1.) HCl is a stronger acid than acetic acid. Which is the
stronger conjugate base, Cl- or acetate
(C2H3O2-)?
2.) Ammonia, NH3, is a weak base.
a.) Write the equation that describes what happens when
NH3 is dissolved in water (e. g. the base
hydrolysis reaction).
b.) Identify the two-conjugate acid-base pairs for the
reaction in (a).

Answer:  m = 179.4 g

Explanation:

Answer:

26.5385

Explanation:

The concentration of each ion in the solution of ammonium chloride is:

To solve this problem, the formulas and the procedures that we have to use are:

Where:

Information about the problem:

Converting the volume units from (ml) to (L) we have:

v(solution) = 500 ml * (1 L/1000 ml)

v(solution) = 0,50 L

We calculate the moles of the NH₄Cl from the MW:

MW = ∑ AWT

MW (NH₄Cl)= AWT (N) + AWT (H)*4 + AWT (Cl)

MW (NH₄Cl)= 14 g/mol +( 1 g/mol * 4) + 35 g/mol

MW (NH₄Cl)= 14 g/mol + 4 g/mol + 35 g/mol

MW (NH₄Cl)= 53 g/mol

Having the MW we calculate the moles of NH₄Cl:

n(NH₄Cl) = m(NH₄Cl) / MW(NH₄Cl)

n(NH₄Cl) = m(H2SO4) / MW (H2SO4)

n(NH₄Cl) =  5 g / 53 g/mol

n(NH₄Cl) = 0.0943 mol

Applying the molarity formula, we get:

M(NH₄Cl) = n(NH₄Cl)/v(solution) L

M(NH₄Cl) = 0.0943 mol / 0,50 L

M(NH₄Cl) = 0.1886 M

There are 0.1886 moles of NH₄Cl per liter of solution.

Let's recognize that 1 mol NH₄Cl contains:

The concentration of each ion is thus:

(1)*(0.1886 M) = 0.1886 M NH₄⁺

(1)*(0.1886 M) = 0.1886 M Cl⁻

In chemistry a solution is known as a homogeneous mixture of two or more components called:

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Answer:

K is a group 1 element while Ne is a group 0 element

K is a good reducing agent while Ne is inert

K is metal while Ne is a gas

K has one valence electron while Ne has no valence electron

Explanation:

Answer:

number 3.

Explanation:

Answer:

3

Explanation:

The balanced equation for neutralization reaction of H2SO4 and KOH is:H2SO4 + 2KOH → K2SO4 + 2H2OWe can use the stoichiometry of the reaction to calculate the number of moles of H2SO4 and KOH.

We have: Volume of H2SO4 solution = 28.37 mL = 0.02837 L Volume of KOH solution = 43.15 mL = 0.04315 L Concentration of H2SO4 solution = 0.142 M Concentration of KOH solution = 0.334 M Number of moles of H2SO4 = Concentration × Volume = 0.142 × 0.02837 = 0.00402854 mol Number of moles of KOH = Concentration × Volume = 0.334 × 0.04315 = 0.0144201 mol From the balanced equation, 2 moles of KOH reacts with 1 mole of H2SO4. Therefore, the number of moles of KOH that reacted is:2 × 0.00402854 = 0.00805708 mol

The remaining number of moles of KOH is the total number of moles of KOH minus the number of moles of KOH that reacted:0.0144201 - 0.00805708 = 0.00636302 mol The volume of the solution is the sum of the volumes of H2SO4 and KOH solutions:0.02837 + 0.04315 = 0.07152 L Therefore, the concentration of OH- that is unreacted is:0.00636302 / 0.07152 = 0.0889 M

Answer: 0.0889 M

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If the daily value for Ca is 1500 mg, the number of Tums tablets needed by older women each day would be  7.5 tablets.

Calcium carbonate consists of calcium and carbonate ions as follows:

\(CaCO_3 -- > Ca^{2+} + CO_3^{2-}\)

Thus, for every 1 mole of calcium carbonate, 1 mole of calcium is involved.

Recall that: mole = mass/molar mass

500 mg of calcium carbonate would be equivalent to:

0.5/100 = 0.005 mol

The equivalent mole of calcium would also be 0.005 mol.

5 mol of calcium would be equivalent to:

0.005 x 40 = 0.2 grams or 200 mg of calcium.

This means that 1 Tums tablet, contains 200 mg of calcium. But 1500 mg is needed daily.

1500/200 = 7.5

This means that older women will need to take 7.5 tablets of Tums per day in order to meet up with the daily calcium requirement of 1500 mg.

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The standard emf of the  voltaic cell based on Ag+(aq)/Ag(s) and Fe3+(aq)/Fe2+(aq) half-cells is 0.03 V.

