1) Fill in the contents of the hash table below after inserting the items shown. To insert the item k use the has function k% Table size and resolve collisions with quadratic probing. Insert: 54,174,73,213,15
Answers
To fill in the contents of the hash table using quadratic probing, we'll start with a hash table of size 10 (assuming the table size is 10) and use the hash function `k % Table size` to determine the initial position for each item. If there is a collision, we'll use quadratic probing to find the next available position by incrementing the position with a quadratic sequence.
Here's how the hash table would look like after inserting the given items:
| Index | Item |
|-------|------|
| 0 | 213 |
| 1 | |
| 2 | 54 |
| 3 | 15 |
| 4 | |
| 5 | 73 |
| 6 | |
| 7 | 174 |
| 8 | |
| 9 | |
Let's go through the insertion process step by step:
1. Inserting 54:
- Calculate the initial position using `54 % 10 = 4`.
- Since the position is empty, insert 54 at index 4.
2. Inserting 174:
- Calculate the initial position using `174 % 10 = 4`.
- There is a collision at index 4, so we need to resolve it using quadratic probing.
- Increment the position by 1 squared: `4 + (1^2) = 5`.
- Since the position is empty, insert 174 at index 5.
3. Inserting 73:
- Calculate the initial position using `73 % 10 = 3`.
- Since the position is empty, insert 73 at index 3.
4. Inserting 213:
- Calculate the initial position using `213 % 10 = 3`.
- There is a collision at index 3, so we need to resolve it using quadratic probing.
- Increment the position by 1 squared: `3 + (1^2) = 4`.
- There is another collision at index 4, so we continue with quadratic probing.
- Increment the position by 2 squared: `4 + (2^2) = 8`.
- Since the position is empty, insert 213 at index 8.
5. Inserting 15:
- Calculate the initial position using `15 % 10 = 5`.
- There is a collision at index 5, so we need to resolve it using quadratic probing.
- Increment the position by 1 squared: `5 + (1^2) = 6`.
- Since the position is empty, insert 15 at index 6.
After inserting all the items, the hash table is as shown in the table above. Note that the positions are determined based on the hash function and quadratic probing to handle collisions.
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Related Questions
How does inductive reactance depend on the frequency of the ac voltage source and the rms current through the inductor?.
Answers
Directly proportional.
As the inductive reactance is directly proportional to the frequency, by increasing the frequency the inductive reactance of the inductor increases.
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Consider a condenser in which steam at a specified temperature is condensed by rejecting heat to the cooling water. If the heat transfer rate in the condenser and the temperature rise of the cooling water is known, explain how the rate of condensation of the steam and the mass flow rate of the cooling water can be determined. Also, explain how the total thermal resistance R of this condenser can be evaluated in this case.
Answers
Answer:
Q = [ mCp ( ΔT) ] \(_{cooling water }\)
(ΔT)\(_{cooling water}\) and Q is given
\(m_{cooling water}\) = \(\frac{Q}{Cp[ T_{out} - T_{in} ] }\)
next the rate of condensation of the steam
Q = [ m\(h_{fg}\) ]\(_{steam}\)
\(m_{steam} = \frac{Q}{h_{fg} }\)
Total resistance of the condenser is
R = \(\frac{Q}{change in T_{cooling water } }\)
Explanation:
How will the rate of condensation of the steam and the mass flow rate of the cooling water can be determined
Q = [ mCp ( ΔT) ] \(_{cooling water }\)
(ΔT)\(_{cooling water}\) and Q is given
\(m_{cooling water}\) = \(\frac{Q}{Cp[ T_{out} - T_{in} ] }\)
next the rate of condensation of the steam
Q = [ m\(h_{fg}\) ]\(_{steam}\)
\(m_{steam} = \frac{Q}{h_{fg} }\)
Total resistance of the condenser is
R = \(\frac{Q}{change in T_{cooling water } }\)
Tech A says that in a performance engine, large valve overlap and lift increase high-end rpm. Tech B says that low-end torque is sacrificed as a result of large valve overlap. Who is correct
Answers
Tech A says that in a performance engine, large valve overlap and lift increase high-end rpm. Tech B says that low-end torque is sacrificed as a result of large valve overlap.In a performance engine, large valve overlap and lift increases high-end RPM, this is said by Tech A. Whereas, Tech B claims that large valve overlap sacrifices low-end torque.
