Answer:
a) 0.03050 = 3.050 × 10-²
b) 0.256 x 10°= 2.56 × 10-¹
c) 25.005 10 = 2.500510 × 10¹
Explanation:
Scientific notations is a way of making very large or very small numbers more comprehensive or simplified. It involves the use of power of ten (10^). The numbers are represented to the power of ten. The following format is used:
a x 10^b
where; a is a number or decimal number between 1 and 10 i.e less than 10 but greater than 1
b is the power of ten
To write a number in scientific notation,
- we move the decimal point right or left depending on whether we're trying to reduce or increase the number
- we count the number of times the decimal point was moved. This serves as the b in the format above.
For example,
a) 0.03050 = 3.050 × 10-²
The decimal point was moved rightward twice. This caused the ^-2 power.
b) 0.256 x 10°= 2.56 × 10-¹
The decimal point was moved rightward once. This caused the ^-1 power.
c) 25.005 10 = 2.500510 × 10¹
The decimal point was moved leftward once. This caused the ^1 power.
A solution of KC2H3O2 is diluted from its original concentration of 2.3 M to a new concentration 2.1 M. If it’s new volume is 191.8 mL, what was the original volume of the concentration solution?
The original volume of the concentrated solution was 182.7 mL.
To solve this problem, we can use the formula for dilution:
C1V1 = C2V2
Where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.
We are given that the initial concentration (C1) is 2.3 M, the final concentration (C2) is 2.1 M, and the final volume (V2) is 191.8 mL. We want to find the initial volume (V1).
Plugging in the values we know into the dilution formula, we get:
(2.3 M) V1 = (2.1 M) (191.8 mL)
Simplifying this expression, we can solve for V1:
V1 = (2.1 M) (191.8 mL) / (2.3 M)
V1 = 182.7 mL
It's important to note that the units of concentration and volume must be consistent in this formula. In this case, the concentrations are given in units of M (moles per liter), and the volumes are given in units of mL (milliliters).
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What is TRUE about expert witnesses?
A.
They offer personal and professional knowledge.
B.
They are not allowed to practice their testimony.
C.
They are required to link all evidence to the crime.
D.
They have all written a book about their area of expertise.
The statement they offer personal and professional knowledge is TRUE about expert witnesses (Option A).
What is the role performed by witnesses?The specific role performed by witnesses in a given case is to answer questions associated with a subject matter, which are associated with evidence to confirm or reject a given hypothesis.
Therefore, with this data, we can see that the work performed by witnesses is to provide answers in a given subject matter, which is information that may be used as empirical evidence to confirm or reject a given process.
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An empty graduated cylinder weighs 25.489 g. When the cylinder contains 45.3 mL of an
unknown liquid,
it weighs 57.847 g. What is the mass of the unknown liquid? Show your work.
Answer:
In the given question, the mass of empty slender is given 25 points 489 Grand. The mass of Slender plus unknown liquid is given 57 points 847 g. The volume of a non liquid is given 45 three ml. We have to find the density of a non liquid. Firstly we will find the mass of unknown liquid. As the mass of unknown liquid is equal to the mass of cylinder plus unknown liquid minus the mask of empty cylinders. So the mass of a non liquid is equal to seven points 847 g -25 points 489 g. The mass of a non liquid will be 32 points 358 g. The formula to calculate the density of a non liquid is equal to the mass of a non liquid divided by the volume of a non liquid. So we will put the values as the mass of a non liquid is 32.358 g, Divided by the volume, which is given 45.3 ML. When we solve this Comes out to be 0.71 g, but I am in. So the Final answer is the density of a non liquid is equal to 0.71 g.
Study each picture that depicts the involvement of a particular gland in the endocrine system. Write down the name of the endocrine gland and explain its effect, according to its function.
The thyroid gland produces and secretes two hormones, thyroxine (T4) and triiodothyronine (T3), which are involved in regulating the body's metabolism.
What is thyroid gland?The thyroid gland is regulated by the pituitary gland, which secretes thyroid-stimulating hormone (TSH). When TSH binds to receptors on the thyroid gland, it stimulates the production and secretion of T4 and T3. These hormones play an important role in the growth and development of the body's tissues and organs, including the brain, heart, and muscles.
