 x n2 / n1

V2 = 3.80 x 2.60 / 1.70 = 5.81 L

Answer: V2 = 5.81 L

b) How many moles are in a sample that occupies 1.45 L?

n2 = n1 x V2 / V1 = 1.70 x 1.45 / 3.80 = 0.65 mol

Answer: n2 = 0.65 mol

Explanation:

The volume of the sample that has 2.60 moles and occupies is 5.81 l.

Volume is the space occupied by a three-dimensional object.

The moles of the sample m1 is 1.70

The volume V1 is 3.8 l  

The moles m2 is 2.60

V2 = ?

\(V2 = V1 \times \dfrac{n_2}{n_1} \\\\\\V2 = 3.80 \times \dfrac{2.60}{1.70} = 5.81 \;l\)

Thus, the volume of the sample that has 2.60 moles and occupies is 5.81 l.

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Answer:

Substance C

Explanation:

Substance C would be the answer because Substance C has a lower attraction level. Because of this, it takes more energy to take out of in order to become a liquid.

Answer:

An acid is any hydrogen-containing substance that is capable of donating a proton (hydrogen ion) to another substance. A base is a molecule or ion able to accept a hydrogen ion from an acid.

Answer:

1.Sour in taste

2. Tum blue litmus into red

3. Acids change methyl orange to red

4.Phenolphthalein remains colourless

5. Acids do not give soapy touch

6. Give hydrogen ions in solution

Bitter in taste