Both technicians’ statements are true, but their statements only represent the incomplete picture of the valve overlap’s behavior. Valve overlap is a significant variable in engine performance. During operation, the process of a motor engine involves four strokes or stages: intake, compression, power, and exhaust. The motion of the valves (intake and exhaust) determines the amount of airflow within the combustion chamber. The intake valve opens, and fuel/air mixture enters during the intake stroke, while the exhaust valve opens.
Exhaust gasses leave the cylinder during the exhaust stroke.Valve overlap is the time when both the intake and exhaust valves are partially open. It happens during the end of the exhaust stroke and the beginning of the intake stroke. It occurs once per cycle, and the time it occurs is called duration. Large valve overlap provides higher RPM because it promotes better cylinder filling with fuel/air mixture. However, the motor suffers a power loss on low RPMs since some of the fuel/air mixture that enters through the intake valve escapes through the exhaust valve.
A high valve lift is when the valve is opened farther. It allows more air to enter the combustion chamber, which can increase power. However, it can also cause some air to be lost to the cylinder during the intake stroke. In conclusion, Tech A and Tech B both are correct as they each point to one side of the same picture.
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This may reduce low-end torque, making it more difficult to start the engine and get it moving. This makes Tech B's statement valid. Therefore, Tech B is correct.
Tech A says that in a performance engine, large valve overlap and lift increase high-end rpm, while Tech B says that low-end torque is sacrificed as a result of large valve overlap. The correct person in this case is Tech B.Large valve overlap and lift can result in a higher engine speed, but low-end torque is sacrificed as a result of the reduced air velocity during low speed running when the engine requires it.
Let's see what the valve overlap is.Valve overlap occurs when the intake and exhaust valves are both open at the same time in an engine. The period of time when both valves are open is known as the overlap period. The crankshaft angle in degrees when the intake and exhaust valves are both open in the engine is referred to as the lobe separation angle, or LSA.
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Production machines often lock out the operator while processing parts plus a fixed time for the machine to come to a stop. A TOF timer locks the machine doors at the start of the process and lights a door locked indicator. When the part is finished, the TOF timer keeps the doors locked for an additional 5 seconds for the machine to stop
Answers
Production machines often lock out the operator while processing parts plus a fixed time for the machine to come to a stop.
A TOF timer locks the machine doors at the start of the process and lights a door locked indicator. When the part is finished, the TOF timer keeps the doors locked for an additional 5 seconds for the machine to stop.The process of a machine tool working on a part without any human intervention is known as machining automation. This procedure frequently necessitates machine guarding and automation safety devices. In order to increase safety, manufacturing machines are usually equipped with sensors, lights, and barriers. The TOF (Time-Off Delay) timer is one of the most prevalent automation safety devices.The doors of the machine are locked by the TOF timer, indicating that the machine has started the process, which is shown by a door locked indicator. The TOF timer then keeps the doors closed for an additional five seconds after the part is completed in order to stop the machine. As a result, the operator cannot open the door until the machine has stopped.
The TOF timer is one of the several safety devices used in manufacturing. There are other safety devices that serve a similar function to the TOF timer, such as the interlock switch, which prevents the machine from starting until the door is closed, and the safety mat, which stops the machine if someone steps on it while the machine is running.Automation is a strategy for minimizing the amount of direct human intervention required to operate and maintain machinery, equipment, and other applications. Automation in manufacturing has been employed to accomplish high-volume and high-quality production, as well as to reduce waste and labor costs. With the utilization of automation, the manufacturing process has become more efficient, cost-effective, and safe.