What is hyperthyroidism?If there is an overproduction of thyroid hormones, it can lead to hyperthyroidism, which can cause symptoms such as weight loss, nervousness, and rapid heartbeat. On the other hand, an underproduction of thyroid hormones can lead to hypothyroidism, which can cause symptoms such as fatigue, weight gain, and cold intolerance.
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6.802 x 1020 particles of Mn(NO3)3 is dissolved in 0.38 L of water.
What is the concentration of this solution in molarity?
A) 3.5 x 10-2M
B) 3.0 x 10 M
C) 0.30M
D) 0.38M
The concentration of the solution in molarity, given that 6.802×10²⁰ particles were dissolved in 0.38 L of water is 3.0×10⁻³ M (option B)
How do i determine the molarity of the solution?First, we shall determine the number of mole that contains 6.802×10²⁰ particles of Mn(NO₃)₃. Details below:
From Avogadro's hypothesis,
6.022×10²³ particles = 1 mole of Mn(NO₃)₃
Therefore, we can say that
6.802×10²⁰ particles = 6.802×10²⁰ / 6.022×10²³
6.802×10²⁰ particles = 0.001 mole of Mn(NO₃)₃
Finally, we shall obtain the molarity of the solution. Details below:
Number of mole of Mn(NO₃)₃ = 0.001 moleVolume of solution = 0.38 LMolarity of solution = ?Molarity of solution = mole / volume
Molarity of solution = 0.001 / 0.38
Molarity of solution = 3.0×10⁻³ M (option B)
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One liter= 1.056 quarts and 4 quarts =1 gallon. How many gallons of water are represented by 500 liters of water?
Answer:
132 gallons.
Explanation:
\( \frac{1.056 \times 500}{4} = 132 \: gallons\)
The volume of water contained in 500 litres is approximately similar to 132 gallons of water.
We will make use of the following conversion factors in order to convert five hundred litres of water to gallons: 1 litre = 1.056 quarts and 4 quarts = 1 gallon.
First, let's convert litres to quarts:
500 litres * 1.056 quarts/liter = 528 quarts.
Next, let's convert quarts to gallons:
528 quarts * (1 gallon / 4 quarts) = 132 gallons.
Therefore, the volume of water contained in 500 litres is approximately similar to 132 gallons of water.
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Between these three liquids, which one would burn through this website's new "interactive" advertising system the fastest? (asking for a friend)
A. Molten lava
B. Hydrochloric acid
C. Nitric acid
for reference assume the "interactive" advertisements are made of the materials in a standard monitor, a visual display, circuitry, casing, and power supply
Answer:
Most likely A. Molten lava, since it straight up melts the equipment which is much faster than chemicals dissolving the equipment like hydrochloric acid and nitric acid.
Explanation:
Hope this helped!
P.S. Sure, why not?
2 Na + 2 H20 = 2 NaOH + H2 is this equation balanced
Answer: yes it it balanced you have 2 atoms on both sides of the equation
Explanation:
What do the black lines on the map represent?
Answer:
they show fracture lines shown in geological maps
Explanation:
hope this helps
a) At 40 °C, what the saturated solubility level of KCl (aq)? (1 mark)
b) If 40 g of KCl is added to 100 g of water at 90 °C, would the solution be saturated? Explain. (2 marks)
c) Describe two ways in which saturation can be achieved if only 40 g of KCl is added to 100 g of water at 90 ° (3 marks)
a) The saturated solubility level of KCl (aq) at 40°C is 35.7 g/100 mL of water.
b) No, the solution would not be saturated at 90°C. At this temperature, the solubility of KCl in water is higher than at 40°C. Therefore, more KCl can dissolve in 100 g of water at 90°C than at 40°C. To determine if the solution is saturated, we need to compare the amount of KCl that actually dissolved in the water to the maximum amount of KCl that can dissolve in the water at that temperature. If the amount of KCl that dissolved is less than the maximum amount, then the solution is unsaturated. If the amount of KCl that dissolved is equal to the maximum amount, then the solution is saturated. If the amount of KCl that dissolved is greater than the maximum amount, then the solution is supersaturated.
