1. Fill in the chart
Words
Expression
The Value of the Expression
a. 50 times the sum of 64 and 36
50 x 64 + 36 )
5000
b. Divide the difference between
1,200 and 700 by 5
(1,200 - 700): 5
100
C. The sum of 3 fifteens and 17
fifteens
45 + 255
d. 15 times the sum of 14 and 6
e.
10 x (250 +45)
f.
(560 + 440) x 14

Answer:

yes

Step-by-step explanation:

Answer:

yes the answer is right it is 48.98

Answer:

radius= diameter/2= 10/2

*radius=5

circumference= diameter*pi=10*3.14

*circumference=31.4

Step-by-step explanation: hope this helps

The chi-square test for homogeneity is used if he wants to determine if the distributions are the same.

What is the chi-square test?

Chi-square is a statistical test that looks at how categorical variables from a random sample differ from one another to see if the expected and actual findings match together well.  It is a contrast of two sets of statistical data. Karl Pearson developed this test in 1900 for the analysis and distribution of categorical data.

Here,

We have to determine for which situations should the chi-square test for homogeneity be used.

We concluded from the given option that:

A researcher is trying to determine if salaries for men and women in the tech industry have the same distribution.

He surveys a random sample of men and women in the industry and records the distribution of salaries for each gender.

He wants to determine if the distributions are the same.

Hence, the chi-square test for homogeneity is used if he wants to determine if the distributions are the same.

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Answer:

C The speaker describes the neighbor’s superstitious beliefs about elves in order to characterize him as uncivilized and misguided. The speaker describes the neighbor’s superstitious beliefs about elves in order to characterize him as uncivilized and misguided.

Step-by-step explanation:

This is likely the answer to the question asked.

Answer: A

Step-by-step explanation:

other guy wrong

Answer:

need help

Step-by-step explanation:

Carla is 1.3 miles away from the home.

Given that, Carla leaves home and walks 40° easy to the north for 1.5 miles, then turns and continues due west for 2 miles.

The formula for the cosine rule is c=√(a²+b²-2ab cosC)

Here, c=√(1.5²+2²-2×1.5×2 cos40°)

c=√(2.25+4-6×0.7660)

c=√1.654

c=1.28

c=1.3 miles

Therefore, Carla is 1.3 miles away from the home.

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Answer:

The value of x is 3 and y is 6.

Step-by-step explanation:

You can solve this simultaneous equation by elimination method :

\( - 2x + y = 0 - - - (1)\)

\(x - y = - 3 - - - (2)\)

\((1) + (2)\)

\( - 2x + y + x + (- y) = 0 + ( - 3)\)

\( - x = - 3\)

\(x = 3\)

\(substitute \: x = 3 \: into \: (2)\)

\((2)⇒\)

\(3 - y = - 3\)

\( - y = - 6\)

\(y = 6\)

Answer:

1 1/2

Step-by-step explanation:

7 6/11 is close to 7 1/2

5 13/15 is close to 6

7 1/2 - 6 = 1 1/2

Answer:

Even

Step-by-step explanation:

An odd number added by an odd number will equal an even number.

Good luck :)

Answer:

Even

Step-by-step explanation:

All the answers to adding up odd numbers in the bellow examples shows even answers.

Answer:

Step-by-step explanation:

Original 873  New 781

The new went down by about 10.5%

873*10.5%= 91.67

873-91.67= 781.33

It decreased 10.5%

The inequality to determine how much more money he needs to save so he can buy the shoes is x ≥ $45

Let x be the amount of money Jordan still needs to save to buy the shoes.

The total cost of the shoes is $75, and Jordan has already saved $30. Therefore, the amount of money he still needs to save is:

x = $75 - $30

Simplifying the right side:

x = $45

So, the inequality that represents how much more money Jordan needs to save is:

x ≥ $45

This means that Jordan needs to save at least $45 more to be able to buy the shoes.

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If Noah earns £160 a week and pays £55 in tax, he has £160 - £55 = £160-£55 = £105 to spend.

Subtraction is a mathematical procedure that includes subtracting one number from another. For example, if we have five apples and subtract three of them, we are left with two apples. Beginning with the bigger number and deducting the smaller number from it is how subtraction is done. Subtraction is denoted by the minus symbol (-). A difference is the outcome of a subtractive operation.

We may better grasp how to solve issues requiring the removal of one or more elements from a set by understanding the fundamental mathematical formula of subtraction. It is employed in many different scenarios, such as when we need to subtract incomes on a regular basis.

How to solve?

The formula for the money Noah has to spend each week is m = w - t.