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Technician a says all heavy-duty diesels use 15w-40 engine oil in the summer. Technician b says newer engines use 10w-30 oil. Who is correct?
Answers
As technician b says that all newer engines use 10W-30 oil, hence he is correct.
If a rubber band is stretched adiabatically, its temperature increases. (a) If the rubber band is stretched isothermally, does its entropy in- (b) If the rubber band is stretched adiabatically, does the internal crease, decrease, or stay the same? Energy increase, decrease, or stay the same?
Answers
If two current are in the same direction at any instant of time in a given branch of a circuit, the net current at that instant
Answers
If two currents are in the same direction at any instant of time in a given branch of a circuit, the net current at that instant will be the sum of the two individual currents. In other words, the net current is the algebraic sum of the two currents.
How can this be illustrated?For example, if one current is 2 amperes and the other current is 3 amperes, and they are flowing in the same direction in a given branch of the circuit, then the net current at that instant will be 5 amperes (2 + 3 = 5).
It's important to note that this only applies at a specific instant in time, and the net current may change as the circuit changes or the currents vary.
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I have an AC waveform with the voltage peak value of 100 V. I'm trying to find the RMS value of the voltage
Answers
Answer:
98 x 100=9,00
Explanation:
(20 points) {brainliest} pls helpp
Manufacturing processes involve several types of waste. Which methodology seeks to reduce all types of waste to improve efficiency?
A. Six Sigma
B. Just-in-time production
C. Agile project management
D. Lean manufacturing
Answers
Hope this helps
In addition to passing an ASE certification test, automotive technicians must have __________ year(s) of on the job training or __________ year(s) of on the job training and a two-year degree in automotive repair to qualify for certification.
Answers
Consider the following chain-reaction mechanism for the high-temperatureformation of nitric oxide, i.e., the Zeldovich mechanism:
O + N2------ NO + N Reaction 1
N + O2------ NO + O Reaction 2
A. Write out expressions for d[NO] / dt and d[N] / dt.
B. Assuming N atoms exist in steady state and that the concentrations of O, O2, and N2 are at their equilibrium values for a specified temperature and composition, simplify your expression obtainedabove for d[NO] / dt for the case of negligible reverse reactions.(Answer: d[NO]/d 2 [O] [N ] . 1 2 t k f eq eq = )
C. Write out the expression for the steady-state N-atom concentrationused in part B.
D. For the conditions given below and using the assumptions of part B,how long does it take to form 50 ppm (mole fraction â 106) of NO?
T = 2100 K,
rho = 0.167 kg/m
MW = 28.778 kg/ kmol,
Xo,eq = 7.6.10 (mole fraction),
Xo2,eq = 3.025.10^-3 (mole fraction),
Xn2,eq = 0.726 (mole fraction),
k1f = 1.82.10^14 exp[-38,370/T(K)] with units of cm/gmo
Calculate the value of the reverse reaction rate coeffi cient for the fi rstreaction, i.e., O +â + N NO 2 N, for a temperature of 2100 K.F. For your computations in part D, how good is the assumption thatreverse reactions are negligible? Be quantitative.G. For the conditions of part D, determine numerical values for [N] and ÏN.(Note: k2 f = 1.8 â 1010 T exp(â4680 / T) with units of cm3/ gmol-s.)
Answers
Answer is in the photo. I can only upload it to a file hosting service. link below!