c) Two ways in which saturation can be achieved if only 40 g of KCl is added to 100 g of water at 90°C are:
i) Heating the solution to a higher temperature: As the temperature of the solution is increased, the solubility of KCl in water also increases. Therefore, by heating the solution to a higher temperature than 90°C, more KCl can be dissolved in the water until the solution becomes saturated.
ii) Allowing the solution to cool slowly: If the solutionis heated to a temperature higher than 90°C and then allowed to cool slowly, the solubility of KCl in water decreases as the temperature decreases. This means that as the solution cools, KCl will begin to precipitate out of the solution until the solution becomes saturated. Alternatively, if the solution is left undisturbed at 90°C and allowed to cool slowly, KCl will begin to precipitate out of the solution as it reaches its saturation point.
A freezer is maintained at -7°C by removing heat from it at a rate of 80 kJ/min. The power input to the freezer is 0.5 kW, and the surrounding air is at 25°C. Determine (C) the second-law efficiency of this freezer
The second-law efficiency of this freezer is 94.7%.
What is the the second-law efficiency of a refrigerator?The second-law efficiency of a refrigerator or freezer is described as as the ratio of the desired cooling effect which is the heat removed from the cold reservoir) to the energy input required to achieve this cooling effect.
The second-law efficiency of a refrigerator formula is
η = Qc / W
we have the equation as
Qh = mCΔT = Qc
Tc = -7°C = 266 K
Th = 25°C = 298 K and
W = Qh / (1 - Tc/Th) = Qc / (1 - Tc/Th) = 3.3 W
we have found Qc = 3.125
W = 3.3 W
we then substitute into the second-law efficiency formula:
η = Qc / Wmin
η= 3.125 W / 3.3 W
η= 0.947 or 94.7%
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What element has the same number of valence electrons as phosphorus, and the same number of electron shells as iodine.
The element that has the same number of valence electrons as phosphorus and the same number of electron shells as iodine is Antimony, Sb.
What are valence electrons?Valence electrons are the electrons that are found in the outermost shell of an atom of an element.
The number of valence electrons in an atom determines the group to which the elements belong.
Electron shells are the shells in an atom to which an electron is fed into the atom. An electron shell determines the period an element belongs to.
Phosphorus has 5 valence electrons, hence belongs to group 5A or 15.
Iodine has 5 electron shells, hence belongs to period 5.
The element that belongs to group 5A period 5 is antimony.
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Suppose, in an experiment to determine the amount of sodium hypochlorite in bleach, you titrated a 23.92 mL sample of 0.0100 M K I O 3 with a solution of N a 2 S 2 O 3 of unknown concentration. The endpoint was observed to occur at 13.80 mL . How many moles of K I O 3 were titrated
Answer:
2.39x10⁻⁴ moles
Explanation:
As the problem asks us the number of moles of KIO₃ that were titrated, all that is required of us is to calculate how many moles of KIO₃ are there in 23.92 mL of a 0.0100 M solution (All moles in the samples are titrated).
We can do so by using the definition of molarity:
Molarity = moles / litersconverting 23.92 mL ⇒ 23.92 / 1000 = 0.02392 L
moles = 0.0100 M * 0.02392 Lmoles = 2.39x10⁻⁴ molesIf a substance has a density of 0.123 g/mL, 10.0 dL would weigh in g?
Answer:
123 g
Explanation:
First, we convert 10.0 dL into mL, keeping in mind that:
1 dL = 100 mL; then10.0 dL * 100 = 1000 mLNow we can multiply the density by the volume in order to calculate the mass:
Density = mass / volumeDensity * volume = mass0.123 g/mL * 1000 mL = 123 g10.0 dL of a substance with a density of 0.123 g/mL would weigh 123 grams.
Which scenario would adhere to the law of conservation of energy?
Examples of scenarios that would adhere to the law of conservation of energy are as follows:
In a loudspeaker, electrical energy is converted into sound energy.In a microphone, sound energy is converted into electrical energy.In a generator, mechanical energy is converted into electrical energyWhat is law is conservation of energy?The law of conservation of energy states that energy cannot be created nor destroyed but is conserved when it is transferred from one form to another.