To determine the reactions at the cathode and anode, we need to know the standard reduction potentials of the given half-cells. The standard reduction potentials are as follows:

Ag+(aq) + e- → Ag(s) E° = +0.80 V
Fe3+(aq) + e- → Fe2+(aq) E° = +0.77 V
Since the higher reduction potential will occur at the cathode and the lower one at the anode, we have:
Cathode reaction: Ag+(aq) + e- → Ag(s)
Anode reaction: Fe3+(aq) + e- → Fe2+(aq)
The cathode reaction involves the reduction of silver ions to silver metal, and the anode reaction involves the reduction of ferric ions to ferrous ions. And the standard emf of the cell is:

E°cell = E°cathode - E°anode

E°cell = +0.80 V - (+0.77 V)

E°cell = 0.03 V

In this voltaic cell, the cathode reaction is Ag+(aq) + e- → Ag(s), and the anode reaction is Fe3+(aq) + e- → Fe2+(aq). The standard emf of the cell is 0.03V.

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A voltaic cell is based on Ag+(aq)/Ag(s) and Fe3+(aq)/Fe2+(aq) half-cells. The cathode reaction is \(Ag^+(aq) + e^{-}\ - > Ag(s)\) and the anode reaction is \(Fe^{3+}(aq)\ - > Fe^{2+}(aq) + e^{-}\).

Determine the cathode and anode reactions

To determine the cathode and anode reactions in the voltaic cell based on the \(Ag^+(aq)/Ag(s)\ and\ Fe^{3+}(aq)/Fe^{2+}(aq)\) half-cells, we need to compare the reduction potentials of each half-reaction. The reaction with the higher reduction potential will occur at the cathode (where reduction takes place), while the reaction with the lower reduction potential will occur at the anode (where oxidation takes place).

The standard reduction potentials for the half-reactions are as follows:

\(Ag^+(aq) + e^{-}\ - > Ag(s) \ \ \ \ \ \ \ \ E\° = +0.80 V\)

\(Fe^{3+}(aq) + e^{-} \ - > Fe^{2+}(aq) \ \ \ \ \ \ \ \ E\° = +0.77 V\)

Since the standard reduction potential for \(Ag^+(aq)/Ag(s)\) is higher than that of \(Fe^{3+}(aq)/Fe^{2+}(aq)\), the \(Ag^+(aq)/Ag(s)\) half-reaction will occur at the cathode (reduction) and the \(Fe^{3+}(aq)/Fe^{2+}(aq)\) half-reaction will occur at the anode (oxidation).

A.) Cathode reaction:

\(Ag^+(aq) + e^{-}\ - > Ag(s)\)

B.) Anode reaction:

\(Fe^{3+}(aq)\ - > Fe^{2+}(aq) + e^{-}\)

It's important to note that the oxidation half-reaction is typically written in the reverse direction (as an oxidation) to emphasize the loss of electrons.

Therefore, the cathode reaction is \(Ag^+(aq) + e^{-}\ - > Ag(s)\) and the anode reaction is \(Fe^{3+}(aq)\ - > Fe^{2+}(aq) + e^{-}\).

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Methylamine could be said to be a Brownstead Lowry base because of 3.

A Brnsted-Lowry base is a type of organism or molecule with the capacity to bind to or take a proton from an acid. A base transforms into its conjugate acid when it takes a proton. This hypothesis is based on the notion that protons are transferred across species during an acid-base reaction.

In contrast to the Arrhenius theory, which defines bases as chemicals that create hydroxide ions, the Brnsted-Lowry base idea offers a broader and more encompassing definition of bases.

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Answer:

yes the answer is c

Explanation:

Answer:

ok

Explanation:

Answer:

Yes it is balanced

Explanation:

You can check by finding the total of each element on both sides so:

Left Hand Side :

Carbons: 6

Oxygens: 6x2 (carbon dioxide) and 6 (water) so there are 18

Hydrogens: 6x2 (carbon dioxide) so 12

Right Hand Side:

Carbons: 6

Oxygens: 6 (glucose) then 6x2 (oxygen) so there are 18

Hydrogens: 12

it is important to analyze the NMR spectrum of β-caryophyllene in the appropriate NMR experiment, typically proton NMR (1H NMR), to identify the characteristic peaks corresponding to this natural terpene compound.

What is β-caryophyllene?

β-caryophyllene is a natural terpene compound found in many essential oils, particularly in spices such as black pepper, cloves, and cinnamon. It is a sesquiterpene, which means it is composed of three isoprene units, and has the molecular formula C15H24.