linkcutter.ga/gyko
A thin aluminum sheet is placed between two very large parallel plates that are maintained at uniform temperatures T1 = 900 K, T2 = 300 K and emissivities ε1 = 0.3 and ε2 =0.7, respectively. Thin aluminum sheet has an ε3 of 0.1 facing on the sides of plate 1 and ε3 of 0.2 facing on the sides of plate 2. Determine (a) the net radiation heat transfer between the two plates per unit surface area of the plates (b) compare the result to that without the shield. (c) temperature of the radiation shield in steady operation
Answers
The net radiation heat transfer between the two plates per unit surface area of the plates with shield and without shied are respectively; 2282.76 W/m² and 9766.75 W/m²
How to find the net radiation heat transfer?We are given;
Temperature 1; T₁
Temperature 2; T₂
Temperature 3; T₃
Emissivity 1; ε₁ = 0.3
Emissivity 2; ε₂ = 0.7
Emissivity 3; ε₃ = 0.2
The net rate of radiation heat transfer with a thin aluminum shield per unit area of the plates with shield is;
Q'₁₂ = σ(T₁⁴ - T₂⁴)]/[((1/ε₁) + (1/ε₂) - 1) + ((1/ε₃,₁) + (1/ε₃,₂) - 1)]
Q'₁₂ = 5.67 * 10⁻⁸(900⁴ - 300⁴)/[((1/0.3) + (1/0.7) - 1) + ((1/0.15) + (1/0.15) - 1)]
Q'₁₂,shield = 2282.76 W/m²
The net rate of radiation heat transfer with a thin aluminum shield per unit area of the plates with no shield is;
Q'₁₂,no shield = σ(T₁⁴ - T₂⁴)]/((1/ε₁) + (1/ε₂) - 1))
Q'₁₂,no shield = 5.67 * 10⁻⁸(900⁴ - 300⁴)/[(1/0.3) + (1/0.7) - 1)]
Q'₁₂,no shield = 9766.75 W/m²
Then the ratio of radiation heat transfer for the two cases becomes;
Q'₁₂,shield/Q'₁₂,no shield = 2282.76/9766.75 = 0.2337 or 4/17
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When driving a commercial motor vehicle safely, it is recommended that you leave at
least one second between your vehicle and the vehicle you are following for each
feet of your vehicle's length.
Answers
Answer:
If you are driving below 40 mph, you should leave at least one second for every 10 feet of vehicle length.
how do scientists learn about the layers deep inside earth
Answers
Scientists use a variety of methods to learn about the layers deep inside Earth. One way is by studying seismic waves, which are waves of energy that travel through the Earth's interior during earthquakes.
By analyzing how seismic waves behave as they pass through different layers of the Earth, scientists can infer the composition and properties of each layer. Another way is by examining rocks and minerals that have been brought to the surface by volcanic activity or mountain building. By analyzing the composition of these rocks, scientists can learn about the deeper layers from which they originated. Additionally, scientists use computer models and simulations to study the behavior and composition of the Earth's interior.
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The team needs to choose a primary view for the part drawing. Three team members make suggestions:
- Team member 1 suggests an orthographic top view because that is how the plans for the part were submitted.
- Team member 2 suggests an isometric view showing side details that were documented within the submitted plans.
- Team member 3 suggests all three orthogonal views should be presented as the primary view.
What is the best way to proceed?
Answer choices below:
Answers
Answer:
Option 1
Explanation:
As the team has already submitted the plans for the part drawing, the best way to proceed would be how it was given in the plans. Hence, the option to be selected :
Team member 1 suggests an orthographic top view because that is how the plans for the part were submitted.Answer:
The first option
Explanation:
Team member 1 suggests an orthographic top view because that is how the plans for the part were submitted.
(a) Calculate the heat flux through a sheet of steel that is 10 mm thick when the temperatures oneither side of the sheet are held constant at 300oC and 100oC, respectively.(b) Determine the heat loss per hour if the cross-sectional area of the sheet is 0.25 m2.(c) What will be the heat loss per hour if a sheet of soda-lime glass is used instead
Answers
Answer:
do the wam wam
Explanation:
The heat flux is =1038kW/m² , the heat lost per hour is =259.5 kW, the heat lost per hour using a sheet of soda- lime glass.
Calculation of heat fluxThe thickness of steel( t) = 10mm = 10× 10^-³m
The temperature difference on both sides = 300-100
∆T = 200°C
But the formula for heat flux = q = k∆T/t
Where K = thermal conductivity for steel = 51.9W/mK.