The law of conservation of energy is obeyed by majority of natural and artificial systems. For example;
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Answer:
Answer is D on edge 2022
Explanation:
1. Given the following equation: Cu + 2 AgNO3 ---> Cu(NO3)2 + 2 Ag
a. If 12.6 moles of silver (Ag) were produced, how many moles of copper (Cu) were used?
when 1.00g of magnesium is reacted with excess hydrochloric acid, what volume of hydrogen gas will be produced at standard temperature and pressure? statndard temperature and pressure is defined as 0 C and 1 atm. At STP, 1 mole of gas occupies 22.4L.
Answer:
0.93L
Explanation:
Hello,
To solve this question, we need to first of all write down the equation of reaction.
Equation of reaction,
2Mg + 4HCl → 2MgCl₂ + 2H₂
From the equation of reaction, it shows that 2 moles of Mg produces 2 moles of H₂.
Number of moles = mass / molar mass
Mass = number of moles × molar mass
Molar mass of Mg = 24g/mol
Mass = 2 × 24 = 48g
Therefore, 48g of Mg produces (2 × 22.4)L of H₂
48g of Mg = 44.8L of H₂
1g of Mg = xL of H₂
x = (1 × 44.8) / 48
x = 0.93L
1g of Mg will produce 0.93L of H₂
For the reaction below taking place at STP_S + _O2 --> _SO3 How many L of O2 would be needed to produce with 9.1 L of SO3?Give # and unit and remember sig figs.
1) First, let's balance the chemical equation:
_S + _O2 --> _SO3
To balance the equation, we need to equal the number of atoms of each element on the reactants and products side.
2 S + 3 O2 --> 2 SO3
Reactants side:
S - 2
O - 6
Products side:
S - 2
O - 6
2) Now to calculate, we need to know the molar volume value. This is the space occupied, in liters, by 1 mole of any matter in a gaseous state and under normal conditions of temperature and pressure (STP). The value is 22.4 liters/mol
So let's transform 9.1 L of SO3 into mole:
22.4 liters --- 1 mol
9.1 liters ---- x mol
22.4x = 9.1
x = 0.406 moles of SO3
3) Now we use the reaction proportion to know how many moles of O2 is needed:
3 moles of O2 ----- 2 moles of SO3
x moles of O2 ----- 0.40625 moles of SO3
2x = 1.21875
x = 0.609375 moles of O2
4) Now let's transform moles of O2 into liters using the molar volume value:
22.4 L ---- 1 mol
x L ----- 0.609375
x = 13.7 liters of O2
Answer: It is needed 13.7 liters of O2.
calculate the number of moles for the quanity 8.06 x 1021 atoms of Pt
The number of moles for the quanity 8.06 x\(10_{21\) atoms of Pt is approximately 2.61 grams.
To calculate the number of moles for a given quantity of atoms, we can use Avogadro's number and the molar mass of the element. Avogadro's number is 6.022 x 10²³ atoms/mol.
In this case, you have 8.06 x 10²¹ atoms of Pt. To find the number of moles, divide this quantity by Avogadro's number:
8.06 x 10²¹ atoms Pt / 6.022 x 10²³ atoms/mol = 0.0134 mol Pt
So, there are approximately 0.0134 moles of Pt in 8.06 x 10²¹ atoms of Pt.
The molar mass of Pt (platinum) is 195.08 g/mol. To convert the number of moles to grams, multiply the number of moles by the molar mass:
0.0134 mol Pt x 195.08 g/mol = 2.61 g Pt
Therefore, there are approximately 2.61 grams of Pt in 8.06 x10²¹ atoms of Pt.
In summary, the number of moles for the quantity 8.06 x 10²¹ atoms of Pt is approximately 0.0134 moles. This is equivalent to approximately 2.61 grams of Pt. Remember to use Avogadro's number and the molar mass to perform these calculations accurately.
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Propane is used as a fuel for camp stoves. It undergoes combustion to form carbon dioxide and water.