£160 - £55 = £160 - £55 = £105

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lower limit of the 99% interval = 3.7265

Upper limit of the 99% interval = 6.1535

What do you mean  by standard deviation?

The standard deviation is a quantity that reveals the degree of variation (such as spread, dispersion, and spread) from the mean.

Number of students, n = 11

Averange time , mean , μ = 4.94

Standard deviation , \(s_{x}\) = 1.27

Significance level , α = 1 -= 0.99 = 0.01

Degree of freedom for t-distribution , d.f. = n - 1 = 11 - 1 = 10

Critical value = \(t_{\alpha /2,d.f\) = \(t_{0.005,10}\) = 3.169

Margin of error ,E = \(t_{\alpha /2,d.f\) × \(\frac{s_{x} }{\sqrt{n} }\) = 3.169  ×\(\frac{1.27}{\sqrt{11} }\) = 3.169 × 0.38292 = 1.21347

Limits of 99% confidence intervals are given by:

a) Lower limit = μ - E = 4.94 - 1.21347 = 3.7265

b) Upper limit = μ + E = 4.94 + 1.21347 = 6.1535

Therefore, lower limit of the 99% interval = 3.7265

Upper limit of the 99% interval = 6.1535

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We know that probability is defined as the ratio of the number of favourable outcomes to the total number of possible outcomes. A probability must always lie between 0 and 1, inclusive.

In other words, it is a measure of the likelihood of an event occurring. So, out of the given options, 4/3 and 85 cannot be a probability because they are greater than 1 and 0.0002 can be a probability since it lies between 0 and 1. Probability is a measure of the likelihood of an event occurring. It is defined as the ratio of the number of favourable outcomes to the total number of possible outcomes. A probability must always lie between 0 and 1, inclusive. If the probability of an event is 0, then it is impossible, and if it is 1, then it is certain. A probability of 0.5 indicates that the event is equally likely to occur or not to occur. So, out of the given options, 4/3 and  85 cannot be a probability because they are greater than 1. A probability greater than 1 implies that the event is certain to happen more than once, which is not possible. For example, if we toss a fair coin, the probability of getting a head is 0.5 because there are two equally likely outcomes, i.e., head and tail.

However, the probability of getting two heads in a row is 0.5 x 0.5 = 0.25 because the two events are independent, and we multiply their probabilities. On the other hand, a probability less than 0 implies that the event is impossible. For example, if we toss a fair coin, the probability of getting a head and a tail simultaneously is 0 because it is impossible. So, 0.0002 can be a probability since it lies between 0 and 1. Out of the given options, 4/3 and  85 cannot be a probability because they are greater than 1 and 0.0002 can be a probability since it lies between 0 and 1.

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Answer:

Translation

Step-by-step explanation:

Answer:

7 for your x axis and -3 for Y

So your are going from G to H, thats important.

You go to the right seven times and down (hence -3) three times

Answer:

y= 3/4x-4

Step-by-step explanation:

y=mx+b to find the equation

(a) The sampling distribution of p-hat1 - p-hat2 can be approximated by a normal distribution. According to the Central Limit Theorem, when the sample sizes are large enough , the sampling distribution of the difference in sample proportions will be approximately normal, regardless of the shape of the population distributions. Therefore, the shape of the sampling distribution of p-hat1 - p-hat2 is approximately normal.

(b) The mean of the sampling distribution of p-hat1 - p-hat2 can be calculated as:

mean = p1 - p2

where p1 is the population proportion of orange M&M's milk chocolate candies and p2 is the population proportion of orange peanut M&M's.

mean = 0.20 - 0.23 = -0.03

The standard deviation of the sampling distribution of p-hat1 - p-hat2 can be calculated using the formula:

standard deviation = sqrt((p1(1 - p1) / n1) + (p2(1 - p2) / n2))

For M&M's milk chocolate candies:

p1 = 0.20 (proportion of orange M&M's milk chocolate candies)

n1 = 240 (sample size of M&M's milk chocolate candies)

For peanut M&M's:

p2 = 0.23 (proportion of orange peanut M&M's)

n2 = 240 (sample size of peanut M&M's)

standard deviation = sqrt((0.20(1 - 0.20) / 240) + (0.23(1 - 0.23) / 240))

(c) To find P(p-hat1 - p-hat2 > 0), we need to calculate the probability that the difference in sample proportions is greater than zero. This can be interpreted as the probability of observing a greater proportion of orange M&M's milk chocolate candies than orange peanut M&M's.

To calculate this probability, we need to standardize the sampling distribution using the mean and standard deviation calculated in part (b) and then find the area under the normal curve to the right of zero.

Let Z be the standard normal variable.

