(1 point) consider a reaction: a b → 2c . when this reaction occurs, the solution decreases in temperature. is this reaction exothermic or endothermic?

Answer:

Your answer is ATOM

Explanation:

Atoms consist of a nucleus made of protons and neutrons orbited by electrons. Atoms are the basic units of matter and the defining structure of elements.

Basically, they are the building block of life because everything made of matter has atoms

The concentration of A after 30 seconds when the given reaction obeys the rate law rate = k[A]²[B].

We use the initial concentration of A and B and the rate constant of the reaction to find the rates at these concentrations. Using the integrated rate law for a second-order reaction, we find the concentration of A after 30 seconds to be 0.0934 M.

Given reaction obeys the rate law, rate=k[A]²[B].

Here, the initial concentration of A= 0.10 M,

initial concentration of B = 0.05 M, and

rate constant, k = 2.0 × 10⁻⁴ M⁻¹s⁻¹

We have to find the concentration of A, after 30 seconds.

To find the concentration of A, we need to know the rate at 0.10 M and 0.05 M. Therefore, we have to calculate the rates at these concentrations.

rate1 = k[A]²[B]

= (2.0 × 10⁻⁴ M⁻¹s⁻¹)(0.10 M)²(0.05 M)

= 1.0 × 10⁻⁷ M/srate2

= k[A]²[B] = (2.0 × 10⁻⁴ M⁻¹s⁻¹)(0.09 M)²(0.04 M)

= 6.48 × 10⁻⁸ M/s

Using the integrated rate law for a second-order reaction: [A] = [A]₀ - kt where [A]₀ = initial concentration of A, k = rate constant, and t = time in seconds.

We know [A]₀ = 0.10 M and k = 2.0 × 10⁻⁴ M⁻¹s⁻¹.

Substituting the values in the above equation, we get: [A] = [A]₀ - kt= 0.10 M - (2.0 × 10⁻⁴ M⁻¹s⁻¹)(30 s)≈ 0.0934 M

Therefore, the concentration of A in the vessel after 30 seconds is 0.0934 M.

This question requires us to calculate the concentration of A after 30 seconds when the given reaction obeys the rate law rate = k[A]²[B].

We are given the initial concentration of A and B and the rate constant of the reaction. To find the concentration of A after 30 seconds, we need to calculate the rates at the initial concentrations of A and B.

Using the integrated rate law for a second-order reaction, we can find the concentration of A at any given time. We substitute the given values in the formula and solve for [A]. We get the concentration of A as 0.0934 M after 30 seconds. This calculation is based on the assumption that no other reaction is important.

The concentration of A after 30 seconds when the given reaction obeys the rate law rate = k[A]²[B]. We use the initial concentration of A and B and the rate constant of the reaction to find the rates at these concentrations. Using the integrated rate law for a second-order reaction, we find the concentration of A after 30 seconds to be 0.0934 M. This calculation assumes that no other reaction is important.

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Answer:

Cornea >iris>lens >retina

Explanation:

Can't exactly figure out the answer but I think it should look like this

Answer: cornea → iris → lens → retina

Explanation: I have my ways ;>

Answer:

troposphere

Explanation:

Commercial jet aircraft fly in the lower stratosphere to avoid the turbulence which is common in the troposphere below. The stratosphere is very dry; air there contains little water vapor. Because of this, few clouds are found in this layer; almost all clouds occur in the lower, more humid troposphere.

The plane is mostly flying in the troposphere layer.

Hope it helps you...

Answered by Benjemin ☺️

Answer:

No, hydrogen can't be a central atom.

Answer:

no

Explanation:

There are 31. 5 moles in 2.00 kg of copper.We only needed the atomic weight to calculate the molar mass.

To calculate the number of moles of copper in 2.00 kg, we need to use the formula: number of moles = mass / molar mass

First, we need to convert the mass of copper from 2.00 kg to 2000 g. Then we can calculate the molarmass of copper using the atomic weight provided, which is 63.5 g/mol. Now we can substitute these values in the formula: number of moles = 2000 g / 63.5 g/mol = 31.5 mol

So there are 31.5 moles of copper in 2.00 kg. It's important to note that the density of copper given (8.90 g/cm3) was not needed to solve this problem, as it relates to the physical size of the copper sample rather than its chemical composition. We only needed the atomic weight to calculate the molar mass.

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Answer:

FALSE.

Explanation:

This question is not clearly stated. But if i got you clearly, then this is the explanation to my answer.

In reaction involving gasses, a decrease in the volume which means an increase in the pressure( from boyle's concept) will favour the reaction which will reduce the pressure. Therefore, the reaction direction which produces fewer number of moles of gasses is favoured.