The proton (1H) NMR spectrum of β-caryophyllene would likely show peaks corresponding to the various types of hydrogen atoms in the molecule. For example:

Protons on the alkene (C=C) double bonds: β-caryophyllene has three alkene double bonds, which would typically appear as multiple peaks in the region of 5-7 ppm in the proton NMR spectrum.

Protons on the cyclohexene ring: β-caryophyllene has a cyclohexene ring, which would typically show peaks in the region of 1-3 ppm in the proton NMR spectrum.

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Question 24:

Answer C : Q is placed in group 13 and period 2.

Question 25:

Answer C : II and IV.

Question 26:

Answer D

The particles move faster as their kinetic energy increases with rising temperature, leading to higher collision and diffusion rates. The particles gain kinetic energy as the temperature rises, which causes them to vibrate more quickly.

An object's kinetic energy is the energy it has as a result of motion. Applying force is necessary if we wish to accelerate an object. We have to put forth work to apply a force. After the job is finished, the object will be travelling at a new, constant speed because energy has been transferred to it.

We use the aforementioned logic to get the kinetic energy and start by determining the work done, W, by a force, F, in a straightforward example. Consider a force parallel to a surface pushing a box with mass mm through a distance d along that surface.

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The false statement about buffers is: d) a buffer always consists of a weak acid and a soluble ionic salt of the weak acid.

Buffers are solutions that can resist changes in pH when small amounts of acids or bases are added. They typically consist of a weak acid and its conjugate base (or a weak base and its conjugate acid). The weak acid and its conjugate base are present in equilibrium, allowing the buffer to accept or donate protons to maintain a relatively constant pH. Option d is false because a buffer can consist of a weak acid and its conjugate base, or a weak base and its conjugate acid. It is not necessary for a buffer to always include a soluble ionic salt.

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The number of moles of iron (III) oxide contained in 2.5 kg of rust is 15.625 moles.

A mole is the mass of a substance that contains 6.023×10²³ particles of that substance.

To calculate the number of moles of iron (III) Oxide contained in 2.5 kg of the rust, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, The number of moles of iron (III) oxide contained in 2.5 kg of rust is 15.625 moles.

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The unknown metal X is iron metal as it reacts with copper sulfate solution but does not react with magnesium chloride.

Some metals are very reactive while other metals are less reactive or unreactive. When a more reactive metal is added to the solution of a less reactive metal, then the more reactive displaces the less reactive metal from its solution is known as a displacement reaction.

The general form of a single displacement reaction can be represented as:

\(A + BC \longrightarrow B + AC\)

When iron is placed in copper sulfate (CuSO₄) solution then the blue color of the copper sulfate solution turns a red-brown coating of copper metal deposited on the iron.

\(CuSO_4 (aq)+ Fe (s)\longrightarrow FeSO_4 (aq) +Cu(s)\)

Iron lies above the electrochemical series and is more reactive than copper. So it reacts with copper sulfate but does not give any reaction with magnesium chloride.

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Answer:

ywhehehehehdgdudcdudcd uy dshdcvv

Explanation:

bdbdkzkzjzdkdkzdvdisisksjskakskskzbx vxydcdudschahahbshshs

Light energy constitutes minute packets discrete from one another called as photons.

The Light energy is the electromagnetic radiation. It will exists in the discrete packets of the energy called as the quanta, or the photons. The Photon cannot be subdivided, and the consequently light will always consists of the integer number of the photon. The photon will differ from the each other in the amount of the energy they contain.

The expression for the energy of the photon is as :

E = hv

Where

v is the frequency of light incident.

h is the Planck's constant

Thus , photons is light energy that constitutes minute packets discrete from one another.

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The chemical reaction that occurs when the positive ion from one compound replaces the positive ion of the other compound is double replacement

What is a double displacement reaction?

This is a type of reaction in which there is an exchange of ion between the reacting agent. The ion in one of the reactant replaces or displaces the ion in the other reactant to produce two new products.

The reaction between sulphuric acid and potassium hydroxide illustrates a double displacement reaction

H₂SO₄ + 2KOH —> K₂SO₄ + 2H₂O

From the above equation, we can see that K and H exchange to produce K₂SO₄ and H₂O

With the above illustration we can answer the given question as follow

AB + CD = AD + CB

The above reaction is a double displacement reaction since A and C exchange to produce AD and CB

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Homogeneous and heterogeneous mixture in colloid, suspension and solution

A colloid is a heterogeneous mixture in which the dispersed particles are intermediate in size between those of a solution and a suspension and within the categories of homogeneous and heterogeneous mixtures there are more specific types of mixtures including solutions is alloys, suspensions, and colloids and a solution is a mixture where one of the substances dissolves in the other and the substance that dissolves is called the solute

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Answer:

more reactents and products

The concentration of the HCl solution is 0.148 M.