Z = (p-hat1 - p-hat2 - mean) / standard deviation

Z = (0 - (-0.03)) / standard deviation

Using the calculated mean and standard deviation, we can find the corresponding Z-score and then find the area to the right of zero using a standard normal table or calculator. This area represents P(p-hat1 - p-hat2 > 0), the probability of observing a greater proportion of orange M&M's milk chocolate candies than orange peanut M&M's.

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The standard form of the equation of a line perpendicular to the line (3x + 6y = 5) and passing through the point (1, 3) is (2x - y = -1)

To determine the equation of a line perpendicular to the line (3x + 6y = 5) and passing through the point (1, 3), we can follow these steps:

1. Obtain the slope of the provided line.

To do this, we rearrange the equation (3x + 6y = 5) into slope-intercept form (y = mx + b):

6y = -3x + 5

y =\(-\frac{1}{2}x + \frac{5}{6}\)

The slope of the line is the coefficient of x, which is \(\(-\frac{1}{2}\)\).

2. Determine the slope of the line perpendicular to the provided line.

The slope of a line perpendicular to another line is the negative reciprocal of the slope of the provided line.

So, the slope of the perpendicular line is \(\(\frac{2}{1}\)\) or simply 2.

3. Use the slope and the provided point to obtain the equation of the perpendicular line.

We can use the point-slope form of a line to determine the equation:

y - y1 = m(x - x1)

where x1, y1 is the provided point and m is the slope.

Substituting the provided point (1, 3) and the slope 2 into the equation, we have:

y - 3 = 2(x - 1)

4. Convert the equation to standard form.

To convert the equation to standard form, we expand the expression:

y - 3 = 2x - 2

2x - y = -1

Rearranging the equation in the form (Ax + By = C), where A, B, and C are constants, we obtain the standard form:

2x - y = -1

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the above list shows all the possibilities for the number of people Philippe could place on each team.

Philippe is creating equal-sized teams for his family's game night. 15 people will be playing. The list that shows all the possibilities for the number of people Philippe could place on each team is:{1, 14}{2, 13}{3, 12}{4, 11}{5, 10}{6, 9}{7, 8}Explanation:It is given that Philippe is creating equal-sized teams for his family's game night and 15 people will be playing.In order to find the list that shows all the possibilities for the number of people Philippe could place on each team, we need to find out all the factors of 15.15 can be expressed as:$$15=1 \times 15=3 \times 5$$Therefore, all the possibilities for the number of people Philippe could place on each team are:{1, 14}{2, 13}{3, 12}{4, 11}{5, 10}{6, 9}{7, 8}

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The list that shows all the possibilities for the number of people Philippe could place on each team would be: C. 3, 5

To determine the possibilities for the number of people that could be placed on each team, we would first find all of the factors of 15 and these would be:

1, 15

3, 5

5, 3

So, in all, we have 1, 3, 5, 15.

But the list that shows the possibility of creating equal-sied teams would be; 3 and 5. We cannot have teams of just 1 person each and 15 people would leave us with no team, so 3 and 5 can yield equal-sized teams.

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Let's call A the initial amount of water, in liters, in that barrel.

After y liters were spilled, the amount left was

A - y

Then, after 6 liters were added, the final remaining amount was given by:

A - y + 6

Now, since x liters remain, we have:

x = A - y + 6

Therefore, if we can find the expression for the initial amount of water, in liters, by isolating A in that equation:

x = A - y + 6

x + y = A + 6

x + y - 6 = A

A = x + y - 6

Thus, the initial amount of water was (x + y - 6) liters.

Two teams can be selected out of 10 teams in C(10,2) = 10!/8! 2! = 45 ways

=> If each team plays exactly 3 matches with each other team, number of matches will be 45 x 3 = 135.

:-)

Answer:

Step-by-step explanation:

Number of teams = 10

Each team play each of the other 9 teams once.

Correct choice is B

Answer:

A

Median

5

Mean

6

Mean

4

Use the numbers

1,2,3,4,5,6,7,8 & 9

To complete this table

Mean

4

Mean

36

Mean

8

8

Do now

r = 88.5

y = 3/4

Step-by-step explanation:

From the lower triangle,

97 - 2x = 4x -2

Collecting all similar terms, we get

6x = 99 or x = 16.5

From the upper triangle, we can see that

5x + 6 = r ---> 5(16.5) + 6 = r or r = 88.5

Since the sum of all the interior angles of a triangle is equal to 180, we can write

4y + (5x + 6) + r = 180 ---> 4y + 5(16.5) + 6 + 88.5 = 180

4y = 3 or y = 3/4

Answer:

(9,5.5)

Step-by-step explanation:

The exact prοbability οf there being exactly 70 accidents at the intersectiοn in οne year is apprοximately 0.00382.