When an organism's cells only have one set of chromosomes, the organism is said to be haploid. All organisms that reproduce sexually are diploid (having two sets of chromosomes, one from each parent). Only the egg and sperm cells in humans are haploid.

The term "diploid" describes an organism's cells having two full sets of chromosomes, with one chromosome from each parent present in each pair. Since humans are diploid, the majority of their cells have 23 pairs of chromosomes.

Distinguish between haploid and diploid.

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No of counts:-

\(\\ \sf\longmapsto 5/1.5\)

\(\\ \sf\longmapsto 3.3counts\)

Answer: its blank???

Explanation:

After 30 minutes, there would be 1.05 kilograms of salt in the tank.

1. The differential equation that y(t) satisfies can be obtained by considering the rate of change of salt in the tank. The rate at which salt is added to the tank is given by the concentration of the solution (0.7 kg/L) multiplied by the rate at which the solution is added (6 L/min). The rate at which salt is drained from the tank is given by the concentration of salt in the tank (y(t) kg/L) multiplied by the rate at which the solution is drained (4 L/min). Therefore, the differential equation is:

dy/dt = (0.7 kg/L * 6 L/min) - (y(t) kg/L * 4 L/min)

Simplifying further, we have:

dy/dt = 4.2 - 4y(t)

2. To determine the amount of salt in the tank after 30 minutes, we need to solve the differential equation. One approach is to find the particular solution by assuming y(t) takes the form of a constant, y. Substituting this into the differential equation, we have:

dy/dt = 4.2 - 4y

Setting dy/dt to zero (since y is constant), we can solve for y:

0 = 4.2 - 4y

4y = 4.2

y = 4.2/4

y = 1.05 kg

Therefore, after 30 minutes, there would be 1.05 kilograms of salt in the tank.

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Explanation:

A. The number of moles of C₃H₈ Mr Tooker burn is 70 moles

B. The mass of O₂ that reacted with 3080 grams of C₃H₈ is 11200 grams

The number of mole of C₃H₈ can be obtained as follow:

Mole = mass / molar mass

Number of mole of C₃H₈ = 3080 / 44

Number of mole of C₃H₈ = 70 mole s

Thus, the number of mole is 70 moles

The mass of O₂ that reacted can be obtained as illustrated below:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

From the balanced equation above,

44 grams of C₃H₈ reacted with 160 grams of O₂

Therefore,

3080 grams of C₃H₈ will react with = (3080 × 160) / 44 = 11200 grams of O₂

Thus, the mass of O₂ that reacted is 11200 grams

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The compound in which the octet is expanded to include 12 electrons is SF6 (sulphur hexafluoride). In SF6, the sulphur atom has six fluorine atoms surrounding it, and in order to bond with all six fluorine atoms, the sulphur atom must have an expanded octet, meaning it has 12 electrons in its outermost energy level.

The octet is expanded to include 12 electrons in compounds where the central atom can accommodate more than eight electrons. Such compounds typically involve elements from the 3rd period or below. A common example is sulfur hexafluoride (SF6), where sulfur has an expanded octet of 12 electrons.

The inorganic compound sulphur hexafluoride is a colourless, odourless, nonflammable, and nontoxic gas. With six fluorine atoms joined to a central sulphur atom, SF6 has an octahedral structure. As might be expected for a non-polar gas, SF6 dissolves poorly in water but readily in non-polar organic solvents. At sea level, it has a density of 6.12 g/L, which is significantly higher than the density of air (1.225 g/L). It is often carried as a compressed gas that has been liquefied.

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The oxidized form of the molecule is quinone.

Oxidation has several definitions. Some of them are

In this case, quinone gained an electron from complex 1 to become quinol. Following the definition of oxidation as the loss of electrons, then we can say that the oxidized form of the molecule is quinone itself.

Immediate it gains an electron, it becomes reduced to quinol.

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Isoborneol is the major product in the reduction of camphor with borohydride because borohydride is an effective reducing agent, and isoborneol is the most thermodynamically stable product of the reaction.

The borohydride anion acts as a nucleophile and attacks the carbonyl carbon of camphor from the least hindered side. This leads to the formation of isoborneol as the major product, as it is the most stable and energetically favored product.

In addition, the reduction of camphor with borohydride is a stereoselective reaction, meaning that it preferentially produces one stereoisomer over another. In this case, isoborneol is the preferred product due to its more stable conformation.

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The molecular formula of the unknown compound is C2H2O2.

To determine the molecular formula of the unknown compound, we need to calculate the empirical formula first and then find the multiple of its subscripts to obtain the molecular formula.

Given:

Percentage of carbon = 40.0%

Percentage of hydrogen = 6.7%

Percentage of oxygen = 53.3%

Molecular mass = 60.0 g/mol

Step 1: Convert the percentages to grams.