C3H3 +502 – 3 CO2 + 4H20
Determine the number of molecules of propane needed to produce 10.01 liters of carbon dioxide
Answer:
\(8.97x10^{22}molecules C_3H_8\)
Explanation:
Hello there!
In this case, according to the given chemical reaction and the fact that 22.4 L of a gas are occupied by 1 mol at standard pressure and temperature conditions, it will be possible for us to calculate the number of molecules of propane, by using the Avogadro's number, the 1:3 mole ratio with carbon dioxide and the aforementioned volume-mole ratio to obtain:
\(10.01LCO_2*\frac{1molCO_2}{22.4LCO_2}*\frac{1molC_3H_8 }{3molCO_2} *\frac{6.022x10^{23}molec\ C_3H_8}{1molC_3H_8} \\\\=8.97x10^{22}molecules C_3H_8\)
Regards!
Can someone tell me how much does 2 drops of food coloring weight?
Answer:
.3
Explanation:
consider the chemical reaction where and are unknown positive integers. the reaction must be balanced; that is, the number of atoms of each element must be the same before and after the reaction. for example, because the number of oxygen atoms must remain the same, while there are many possible choices for and that balance the reaction, it is customary to use the smallest possible integers. balance this reaction.
aC2H6 + bCO2 + cH2O → dC2H5OH The balanced equation for the reaction is given as; 6C2H6 + 2CO2 + 3H2O → 7C2H5OH, Check! Oxygen Product = 7 Carbon Reactant = 6 * 2 + 2 = 14 Product = 7 * 2 =14 Hydrogen d = 7.
O2 is used to refer to oxygen; O is not?The manner that chemical equations are written ensures that almost all of the molecules are visible.Each oxygen molecule contains two oxygen atoms, which is why the symbol for it is [2].Recall that only two oxygen atoms make up each diatomic oxygen molecule that we breathe.
What processes does carbon undergo?Oxidation processes, addition reactions, substitution reactions, and combustion reactions are the four basic types of reactions in which carbon is primarily involved.When carbon burns with oxygen present, heat and light are produced.
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When an alarm sounds in the laboratory, it is important to respond _______ and remain ______. Listen for any other instructions, turn off any _______ in use, and be prepared to leave immediately.
1) calmly
2) quiet
3) equipment
When an alarm sounds in the laboratory, it is important to respond quickly and remain calm. Listen for any other instructions, turn off any equipment in use, and be prepared to leave immediately.
What is laboratory?
Laboratory is a place where scientific experiments and measurements are performed. It is equipped with various types of equipment and instruments to carry out experiments and tests. Laboratories are usually used by scientists and technicians to conduct experiments, analyze samples, and conduct research. It is an area that is designed to be kept clean and organized in order to ensure safety and accuracy when conducting experiments. Laboratories can be found in many different settings such as hospitals, universities, research and development centers, and manufacturing facilities.
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PbO2 + 4HCl --- PbCl2 + Cl2 + 2H2O who buys electrons and who loses electrons?
Answer: Electrons are taken up by \(PbO_2\) and they are lost by \(HCl\)
Explanation:
Redox reaction is defined as the reaction in which oxidation and reduction take place simultaneously. It is also called the reaction where the exchange of electrons takes place.
An oxidation reaction is defined as the reaction in which a chemical species loses electrons takes place. In this reaction, the oxidation state of a substance gets increased.
A reduction reaction is defined as the reaction in which a chemical species gains electrons takes place. In this reaction, the oxidation state of a substance gets reduced.
For the given chemical reaction:
\(PbO_2+4HCl\rightarrow PbCl_2+Cl_2+2H_2O\)
The half-reactions for this redox rection follows:
Oxidation half-reaction: \(2HCl\rightarrow ClO_2 + 2e^-\)
Reduction half-reaction: \(PbO_2+2e^-\rightarrow PbCl_2\)
Hence, electrons are taken up by \(PbO_2\) and they are lost by \(HCl\)
For electron as a particle, Energy, E=
For an electron as a particle, E = \(1/2mv^2\)
Electron as a particleFor an electron as a particle, the energy E can be described using the equation:
E = \(1/2mv^2\)
where
This equation represents the kinetic energy of the electron, which is the E is the energy
m is the mass of the electronv is the velocity of the electron.energy associated with its motion.