The concentration of a solution is typically measured in moles per liter (M). We can calculate the concentration of HCl in the given solution as follows:

Concentration (M) = moles of solute/volume of solution (in liters)

We are given that the solution contains 0.0074 moles of HCl in 0.05 liters of solution. Plugging these values into the equation above, we get:

Concentration (M) = 0.0074 mol / 0.05 L

Concentration (M) = 0.148 M

The concentration of the HCl solution is 0.148 M.

A mole is a measurement used to quantify a substance's quantity. A material is said to have one mole if there are the same number of its constituent parts (such as atoms, molecules, or ions) in it as there are 12 grams of carbon-12.

Because they help us connect a substance's bulk to the number of particles it contains, moles are crucial in the study of chemistry. The mass in grams of one mole of a material, for instance, is known as its molar mass.

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The sound is a mechanical wave because; the sound wave causes vibration in the air.

We know that a wave is a mechanical wave when the direction of the wave motion is parallel to that of the motion that is producing the wave. Also for the mechanical waves, we know that they must be able to pass through matter.

Having this in mind, let us remind ourselves that sound moves through the air and its sets the particles of the air into vibration as we know as such sound is a mechanical wave.

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Missing parts;

The diagram below shows a sound wave moving through air.

What about the diagram that shows that the sound wave is a mechanical wave?

The sound wave was made by a machine.

The sound wave vibrates perpendicular to the direction of the wave motion.

The sound wave causes extra air particles to form.

The sound wave causes vibration in the air.

For each chemical reaction listed in the table below, decide whether the highlighted atom is being oxidized or reduced. H₂S 2NAOH is the highlighted atom being reduced in the given chemical reaction is sulfur (S), while the highlighted atom being oxidized is hydrogen (H).

H₂S + 2NaOH → 2H₂O + Na₂S, is the chemical equation provided in the table above. The reaction between hydrogen sulfide and sodium hydroxide is a redox reaction. A redox reaction is a reaction that involves a transfer of electrons between two species. The oxidation state of sulfur (S) changes from -2 to 0; thus, the sulfur (S) atom is reduced in this reaction. Sodium's (Na) oxidation state changes from +1 to 0, indicating that it has been reduced.

The hydrogen's (H) oxidation state has not changed; it remains +1, indicating that it is neither oxidized nor reduced. The hydrogen sulfide's (H₂S) oxidation state changes from -2 to 0, indicating that it has been oxidized. The sodium hydroxide's (NaOH) oxidation state changes from +1 to -1, indicating that it has been oxidized as well. Hence, the highlighted atom being reduced in the given chemical reaction is sulfur (S), while the highlighted atom being oxidized is hydrogen (H).

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The formula that represents an isomer of the compound is formula 1.

The formula that represents a saturated hydrocarbon is C₃H₈.

The formula that represents a saturated hydrocarbon is C₆H₁₄.

A saturated hydrocarbon is one in which there are only single carbon-carbon bonds. A hydrocarbon is an organic substance made up only of hydrogen and carbon.

The general formula of saturated hydrocarbons is CₙH₂ₙ ₊₂.

The compounds C₃H₈ and C₆H₁₄ follow the general molecular formula of saturated hydrocarbons.

Isomers are compounds that have the same molecular formula but different structural formulas.

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Answer:

Fast, Direction, Time

Explanation:

The climate zones lying between 23.5° and 66.5° north and south latitude are called the Temperate Climate Zones. The regions lying between the latitudes of the Tropics of Cancer and Capricorn (23.5° north and 23.5° south, respectively) are characterized by a tropical climate.

These regions are called the Tropical Climate Zones. The earth is divided into three broad climatic regions based on latitude. The region from the equator to the Tropic of Cancer and the Tropic of Capricorn is referred to as the tropical zone. Because of the proximity to the equator, the tropical zone receives more heat and has higher temperatures throughout the year. The area between the Tropic of Cancer and the Arctic Circle and the Tropic of Capricorn and the Antarctic Circle is known as the temperate zone. In this zone, the seasons are typically more pronounced, and the temperatures vary significantly from summer to winter. The polar zone extends from the Arctic Circle to the North Pole and the Antarctic Circle to the South Pole. It has extremely low temperatures and receives little to no sunlight for half of the year due to the tilt of the Earth's axis.

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The work would become four times if the spring is stretched twice , as the work done while stretching a spring is proportional to the force times the distance therefore the correct answer is option C.

The spring constant is used to define the stiffness of the spring, the greater the value of the spring constant stiffer the spring, and it is more difficult to stretch the spring.

Since the work involved in extending a spring is proportional to the force times the distance, option C is the right response. If the spring is stretched twice, the effort would increase by a factor of four.

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