Assuming we have 100 grams of the compound:

Mass of carbon = 40.0 g

Mass of hydrogen = 6.7 g

Mass of oxygen = 53.3 g

Step 2: Convert the masses to moles using the molar masses of the elements.

Molar mass of carbon = 12.01 g/mol

Molar mass of hydrogen = 1.008 g/mol

Molar mass of oxygen = 16.00 g/mol

Number of moles of carbon = Mass of carbon / Molar mass of carbon

= 40.0 g / 12.01 g/mol

= 3.332 mol

Number of moles of hydrogen = Mass of hydrogen / Molar mass of hydrogen

= 6.7 g / 1.008 g/mol

= 6.648 mol

Number of moles of oxygen = Mass of oxygen / Molar mass of oxygen

= 53.3 g / 16.00 g/mol

= 3.331 mol

Step 3: Determine the empirical formula by dividing the moles by the smallest value.

Dividing the moles of carbon, hydrogen, and oxygen by 3.331 gives approximately 1 for each element.

So, the empirical formula of the compound is CHO.

Step 4: Determine the multiple of the subscripts to obtain the molecular formula.

To find the multiple, we divide the molecular mass by the empirical formula mass.

Molecular mass = 60.0 g/mol

Empirical formula mass = (12.01 g/mol) + (1.008 g/mol) + (16.00 g/mol) = 29.018 g/mol

Multiple = Molecular mass / Empirical formula mass

= 60.0 g/mol / 29.018 g/mol

= 2.07

Rounding to the nearest whole number, we get 2.

Therefore, the molecular formula of the unknown compound is C2H2O2.

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Answer:

C

Explanation:

Increasing temp causes increased molecule movment in sample 2

Answer:

\( \frac{(179.6g) \times (1mol)}{63g} = 2.8 \approx3 \: mol \: HNO_3\\ \frac{4 mol H_2O \times 3}{8 mol HNO_3}=1.5 mol\\ H_2O\\1.5 mol H2O × 175.6g H_2O / 1 mol H_2O = 263. 4g H_2O \)

Answer:

Nanowires can be made from a wide variety of materials, including silicon, germanium, carbon, and various conductive metals, such as gold and copper. Their small size makes them good conductors, with electrons passing easily through them, a property that has allowed for important advances in computer science.

Answer:

No, the two substances will not react with each other

Explanation:

We already know that argon belongs to group 18 in the periodic table. Members of this group are commonly referred to as noble gases. So, we can say that argon is a noble gas.

One characteristic of noble gases is that they possess a filled outermost shell, they have a complete octet of electrons. As a result of this, they hardly  participate in chemical reactions since they have already attained the stability that arises from having a complete octet of electrons.

Hence, argon will not react with hydrogen.

Answer:

No. Two atoms of the same chemical element are typically not identical.

Explanation:

The correct statement that describes the relationship between thermal energy and particle movement is "As thermal energy increases, there is more particle movement".

WHAT IS THERMAL ENERGY?

Hence, as thermal energy of substance increases, there is more particle movement of that substance.

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The empirical formula of citric acid is C₃H₄O₃.

To determine the empirical formula of citric acid based on its elemental composition, we need to convert the percentages into moles and find the simplest ratio of the elements present.

Given the percentages:

Carbon (C): 37.51%

Hydrogen (H): 4.20%

Oxygen (O): 58.29%

Assume we have 100 grams of citric acid, which allows us to directly convert the percentages into grams.

Carbon (C): 37.51 grams

Hydrogen (H): 4.20 grams

Oxygen (O): 58.29 grams

Next, we calculate the number of moles for each element using their respective atomic masses:

Carbon (C): 37.51 g / 12.01 g/mol = 3.12 mol

Hydrogen (H): 4.20 g / 1.01 g/mol = 4.16 mol

Oxygen (O): 58.29 g / 16.00 g/mol = 3.64 mol

Now, we divide each element's moles by the smallest number of moles (3.12) to obtain the simplest, whole-number ratio:

Carbon (C): 3.12 mol / 3.12 mol = 1

Hydrogen (H): 4.16 mol / 3.12 mol = 1.33

Oxygen (O): 3.64 mol / 3.12 mol = 1.17

Rounding to the nearest whole number, we find the empirical formula of citric acid is:

C₁H₁.₃₃O₁.₁₇

However, since we need to express the formula with whole numbers, we multiply all the subscripts by 3 to get:

C₃H₄O₃

Therefore, Citric acid's empirical formula is C₃H₄O₃.

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INFORMATION:

We know that:

- sodium and oxygen react to produce Sodium Oxide

-