This equation assumes classical mechanics and does not take into account relativistic effects that become significant at high speeds close to the speed of light.
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What is the correct formula that would result from the combination of the two ionic species? Cu2+ and SO42-
The reactant concentration in a zero-order reaction was 8.00×10−2 M
after 140 s and 4.00×10−2 M after 400 s
. What is the rate constant for this reaction?
The rate constant for the reaction is either 7.14×10−3 s−1 or 2.50×10−3 s−1, depending on which rate was used to calculate it.
Determining the rate constantThe rate of the reaction is given by the equation:
Rate = -k[A]
where k is the rate constant and [A] is the concentration of the reactant.
Rate at t=140 s:
Rate = (8.00×10−2 M - 0 M) / (140 s - 0 s)
= 5.71×10−4 M/s
Rate at t=400 s:
Rate = (4.00×10−2 M - 0 M) / (400 s - 0 s)
= 1.00×10−4 M/s
Since this is a zero-order reaction, the rate of the reaction is constant, and we can use either rate to calculate the rate constant:
k = Rate / [A]
Using the rate at t=140 s:
k = 5.71×10−4 M/s / 8.00×10−2 M = 7.14×10−3 s−1
Using the rate at t=400 s:
k = 1.00×10−4 M/s / 4.00×10−2 M
= 2.50×10−3 s−1
The rate constant for the reaction is either 7.14×10−3 s−1 or 2.50×10−3 s−1.
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Which statement BEST describes the process of oxidation?
A. addition of hydrogen
B. loss of oxygen
C. decrease in oxidation number
D. loss of electrons
E. gain of elections.
The correct option is D. loss of electrons.
Loss of electrons is the statement best describes the process of oxidation.
Chemical reaction known as oxidation is described as a procedure that takes place when atoms or group of atoms lose electrons. If a chemical species gains oxygen or loses hydrogen, that is an example of oxidation. Oxidation takes place when these things happen.
An oxidising agent is any substance that causes another chemical lose electrons (become oxidised). On the other hand, a reducing agent is any chemical that causes another chemical to gain electrons.
The biochemical oxygen demand of wastewater is reduced after oxidation, which also reduces some contaminants' toxicity. Some contaminants undergo this treatment and are transformed into carbon dioxide, water, and biosolids. Disinfection is frequently accomplished using chemical oxidation.
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What is mass of 0.6 molC4H10
Answer:
35 gm
Explanation:
What is mass of 0.6 mol C4H10
C4H10 has a molar nass of
(4X12) (10
X 1) = 48 + 10 8
so 1 mole of C4H10 is 58 gm
so 0.6 moles is
(0.6 X58) = 35 gm
Imagine that you mix 25 g of water at 25 ºC with 25 g of water at 65 ºC. Predict the final temperature of the sample.
The final temperature of the mixture given that 25 g of water at 25 °C is mixed with 25 g of water at 65 °C, is 45 °C
How do i determine the final temperature of the mixture?The final temperature of the mixture can be obtained by calculating the equilibrium temperature of the mixture. This is shown below:
Mass of cold water (M) = 25 gTemperature of cold water (T) = 25 °CMass of warm water (Mᵥᵥ) = 25 gTemperature of warm water (Tᵥᵥ) = 65 °CEquilibrium temperature (Tₑ) =?Heat loss by warm water = Heat gain by cold water
MᵥᵥC(Tᵥᵥ - Tₑ) = MC(Tₑ - T)
Cancel out C
Mᵥᵥ(Tᵥᵥ - Tₑ) = M(Tₑ - T)
25× (65 - Tₑ) = 25 × (Tₑ - 25)
Cancel out 25
65 - Tₑ = Tₑ - 25
Collect like terms
65 + 25 = Tₑ + Tₑ
90 = 2Tₑ
Divide both side by 2
Tₑ = 90 / 2
Tₑ = 45 °C
Thus, we can conclude that the final temperature the mixture is 45 °C
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