Prοbability can be defined as ratiο οf number οf favοurable οutcοmes and tοtal number οutcοmes.

(a) Tο find the exact prοbability that there wοuld be exactly 70 accidents at the intersectiοn in οne year, we can use the Pοissοn distributiοn fοrmula:

P(X = k) =( \(e^{(-λ)\) * \(λ^k\)) / k!

where X is the number of accidents, λ is the average rate of accidents per week (1.4), and k is the number of accidents we're interested in (70).

To find the probability of 70 accidents in one year, we need to adjust the value of λ to reflect the rate over a full year instead of just one week. Since there are 52 weeks in a year, the rate of accidents over a year would be 52 * λ = 72.8.

So, we have:

P(X = 70) = (\(e^{(-72.8)\)* \(72.8^(70)\)) / 70!

Using a calculatοr οr sοftware, we can evaluate this expressiοn and find that:

P(X = 70) ≈ 0.00382

Therefοre, the exact prοbability οf there being exactly 70 accidents at the intersectiοn in οne year is apprοximately 0.00382.

(b) Tο use the nοrmal distributiοn as an apprοximatiοn, we need tο assume that the Pοissοn distributiοn can be apprοximated by a nοrmal distributiοn with the same mean and variance. Fοr a Pοissοn distributiοn, the mean and variance are bοth equal tο λ, sο we have:

mean = λ = 1.4

variance = λ = 1.4

Tο use the nοrmal apprοximatiοn, we need tο standardize the Pοissοn randοm variable X by subtracting the mean and dividing by the square rοοt οf the variance:

\(Z = (X - mean) / \sqrt{(variance)\)

Fοr X = 70, we have:

Z = (70 - 1.4) / \(\sqrt{(1.4)\) ≈ 57.09

We can then use a standard nοrmal table οr calculatοr tο find the prοbability that a standard nοrmal randοm variable is greater than οr equal tο 57.09. This prοbability is extremely small and practically 0, indicating that the nοrmal apprοximatiοn is nοt very accurate fοr this particular case.

Therefοre, the exact prοbability οf there being exactly 70 accidents at the intersectiοn in οne year is apprοximately 0.00382.

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The approximation using the normal distribution gives a probability of approximately 0.3300 that there would be exactly 70 accidents at this intersection in one year.

what is probability?

Probability is a measure of the likelihood of an event occurring. It is a number between 0 and 1, where 0 means the event is impossible and 1 means the event is certain to happen.

(a) Using the Poisson distribution, the probability of exactly 70 accidents at this intersection in one year (i.e., 52 weeks) is:

P(X = 70) = (e^(-λ) * λ^x) / x!

where λ = average rate of accidents per week = 1.4

and x = number of accidents in 52 weeks = 70

Therefore, P(X = 70) = (e^(-1.4) * 1.4^70) / 70! ≈ 3.33 x 10^-23

(b) We can use the normal approximation to the Poisson distribution to approximate the probability that there would be exactly 70 accidents at this intersection in one year. The mean of the Poisson distribution is λ = 1.4 accidents per week, and the variance is also λ, so the standard deviation is √λ.

To use the normal distribution approximation, we need to standardize the Poisson distribution by subtracting the mean and dividing by the standard deviation:

z = (x - μ) / σ

where x = 70, μ = 1.452 = 72.8, σ = √(1.452) ≈ 6.37

Now we can use the standard normal distribution table to find the probability that z is less than or equal to a certain value, which corresponds to the probability that there would be exactly 70 accidents at this intersection in one year:

P(X = 70) ≈ P((X-μ)/σ ≤ (70-72.8)/6.37)

≈ P(Z ≤ -0.44)

≈ 0.3300

Therefore, the approximation using the normal distribution gives a probability of approximately 0.3300 that there would be exactly 70 accidents at this intersection in one year.

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Answer:

Heather paid $26.25 for both items

Answer:

yes its a polynomial espero te sirva

Rational Numbers: Any number that can be written in fraction form is a rational number. This includes integers, terminating decimals, and repeating decimals as well as fractions. An integer can be written as a fraction simply by giving it a denominator of one, so any integer is a rational number.

Hope this helps!

By using combination, it can be obtained that

Number of simple random samples of size 3 that can be selected from a population of size 7 = 35

What is combination?

Combination determines the number of arrangements that can be made from a collection of objects when the order of arrangement is not taken into account.

Here, concept of combination is used

Number of simple random samples of size 3 that can be selected from a population of size 7 = \({7 \choose 3}\) = 35

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