Substitute the variables into the formula for heat flux;
q = 51.9 × 200/10 × 10-³
q = 10380 × 10³/10
q = 10380000/10
q = 1038000 W/m² = 1038kW/m²
To calculate the heat lost per hour if the cross sectional area is = 0.25 m2 use the formula q × A
= 1038kW/m² × 0.25 m2
= 259.5 kW.
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Generic Motors (GM) is making plans for its weekly operation for next year. GM makes three lines of
cars: Luxury (L), Mid-sized (M), and Economy (E). They have divided the country into four regions:
Northeast (NE), Northwest (NW), Southeast (SE) and Southwest (SW). They have two factories that can
ship to the four distribution center via train. Each distribution center will need to provide cars to the
dealers in that region; this is done via trucking. Note that since customers need their cars within a week,
everything is built on a weekly production and shipment schedule. The following information is included:
1) Production costs and capacities at the two factories for the three lines.
2) Retail cost of the three lines.
I
3) A weekly demand model for each of the four regions.
4) Shipping information from the factories to the distribution center of the four regions.
5) Shipping information from the distribution center to the dealers.
You have been asked to maximize the expected weekly profit for GM.
Make sure the spreadsheet is well documented! Use the color coding and headers we used all
semester long. You do not need to reproduce the spreadsheet in the report except the decision tree,
and a summary of your results.
Answers
The Document is automatically shared with support when a ticket is created.
Answers
The following statement of the document is false.
What do you mean by document?
A document is a written, drawn, presented, or documented statement of ideas that frequently includes both non-fictional and fictitious content. The term comes from the Latin Documentum, which means "teaching" or "lesson": the verb doce means "to teach." Historically, the term was used to refer to written proof that may be used as evidence of a truth or reality. "Document" in the computer age usually refers to a mostly textual computer file, including its structure and format, such as fonts, colours, and graphics. Given the existence of electronic documents, the term "document" is no longer defined by its transmission medium, such as paper.
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According to the video, which abilities and skills do Human Resources Managers need to have? Check all that apply.
math skills
in-depth knowledge of the company's product
sensitivity to other people's needs
speaking skills
writing skills
Answers
Answer:
C, D, E
Explanation:
just did it on edge 2020
Answer:
c
d
e
Explanation:
edgunity 2020
Sadie is the props manager for a small community theater. Because she does not have a part onstage, Sadie is not part of the Performing Arts pathway of the Arts, AV Technology and Communication cluster.
True
False
Answers
Answer:
I think it is false!
Explanation:
Answer: I think it's true
Explanation:
Because if you were part of a play, you would have a part but if you work on props, you don't have a part onstage.
meta quest 2 are compatible on ps4 vr starter pack? yes or not
Answers
Answer: The short answer is: no, No, Oculus Quest 2 is not officially compatible with any Playstation console.
What relates a landscape architect's knowledge of design to the landscape architect's knowledge of law and government?
Answers
Answer:
The landscape architect uses knowledge of legal requirements to inform design choices.
Explanation:
The landscape architect doesn’t only draw on knowledge of law and government to design grounds for public buildings, but will draw on that knowledge quite often on many projects. The landscape architect’s knowledge of design is not purely intuitive but is a product of study and might involve research. The landscape architect’s knowledge of law and government, however, does come into play in making design choices that are consistent with the law and government regulations.
TUICUS
4. What are the physical meanings of the Lennard-Jones parameters and how can they be deter-mined from viscosity data? Is the determination unique?
Answers
Answer:
yea of cose you can do it physical inwesment a long risalt can wery high coletty so do it you can
what is the worst way to show self-management?
a. Plant a time to evaluate your progress
b. Set your own career your
c. Ask your boss to set all your goals
d. Ask for feedback on your progress
Answers
The worst way to show self-management is to ask your boss to set all your goals. Self-management is the act of managing one's own behavior, time, and resources effectively to reach a goal.
It is the ability to organize oneself and control impulses, emotions, and actions. It is a skill that requires discipline, self-awareness, and commitment. There are different ways to show self-management, but some ways are better than others.Asking your boss to set all your goals is the worst way to show self-management because it shows a lack of initiative and responsibility. It suggests that you are not willing to take ownership of your career or invest in your development. It also implies that you are not confident in your ability to set and achieve your own goals. By asking your boss to set all your goals, you are giving away your power and agency, and relying on someone else to define your success and progress. This approach can be limiting, disempowering, and demotivating.There are better ways to show self-management, such as planting a time to evaluate your progress, setting your own career goals, and asking for feedback on your progress. Planting a time to evaluate your progress is a proactive way to assess your performance and identify areas for improvement. Setting your own career goals demonstrates ambition, vision, and ownership of your future. Asking for feedback on your progress shows a willingness to learn, grow, and adapt to new challenges. These approaches are more empowering, engaging, and effective than relying on your boss to set all your goals.
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A drilling fluid with oil being the continuous phase and water being dispersed in it, is called
oil-based mud. Despite higher initial cost of oil-based mud compared to that of water-based
mud, there are several cases that oil-based muds are used during drilling operations.
Describe four different applications of oil-based mud and explain the characteristics of oilbased mud that make the oil-based mud a good selection for that applications
Answers
Oil-based mud is a type of drilling fluid used in the oil and gas industry to assist in the drilling process.
What are the characteristics of Oil based Mud?Oil-based mud is a type of drilling fluid used in the oil and gas industry to assist in the drilling process. It has several characteristics that make it a suitable choice for various applications. Here are examples of applications of oil-based mud and the characteristics that make it a good selection:
Drilling through formations with high levels of hydrocarbons: Oil-based mud can be used to drill through formations with high levels of hydrocarbons because it is less likely to cause the hydrocarbons to emulsify, which can lead to problems with hole stability and well control.
Drilling in high-temperature environments: Oil-based mud has a higher flash point than water-based mud, which means it is less likely to ignite in high-temperature environments. This makes it a good choice for drilling in areas with high temperatures, such as in desert regions or deep underground.
Overall, the characteristics of oil-based mud that make it a good selection for these applications include its high viscosity, low density, resistance to corrosion and emulsification, and high flash point.
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A site is underlain by a soil that has a unit weight of 118 lb/ft3. From laboratory shear strength tests that closely simulated the field conditions, the total stress parameters were measured to be C total = 250 lb/ft2 and φ total = 29°. Estimate the shear strength on a horizontal plane at a depth of 12 ft below the ground surface at this site in lbs/ sq ft
Answers
Answer: the shear strength at a depth of 12 ft is 1034.9015 lb/ft²
Explanation:
Given that;
Weight of soil r = 118 lb/ft³
stress parameter C = 250 lb/ft²
φ total = 29°
depth Z = 12 ft
The shear strength on a horizontal plane at a depth of 12ft
ζ = C + δtanφ
where δ = normal stress
normal stress δ = r × z = 118 × 12 = 1416
so
ζ = C + δtanφ
ζ = 250 + 1416(tan29°)
ζ = 250 + 1416(tan29°)
ζ = 250 + 784.9016
ζ = 1034.9015 lb/ft²
Therefore the shear strength at a depth of 12 ft is 1034.9015 lb/ft²
Ground effect is felt at a height that is equal to the plane's wingspan.
True or False
Answers
Answer:
True
Explanation:
In a single-flash geothermal power plant, geothermal water enters the flash chamber (a throttling valve) at 230C as a saturated liquid at a rate of 50 kg/s. The steam resulting from the flashing process enters a turbine and leaves at 20 kPa with a moisture content of 5 percent. Determine the temperature of the steamafter the flashing process and the power output from the turbine if the pressure of the steam at the exit of the flash chamber (푃2) is 1 MPa
Answers
195.96 degrees C and -59.35 kW is the temperature of the steam after the flashing process and the power output from the turbine if the pressure of the steam at the exit of the flash chamber is 1 MPa.
To solve this problem, we need to apply the energy balance and the steam table.
First, we need to determine the state of the geothermal water before the flashing process. Since it enters the flash chamber as a saturated liquid, we can use the steam table to find its properties at the given temperature of 230 degrees C:
h1 = hf + x * hfg = 834.46 kJ/kg (from the steam table)
where h1 is the enthalpy of the geothermal water, hf is the enthalpy of the saturated liquid at 230 degrees C, hfg is the enthalpy of vaporization at 230 degrees C, and x is the quality of the water (which is 0 since it is a saturated liquid).
Next, we need to find the state of the steam after the flashing process. We know that the pressure at the exit of the flash chamber is 1 MPa, and we can assume that the process is adiabatic (no heat transfer). Using the steam table, we can find the enthalpy and quality of the steam at this pressure:
hf = 191.81 kJ/kg (from the steam table)
hfg = 1984.4 kJ/kg (from the steam table)
hg = hf + hfg = 2176.21 kJ/kg
x = (h1 - hf) / hfg = 0.314
where hg is the enthalpy of the saturated vapor at 1 MPa.
Therefore, the temperature of the steam after the flashing process can be found by interpolation:
Tg = 230 + x * (Tsat(1 MPa) - 230) = 230 + 0.314 * (184.97 - 230) = 195.96 degrees C
where Tsat(1 MPa) is the saturation temperature at 1 MPa (from the steam table).
Finally, we can use the steam table again to find the enthalpy of the steam at the exit of the turbine:
hf = 96.83 kJ/kg (from the steam table)
hfg = 2434.4 kJ/kg (from the steam table)
hg = hf + x * hfg = 835.63 kJ/kg
where x is the quality of the steam, which is given as 5%.
Therefore, the power output from the turbine can be calculated as:
P = m * (h1 - hg) = 50 * (834.46 - 835.63) = -59.35 kW
The negative sign indicates that the turbine is consuming power instead of generating power. This is because the quality of the steam at the exit of the turbine is only 95%, which means that there is some moisture content that needs to be removed. To improve the power output, we can use a moisture separator or a reheater to increase the quality of the steam.
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Correct question:
In a single-flash geothermal power plant, geothermal water enters the flash chamber (a throttling valve) at 230 dgrees C as a saturated liquid at a rate of 50 kg/s. The steam resulting from the flashing process enters a turbine and leaves at 20 kPa with a moisture content of 5%. Determine the temperature of the steam after the flashing process and the power output from the turbine if the pressure of the steam at the exit of the flash chamber is 1 MPa.
Describe some typical pairs of entities that you think might be common in business, and describe their relationships, whether many-to-many, one-to-many, many-to-one, or one-to-one. Explain why you think that a particular relationship applies to that pair of entities.
Answers
Answer:
Sole Proprietorship, General Partnership , Limited Partnership, corporation
Explanation:
Business in something that an individual or a group of people do for a living and produce products and services that benefits the society and the people. There are several entities that can be common in business. Some common form of entities are :
Sole Proprietorship : One to one
-- here there is only one owner in the business and he maintains and manages the entire business functions under his control.
Limited Partnership : many to one
-- here two or more than two partners establish business and runs it but only one or more is liable to the amount of the investments.
General Partnership : many to many
-- It is a business partnership where all the partners shares the profits, the assets, legal liabilities and financial liabilities, etc.
Corporation : many to one
It is a business entity where a group of individual or a group of companies run a single business which is generally authorized by the state.
Some of the typical types of the entities that one may think to be common in term of the business entities are about the relationships that are held within many to many and one to many.
The one to one relation is Sole Proprietorship, General Partnership, Limited Partnership, corporation.Learn more about the typical pairs of entities.
brainly.com/question/24935985.
_____is the ability of a system to grow as the volume of users increases.
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Answers
Answer:
Scalability
Explanation:
just took a test and it was right.